The EPA has used the slogan “Ozone: good up high, bad nearby” in some of its publications for the general public. Explain the message

Answers

Answer 1

Answer:

------------------------------

Explanation:

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Related Questions

A solution that contains less than the amount of solute that would be dissolved at equilibrium is considered to be

Answers

Answer:

dilute solution

A solution containing less solute than the equilibrium amount is called a dilute solution. The solvent has a limited capacity to dissolve a solute.

Explanation:

TRUE or FALSE 1. Badminton began in India as a game called poona. 2. The shuttle was then called a bird because it was made from goose feather. 3. Ti jian zi played by throwing up in the air. 4. Racket is made of either metal or synthetic materials. 5. Head, throat, shaft, and handle are the parts of the rackets. 6. Shuttlecock is made up of 16 goose feathers. 7. Forehand, Backhand, and Sidestroke are the three basic skills of Badminton. 8. Backhand is use to depends on the type of shot to be executed. 9. Stroke means to propel with a controlled swinging blow. 10. The whole size of the badminton court has 39 meters.​

Answers

Answer:

1.false

2.true

3.true

4.true

5.false

6.false

7.false

8.true

9.false

10.true

Explanation:

I took the test

chlorine has two isotopes chlorine-35 and chlorine-37 with average atomic mass 35.5.find the percentage abundance of each isotopes​

Answers

Answer:

75% Cl-35 and 25% Cl-37

Explanation:

chlorine has two isotopes chlorine-35 and chlorine-37 with average atomic mass 35.5.find the percentage abundance of each isotopes​

assume Cl-35 has Y%  Then Cl-37 has (100-Y) %

The weighted average of 35.5 is given by

[(35 x Y) + ((100-Y) x 37)]/100 = 35.5

so

(35 x Y) + ((100-Y) x 37) =3550

35Y + 3700 -37Y =  3550

-2Y = -15075% Cl-35 and 25% Cl-37

Y = so average weight chlorine is

75% Cl-35 and 25% Cl-37

HELP ME OUT PLEASE!!!!

Which statement correctly describes one of the changes?

A) Picture I shows a chemical change, because a new substance is formed.

B) Picture Il shows a chemical change, because a new substance is formed.

C) Picture I shows a chemical change, because the same substance changes form,

D) Picture Il shows a chemical change, because the same substance changes form.​

Answers

Answer:

Answer D. Picture II shows a chemical change, because the same substance changes form

Explanation:

This is the temperature that water molecules slow down enough to stick to each other and form a solid crystal

Answer:

D Im 90% Sure

Explanation:

If its not right i owe you one I did this one before

All of the following are properties of molecular compounds except
O A A crystal structure,
O B. low melting points.
C. bonds formed through shared electrons,
D. the inability to conduct electric current when melted or dissolved in water,

Answers

Answer: the answer is c.

Explanation:

i juss guessed and it was right?

A student performs a titration of 51.0 mL of a phosphoric
acid (H PO) solution of unknown concentration with a
standardized 1.25 M NaOH solution. The titration requires
26.2 mL of base to reach the third equivalence point. What is
the concentration of the H3PO4
solution?

Answers

From the information available in the question, the concentration of the acid is 0.21 M.

H3PO4(aq) + 3NaOH(aq) -----> Na3PO4(aq) + 3H2O(l)

Volume of acid(VA) = 51.0 mL

Concentration of acid (CA) = ?

Volume of base (VB) = 26.2 mL

Concentration of base (CB) = 1.25 M

Number of moles of acid (NA) = 1

Number of moles of base (NB) = 3

Using the formula;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CA =  CBVBNA/VANB

CA =  1.25 M × 26.2 mL × 1/51.0 mL × 3

CA = 0.21 M

The concentration of the acid is 0.21 M.

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Convert the heat of neutralization of acetic acid from -49,8 kj/mmol to calories per
millimole and ROUND TO ONE DECIMAL PLACE (1 cal = 4.184 J)
DO NOT INCLUDE UNITS

Answers

This question is providing the exothermic heat of neutralization of acetic acid in units of kilojoules per mollimole (-49,8 kj/mmol) and asks for the same value but in calories per millimole which results -11,902.5 cal/mmol.

In this case, according to the given problem, it turns out necessary to solve a two-factor conversion in order to convert the kilojoules to joules and finally to calories as shown below:

[tex]-49.8\frac{kJ}{mmol}*\frac{1000J}{1kJ}*\frac{1cal}{4.184J}[/tex]

Thus, we cancel out the kJ and J, to obtain the following result, rounded to one decimal place:

[tex]-11,902.5\frac{cal}{mmol}[/tex]

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If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is
the final volume? Assume temperature remains constant.

Answers

Answer: .039L

Explanation:

radium-223 decays with a half-life of 11.4 days, how long will it take for a 0.240-mol sample of radiuim to decay to 1.88 x 10-3 mol

Answers

The time taken for 0.240 mole sample of radiuim to decay to 1.88×10¯³ mole is 79.8 days

We'll begin by calculating the number of half-lives that has elapsed.

Original amount (N₀) = 0.240 mole

Amount remaining (N) = 1.88×10¯³ mole

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

1.88×10¯³ = 1/2ⁿ × 0.240

Cross multiply

1.88×10¯³ × 2ⁿ = 0.240

Divide both side by 1.88×10¯³

2ⁿ = 0.240 / 1.88×10¯³

2ⁿ = 128

2ⁿ = 2⁷

n = 7

Thus, 7 half-lives has elapsed

Finally, we shall determine the time.

Number of half-lives (n) = 7

Half-life (t½) = 11.4 days

Time (t) =?

t = n × t½

t = 7 × 11.4

t = 79.8 days

Therefore, the time taken for 0.240 mole sample of radiuim to decay to 1.88×10¯³ mole is 79.8 days

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Part C
Describe the shape of the graph showed in part B.
(Is it like- a normal shape??)

Answers

This graph shows a straight line.

Answer:

The graph is a straight line that angles upward.

In chemical reactions, _______ always involves the release of energy during the reaction process.

a) the breaking of bonds
b) the formation of bonds
c) the addition of a catalyst
d) overcoming activation energy

Answers

Answer:

a. the breaking of bonds

Answer:

B

Explanation:

Hey, I am almost positive that the answer to this question is B. The breaking of bonds uses the energy but when they are created it releases energy. I hope this helps, Have a good day!

What is caused by temperature differences in the mantle resulting in plate movement?



Crust

Convection Currents


Lithosphere

Answers

Answer:

Convection Currents

Explanation:

A radioactive sample has a half life of 1 hour. If you start with 1.000 gram of it at noon, how much of it remains at 4pm

Answers

The amount of the sample remaining at 4pm is 0.0625 g

We'll begin by calculating the number of half-lives that has elapsed

Half-life (t½) = 1 hour

Time (t) = 4 hour

Number of half-lives (n) =?

n = t / t½

n = 4 / 1

n = 4

Finally, we shall determine the amount the sample remaining at 4pm

Number of half-lives (n) = 4

Initial amount (N₀) = 1 g

Amount remaining (N) =?

[tex]N = \frac{N_0}{ {2}^{n}} \\ \\ N = \frac{1}{ {2}^{4}} \\ \\ N = \frac{1}{16} \\ \\ N = 0.0625 \: g[/tex]

Thus, the amount remaining at 4pm is 0.0625 g

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PLEASE HELP ME ASAP

Use the equation to answer the question.
4NaCl + 2502 +_____
H2O +______02 →______Na2SO4 + 4HCI
Which numbers balance this equation?
(1 point)
O 2, 1, 2
O 1,2,4
O 2, 1,4
o 1,2,2

Answers

Answer: O 2, 1,4

Explanation:

HELP I BEG
What are two ways the atmosphere helps protect living things?
A. It traps enough energy from the Sun to keep Earth warm.
I B. It keeps Earth cold enough that most of the water is frozen and
can't evaporate.
O C. Most meteoroids bounce off its outer layers instead of striking
Earth's surface.
OD. It contains oxygen gas and carbon dioxide gas, which living things
need.

Answers

Answer:

I would say D and A

But i might be wrong

Answer:

A and D

Explanation:

Now try marking the other guy as brainiest.

What will happen to the temperature of an object if the kinetic energy of the particles increases?

Answers

The temperature of an object will increase if the kinetic energy of the particle increases.

Kinetic energy is an energy that is said to be in motion. According to the kinetic molecular theory of ideal gas, the particles of the gas are usually moving in constant random motion and they exert no force on each other.

Also, the temperature varies directly proportional to the average kinetic energy of the gas particles. As a result, when the kinetic energy of the particles increases, the temperature will also increase.

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Why we use two different methods for detection of cogulase enzyme ? Or what other reason or what basic different between them?

Answers

I’m so sorry I hope you have a wonderful day good luck

CALCULATE the no of atoms in 0.6g of Ca ?

Answers

Explanation:

CALCULATE the no of atoms in 0.6g of Ca ?

Answer:

Explanation:

Every periodic table is rounded differently. My numbers will be approximate.

mols = 0.6 grams/ 40 grams / mol         40 is the number you need to get from the periodic table.

mols = 0.015

1 mol of anything is 6.02 * 10^23

So the formula you should use is atoms = 0.015 * 6.02 * 10^23

Answer: 9.03 * 10^21

PLS HELP ILL GIVE BRAINLIEST
Upload images that have physical and chemical properties
(six physical properties and 2 chemical properties)

Answers

Answer:

Explanation:

I hope this helps

If 5 g of sodium chloride saturates 12.5 g of water at 10 °C, what mass of sodium chloride would saturate 50 g of water at constant temperature? ​

Answers

Explanation:

since 5g saturates 12.5g of water at 10°c

so......x would saturate 50g of water at 0°c

then you can cross multiply

To what pH should you adjust a standard hydrogen electrode to get an electrode potential of -0.128 V ? (Assume that the partial pressure of hydrogen gas remains at 1 atm.) Express your answer using two decimal places.\

Answers

The pH of the standard hydrogen electrode that has electrode potential of -0.128 V  is 4.3.

The equation of the hydrogen electrode is;

2H^+(aq) + 2e ⇄ H2(g)

The standard electrode potential of hydrogen is 0.00 V

Using the Nernst equation;

Ecell = E°cell - 0.0592/n log Q

Now;

E°cell = 0.00 V

n = 2

Q = 1/[H^+]

-0.128 = 0.00 - 0.0592/2 log  1/[H^+]

-0.128 = 0.00 - 0.0296 log 1/[H^+]

 -0.128 =  - 0.0296 log 1/[H^+]

-0.128/  - 0.0296  =  log 1/[H^+]

1/[H^+] = Antilog (4.32)

[H^+] = 4.79 × 10^-5

Now;

pH = -log[H^+]

pH = -log (4.79 × 10^-5)

pH = 4.3

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PLEASE HELP!!
ATTACHMENT BELOW

Answers

Answer:

read the story

Explanation:

read it and then you will find the answer

formula of sodium bicarbonate​

Answers

Answer:

NaHCO3

Explanation:

The three is small at the bottom at the end

từ một dung dịch có pH=7 muốn tạo thành dung dịch có pH nhỏ hơn 7 thì cho vào dung dịch

Answers

Answer:

you lift my feet off the ground spin me around you make me crazier crazier

lons form because the loss of one or more electrons makes
them less stable than their corresponding atoms; this state
requires more energy to maintain.
TRUE
FALSE

Answers

This statement lons form because the loss of one or more electrons makes them less stable than their corresponding atoms; this state requires more energy to maintain is FALSE.

An ion forms when an atom loses or gains one more electrons. This loss or gain of electrons causes the ion to gain the stable octet configuration. This stable octet configuration requires less energy to maintain than the corresponding atom.

So, since the stable octet configuration of the ion requires less energy than the corresponding atom, the statement is false.

So, the statement lons form because the loss of one or more electrons makes them less stable than their corresponding atoms; this state requires more energy to maintain is FALSE.

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4
Fe
(
III
)
+
3
O
2

2
F
e
2
O
3

Answers

Answer:

230293

Explanation:

4fe(lll) + 3o2 2o2 2Fe 2O3 + 230293

The elements chlorine and iodine have similar chemical properties
because they

Answers

Answer:

They are both halogens and have the same number of electrons on their outer shell.

Any element with 7 electrons in the outermost shell will have similar properties. Thus other elements in the same column of the periodic table as chlorine will have similar properties.

If you liked my answer, please mark me brainliest!!!

2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder
whose volume is 26 0 L? (2 points)

Answers

Answer:

7.54 atm

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

[tex]P_2 = \frac{1 \times 196}{26} = \frac{196}{26} \\ = 7.538461...[/tex]

We have the final answer as

7.54 atm

Hope this helps you

What would be the freezing point of a solution that has a molality of 1.506 m which was prepared by dissolving biphenyl (C12H10) into naphthalene

Answers

The freezing point of a solution prepared by dissolving biphenyl (C12H10) into naphthalene is  67.99oC.

Freezing point can be obtained from;

ΔT = K m i

ΔT = freezing point depression

m = molality of the solution = 1.506 m

i = Van't Hoff factor = 1 for molecular substances

K = Freezing constant of naphthalene = 8.15 oC/m

ΔT = 8.15 oC/m × 1.506 m × 1 = 12.27oC

Freezing point of pure naphthalene = 80.26 °C

ΔT =  Freezing point of pure naphthalene - Freezing point of solution

Freezing point of solution =  Freezing point of pure naphthalene - ΔT

Freezing point of solution =  80.26 °C - 12.27oC = 67.99oC

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Is there more than one possible model that could be inferred from Rutherford’s data?

Answers

Rutherford's model of atoms represented the solar system. Where the positive charge is at the centre like the sun and electrons revolve around it like a planet. Therefore, his model is known as planetary model.

Rutherford proposed the nuclear model of atom. The only one model which can be inferred from this model is nucleus with protons and revolving electrons around.

What is Rutherford model?

Rutherford proposed some aspects of atomic structure based on his gold foil experiment. He discovered that the alpha ray is scattering from foil by the repulsion it experienced from the metal.

This results lead to the discovery of positively charged particles in atom latter called as protons. Rutherford proposed that theses protons are located inside the nucleus and the electrons are revolving around the nucleus.

Latter Niels Bohr his student interpreted the nuclear model of Rutherford with quantum mechanics and theory of max planck and he proposed the equations for the determination of energy and momentum of electrons and the radius of atom.

Therefore, no other inferences except the presence of protons and revolving electrons can be obtained from Rutherford's model of atom.

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