TIMED!! pls
What are the zeros of the quadratic function f(x) = 2x^2 + 16x - 9?

Using it's concept, it is found that Brandon's net yardage for the game was of 26.

The total net yardage is the sum of all the yardage they gain, that is, the positive gains are added with a plus signal, while the negative gains are added with a negative signal.

Hence, his net yardage, considering that he gained 20 yards on his last 7 carries, is given by:

6 + 20 = 26.

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Answer:

Step-by-step explanation:

Comment

x and 133 sit on the the same straight line with MO in common. Therefore they are supplementary which means that the add to 180o.

Equation

x + 133 = 180

Solution

Subtract 133 from both sides

x + 133 = 180                    

x + 133 - 133 = 180 - 133

x = 47 degrees.

Answer

x = 47

Answer:

rate = 0.4 %

Step-by-step explanation:

Interest = principal x rate x time

33549 = 8635 x r x 11

33549 = 94985r

r = 33549/94985

r = 0.3532

r = 0.4

rate = 0.4 %

Answer:

No. There should be 210 small triangles

Step-by-step explanation:

The number of small triangles in these figures forms a sequence

Fig         No Small Triangles
1             1
2            3  (1+2)
3            6  (1+2+3)

So the nth figure should have 1+2+3+.....+(n-1)+ n

1+2+3+.....+(n-1)+ n = [tex]\frac{n (n-1)}{2}[/tex]
So for 20th figure, n = 20 and number of small triangles = 20 x 21 /2 = 420/2 = 210

Answer:

y = 16.5 ft

Step-by-step explanation:

• in the right triangle BCD :

cos(∠BCD) = 8/14

________

• In the right triangle ABC :

cos(∠BCA) = 14/(8+y)

________

Since ∠BCD and ∠BCA are the same one

then

cos(∠BCD) = cos(∠BCA)

Therefore

[tex]\frac{8}{14} =\frac{14}{y+8}[/tex]

[tex]\Longleftrightarrow 8(y+8)=14^2[/tex]

[tex]\Longleftrightarrow 8y+64=196[/tex]

[tex]\Longleftrightarrow 8y=196-64[/tex]

[tex]\Longleftrightarrow 8y=132[/tex]

[tex]\Longleftrightarrow y=\frac{132}{8}[/tex]

[tex]\Longleftrightarrow y=16.5[/tex]

Answer:

n = 250

See solution and check blow.

Step-by-step explanation:

Solution:

-17 + n/5 = 33

Add 17 to both sides.

-17 + 17 + n/5 = 33 + 17

n/5 = 50

Multiply both sides by 5.

n/5 × 5 = 50 × 5

n = 250

Check:

-17 + n/5 = 33

Since we found out that n = 250, substitute 250 for n in the equation.

-17 + 250/5 = 33

Simplify the left side. Divide 250 by 5.

-17 + 50 = 33

Add on the left side.

33 = 33

Since 33 = 33 is a true statement, the solution n = 250 is correct.

Answer:

There are 240 students in the school

Step-by-step explanation:

Givens

55% of the total number of students in a school are girls.

Equation

55/100 * x = 132

Solution

Multiply both sides of the equation  by 100

55/100x * 100  = 132 * 100

55x = 13200                          Divide by 55

55x/55  = 13200/55

x = 240

The vertex form of the give quadratic equation is f(x) = (x+1)² + 2

The standard vertex form of a quadratic equation is expressed as

y = a(x -h)² + k

where (h, k) is the vertex

Given the quadratic equation

f(x) = x^2 + 2x + 3

Complete the question

f(x) = (x^2+2x) + 3

f(x) = (x^2+2x+1)-1 + 3

f(x) = (x+1)² + 2

Hence the vertex form of the give quadratic equation is f(x) = (x+1)² + 2

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The solution for the given equation will be x=7.8873 and x=0.112699.

The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.

Find the Solution for

9x²−72x+8=0

using the Quadratic Formula where

a = 9, b = -72, and c = 8

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\dfrac{(-72)\pm\sqrt{(-72)^2-4(9)(8)}}{2(9)}[/tex]

x=   [tex]\dfrac{72\pm4896}{\sqrt{18}}[/tex]

The discriminant b2−4ac>0

so, there are two real roots. After solving for plus and then minus we will get two values as follows.

x=7.8873

x=0.112699

Therefore the solution for the given equation will be x=7.8873 and x=0.112699.

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Answer: Quadrant III

Step-by-step explanation:

The slope is negative and the y-intercept is positive.

This means that it is impossible for both x and y to be negative, and thus it does not pass through Quadrant III

£36

20+25=45          Take away 13 and it's 32.   32+4 (the shipping charge) is 36. So Ruth pays 36 pounds.

Answer:

20 counters/box

Step-by-step explanation:

Missing counters(m)= 8

Total number of counters available (t-m)= 132

Required number of counters(t):

=(t-m) + m

= 132 + 8 = 140

Total number of boxes(tB) = 7( 6 full and one with eight missing)

Total Counters/Boxes= t/tB

= 140/7

= 20

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Answer:  [tex]\textsf{Option A, (-2, 4)}[/tex]

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Given:  [tex]\textsf{f(x) = x + 6}[/tex]

Find:  [tex]\textsf{f(-2)}[/tex]

Solution:  We need to plug in the value -2 into every variable x that we have in the expression and simplify to get the solution.

Plug in the values

Simplify

Therefore, the ordered pair that would match would have a x-coordinate of -2 and a y-coordinate of 4 producing (-2, 4) which matches option A.

Answer:

A fraction equivalent to [tex]\frac{1}{2}[/tex] on the number line is [tex]\frac{3}{6}[/tex].

Drag the dot to [tex]\frac{3}{6}[/tex] on the number line.

Step-by-step explanation:

3 is half of 6. To check if this is correct multiply [tex]\frac{1}{2}[/tex] and 3.

[tex]\frac{1}{2}*3=\frac{3}{6}[/tex]

Hope this helps!

If not, I am sorry.

Answer:

6 because 30 divided by 5 is 6 so he would have 1$ change

Answer:

Toby can buy 6 T-shirts with 1 extra dollar leftover

Step-by-step explanation:

Hook me up with a 5 star and a thanks :)

Answer:

.

Step-by-step explanation:

The values of k and r are given by 5 and 3 respectively.

Here in this problem it is given that,

General formula for the sequence is given by,

[tex]U_{n+1}=kU_n+r[/tex]

First term of the sequence, [tex]U_1=37[/tex]

Second term,

[tex]U_2=188[/tex]

[tex]U_{1+1}=188[/tex], rearranging

[tex]kU_1+r=188[/tex], applying general formula

[tex]37k+r=188[/tex]..........(1)

Third term,

[tex]U_3=943[/tex]

[tex]U_{2+1}=943[/tex], rearranging

[tex]kU_2+r=943[/tex], applying general formula

[tex]188k+r=943[/tex]..........(2)

Now (2) - (1) we get,

188k+r-37k-r = 943-188

151k = 755

k = 755/151 = 5

Hence the value of k is 5.

Substituting the value of k in (1) we get,

37*5+r = 188

185+r = 188

r = 188-185 = 3

Thus the value of r is 3.

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Answer:

w≈7.6in

Step-by-step explanation:

L= 7.25

D= 10.5

Answer:-

The width of this rectangle is = 7.59

Given:-

In this question, it is given that -

The diagonal of this rectangle is = 10.5

the length of this rectangle is = 7.25

To find:-

We have to find the width of this rectangle.

Solution:-

We can easily solve this problem using the Pythagorean theorem.

In this problem, it is given that the length of this rectangle is = 7.25 and the diagonal is =10.5

so by the Pythagorean theorem, we can get-

(length)² + (width)² = (diagonal)²

or, (7.25)² + (width)² = (10.5)²

or, (width)² = (10.5)² - (7.25)²

= 17.75 × 3.25

= 57.6875

or, width = 7.59

So, the width of the rectangle is 7.59.

The graph would be the normal parent function of f(x) but all points would be 6 units up.

There's an upward vertical shift of 6. To graph this, you need to graph the function f(x) and then add 6 units to all the y values.

Answer:

9. 15b + 4

10. 4y + 6

11. 15r+72

12. 130n + 20

Step-by-step explanation:

9. Combine Like terms

10. Combine Like terms

11. Distribute the 8 into (r + 9) then combine like terms

12. Distribute 10 into (3n + 2 + 10n) then combine like terms

Answer:

[tex]\mathsf {9) 15b + 4}\\\mathsf {10) 4y + 6}\\\mathsf {11) 15r + 72}\\\mathsf {12) 130n + 20}[/tex]

Step-by-step explanation:

[tex]\textsf {Question 9}[/tex]

[tex]\mathsf {3 + 8b + 4 + 7b - 3}[/tex]

[tex]\mathsf {8b + 7b + 4 + 3 - 3}[/tex]

[tex]\mathsf {15b + 4}[/tex]

[tex]\textsf {Question 10}[/tex]

[tex]\mathsf {8 + 7y - 3y + 2 - 4}[/tex]

[tex]\mathsf {7y - 3y + 8 + 2 - 4}[/tex]

[tex]\mathsf {4y + 6}[/tex]

[tex]\textsf {Question 11}[/tex]

[tex]\mathsf {8(r + 9) + 7r}[/tex]

[tex]\mathsf {8r + 8(9) + 7r}[/tex]

[tex]\mathsf {8r + 7r + 72}[/tex]

[tex]\mathsf {15r + 72}[/tex]

[tex]\textsf {Question 12}[/tex]

[tex]\mathsf {10(3n + 2 + 10n)}[/tex]

[tex]\mathsf {10(13n + 2)}[/tex]

[tex]\mathsf {10(13n) + 10(2)}[/tex]

[tex]\mathsf {130n + 20}[/tex]

The inequality 4(x – 3) + 4 < 10 + 6x is solved as x > -9. Then the variable x is greater than the negative 9. Then the correct option is B.

Inequality is defined as an equation that does not contain an equal sign.

The inequality equation is given below.

4(x – 3) + 4 < 10 + 6x

Then the steps of solving are given below.

1. The distributive property: 4x – 12 + 4 < 10 + 6x

2. Combine like terms: 4x – 8 < 10 + 6x

3. The addition property of inequality: 4x < 18 + 6x

4. The subtraction property of inequality: –2x < 18

5. The division property of inequality: x > –9

Then x is greater than the negative 9.

Then the correct option is B.

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Answer:

1. Statement C is not true.

2. Option B is correct

3. Option C is correct

4.Option C is correct

Step-by-step explanation:

1. There are 5 Platonic solids : The tetrahedron, cube

,octahedron, dodecahedron ,icosahedron.

therefore statement C is incorrect.

2. Polyhedron formula : Vertices - Edges + Faces = 2

now put the values

12 - 18 + F= 2

F = 8.

3. Polyhedron formula : Vertices - Edges + Faces = 2

now put the values

V - 30 + 12 = 2

V = 20.

4. Probability is the number of favourable or unfavourable event divided by total events.

therefore denominator always greater than numinator.

so [tex]\frac{8}{7}[/tex] cannot represent the probability

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Answer:

vertex = ( [tex]\frac{2}{3}[/tex], [tex]\frac{8}{3}[/tex] )

Step-by-step explanation:

given the equation of a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

x = - [tex]\frac{b}{2a}[/tex]

y = 3x² - 4x + 3 ← is in standard form

with a = 3 , b = - 4 , then

x = - [tex]\frac{-4}{6}[/tex] = [tex]\frac{2}{3}[/tex]

substitute x = [tex]\frac{2}{3}[/tex] into the equation for corresponding y- coordinate of vertex

y = 3([tex]\frac{2}{3}[/tex] )² - 4([tex]\frac{2}{3}[/tex] ) + 3

  = 3([tex]\frac{4}{9}[/tex] ) - [tex]\frac{8}{3}[/tex] + 3

  = [tex]\frac{4}{3}[/tex] - [tex]\frac{8}{3}[/tex] + [tex]\frac{12}{3}[/tex]

  = [tex]\frac{8}{3}[/tex]

vertex = ( [tex]\frac{2}{3}[/tex], [tex]\frac{8}{3}[/tex] )

Answer:x>7

Step-by-step explanation:

Its saying a nuber greater than 7 and 3 plus 8 would be 11

Answer:

Step-by-step explanation:

The quadratic expression having repeated root is 8x² - 32x + 32.

Quadratic expressions are polynomial expressions of second degree.

The general form of a quadratic expression is ax² + b x + c.

We have to find the root of each quadratic expression.

x² - 18x - 81 = 0

Discriminant = [tex]\sqrt{(-18)^2-(4*-81)}[/tex] = [tex]\sqrt{648}[/tex]

x = (18 + √648) / 2 or x = (18 - √648) / 2

Distinct roots

x² - 2x + 3

Discriminant = [tex]\sqrt{(-2)^{2}-(4*3) }[/tex] = [tex]\sqrt{-8}[/tex]

x = (2 + [tex]\sqrt{-8}[/tex]) / 2 or x =  (2 - [tex]\sqrt{-8}[/tex]) / 2

Distinct roots

8x² - 32x + 32

Discriminant = [tex]\sqrt{(-4)^{2}-(4*4) }[/tex] = 0

x = (4 + 0)/ 2 or x = (4 - 0) / 2

x = 2 or x = 2

Repeated roots

Hence the quadratic expression having repeated roots is 8x² - 32x + 32.

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[tex] \frac{ - n}{5} + 7 = 2 \\ \\ \frac{ - n + 35}{5} = 2 \\ \\ - n + 35 = 10 \\ \\ - n = 10 - 35 \\ \\ - n = - 25[/tex]

cancel (-) sign both sides ,

[tex]n = 25.[/tex]

Answer:

[tex]12z^{2} -10z -12[/tex]

Step-by-step explanation:

Let the number be z

2 more than 3 times z ==> 3z + 2

6 less than 4 times z ==> 4z - 6

Product of the above two is
[tex](3z + 2) (4z - 6) \\= (3z)(4z) + (3z)(-6) + (4z)(2) + (2)(-6)\\= 12z^{2} -18z + 8z - 12\\= 12z^{2} -10z -12[/tex]

Answer:

Yes

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

4 + -x ==> 4 - x

Example

x = 3; 4 + (-3) = 4-3 =1

Answer:

here is answer try this type