The function​ s(t) represents the position of an object at time t moving along a line. Suppose s (1 )equals 62 and s (5 )equals 102. Find the average velocity of the object over the interval of time [1 comma 5 ].

Answers

Answer 1

Answer:

v = 10

the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time

Step-by-step explanation:

Given;

function​ s(t) represents the position of an object at time t moving along a line.

s(1) = 62 at t1 = 1

s(5) = 102 at t5 = 5

Velocity v = distance/time

Average velocity v over time t is;

v = ∆s/∆t

v = [s(5) - s(1)]/[t5 - t1]

Substituting the given values;

v = (102 - 62)/(5 - 1)

v = 10

the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time


Related Questions

Suppose you have a job teaching swimming lesson and get paid $6 an hour you also have a job as a chasier and get pay $8 and hour if you cannot work more than 15 hours a week what are the number you f hours you can work at each job and still make at least $100

Answers

Answer:

  You can work no more than 10 hours teaching, and must work at least 5 hours cashiering. The remaining hours can be worked at the other job until the goal is reached.

Step-by-step explanation:

The restrictions give rise to two inequalities. If we  ...

  let x represent teaching hours

  let y represent cashiering hours

then the restrictions are ...

  x + y ≤ 15 . . . . total hours cannot exceed 15

  6x +8y ≥ 100 . . . . you want to earn at least $100

The solution set for these inequalities is a triangular area on a graph with vertices at ...

  (x, y) = (10, 5), (0, 12.5), (0, 15)

You must work at least 5 hours cashiering, and the remainder of necessary time at teaching.

After the accounts have been adjusted at December 31, the end of the fiscal year, the following balances were taken from the ledger of Pioneer Delivery Services Co.:
Kerry Buckner, Capital. $9,556,300
Kerry Buckner, Drawing 80,000
Wages Expense 1,878,400
Rent Expense 1,415,500
Supplies Expense 125,000
Fees Earned 30,600
Miscellaneous Expense 22,100
Journalize the two entries required to close the accounts.

Answers

Jhdbdhdhrkhbe’h546;&7;;$4

Which of the given shapes has a larger area?

Answers

Answer:

Rectangle

Step-by-step explanation:

Count the units. For the triangle, A=0.5bh. 0.5(4)(6)=A. A=12

Now, for the rectangle, A=bh. A=(3)(5). A=15. The rectangle is larger

The diameter of a circle is 5 ft. Find its area to the nearest tenth.

Answers

Answer:

A = 19.6 ft²

Step-by-step explanation:

A = πr²            Use this equation to find the area of the circle

A = π(2.5)²      Multiply

A = π(6.25)     Multiply

A = 19.6 ft²

Los Angeles workers have an average commute of 33 minutes. Suppose the LA commute time is normally distributed with a standard deviation of 15 minutes. Let X represent the commute time for a randomly selected LA worker. Round all answers to 4 decimal places where possible.
a. What is the distribution of X? X N
b. Find the probability that a randomly selected LA worker has a commute that is longer than 38 minutes
c. Find the 80th percentile for the commute time of LA workers. _______ minutes

Answers

Answer:

a) N(33,15).

b) 37.33% probability that a randomly selected LA worker has a commute that is longer than 38 minutes

c) 45.6 minutes.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 33, \sigma = 15[/tex]

a. What is the distribution of X?

Normal with mean 33 and standard deviaton 15. So

N(33,15).

b. Find the probability that a randomly selected LA worker has a commute that is longer than 38 minutes

This is 1 subtracted by the pvalue of Z when X = 38. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{38 - 33}{15}[/tex]

[tex]Z = 0.333[/tex]

[tex]Z = 0.333[/tex]  has a pvalue of 0.6267.

1 - 0.6267 = 0.3733

37.33% probability that a randomly selected LA worker has a commute that is longer than 38 minutes

c. Find the 80th percentile for the commute time of LA workers.

This is X when Z has a pvalue of 0.8. So it is X when Z = 0.84.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.84 = \frac{X - 33}{15}[/tex]

[tex]X - 33 = 0.84*15[/tex]

[tex]X = 45.6[/tex]

45.6 minutes.

what is the value of x?​

Answers

Answer:

solution

Step-by-step explanation:

x=5

y=4

The answer is the value of x is 5

On a piece of paper, graph fx) = 2• (0.5)*. Then determine which answer choice matches the graph you drew.

Answers

Answer:

Graph A

Step-by-step explanation:

The common ratio is less than 1, so the graph will be decreasing. The initial value is 2, so the y-intercept will be 2. Graph A fits this criteria.

I hope this helps :))

The graph A is correct.

What is a graph?

A diagram (such as a series of one or more points, lines, line segments, curves, or areas) that represents the variation of a variable in comparison with that of one or more other variables.

The equation is,

[tex]y=2(0.5)^{x}[/tex]

Plotting the graph, we get,

Option A

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Which equation does not represent a linear function of x?


a. y = -3 over 4 x
b. y = x over 2
c. y = - 3 + 2x
d. y = 3x2 - 2

Answers

The answer is b. y = x over 2

12 and 3/6 -5 and 2/12

Answers

Answer:

7.33333333333 I think. Hope this helped.

7.333333333
or 7 and 1/3

In △DEF, d = 25 in., e = 28 in., and f = 20 in. Find m∠F. Round your answer to the nearest tenth.

Answers

Answer:

  ∠F ≈ 43.9°

Step-by-step explanation:

The Law of Cosines is used to find an angle when all triangle sides are known.

  f² = d² +e² -2de·cos(F)

  cos(F) = (d² +e² -f²)/(2de) = (25² +28² -20²)/(2·25·28) = 1009/1400

  F = arccos(1009/1400)

  F ≈ 43.9°

Solve.
3^x+1 = 9^ 5x
a. x=3
b. x = 1/3
c. x=9
d. x= 1/9

Answers

Answer:

x = 1/9

Step-by-step explanation:

3^ (x+1) = 9 ^ (5x)

Replace 9 with 3^2

3^ (x+1) = 3^2 ^ (5x)

We know that a^b^c = a ^(b*c)

3^ (x+1) = 3^(2 * (5x))

3^ (x+1) = 3^(10x)

The bases are the same so the exponents are the same

x+1 = 10x

Subtract x from each side

x+1-x = 10x-x

1 = 9x

Divide each side by 9

1/9 = 9x/9

1/9 =x

The mean of 3 numbers is 4
The two numbers are 1,9
what is the missing number?

Answers

Answer:

2

Step-by-step explanation:

1+9+2 = 12

12/3= 4

Answer:2

Step-by-step explanation:9+2+1=12

So 12/3=4

ANSWER=2

Makeeya only has $25 to spend on a custom T-shirt. It costs $10 for a plain T-shirt, and there is a charge of $$1.50 for each square inch of design added to the T-shirt. Which solution represents the number of square inches of design,x , Makeeya can put on her T-shirt?

Answers

Answer:

10 square inches

Step-by-step explanation:

cost of a plain t-shirt = $10

cost of 1 square inch of design addition = $1.50

let there be x square inches of design

then cost of x square inches of design = x*cost of 1 square inch of design

                                                                 = 1.50*x = 1.5x

Total cost for t-shirt with x square inches of design = cost of a plain t-shirt + cost of x square inches of design   = 10 + 1.5 x

It is given that Makeeya has only $25, then total cost which can be afforded by him will be $25 only

Thus,

10 + 1.5 x = 25

=> 1.5x = 25-10 = 15

=> x = 15/1.5 = 10

Thus, Makeeya can  put 10 square inches of design on her T-shirt.

which rule represents the translation from the pre-image ABCD, to the image, a’b’c’d’

Answers

Answer:

Pre-image ABCD has been shifted 2 units right and 1 unit upwards.

Step-by-step explanation:

Coordinates of the points A,B,C and D of the pre-image ABCD,

A(-4, 4), B(-1, 4), C(-5, 1), D(-2,1)

Coordinates of the points A', B', C' and D' of the image A'B'C'D'.

A'(-2, 5), B'(1, 5), C'(-3, 2), D'(0, 2)

Now we choose points A from the pre-image and A' from the image,

A(-4, 4) → A'(-2, 5)

Rule for the translation will be,

A(-4, 4) → A'(-4+2, 4+1)

Or A(x, y) → A'(x+2, y+1)

Therefore, pre-image ABCD has been shifted 2 units right and 1 unit upwards to form image A'B'C'D'.

Answer: It's D

Step-by-step explanation:

the last one I just took the quiz

Help asap giving branlist!!!

Answers

Answer:

Option 2

Step-by-step explanation:

The first statement is false because the price for 10 gallons is about $37 from the graph. Using this same reasoning, the third statement is also false. The last statement doesn't make sense because the graph has nothing to do with the amount of miles driven. Therefore, the answer is the second statement. We can prove it by looking at the point (4, 15). This means that it costs $15 for 4 gallons, so then the price for one gallon will be 15 / 4 = $3.75.

What’s the correct answer for this question?

Answers

Answer: 3/20

Step-by-step explanation:

p(A)=the day selected in Monday =1/5

p(B)=student is absent

P(A∩B)=it is Monday AND a student is absent =3/100

Events A and B are independent so

P(A∩B) = P(A) · P(B)

3/100=1/5*p(B)

p(B)=3/20

Thw sum of 12x^2+9x^2

Answers

Answer:

21 x^2

Step-by-step explanation:

12x^2+9x^2

Combine like terms

x^2(12+9)

x^2(21)

21 x^2

​Jan's All You Can Eat Restaurant charges ​$9.10 per customer to eat at the restaurant. Restaurant management finds that its expense per​ customer, based on how much the customer eats and the expense of​ labor, has a distribution that is skewed to the right with a mean of ​$8.10 and a standard deviation of ​$4.
A. If the 100 customers on a day have the characteristics of the random sample from their customer base, find the mean and standard error of the sampling distribution of the restaurant's sample mean expense per customer.
B. Find the probability that the restaurant makes a profit that day, with the sample mean expense being
less than $8.95.

Answers

Answer:

Step-by-step explanation:

From the given question;

Given that:

Jan's All You Can Eat Restaurant charges ​$9.10 per customer to eat at the restaurant.

Distribution  is skewed and and has a mean of $8.10 and a standard deviation of ​$4.

A.  If the 100 customers on a day have the characteristics of the random sample from their customer base, find the mean and standard error of the sampling distribution of the restaurant's sample mean expense per customer.

the mean by using the central limit theorem is 8.10

the standard error of the sampling distribution  = [tex]\dfrac{\sigma}{\sqrt{n}}[/tex]

the standard error of the sampling distribution = [tex]\dfrac{4}{\sqrt{100}}[/tex]

= 4/10

= 0.4

B.  

P(X > $8.95) = P (Z > 8.95 - 8.10/0.4)

P(X > $8.95) = P (Z > 2.1)

P(X > $8.95) = 1 - P (Z < 2.1)

P(X > $8.95) = 1 - 0.9821

P(X > $8.95) = 0.0179

Help me, please ?? :)

Answers

Answer:

  a) 11

  b) 16

  c) between 5 and 6

  d) 16

Step-by-step explanation:

[tex]\text{a. }\quad\sqrt{121}=\sqrt{11^2}=\boxed{11}\\\\\text{b. }\quad 8\sqrt{4}=8\sqrt{2^2}=8\cdot 2=\boxed{16}\\\\\text{c. }\quad\sqrt{35}\ \dots\ \sqrt{25}<\sqrt{35}<\sqrt{36}\\\\\text{ }\qquad\sqrt{5^2}<\sqrt{35}<\sqrt{6^2}\\\\\text{ }\qquad \boxed{5<\sqrt{35}<6}\\\\\text{d. }\quad\dfrac{.8}{.05}=\dfrac{0.80\cdot 20}{.05\cdot 20}=\dfrac{16}{1}=\boxed{16}[/tex]

Simplify the following expression:
-5[(x^3 + 1)(x + 4)]​

Answers

Answer:

[tex]-5x^{4} -20x^{3} -5x-20[/tex]

Step-by-step explanation:

[tex]-5[(x^{3} +1)(x+4)][/tex]

Use the FOIL method for the last two groups.

[tex]-5(x^{4} +4x^{3} +x+4)[/tex]

Now, distribute the -5 into each term.

[tex]-5x^{4} -20x^{3} -5x-20[/tex]

Please give answer with explanation of formula. Please reply fast I have exam.

Answers

Answer:

D

Step-by-step explanation:

3/40 * 2.5/2.5 = 7.5/100 = 0.075

liam is a tyre fitter it takes him 56 minutes to fit 4 tyres to a van

Answers

Answer:

Step-by-step explanation:

I am not really sure because u did not finish the question but is u are asking how much time it takes to fit one tyre:

answer is time/tyres

56min./4

14 min. Per type

Which answer is equivalent to the equation shown below?
7c = 49
A.log7 c = 49
B.c = log49 7
C.logc49 = 7
D.c = log7 49

Answers

Answer:

D.

Step-by-step explanation:

The base of a log is also the base of an exponent. So 7 to the c power, our 7 would be the base. To find c, we simply just do log base 7 of 49, which comes out to be 2.

Answer: D
Hope this helped

Two samples are randomly selected from each population. The sample statistics are given below.
n1 = 150 n2 = 275
x1 = 72.86 -x2 = 67.34
s1 = 15.98 s2 = 35.67
The value of the standardized test statistic to test the claim that μ1 > μ2 is _________.
-2.19
2.19
3.15
-3.15

Answers

Answer:

Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]

Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]

The statistic is given by:

[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]

And replacing we got:

[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]

And the best option would be:

2.19

Step-by-step explanation:

We have the following info given:

n1 = 150 n2 = 275

[tex]\bar x_1 = 72.86, \bar x_2 = 67.34[/tex]

s1 = 15.98 s2 = 35.67

We want to test the following hypothesis:

Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]

Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]

The statistic is given by:

[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]

And replacing we got:

[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]

And the best option would be:

2.19

• Write this number as a fraction:178.25​

Answers

Answer: 178 1/4 or 713/4

Step-by-step explanation:

178.25 = 178+0.25 = 178+25/100

gcd(25,100) = 25

178.25 = 178+(25/25)/(100/25) = 178+1/4 = 713/4

178.25 as a fraction is 178 1/4 or 713/4

What is the equation of the following line? Be sure to scroll down first to see all answer options.(0,0)(4,-2)

Answers

Answer:

i hope this helps you

The Equation of the line is 2y = -x.

What is the equation of a line passing through two given points in 2 dimensional plane?

Suppose the given points are (x_1, y_1) and (x_2, y_2), then the equation of the straight line joining both two points is given by

[tex](y - y_1) = \dfrac{y_2 - y_1}{x_2 - x_1} (x -x_1)[/tex]

Given Points of the line are (0,0) and (4,-2).

Since we are given two points.

[tex](y - y_1) = \dfrac{y_2 - y_1}{x_2 - x_1} (x -x_1)\\\\\\(y - (-2)) = \dfrac{-2- 0}{4 - 0} (x -4)\\\\\\(y - (-2)) = \dfrac{-1}{2} (x -4)\\\\2(y + 2) =-1(x -4)\\\\2y + 4 = -x + 4\\\\2y = -x\\\\[/tex]

Therefore, Equation of the line is 2y = -x.

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Find the value of y when equals zero. -7x+3y=30

Answers

Answer:

x = -30/7

Step-by-step explanation:

-7x+3y=30

Let y=0

-7x +0 = 30

Divide by -7

-7x /-7 = 30/-7

x = -30/7

Answer:

[tex]-\frac{30}{7}[/tex]

Step-by-step explanation:

y equals zero => y = 0

-7x+3y=30

-7x +3.0 = 30

-7x + 0 = 30

-7x = 30

-7x/-7 = 30/-7

x = -30/7

Hope this helps ^-^

Use Greens Theorem to evaluate integral x^2ydx - xy^2dy, where C is 0 ≤ y ≤ √9-x^2 with counterclockwise orientation

Answers

Answer:

Step-by-step explanation:

a circle will satisfy the conditions of Green's Theorem since it is closed and simple.

Let's identify P and Q from the integral

[tex]P=x^2 y[/tex], and [tex]Q= xy^2[/tex]

Now, using Green's theorem on the line integral gives,

[tex]\oint\limits_C {x^2ydx-xy^2dy } =\iint\limits_D {y^2-x^2} \, dA\\\\[/tex]

Please answer this correctly

Answers

Answer:

174

Step-by-step explanation:

l x w

5x20

8x4

6x7

174

A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 5% of the employees suffered lost-time accidents last year. Management believes that a special safety program will reduce such accidents to 4% during the current year. In addition, it estimates that 15% of employees who had lost-time accidents last year will experience a lost-time accident during the current year. a. What percentage of the employee will experience a lost-time accident in both years (to 1 decimal)?

Answers

Answer:

The percentage of the employee will experience a lost-time accident in both years is 0.0%

Step-by-step explanation:

Let A denote events that employees suffered lost-time accidents during the last year

Let B denote events that employees suffered lost-time accidents during the current year

P(A) = 5% = 0.05

P(B) = 4% = 0.04

P(B | A) = 15% = 0.15

(a) P (A ∩ B) = P(B | A) × P(A)

= 0.15 × 0.05

= 0.0075

= 0.0 (1 decimal place)

The probability that an employee will experience a lost- time accident in both years is 0.0

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