Answer:
A. 1.8 ×[tex]10^{30}[/tex] Kg
B i. 3.0 × [tex]10^{17}[/tex] seconds
ii. 9.6 × [tex]10^{9}[/tex] years
C. After 9.2 × [tex]10^{9}[/tex] (9.2 billion) years
Step-by-step explanation:
Given that the mass of the Sun = 2× [tex]10^{30}[/tex] Kg.
Mass of hydrogen when Sun was formed = 76% of 2× [tex]10^{30}[/tex] Kg
= [tex]\frac{76}{100}[/tex] ×2× [tex]10^{30}[/tex] Kg
= 1.52 × [tex]10^{30}[/tex] Kg
Mass of hydrogen available for fusion = 12% of 1.52 × [tex]10^{30}[/tex] Kg
= [tex]\frac{12}{100}[/tex] × 1.52 × [tex]10^{30}[/tex] Kg
= 1.824 ×[tex]10^{30}[/tex] Kg
A. Total mass of hydrogen available for fusion over the lifetime of the sun is 1.8 ×[tex]10^{30}[/tex] Kg.
B. Given that the Sun fuses 6 × [tex]10^{11}[/tex] Kg of hydrogen each second.
i. The Sun's initial hydrogen would last;
[tex]\frac{1.8*10^{30} }{6*10^{11} }[/tex]
= 3.04 × [tex]10^{17}[/tex] seconds
The Sun's hydrogen would last 3.0 × [tex]10^{17}[/tex] seconds
ii. Since there are 31536000 seconds in a year, then;
The Sun's initial hydrogen would last;
[tex]\frac{3.04*10^{17} }{31536000}[/tex]
= 9.640 × [tex]10^{9}[/tex] years
The Sun's hydrogen would last 9.6 × [tex]10^{9}[/tex] years.
C. Given that our solar system is now about 4.6 × [tex]10^{9}[/tex] years, then;
[tex]\frac{9.6*10^{9} }{4.6*10^{9} }[/tex]
= 2.09
So that; 2 × 4.6 × [tex]10^{9}[/tex] = 9.2 × [tex]10^{9}[/tex] years
Therefore, we need to worry about the Sun running out of hydrogen for fusion after 9.2 × [tex]10^{9}[/tex] years.
Part(A): The total mass of hydrogen available 9.6 billion years.
Part(B): The total time is 5.10 billion years.
Part(D): The hydrogen will last [tex]5.04\times 10^9 \ years[/tex]
Mass of the sun:Our sun is the largest object in our solar system. The mass of the sun is approximately [tex]1.988\times 1030[/tex] kilograms
Part(A):
Given that,
The total mass of the Sun =[tex]2\times10^{30} kg[/tex]
Mass of hydrogen in Sun = [tex]2\times10^{30} \times0.76\ kg[/tex]
The mass of hydrogen ever available for fusion is,
[tex]2\times10^{30} \times 0.76 \times 0.12 kg = 1.824\times 10^{29}[/tex]
Mass of hydrogen fuses each second = 600 billion kg/second.
Time hydrogen will last in seconds=[tex]1.824\times 10^{29}seconds.[/tex]
[tex]= 0.00304\times 10^{29 }= 3.04\times 10^{17}.[/tex]
Time hydrogen will last in seconds =[tex]1 year = 31,536,000 seconds.[/tex]
[tex]31,536,000 x = 3.04\times 10^{17} = 9.6 \ billion \ years.[/tex]
(B) Present age of sun = [tex]9.6-4.5 \ billion \ years[/tex]
The time when we need to worry about Sun running out of hydrogen for fusion = 5.10 billion years.
(D) The solar system is 4.6 billion years old that is [tex]4.6\times 10^9\ years[/tex]
And in part (B) we have calculated that hydrogen will last [tex]9.64\times 10^9[/tex] then,
[tex]9.64\times 10^9-4.6\times 10^9=5.04\times 10^9[/tex]
Learn more about the topic mass of the sun:
https://brainly.com/question/11359658
what is the diagonal of asquare with length 3cm
Answer:
3√2
Step-by-step explanation:
If you draw the diagonal, you have a 45°45°90° triangle.
The two legs are 3, so the hypotenuse is 3√2
Help asap giving branlist!!!
Answer:
Option A.
The heartbeat has a pattern of 60 + (5 x minutes) and linear graphs are straight. The only way the linear graph is straight if there is a pattern.
Step-by-step explanation:
Please answer this correctly
Answer:
Area of the figure = 254.5 cm²
Step-by-step explanation:
Area of rectangle = Length × Width
Area of triangle = 1/2(base × Height)
Dividing the figure into parts for convenience
So,
Rectangle 1 (the uppermost):
4 × 6 = 24 cm²
Rectangle 2 (below rectangle 1):
15 × 8 = 120 cm²
Rectangle 3 (with rectangle 2):
11 × 4 = 44 cm²
Triangle 1 :
1/2(7 × 19) = 133/2 = 66.5 cm²
Now adding up all to get the area of the figure:
Area of the figure = 24 + 120 + 44 + 66.5
Area of the figure = 254.5 cm²
Graph the equation below by plotting the
y-intercept and a second point on the
line.
Answer:
Step-by-step explanation:
On the y-axis, graph the point on (0,4). Then from there, go up one, and to the right 4.
Three dogs eat 30 pounds of food in 10 days. If each dog eats the same amount, how much food does 1 dog eat in 1 day? 1 pound 3 pounds 9 pounds 10 pounds
Answer:
Unable to read entire question, but see explanation for answer
Step-by-step explanation:
First, you need to find the unit rate per dog. If it takes 3 dogs 10 days to finish 30 pounds of food, then it takes 1 dog 1 day to finish 1 pound of food. I cannot read the entirety of the question because of the cropping, but you can find how much food a single dog eats in that amount of days by just multiplying by the number of days (say, 1 pound in 1 day, or 3 pounds in 3 days). Hope this helps!
Answer:
1
Step-by-step explanation:
took test
The table below represents the total cost of leasing a car at the end each month.
Month 1 -------- 3 -------- 8 -------- 12
Cost $1,859 --- $2,577 --- $4,372 --- $5,808
Write an equation in slope-intercept form to represent the total cost, y, of leasing a car for x months.
Answer:
y= 359 x+1500
Step-by-step explanation:
find the slope m= (2577-1859)÷(3-1) = 359
y=mx+b
find b : substitute x ,y, and m
get b = 1857 - 359*1 = 1500
Answer:
y= 359 x+1500
Step-by-step explanation:
A square has an area of 349.69m2.
Work out the perimeter of the square.
Answer:
[tex]74.8m[/tex]
Step-by-step explanation:
[tex]A=a^2\\P=4a\\P=4\sqrt{A} \\=4*\sqrt{349.69} \\=74.8m[/tex]
Find the third-degree polynomial function that has zeros −2 and −15i, and a value of 1,170 when x=3.
Answer:
The third degree polynomial function = x³ + 27x² + 200x + 300
Step-by-step explanation:
The third-degree polynomial function has zeros −2 and −15.
From the above, we have been given two factors of the polynomial function. Let's derive the factors from the two zeros of the polynomial given.
The two given zeros of the polynomial can be written as:
x= -2
x+2 = 0
(x+2) is a factor of the polynomial
x= -15
x+15 = 0
(x+15) is a factor of the polynomial
So we have two factors of the polynomial (x+2) and (x+15). But since it is a third degree polynomial, we have to find the third factor.
Let (x-b) be the third factor and f(x) represent the third degree polynomial
f(x) = (x-b) (x+2) (x+15)
Expanding (x+2) (x+15) = x² + 2x + 15x + 30
(x+2) (x+15) = x² + 17x + 30
f(x) = (x-b) (x² + 17x + 30)
From the given information, a value of 1,170 is obtained when x=3
f(3) = 1170
Insert 3 for x in f(x)
f(3) = (3-b) (3² + 17(3) + 30)
1170 = (3-b) (9 + 51 + 30)
1170 = (3-b) (90)
1170/90 = 3-b
3-b = 13
b = 3-13 = -10
Insert value of b in f(x)
f(x) = [x-(-10)] (x² + 17x + 30)
f(x) = (x+10) (x² + 17x + 30)
f(x) = x³ + 17x² + 30x + 10x² + 170x + 200x + 300
f(x) = x³ + 27x² + 200x + 300
The third degree polynomial function = x³ + 27x² + 200x + 300
Mary is three quarters of Cameron's age. Mary is 24 years old. How old is Cameron?
Answer:
32 years oldStep-by-step explanation:
3/4=24 so 1/4= 24÷3= 8
1/4=8
So to get 4/4 or Cameron's age it is 8×4=32yrs
[tex]answer \\ 32 \: years \: old \\ solution \\ mary's \: age = 24 \\ let \: cameron's \: age \: be \: x \\ given \\ \frac{3}{4} x = 24 \\ or \: x = 24 \times \frac{4}{3} \\ x = 32 \\ hope \: it \: helps[/tex]
A computer manufacturer conducted a survey. It showed that a younger customer will not necessarily purchase a lower or higher priced computer. What is likely true? There is no correlation between age and purchase price. There is a correlation between age and purchase price. There may or may not be causation. Further studies would have to be done to determine this. There is a correlation between age and purchase price. There is probably also causation. This is because there is likely a decrease in the purchase price with a decrease in age.
Answer:
There is no correlation between age and purchase price
Step-by-step explanation:
In the survey, the researcher found out that a younger customer will not necessarily purchase a lower or higher priced computer thing it is likely true that there might be no correlation between purchase price and age.
It assumes that a younger customer can buy either buy a lower priced computer or can also buy a higher priced if he or she has the money for it.
Peter has invented a game with paper cups. He lines up 121 cups face down in a straight line from left to right and consecutively labels them from 1 to 121. He then walks from left to right down the line of cups, flipping all of the cups over. He returns to the left end of the line, then makes a second pass from left to right, this time flipping cups 2,4,6,8... On the third pass, he flips cups 3,6,9,12.... He continues like this: On the ith pass, he flips over cups i, 2i, 3i, 4i,.... (By "flip," we mean changing the cup from face down to face up or vice versa.) After 121 passes, how many cups are face up?
Answer:
After 121 passes, there will be 11 cups facing up
Step-by-step explanation:
Given that:
Peter initially lines up 121 cups facing down in a straight line from left to right and consecutively labels them from 1 to 121.
We can have an inequality ; i.e 1 ≤ n ≤ 121; if n represents the divisor including n itself for which n = odd number. Thus at the end of this claim, the cup will be facing up.
On the ith pass, he flips over cups i, 2i, 3i, 4i,.... (By "flip," we mean changing the cup from face down to face up or vice versa.)
For each divisor on the ith pass of n;
[tex]i \ th \ pass \ = \ n \ \to \ p |n[/tex] since we are dealing with possibility of having an odds number:
Thus; [tex]p =i[/tex] and [tex]i^2 = n[/tex] where ; n = perfect square.
Thus ; we will realize that between 1 to 121 ; there exist 11 perfect squares. Therefore; as a result of that ; 11 cups will definitely be facing up after 121 passes
–3y = 15 – 4x rewritten in slope-intercept form is
Answer:
[tex] y = \frac{4}{3} - 5[/tex]
Step-by-step explanation:
[tex] - 3y = 15 - 4x \\ - 3y = - 4x + 15 \\ \\ y = \frac{ - 4x + 15}{ - 3} \\ \\ y = \frac{ - 4}{ - 3} x + \frac{15}{ - 3} \\ \\ y = \frac{4}{3} x - 5 \\ which \: is \: in \: slope - intercept \: form.[/tex]
What’s the correct answer for this?
Answer:
s = 4.43
Step-by-step explanation:
Using formula for bigger circle
s =r∅
Where s is the Arc length, r is rdius and ∅ is theta(angle)
8.84=5∅
∅= 8.84/5
Angle = 1.77 radians
So both angles equal to 1.77 radians
Now again
Using formula
s = r∅
Where s is the Arc length, r is rdius and ∅ is theta(angle)
s = (2.5)(1.77)
s ≈ 4.43
The longer leg of a 30-60-90° triangle is 18. What is the length of the other leg?
A) 1213
B) 93
C) 9
D) 63
Answer:
D
Step-by-step explanation:
In a 30-60-90 triangle, the longer leg is [tex]\sqrt{3}[/tex] times larger than the smaller leg. The length of the shorter leg is therefore:
[tex]\dfrac{18}{\sqrt{3}}= \\\\\\\dfrac{18\sqrt{3}}{3}= \\\\\\6\sqrt{3}[/tex]
Hope this helps!
What is the value of y ??????????????
Answer & Step-by-step explanation:
For this problem we can just set up an equation and equal it to 180.
(2y) + (y + 10) + 50 = 180
Combine like terms.
3y + 60 = 180
Subtract 60 from 180.
3y = 120
Divide 120 by 3.
y = 40
So, the value of y is 40°
the sum of the three numbers in 2003,two of the numbers are 814 and 519 what is the third number
Answer:
670
Step-by-step explanation:
2003-814=1189
1189-519=670
Answer: The third number is 670.
Step-by-step explanation:
The sum means three numbers being added up is equal to 2003 so give two of those numbers you have to add them up and subtract it from 2003 to find the third number.
814 + 519 + x = 2003 where x is the third number
1333 + x = 2003
-1333 -1333
x = 670 So the third number is 670
Check:
814 + 670 + 519 = 2003
2003 = 2003 so yes again 670 is the third number.
Felicia walks 3 blocks west, 4 blocks south, 3 more blocks west, then
2 blocks south again. How far is Felicia from her starting point?
Answer:
blocks
Answer: i did the question i told you the steps
Step-by-step explanation:
From the starting point move three to the left. Then move four down. Then move three times to the left. Lastly move two down.
A designer makes a model of a patio using 1/2 inch square tiles each 1/2 inch square tiles = 4 square feet what area is represented by the 8 x 6 model
Answer:
[tex]192ft^2[/tex]
Step-by-step explanation:
The model of a patio was made by
using 1/2 inch square title=4 square feet.
area represented by the 8 *6 model can be calculated as follows;
FIRSTLY, the number of tiles in the 8 *6 model can be calculated by multiplying it i.e
8 *6 model =[tex]48 tiles[/tex]
Hence there are 48 tiles in 8 *6 model
It was given that 1/2 inch square title=4
square feet.
So to calculate the total Area occupied by the 48 tiles
[tex]Area=1/2×48[/tex]
[tex]Area=24inches^2[/tex]
If [tex]1/2inches^2=4ft^2[/tex] ( from the question)
Let X represent [tex]24inches^2[/tex]
Then, [tex]24inches^2=Xft^2[/tex]
Cross multiply
[tex]4×24=X×1/2
X=4×24×2
X=[tex]192ft^2[/tex]
[tex]24inches^2=[tex]192ft^2[/tex]
Therefore, the area represented by the 8 *6 model is [tex]192ft^2[/tex]
Based on historical data, your manager believes that 39% of the company's orders come from first-time customers. A random sample of 171 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.21 and 0.32
Answer:
[tex] z= \frac{0.21- 0.39}{0.0373}= -4.829[/tex]
[tex] z= \frac{0.32- 0.39}{0.0373}=-1.877[/tex]
And we can find the probability with this difference:
[tex] P(-4.829<z< -1.877) = P(Z<-1.877) -P(Z<-4.829)=0.0303- 6.86x10^{-7}=0.0303[/tex]
Step-by-step explanation:
For this case we have the following info given:
[tex] n = 171[/tex] represent the sample size
[tex]p =0.39[/tex] the proportion of interest
We want to find the following probability:
[tex] P( 0.21 < \hat p < 0.32)[/tex]
We can use the normal approximation for this case since np >10 and n (1-p) >10
For this case we know that the distribution for the sample proportion is given by:
[tex]\hat p \sim N( p , \sqrt{\frac{p (1-p)}{n}} )[/tex]
And we can use the following parameters:
[tex] \mu_{\hat p}= 0.39[/tex]
[tex] \sigma_{\hat p} =\sqrt{\frac{0.39*(1-0.39)}{171}}= 0.0373[/tex]
And we can apply the z score formula given by:
[tex] z = \frac{p \\mu_{\hat p}}{\sigma_{\hat p}}[/tex]
And using this formula we got:
[tex] z= \frac{0.21- 0.39}{0.0373}= -4.829[/tex]
[tex] z= \frac{0.32- 0.39}{0.0373}=-1.877[/tex]
And we can find the probability with this difference:
[tex] P(-4.829<z< -1.877) = P(Z<-1.877) -P(Z<-4.829)=0.0303- 6.86x10^{-7}=0.0303[/tex]
Find the characteristic polynomial and the eigenvalues of the matrix. [Start 2 By 2 Matrix 1st Row 1st Column 11 2nd Column 2 2nd Row 1st Column 2 2nd Column 11 EndMatrix ]The characteristic polynomial is nothing.
Answer:
Step-by-step explanation:
The answer is 3x 987 colunm 2
#2 Jamal is an apprentice on a boat on Long Island Sound. He is helping the captain collect samples of
marine life for an environmental study, and the captain is teaching him about nautical navigation.
When the boat leaves the environmental station, it will return to its home port 9 nautical miles away.
If
the boat maintains a constant speed of 15 knots (nautical miles per hour), how many minutes will the
trip take?
Answer:
The trip will take 36 minutes.
Step-by-step explanation:
This question can be solved using a rule of three.
The boat maintains a constant speed of 15 knots (nautical miles per hour). How many minutes it will take to return to its home port 9 nautical miles away?
So in 60 minutes, 15 nautical miles. How many minutes for 9 nautical miles?
60 minutes - 15 nautical miles
x minutes - 9 nautical miles
[tex]15x = 60*9[/tex]
[tex]x = \frac{60*9}{15}[/tex]
[tex]x = 36[/tex]
The trip will take 36 minutes.
A bottler of drinking water fills plastic bottles with a mean volume of 1,007 milliliters (mL) and standard deviation The fill volumes are normally distributed. What proportion of bottles have volumes less than 1,007 mL?
Answer:
0.5 = 50% of bottles have volumes less than 1,007 mL
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 1007[/tex]
What proportion of bottles have volumes less than 1,007 mL?
This is the pvalue of Z when X = 1007. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1007 - 1007}{\sigma}[/tex]
[tex]Z = 0[/tex]
[tex]Z = 0[/tex] has a pvalue of 0.5
0.5 = 50% of bottles have volumes less than 1,007 mL
please see attachment
Answer:
a) The value of absolute minimum value = - 0.3536
b) which is attained at [tex]x = \frac{1}{\sqrt{2} }[/tex]
Step-by-step explanation:
Step(i):-
Given function
[tex]f(x) = \frac{-x}{2x^{2} +1}[/tex] ...(i)
Differentiating equation (i) with respective to 'x'
[tex]f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }[/tex] ...(ii)
[tex]f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }[/tex]
Equating Zero
[tex]f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0[/tex]
[tex]\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0[/tex]
[tex]2 x^{2}-1 = 0[/tex]
[tex]2 x^{2} = 1[/tex]
[tex]x^{2} = \frac{1}{2}[/tex]
[tex]x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }[/tex]
Step(ii):-
Again Differentiating equation (ii) with respective to 'x'
[tex]f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }[/tex]
put
[tex]x = \frac{1}{\sqrt{2} }[/tex]
[tex]f^{ll} (x) > 0[/tex]
The absolute minimum value at [tex]x = \frac{1}{\sqrt{2} }[/tex]
Step(iii):-
The value of absolute minimum value
[tex]f(x) = \frac{-x}{2x^{2} +1}[/tex]
[tex]f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}[/tex]
on calculation we get
The value of absolute minimum value = - 0.3536
Final answer:-
a) The value of absolute minimum value = - 0.3536
b) which is attained at [tex]x = \frac{1}{\sqrt{2} }[/tex]
Let D= {(x,y) | x^2+y^2 ≤ 4x} Using polar coordinates, What is the integral: ∬y^2/ (x^2+y^2)dxdy?
In polar coordinates, the inequality changes to
[tex]x^2+y^2\le4x\implies r^2\le4r\cos\theta\implies r\le4\cos\theta[/tex]
which is a circle of radius 2 and centered at (2, 0). The set D is then
[tex]D=\left\{(r,\theta)\mid0\le r\le4\cos\theta\land0\le\theta\le\pi\right\}[/tex]
The integral is then
[tex]\displaystyle\iint_D\frac{y^2}{x^2+y^2}\,\mathrm dx\,\mathrm dy=\int_0^\pi\int_0^{4\cos\theta}\frac{r^2\sin^2\theta}{r^2}r\,\mathrm dr\,\mathrm d\theta[/tex]
[tex]=\displaystyle\int_0^\pi\int_0^{4\cos\theta}r\sin^2\theta\,\mathrm dr\,\mathrm d\theta[/tex]
[tex]=\displaystyle\frac12\int_0^\pi((4\cos\theta)^2-0^2)\sin^2\theta\,\mathrm d\theta[/tex]
[tex]=\displaystyle8\int_0^\pi\cos^2\theta\sin^2\theta\,\mathrm d\theta[/tex]
There are several ways to compute the remaining integral; one would be to invoke the double-angle formula,
[tex]\sin(2\theta)=2\sin\theta\cos\theta[/tex]
so that the integral is
[tex]=\displaystyle8\int_0^\pi\frac{\sin^2(2\theta)}4\,\mathrm d\theta[/tex]
[tex]=\displaystyle2\int_0^\pi\sin^2(2\theta)\,\mathrm d\theta[/tex]
Then invoke another double-angle formula,
[tex]\sin^2\theta=\dfrac{1-\cos(2\theta)}2[/tex]
to change the integral to
[tex]=\displaystyle\int_0^\pi1-\cos(4\theta)\,\mathrm d\theta[/tex]
[tex]=(\pi-\cos(4\pi))-(0-\cos0)=\boxed{\pi}[/tex]
please very soon I offer the crown !!! + 10 points urgently !!!
Answer:
odd numbers always end in 1,3,5,7 and 9
odd numbers - 51,23,95,11,67,75,83, and 29
even numbers - 16,32,38,76,62,40 and 80
19p 25p 16p
9 - 2p , 1 - 1p 12- 2p, 1- 1p 5- 2p, 6- 1p
19 - 1p 10 - 2p, 5- 1p 6 - 2p, 2- 1p
7- 2p , 5- 1p 8- 2p, 9- 1p 4- 2p, 8- 1p
9- 2p, 6- 1p 6- 2p, 4- 1p
Are the two terms on each tile like terms? Sort the tiles into the appropriate categories.
-7y^2and y^2
-4p and p^2
0.5kt and -10kt
6 and 9
5x and 5
3ad and 2bd
Answer:
LIKE TERMS: 6 and 9, 0.5kt and -10kt, and -7y2 and y2. UNLIKE TERMS: 3ad and 2bd, 5x and 5, and the last one is -4p and p2
Step-by-step explanation:
Answer: like terms: 6&9 , 0.5kt&-10kt , -7y^2&y^2
unlike terms 3ad&2bd, 5x&5, -4p&p^2
Step-by-step explanation:
passed
what is tge surface area of tge dquare pyramid GELP IM TIMED AND ABOUT TO RUN OUT OF TIME
Answer:
Step-by-step explanation:
a consumer affairs company is interested in testing at the 5% level of significance that the average weight of a package of butter is less than 16 oz if the p value is 0.003 the conclusion is
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minutes per day that people spend standing or walking. Among mildly obese people, minutes of activity varied according to the N(373, 61) distribution. Minutes of activity for lean people had the N(525, 104) distribution. Within what limits do the active minutes for 95% of the people in each group fall
Answer:
Among mildly obese people, 95% of the people have between 251 and 495 minutes of activity per day.
Among lean people, 95% of the people have between 317 and 733 minutes of activity per day.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
Within what limits do the active minutes for 95% of the people in each group fall
By the Empirical Rule, within 2 standard deviations of the mean.
Mildly obese:
Mean = 373, standard deviation = 61.
373 - 2*61 = 251 minutes
373 + 2*61 = 495 minutes
Among mildly obese people, 95% of the people have between 251 and 495 minutes of activity per day.
Lean people:
Mean = 525, standard deviation = 104
525 - 2*104 = 317 minutes
525 + 2*104 = 733 minutes
Among lean people, 95% of the people have between 317 and 733 minutes of activity per day.
Determine the area of the shaded region
Answer:
61.76 ft^2
Step-by-step explanation:
First find the area of the rectangle without the circle
A = l*w = 14*8 =112
Then find the area of the circle
The diameter is 8 so the radius is 8/2 =4
A = pi r^2 = 3.14 * 16 =50.24
The shaded region is the rectangle minus the circle
112-50.24 =61.76 ft^2