The "Na" is called the element ​

Answers

Answer 1

Answer:

No

It's called a formula of an element which is a sodium element.


Related Questions

5.05 g
Express your answer as an integer.

Answers

Answer:5.5

Explanation:

Glassblower creating sculptures out of glass physical or chemical

Answers

Answer:

phsical

Explanation:

it is a phisical cuz your only changing the shape not the chemical structure

A sample of water is measured with a 2 mL volumetric pipet. What volume
measurement should be recorded with the correct number of decimal places?

Answers

Answer:

Explanation:

A pipette is used to measure an exact volume of liquid; a pipette can only measure it's exact recommended volume (it can't measure more or less).

Hence, a 2-mL volumetric pipette can only measure 2 ml and would be recorded as 2.00 (ml). This is because simple volumes are usually recorded in two decimal places.

Calculate the molar solubility of CaF2 in a 0.25 m solution of NaF(aq).
(Ksp (CaF2) = 4.0 x 10-11)

Answers

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

The molar solubility should be 6.4 × 10^-10 M

Calculation of the molar solubility:

Here

CaF2 will dissociate should be

CaF2 ⇌Ca2+ + 2F-

where,

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

Now

NaF will also dissociate like

NaF ⇌ Na+ + F-

Here

Na+ = 0.25M

F- = 0.25M

Now

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

Learn more about solution here: https://brainly.com/question/14619461

Explain why or why not it’s necessary for the scientific process to always follow the same route

Answers

Answer:

Explanation:

The scientific method describes the processes by which scientists gain knowledge about the world. It's characterized by six key elements: questions, hypotheses, experiments, observations, analyses, and conclusions. These elements are interrelated steps, so they don't always function in the same order.

17. SiH3P
How do you create a Lewis structure for this formula?

Answers

Answer:

See attached picture.

Explanation:

Hello,

In this case, considering that Lewis structures are drawn in order to show up the bonding among equal or different atoms via their valence electrons, since hydrogen has one valence electron, silicon four and phosphorous five, the most suitable way to draw and attain the octet for both silicon and phosphorous is by bonding them via a double bond, one hydrogen bonded to the phosphorous and two hydrogen atoms bonded to the silicon as shown on the attached picture, wherein you can count eight electrons for both phosphorous and silicon.

Best regards.

Determine the partial negative charge on the bromine atom in a c−br bond. the bond length is 1.93 å and the bond dipole moment is 1.40 d . express your answer using 3 significant figures. the partial negative charge on the bromine atom = previous answersrequest answer incorrect; try again; 4 attempts remaining provide feedback.

Answers

Answer:

The value is [tex]x = 0.151 \ e [/tex]

Explanation:

From the question we are told that

The bond length is [tex]l = 1.93\ \r a = 1.93 *1 *10^{-10} =1.93 *10^{-10}\ m [/tex]

The bond dipole moment is [tex] \mu = 1.40 d = 1.40 * 3.33564 *10^{-30} = 4.6699 *10^{-30} \ C \cdot m[/tex]

Generally the dipole moment is mathematically represented as

[tex]\mu = Q * l[/tex]

Here Q is the partial negative charge on the bromine atom

So

[tex]Q = \frac{\mu}{ l}[/tex]

=> [tex]Q = \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }[/tex]

=> [tex]Q = 2.42 *10^{-20} C [/tex]

Generally

1 electronic charge(e) is equivalent to [tex]1.60*10^{-19} C[/tex]

So x electronic charge(e) is equivalent to [tex]Q = 2.42 *10^{-20} C [/tex]

=> [tex]x = \frac{2.42 *10^{-20}}{1.60*10^{-19} }[/tex]

=>     [tex]x  =  0.151  \ e [/tex]

(3.605 X 10^-27) + (4.01 X 10^-25)
Answer in scientific notation

Answers

the answer is 4.04605 X 10^-25

Which is more dense? A foam ball or a bowling ball?
Please help! Only answer if you know the answer 100%

Answers

a bowling ball.
definition of dense-closely compacted in substance

How much grams are in 4.78 cup

Answers

Answer:

1130.89

Explanation:

Answer:

963.648

Explanat:::::::)))))))

A compound is found to contain 46.68 % nitrogen and 53.32 % oxygen by mass. To answer the question, enter the elements in the order presented above. QUESTION 1: The empirical formula for this compound is . QUESTION 2: The molar mass for this compound is 30.01 g/mol. The molecular formula for this compound is

Answers

Answer:

Q1: NO

Q2: NO

Explanation:

Step 1: Given data

Percentage by mass of nitrogen: 46.68%

Percentage by mass of oxygen: 53.32%

Step 2: Divide each percentage by the mass of the element

N: 46.68/14.01 = 3.332

O: 53.32/16.00 = 3.332

Step 3: Divide both numbers by the smallest one (in this case is the same)

N: 3.332/3.332 = 1

O: 3.332/3.332 = 1

The empirical formula is NO. Its molar mass is 30.01 g/mol.

Step 4: Calculate "n"

n = molar mass of the molecular formula / molar mass of the empirical formula

n = (30.01 g/mol) / (30.01 g/mol) = 1

Step 5: Determine the molecular formula

We do so by multiplying the empirical formula by "n".

NO × 1 = NO

how are the troposphere and the thermosphere alike

Answers

This layer also contains ratios of nitrogen and oxygen similar to the troposphere, except the concentrations are 1000 times less and there is little water vapor there, so the air is too thin for weather to occur. The thermosphere is the uppermost layer of the atmosphere.

Several properties of the element magnesium are shown. Which one is a chemical property?
O A. has a density of 1.7 g/cm3
B. melts at 650°C
C. conducts electricity
D. has a silvery-white color
E. burns when exposed to heat

Answers

Answer:

E

Explanation:

burning a substance changes it chemically.

Calculate the [H+] and pH of a 0.000185 M acetic acid solution. Keep in mind that the Ka of acetic acid is 1.76×10−5. This is a problem that will require you to use the quadratic. Start by setting up the quadratic equation before using the quadratic formula and find the coefficients. Then, solve the quadratic. Quadratic formula: ax2+bx+c=0; enter the values of a, b, and c

Answers

Answer:

[H⁺] = 0.000048936M

pH = 4.31

Explanation:

Acetic acid, CH₃COOH, dissociates in water as follows:

CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)

And Ka is defined as:

Ka = 1.76x10⁻⁵ =  [H⁺] [CH₃COO⁻] / [CH₃COOH]

Where [] are equilibrium concentrations of the species.

The 0.000185M of acetic acid will decreases X, and X of [H⁺] and [CH₃COO⁻] will be produced. That means Ka is:

1.76x10⁻⁵ =  [X] [X] / [0.000185 - X]

3.256x10⁻⁹ - 1.76x10⁻⁵X = X²

3.256x10⁻⁹ - 1.76x10⁻⁵X - X² = 0

Solving for X:

X = -0.000066M → False solution. There is no negative concentrations.

X = 0.000048936

As [H⁺] = X,

[H⁺] = 0.000048936M

And pH = -log [H⁺]

pH = 4.31

A plate moves 200 m in 10,000 years. What is its rate in cm/year?

Answers

Answer:

The answer is

2 cm/year

Explanation:

To find the rate in cm/year we must first convert 200 m into cm

1 m = 100 cm

if 1 m = 100 cm

Then 200 m = 200 × 100 = 20 ,000 cm

So the rate is

[tex] \frac{20000}{10000} [/tex]

Reduce the fraction with 10,000

We have the final answer as

2 cm/year

Hope this helps you

Answer:

2 CM/year just now got 100 Edge.

Explanation:

Calculate the [OH-] and the pH for a solution of 0.24M methylamine, CH3NH2. Kb = 3.7 X 10-4.

Answers

Answer:

[tex][OH^-]=9.24x10^{-3}M[/tex].

[tex]pH=11.97[/tex].

Explanation:

Hello,

In this case, since the ionization of methylamine is:

[tex]CH_3NH_2(aq)+H_2O(l)\rightleftharpoons CH_3NH_3^+(aq)+OH^-(aq)[/tex]

The equilibrium expression is:

[tex]Kb=\frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}[/tex]

And in terms of the reaction extent [tex]x[/tex] which is equal to the concentration of  OH⁻ as well as that of CH₃NH₃⁺ via ice procedure we can write:

[tex]3.7x10^{-4}=\frac{x*x}{024-x}[/tex]

Whose solution for [tex]x[/tex] via quadratic equation is 9.24x10⁻³ M since the other solution is negative so it is avoided. Therefore, the concentration of OH⁻ is:

[tex][OH^-]=x=9.24x10^{-3}M[/tex]

With which we can compute the pOH at first:

[tex]pOH=-log([OH^-])=-log(9.24x10^{-3})=2.034[/tex]

Then, since pH and pOH are related via:

[tex]pH+pOH=14[/tex]

The pH turns out:

[tex]pH=14-pOH=14-2.034\\\\pH=11.97[/tex]

Best regards.

Which of the following describes the formation of an ionic bond

Answers

Explanation:

loosing or gaining one or more electrons

The reason a theory may be changed or thrown out is

Answers

Answer:

If it is not proven and if it isn't backed up by any facts or has been proven to be false.

Two separate pure samples of carbon dioxide were analyzed. Both samples were found to contain 27.29% carbon by mass. Justify these findings on the basis of atomic molecular theory.

Answers

Answer:

Atoms of the same element are exactly alike in all respects and are different from atoms of other elements.

Explanation:

One of the postulates of the Dalton's atomic theory is that 'Atoms of the same element are exactly alike in all respects and are different from atoms of other elements.'

Hence, if carbon dioxide from two sources are obtained and analysed, the mass percentage of carbon in both samples should be exactly the same since they both contain atoms of carbon. The atoms of carbon in the both samples are exactly the same in all respects in accordance with the Dalton's atomic theory, hence the observation.

Liquids that do not mix can be separated by which technique

A) Filtration
B) Distillation
C) Decantation
D) Evaporation

Answers

Decantation, like when you take oil and mix it with water.

What are the effects of inhalation of acetone vapor?

Answers

Answer:

it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma

A gas cylinder is filled with silane (SiH4), used in semiconductor processes. The cylinder’s internal volume is 2.40 L, and it contains 542 g of the compound. Estimate the pressure inside the cylinder at 21oC. The properties of silane: Tc = 269.7 K, Pc = 48.4 bar, and ω = 0.094.

Answers

Answer:

The value is [tex]P = 7.8 *10^{6} \ Pa [/tex]

Explanation:

From the question we are told that

The internal volume is [tex]V_i = 2.40 \ L = 2.40 *10^{-3} \ m^3[/tex]

The mass of the compound contained is [tex]m = 542 \ g[/tex]

The temperature is [tex]T = 21^o C = 21 + 273 = 294 \ K[/tex]

The critical temperature of silane is [tex]T_c = 269.7 \ K[/tex]

The critical pressure of silane is [tex]P_c = 48.4 bar = 48.4 *10^{5} \ Pa[/tex]

Generally the number of moles of silane inside the cylinder is mathematically represented as

[tex]n = \frac{m}{M}[/tex]

here M is the molar mass of silane with value [tex]M = 32 g/mol[/tex]

So

[tex]n = \frac{542}{32}[/tex]

=> [tex]n = 16.4 \ mol[/tex]

Generally the molar volume of silane in the cylinder is mathematically represented as

[tex]Vn = \frac{V_i}{n}[/tex]

=> [tex]Vn = \frac{2.40 *10^{-3}}{16.4}[/tex]

=> [tex]Vn = 1.42*10^{-4} \ m^3 / mol[/tex]

Generally from Soave-Redlich-Kwon we have that

[tex]P = \frac{RT}{V_n - b} - \frac{a}{V_n (V_n + b)}[/tex]

Here b is a constant which is mathematically represented as

[tex]b = 0.08664 * \frac{R T_c }{P_c}[/tex]

substituting [tex]8.314 J/mol\cdot K[/tex] for R we have \

[tex]b = 0.08664 * \frac {8.314* 269.7}{48.4*10^{5}}[/tex]

[tex]b = 4.0139 *10^{-5} m^3/mol[/tex]

a is also a constant which is mathematically represented as

[tex]a = 0.42748 * \frac{(R * T_c)^2}{P_c} * (1 + m [1-\sqrt{T_r} ])^2[/tex]

Here [tex]T_r[/tex] is the reduced temperature which is mathematically represented as

[tex]T_r = \frac{T}{T_c}[/tex]

=> [tex]T_r = 1.09[/tex]

m is a constant which is mathematically represented as

[tex]m = 0.480 + 1.574w - 0.176w^2[/tex]

=>           [tex]m  =  0.480 + 1.574 (0.094) - 0.176(0.094)^2[/tex]

=> [tex]m = 0.626[/tex]

So

[tex]a = 0.42748 * \frac{(8.314 * 269.7)^2}{48.4*10^{5}} * (1 + 0.626 [1-\sqrt{1.09} ])^2[/tex]

[tex]a = 0.4198[/tex]

From   [tex]P =  \frac{RT}{V_n - b} - \frac{a}{V_n (V_n + b)}[/tex] we have

[tex]P = \frac{8.314 * 294}{1.42*10^{-4} - 4.0139 *10^{-5} } - \frac{0.626}{1.42*10^{-4} (1.42*10^{-4} + 4.0139 *10^{-5} )}[/tex]

[tex]P = 7.8 *10^{6} \ Pa [/tex]

You have a 16 g sample of ethanol with a density of 0.7893 g/mL. What volume of ethanol do you have?

Answers

Answer:

Density is mass/volume d=m/v   so volume = m/d or mass divided by density.

That would be 23 / 0.7893 = 29.1397 or 29.14 mL.  Grams cancels out

Explanation:

The volume of ethanol is 20.27 g/ml.

What is volume?

The area occupied by a three-dimensional object is its volume. It can be determined using density and mass. Liters are used to measure it. The overall weight of a thing is its mass. M designates it.

The mass per unit volume is known as density. The capital letter D and the symbol rho stand for density. You can figure it out by dividing the mass by the volume.

rho = m / V

rho = density

m = mass

V = volume

Given the mass of the sample of ethanol weighs 16 g

The density of 0.7893 g/mL

Putting the values in the equation

Volume = 16 / 0.7893 = 20.27

Thus, the volume of ethanol is 20.27 g/ml.

To learn more about volume, refer to the link:

https://brainly.com/question/16940422

#SPJ2

which are made matters

Answers

Answer:

Everything you can hold, taste, or smell is made of matter. Matter makes up everything you can see, including clothes, water, food, plants, and animals. It even makes up some things you cannot see, such as air or the smell of perfume.

What is the potential energy of the ball when it gets to its maximum height just before falling back to the ground?J

Answers

Answer:

9.8 joules

Explanation:

due to acceleration due to gravity

What is the period number in which helium is found

Answers

Answer:

Helium is the second element on the periodic table. It is located in period 1 and group 18 or 8A on the righthand side of the table. This group contains the noble gases, which are the most chemically inert elements on the periodic table. Each He atom has two protons and usually two neutrons and two electrons.

Explanation:

thoughtco.com

Answer:

period 1 and group 18 or 8A on the righthand side of the table.

Explanation:

a non-aqueous solution has a solvent that is not water. which is an example of a non aqueous solution?

paint
steel
orange juice
shaving cream

i’m confused because normally paint would be classified as a heterogenous mixture (not a solution) but the only other logical answer is orange juice but that is aqueous since it’s a solution based off the natural waters found in the orange. :/

Answers

Answer:

It is B. Steel

Explanation:

Answer:

Defenitly B !!

( Steel )

Explanation:

Write the net ionic equation for the reaction that takes places between aqueous copper and nitrate.

Answers

Answer:

Cu+HNO3

Explanation:

Multiply 17.243 × 0.95 = _____

Answers

Answer:16.38085

Explanation:Aline the decimals then start multiplying.

What technique would you use to separate the Drierite from the silicon? *

Answers

Answer:

Filtration

Explanation:

Filtration is a separation technique used in the laboratories to separate two elements or compounds by using a filter paper and a beaker.

Drierite is also know as calcium sulphate and silicon is made up of silica.

The filtration equipment are taken to separate these two components. The separation method is used in the second beaker by pouring the mixture through a filtering funnel and using a filter paper. The solid remaining of silicon remains on the filter paper separating the two.

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