Physics High School

The mass of an object is 50 kg. If its weight is 600N on a certain planet. Calculate the
gravitational field strength of the planet.,
​

Answers

Answer 1

Answer: The answer is 700kg

Explanation:

Related Questions

A soccer player kicks a ball with an initial velocity of 10m/s at an angle of 30 degrees above the horizontal. Find the; a) magnitude of the horizontal component b) Vertical component c) The magnitude of the vector.

Answers

Answer:

a) V₀ₓ = 8.66 m/s

b) V₀y = 5 m/s

c) Magnitude of velocity vector = 10 m/s

Explanation:

a)

The magnitude of the horizontal component of launch velocity can easily be given by the following formula:

V₀ₓ = V₀ Cos θ

where,

V₀ₓ = horizontal component of velocity = ?

V₀ = Launch Velocity = 10 m/s

θ = Launch Angle of the ball with the horizontal = 30°

Therefore,

V₀ₓ = (10 m/s)(Cos 30°)

V₀ₓ = 8.66 m/s

b)

The magnitude of the vertical component of launch velocity can easily be given by the following formula:

V₀y = V₀ Sin θ

where,

V₀y = vertical component of velocity = ?

V₀ = Launch Velocity = 10 m/s

θ = Launch Angle of the ball with the horizontal = 30°

Therefore,

V₀y = (10 m/s)(Sin 30°)

V₀y = 5 m/s

c)

The magnitude of the velocity vector will be equal to the resultant velocity or net velocity, which is 10 m/s.

Magnitude of Velocity Vector = 10 m/s


The ratio of the magnitude of the frictional force to the magnitude of the force
holding two surfaces together is called the and its UNIT is

Answers

Answer: the coefficient of friction

Explanation:

The coefficient of friction (μ (mu)) has no unit because it is a ratio of forces so the units of N (newtons, which are the units of force) cancel out.

The magnitude of frictional force is [tex]\mu[/tex]N and the magnitude of the force is N. So if we take the ratio of it we will get  [tex]\mu[/tex] In result.

What is the Coefficient of friction?

The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between them. Typically, the Greek letter is used to symbolize it, i.e., [tex]\mu[/tex]. In mathematical terms, is equal to F/N, where F represents frictional force and N represents normal force. Since both F and N are measured in units of force, the coefficient of friction is a dimensional less quantity (such as newtons or pounds).

For both static and kinetic friction, the coefficient of friction has a range of values. When an object experiences static friction, the frictional force resists any applied force, causing the object to stay at rest until the static frictional force is removed. In kinetic friction, the frictional force resists the motion of the object.

To get more information about the Coefficient of friction :

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the cylinder of gravity of cylinder is where

Answers

Explanation:

In uniform gravity it is the same as the centre of mass. For regular shaped bodies it lies at the centre of the that particular body. Hence for a cylinder centre of gravity lies at the midpoint of the axis of the cylinder.

Explanation:

We developed a spherical harmonic series that represents the gravitational potential and its gravity field due to a buried right vertical cylinder. This series can be used at far- and intermediate-regions, and is fast and accurate, using only a few terms. We compared the values of the fields acquired by this new spherical harmonic series, with ones computed by direct numerical integrations, using a fine-mesh structure for a vertical cylinder. Results of the calculations are shown and performances of the two different methods are compared. Faithfulness of the spherical harmonic series is tested with an inversion example.

1. A Force of 50N acts uniformly over and at night angles to a surface. When
the area of the surface is 5m2, then the pressure on the area is:
A. 250Pa
B. 10Pa
C. 45Pa
D. 55Pa
​

Answers

Answer:

The answer would be 10 pascal.

Answer:

B. 10Pa

Explanation:

A squeeze bottle squeezes when pressed. It regains its shape when pressed .It regains its shape when the pressure from your hand is withdrawn. What may happen if the squeeze bottle is pressed to take the sauce out and then immediately corked tightly? Will it regain its shape? If not, Why?

Answers

Answer:

The squeeze will not regain its shape

Explanation:

The squeeze bottle will not regain its shape.

This is because the atmospheric pressure compresses the squeeze bottle. Since the pressure in the squeeze bottle is now not equal to the atmospheric pressure since it has been corked tightly, its internal pressure cannot balance out the atmospheric pressure and thus cancel its effect.

So, the squeeze bottle does not regain its shape due to this imbalance of pressure.

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