The histogram to the right represents the weights​ (in pounds) of members of a certain​ high-school debate team. What is the class​ width? What are the approximate lower and upper class limits of the first​ class? The class width is_______.

Answer: D

Step-by-step explanation:

In order to increase each ticket by $2, you are ADDING 2 to each value.

So you create a matrix of all 2's and add that to the given matrix.

[tex]\left[\begin{array}{cc}2&2\\2&2\\2&2\end{array}\right] +\left[\begin{array}{cc}8&10\\12&16\\6&8\end{array}\right]\quad =\quad \large \left[\begin{array}{cc}10&12\\14&18\\8&10\end{array}\right][/tex]

Answer:

Unit 8 test answers

Step-by-step explanation:

1: a.)3x4

2:b.)

3:a.)

4:b.)

5:c.) matrix CD would have the dimensions 7x7

6: a.)

7:67

8:c.)

9:b.) Scott sold 1 van

10:d.)

Answer:

They are all multiplied by 6

Answer:

Geometric sequence.

Step-by-step explanation:

Here are the terms :

-2/3, -4, -24, -144

Now the first term T1 = -2/3

The second Term T2 = -4

But T2/T1 = -4÷ -2/3 = -4 x -3/2 = 6

Similarly Term 3, T3 = -24

T3/T2 = -24/-4= 6

Hence the expression is a geometric sequence.

a×r^(n-1); a is the first term

r is the common ratio 6

n is the number of terms.

Answer:

(1)  f(x,y) = 1-|x|-|y|

(a) 3d figure attached

(b) 2d figure attached

(2) f(x,y) = 6-2x-3y

(a) 3d figure attached

(b) 2d figure attached

Step-by-step explanation:

The Function is not given in the question. Lets solve this for 2 common function for the internet. Hopefully it can solves the given problem

(1)  f(x,y) = 1-|x|-|y|

(2) f(x,y) = 6-2x-3y

All the figures are labelled to avoid confusion. (a) part of both functions have 3D sketches. (b) part of both functions have 2d sketches

Answer:

B. Cluster

Step-by-step explanation:

Samples may be classified as:

Random: Basically, put all the options into a hat and drawn some of them.

Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.

Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.

Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.

In this question:

Each Continental Airlines flight is a group.

30 of them are chosen, and in each group chosen, every passenger is surveyed.

So cluster sampling was used.

Answer:

The answer is 8300.

Step-by-step explanation:

1) We round the number up to the nearest hundred, if the last two digits in the number are 50 or above.

2) We round the number down to the nearest 100 if the last two digits in the number are 49 or below.

3) If the last two digits are 00, then we do not have to do any rounding because it is already to the hundred.

Answer:24600 , 16400

Step-by-step explanation:

Let the first part be x

So, second part will be 41000 - x

For amount x

SI = prt / 100

SI = x * 0.50 * 2

SI = 1x

For amount 41000 - x

SI = (41000-x) * 0.50 * 3

SI = 61500 - 1.5x

1x = 61500 - 1.5x

1.5x + x = 61500

2.5x = 61500

x = 61500 / 2.50 = 24600 for 2 years

2nd part = 41000 - 24600 = 16400 for three years

Answer:

look to rule number five

Step-by-step explanation:

Rule Number 5 best explains the answer

A = 14 m^2

Step-by-step explanation:

The equation for the area of a triangle is...

[tex]A=\frac{1}{2}bh[/tex]

For this we need the base and the height. Looking at the picture, we can see that the height is 4. The base is split into 2 parts, so we just need to add the 3 and the 4 together, that will make our base 7. Now we can plug these into the equation, but I'm also just going to make the 1/2 a 0.5.

[tex]A=0.5*4*7[/tex]

[tex]A=[/tex]

14 m^2

Answer:

B:

Step-by-step explanation:

If we rotate the 3-D figure around y-axis we'll obtain a cone with a radius of 3 units

Answer:

y = -3/5 x +3

Step-by-step explanation:

3x + 5y = 15

Subtract 3x from each side

-3x+3x + 5y = -3x+15

5y = -3x+15

Divide each side by 5

5y/5 = -3x/5 +15/5

y = -3/5 x +3

Answer:

Classifications would include

Rational; Fraction; Can be turned into Decimal; Positive

Those would be classifications

Answer: rational number, 0.375

Step-by-step explanation:

The probability that it also rained that day would be 0.30

Answer:

  see the attachment

Step-by-step explanation:

A "line of best fit" generally has about as much data above the line as below it. If the data has any trend, it generally follows the trend.

The best choice here is B.

Answer:Answer:

 see the attachment

Step-by-step explanation:

A "line of best fit" generally has about as much data above the line as below it. If the data has any trend, it generally follows the trend.

The best choice here is B.

Step-by-step explanation:

Answer:

Relative frequency:

[tex]\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\[/tex]

The most serious threat to aviation safety is, according to this data, "mechanical failures". It can be improved by more rigorous inspection and better maintenance policies and execution.

Step-by-step explanation:

We have the data for fatal plane crashes. The sum of plane crashes is

We can calculate the relative frequency as:

[tex]\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\[/tex]

We can see that the most frequent cause is "mechanical problems", with a relative frequency of 0.45.

Answer: 90/pi degrees

Step-by-step explanation:

It forms a 15cm arc from a circle of radius 30 cm.

The diameter is 30*2*pi = 60pi cm. So the arc is 15/60pi = 1/4pi of the way around a 360 degree circle. This is 1/4pi * 360 = 90/pi degrees.

Hope that helped,

-sirswagger21

The pendulum will swing 28.68° if the 30-cm pendulum traverses an arc of 15 cm.

It is defined as the combination of points that, and every point has an equal distance from a fixed point (called the center of a circle).

We know that relationship between arc length s and central angle θ:

s = rθ

Where r is the radius of the circle

We have s = 15 cm

r = 30 cm

15 = (30)(θ)

θ = 0.5 radians

To convert it to a degree, multiply it by 180/π

θ = 0.5(180/π)

θ = 28.647 ≈ 28.68°

Thus, the pendulum will swing 28.68° if the 30-cm pendulum traverses an arc of 15 cm.

Learn more about circle here:

brainly.com/question/11833983

#SPJ2

Answer:

The 7 is in the hundredths place.

The 3 is in the ones place.

3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).

Step-by-step explanation:

Given the number 3.872, to check all the given options that are true apply to the number, let's take a look at each position occupied by each digit. In order words, let's consider their place value.

Thus,

The 3 is in the ones place and as such has a value of 3.

8 is in the tenths place having a place value of 0.8 (⁸/10)

7 is in the hundredths place having a place value of 0.07 (⁷/100)

2 is in the thousandths place having a place value of 0.002 (²/1000)

Going by these, the following statements are true :

"The 7 is in the hundredths place."

"The 3 is in the ones place."

"3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001)."

The number is pronounced as three and eight hundred seventy-two thousandths rather than the option given.

Therefore, only 3 if the options are correct

Answer: The 7 is in the hundredths place.

The 3 is in the ones place.

3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).

Step-by-step explanation:

In the question, 3 is in the ones place. The first number after the decimal point is the tenths. In the question, the place value of 8 is 8 tenths; 7 is in the hundredths place.

3.872 = (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001)

= 3 + 0.8 + 0.07 + 0.002

= 3.872

The number is pronounced as three and eight hundred seventy-two thousandths

Answer:

a. X: amount of children that a Japanese woman has in her lifetime.

b. X can take natural numbers (all positive integers) as values.

c. X~Poi(1.37).

d. P(X=0)=0.2541

e. P(X<1.37)=0.6022

Step-by-step explanation:

a) This can be modeled with a Poisson distribution.

We let the variable X be the amount of children that a Japanese woman has in her lifetime.

The parameter of the Poisson distribution is λ=1.37.

This is also the value of the mean and the standard deviation.

b) X can take all positive integer values.

c) X is modeled as a Poisson variable with λ=1.37.

d) This can be calculated as:

[tex]P(0)=\lambda^ke^{-\lambda}/k!=1.37^{0} \cdot e^{-1.37}/0!=1*0.2541/1=0.2541\\\\[/tex]

e) Having fewer children than the average means that she has one or none children.

This can be calculated as:

[tex]P(X<1.37)=P(0)+P(1)\\\\\\P(0)=1.37^{0} \cdot e^{-1.37}/0!=1*0.2541/1=0.2541\\\\P(1)=1.37^{1} \cdot e^{-1.37}/1!=1.37*0.2541/1=0.3481\\\\\\P(X<1.37)=0.2541+0.3481=0.6022[/tex]

Answer: she putz 9 in the last shelter

Step-by-step explanation:

ANSWER:

I believe you wish to calculate the sum of squares total (SST) for this regression analysis. The sum of squares total is 1053.15

Step-by-step explanation:

The sum of squares total is numerically derived by adding the sum of squares regression (regression sum of squares) to the sum of squares error (error sum of squares). The regression sum of squares here is 752.25 and the error sum of squares is 300.9

This gives us a total sum of squares of 1053.15

Sums of squares tell if a linear regression of one variable (or variables) on another is good or not.

The squared differences between the observed dependent variable and its mean is a measure of the total variability of the data set.

So the SST is equal to 752.25 + 300.9 = 1053.15

Answer:

D. 150°

Step-by-step explanation:

x= 150°

Choice D

Answer:

  27/8

Step-by-step explanation:

You seem to want to evaluate ...

  [tex]\dfrac{3a^{-3}b^2}{2a^{-1}b^0}[/tex]

I like to simplify the expression first, even though the order of operations would have you evaluate it as is.

  [tex]=\dfrac{3}{2}a^{-3-(-1)}b^{2-0}=\dfrac{3b^2}{2a^2}[/tex]

Substitute the given values for "a" and "b" and do the arithmetic.

  [tex]=\dfrac{3(-3)^2}{2(-2)^2}=\dfrac{3\cdot 9}{2\cdot 4}=\boxed{\dfrac{27}{8}}[/tex]

Correction

The revenue function for a school group selling n bookmarks is given by R(n) =2n and the total cost function is given by C(n)=144+0.08n. Determine the number of bookmarks sold at which they break-even.

Answer:

75 bookmarks

Step-by-step explanation:

The break-even point is the point at which revenue earned is equal to the cost of production.

Given the cost and revenue functions respectively:

Cost=Revenue

C(n)=R(n)

144+0.08n=2n

144=2n-0.08n

144=1.92n

Divide both sides by 1.92

n=75

When 75 bookmarks are sold, the school group will break even.

Answer:

Step-by-step explanation:

6/8 in simplest form is 3/4 but value is still the same so

1. no

Answer:

  (-√8, -√6] ∪ [-√2, 0) ∪ (0, √2] ∪ [√6, √8)

Step-by-step explanation:

The inequality resolves into 4 inequalities. There are 4 intervals in the solution.

Starting at the left, for the absolute value argument less than 0:

  2 ≤ -(x^2 -4) . . . . . . . for x^2 -4 ≤ 0

  2 ≤ -x^2 +4

  -2 ≤ -x^2

  2 ≥ x^2 . . . . . . . . . . consistent with the above 4 ≥ x^2

  -√2 ≤ x ≤ √2 . . . . . square root; may be limited by other constraints

For the absolute value argument greater than 0:

  2 ≤ x^2 -4 . . . . . . . for x^2 -4 ≥ 0

  6 ≤ x^2 . . . . . . . . . .consistent with x^2 ≥ 4

  -√6 ≥ x ∪ x ≤ √6 . . . . take the square root

__

The inequality on the right can be written as the compound inequality ...

  -4 < x^2 -4 < 4

  0 < x^2 < 8 . . . . . add 4

  0 < |x| < √8 . . . . take the square root

This resolves to ...

  -√8 < x < 0 ∪ 0 < x < √8

__

So, the solution set is the set of values of x that satisfy these restrictions on x:

  -√2 ≤ x ≤ √2

  x ≤ -√6 ∪ x ≤ √6

  -√8 < x < 0 ∪ 0 < x < √8

That is a collection of 4 intervals:

  (-√8, -√6] ∪ [-√2, 0) ∪ (0, √2] ∪ [√6, √8)

_____

You may be expected to write √8 as 2√2.

__

These intervals are the portions of the red curve that lie between the two horizontal lines. The points on the upper (dashed) line are not part of the solution set. The points on the lower (solid) line are part of the solution set.

Answer:

18

Step-by-step explanation:

Let x represent the years ago

103-x = 5(35-x)

103-x = 175 +5x

4x = 72

x = 18

Answer:

[tex]P(X=0)=(9C0)(0.55)^9 (1-0.55)^{9-0}=0.000757[/tex]

[tex]P(X=1)=(9C1)(0.55)^9 (1-0.55)^{9-1}=0.0083[/tex]

[tex]P(X=2)=(9C2)(0.55)^9 (1-0.55)^{9-2}=0.0407[/tex]

[tex]P(X=3)=(9C3)(0.55)^9 (1-0.55)^{9-3}=0.1160[/tex]

And adding we got:

[tex] P(X < 4) = 0.000757 +0.0083+0.0407 +0.1160= 0.2626[/tex]

Step-by-step explanation:

Let X the random variable of interest "number of correct answers", on this case we now that:

[tex]X \sim Binom(n=9, p=0.55)[/tex]

The probability mass function for the Binomial distribution is given as:

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]

And we want to find this probability:

[tex] P(X < 4) =P(X=0) +P(X=1) +P(X=2) +P(X=3) [/tex]

And we can find the individual probabilities:

[tex]P(X=0)=(9C0)(0.55)^9 (1-0.55)^{9-0}=0.000757[/tex]

[tex]P(X=1)=(9C1)(0.55)^9 (1-0.55)^{9-1}=0.0083[/tex]

[tex]P(X=2)=(9C2)(0.55)^9 (1-0.55)^{9-2}=0.0407[/tex]

[tex]P(X=3)=(9C3)(0.55)^9 (1-0.55)^{9-3}=0.1160[/tex]

And adding we got:

[tex] P(X < 4) = 0.000757 +0.0083+0.0407 +0.1160= 0.2626[/tex]

Answer:

20%

Step-by-step explanation:

Use the table provided... it says -10 is .2 which is the same as 20%

Answer:

0.20

Step-by-step explanation:

requires decimal not percentage

f(3x - 1) = 6x - 1

Rewrite 6x - 1 as a function of 3x - 1:

6x - 1 = 6x - 2 + 1 = 2(3x - 1) + 1

That is,

f(3x - 1) = 2(3x - 1) + 1

which means

f(x) = 2x + 1

and so

f(0) = 2*0 + 1 = 1

Answer:

a) P(x=5) = 0.2456

b) P(x≥6) = 0.3526

c) P(x<4) = 0.1887

Step-by-step explanation:

We can model this as a binomial experiment, with sample size n=10 and p=0.49.

To calculate the probability of having k subjects with very little confidence in the sample of 10, we solve:

[tex]P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}[/tex]

a) We have to calculate P(x=5).

For a binomial variable with n=10 and p=0.49, this can be calculated as:

[tex]P(x=5) = \dbinom{10}{5} p^{5}q^{5}=252*0.0282*0.0345=0.2456\\\\[/tex]

b) We have to calculate P(x≥6). This can be calculated as:

[tex]P(x\geq6)=P(x=6)+P(x=7)+P(x=8)+P(x=9)+P(x=10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0138*0.0677=0.1966\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.0068*0.1327=0.1080\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0033*0.2601=0.0389\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0016*0.51=0.0083\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.0008*1=0.0008\\\\\\P(x\geq6)=0.1966+0.1080+0.0389+0.0083+0.0008\\\\P(x\geq6)=0.3526[/tex]

c) We have to calculate P(x<4). That is:

[tex]P(x<4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)\\\\\\P(x=0) = \binom{10}{0} p^{0}q^{10}=1*1*0.0012=0.0012\\\\P(x=1) = \binom{10}{1} p^{1}q^{9}=10*0.49*0.0023=0.0114\\\\P(x=2) = \binom{10}{2} p^{2}q^{8}=45*0.2401*0.0046=0.0494\\\\P(x=3) = \binom{10}{3} p^{3}q^{7}=120*0.1176*0.009=0.1267\\\\\\P(x<4)=0.0012+0.0114+0.0494+0.1267\\\\P(x<4)=0.1887[/tex]