the wavelength of a light wave whose frequency 5.0x 10^9 s^-1 is

Answers

Answer 1

Answer:

wavelength = 6 cm .

Explanation:

frequency given = 5 x 10⁹ .

wavelength = velocity of light / frequency

= 3 x 10⁸ / 5 x 10⁹

= .06 m

= 6 cm


Related Questions

If the temperature outside increases, but the amount of water vapor stays the same, what happens to the relative humidity? (50 points, please explain)

Answers

If the water vapor content remains the same and the temperature decreases, the relative humidity rises.

If the water vapor content remains the same and the temperature increases, the relative humidity falls.

This is because colder air doesn’t need as much moisture to become saturated as warmer air.

Hope this helps

what is the difference between an exothermic and endothermic reaction.

Answers

Answer:

An endothermic reaction takes in heat, but feels cold to the touch. An exothermic reaction gives off heat and feels warm to the touch because it is heating the outside objects.

What is sodium bicarbonate an example of? a buffer an acid a liquid a base

Answers

Answer:

base

Explanation:

carbonic acid - H2CO3 - is a weak acid. Therefore, HCO3 itself is its conjugate base. The Na(sodium) ion is neutral.

This means that NaHCO3 is a base. (a weak one)

Describe one way in which uranium is disposed of.

Answers

Answer:

In the oxide form, uranium can be disposed of as low-level radioactive waste at an approved disposal facility. Approximately 350,000 tons of anhydrous HF are used annually in the United States.

Explanation:

Which of he following is a secondary alkanol?
a. CH3CH2CH2OH
b. CH3CH2CH2CH2OH
c. C(CH3)3OH
d. CH3CH(OH)CH3

Answers

Answer: Thus [tex]CH_3CH(OH)CH_3[/tex] is a secondary alkanol.

Explanation:

Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.

Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: [tex]CH_3CH_2CH_2OH[/tex] and [tex]CH_3CH_2CH_2CH_2OH[/tex]

Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example: [tex]CH_3CH(OH)CH_3[/tex]

Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: [tex]C(CH_3)_3OH[/tex]

Thus [tex]CH_3CH(OH)CH_3[/tex] is a secondary alkanol.

How marly electrons are in an atom of elemental
sodium?

Answers

Answer: 11 Electrons

Explanation:

We know that the atomic number of sodium is 11. This tells us that sodium has 11 protons and because it is neutral it has 11 electrons.

Answer:

The sodium atom is left with a full outermost electron shell with eight electrons, and the outermost shell of the other atom is full as well.

Explanation:

The sodium atom now has a positive electrical charge of plus 1, and the other atom has a negative charge of minus 1. The two opposite charges attract, and the two atoms now form the molecule of a compound.

Which structure below contains all of the others?
DNA
gene
chromosome
nucleus

Answers

Answer:

nucleus

Explanation:

The nucleus holds all the other things, keeping them safe and confined.

Answer:

Nucleus

Explanation:

It contains DNA which contains a GENE which contains a CHROMOSOME so its NUCLEUS

What shape would a molecule with two bound groups and two lone pairs
have?
A. Trigonal pyramidal
B. Tetrahedral
C. Linear
D. Bent

Answers

Answer:

It would have to be D, a bent shape

Explanation:

I just took the quiz

If 1.50 L of 0.780 mol/L sodium sulfide is mixed with 1.00 L of a 3.31 mol/L lead(II) nitrate solution, what mass of precipitate would you expect to form?

Answers

Answer:

336.1 g of PbS precipitate

Explanation:

The equation of the reaction is given as;

Na2S(aq) + Pb(NO3)2(aq) ----> 2NaNO3(aq) + PbS(s)

Ionically;

Pb^2+(aq) + S^2-(aq) -----> PbS(s)

Number of moles of sodium sulphide= concentration of sodium sulphide × volume of sodium sulphide

Number of moles of sodium sulphide= 0.780 × 1.5 = 1.17 moles

Number of moles of lead II nitrate= concentration of lead II nitrate × volume of lead II nitrate

Number of moles of lead II nitrate= 3.31× 1.00= 3.31 moles

Then we determine the limiting reactant. The limiting reactant yields the least amount of product.

Since 1 moles of sodium sulphide yields 1 mole of lead II sulphide

1.17 moles of sodium sulphide also yields 1.17 moles of lead II sulphide

Hence sodium sulphide is the limiting reactant.

Thus mass of precipitate formed= amount of lead II sulphide × molar mass of sodium sulphide

Molar mass of lead II sulphide= 287.26 g/mol

Mass of lead II sulphide = 1.17 moles × 287.26 g/mol

Mass of lead II sulphide= 336.1 g of PbS precipitate

the vessel in which electrolysis takes place is called


PLEASE GUYS ANSWER IT

Answers

The process of electrolysis is carried out by taking the solution of an electrolyte in a suitable vessel. The vessel is called electrolytic tank.

Potassium atoms contribute one eletron to metallic bonding,but calcium atoms contribute two eletrons .Explain which metal is likely to be harder

Answers

Answer:

potassium is likely to be harder

Explanation:

because whenan atom loss electron they can form particle ion acquare stable a arrangement that loos electron can transfer to another which that also to acquaire stable

7. What volume of a 0.10 mol/l HCl solution is needed to neutralize 10 ml of a 0.15
mol/l LiOH solution (5 points)

Answers

Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]HCl[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is LiOH.

We are given:

[tex]n_1=1\\M_1=0.10mol/L\\V_1=?mL\\n_2=1\\M_2=0.15mol/L\\V_2=10mL[/tex]

Putting values in above equation, we get:

[tex]1\times 0.10\times V_1=1\times 0.15\times 10\\\\V_1=15mL[/tex]

Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

Allicin is the compound responsible for the characteristic smell of Garlic. An analysis of the compound gives the following percent composition by mass; C = 44.4 percent, H = 6.21 percent. S = 39.5 percent, O = 9086 percent. Calculate its empirical formula. What is its molecular formula given that its molar mass is about 162 g?

Answers

Answer:

The empirical formula is same as the molecular formula = C6H10S2O

Explanation:

we start by dividing the percentage of each of the elements by their atomic mass

Carbon = 44.4/12 = 3.7

Hydrogen = 6.21/1 = 6.21

Sulphur = 39.5/32 = 1.234375

oxygen = 9.89/16 = 0.618125

That of oxygen is smallest so we divide all by that of oxygen

C = 3.7 / 0.618125 = 6

H = 6.21/ 0.618125 = 10

S = 1.234375/ 0.618125 = 2

Automatically, oxygen is 1

So the empirical formula is;

C6H10S2O

Let’s get its molecular formula. We multiply each of the subscript by the number;

(72 + 10 + 64 + 16)n= 162

162n = 162

n = 1

So the molecular formula is same as the empirical formula

Predict your observation if a magnesium ribbon is put in potassium hydroxide solution and tested with a lighted wooden splinter.​

Answers

mg reacts with the acid and produce visible bubbles of hydrogen gas. they will produce audible pops as the hydrogen ignites. ... Hydrochloric acid is a corrosive liquid. Hydrogen gas is explosive.

4. Why does ammonia, NH3, behave as a base when it reacts with an acid?
A It accepts a neutron and becomes NH3+.
B It accepts a proton and becomes NH4+.
OC It donates a proton and becomes NH2

Answers

B is the answer ,ammonium accepts a proton and becomes ammonium ion

1. Calculate the pH of a 0.35 mol/L solution of ammonia.

Answers

Answer:

Explanation:

NH3 + H2O ⇌ NH4  + OH-

0.35                              0.35

-log[OH-] = -log0.35 = 0.46 = pOH

14 - 0.46 = 13.54 = pH

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