(the problem setup and question are below)

(the Problem Setup And Question Are Below)
(the Problem Setup And Question Are Below)

Answers

Answer 1

The gauge pressure at bottom of vaccine solution will be 16 kPa

Positive pressure is another name for gauge pressure. When a system's internal pressure exceeds that of its surroundings, it is said to be under positive pressure. Any leak that develops in the positively pressured system will therefore escape into the outside world. In contrast, a negative pressure chamber draws air into it.

Given As seen in the illustration, a syringe is held vertically. The container carries a 3 cm tall column of vaccine solution and has an open inner diameter of 1 cm. The needle contains a 2 cm column of vaccine solution and has an open inner diameter of 0.5 mm. At the needle's open end, the solution is exposed to the air. The vaccination solution has a density of 1200 kg/m3.

We have to find the gauge pressure at bottom of vaccine solution

Since the 5N force is applied to vaccine solution the pressure exerted will be much more

Hence the gauge pressure at bottom of vaccine solution will be 16 kPa

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Related Questions

Any Acellus folk figure out the answer to this one??? I CANNOT for the life of me.

What is the angular velocity of the minute hand of a clock?
[?] rad/s

Hint: It travels clockwise and takes 60 minutes to make one revolution.



(not 1.25, 1.7, 1800, 30, 60, 0.1047)

Answers

Answer:

-0.10472[tex]\frac{rad}{s}[/tex]

Explanation:

Remember that any clockwise rotation is considered negative, and any counterclockwise rotation is considered positive.

The formula for period is:

[tex]T = \dfrac{2\pi}{\omega}[/tex]

Solve for [tex]\omega\\[/tex] and you get:

[tex]\omega=\dfrac{2\pi}{T}[/tex]

The period is 60 seconds so make that division and you're left with -0.10472[tex]\frac{rad}{s}[/tex] or -0.10[tex]\frac{rad}{s}[/tex] if significant figures apply (negative because the rotation is clockwise).

A mass of 2.0 kg of water is heated. The temperature increase of the water is 80 degrees Celsius. The specific heat capacity of water is 4200 J / kg degrees Celsius. Calculate the change in thermal energy when the water is heated. Use the equation. change in the thermal energy = mass x specific heat capacity x temperature change

Answers

Answer:

672 000 J      or 672 kJ

Explanation:

change in the thermal energy = mass x specific heat capacity x temperature change

     =   2 kg * 4200J/kg-C *80 C =672000 J


On Earth, a scale shows that you weigh 490 N. What is your mass?
A 50 kg
B 100 kg
c) 75 kg
D 22 kg

Answers

A 50 kg

490N = m(kg) *9.8(m/s^2)=>m=490/9.8 = 50kg

Answer:

a

Explanation:

Which of the following is not a use of nuclear chemistry in industry?

thickness gauges
tracers
leak detectors
stimulate plant growth

Answers

Stimulating plant growth is not a use of nuclear chemistry in industry. Thus, the correct option is D.

What is Nuclear Chemistry?

Nuclear chemistry may be defined as the sub-branch of chemistry that involves the investigation of physical and chemical characteristics of elements that are affected by transformations in the configuration of the atomic nucleus.

Thickness gauges measure the thickness, density, and fill levels and are utilized in manufacturing to make sure that an entire product or a set of products are of identical thickness.

Tracers are utilized in tracing the actual composition of radioactive decay through the chemical compounds. While the leak detectors monitor the actual and constant flow of water through a given system precisely.

Therefore, the correct option for this question is D.

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Answer:

it is d

Explanation:

At a given temperature, lighter gas molecules:
A) have an average speed less than heavier gas molecules.
B) have an average speed greater than heavier gas molecules.
C) ll move more slowly than heavier gas molecules.

Answers

At a given temperature, lighter gas molecules, have an average speed greater than heavier gas molecules.

What is temperature?

Temperature is the measure of degree of hotness or coldness of a body. It is also the measure of average kinetic energy of a body.

As temperature increases, the average kinetic energy of a body increases.

K.E = ¹/₂mv²

v² = 2K.E/m

v = √( 2K.E/m)

where;

m is massv is velocityK.E is kinetic energy

From the equation above, at a constant temperature, the speed of a gas molecule will decrease with increase in the mass of the molecules and vice versa.

Thus, at a given temperature, lighter gas molecules, have an average speed greater than heavier gas molecules.

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Question 4 of 20
If the distance between two objects is doubled, what happens to the
gravitational force between them?
A. It decreases to 1/2 its original magnitude.
B. It increases to 2 times its original magnitude.
C. It increases to 4 times its original magnitude.
D. It decreases to 1/4 its original magnitude.

Answers

Answer:

D

Explanation:

F = G m1 m2 / r^2       now double  r

 F =  G m1m1/ (2r)^2

    F =  1/4  G m1m2/r^2     <===== this is 1/4 of the original

Calculate the frequency of the wave shown below.
Frequency = Speed/Wavelength (λ)

Select one:
a. 4 hertz
b. 3 hertz
c. 2 hertz
d. 1 hertz

Answers

[tex] \color{skyblue}{ \underline{ \frak { \: option \: ( \: c \: ) = 2 \: hertz ✓}}}[/tex]

[tex] \: \: [/tex]

Given :

Wavelength ( λ ) = 2 m

[tex] \: \: [/tex]

Speed = 4 m/s

[tex] \: \: [/tex]

We, have to find frequency :

[tex] \: [/tex]

[tex] \large \tt \: Frequency = \frac{Speed}{Wavelength ( \: λ \: )} [/tex]

[tex] \: \: [/tex]

[tex]\large \tt \: Frequency = \frac{4}{2} [/tex]

[tex] \: \: [/tex]

[tex]\large \tt \: Frequency = \cancel \frac{4}{2} [/tex]

[tex] \: \: [/tex]

[tex] \pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}[/tex]

[tex] \: \: [/tex]

Hope Helps!

pleaseeeeeee I need HELP in 20 mins,Asap!!!


A 6.00 -kg clay ball is thrown directly against a perpendicular brick wall at a velocity of 22m/s^2 and shatters into three pieces, which all fly backward. The wall exerts a force of 2640N on the ball of for 0.1s. One piece of mass 2kg travels backward at a velocity of 10m/s and an angle of 32° above the horizontal. A second piece of mass 1kg travels at a velocity of 8m/s and an angle of 28° below the horizontal. What is the velocity of the third piece?​

Answers

The velocity of the third piece is 124.02 m/s at 1.05⁰ below the horizontal.

Velocity of the third piece

The velocity of the third piece is calculated from the principle of conservation of linear momentum.

mu = m₁u₁ + m₂u₂ + m₃u₃

where;

m is mass of the clayu is velocity of the clayu₁ is velocity of first pieceu₂ is velocity of second pieceu₃ is velocity of third piecem₃ is mass of the third piece = 6 kg - (2 kg + 1 kg) = 3 kgMomentum in y - direction

6(22)sin(0) = 2(10)sin32 - 1(8)sin(28) + 3u₃y

0 = 6.84 + 3u₃y

u₃y = -6.84/3

u₃y = -2.28 m/s

Change in momentum

ΔP = Pf - Pi = J

where;

Pf is final momentumPi is the initial momentumJ is impulse

2640(0.1) = 2(10)cos32 +  1(8)cos(28) + 3u₃x - 6(22)

264 = -108 + 3u₃x

3u₃x = 372

u₃x = 372/3

u₃x = 124 m/s

Resultant velocity

u₃ = √(124² + 2.28²)

u₃ = 124.02 m/s

Direction of the velocity

tanθ = u₃y/u₃x

tanθ = 2.28/124

tanθ = 0.018

θ = 1.05⁰ (below the horizontal)

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What is the gravitational potential energy of a 15.0kg object that is 5.00m above the ground relative to a point 8.00m above the ground?
-441J
735J
-735J
441J

Answers

Explanation:

an object's gravitational potential energy Eg is m×g×h where:

m=mass

g=9.8m/s²

h=height relative to the closest object below it (because it cannot potentially fall through it

so Eg = 15×9.8×5=735J

The three waves shown in the picture below are equal in wavelength, but are travelling at different speeds. Given this information, which wave has the highest frequency?
Select one:
a. 1
b. 2
c. 3
d. Can't tell from the information given.

Answers

Wave 3 will have the highest frequency. Option c is correct.

What is the frequency?

Frequency is defined as the number of repititions of a wave occurring waves in 1 second.

Frequency is given by the formula as,

[tex]\rm v = \lambda \times f[/tex]

If the wavelength of the wave is content the velocity of the wave is directly propotional to the frequency.

The velocity of wave 3 is maximum. So that the wave 3 will have the highest frequency.

Hence option c is correct.

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the road from city A to city B is described by a car with Vm 40 km / h. When the car turns (from B to A) the average speed is 60 km / h. Find the average round trip speed.​

Answers

Answer:

Let distance between two cities is x km . So total distance travelled bus x+x=2x km and time taken was=(x/40)+(x/60)=(3x+2x)/120=5x/120=x/24 hrs . So avg speed is 2x/(x/24)=48 km per hr.

or

dt1=60km1h

dt2=30km1h

2dt1+t2=r¯

d=60t1

d=30t2

60t1=30t2

2t1=t2

2dt1+(2t1)=r¯

2(60t1)t1+2t1=r¯

2(60t1)=r¯(t1+2t1)

120=r¯+2r¯

r¯=1203

r¯=40km/h

10 precautions for obtaining the refractive index of a triangular glass prism. ​

Answers

Answer:

Following precautions for obtaining the refractive index of a triangular glass prism:-

Explanation:

(1) All the faces of the prism should be neat and clean.

(2) Pins for holding the paper on the drawing board must be pinned perpendicular to the paper for better handling.

(3) While fixing the pins for checking the refractive index of the prism, make sure that the reflective images of the pins should be aligned to your eye to avoid any type of parallax error.

(4) Pins should not be removed or pinned again during the experiment.

(5) Avoid mishandling of the prism.

(6) Same edge of the prism should be taken as vertex for observations.

(7) For drawing the boundary of the prism, a sharp pencil should be used.

(8) Soft board and pointed pins should be used.

(9) The distance between the pins should be 5 cm or more.

(10) Make sure the glass slab or prism taken are polished and not broken.

Hope this helps!

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a 1kg ball is bening pushed by the rod to move in horizontal groved smooth slot if it startes from angle teta = zero degree . determaine the force the rod exertes on the ball at teta is =15 dgree if ai this instant the rod moves at angular speed of teta = 1 rad per sec end with angular acceleration theta = 2 rad persec and square the ball is only in contact with the outer side of the slot​

Answers

The force the rod exerts on the ball at the given angle is determined as 3.94 N.

Force exerted on the rod by the ball

The force exerted is calculated as follows;

F = ma

F = mv²/r

F = mω²r

where;

m is mass of the ballω is angular speed of the ballr is radius of the path

r = 2cosθ

Angular speed when the ball moves 15 degrees

ωf² = ωi² + 2αθ

where;

θ is angular displacement in radians, 15⁰ = 15 x π/180 rad

ωf² = (1)² + 2(2)(15 x π/180)

ωf² = 2.04

ωf = √2.04

ωf = 1.428 rad/s

F = mω²(2cosθ)

F = (1)(1.428)²(2 x cos15)

F = 3.94 N

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A 200-gram liquid sample of Alcohol Y is prepared at -6°C. The sample is then added to 400 g of water at 20°C in a sealed styrofoam container. When thermal equilibrium is reached, the temperature of the alcohol-water solution is 12°C. What is the specific heat capacity of the alcohol? Assume the sealed container is an isolated system. The specific heat capacity of water is 4.19 kJ/kg · °C. 3.14 kJ/kg \xe2\x88\x99 °C 4.14 kJ/kg \xe2\x88\x99 °C 3.72 kJ/kg \xe2\x88\x99 °C 4.88 kJ/kg \xe2\x88\x99 °C

Answers

The specific heat capacity of the alcohol will be 3.72  kJ/kg°C.

What is the specific heat capacity?

The amount of heat required to increase a substance's temperature by one degree Celsius is known as its "specific heat capacity."

Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.

Given data;

Mass of liquid sample of Alcohol  m₁ = 200-gram

The temperature of alcohol, T₁ =  -6°C.

Mass of liquid sample of water  m₂ = 400-gram

The temperature of the water, T₂=  20°C.

The specific heat capacity of the alcohol, S₁=?

The specific heat capacity of water is, S₂=4.19 kJ/kg.°C

As we know that;

[tex]\rm Q_{gain}= Q{loss} \\\\ Q_{alcohol} =Q_{water} \\\\\ m_1s_1\triangle T_1 = m_2S_2 \triangle S_2 \\\\ 200 \times 10^{-3} \times S_1 [ (12-(-6) ] = 40 \times 10^{-3} \times 4.19 \times 10^{-3} \times (20-12)\\\\S_1 = 2 \times 4.19 \times 10^3 \times \frac {8}{18} \\\\ S_1 = 3.72 \ kJ /kg ^0 C[/tex]

Hence the specific heat capacity of the alcohol will be 3.72  kJ/kg°C.

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What is the mass of an object if it has 915J of energy when it is 6.50m above the ground?
A.851kg
B0.0696kg
C.583kg
D.14.4kg

Answers

Answer:

D

Explanation:

GPE = mgh

GPE / gh = m

m = GPE/gh

m = 915 / 6.5 x 9.8

m = 915 / 63.7

m = 14.4kg

p ⇒ q, r ⇒ s, p ∨r q ∧ s is invalid

Answers

Answer:

My explanation and answer are down here↓:

Explanation:

p→q is false only when p is true and q is false.

∴p→(q∨r) is false when p is true and (q∨r) is false, and

q∨r false when both q,r are false.

Hence T,F,F.

(i). A ball of mass 1.500 kg is attached to the end of a cord 1.50 m long. The ball moves in a horizontal circle. If the cord can withstand a maximum tension of 64.0 N, a. What is the maximum speed at which the ball can move before the cord breaks? Assume the string remains horizontal during the motion. (5 marks) b. Suppose the ball moves in a circle of larger radius at the same speed v. Is the cord more likely or less likely to break? ( i ) . A ball of mass 1.500 kg is attached to the end of a cord 1.50 m long . The ball moves in a horizontal circle . If the cord can withstand a maximum tension of 64.0 N , a . What is the maximum speed at which the ball can move before the cord breaks ? Assume the string remains horizontal during the motion . ( 5 marks ) b . Suppose the ball moves in a circle of larger radius at the same speed v . Is the cord more likely or less likely to break ?​

Answers

(a) Let [tex]v[/tex] be the maximum linear speed with which the ball can move in a circle without breaking the cord. Its centripetal/radial acceleration has magnitude

[tex]a_{\rm rad} = \dfrac{v^2}R[/tex]

where [tex]R[/tex] is the radius of the circle.

The tension in the cord is what makes the ball move in its plane. By Newton's second law, the maximum net force on it is

[tex]F = (1.500\,\mathrm{kg}) a_{\rm rad}[/tex]

so that

[tex](1.500\,\mathrm{kg}) \dfrac{v^2}{1.50\,\rm m} = 64.0\,\mathrm N[/tex]

Solve for [tex]v[/tex] :

[tex]v^2 = \dfrac{(64.0\,\mathrm N)(1.50\,\mathrm m)}{1.500\,\rm kg} \\\\ \implies \boxed{v = 8.00 \dfrac{\rm m}{\rm s}}[/tex]

(b) The net force equation in part (a) leads us to the relation

[tex]F = \dfrac{mv^2}R \implies v = \sqrt{\dfrac{FR}m}[/tex]

so that [tex]v[/tex] is directly proportional to the square root of [tex]R[/tex]. As the radius [tex]R[/tex] increases, the maximum linear speed [tex]v[/tex] will also increase, so the cord is less likely to break if we keep up the same speed.

Which sentence describes an object that has kinetic energy?

Answers

Answer:

Kinetic energy is referred to the energy associated with movement and or motion, thus the only object that is moving would be A boat sailing across the ocean.

Explanation:

an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall, what is the height of the object?

Answers

The height of the object will be -5.19 cm

A concave mirror's reflecting surface curves inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.

Given an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall

So let,

v =  Image distance from the mirror = -33.5 cm

u = object distance from the mirror (concave) = 24 cm

hi = Image height = 7.25 cm

h = height of the object = ?

Using below formula to find height of the object

-v/u = hi/h

Putting all value in the formula we get

-(-33.5)/(-24) = 7.25/h

h = -5.19 cm

Therefore the height of the object will be -5.19 cm

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A mass of (200 of hot water at (75, 0 degrees * C) is mixed with cold water of mass M at (5, 0 degrees * C) The final temperature of the mixture is (25, 0 degrees * C) What is the mass of the cold water (M)

Answers

Q in = Q out

mcΔt in = mcΔt out (c = equal)

mΔt in = mΔt out

200 x  (75-25) = M x (25-5)

M = 500 g

∆T for hot water

75-2550°C

∆T for cold water

25-520°C

Both are equal according law of conservation of energy

[tex]\\ \rm\Rrightarrow m_1c\delta T_0=m_2c\delta [/tex]

[tex]\\ \rm\Rrightarrow 200(50)=m_2(20)[/tex]

[tex]\\ \rm\Rrightarrow 10000=m_2(20)[/tex]

[tex]\\ \rm\Rrightarrow m_2=500g=0.5kg[/tex]

PLEASE HELP!! 50 points. The answer is not 2.6 m/s.

Answers

Answer:

A

Explanation:

5.2mm/s

hope this helps

You are standing in an open field near a train track as a train goes by at a constant speed blowing its horn in all directions (except down, into the ground) at a constant frequency. You are first able to hear it when it is approaching you 1 km away. When it is a quarter of a kilometer past you, by how many decibels has the train's sound level intensity shifted?
(options: 6, 12, 58, 105, 108, or 114)

Answers

Answer:

108 is the correct answer

Compute the speed of sound waves in air at room temperature (T=200C) and find the range of wavelengths in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive. The mean molar mass of air (a mixture of principally nitrogen and oxygen) is 28.8 x 10-3kg/mol and the ratio of heat capacity is ϒ = 1.40.

Answers

The speed of sound waves in air at room temperature T=20° is 344.035 m/s.

The range of wavelength in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive is  17.20 m to  0.0172 m.

What is wavelength?

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = c/f

where c is the speed of sound wave.

Given the room temperature T = 20 +273 = 293K

The velocity of sound wave is given by

v = √(γRT/m)

​where γ =1.4 , m = 28.8×10⁻³ kg/mol  R = 8.31 J/K.mol

Substituting the values, we get

v = 344.035 m/s

Thus, the speed of sound wave is 344.035 m/s

The human ear can hear frequencies in the range of 20 – 20,000Hz.

The wavelength corresponding to 20Hz is

λ = c/f

λ =  344.035 /20

λ  = 17.20 m

The wavelength corresponding to 20,000Hz is

λ =  344.035 /20000

λ  = 0.0172 m

Thus, the range of wavelength is 17.20 m to  0.0172 m sensitive to human ear.

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suppose the velocity of a particle is given by the equation, V=m+nt2, where m=10cms and n=2cm/s3.
A, find the change in velocity of the particle in the initial time interval b/n t₁=2sec and t₂=5sec
B, find the average acceleration in this time interval
C, find the instantaneous acceleration at time t₁=2sec​

Answers

Hello!

Begin by plugging in the values for m and n. We get the equation for the velocity of the particle to be:
[tex]v(t) = 10 + 2t^2[/tex]

A.

To find the change in velocity over the interval (2s ≤ t ≤ 5s), we can simply find the difference in the velocities at these times.

[tex]\Delta v= v_f - v_i[/tex]

For this situation:
[tex]\Delta v = v(5) - v(2)[/tex]

Substitute these times for 't' into the equation and solve.

[tex]v(5) = 10 + 2(5^2) = 60 \frac{cm}{s}\\\\v(2) = 10 + 2(2^2) = 18 \frac{cm}{s}\\\\\Delta v = 60 - 18 = \boxed{42 \frac{cm}{s}}[/tex]

B.

To find the average acceleration, we must take the SLOPE of the velocity function over this interval using the slope formula:

[tex]a_{avg} = \frac{v_f - v_i}{\Delta t}[/tex]

Plug in the values for the particle's velocity at t = 2 s and 5 s that we solved for above.

[tex]a_{avg} = \frac{60- 18}{5 - 2}\\\\a_{avg} = \frac{42}{3} = \boxed{ 14 \frac{cm}{s^2}}[/tex]

C.

The instantaneous acceleration can be found by taking the derivative of the v(t) function using the power rule. Recall:
[tex]\frac{dy}{dx} x^n = nx^{n-1}[/tex]

Using this rule:
[tex]a(t) = v'(t) = 2(2t) = 4t[/tex]

Substituting in t = 2 s:
[tex]a(2) = 4(2) = \boxed{8 \frac{cm}{s^2}}[/tex]

What is the magnitude of the gravitational force of attraction to Jupiter exerts on IO

Answers

The gravity force between Jupiter and Io will be 6.343 × 10²² N.

What is Newton's law of gravitation?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Given data;

Mass of Jupiter,[tex]\rm m_j = 1.9 \times 10^{27} \ kg[/tex]

Mass of moon of Jupiter,[tex]\rm m_{i_0}= 8.9 \times 10^{22} \ kg[/tex]]

The gravitational constant is,[tex]\rm G = 6.67 \times 10^{-11 } \ m^3 kg^{-1} s^{-2}[/tex]

Distance between Jupiter and Io, R = 421,700 km = 4,217,00,000 m

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

The gravitational force is found as;

[tex]\rm F = G \frac{ m_J m_{I_0}}{R^2} \\\\\ F = (6.67\times 10^{-11}) \frac{( (1.9\times 10^{27})\times (8.9\times 10^{22} )} { (421700000)^2}\\\\ F_g = 6.343 \times 10^{22} \ N[/tex]

Hence, the gravity force between Jupiter and Io will be 6.343 × 10²² N.

The complete question is

"Jupiter has a mass of 1.9 × 1027 kg, and its moon Io has a mass of 8.9 × 1022 kg. Their centers are separated by a distance of 421,700 km what is the force of gravity acting on Io? "

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Answer asap for brainlist

Answers

They use less wire, A

How to magnetic stripes provide evidence of seafloor spreading

Answers

Magnetic stripes provide evidence of seafloor spreading due to their occurrence in the region of sea floor.

How to magnetic stripes provide evidence of seafloor spreading?

When the Earth's magnetic field reverses, a new stripe starts to form. Such magnetic patterns enable the scientist to recognize the occurrence of sea-floor spreading and provides strongest evidence for the theory of plate tectonics.

So we can conclude that magnetic stripes provide evidence of seafloor spreading due to their occurrence in the region of sea floor.

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After the terrorist attacks of September 11th, 2001, the National Center on the Psychology of Terrorism was founded to research psychological aspects of terrorism. This is an example of how __________ affect theories and perspectives in psychology.
A.
current events
B.
new discoveries
C.
oppositions
D.
personal ideologies

Answers

reposta letra C oppositions

You drive 8.50 km in a straight line in a direction 30° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.

Answers

(a.1) The component of displacement along the East is  7.36 km.

(a.2) The component of displacement along the North is  4.25 km.

(b)  When the East and North legs are reversed in order, you will still travel 8.5 km.

Component of displacement along the East

dx = d cosθ

dx = 8.5 km x cos(30)

dx = 7.36 km

Component of displacement along the North

dy = d sinθ

dy = 8.5 km x sin(30)

dy = 4.25 km

When East and North legs are reversed;

dx = 4.25 km

dy = 7.36 km

Resultant displacement;

R = √(dx² + dy²)

R = √(4.25² + 7.36²)

R = 8.5 km

Thus, when the East and North legs are reversed in order, you will still travel 8.5 km.

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what type of forces that created at shaping machine

Answers

Answer:

a magnetic force

Explanation:

Other Questions
Each x block shown on the scale has the same weight. See if you can answer the question. When you have your answer, enter it in the box below and select Submit to see if you are correct. How Much Does Each "x" Weight Weigh? Suppose you spend time clipping coupons for cereal before going to the grocery store. However, once you arrive at the store you realize that the coupons have already expired. The time spent clipping coupons are an example of a ... what was one strong opposing point of the British politician? Will bought a new skateboard that was on sale. The original price of the skateboard was $60. The store had marked it down by 20 percent, and Will had a 25 percent off coupon as well. Explain how the wall thicknesses are related to the functions of the chambers. A compare-and-contrast essay should begin with _____.a paragraph that specifically details both the similarities and differences of all the features being considereda paragraph that introduces the subjects features and states the writers conclusiona paragraph that shows the similarities and differences in a block arrangement of specific details 100 students take a test. The mean score of the results is 88% with a standard deviation of 4%. Considering that the results were normally distributed, what is the median of the graph, what scores are within 2 standard deviations away, and how many student's scores would be within 1 standard deviation from the mean? Look at the image, read, and select the correct option.Two month calendar with la Fiesta Nacional de Espana highlighted in blue on the month after September, the day after the eleventh and after Wednesday, el primer dia de clases de K to 8 highlighted in yellow on the month before October, the day after the tenth, and the day after Sunday, el primer dia de clases de 9 to 12 highlighted in green on the month before October, the day after the fourteenth, and after Thursday.Cundo es el primer da de clases de K-8? El lunes, 11 de septiembre de 2017 El 11, Martes de septiembre de 2017 El Lunes, 11 de septiembre de 2017 El martes, Septiembre 11, de 2017 Calculate the height of stairs a 60 kg student would have to run in order to burn off 1 Calorie of food energy, which is the equivalent of 4190 Joules. Rewrite the expression as a fraction. Based on Agamemnons and Amphimedons speeches in The Odyssey - Amphimedon, how have the characters been changed by their deaths?Both show humility after their deaths.Neither has changed after their deaths.Both show great anger after their deaths.Neither has grown arrogant after their deaths Question,What is the main purpose of the Declaration of Independence?A. to disguise the real reasons for separation with Great BritainB. to convince people to think about the value of freedomC. to make an official statement of separation from Great BritainD. to describe personal feelings and ideas What is the y-value when x equals 23?y = 460 - 11(x) 3Read the following passage about President Hoover's policies.During his 1932 presidential re-election campaign, Republican President Herbert Hoover spoke out loudly against the New Deal programsproposed by his opponent, Democratic candidate Franklin D. Roosevelt. He claimed that Roosevelt's attempts to help people through times ofpoverty and hardship would create an unhealthy dependency on the government. During his time as president, Hoover responded to the BonusArmy's demand to be paid their bonuses for wartime service early by sending federal troops to attack them and burn their encampments. Manybelieve these were both factors in Hoover's loss of the 1932 election to Roosevelt.Which conclusion can you draw from this passage about Hoover's attitude toward direct federal ald?A He was against direct federal aid to American citizens.B. He was against direct federal aid to help big corporations.C. He supported direct federal aid to help big corporations.D. He supported direct federal aid to American citizens. HELP WILL GIVE BRAINLIEST AND THANKSsee the attached image The process which RNA polymerase binding together with one or more general transcription factor called... trigonometry is so hard help me during a client's vascular assessment, the nurse is palpating the pulse just under the client's inguinal ligament. the nurse is assessing which pulse? 13C and 14C are isotopes of 12C, which has 6 electrons, 6 protons, and 6 neutrons. What is the arrangement of subatomic particles in 14C?A. 6 electrons, 7 protons, and 6 neutronsB. 6 electrons, 7 protons, and 8 neutronsC. 6 electrons, 6 protons, and 8 neutrons What is the surface area of the cylinder below?