The graph shows a relationship between x and y.
What are the zeros of the function?

The value of the composite function f(g(x)) is 2(x-8)^2

Composite functions are functions in another function. Given the following functions

f(x)=2x^2 and

g(x)=x-8

Determine f(g(x))

f(g(x)) = f(x-8)

f(x-8) = 2(x-8)^2

f(g(x)) = 2(x-8)^2

Hence the value of the composite function f(g(x)) is 2(x-8)^2

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Answer:

-2(10(-4))²

-2(-40)²

-2 × 1600

= -3200

Answer: = -3200

Step-by-step explanation:

took the test

Answer:

4 kg

Step-by-step explanation:

........................

Answer:

4 kg

Explanation:

Let the mass of tank be 't' and water 'w'

First equation :              (when it is 1/4 filled with water)

Second equation :        (when it is filled fully with water)

Insert second equation into first equation :

[tex]\rightarrow \sf t + \dfrac{1}{4} (10.4 - t) = 5.6[/tex]

[tex]\rightarrow \sf t - \dfrac{1}{4} t + 2.6 = 5.6[/tex]

[tex]\rightarrow \sf \dfrac{3}{4} t = 5.6 - 2.6[/tex]

[tex]\rightarrow \sf \dfrac{3}{4} t = 3[/tex]

[tex]\rightarrow \sf t = 4[/tex]

The tank weights 4 kg when it is empty.

The area of Maria’s circle is 18π square units option fourth is correct.

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

The figure is missing.

Please refer to the attached picture for the figure.

We have given the radius of the circle as 3 units

r = 3 units

Area of circle = πr² = π(3)² = 9π square units

The area of Maria’s circle = 2(9π) = 18π square units

Thus, the area of Maria’s circle is 18π square units option fourth is correct.

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Answer:

Answers are 20, 12 and 16

Step-by-step explanation:

Y=4x

for x = 5

y=4(5)

y=20

for x = 3

y=4(3)

y=12

for x = 4

y=4(4)

y=16

Answer:

X I Y

5 20

3 12

4 16

Step-by-step explanation:

since y=4 multiplied by x

so, 5x4=20

3x4=12

4x4=16

Answer:

219,221

Step-by-step explanation:

the second number can be represented by the equation n1+2=n2

adding these expressions together you get

(n+2)+n=440

youre going to think of n now as just your first number because the equation solves for n1

with that you will get a number valued at 219

you then solve the first equation n1+2=n2 because we now know the value of n1

219+2=221

so the second numbers value is 221

The trigonometry ratios are cos(θ) = -7/√58, sec(θ) = -√58/7 and cot(θ) = -7/3

The point on the terminal side is given as:

(x, y) = (-7, 3)

Start by calculating the hypotenuse using:

[tex]h= \sqrt{x^2 + y^2[/tex]

So, we have:

[tex]h= \sqrt{(-7)^2 + 3^2[/tex]

Evaluate

[tex]h= \sqrt{58[/tex]

The cosine is then calculated using:

cos(θ) = x/h

This gives

cos(θ) = -7/√58

The secant is then calculated using:

sec(θ) = 1/cos(θ)

This gives

sec(θ) = -√58/7

The cotangent is then calculated using:

cot(θ) = cos(θ)/sin(θ)

Where

sin(θ) = y/h

So, we have:

sin(θ) = 3/√58

So, we have:

cot(θ) = (-7/√58)/(3/√58)

This gives

cot(θ) = -7/3

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Let's prove that (sec x)(csc x) is equal to cot x + tan x

[tex]\Longrightarrow \sf (sec(x) )(csc(x))[/tex]

[tex]\Longrightarrow \sf \dfrac{1}{\cos \left(x\right)\sin \left(x\right)}[/tex]

[tex]\Longrightarrow \sf \dfrac{\cos ^2\left(x\right)+\sin ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)}[/tex]

[tex]\Longrightarrow \sf \dfrac{\cos ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)} + \dfrac{\sin ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)}[/tex]

[tex]\Longrightarrow \sf \dfrac{\cos\left(x\right)}{\sin \left(x\right)} + \dfrac{\sin \left(x\right)}{\cos \left(x\right)}[/tex]

[tex]\Longrightarrow \sf cot(x) + tan(x)[/tex]

Hence student A did correctly prove the identity properly.

Also Looking at student B's work, he verified the identity properly.

So, Both are correct in their own way.

Identities used:

[tex]\rightarrow \sf sin^2 (x) + cos^2 (x) = 1[/tex]       (appeared in step 3)

[tex]\sf \rightarrow \dfrac{cos(x) }{sin(x) } = cot(x)[/tex]               (appeared in step 6)

[tex]\rightarrow \sf \dfrac{sin(x )}{cos(x) } = tan(x)[/tex]               (appeared in step 6)

Answer:

[tex] \cfrac{61}{24} [/tex]

Step-by-step explanation:

Given expression:

[tex] \cfrac{2}{3} + \bigg(\cfrac{5}{2} \bigg) {} ^{ 2} \times \cfrac{3}{10} [/tex]

Solution:

Simplify using PEMDAS.

[tex] = \sf \cfrac{2}{3} + \cfrac{25}{4} \times \cfrac{3}{10} \\ \\ = \cfrac{2}{3} + \cfrac{15}{8} \\ \\ = \cfrac{16 +45 }{24} \\ \\ = \boxed{\cfrac{61}{24} }[/tex]

Done!

Answer:

[tex]\frac{61}{24}[/tex]

Step-by-step explanation:

[tex]\frac{2}{3}[/tex] + ( [tex]\frac{5}{2}[/tex] )² × [tex]\frac{3}{10}[/tex] ← evaluate exponent

= [tex]\frac{2}{3}[/tex] + [tex]\frac{25}{4}[/tex] × [tex]\frac{3}{10}[/tex] ← evaluate multiplication ( cancel 25 and 10 by 5 )

= [tex]\frac{2}{3}[/tex] + [tex]\frac{5}{4}[/tex] × [tex]\frac{3}{2}[/tex]

= [tex]\frac{2}{3}[/tex] + [tex]\frac{15}{8}[/tex] ← evaluate addition

= [tex]\frac{2(8)}{3(8)}[/tex] + [tex]\frac{15(3)}{8(3)}[/tex]

= [tex]\frac{16}{24}[/tex] + [tex]\frac{45}{24}[/tex]

= [tex]\frac{61}{24}[/tex]

The asnwer is C

for finding domain look at just x-axis from left to right , because there are arrows , so domain is all real numbers or from negative infinity to positive infinity

Please give brainliest

The composite function is given as follows:

[tex](f \circ g)(x) = \frac{2x + 6}{3x + 22}[/tex]

The domain of the composite function is: [tex]\mathbb{R} - \left\{-\frac{22}{3}, 3\right\}[/tex]

The composite function is given by:

[tex](f \circ g)(x) = f(g(x))[/tex]

In this problem, the functions are:

Hence the composite function is:

[tex](f \circ g)(x) = f\left(\frac{13}{x + 3}\right) = \frac{2}{\frac{13}{x + 3} + 3} = \frac{2(x + 3)}{13 + 3(x + 3)} = \frac{2x + 6}{3x + 22}[/tex]

For the domain, we have to remove the points outside the domain of both the primitive and the composite functions, that is, the zeroes of the denominators, hence:

[tex]x + 3 \neq 0 \rightarrow x \neq 3[/tex]

[tex]3x + 22 \neq 0 \rightarrow x \neq -\frac{22}{3}[/tex]

Hence the domain is:

[tex]\mathbb{R} - \left\{-\frac{22}{3}, 3\right\}[/tex]

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Answer:

∠a = 50°

∠b = 130°

∠c = 130°

Explanation:

Following Vertical Angles Theorem:

A straight line has 180° angle measure, ∠c and ∠a lies on a straight line

Also, following vertical angle theorem:

The expression are; [tex](h - g) (x) = 3x^{3} -x^{2}[/tex], [tex](h + g) (x) = 3x^{3} +x^{2}[/tex] , [tex](h.g) (-1) = -3[/tex].

The function is a type of relation, or rule, that maps one input to specific single output.

Given function;

g(x) = [tex]x^{2}[/tex]

h(x) = [tex]3x^{3}[/tex]

The expression;

[tex](h - g) (x) = 3x^{3} -x^{2}[/tex]

[tex](h + g) (x) = 3x^{3} +x^{2}[/tex]

[tex](h.g) (-1) = x^{2} .3x^{3} \\\\(h.g) (-1) = 3x^5\\\\(h.g) (-1) = 3(-1)^5\\\\(h.g) (-1) = -3[/tex]

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Answer:

x-23=.55

Step-by-step explanation:

Answer: 0.55 = x - 23

Step-by-step explanation:

let his savings = x

We have that O(n²) is the theta notation for 7n² + 4n + 2.

Let's give big-Oh a formal definition:

O(g(n)) = {the set of all f such that 0 [tex]\leq[/tex] f(n) [tex]\leq[/tex] cg(n) for any n >= n₀ fulfilling positive constants c and n₀}

To show this

We need to find c and n₀ such that:

7n² + 4n + 2 <= cn² for all n >= n₀ .

Divide both sides by n², getting:

7 + 4/n + 2/(n²) <= c for all n >= n₀ .

If we choose n₀ equal to 1, then we need a value of c such that:

7 + 4 + 2 <= c

We can set c equal to 13. Now we have:

7n² + 4n + 2 <= 13n² for all n >= 1 .

Hence, 7n² + 4n + 2=O(n²)

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The total distance travelled is 1075.91 km.

The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity.

45 * (x +12)= 50* 1/5 + 1/2 *x

45x + 540= 10+ 0.5 x

44.5 x = 530

x= 11.91 (neglect the negative sign cause time can't be negative)

So, distance= 45* 23.91 = 1075.91 Km

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Answer:

3

Step-by-step explanation:

374274 =3.74274 x 100000=3.74272x 10^5

The parabola is a downward parabola which is passing through origin and leading coefficient of the negative 2.

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

The equation of a quadratic function, of vertex (h, k), is given by:

y = a(x – h)² + k

where a is the leading coefficient.

The equation of the parabola will be

y = -x²

The given parabola is a downward parabola which is passing through origin and leading coefficient of the negative 2.

The graph of the function is given below.

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Answer: 10

Step-by-step explanation:

The sum of the roots is [tex](5+3i)+(5-3i)=10[/tex], so the answer is 10

Answer:

5. 540°

Step-by-step explanation:

m<a + m<c = 180°

m<h + m<f = 180°

m<k + m<m = 180°

Then m<a + m<c + m<h + m<f + m<k + m<m = 180° x 3 = 540°

Answer:

jjjijijijiiijijijijijijij no pliss inglés. ;D.

The second derivative of the first function is s"(x) = = -[8e^(x/5) - 2]e^(x/5)/25(e^(x/5) + 2)³.

The second derivative of the second function is; k''(t) = (36t² - 6)e^(-3t²)

1)  We are given the function;

s(x) = 4/(1 + 2e^(-0.2x)

First derivative is;

ds/dx = [8e^(x/5)]/5(e^(x/5) + 2)²

Second Derivative is;

d²s/dx² = -[8e^(x/5) - 2]e^(x/5)/25(e^(x/5) + 2)³

At x = 0;

d²s/dx² = -[8e^(0/5) - 2]e^(0/5)/25(e^(0/5) + 2)³

d²s/dx² = 8/675

B) We are given the function;

k(t) = e^(-3t²)

The first derivative is;

dk/dt = -6te^(-3t²)

The second derivative is;

k''(t) = (36t² - 6)e^(-3t²)

At t = 1, we have;

k''(t) = (36(1)² - 6)e^(-3(1²))

k"(t) = 1.494

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Caden needs to grow 4 inches tall enough to ride the Super Slide.

Multiplication or division by a numerical factor, selection of the correct number of significant figures, and unit conversion are all steps in a multi-step procedure.

Given that:-

Caden's height = 4 feet

Min height to ride the Super slide is = 52 inches

Caden's height in inches will be:-

1 feet = 12 inches

4 feet = 12 x 4 = 48 inches.

The difference between the height will be given as:-

D = 50 - 48 = 4 inches

So Caden should grow his height by 4 inches to ride the super slide.

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The missing value of x will be 9.6 mL.

A ratio is a collection of ordered integers a and b represented as a/b, with b never equaling zero. A proportionate expression is one in which two items are equal.

The equation is given below.

12.5 mg : 5 mL = 24 mg : x mL

Then the value of x will be

12.5 / 5 = 24 / x

          x = (24 × 5) / 12.5

          x = 9.6 mL

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Step-by-step explanation:

On a polar plane, the shape will be a line that goes through the pi/2- pi quadrant , and 3pi/2- 2pi quadrant

On a Cartesian or rectangular plane, the shape will be a line as well passing through 2nd and 4th quadrant

Answer:

56

Step-by-step explanation:

all your doing is removing the .053 to get your whole number