The velocity ratio of a pulley system is 4. What does it means

Answers

Answer 1

Answer:

Velocity ratio = distance travelled by effort / distance travelled by load. Which is equal to effort arm / load arm. When velocity ratio (VR) is 4, the effort arm is greater than load arm.


Related Questions

Please help (I didn’t know what subject to put this in but it’s earth science)

Answers

Spring summer and USA for the first 2
2. The answer is USA! https://www.netweather.tv/weather-forecasts/news/10277-tornado-facts-which-countries-have-the-most-and-the-deadliest-tornadoes

I think 1. Is A.

3. F5

4. A.

They want a mixture of 150 grams of water at 60 degrees Celsius, using hot water at 90 degrees Celsius and cold water at 14 degrees Celsius, how many grams of water should be used per face?​

Answers

Answer:

Explanation:

Here,

Final mass(m)=150g

Final Temperature(t)=60°C

Temperature of hot water(t1)=90C

Temperature of cold water(t2)=14C

Let the grams of water to be used per face be m1 grams and (150-m1) grams for hot and cold water respectively.

We know that,

Heat lost by hot body=Heat gained by cold body

or, m1 s1 Δt1=m2 s2 Δt2

or, m1 (t1-t)=(150-m1) (t-t2)  [∵s1=s2, SHC of water is taken to be same]

or, m1 (90-60)=(150-m1) (60-14)

or, 30m1=6900-46m1

or, 76m1=6900

∴m1=90.79g

(150-m1)=59.21g

Hence, 90.79g and 59.21 g hot and cold water must be used respectively.


What is conserved in a thermodynamically closed system?
A. Both energy nor matter
B. Energy
C. Both energy and matter
D. Matter

Answers

Explanation:

C. Both energy and matter

A rocket travels vertically at a speed of 1200 km/h. The rocket is tracked through a telescope by an observer located 16km from the launching pad. Find the rate at which the angle between the telescope and the ground is increasing 3 min after lift-off. Round your answer to the nearest hundredth rad/hr

Answers

Answer:

w = 0.01 t⁻²   rad/h

Explanation:

Let's use trigonometry to find the elevation angle of the telescope, we assume that the rocket remains fixed in the telescope.

        tan θ = CO / CA

the adjacent leg is CA = 16 km = 16 10³ m

Let's use kinematics to find the height of the rocket

          v = y / t

          y = v t

this height is equal to the opposite leg

          CO = v t

     

we substitute

         tan θ = vt / 16

         tan θ = 1200/16 t

         tan θ = 75 t

         θ = tan⁻¹ ( 75 t )

speed is defined by

          w = dθ/dt

          w = [tex]\frac{1}{1 + (75 t)^2} \ 75[/tex]  

         

as time increases we can neglect the 1 of the denominator

          w = 1/75 t²

          w = 0.0133 t⁻²

Using three significant figures

           w = 0.01 t⁻²   rad/h

for this answer the time must be given in hours

three letters (JET) are placed in front of a plane mirror the image formed is in what arrangement???​

Answers

Answer:

TEJ as this is a thing you wont get

Provide two positives and two negatives the Sarah‘s family would face if they switched to organic farming

Answers

Answer:

Organic farming would have higher costs, and would be more complex than conventional farming. However, the Suarez family could charge a higher price for organic produce. This type of farming also would be better for the land.

Explanation:

Answer expert verified for the same question. (question/4178423)

; (b) A uniform beam 150cm long weighs 3.5kg and
supported on knife-edges at its ends. The beam
supports a weight 7kg at a distance 30cm from
one end. Find the reactions of the supports.

Answers

Explanation:

(b) A uniform beam 150cm long weighs 3.5kg and

supported on knife-edges at its ends. The beam

supports a weight 7kg at a distance 30cm from

one end. Find the reactions of the supports.

Derive the following equations. :a=u-v by t​

Answers

here is the answer!

pls someone help me pls…. and pls explain to me how

Answers

Answer:

1.12 × 10⁴ m/s

Explanation:

The escape velocity of the object v = √(2GM/R) where G = gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of the Earth = 6 × 10²⁴ kg and R = radius of the Earth = 6.4 × 10⁶ m

Since v = √(2GM/R)

Substituting the values of the variables into the equation, we have

v = √(2GM/R)

v = √(2 × 6.67 × 10⁻¹¹ Nm²/kg² × 6 × 10²⁴ kg/6.4 × 10⁶ m)

v = √(13.34 × 10⁻¹¹ Nm²/kg² × 6 × 10²⁴ kg/6.4 × 10⁶ m)

v = √(80.04 × 10⁻¹¹ × 10²⁴Nm²/kg/6.4 × 10⁶ m)

v = √(80.04 × 10¹³Nm²/kg ÷ 6.4 × 10⁶ m)

v = √(80.04 ÷ 6.4 × 10¹³ ÷ 10⁶Nm/kg)

v = √(12.50625 × 10⁷ Nm/kg)

v = √(125.0625 × 10⁶ Nm/kg)

v = 11.18 × 10³ m/s

v = 1.118 × 10 × 10³ m/s

v = 1.118 × 10⁴ m/s

v ≅ 1.12 × 10⁴ m/s

How can we drop eggs the fewest amount of times without breaking it?​

Answers

Answer:

drop in water

Explanation:

follow me m mm m

A car travels initially at 24 m/s, until it enters the highway. If the car accelerates at 4 m/s^2 for a 96 meters, what is the car's new velocity?

Answers

initial velocity=u=24m/sAcceleration=a=4m/s^2Distance=s=96mFinal velocity=v

Using 3rd equation of kinematics

[tex]\boxed{\Large{\sf v^2-u^2=2as}}[/tex]

[tex]\\ \Large\sf\longmapsto v^2=u^2+2as[/tex]

[tex]\\ \Large\sf\longmapsto v^2=24^2+2(4)(96)[/tex]

[tex]\\ \Large\sf\longmapsto v^2=576+768[/tex]

[tex]\\ \Large\sf\longmapsto v^2=1344[/tex]

[tex]\\ \Large\sf\longmapsto v=\sqrt{1344}[/tex]

[tex]\\ \Large\sf\longmapsto v=36.6m/s[/tex]

GUYS PLEASE HELP ME THIS IS FOR MY FINAL !!!

Answers

Answer:

just add co-ratios and then find the average.

Explanation:

Explanation of the physics involved i the northern lights(aurora borealis) why can't it occur in mire southerns latitudes?

Answers

Answer:

The northern lights come from the interaction of electrically charged particles given off by the Sun surface during solar storms and the Earth's magnetic field which is pointed in the northern to southern poles of the Earth. Therefore, the charged particles that travel through millions of miles from the Sun to the Earth accelerate towards the magnetic poles and appear as the northern (and southern) lights

Boreal is an adjective word for the north or northern regions. In the southern latitudes, in the southern hemisphere, the phenomenon is called aurora australis (australis is the adjective for 'of the south')

Explanation:

a teacher and two students are mesuring the speed of sound. the teacher makes loud sound by hitting two cymbals together. each students starts a stopwatch then they see the teacher hit the cymbals, they each stop their stop watch when they hear the sound. describe how a sound wave moves through the air.​

Answers

Answer:

Slowly and smoothly lol

Answer:

S.I. on Rs. 1600 = T.D. on Rs. 1680. Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%. Time =100 x 80year=1year = 4 months.1600 x 153

Explanation:

Is this you are?

. A radio station transmitting at a frequency of 200KH, emits waves of wavelength 1.5 km.the velocity of the radio waves is​

Answers

Answer:

Explanation: as,

v=f∧

v=200×10³×1.5×10³

v=2.7×10^7ms⁻¹

The velocity of the radio waves is 3 × 10⁸ ms⁻¹.

A radio station frequency = 200 KH

wavelength = 1.5 km

How the velocity of the radio waves are calculated?

         Radio waves in the electromagnetic spectrum has the longest wavelength and it will always be below 300GHz. The radio waves can be generated with acceleration through some charged particles. Only through the transmitter via antenna the radio waves can gets transmitted. Radio waves can be used in all the electronic devices as mobile phones, radio communication, radars and navigations.

                               V = f λ

            Velocity,  v = ( 200 × 10³ ) × ( 1.5 × 10³ )

                               = ( 300 × 10⁶ )

                             v = 3 × 10⁸ ms⁻¹.

Hence, the velocity of the radio waves is 3 × 10⁸ ms⁻¹.

Learn more about the radio waves,

https://brainly.com/question/21995826

#SPJ2

resistances is inversely proprtional to___of the conductor​

Answers

Answer:

resistances is inversely proportional to the area of cross section of the conductor

Explanation:

The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area.

hope this helps you

have a nice day:)

what can be done to increase speed of rotation of a DC motor​

Answers

Answer: There are multiple options:

By varying the supply voltage.

By varying the flux, and by varying the current through the field winding.

By varying the armature voltage, and by varying the armature resistance.

Helpful Link:

https://www.elprocus.com/what-are-the-best-ways-to-control-the-speed-of-dc-motor/

A van of mass 1200kg is moving with speed of 90km/hr. It is brought in 3 seconds by applying brakes. Calculate the force applied to bring van to rest. ​

Answers

Answer:

Explanation:

The main equation to solve this is F = ma, where F is the force applied to the brakes with respect to its acceleration. We have the mass that we need, but we do not have the acceleration. That's the first thing we have to find. However, our velocity needs to be stated in m/s and right now it's in km/h. Converting that:

[tex]90\frac{km}{hr}*\frac{1000m}{1km}*\frac{1hr}{3600s} =25\frac{m}{s}[/tex] Now we're ready to find the acceleration:

[tex]a=\frac{v_f-v_0}{t}[/tex] where the top line there translates to the final velocity minus the initial velocity.

[tex]a=\frac{0-25}{3.0}[/tex] so the acceleration is -8.3 m/s/s

We can use that now in the force equation above:

F = 1200(-8.3) and

F = -1.0 × 10⁴ N (that's 10,000 N to the correct number of sig dig's; the negative sign means that the force is being applied in the direction opposite to that which the van is currently moving)

what is the relation between centre of gravity and stability

Answers

Explanation:

tilting it will raise the height of its center of gravity.

HELP ME
Which two changes to the can opener would increase its mechanical efficiency?
A shorten the paddle so that they are closer in size to the axle that they turn
B grease the rotating wheel of the opener so that there is less breaks in between moving parts
C replaced it with a straight handle the act as levers with shorter pieces of metal
D sand the cutting surface of the metal piece so that it is perfectly smooth and sharp

Answers

Answer:

I THINK IT'S D....

HOPE SO

3. There is a bell at the top of a tower that is 45 m high. The bell weighs 64 kg. The
bell has joules of potential energy.

Answers

Answer:It has 8550 j energy

A ball is dropped from the roof of a 25-m-tall building. What is the velocity of the object when it touches the ground? Suppose the ball is a perfect golf ball and it bounces such that the ve locity as it leaves the ground has the same magnitude but the op posite direction as the velocity with which it reached the ground How high will the ball bounce? Now suppose instead that the ball bounces back to a height of 20 m. What was the velocity with which it left the ground?

Answers

Answer:

a)  [tex]h=25m[/tex]

b)  [tex]v=19.8m/sec[/tex]

Explanation:

From the question we are told that:

Height [tex]h=25m[/tex]

Bounce Height [tex]h'=20m[/tex]

Generally the Kinematic equation is mathematically given by

[tex]V=\sqrt{2gh}\\\\V=\sqrt{2*9.81*25}[/tex]

[tex]V=22.1m/sec[/tex]

Therefore Height

[tex]h=\frac{V^2}{2g}\\\\h=\frac{22.1^2}{2*9.81}[/tex]

[tex]h=25m[/tex]

b)

Generally the Kinematic equation is mathematically given by

[tex]v^2=2ah[/tex]

[tex]v^2=2*9.8*20[/tex]

[tex]v=\sqrt{2*9.8*20}[/tex]

[tex]v=19.8m/sec[/tex]

write down any 5 example of conservation of momentum?​

Answers

Answer:

1) Motion of air mass moving from equator northward (closer to earth axis)

2) Motion of object in orbit

3) Collision of 2 objects

4) Skater changing rotation by extension of arms

5) Motion of rocket due to velocity of expelled gas

Which device is used to measure the weight of a body?

Answers

Answer:

The beam balance is a device used for the determination of the mass of a body under gravitation. Beam balance is used for high precision measurements like masses up to 250g, it consists of a pair of scale pans one at each end of a rigid beam.

we use a scale to measure the weight of our bodies

một hòn đá có khối lượng 5kg bay với vận tốc 72kg/h . động lượng của hòn đá là

Answers

Answer:

Momentum = 100 Kgm/s

Explanation:

Given the following data;

Speed = 72 km/h

Mass = 5 kg

To find the momentum of the stone;

First of all, we would have to convert the value of speed to meter per seconds.

Conversion:

72 km/h to m/s = (72 * 1000)/3600 = 20 m/s

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

Substituting the values into the formula, we have;

Momentum = 5 * 20

Momentum = 100 Kgm/s

A 45.0 kg student runs at a constant velocity up the incline 6 metres high. If the power output of the student is 1.50 x 103 W, how long does it take the student to run the 9.0 m along the incline?

Answers

Answer:

The time taken is 1.76 s.

Explanation:

mass of student, m = 45 kg

height, h = 6 m

power, P = 1500 W

Power is defined as the rate of doing work.

Work done in moving height is

W = m g h

Let the time is t.

P = m g h / t

1500 = 45 x 9.8 x 6 / t

t = 1.76 s

how do atoms lose electrons ?

Answers

Atoms lose electrons by a process called ionic bonding. Specifically, the metal atom donates its electron to a non-metal atom and thus takes on the noble gas electron configuration of the noble gas in the period (row of the periodic table) preceding its own.

Answer:

Explanation:

By being close to an atom that will gladly take the electrons being offered.

Suppose you are talking about Be. It is in the second column. It has two outer electrons that can be given away. It will not give away one of the two remaining electrons because they are too close to the + nucleus.

Along comes a Fluorine atom. It has 7 electrons in its outer ring. The chemistry of the situation allows it to take on one of the two electrons Be is offering. It is all a matter of charges and attractions.

Another Fluorine atom will take on the remaining electron from the Be. The outer ring cannot take on more than 1 electron, but that is enough

A motorcycle moving with velocity and 30m/s accelerate with 4m/s2 to gain velocity of 6mls. calculate its time to gain that velocity​

Answers

Initial velocity=30m/s=uAcceleration=a=4m/s^2Final velocity=v=6m/sTime=t

Using first equation of kinematics

[tex]\boxed{\sf v=u+at}[/tex]

[tex]\\ \sf\longmapsto t=\dfrac{v-u}{a}[/tex]

[tex]\\ \sf\longmapsto t=\dfrac{30-6}{4}[/tex]

[tex]\\ \sf\longmapsto t=\dfrac{24}{4}[/tex]

[tex]\\ \sf\longmapsto t=6s[/tex]

Người ta thực hiện công 100J để nén khí trong một xilanh. Biết khí truyền ra xung quanh là nhiệt lượng 20J. Độ biến thiên nội năng của khí là

Answers

Answer:

DU = -80 Joules

Explanation:

Given the following data;

Work done = 100 J

Quantity of heat = 20 J

To find change in internal energy of the gas;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

DU is the change in internal energy.

Q is the quantity of energy.

W is the work done.

Substituting the values into the formula, we have;

DU = 20 - 100

DU = -80 Joules

Therefore, the final energy of the gas is lower than its initial energy.

If 200 ml of tea at 90 °C is poured into a 400 g glass cup initially at 25 °C, what would be the final temperature of the mixture?
Note: The specific heat capacity of water is 4186 J/kg °C, and the specific heat capacity of glass is 840 J/kg °C.

Answers

The final temperature of the mixture is 43.62 °C, If 200 ml of tea at 90 °C is poured into a 400 g glass cup initially at 25 °C.

To solve the question above, we apply the law of calorimetry

The law of calorimetry: which states that if there is no lost of heat the surrounding, heat lost is equal to heat gained, or it can be stated as heat absorbed by a cold body is equal to heat released by a hot body, provided there is no lost of heat to the surrounding.

The law above is expressed mathematically as

[tex]Cm(T-t) = C'm'(t-T')[/tex]............. Equation 1

Using equation 1 to solve the question,

Let: C = specific heat capacity of glass cup, m = mass of glass cup, C' = specific heat capacity of tea, m' = mass of tea, T = initial temperature of tea, T' = initial temperature of glass cup, t = final temperature of the mixture.From the question,Given: m = 400 g = 0.4 kg, C = 840 J/kg°C, m' = 200g (tea is a liquid made of water and the volume of water in ml is thesame a its mass in gram) = 0.2 kg, C' = 4186 J/kg.°C, T = 90°C, T' = 25°CSubstitute these values into equation 1 and solve for t₃

[tex]0.4(840)(90-t) = 0.2(4186)(t-25)[/tex]

[tex]336(90-t) = 837.2(t-25)[/tex]

[tex]30240-336t = 837.2t-20930[/tex]

collect like terms

[tex]837.2t + 336t = 30240+20930[/tex]

[tex]1173.2t = 51170[/tex]

[tex]t = 51170/1173.2[/tex]

[tex]t = 43.62[/tex] °C

Hence, the final temperature of the mixture is 43.62 °C

Learn more about calorimeter here: https://brainly.com/question/15479803

Answer:

The final temperature of the system is 41.657 °C.

Explanation:

Let consider the tea-cup system as an isolated system, that is, a system with no energy and mass interactions with the surroundings. From the perspective of the First Law of Thermodynamics, the tea releases heat, which is received by the glass cup until thermal equilibrium is reached. The following formula represents the model under assumption that process was at steady state:

[tex]\rho_{w}\cdot V\cdot c_{w}\cdot (T_{w,o}-T) + m_{g}\cdot c_{g}\cdot (T_{g,o}-T) = 0[/tex] (1)

Where:

[tex]\rho_{w}[/tex] - Density of water, in grams per mililiter.

[tex]V[/tex] - Volume of tea, in mililiters.

[tex]c_{w}[/tex] - Specific heat of water, in joules per gram-degree Celsius.

[tex]m_{g}[/tex] - Mass of the glass cup, in kilograms.

[tex]c_{g}[/tex] - Specific heat of the glass cup, in joules per gram-degree Celsius.

[tex]T_{w,o}[/tex] - Initial temperature of tea, in degrees Celsius.

[tex]T_{g,o}[/tex] - Initial temperature of the glass cup, in degrees Celsius.

[tex]T[/tex] - Final temperature of the tea-cup system, in degrees Celsius.

If we know that [tex]\rho_{w} = 1\,\frac{g}{mL}[/tex], [tex]V = 200\,mL[/tex], [tex]c_{w} = 4.186\,\frac{J}{g\cdot ^{\circ}C}[/tex], [tex]m_{g} = 400\,g[/tex], [tex]c_{g} = 0.840\,\frac{J}{g\cdot ^{\circ}C}[/tex], [tex]T_{w,o} = 90\,^{\circ}C[/tex] and [tex]T_{g,o} = 25\,^{\circ}C[/tex], then the final temperature of the tea-cup system is:

[tex]\rho_{w}\cdot V\cdot c_{w}\cdot (T_{w,o}-T) + m_{g}\cdot c_{g}\cdot (T_{g,o}-T) = 0[/tex]

[tex]\rho_{w}\cdot V\cdot c_{w}\cdot T_{w,o} +m_{g}\cdot c_{g}\cdot T_{g,o} - (\rho_{w}\cdot V\cdot c_{w}+m_{g}\cdot c_{g})\cdot T = 0[/tex]

[tex]T = \frac{\rho_{w}\cdot c_{w}\cdot T_{w,o}+m_{g}\cdot c_{g}\cdot T_{g,o}}{\rho_{w}\cdot V\cdot c_{w}+m_{g}\cdot c_{g}}[/tex]

[tex]T = \frac{\left(1\,\frac{g}{mL} \right)\cdot \left(4.186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (200\,mL)\cdot (90\,^{\circ}C)+(400\,g)\cdot \left(0.840\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (25\,^{\circ}C)}{\left(1\,\frac{g}{mL} \right)\cdot \left(4.186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (200\,mL) +(400\,g)\cdot \left(0.840\,\frac{J}{g\cdot ^{\circ}C} \right)}[/tex]

[tex]T = 41.657\,^{\circ}C[/tex]

The final temperature of the system is 41.657 °C.

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