The truss shown in the figure carries a
load F= 20 kN at joint D. The truss is
designed with nine rods, six of which (the
inclined ones) have the same length d=2
m. Rods BC, EC, DE, and BD form a
square.
1. Find the support reactions at joints A
and F.
2. Using the method of joints or method of
sections to find the tensions in rods BD
and BC.
3. State whether each member is in
tension or compression.

Answer:

Explanation:

______?

Net forces always result in an acceleration. Newton's Second Law of Motion states that a net force (the sum of all forces acting on an object) will cause an object to accelerate in the same direction as the net force. The acceleration is proportional to the magnitude of the net force and inversely proportional to the mass of the object.

Answer:

A net force always result in a acceleration

Answer:

Option a. The baton's center of mass is closer to the larger sphere, making the lever arm distance between your hand and the center of mass longer in option a than in option b. The longer lever arm distance gives you finer control.

Answer:

Explanation:

(a) Q=ap^n

Function of p and q:

p = q^(1/n)

(b) Q^m=ap^n

Function of p and q:

p = (q^(1/m))^(1/n)

Answer:

Light waves do not need a medium in which to travel but sound waves do. Explain that unlike sound, light waves travel fastest through a vacuum and air, and slower through other materials such as glass or water.

Explanation:

Light travels in a straight line as a wave. It does not require any medium or material to travel like sound waves which means it can travel in vacuum.The speed of the light  from the special theory of relativity is a constant value of 38x10^8m/second

According to the question: the net force on the roof is 8.45 kN.

The vector sum of the forces operating on a particle of object is known as the net force in mechanics. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force. In accordance with Newton's second rule of motion, it causes the particle to accelerate at a rate equal to the sum of all those actual forces.

The net force on the roof is equal to the air pressure multiplied by the surface area of the roof. The air pressure is equal to the density of the air multiplied by the wind speed squared. Therefore, the net force on the roof can be calculated as follows:
Force = (density x wind speed²) x surface area
Force = (1.29 kg/m² x (40 m/s)²) x (250 cm²)
Force = 8.45 kN
Therefore, the net force on the roof is 8.45 kN.

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The purpose of the chiller is to remove heat from the air and is therefore denoted as option A.

This is a type of device which is referred to as type of a cooling system that removes heat by circulating heat-absorbing a refrigerant through a series of mechanisms through which the heat is released.

The result of this process is that the heat in the air is removed as a result of the refrigerant being adequately circulated and then the environment becomes cooler and is therefore the reason why it was chosen as the correct choice.

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The displacement at which the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm is 1.5cm.

The amplitude of simple harmonic motion affects the ratio of kinetic to potential energy at a specific displacement in the following way: as the amplitude increases, the ratio of kinetic to potential energy decreases. This is because the amplitude represents the maximum displacement from the equilibrium position, and as the amplitude increases, the potential energy of the particle increases, while the kinetic energy remains constant. Therefore, at a specific displacement, a particle with a larger amplitude will have a greater proportion of its energy in the form of potential energy, while a particle with a smaller amplitude will have a greater proportion of its energy in the form of kinetic energy.

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Answer:

1.98×1020 N 1.98 × 10 20 N

Explanation:

The gravitational force between the Earth and the Moon is 1.98×1020 N 1.98 × 10 20 N.

As per the problem statement the average angular acceleration is 4.7/4.5 = 1.78 rad/s2

The rate at which the angular velocity of an item changes over time is known as its angular acceleration. It is a vector quantity that describes the rate of change in angular velocity, which is the rotational equivalent of linear acceleration. It is the angular equivalent of linear acceleration, which is the rate of change of linear velocity over time. Angular acceleration is typically expressed in units of radians per second squared (rad/s2).  It is also referred to as angular je rk, angular deceleration, or angular frequency.

The average angular acceleration is 1.78 rad/s2.
This is calculated by taking the change in angular speed (8.1 - 3.4 = 4.7) and dividing it by the time interval (4.5 s).
Thus, the average angular acceleration is 4.7 / 4.5 = 1.78 rad/s 2.

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Answer:

I need this message as well so please ket me know when you have it

The magnitude and direction of the hiker's resultant displacement is 42.7 km, 64.6° north of east.

To find the magnitude and direction of the hiker's resultant displacement, we can use vector addition.

First, we need to convert the given magnitudes and directions into x and y components. We can use trigonometry to do this:

x component of the first displacement = 27.0 km * cos(35°) = 21.5 km

y component of the first displacement = 27.0 km * sin(35°) = 15.5 km

x component of the second displacement = 41.0 km * cos(65°) = 17.6 km

y component of the second displacement = 41.0 km * sin(65°) = 30.6 km

Now we can add the x and y components of each displacement to find the x and y components of the resultant displacement:

x component of the resultant displacement = 21.5 km + 17.6 km = 39.1 km

y component of the resultant displacement = 15.5 km + 30.6 km = 46.1 km

To find the magnitude of the resultant displacement, we can use the Pythagorean theorem:

magnitude of the resultant displacement = sqrt(39.1 km^2 + 46.1 km^2) = sqrt(1820.81 km^2) = 42.7 km

Finally, we can use the arctangent function to find the direction of the displacement:

direction = arctan(46.1 km / 39.1 km) = 64.6° north of east.

So the magnitude and direction of the hiker's resultant displacement is 42.7 km, 64.6° north of east.

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Answer:

d. 16 kg-m/s

Explanation:

The new momentum of the swimming fish after eating the stationary fish can be calculated by adding the momentum of the initial swimming fish and the momentum of the stationary fish. Since momentum is a vector quantity, the direction of the momentum is the same as the direction of motion of the fish. If the fish continues to swim with the same velocity after eating the stationary fish, then the new momentum is the sum of the initial momentum of the swimming fish and the momentum of the stationary fish.

Initial momentum of swimming fish = 8 kg-m/s

Momentum of stationary fish = 2 kg * 0 m/s = 0 kg-m/s

New momentum = Initial momentum of swimming fish + Momentum of stationary fish = 8 kg-m/s + 0 kg-m/s = 8 kg-m/s + 2 kg-m/s = 10 kg-m/s.

So, the correct answer is (d) 16 kg-m/s.

Answer:

C

Explanation:

Using law of conservation of momentum of the system

Momentum before = momentum after

         8 kg m/s       = 8 kg m/s

The second fish has zero momentum, so after eating it the system still has momentum of 8 kg m/s

Answer:

1.5 minutes

Explanation:

To find out how long it will take to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle, we can use the equation:

Q = mcΔT

Where Q is the heat energy added, m is the mass of the water, c is the specific heat capacity of water and ΔT is the change in temperature.

The heat energy added to the water can be calculated as:

Q = (5 kg) x (400 J/kg·K) x (88°C - 28°C) = (5 kg) x (400 J/kg·K) x (60°C) = 120000 J

The power of the electric kettle can be calculated using the formula:

P=VI

where P is the power, V is the voltage and I is the current,

P = (220 V) x (6 A)

= 1320 W

Now we can calculate the time it takes to heat the water by dividing the heat energy added by the power:

time = Q/P = 120000 J / 1320 W

= 90.909 seconds or 1.5 minutes

It will take 1.5 minutes to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle taking 6 amperes from a 220 volt supply.

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Answer:

Substance       ΔH (kJ/g)

Coal               -40.23

Hydrogen           -242.82

Methanol           -252.45

Octane               -43.99

Propane             -214.46

Explanation:

Methanol made the worst fuel because it has the lowest ΔH value of -252.45 kJ/g, which means that it releases the lowest amount of energy when used as a fuel. The other substances have higher ΔH values, so they produce more heat energy when burned.

The amount of work the engine can do in 1.0 hour, given that the engine generates 56 MegaWatts is 2016×10⁸ Joules

Work is defined as the product of force and distance moved in the direction of the force.

Work done (Wd) = force (F) × distance (d)

Power is defined as the rate at which work is done:

Power = Work / time

Using the power-work relationship formula above, we can detertmine the work the engine will do in 1.0 hour as follow:

Power = Work / time

Cross multiply

Work = Power × time

Work = 56×10⁶ × 3600

Work = 2016×10⁸ Joules

Therefore, we can conclude from the above calculation that the work the engine will do is 2016×10⁸ Joules

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The features of a Desert Climate sare mainly associated with the absence of precipitation and high solar radiation (question a), plants adapt to live in that type of climate due to the close of stomata and avoiding the presence of many leaves that lose too much water and or succulence in the plant shoot (questions b and c).

The relationship between desert conditions and plant adaptations in terms of evolution is based on certain anatomical and or physiological features used by these organisms to avoid the excessive loss of water under extreme desertic conditions such as the presence of small leaves and close stomata.

Therefore, with this data, we can see that plant adaptations in terms of evolution in desert environments are mainly associated with small leaves and also close stomata for gas exchange.

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Several vectors in the x-y plane are shown in the figure with their tails at the origin of the coordinate system and with a label at their heads.The value of M = (P+Q) is

3.65 meters

Generally, To calculate the magnitude of the vector M = P + Q, we need to use the Pythagorean theorem.

M = P + Q

M= (2.80i + 2.30j) + (-3.90i + 1.20j)

M= (-1.10i + 3.50j)

The magnitude of the vector M is the square root of the sum of the squares of the x and y components of the vector.

|M| = √((-1.10)^2 + (3.50)^2)

= √(1.21 + 12.25)

= √13.46

≈ 3.65 meters

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If the earth is 5 times as massive and the radius 5 times its present value, your weight will be 130 N.

Weight is the amount of gravitational force acting on an object as a result of the gravitational attraction of the Earth.

Assuming gravitational force = [tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

where G = 6.67 x 10⁻¹¹m³/kgs², a universal constant.

m = masses of two objects and

r = distance of two objects.

Given that W = 650 N

m₁ = 5Me, new mass of earth

r = 5re, new radius of earth

Then [tex]650 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]

Let the new weight be [tex]F = \frac{GM m}{r^{2} }[/tex]

Substituting the new mass and radius;

[tex]F = \frac{G(5M_{E}) m}{(5r_{E})^{2}}[/tex]

[tex]F = \frac{5}{25} \frac{GM_{E} m}{r^{2}_{E}}[/tex]

Knowing that [tex]650 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]

[tex]F = \frac{5}{25}(650 N)[/tex] = 0.2 x 650N

F = 130 N

When the earth is 5 times its radius and 5 times its mass a weight of 650N will become 130 N.

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Acceleration is the rate of change of velocity. It can be calculated using the formula:

a = (vf - vi) / t

Given:

vi = 25 m/s (initial velocity)

vf = 10 m/s (final velocity)

t = 3 s (time interval)

a = (vf - vi) / t = (10 m/s - 25 m/s) / 3 s = -15 m/s^2

The acceleration of the roller coaster is -15 m/s^2.

Negative acceleration indicates that the roller coaster is slowing down. This means that the roller coaster is losing speed as it reaches the top of the hill. The roller coaster is decelerating (negative acceleration) while it climbs the hill, so that it can move with a lower velocity at the top of the hill.

If  the maximum acceleration is equal to maximum velocity, then frequency of applied force is equal to natural frequency of the vibrating body.

A simple harmonic motion is characterized by this changing acceleration that always is directed toward the equilibrium position and is proportional to the displacement from the equilibrium position.

Mathematically, the formula for the maximum acceleration of a simple harmonic motion is given as;

a ( max ) = ω²A

where;

Resonance vibration is a type of forced vibration in which the natural frequency of vibration of the body is the same as the impressed frequency of external applied force and the amplitude of forced vibration is maximum.

Thus, we can conclude that, the natural frequency of the vibrating body or object is equal to the frequency of the applied force, hence the term resonant vibration.

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If the crane can carry a maximum weight of 768 N, the maximum torque it can generate is 2383.4 N

The axis of rotation is the point at which the item rotates, and torque is the twisting force that causes rotation. Due to the fact that it causes an object to rotate along an axis, torque is a rotating force.

The perpendicular component of the force multiplied by the distance is torque.

T = F _|_ T

Part One

T = (768 N cos 13.9°) (16.0 m)

T = 10,368 Nm

Part Two

10368 Nm = (F cos 27.0°) (16.0 m)

F = 2383.4 N

Hence, maximum torque can the crane with-stand if the maximum load the crane can handle is 768 N is 2383.4 N

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Answer:

Explanation:

bxvbrzfbd

The magnitude of the tension in the rope is 12.2625 N, and the rope is being pulled horizontally to the left by the wind force..

What is tension?

Tension is the force transmitted through a string, rope, cable or wire when it is pulled tight by forces acting on it from opposite ends. It is a force that is directed along the length of the string, rope, cable or wire and is always directed away from the object that is creating the tension.

When an object is suspended from a rope or cable, the tension in the rope or cable must be equal to the weight of the object in order for the object to remain stationary or move at a constant velocity. If the tension is less than the weight of the object, the object will fall, and if the tension is greater than the weight of the object, the object will rise.

Tension plays an important role in many areas of physics and engineering, such as in the design of suspension bridges, elevator systems, and the motion of satellites in orbit.

To find the tension in the rope and the rope's angle from the vertical, we can start by drawing a free body diagram of the object:

       Tension (upwards)

                   |

                   |

                   |

                   |

        Weight (downwards)

                   |

                   |

                   |

                   |

Wind force (to the right)

where Tension is the tension in the rope, Weight is the weight of the object, and Wind force is the horizontal force due to the wind.

The object is in equilibrium, so the net force on it is zero. We can write two equations based on the forces in the vertical and horizontal directions:

Vertical equilibrium:

             Tension - Weight = 0

                Tension = Weight

Horizontal equilibrium:

   Wind force = Tension * sin(theta)

where theta is the angle between the rope and the vertical.

We can solve these equations for the tension and theta:

Weight = m * g = 1.25 kg * 9.81 m/s^2 = 12.2625 N

Tension = Weight = 12.2625 N

sin(theta) = Wind force / Tension = 18.3 N / 12.2625 N = 1.492

Since sin(theta) is greater than 1, there is no solution for theta. This means that the rope is not making an angle with the vertical, and is instead being pulled directly to the left by the wind force.

Therefore, the magnitude of the tension in the rope is 12.2625 N, and the rope is being pulled horizontally to the left by the wind force.

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The electric field strength in volts per meter is 380 V. Option D is the correct answer.

This refers to the physical field that encloses electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It can also be called the physical field for a system of charged particles or ( E-field).

The electric field strength (E) can be calculated using the  b the formula:

E = V / d,

where,

V = the potential difference (in volts)

d = the distance (in meters) between the plates.

Calculating the electric:

V = 15.0 V

d = 0.04 m (4.0 cm converted to meters).

Hence,

E = 15.0 V

      0.04 m

= 375 V/m.

E ≈ 380 V

Hence The electric field strength (E) is 380 V.

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There could be several explanations for the discrepancies in the number of aggressive behaviors observed by the research assistants, but the most likely explanation is that the observations were subjective and prone to bias.

1. Observer bias: The research assistants may have different definitions of what constitutes aggressive behavior, or they may have different levels of sensitivity to detecting aggressive behaviors. This can lead to different interpretations of the same behavior and result in different counts.

2. Different focus: The research assistants may have focused on different aspects of the gaming session and paid attention to different details, resulting in different counts.

3. Fatigue: The research assistants may have become less attentive or less accurate in their counting as the gaming session progressed, which could explain why some of the counts are higher than others.

4. Confirmation bias: Research assistants may have been more likely to notice behaviors that confirm their preconceptions about the gamer, leading to counts that are higher or lower than what was actually observed.

5. Different cultural background: Research assistants from different cultural background may have different understanding of what is aggressive behavior.

Answer:

T=80

Explanation:

soln

v=0.25ms

d=20m

t=?

therefore; velocity=distance/time taken

equating the valuables we have

0.25=20/t

making t the subject formula we have

t=20/0.25 => 80s

Answer:

4300N

Explanation:

Based on the free body diagram, the friction (fFr in the attached diagram) is dependent on the reaction force (Rn in the attached diagram) acting on the object, in this case a car. The frictional force will always act against the direction of movement (DOM in the attached diagram.)

Given the condition is dry,

Summation of forces in the vertical direction (Positive for upward forces) = 0

Reaction Force - Weight of car = 0

Reaction Force = Weight of car = 14000N

Since the friction is dependent on the reaction force with the formula: Coefficient of friction X Reaction Force,

Friction (Dry Condition) = 0.7 * 14000N = 9800N

Now given the condition is wet,

We will use the same formula but with a change to the coefficient of friction.

Friction (Wet Condition) = 0.4 * 14000N = 5600N

Difference between them = 9800N - 5600N = 4300N.

( 1) The net gravitational force between the 74.8 kg mass is  8.09 x 10⁻⁵ N.

( 2) The distance from the from the 494 kg mass where the middle mass experiences net zero force is 0.258 m.

The net gravitational force between the 74.8 kg mass is calculated by applying Newton's law of universal gravitation as shown below.

F = ( GmM ) / ( R² )

where;

The force between the first mass and the middle mass is calculated as;

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( 0.198² )

F' = 1.8 x 10⁻⁵ N

The force between the third mass and the middle mass is calculated as;

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.198² )

F'' = 6.29 x 10⁻⁵ N

The net gravitational force on the middle mass;

F (net)  = 6.29 x 10⁻⁵ N + 1.8 x 10⁻⁵ N

F ( net ) = 8.09 x 10⁻⁵ N

Let the distance of zero net force = d

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( d² )

F' = 0.704 x 10⁻⁶ / d²

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.396 - d )²

F'' = 2.47 x 10⁻⁶ / ( 0.396 - d )²

for zero net force, the two forces must be equal

0.704 x 10⁻⁶ / d²  = 2.47 x 10⁻⁶ / ( 0.396 - d )²

0.704 (0.396 - d )² = 2.47d²

(0.396 - d )²  = ( 2.47d² ) / ( 0.704 )

(0.396 - d )²  = 3.51d²

0.396 - d = √ ( 3.51d² )

0.396 - d = 1.87d

1.87d + d = 0.396

d (1.87 + 1) = 0.396

d (2.87) = 0.396

d = 0.396 / 2.87

d = 0.138 m

The distance from the 494 kg mass = 0.396 - 0.138 m = 0.258 m

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