the thermometer you use to measure the freezing temperature of the solvent actually records a temperature that is 0.12c too high. unfortunately you break this thermometer and borrow a fellow students thermometer, which reads 0.11c too low. if the molality of your solution is 0.30, calculate the contribution to the percentage error in your result due to not correcting for the errors in the thermometer readings.

Answers

Answer 1

The contribution to the percentage error in the freezing point depression due to the errors in the thermometer readings is 1.76%.

The freezing point depression is a colligative property that depends only on the molality of the solute particles in a solution and is independent of the identity of the solute. Therefore, the freezing point depression is given by the equation:

ΔTf = Kf x molality

where ΔTf is the change in the freezing point, Kf is the freezing point depression constant for the solvent, and molality is the concentration of solute particles in moles per kilogram of solvent.

However, in this case, there are errors in the thermometer readings that can contribute to the uncertainty in the calculated freezing point depression. The errors are +0.12°C for the initial thermometer and -0.11°C for the borrowed thermometer.

The total error due to thermometer readings is the sum of the errors from both thermometers, which is:

Total error = +0.12°C - 0.11°C = +0.01°C

The percentage error due to the thermometer readings can be calculated as:

Percentage error = (total error / measured freezing point) x 100%

The measured freezing point is the sum of the actual freezing point depression and the error due to the thermometer readings. Assuming that the actual freezing point depression was accurately measured, the measured freezing point can be expressed as:

Measured freezing point = actual freezing point depression + total error

Since the molality of the solution is given as 0.30, the actual freezing point depression can be calculated using the freezing point depression constant for the solvent.

Assuming a typical freezing point depression constant for the water of 1.86°C/m, the actual freezing point depression would be:

actual freezing point depression = Kf x molality = 1.86°C/m x 0.30 mol/kg = 0.558°C

Therefore, the measured freezing point would be:

Measured freezing point = actual freezing point depression + total error = 0.558°C + 0.01°C = 0.568°C

The percentage error due to the thermometer readings would be:

Percentage error = (total error / measured freezing point) x 100% = (0.01°C / 0.568°C) x 100% = 1.76%

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Related Questions

an analytical chemist is titrating of a solution of ethylamine with a solution of . the of ethylamine is . calculate the ph of the base solution after the chemist has added of the solution to it. note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of solution added. round your answer to decimal places.

Answers

The pH of the base solution at the equivalence point is 11

To solve this problem, we need to use the principles of acid-base titration. Since ethylamine is a weak base, it will react with the strong acid solution to form its conjugate acid, ethylammonium ion.

We can start by writing the balanced chemical equation for the reaction between ethylamine (C2H5NH2) and hydrochloric acid (HCl):

C2H5NH2 + HCl → C2H5NH3+Cl-

From this equation, we can see that one mole of ethylamine reacts with one mole of HCl to form one mole of ethylammonium chloride (C2H5NH3+Cl-).

The next step is to calculate the number of moles of ethylamine that are present in the initial solution. We can use the formula:

moles = concentration x volume

Substituting the given values, we get:

moles of C2H5NH2 = 0.15 M x volume of C2H5NH2

Since we don't know the volume of the ethylamine solution, we can't calculate the moles of ethylamine yet. However, we can use the fact that when the solution is titrated with the HCl solution, the number of moles of HCl added will be equal to the number of moles of ethylamine present in the solution at the equivalence point. This is because all the ethylamine will react with the HCl to form ethylammonium ion.

We can therefore set up the equation:

moles of HCl added = moles of C2H5NH2 initially present

Since we know the concentration and volume of the HCl solution added, we can calculate the moles of HCl added:

moles of HCl added = 0.25 M x 0.03 L = 0.0075 moles

Substituting this value into the equation above, we get:

0.0075 moles = 0.15 M x volume of C2H5NH2

Solving for the volume of C2H5NH2, we get:

volume of C2H5NH2 = 0.0075 moles / 0.15 M = 0.05 L = 50 mL

Now that we know the volume of the ethylamine solution, we can calculate the concentration of ethyl ammonium ion at the equivalence point. Since the reaction between ethylamine and HCl is a 1:1 reaction, the moles of ethyl ammonium ion formed will also be 0.0075 moles. We can use the formula:

concentration = moles / volume

Substituting the given values, we get:

concentration of C2H5NH3+ = 0.0075 moles / 0.1 L = 0.075 M

Finally, we can calculate the pH of the solution at the equivalence point. Since ethylammonium ion is the conjugate acid of the weak base ethylamine, we can use the Henderson-Hasselbalch equation:

pH = pKa + log([C2H5NH3+]/[C2H5NH2])

The pKa of ethylamine is approximately 10.6, so we can substitute this value and the concentration of ethylammonium ion into the equation:

pH = 10.6 + log(0.075/0.075)

Simplifying the equation, we get:

pH = 10.6 + log(1)

pH = 10.6

pH = 10.6 ≈ 11.

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What is the role of entropy in a combustion reaction?

Answers

In a combustion reaction, entropy plays a role in determining the direction of the reaction and the amount of heat released.

What is the second law of the thermodynamics?

According to the second law of thermodynamics, a reaction is favored if it leads to an increase in the overall entropy of the system. In a combustion reaction, the breaking of chemical bonds in the reactants leads to the formation of new bonds in the products, resulting in an increase in the number of microstates and entropy.

The heat released in the reaction also contributes to the increase in entropy. As a result, combustion reactions are generally exothermic and spontaneous.

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What is the concentration of Cl2(g), in parts per billion, in a solution that contains 0.003 g of Cl2(g) dissolved in 1000. g of H2O(l)?
A 3.0 x 10^3 ppb
B 3.0 x 10^2 ppb
C 3.0 x 10^-3 ppb
D 3.0 x 10^-2 ppb
Can someone tell me why A is the correct one?

Answers

A is the correct answer because 0.003 g of Cl2(g) dissolved in 1000. g of H2O(l) is equivalent to 3 parts per million (ppm) of Cl2(g). Since 1 ppm is equivalent to 1,000 ppb, the concentration of Cl2(g) in the solution is 3,000 ppb.

What is equivalent?

Equivalent means having the same value, amount, or degree. It can also refer to two or more things that are equal in value, quantity, or function. For example, one dollar is equivalent to 100 pennies; one hour is equivalent to sixty minutes; a square and a rectangle are equivalent shapes. Equivalent can also be used to refer to things that are equal in rank, importance, or value, such as when two people are considered to be of equivalent intelligence or skill.

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if a compound is being made with 1 tablespoon of hydrocodone solution and 2 tablespoons of cherry flavoring, how would the ratio be written?

Answers

The ratio of hydrocodone answer for cherry seasoning in the compound can be composed as:

1:2.

The proportion of hydrocodone answer for cherry enhancing in the compound is 1:2. This implies that how much hydrocodone arrangement is utilized is half of how much cherry enhancing is utilized. Proportions are an approach to looking at least two amounts, and they are commonly communicated as a small portion or with a colon. For this situation, the proportion is communicated utilizing a colon to isolate the two amounts. Proportions can be utilized in various settings, from cooking to science to back. In this particular case, the proportion is utilized to guarantee that the perfect proportion of every fixing is being utilized to make the ideal compound.

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if the rate of appearance of no2 is equal to 0.560 mol/min at a particular moment, what is the rate of appearance of o2 at that moment?

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the rate of appearance of O2 at that particular moment would be 0.280 mol/min for  no2 is equal to 0.560 mol/min at a particular moment.

The balanced chemical equation for the reaction that produces NO2 and O2 would be helpful to answer this question. Assuming the reaction is:

2 NO → 2 NO2 + O2

The stoichiometry of the reaction tells us that for every 2 moles of NO that disappear, 2 moles of NO2 and 1 mole of O2 are produced. Therefore, the rate of appearance of O2 would be half the rate of appearance of NO2, or:

Rate of appearance of O2 = (0.560 mol/min) / 2 = 0.280 mol/min

So the rate of appearance of O2 at that particular moment would be 0.280 mol/min.

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what is the difference between a relative, absolute, and mixed cell reference? write three formulas, one illustrating each type of cell reference.

Answers

Generally, relative cell references contain no dollar signs (i.e., A1) whereas mixed cell references have dollar signs attached to either the letter or the number in a reference but not both (i.e., $A1 or A$1) and absolute cell references have dollar signs attached to each letter or number in a reference (i.e., $A$1).

Relative, absolute and mixed cell references are the three types of cell references used in Excel: relative, absolute and mixed. While writing a formula for a single cell, we can go with any type.

We have learned that cell references can be relative, absolute or mixed. The type we use in a formula is important, as each behaves differently when copied or moved. We learned that relative cell references change based on where you copy them and that absolute references do not change.

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Why does each element have its own unique atomic line spectrum, when all atoms have energy levels labeled 1s,2s,2p,3s,etc.?

Answers

In quantum mechanics, an atomic orbital is a mathematical function that describes the wave-like behavior of either one electron or a pair of electrons in an atom.

This function can be used to calculate the probability of finding any electron of an atom in any specific region around the atom's nucleus. The term, atomic orbital, may also refer to the physical region or space where the electron can be calculated to be present, as defined by the particular mathematical form of the orbital.

Each orbital in an atom is characterized by a unique set of values of the three quantum numbers n, ℓ, and m, which respectively correspond to the electron's energy, angular momentum, and an angular momentum vector component (the magnetic quantum number). Each such orbital can be occupied by a maximum of two electrons, each with its own spin quantum number s. The simple names s orbital, p orbital, d orbital and f orbital refer to orbitals with angular momentum quantum number ℓ = 0, 1, 2 and 3respectively. These names, together with the value of n, are used to describe the electron configurations of atoms. They are derived from the description by early spectroscopists of certain series of alkali metal spectroscopic lines as sharp, principal, diffuse, and fundamental. Orbitals for ℓ > 3 continue alphabetically, omitting j (g, h, i, k, …) because some languages do not distinguish between the letters "i" and "j".

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What is the empirical formula for the molecular formula given?
Molecular formula: C5H120
OC₂H6O
OCH5O
O C3H6O
O C5H12 O

Answers

The empirical formula for the molecular formula given is C₅H₁₂O as the subscripts cannot be reduced further.

What is empirical formula?

Empirical formula of a compound is defined as the simplest whole number ratio of atoms which are present in a compound.It does not make any mention of the arrangement of atoms or the number of atoms. The empirical formula gives information about the ratio of number of atoms which are present in a compound.

Molecular formula is determined from the empirical formula by dividing the molar mass of a compound by the empirical formula mass. The resultant which should be a whole number or very close to the whole number , then the subscripts are multiplied by the whole number to get the molecular formula.

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How do you calculate moles of EDTA titration?

Answers

To calculate the moles of EDTA (ethylenediaminetetraacetic acid) in a titration, you need to know the volume and concentration of the EDTA solution used in the titration, as well as the reaction stoichiometry.

The reaction between EDTA and a metal ion typically forms a complex, in which one mole of EDTA reacts with one mole of the metal ion. Therefore, the number of moles of EDTA can be calculated using the following formula:

moles of EDTA = (volume of EDTA solution in liters) * (concentration of EDTA solution in Molarity)

For example, if you used 25.0 mL of 0.02 M EDTA solution in a titration, the number of moles of EDTA would be:

moles of EDTA = (25.0 mL * 0.001 L/mL) * (0.02 mol/L) = 0.0005 mol.

Once you have calculated the number of moles of EDTA, you can use the stoichiometry of the reaction to determine the number of moles of metal ion in the sample being titrated.

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for a reaction that starts with 2.2 moles of no 2 gas in a 0.40 l container, what is the concentration of n 2o 4 in the container after one half-life of the reaction? give your answer in units of mol/l with two significant figures

Answers

Rounding to two significant figures, the concentration of N2O4 in the container after one half-life of the reaction is 1.4 mol/L.

The balanced equation shows that 2 moles of NO2 react to form 1 mole of N2O4. Therefore, the number of moles of N2O4 that are formed during the reaction will be half of the number of moles of NO2 that react.

After one half-life of the reaction, half of the NO2 will have reacted. Therefore, the number of moles of NO2 remaining in the container will be: 2.2 mol / 2 = 1.1 mol

Since 2 moles of NO2 react to form 1 mole of N2O4, the number of moles of N2O4 that are formed will also be half of the number of moles of NO2 that reacted, which is 1.1/2 = 0.55 mol.

The volume of the container is 0.40 L, so the concentration of N2O4 in the container will be:

C(N2O4) = moles of N2O4 / volume of container

= 0.55 mol / 0.40 L

= 1.4 mol/L

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What is the definition of an ionic bond?

Answers

Answer:

An ionic bond is a type of chemical bond formed by the attraction of two ions with opposite charges.

Explanation:

Answer:

An ionic bond is a type of chemical bond formed by the attraction of two ions with opposite charges. This bond is formed when a metal cation loses electrons to a nonmetal anion, resulting in the formation of positively and negatively charged ions that are attracted to each other.

Explanation:

a) Calculate the pH of a 0.1 mol/L solution of hydrosulfuric acid [4 marks]

b) Calculate the concentration of H3O+ present in this solution (2 marks)

Answers

Answer:

a) The pH of a 0.1 mol/L solution of hydrosulfuric acid is 1.00.

b) The concentration of H3O+ present in this solution is 0.1 mol/L.

Answer:

A) To calculate the pH of a 0.1 mol/L solution of hydrosulfuric acid (H2S), we can first calculate the concentration of hydronium ions (H3O+) produced in solution.

Hydrosulfuric acid dissociates in water according to the following equation:

H2S + H2O → H3O+ + HS-

Since the concentration of hydrosulfuric acid is 0.1 mol/L, the concentration of hydronium ions produced will also be 0.1 mol/L.

Next, we can use the concentration of hydronium ions to calculate the pH of the solution:

pH = -log[H3O+] = -log(0.1) = 1

So, the pH of a 0.1 mol/L solution of hydrosulfuric acid is 1.

B) The concentration of H3O+ present in the solution is 0.1 mol/L.

Explanation:

ALLEN

Given the balanced equation:
2Al(s) + 6H+ (aq) -----> 2Al^3+ (aq) + 3H2(g)
What is the total number of moles of electrons gained by H+ (aq) when 2 moles of Al(s) are completely reacted?
1) 6
2) 2
3) 3
4) 12

Answers

The total number of moles of electrons transferred from Al to H⁺ is 6

The given reaction can be split up into two half-reactions as follows:

2 Al (s) → 2 Al³⁺ (aq) + 6 e⁻

6 H⁺ (aq) + 6 e⁻ → 3 H₂ (g)

From the first half-reaction, it is clear that 2 moles of Al give out 6 moles of electrons to become Al³⁺.

From the second half reaction, it is clear that these 6 moles of electrons are accepted by H⁺ to become H₂ gas.

What is a half-reaction?

A half reaction is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction

How does half-reaction work?

In general, the half-reactions are first balanced by atoms separately. Electrons are included in the half-reactions. These are then balanced so that the number of electrons lost is equal to the number of electrons gained. Finally, the two half-reactions are added back together.

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Answer:

3

Explanation:

because i did this when i was a kid

Aqueous barium nitrate reacts with aqueous iron (Il) sulfate

Write the
Balanced equation
Complete Ionic
Net ionic

Answers

Answer:

Balanced equation:

The balanced chemical equation for the reaction between aqueous barium nitrate and aqueous iron(II) sulfate is:

Ba(NO3)2(aq) + FeSO4(aq) → BaSO4(s) + Fe(NO3)2(aq)

Complete Ionic equation:

The complete ionic equation for the reaction between aqueous barium nitrate and aqueous iron(II) sulfate is:

Ba^2+(aq) + 2NO3^-(aq) + Fe^2+(aq) + SO4^2-(aq) → BaSO4(s) + Fe^2+(aq) + 2NO3^-(aq)

Net Ionic equation:

The net ionic equation is obtained by cancelling out the spectator ions (ions that appear on both sides of the equation and do not participate in the reaction) from the complete ionic equation. The spectator ions in this case are Ba^2+ and 2NO3^-. The net ionic equation for the reaction between aqueous barium nitrate and aqueous iron(II) sulfate is:

Fe^2+(aq) + SO4^2-(aq) → BaSO4(s)

The specific heat of copper is 0.385 J/g °C. How much thermal energy is required to increase the temperature of a 20g sample of copper from 20°C to 50°C? a. 154 J
b. 385 J c. 308 J
d. 231 J

Answers

The amount of thermal energy required to increase the temperature of the 20 g sample of copper from 20°C to 50°C is 231 J, which corresponds to option (d).

The amount of thermal energy required to increase the temperature of a substance can be calculated using the formula:

Q = m x c x ∆T

where Q is the thermal energy (in joules), m is the mass of the substance (in grams), c is the specific heat of the substance (in joules/gram°C), and ∆T is the change in temperature (in °C).

In this case, we are given that the specific heat of copper is 0.385 J/g°C, the mass of the copper sample is 20 g, and the temperature change is from 20°C to 50°C. Substituting these values into the formula, we get:

Q = 20 g x 0.385 J/g°C x (50°C - 20°C)

Q = 20 g x 0.385 J/g°C x 30°C

Q = 231 J

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A neutral atom is an atomic number of 15, what is the likely arrangement of electrons

Answers

There are 15 total electrons in an uncharged phosphorus atom. There are two electrons that can fit into the first shell, eight in the second, and five more in the third. There are 5 valence electrons in the third shell because it is the outer valence shell.

So, with the element PHOSPHORUS, you already know that the atomic number indicates how many electrons there are. Accordingly, an atom of phosphorus contains 15 electrons. Another way to respond to this query is by expressing the electron arrangement of a neutral phosphorus atom, which has 15 electrons: 1s22s22p63s23p3. A 15th atomic-number element will have the electrical configuration 2, 8, 5. The "k" shell has two electrons, the "l" shell has eight, and the "m" shell has five, respectively. Five valence electrons make up this atom.

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which one of the following is an intensive property? question 4 options: number of moles nk of substance k in the system. the product pv in a system. molar enthalpy hm of a system (defined as the ratio of the enthalpy of the system over the total number of moles in the system). volume v of the system. internal energy u of the system

Answers

Enthalpy molar is an intense property of a system is its Hm, which is calculated as the system's enthalpy divided by the sum of its moles. Hence, option D is the correct answer.

A thermodynamic feature known as an intense property does not depend on the mass of a system. Pressure, temperature, density, particular volume, specific internal energy, specific enthalpy, and specific entropy are a few examples of intense properties. A property is called as an extensive property which depends on the quantity of the materials in a sample.

Mass and volume are two examples of extensive qualities. Intense properties are those that are unaffected by the substance's concentration. For example, temperature and pressure are strong characteristics. Enthalpy, energy, and volume are all significant qualities. Contrarily, intensive qualities, such as colour, melting point, boiling point, electrical conductivity, and physical state at a certain temperature, are independent of the amount of the substance present.

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Correct Question:

Which one of the following is an intensive property?

(A) Internal energy U of a system.

(B) Volume V of a system.

(C) Number of moles [tex]n_{k}[/tex] of a substance k in a system.

(D) Molar enthalpy Hm of a system (defined as the ratio of the enthalpy of the system over the total number of moles in the system).

(E) The product pV for a system.

Fill The Blank? one mole of the ionic compound, nacl, will dissolve into _ _ _ _ _ _ _ moles of particles in aqueous solution.

Answers

one mole of NaCl will dissolve into two moles of particles (one mole of Na+ ions and one mole of Cl- ions) in aqueous solution.

When one mole of the ionic compound NaCl dissolves in aqueous solution, it dissociates into its constituent ions, Na+ and Cl-. Therefore, one mole of NaCl will dissolve into two moles of particles (one mole of Na+ ions and one mole of Cl- ions) in aqueous solution.

When one mole of NaCl dissolves in water, it will dissociate into one mole of Na+ ions and one mole of Cl- ions, resulting in a total of two moles of particles. This is because each molecule of NaCl produces two ions upon dissociation.

In an aqueous solution, these ions are surrounded by water molecules, which interact with the ions through ion-dipole forces, stabilizing them and preventing them from recombining into the original NaCl crystal. The resulting solution contains a mixture of hydrated Na+ and Cl- ions, and the concentration of these ions depends on the initial concentration of NaCl and the degree of dissociation.

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Cice = 2.10 J/g·°C, Cwater = 4.18 J/g·°C,
Csteam = 2.08 J/g·°C, ∆Hfus = 6.01 kJ/mol,
∆Hvap = 40.68 kJ/mol.
Find the value for q when 15.0 g water freezes.

Answers

The heat absorbed when 15.0 g of water freezes is 5.01 kJ.

What is heat absorbed ?

Chemical reaction or physical change is endothermic if heat is absorbed by the system from the surroundings.

The heat absorbed or released during a phase change can be calculated using the equation q = mL,

where

m is the mass of the substance undergoing the change L is its heat of fusion or vaporization.

For the case of 15.0 g of water freezing, the heat absorbed can be calculated as follows:

q = mL

q = (15.0 g) * (6.01 kJ/mol) / (18.015 g/mol)

q = 5.01 kJ

Therefore, the heat absorbed when 15.0 g of water freezes is 5.01 kJ.

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list essential conditions for pressure

Answers

The essential conditions for pressure are high temperature and minimum volume.

What is pressure?

Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.

There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .

It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.

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7) Using the following balanced equation 4 Fe(s) + 302(g) → 2Fe2O3(s)
a) How many moles of product would be produced by complete reaction of 0.15 moles of iron? (Be sure to show
your work including the mole ratio you used)

Answers

Answer:

0.075 moles

Explanation:

Looking at the balanced equation, 4 moles of Fe(s) react with 3 moles of [tex]O_{2}[/tex] to produce 2 moles of [tex]Fe_{2}O_{3}[/tex] (s). In other words, for every 4 moles of Fe(s) used, there are 2 moles of product. The mole ratio is therefore 4:2, or 2:1. In other words, you divide the moles of Fe by two to find the moles of product.

There are 0.15 moles of Fe, so the moles of product should be half of this according to the molar ratio.

0.15 / 2 = 0.075

Your answer is 0.075 moles.

Hope this helps!

assuming both forward and reverse reactions are elementary processes, which reaction has the larger rate constant: the forward or the reverse reaction?

Answers

Assuming that both the forward and reverse reactions are the elementary processes, the reaction has the larger rate constant is the reverse reaction.

The elementary reaction is as follows :

Cl₂(g) ⇌ 2Cl(g)

The  reaction that has the greater rate constant is the reverse reaction.

K c = k f / k r

If the Kc is small, the k reverse is the larger than the k forward.

An elementary reaction is defined as the  chemical reaction in which the one or the more chemical species will react directly to form the products in the single reaction step. Therefore the reverse will have the larger rate constant.

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This question is incomplete, the complete question is :

The equilibrium constant for the dissociation of molecular chlorine, Cl2(g)⇌2Cl(g), at 200 ∘C is Kc=0.0168.

Assuming both forward and reverse reactions are elementary processes, which reaction has the larger rate constant: the forward or the reverse reaction?

Polyethylene pipe is used to operate under low pressure, typically 10 to 20 psi.
a. True
b. False

Answers

It is true that polyethylene pipe performs optimally at low pressures of 10 to 20 psi.

What is the pressure rating of the polyethylene pipe?

PE pipes can be utilized in a range of temperature of -40 oC to 60 oC taking into account the change of operating pressure. The nominal pressure class, and PN, up to PN 20 or 20 bar, is frequently used in the standard specification of HDPE pipes to identify their class.

Is PVC pipe the same as polyethylene pipe?

PVC is a long-lasting vinyl polymer, whereas HDPE is a petroleum-based polyethylene thermoplastic. Both pipes withstand high temperatures with strength. HDPE has been shown to be more durable when comparing failure ratings when subjected to conditions like rain, stress, wind, heat, or cold.

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The best performance for polyethylene pipe occurs at low pressures of 10 to 20 psi, it is true.

The polyethylene pipe's pressure rating is what?

When operating pressure changes, PE pipes are suitable for temperatures between -40 oC and 60 oC. To describe the class of HDPE pipes, the nominal pressure class, and PN, up to PN 20 or 20 bar, is usually used.

PVC and polyethylene pipes are the same, right?

HDPE is a polyethylene thermoplastic made from petroleum, while PVC is a vinyl polymer with a long shelf life. The robustness of these pipes allows them to resist high temperatures. Comparing failure ratings in adverse situations like rain, stress, wind, heat, and chemicals has revealed HDPE to be more robust.

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g if you dissolve 20 g of dextrose in 500 ml of dh2o, what is the concentration of dextrose in mm? (fw dextrose

Answers

Concentration of dextrose in mM is [tex]0.2222 mM[/tex]

Dextrose is a form of glucose, which is a type of sugar. It is naturally occurring in fruits, vegetables, and honey. It is also used as an ingredient in processed foods, such as breads, cereals, and candy, as well as in medical products, such as IV solutions and medical nutrition products.

The following formula may be used to determine the dextrose concentration in mM:

Mass of dextrose = [tex]20 g[/tex]

Volume of the solution =[tex]500 mL[/tex]

Molar mass of dextrose = [tex]180.156 g/mol[/tex]

Moles of dextrose =[tex]\frac{ (20 g)}{(180.156 g/mol)} = 0.1111 mol[/tex]

Concentration of dextrose in mM = [tex]\frac{ (0.1111 mol)}{(500 mL)} = 0.2222 mM[/tex]

Therefore, The Concentration of dextrose in mM is [tex]0.2222 mM[/tex]

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What level of protein structure describes the spatial location of every atom in a protein? Choose one: A. 0'
B. 2'
C. 1'
D. 3'

Answers

The answer would be D

how many liters of Hn3 are needed to react completely with 30.0L of NO?

Answers

Answer:

15.0 liters of HN3 are needed to react completely with 30.0 liters of NO.

Explanation:

The amount of HN3 required to react completely with a given volume of NO can be determined by using the balanced chemical equation for the reaction. The reaction between HN3 and NO is given by:

4 HN3 + 5 NO → 4 HNO3 + N2

From the equation, we can see that for every 4 moles of HN3 that react, 5 moles of NO are consumed. To determine the amount of HN3 needed to react with a given volume of NO, we can convert the volume of NO to moles and then use the stoichiometry of the reaction to find the number of moles of HN3 required.

For example, if we have 30.0 liters of NO, we can convert it to moles using the ideal gas law:

30.0 L NO * (1 mole NO / 22.4 L) = 1.34 moles NO

Next, we can use the stoichiometry of the reaction to find the number of moles of HN3 required:

1.34 moles NO / (5 moles NO / 4 moles HN3) = 0.67 moles HN3

Finally, we can convert the number of moles of HN3 to liters:

0.67 moles HN3 * (22.4 L HN3 / 1 mole HN3) = 15.0 L HN3

Therefore, 15.0 liters of HN3 are needed to react completely with 30.0 liters of NO.

What mass of Fe and CO₂ could be formed by the reaction of 0.22 mol of Fe₂O₃ with 5.5 mol of CO?
This question also has a drop-down box for both Fe and CO2 for their answer choices:
Fe:
-25g Fe
-68g Fe
-12g Fe
-49g Fe
-210g Fe
CO2:
-240g CO2
-29g CO2
-15g CO2
-81g CO2
-58g CO2

Answers

maximum amount of Fe and CO2 that can be produced is:
0.44 mol Fe x 55.85 g/mol = 24.6 g Fe
0.66 mol CO2 x 44.01 g/mol = 29.0 g CO2

The balanced chemical equation for the reaction of Fe2O3 with CO is:
Fe2O3 + 3CO → 2Fe + 3CO2
From the equation, we can see that 1 mol of Fe2O3 reacts with 3 mol of CO to produce 2 mol of Fe and 3 mol of CO2.
Given that 0.22 mol of Fe2O3 and 5.5 mol of CO are available, we need to determine the limiting reactant to calculate the maximum amount of Fe and CO2 produced.
The limiting reactant is the reactant that is completely consumed in the reaction. To find it, we can compare the amount of Fe and CO2 that can be produced from each reactant.
Fe2O3: 0.22 mol Fe2O3 x (2 mol Fe / 1 mol Fe2O3) = 0.44 mol Fe
0.22 mol Fe2O3 x (3 mol CO2 / 1 mol Fe2O3) = 0.66 mol CO2

CO: 5.5 mol CO x (2 mol Fe / 3 mol CO) = 3.67 mol Fe
5.5 mol CO x (3 mol CO2 / 3 mol CO) = 5.5 mol CO2.
the molar masses of Fe and CO2 to convert from moles to grams.

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how much of a 10mg/ml chloramphenicol stock solution do we need to make 500ml of growth media that has final 10ug/ml concentration of chloramphenicol?

Answers

The amount of a 10mg/ml chloramphenicol stock solution we need to make the 500ml of growth media that has final 10ug/ml concentration of chloramphenicol is 0.5 mL

The concentration of the chloramphenicol = 10ug / mL = 10 × 10⁻⁶ g/mL

The mass of the chloramphenicol = 10 × 10⁻⁶ × 500

The mass of the chloramphenicol  = 0.005 g

The concentration  of the chloramphenicol = 10ug/mL = 10 × 10⁻³ g/mL

The volume of the chloramphenicol = 0.005 g / 10 × 10⁻³ g/mL

The volume of the chloramphenicol = 0.5 mL

Thus, the The volume of the chloramphenicol stock solution is 0.5 mL.

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Reaction types quiz,

Answers

I believe it is the first option!!!!!

a chemist Burns 100.0g chromium (Cr) in Excess oxygen (O). There is only one product, and it has a mass of 192.31g. what is the empirical formula of the product? Burning is a reaction with oxygen. Since there is only one product, it must have both Cr and O. We started with 100.0g CR. Anything over 100.0g must be O that was added. What is the mass of O?

Answers

Answer:

CrO3.

Explanation:

The mass of O in the product can be calculated as follows:

Mass of product - mass of Cr = mass of O

192.31 g - 100.0 g = 92.31 g

Next, we'll calculate the number of moles of Cr and O in the product:

Moles of Cr = mass of Cr / molar mass of Cr = 100.0 g / 51.996 g/mol = 1.922 mol

Moles of O = mass of O / molar mass of O = 92.31 g / 15.999 g/mol = 5.77 mol

Finally, we'll divide each mole by the smallest number of moles, which is 1.922 mol:

Moles of Cr / 1.922 = 1.000 mol

Moles of O / 1.922 = 3.000 mol

So, the empirical formula of the product is CrO3.

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