The graph of the function f(x) = (x-3)(x + 1) is shown.
-10-8-6
q
10-

Which describes all of the values for which the graph is
positive and decreasing?
all real values of x where x < -1
all real values of x where x < 1
all real values of x where 1 O all real values of x where x > 3

We need to prove

[tex]\frac{\tan A+\sin A}{\tan A-\sin A}=\frac{\sec A+1}{\sec A-1}[/tex]

[tex]\text{LHS}=\frac{\tan A+\sin A}{\tan A-\sin A}\\\\=\frac{\frac{\sin A}{\cos A}+\sin A}{\frac{\sin A}{\cos A}-\sin A}\\\\=\frac{\sin A+\sin A \cos A}{\sin A-\sin A \cos A}\\\\=\frac{\sin A(1+\cos A)}{\sin A(1-\cos A)}\\\\=\frac{1+\cos A}{1-\cos A}\\\\=\frac{1+\frac{1}{\sec A}}{1-\frac{1}{\sec A}}\\\\=\frac{\sec A+1}{\sec A-1}\\\\ =\text{RHS}[/tex]

Answer:

I think it's C. transitive property of equality

Answer:

search it up ok that's all you can do

Answer:

x = 3

TU = 35

UV = 35

TV = 70

Step-by-step explanation:

As U is the midpoint of TV:

⇒ TU = UV

⇒ 8x + 11 = 12x - 1

⇒ 8x + 11 - 11 = 12x - 1 - 11

⇒ 8x = 12x - 12

⇒ 8x - 12x = 12x - 12 - 12x

⇒ -4x = -12

⇒ -4x ÷ -4 = -12 ÷ -4

⇒ x = 3

Substitute the found value of x into the expression for TU:

⇒ TU = 8x + 11

⇒ TU = 8(3) + 11

⇒ TU = 24 + 11

⇒ TU = 35

Using the transitive property of equality:

As UV = TU and TU = 15 then UV = 35

Using the segment addition postulate:

⇒ TV = TU + UV

⇒ TV = 35 + 35

⇒ TV = 70

Hence

Answer:

175000 km

Step-by-step explanation:

the 1:25000 essentially means that every centimeter represents 25000 kilometers. so the answer is 175000 by multiplying 7 and 25000

Answer:

[tex]\log_8{(3)} + \log_8{(7)}[/tex]

Step-by-step explanation:

Product Rule for Logarithms

[tex]\log_b{(mn)} = \log_b{(m)} + \log_b{(n)}[/tex]

Instead of 21 you can write 3 · 7, because 21 = 3 · 7.

[tex]\log_8{(21)} = \\= \log_8{(3 \cdot 7)} =\\= \log_8{(3)} + \log_8{(7)}[/tex]

Answer: 35.675

Step-by-step explanation:

10.465−(−25.21)

The opposite of −25.21 is 25.21.

10.465+25.21

Add 10.465 and 25.21 to get 35.675.

35.675

Given the polynomial f(x)=x³+5x²+2x-8 and f(1)=0.

Factorization is the process of determining the components of a given value or mathematical statement. The integers that are multiplied to create the original number are known as factors. The components of 18 include, for instance, 2, 3, 6, 9, and 18, as well as;

18 = 2 x 9

18 = 2 x 3 x 3

18 = 3 x 6

In a similar way, the factors in the case of polynomials are the polynomials that are multiplied to create the original polynomial. For instance, (x + 2) (x + 3) are the elements of x2 + 5x + 6. The original polynomial is produced when we multiply both x +2 and x +3. We can also locate the polynomials' zeros after factorization. Zeroes in this situation are x = -2 and x = -3.

2. Now, to write f(x) as the product of (x-1) and another factor.

x³+5x²+2x-8 = (x-1)(x²-6x+8).

3. Now, to write f(x) as the product of three linear factors.

x³+5x²+2x-8 = (x-1)(x²-6x+8)= (x-1)(x-4)(x-2)

4. Look at the sketch below.

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Answer:

c is the answer.

Answer:

x<2 or x ≥ 15/2

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

the range of y=|x| is not all real numbers its [0,inf)

sign - ...

Zekrom

Step-by-step explanation:

well you can distribute the sqrt(15x) to the (√3x + √5) and then combine the radicals using the product property of radicals: [tex]\sqrt[n]{a} * \sqrt[n]{b} = \sqrt[n]{ab}[/tex].

[tex](\sqrt{3x} + \sqrt{5})\sqrt{15x} + 2\sqrt{30}\\(\sqrt{3x} * \sqrt{15x}) + (\sqrt{5} * \sqrt{15x}) + 2\sqrt{30}\\\sqrt{45x^2} + \sqrt{75x} + 2\sqrt{30}\\[/tex]

Now we can simplify the radicals using the same property we used to combine them but instead of combining into one radical we'll separate them into two radicals where one of the radicals simplifies into a number without a radical

[tex](\sqrt{9} * \sqrt{x^2} * \sqrt{5}) + (\sqrt{25} * \sqrt{3x}) + 2\sqrt{30}\\3x\sqrt{5} + 5\sqrt{3x} + 2\sqrt{30}[/tex]

Answer:

is it 1 ques or 4 different questions?

Answer:

Should have ended with "at most -15, not "at least -15."

Step-by-step explanation:

[tex]\leq[/tex] -15 means less than or equal to -15

So it can be -15, but also anything less than -15.  The phrase "at most -15, not "at least -15" says exactly that.

Answer:

B. (4,2)

Step-by-step explanation:

The answer is where the lines intersect.

Hope this helps!

If not, I am sorry.

Answer:

(4,2)

Step-by-step explanation:

the solution is where both lines intersect. We would write the point as (x,y). That’s why the answer is (4,2) not (2,4)

The inequality is 100*[tex]3^{t}[/tex]≤ 656100.

The correct option is (B).

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Given:

From the table attached below:

a=300, r= 900/300 = 3

As, it is GP

Now,

f(t) = [tex]ar^{t-1}[/tex]

f(t) = [tex]300*3^{t-1}[/tex]

f(t) = 300/3 *[tex]3^{t}[/tex]

f(t) = 100*[tex]3^{t}[/tex]

Inequality is used to determine greater than or equal to 656100

100*[tex]3^{t}[/tex]≤ 656100

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If Bruce can deduct 40% from other interest then the total interest deducted is $2927.

Given Adjusted gross income=$36500, mortgage interest =$2787 and other interest $350.

It is said that 40% of other interest can be deducted by Bruce but it is not said that nothing will be deducted by Bruce from Mortgage interest so we will deduct full of mortgage interest and 40% of other interest. So,

Mortgage interest =$2787

Other interest=$350

Other interest deductable=40%*350

=$140

So the total will be 2787+140 =$2927.

Hence the interest deducted by Bruce is $2927if only 40% of  other interest is deductable.

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The function g(x) = ∛(x -3) is positive at the interval x > 3

Given g(x) = ∛(x -3), on what interval is the function positive?

The function is given as:

g(x) = ∛(x -3)

Set the radicand to positive

x - 3 > 0

Add 3 to both sides

x > 3

Hence, the function is positive at the interval x > 3

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Answer:

14 will be the answer...

Step-by-step explanation:

6 13/28 = 6

8 3/32 = 8

6 + 8 = 14

The midpoint of the class interval 80-89 is 84.5.

The mid point of a class interval is also called the class mark of the class interval.

The midpoint is defined as the average of the upper and lower class limits.

Therefore, the midpoint of the class interval 80-89 can be calculated as follows:

mid point = 80 + 89 / 2

mid point = 169 / 2

mid point = 84.5

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Answer:

You have not added a picture soi can not help answer this question.

Step-by-step explanation:

Add the picture by either taking a photo or screenshot of the question then upload it.

Answer:

The answer is 10/143

Step-by-step explanation:

Step-by-step explanation:

please mark me as brainlest

Answer:

-92/35

Step-by-step explanation:

-3 + 4/7 - 1/5 =

-21/7 + 4/7 - 1/5 =

-(21*5) / (7*5) + (4*5)/(7*5) - (1*7)/(5*7) =

-105/35 + 20/35 - 7/35 =

-105+20-7 / 35 = -92/35

∠ROQ and ∠TOS are vertically opposite angles, so must be equal, which means they are 122°

The coordinates for the center and length of the radius of this circle are equal to (½, 1), 2 units.

Mathematically, the standard form of the equation of a circle is given by;

(x - h)² + (y - k)² = r²

Where:

In order to determine the coordinates for the center and the length of the radius of this circle, we would use completing the square method:

x² + y² - x - 2y - 11/4 = 0

x² - x + ¼ + y² - 2y = 11/4 + ¼

(x - ½)² + y² - 2y + 1 = 12/4 + 1

(x - ½)² + (y - 1)² = 4

Comparing with the standard form, we have:

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Complete Question:

A circle is defined by the equation given below.

x^2 + y^2 − x − 2y − 11/4 = 0

What are the coordinates for the center of the circle and the length of the radius?

Answer:

the angles of a triangle always equal 180 so

34+x-5+4y=180

simplify

29+x+4y=180

-29

x+4y=151

-4y

x=-4y+151

then put this into the original equation

29-4y+151+4y=180

simplify

29+151=180

so this proves that this works

-1/4x-151=y

Hope This Helps!!!

Answer: Coordinates: (1,3) length RS: 3 length RT: 2 ST: 3.6

Step-by-step explanation:

a^2+b^2=c^2

3^2+2^2=c^2

9+4=c^2

13=c^2

3.6=c

The solutions to the trigonometric equation in the desired interval are given as follows:

[tex]\theta = \frac{\pi}{3}, \theta = \frac{5\pi}{3}[/tex]

The trigonometric equation is given by:

[tex]\sqrt{3}\cot{\theta} - 1 = 0[/tex]

Solving it similarly to an equation, we have that:

[tex]\sqrt{3}\cot{\theta} = 1[/tex]

[tex]\cot{\theta} = \frac{1}{\sqrt{3}}[/tex]

Since [tex]\cot{\theta} = \frac{1}{\tan{\theta}}[/tex], we have that the equation is equivalent to:

[tex]\tan{\theta} = \sqrt{3}[/tex]

The tangent is positive in the first and in the fourth quadrant. In the first quadrant, the angle [tex]\theta[/tex] with [tex]\tan{\theta} = \sqrt{3}[/tex] is:

[tex]\theta = \frac{\pi}{3}[/tex]

In the fourth quadrant, the equivalent angle is:

[tex]\theta = 2\pi - \frac{\pi}{3} = \frac{5\pi}{3}[/tex]

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