The symmetrical load below is connected to a three-phase network. A line current of 25A has been measured. The load resistors have a value of 18 Ω.
What is the line voltage of the three-phase network?

The Symmetrical Load Below Is Connected To A Three-phase Network. A Line Current Of 25A Has Been Measured.

Answers

Answer 1

Answer:

The line voltage of the three phase network is 346.41 V

Explanation:

Star Connected Load

Resistance, R₁ = R₂ = R₃ = 18 Ω

For a star connected load, the line current = the phase current, that is we have

[tex]I_L = 25 \, A = I_{Ph}[/tex]

Whereby the the voltage across each resistance = [tex]V_R[/tex] is given by the relation;

[tex]V_R[/tex] = [tex]I_{Ph}[/tex] × R

Hence;

[tex]V_{Ph}[/tex] = [tex]V_R[/tex] = [tex]I_{Ph}[/tex] × R  = 25 × 8 = 200 V

Therefore we have;

The line voltage, [tex]V_{L}[/tex] = √3 × [tex]V_{Ph}[/tex] = √3 × 200 = 346.41 V.

Hence, the line voltage of the three phase network = 346.41 V.


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