The mass of Jupiter is 1/1047 of the Sun's mass (that's 0.000955). We want to confirm this using Newton's version of Kepler's Third Law, following the examples in Lecture 7. We'll use the approximate data for two different moons of Jupiter to see how close the results are. Pick the closest answer in each case: (a) Ganymede is the third moon from the inside. It has an orbital period around Jupiter of approximately 0.0194 Earth years. Its semimajor axis is 0.0071 AU. Which of these comes closest to the mass of Jupiter (in solar masses) when using these data → [Select ] 0.000951 (b) Europa is the second moon from the inside. It has an ork 0.000989 approximately 0.0096 Earth years. Its semimajor axis is 0.0045 AU. Which of these comes closest to the mass of Jupiter (in solar masses) when using these data? [Select] Hint: See also example 3.4 in the textbook.

The final velocity of the truck after collision, given that the car and the truck interlock and move together is 11.25 m/s west (Option A)

The final velocity of the truck after the collision can be obtained as illustrated below:

Momentum before = momentum after

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(1500 × 20) - (2500 × 30) = v(1500 + 2500)

30000 - 75000 = v × 4000

-45000 = v × 4000

Divide both sides by 4000

v = -45000 / 4000

v = -11.25 m/s

Recall => West is negative

v = 11.25 m/s west

Thus, the final velocity is 11.25 m/s west (Option A)

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A force can make a body at rest to move. The magnitude of force parallel to surface 1 is 5.04 N and the magnitude of the force parallel to surface 2 is 4.02 N.

The force can be defined as the quantity which is expressed as the product of mass (m) and acceleration (a). It is known as the push or pull on an object which produces acceleration in the body on which it acts.

The equation which is used to calculate the force is given as:

F = ma

a) F₁ = m₁ g sin40

= 0.800 kg × 9.81 m/s² × 0.64

= 5.04 N

b) F₂ = m₂ g sin55

= 0.500 kg × 9.81 m/s² × 0.82

= 4.02 N

Thus the magnitude of the force parallel to surface 1 is 5.04 N and the magnitude of the force parallel to surface 2 is 4.02 N.

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Field representation of a positive or  of a positive or negative charge cannot be a representation for the gravitational field around one mass. It height from the ground must be determined.

The gravitational force is a kind of force by which an object attracts other objects into its center of a mass. Earth attracts every objects in its surface in to the ground and that is why we are all standing on the ground.

Gravitational force between two objects depends on their mass and distance between them. The field representation of the charge does not represent a gravitational field but it can show an electric field between them.

The height of the mass from the surface have to be determined to represent the gravitational field. The gravitational field is not at all depending on the charge of the object.

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Answer:

play used his in but been been by in BBC in in in just not is suspension as SBB is is abbess a

Explanation:

no exception

The average speed for rest of the journey = (632.1 - 281.55) / 5.8  km/hr = 88.4 km/hr.

Average speed is a measure of the rate of change of a certain distance traveled over a period of time. It is usually calculated by dividing the total distance traveled over time, usually in hours, minutes, or seconds. Average speed is a measure of the average rate of motion, not necessarily the actual speed at any given moment.

Let the total distance covered be D. Time taken for first third of the journey = 8.7/3 hrs = 2.9 hrs
Distance covered in first third of the journey = 2.9 * 96.5 km/hr = 281.55 km
Therefore, distance covered in rest of the journey = D - 281.55 km
Time taken for rest of the journey = 8.7 - 2.9 hrs = 5.8 hrs
Average speed for rest of the journey = (D - 281.55) / 5.8  km/hr
Substituting the value of D = 8.7 hrs * 73 km/hr = 632.1 km
Therefore, average speed for rest of the journey = (632.1 - 281.55) / 5.8  km/hr = 88.4 km/hr

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The wavelength of light in micrometers where the Sun's blackbody spectrum peaks is approximately 0.5 micrometers or 500 nanometers.

The simulation provided allows the user to explore blackbody spectra emitted by opaque objects at different temperatures. Such spectra are the characteristic feature of light emitted by any object due to its temperature. The simulation begins by showing the blackbody spectrum of the Sun. By exploring the different options, the user can determine the wavelength of light in micrometers where the Sun's blackbody spectrum peaks, which turns out to be around 0.5 micrometers or 500 nanometers. This is within the visible spectrum of electromagnetic radiation, which is why we can see the Sun as a yellowish-white color. Additionally, the simulation provides information about solar intensity, which is the amount of power per unit area emitted by the Sun.

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Answer:

Explanation:

A

Answer:

The smallest possible value of the principal quantum number (n) for an electron in an atom is n = 1. This is referred to as the first energy level or the "1s" orbital, and it corresponds to the lowest energy state of an electron in an atom.

Explanation:

In general, the value of n determines the size and energy of the electron orbital. The larger the value of n, the larger the size of the orbital and the higher the energy of the electron. The smallest possible value of n is therefore always 1, and it corresponds to the electron being in its lowest energy state.

a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².

The relationship between the temperature,T and the peak wavelength, [tex]\lambda[/tex] emitted by a black body is given by wien's displacement law:

[tex]\lambda[/tex] = b / T

Where, b is a constant and it's value is 2.898 * 10-3 m-K

Given: T = 8400 K

So, [tex]\lambda[/tex] =   (2.898 * 10-3 )/8400

\lambda = 3.45 * 10-7  

\lambda = 345 nm

Hence, the peak wavelength of the object at this temperature is 345 nanometre.

The amount of power emitted per unit area, P is given by Stefan Boltzmann law:

P =[tex]\sigma[/tex]T⁴

Where,

Absolute temperature, T = 8400 K

Stefan Boltzmann constant, [tex]\sigma[/tex] = 5.67 * 10-8 W/m²K⁴

So, P = 5.67 * 10-8 * (8400)⁴

P = 2.82 * 10⁸  W/m²

Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².

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The protons location is nucleus of an atom, the Mass is 1 amu and the charge is positive.

What is protons?

Protons are subatomic particles with a positive electrical charge. They are found in the nucleus of atoms and are responsible for most of the atom’s mass. Protons are one of the three main subatomic particles, along with neutrons and electrons.

Location: Proton is located in the nucleus of an atom. The nucleus is the small, dense, positively charged center of an atom. The protons, along with the neutrons, make up the nucleus of the atom.

Mass: The mass of a proton is approximately 1.007276467 u (unified atomic mass units). It is slightly heavier than a neutron, which has a mass of approximately 1 u.

Charge: A proton has a positive charge of +1 elementary charge (e). This charge is what gives the proton its repelling force to other positively charged particles and its attractive force to negatively charged particles.

Hence, a proton is a positively charged subatomic particle with a mass of 1 amu, located in the nucleus of an atom.

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Answer:

Location:

✔ nucleus

Charge:

✔ positive

Mass:

✔ one amu

Explanation:

Momentum is conserved in both elastic and perfectly inelastic collisions.

In an elastic collision, the total momentum of the colliding objects is conserved before and after the collision. This means that the sum of the momentum of the objects before the collision is equal to the sum of the momentum of the objects after the collision.

In a perfectly inelastic collision, the two objects stick together after the collision, forming a single object with new momentum. In this case, the total momentum of the system is also conserved.

However, in an inelastic collision, momentum is not conserved, as some of the momenta are transformed into other forms of energy, such as heat or sound. This means that the total momentum of the objects before the collision is not equal to the total momentum of the objects after the collision.

Answer:

Explanation:

A

Option D: the link between the total heat flow and the temperature difference between the sample's Centre and the water at a specific time.

[tex]Q\:=\:m_sc_s\left(T_{s,i}-T_s\right)[/tex]

[tex]T_s\right =(T_{s,i}-T_s\right))[/tex]

[tex]Q=m_wc_w\left(T_w-T_{w,i}\right)[/tex]

[tex]Q=m_wc_w\left(T_w-T_{w,i}\right)[/tex]

[tex]T_{diff} =(T_{s}-T_w\right))[/tex]

        = [tex]T_{s,i} -\frac{Q}{m_{s}C_{s}} -(T_{w,i}\right +\frac{Q}{m_{s}C_{s}} )[/tex]

        =[tex](T_{s,i} - T_{w,i} )-Q(\frac{1}{m_{s}C_{s}} +\frac{1}{m_{w}C_{w}})[/tex]

Specific time refers to a precise moment in time, often denoted by a particular time and date. It can be expressed in different ways depending on the context, such as using a 24-hour clock or the AM/PM system. Specific time is essential for scheduling events, meetings, and appointments, and for coordinating activities across different time zones. It is also crucial for time-sensitive activities such as transportation, where schedules must be coordinated down to the minute. The concept of specific time is used in many fields, including science, technology, business, and everyday life. In modern times, technologies such as smartphones and computers have made it easier than ever to track and coordinate specific times across the globe.

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The complete question is:

1. we know that the total amount of heat that flows out of the sample and into the water at a specific time is given by LaTeX: [tex]Q\:=\:m_sc_s\left(T_{s,i}-T_s\right)Q=mscs(Ts,i−Ts)[/tex], where LaTeX: [tex]T_sTs[/tex] is the temperature of the sample at a specific time and, again, LaTeX: [tex]T_{s,i}Ts,i[/tex]is the initial temperature of the sample (at time 0). To simplify the math, we may neglect the heat leak term here to say that this is roughly the same amount of heat the flows into the water, so LaTeX: [tex]Q=m_wc_w\left(T_w-T_{w,i}\right)Q=mwcw(Tw−Tw,i)[/tex], where LaTeX:[tex]T_wTw[/tex] is the temperature of the water at this same specific time and LaTeX:  is the initial temperature of the water.

In the lab, we will measure both the sample and water temperatures as a function of time, but the important quantity is the difference between these temperatures since this is what drives the heat flow between the center of the sample and the water. Using the above equations (solving for the temperatures of the sample and the water bath at a particular time), we can find the relationship between the total amount of heat flow and the difference in the temperatures of the center of the sample and water at some moment in time. This yields _________________________________.

sample and water at some moment in time. This yields _________________________________.

Group of answer choices

A. [tex]T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)-\left(\frac{1}{m_sc_s}-\frac{1}{m_wc_w}\right)Q[/tex]

B [tex]T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)+\left(\frac{1}{m_sc_s}+\frac{1}{m_wc_w}\right)Q[/tex]

C.[tex]T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)+\left(\frac{1}{m_sc_s}-\frac{1}{m_wc_w}\right)Q[/tex]

D. [tex]T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)-\left(\frac{1}{m_sc_s}+\frac{1}{m_wc_w}\right)Q[/tex]

To determine the cation exchange capacity (CEC), calculate the milliequivalents of H, K, Mg, and Ca per 100g of soil (meq/100g soil) by using the following formulas: H, meq/100g soil = 8 (8.00 - buffer pH) K, meq/100g soil = lbs/acre extracted K ÷ 782. Mg, meq/100g soil = lbs/acre extracted Mg ÷ 240.

To begin, multiply the total CEC by the percentage for that ion to determine the cmolc of each cation on the exchange complex. It is 0.05 * 30 cmolc/kg for hydrogen. The cmolc/kg for each ion is then converted to mass of ion per kg by multiplying by the mass of 1 cmolc.
Soil testing laboratories calculate CEC by adding the calcium, magnesium, and potassium levels measured during the soil testing procedure to an estimate of exchangeable hydrogen derived from the buffer pH. In general, CEC values obtained through this summation method will be slightly lower than those obtained through direct measurementsdirect.

The percentage of CEC occupied by bases (Ca2+, Mg2+, K+, and Na+) is represented by base saturation (BS). The%BS increases as soil pH rises (Figure 5). Ca2+, Mg2+, and K+ availability increases as %BS increases. An 80% BS soil, for example, provides cations to plants more easily than a 40% BS soil.
Base saturation is the percentage of base cations (Ca2+, Mg2+, K+, and Na+) held onto soil exchange sites divided by total CEC.

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Forensic Entomology is the study of life cycles of insects that feed on the flesh of dead, to establish time of death and occasionally identify chemicals present in a person's body at time of death

The scientific study of the colonization of dead body by arthropods is called forensic entomology .

Larvae and adults feed on dry skin and hairs of corpse and arrive later in decomposition process : Carpet Beetles

Time since death : postmortem Interval.

Rove Beetles : Arrive a few hours after death and are active throughout decomposition process. They feed on larvae and other insects rather than the corpse itself.

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Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable.

The tension in the cord is approximately 10624 N.

To solve this problem, we can use the principles of Newton's laws and apply them to each of the objects involved. We will also use the fact that the tension in the cord is the same on both sides of the pulley (neglecting any friction or mass in the pulley).

First, we can consider the forces acting on the block (m1). The only forces acting on the block are its weight (mg) and the tension in the cord (T), which is directed upward. We can resolve these forces into components parallel and perpendicular to the inclined plane:

The weight of the block has a component parallel to the inclined plane given by [tex]mg*sin(θ)[/tex].

The tension in the cord has a component parallel to the inclined plane given by [tex]T*sin(θ)[/tex].

Using Newton's second law, we can write:

[tex]m1 * a = T * sin(θ) - m1 * g * sin(θ)[/tex]

where a is the acceleration of the block down the inclined plane.

Next, we can consider the forces acting on the sphere ([tex]m2[/tex]). Since the sphere is hanging from the cord, the only force acting on it is its weight ([tex]mg[/tex]), which is directed downward. Using Newton's second law, we can write:

[tex]m2 * a = m2 * g - T[/tex]

where a is the acceleration of the sphere downward.

Since the cord is assumed to be massless and the pulley is assumed to be frictionless, the tension in the cord is the same on both sides of the pulley. Therefore, we can set the two expressions for T equal to each other:

[tex]T * sin(θ) - m1 * g * sin(θ) = m2 * g - T[/tex]

Solving for T, we get:

T = [tex](m2 + m1) * g / (sin(θ) + 1)[/tex]

Substituting the given values, we get:

T = [tex](540 kg + 2.00 kg) * 9.81 m/s^2 / (sin(49.0°) + 1)[/tex]

T = 10624 N (to three significant figures)

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Answer:

a bus triveling north at 25m/s

The law of Newton that is related to momentum is:

B.) Newton's second law

Newton's second law states that the rate of change of momentum of an object is directly proportional to the force applied to the object and occurs in the direction in which the force is applied. This law is often expressed as F = ma, where F is the force, m is the mass of the object, and a is the acceleration of the object. This law provides the mathematical relationship between force, mass, and acceleration, which is crucial in understanding the concept of momentum.

Option C is the accurate answer. The act of preservation of instigation is grounded on Newton’s third act because of the act of conservancy of instigation.

It can subsist deduced from the act of act and response, which states that every workforce has a repaying level and contrary force. However, the hedge pushes ago against you with an equal quantum of workforce, if you drive against a barrier.  

This act signifies individual harmony in complexion workforces always do in dyads, and one core can not ply a workforce on another without passing a workforce itself.  

Newton’s third act of motion states that:    

“When one core exerts a workforce on the different mass, the foremost core gests a workforce which is collected at the moment on the contrary direction of the force which is wielded ”.  

The above statement means that in every commerce, there's a brace of forces acting on the interacting objects. The magnitude of the workforces are level and the command of the workforce on the foremost thing is contrary to the order of the workforce on the alternate thing.

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No, because covering uniform distance in uniform units of time ( which the graph one represents) is constant speed, and not uniform speed (as represented in the second graph).

What is a graph?

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The coefficient of kinetic friction for the skier, if friction is known to be 25 N, is calculated to be 0.463.

Kinetic friction may be characterized as a type of force that considerably resists the relative movement of the surfaces once they're in motion. It is just the opposite of static friction.

According to the question,

The total weight of a skier = mass of a skier × gravity = 55 × 9.8

The angle at which it inclines = 30° i.e. θ = 30°.

Normal force, N = mgcosθ  

The friction force, F = kinetic friction (N)

25 N = Kf (55 × 9.8 × 30)

Kf = 0.463.

Therefore, the coefficient of kinetic friction for the skier, if friction is known to be 25 N, is calculated to be 0.463.

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Answer: the correct answer is A

Explanation: the correct answer is A. The force would be one-fourth the original force.

To sketch the processes in a p-V diagram, we need to first determine the initial and final states of each process, as well as the path each process takes.

Process 1-2 is a constant pressure expansion from state 1 to state 2. So, the path is a straight horizontal line on the p-V diagram, from (0.2, 5) to (1, 5) (in units of m^3 and bar).

Process 2-3 is a constant volume cooling from state 2 to state 3, so the path is a straight vertical line on the p-V diagram, from (1, 5) to (1, 1).

Process 3-1 is a compression process during which the pressure-volume relationship is pV=constant. This implies that the path on the p-V diagram is a hyperbola, passing through state 3 and returning to state 1.

The work done in each process can be calculated using the following equations:

W = P(V2 - V1) for constant pressure process (1-2)

W = 0 for constant volume process (2-3)

W = -nRT ln(V2/V1) for isothermal process (3-1), where n is the number of moles of CO, R is the gas constant, and T is the temperature of the gas.

Assuming standard temperature and pressure conditions (STP), which is 1 atm and 273.15 K, the gas constant R can be taken as 0.0821 Latm/(molK).

Using these equations, we can calculate the work for each process as follows:

W1-2 = 5*(1-0.2) = 4 kJ

W2-3 = 0

W3-1 = -nRT ln(V2/V1) = -10.0821273.15 ln(1/0.2) = 11.1 kJ

Therefore, the total work done on the gas in the three processes is the sum of the work done in each process, which is 4 kJ + 0 kJ + 11.1 kJ = 15.1 kJ.

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Here are some possible percentages and their corresponding estimated z-scores:

These percentages are based on the empirical rule, which states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, approximately 95% falls within two standard deviations, and approximately 99.7% falls within three standard deviations.

The empirical rule, also known as the 68-95-99.7 rule, is a statistical principle that describes the approximate distribution of data in a normal distribution. The rule states that:

This rule is based on the assumption that the data is normally distributed, meaning that it follows a symmetrical bell-shaped curve. The empirical rule is widely used in statistics and is helpful in understanding the range of values that are likely to occur in a normal distribution.

It is important to note that the empirical rule provides only approximations and can vary in accuracy depending on the specific data and distribution being analyzed.

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Option: B, The percentage of people with blood pressure between 114 and 166 mm

The empirical rule, also known as the 68-95-99.7 rule, is a statistical principle that describes the approximate distribution of data in a normal distribution. The rule states that:

=> P(114 < x < 166)

=> P((114-140)/20 < z < (166-140)/20)

=> P(-1.3 < z < 1.3)

=> 0.8064

=> 80.6% rounded

option: D The percentage of people with blood pressure between 114 and 166 mm

=> P(140 < x < 166)

=> P((140-140)/20 < z < (166-140)/20)

=> P(0 < z < 1.3)

=> 0.4032

=> 40.3% rounded

option: C The percentage of people with blood pressure over 166 mm

=> P(x > 166)

=> P(z > (166-140)/20)

=> P(z > 1.3)

=> 0.0968

=> 9.7% rounded

This rule is based on the assumption that the data is normally distributed, meaning that it follows a symmetrical bell-shaped curve. The empirical rule is widely used in statistics and is helpful in understanding the range of values that are likely to occur in a normal distribution.

It is important to note that the empirical rule provides only approximations and can vary in accuracy depending on the specific data and distribution being analysed.

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Answer:

the cube that will slowly cool is 2

The cube 2 will cool the most slowly.

The removal of heat from a system is known as cooling, and it usually leads to a decrease in temperature or a change in phase.

Here,

Three cubes of same material and density are given in the diagram. They all are said to be cooling starting from 80°C.

The three cubes have different volumes.

We know that, as the volume of the cube increases, the surface area of the cube decreases accordingly. That means, the volume of a cube is inversely proportional to its surface area.

V ∝ 1/A

According to the principle of cooling, the rate of cooling is directly proportional to the surface area. That means, the rate of cooling is higher for objects with higher surface area and slower for those with lower surface area.

So, the cube 2 is having the lowest volume among the three cubes and thus the highest surface area.

Therefore, it will take more time to cool down.

Hence,

The cube 2 will cool the most slowly.

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Considering the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is the same.

The area, space, or field around it is an electric field of an isolated charge. There are mainly two types of electric fields i.e., static and dynamic. Moving charges produced dynamic electric fields whereas static electric fields are produced by stationary charges.

Direction and magnitude do not change over time for static electric fields. The direction can be positive or negative which is determined by the charge of the source.

The electric field formula is the electric field magnitude at a certain point from the charge Q, and it hangs on two factors- the distance r from the point to the origin Q and the amount of charge at the origin Q.

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The correct question is:

Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/mV/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 mm away from the positive charge (1 mm is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength.

Consider the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is________________.

It has all of these. everything has kinetic energy, it is moving so it will have both speed and velocity as well.

A youngster is on a merry-go-round. The centripetal force acting on the toddler is quadrupled as the merry-go-speed round's is doubled. So, option B is correct.

What is centripetal force?

Centripetal force is a term used to describe a force that moves a body along a curved path. The centripetal force is always applied in the general direction of the path's instantaneous center of curvature and against the motion of the subject. According to Isaac Newton, it is "a force by which bodies are dragged or forced, or in any other way gravitate, towards a point as to a center." Gravity is the centripetal force that generates astronomical orbits, according to Newtonian mechanics theory.

As, the formula of Centripetal force,

[tex]F=\frac{mv^2}{r}[/tex],

We can see that, F is directly proportional to [tex]v^{2}[/tex], When the speed of the merry-go-round is doubled, the centripetal force acting on the child is multiplied by four.

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The uncertainty in height is, 0.5 mm.

The "half least count rule" states that the uncertainty in a measurement is equal to half of the smallest division on the measuring instrument. In this case, the ruler is marked in 1 mm increments, so the smallest division is 1 mm.

Using the half least count rule, the uncertainty in the measurement of the height is,

uncertainty = 1/2 * 1 mm = 0.5 mm

Therefore, the uncertainty in the measurement of the height is 0.5 mm. We can express the result as,

h = 121 ± 0.5 mm

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Therefore, the distance over which the force acts is 20 meters.

The initial kinetic energy of the object is zero since it is at rest. The work done on the object by the applied force is equal to the change in its kinetic energy:

[tex]W = ΔK[/tex]

where W is the work done and [tex]ΔK[/tex] is the change in kinetic energy.

The work done by the force can be found using:

[tex]W = Fd[/tex]

where F is the force applied and d is the distance over which the force acts.

Since the object starts from rest, we can use the equation for the work-energy principle:

[tex]W = Kf - Ki[/tex]

where Kf is the final kinetic energy and Ki is the initial kinetic energy.

Setting these two expressions for W equal to each other, we have:

[tex]Kf - Ki = Fd[/tex]

Substituting the given values, we have:

[tex]Kf - 0 = (25 N) dKf = 25d[/tex]

But we also know that the final kinetic energy is[tex]5.0 x 10^2 J[/tex], so:

[tex]5.0 x 10^2 J = 25d[/tex]

d = 20 meter

Therefore, the distance over which the force acts is 20 meters.

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Answer:

their speed maybe cause of the ups and downs