The student claims that the calculated concentration is too high because the filter paper and AgCl(s) precipitate were not fully dry. Do you agree or disagree?

Answers

Answer 1

I disagree, the presence of water would decrease rather then increase the concentration of the precipitate.

Would the concentration be too high?

We know that the term concentration has to do with the amount of substance that is present in a system. We know that water temds to reduce the concentration of a system. The more the amount water in the system, the less the amount of the substance in the system.

The filter paper is used to weigh the precipitate or the solid product that is obtained in the reaction. We know that the standard practice is that the filter paper ought to be dried and then we can then be able to weigh it and obtain the mass of the substances that was in the solution.

If the filter paper is not fully dry, we would have more amount of water in the system and this would reduce the amount of the AgCl thereby reducing the concentration rather than increase it.

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Related Questions

What is the correct equation in word form
Mg + AgNO3 ---> MgCI2 + Ag
Magnesium plus silver nitrate yields magnesium chloride and silver
Magnesium reacts with silver nitrate forming manganese chloride and silver
Manganese plus gold nitrate yields manganese chloride and gold
Magnesium reacts with silver nitride to form magnesium chloride and silver

Answers

Answer:

A

Explanation:

Name the following alkyl halides

Answers

The IUPAC nomenclature of compound 1 is 5-bromo-2-methylchloridepent-2-ene and the name for structure 2 is 5-iodo-hex-2-ene

IUPAC nomenclature is the method of naming the organic chemical compounds by following certain rules and criteria given by IUPAC.

This nomenclature is based on naming a molecules longest chain of carbons connected by single bonds, whether in a continuous or in ring form. Everything else like multiple bonds or atoms are other than carbon and hydrogen are indicated by prefixes or suffixes according to a specific set of priorities.

In structure 1 we can see that we are number so that the double bond that is present gets the least priority and then the naming is done in the alphabetic order. so the name is 5-bromo-2-methylchloridepent-2-ene

In structure 2 the same thing is followed and the name of the structure is

5-iodo-hex-2-ene

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What quantity in moles of chlorine gas at 120.0 °C and 33.3 atm would
occupy a vessel of 36.5 L?

Answers

The number of chlorine moles present in the vessel are 37.67 mol.

What are moles?

Moles are the number of substances present in a system which consists of entities like ions, atoms, or molecules as much as atoms in the weight of pure carbon which is 12 grams. It is the SI unit of amount of substance.

One mole of a substance is equal to the Avogadro Number which is equal to 6.022×10²³.

According to Ideal gas law,

PV=nRT where,

P= Pressure

V= Volume

n= number of moles

R= Ideal gas constant

T= temperature (in Kelvin)

n= PV/RT

⇒33.3×36.5/0.0821×393

⇒1215.45/32.2653

⇒37.670

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What is the normality of a solution of sulfuric acid (H2SO4) that containing 86 g
per liter of solution?

Answers

Normality of a solution of sulfuric acid (H2SO4) that containing 86 g

per liter of solution is 1N

What is normality?

The gram equivalent weight of a solute per liter of solution is what is known as a solution's normalcy. The comparable concentration is another name for it. The units of concentration are denoted by the symbols N, eq/L, or meq/L (= 0.001 N). A hydrochloric acid solution's concentration, for instance, could be stated as 0.1 N HCl. The reactive capacity of a specific chemical species is measured by gram equivalent weight or equivalent (ion, molecule, etc.). Utilizing the chemical species' molecular weight and valence, the equivalent value is calculated. The only concentration unit that is reaction-dependent is normality.

g equivalent mass of H2SO4 = 86g

Volume of solution in liter = 1 l

number of g equivalent of H2SO4 = 86/86 = 1

Normality = number of g equivalent/ volume of solution in liter

N = 1 / 1

Normality = 1 N

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What are some things you do to help you learn and remember new words and what they mean?

Answers

The following are some things you do to help you learn and remember new words and they mean:-

Learn in chunks and scripts.Visualize what the word or phrase looks like.

Reading is one of the only methods to teach vocabulary and normal learning is the approach that gives college students the possibility to exercise and grasp the stages of crucial reading that result in studying success and progressed word utilization.

One of the maximum impactful mastering techniques is allotted practice spacing out your analyzing over several brief intervals of time over several days and weeks. The only exercise is to work a quick time on every elegance every day.

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1. Outline a synthesis showing the necessary reagents and intermediate molecules for the following
transformation. For carbon sources, use alkyl halides with 4 or fewer carbons. You will need to use
more than one reaction.

Answers

A synthesis showing the necessary reagents and intermediate molecules for carbon sources, use alkyl halides with 4 or fewer carbons is zinc and copper pair in alcohol to reduced alkyl halide.

Which alkyl halide is more reactive ?

The Zn/Cu pair in alcohol is used to reduce alkyl halides. In alcohol, the Zn/Cu pair substitutes hydrogen for the halide of an alkyl halide to generate hydrocarbons. The Zn/Cu combination produces methane in alcohol by taking the iodine out of methyl halide and adding hydrogen.

Thus, a synthesis showing the necessary reagents and intermediate molecules for carbon sources, use alkyl halides with 4 or fewer carbons is zinc and copper pair in alcohol to reduced alkyl halide. Alkyl iodide is more reactive.

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Formation of crystals of sugar from a sugary syrup is a …….
chemical change.

Answers

Answer:

im pretty sure thats physical

Explanation:

10x-74=92
answer for algebra

Answers

10x - 74 = 92  --->  (Add 74 to both sides. This gets rid of the 74)

     + 74   +74

10x = 166   --->  (Simplify. The 74 you added to the 92 becomes 166)

10x/10 = 166/10    ---> (Divide both sides by 10. This gets the x by itself)

v(Simplify)v

x = 83/5    OR    x = 16.6

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