Tony's coins in ascending order of value will be 5p, 10p, and 15p.
Definition of in Ascending order
Arranged in a series that begins with the smallest or least and ends with the largest or greatest The children were lined up in ascending order of height. Test score are listed in ascending order from lowest to highest.
How do depict the information?
Based on the information given, the values of the coins will be 5p, 5p, 10p, 15p, and 15p.
In this case, 5p + 10p + 15p = 30p
10p + 15p + 15p = 40p
5p + 5p + 10p + 15p + 15p = 50p
Therefore, Tony's coins in ascending order of value will be 5p, 10p, and 15p.
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The star shape is made from a regular hexagon and six congruent equilateral triangles The area of the star shape is 96cm squared Work out the area of the regular hexagon.
Answer:
48 Square Centimeters
Step-by-step explanation:
The red triangular exterior pieces are all equilateral triangles with some side length.
We don't need to know what that side length is. It doesn't matter.
The area of one red equilateral triangle is some area A.
There are 6 of these red triangles, so the red exterior triangular parts combine to a total area of 6*A.
The hexagon is composed of equilateral triangles as well.
Each of these blue equilateral triangles is congruent to any outer red triangle because the side length is the same.
Therefore, the 6 blue equilateral triangles composing this hexagon combine to get a total area of 6*A
The area of the star overall is 12*A because we have 6 blue triangles combining with the 6 red triangles.
There is a total of 12 triangles.
A culture started with 2,000 bacteria. After 2
hours, it grew to 2,400 bacteria. Predict how
many bacteria will be present after 10 hours.
Round your answer to the nearest whole
number.
P
Aekt
4. Minnie bought 6 postcards during 3 days of vacation. After 8 days of vacation, how many total postcards will Minnie have bought?
A. 4
B. 5
C. 16
D. 12
BC and DE are tangents to this circle. Work out the size of angle 0. Give reasons for your answer. A 52° B O D 27° E 0 C Not drawn accurately BC and DE are tangents to this circle . Work out the size of angle 0 . Give reasons for your answer . A 52 ° B O D 27 ° E 0 C Not drawn accurately
Answer:
Θ = 39°
Step-by-step explanation:
OA = OB ( radii of the circle ) , then
Δ AOB is isosceles with base angles congruent , that is
∠ ABO = ∠ BAO = 52°
the exterior angle of a triangle is equal to the 2 opposite interior angles.
∠ DOB is an exterior angle of the triangle , so
∠ DOB = ∠ ABO + ∠ BAO = 52° + 52° = 114°
the angle between a tangent and the radius at the point of contact is 90°, then
∠ OBC = ∠ ODE = 90°
the sum of the 4 interior angles of quadrilateral OBCD = 360°
∠ OBC + ∠ DOB + ∠ ODC + ∠ BCD = 360°
90° + 114° + (90 + 27)° + Θ = 360°
90° + 114° + 117° + Θ = 360°
321° + Θ = 360° ( subtract 321° from both sides )
Θ = 39°
Which foundation drawing matches this orthographic drawing?
The figure second represents the foundation drawing of a provided front, right, and top view option second is correct.
What is orthographic drawing?Three-dimensional objects can be represented in two dimensions via an orthographic projection.
As we have given orthographic drawings.
The front, right, and the top view is shown in the picture of the cuboid if merge all the view we will find the three-dimensional figure is a cuboid.
We can represent the cuboid by 2×3 grids as shown in the picture second.
Thus, the figure second represents the foundation drawing of a provided front, right, and top view option second is correct.
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can someone please help mee i need the exact answer(30 points will give brainliest!!!)
The domain of the given graph is [−3, ∞) and the range is (−∞, 4].
We need to find the domain and range of the given graph.
What are the domain and range of the function?The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values that it can take.
We can observe that the graph extends horizontally from −3 to the right without a bound, so the domain is [−3, ∞). The vertical extent of the graph is all range values 4 and below, so the range is (−∞, 4].
Therefore, the domain of the given graph is [−3, ∞) and the range is (−∞, 4].
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Help! Will mark the big B for correct answer!
Answer:
The answer is A
Step-by-step explanation:
They both have a maximum of 5!
Find the range of values of x for which
[tex]2{x}^{2} \geqslant 9x + 5[/tex]
See attached images for work.
Help please asap points an brainlist
whats the polynomial of (7x+7)(x+2)
Answer:
okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
will you be my friend
Step-by-step explanation:
.......... okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
The function h(x) is a transformation of the square root parent function,
f(x)=√x. What function is h(x)?
-5
5
-5-
h(x)
f(x)
K
I
5
Answer: [tex]h(x)=\sqrt{x+4}[/tex]
Step-by-step explanation:
The graph of h(x) is the graph of f(x) shifted 4 units left.
y = 2x² - 9x + 10
solve the following quadratic function by factoring
whats is 452 divided by2
Answer:
452/2 = 226
Step-by-step explanation:
45 divided by 2 is 22 and the remainder would be 12, which could be divided by 2 again to get 6. Add this to the total and you get 226.
Hope this helps! :D
Work out the area of this triangle
Step-by-step explanation:
the area of a triangle is
baseline × height / 2
baseline and height must be at a right angle with each other.
so, in our case
6 × 11 / 2 = 3 × 11 = 33 cm²
Answer:
Area = 33 cm²
Step-by-step explanation:
[tex]\textsf{Area of a triangle}=\sf \dfrac{1}{2}bh[/tex]
where:
b is the baseh is the height (perpendicular to the base)If we turn the triangle counterclockwise, so that the side that measures 6 cm is the base, we will see that the length that measures 11 cm is the height of the triangle (see attached).
Therefore:
b = 6 cmh = 11 cmSubstitute the found values into the formula and solve for A:
[tex]\implies \sf A=\dfrac{1}{2}(6)(11)[/tex]
[tex]\implies \sf A=\dfrac{1}{2}(66)[/tex]
[tex]\implies \sf A=33[/tex]
Therefore, the area of the triangle is 33 cm²
2/6+5/6 as a whole number
Answer: 2/6+5/6 + 1.167
Answer:
1.16
Step-by-step explanation:
Which rule describes a composition of transformations the maps pre-image PQRSto image P”Q”R”S”
The rule that describes the composition of transformations that maps figure PQRS to figure P"Q"R"S"is r y-axis • RO, 90° (x, y)
How to determine the transformation?See attachment for complete question
From the image, we have:
P = (1,1)
Q = (1,5)
R = (3,5)
S = (3,1)
Start by reflecting PQRS across the y-axis. i.e. r y-axis
This is done by
(x, y) -> (-x,y)
So, we have:
P' = (-1,1)
Q' = (-1,5)
R' = (-3,5)
S' = (-3,1)
Next, we rotate by 90 degrees counterclockwise i.e. RO, 90° (x, y)
This is done by
(x, y) -> (-y, x)
So, we have:
P'' = (-1,-1)
Q'' = (-5,-1)
R'' = (-5,-3)
S'' = (-1,-3)
Hence, the rule that describes the composition of transformations that maps figure PQRS to figure P"Q"R"S"is r y-axis • RO, 90° (x, y)
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The Volume of a cube depends on the length of its sides.This can be written in function notation as v(s).What is the best interpretation of V(3)=27
Answer and Step-by-step explanation:
There is a cube with side length 3. The volume of this cube is 27.
solve for 2.5w+12 on a graph
x-intercept -4.8
y-intercept 12
slope 2.5
plot points
x y
-2, 7
-1, 9.5
0, 12
1, 14.5
2 ,17
What are the solutions of 2x² - 6x+5=0?
Answer:
no solutions
Step-by-step explanation:
we use the quadratic formula.
for an equation ax²+bx+c=0, the solutions for x are:
x = (-b±sqrt(b²-4ac))/2a
in our case, a=2, b=-6 and c=5, so:
x= (6±sqrt(36-40))/4
we see that we get a negative number inside the sqrt, so we have no real solutions
Answer:
No solution
Step-by-step explanation:
1) Use the quadratic formula
[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
[tex]2x^2-6x+5=0[/tex]
[tex]a=2\\b=-6\\c=5[/tex]
[tex]x=\frac{-(-6)\pm\sqrt{(-6)^2-4*2*5} }{2*2}[/tex]
2) Simplify
Evaluate the exponent:
[tex]x=\frac{6\pm\sqrt{(-6)^2-4*2*5} }{2*2}[/tex]
[tex]x=\frac{6\pm\sqrt{36-4*2*5} }{2*2}[/tex]
Multiply the numbers:
[tex]x=\frac{6\pm\sqrt{36-4*2*5} }{2*2}[/tex]
[tex]x=\frac{6\pm\sqrt{36-40} }{2*2}[/tex]
Subtract the numbers:
[tex]x=\frac{6\pm\sqrt{36-40} }{2*2}[/tex]
[tex]x=\frac{6\pm\sqrt{-4} }{2*2}[/tex]
Multiply the numbers
[tex]x=\frac{6\pm\sqrt{-4} }{2*2}[/tex]
[tex]x=\frac{6\pm\sqrt{-4} }{4}[/tex]
3) No real solutions because the discriminant is negative
The square root of a negative number is not a real number
[tex]d=-4[/tex]
Result
No solution
Find the derivative of y = 4x^3.
Find the derivative of y = 2/x^4.
Find the derivative of y = 3√x.
Find the derivative of y = 3/√x.
Find the derivative of y = x^3/4.
Find the derivative of y = 3 x^5.
Answer:
[tex]\fbox {See below} \downarrow[/tex]
Step-by-step explanation:
Question 1 :
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(4x^{3})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = 4(3)x^{3-1}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = 12x^{2}}[/tex]
Question 2 :
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(\frac{2}{x^{4}})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(2x^{-4})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = 2(-4)x^{-4-1}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = -8x^{-5}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = -\frac{8}{x^{5}}}[/tex]
Question 3 :
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(3\sqrt{x})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(3(x)^{\frac{1}{2}})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = 3(\frac{1}{2})x^{\frac{1}{2}-1}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = \frac{3}{2}x^{-\frac{1}{2}}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = \frac{3}{2\sqrt{x}}}[/tex]
Question 4 :
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(\frac{3}{\sqrt{x}})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(3x^{-\frac{1}{2}})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = 3(-\frac{1}{2})x^{-\frac{1}{2}-1}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = -\frac{3}{2}x^{-\frac{3}{2}}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = -\frac{3}{2x\sqrt{x}}}[/tex]
Question 5 :
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(\frac{x^{3}}{4})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = \frac{1}{4}(3)x^{3-1}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = \frac{3}{4}x^{2}}[/tex]
Question 6 :
[tex]\mathsf {\frac{dy}{dx} = \frac{d}{dx}(3x^{5})}[/tex]
[tex]\mathsf {\frac{dy}{dx} = 3(5)x^{5-1}}[/tex]
[tex]\mathsf {\frac{dy}{dx} = 15x^{4}}[/tex]
Match each data set with its standard deviation.
Round your answer to the nearest tenth, if necessary.
Click on the link to use the GeoGebra graphing calculator to assist you.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
{74,76,77,77,78,82,130}
{8,74,76,77,77,78,82}
{74,74,76,77,77,78,82}
Answer:
don't know but please keep trying up
Figure it out..............................................
Determine the linear function for a graph that is a line with a slope of 1/7
and contains the point
(−4, 1).
The linear equation is y = (1/7)*x + 11/7.
How to get the linear equation?
The general linear equation is:
y = a*x + b
Where a is the slope.
Here we know that a = (1/7), then the line is:
y = (1/7)*x + b
We also know that the line contains the point (-4, 1), this means that when x = -4, we must have y = 1.
Replacing that, we get:
1 = (1/7)*(-4) + b
1 + 4/7 = b
7/7 + 4/7 = b
11/7 = b
So the linear equation is:
y = (1/7)*x + 11/7.
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The equation of the linear function of the line is: y = 1/7x + 11/7.
What is a Linear Function Equation?A linear function equation is modelled as, y = mx + b, where m is the slope and b is the y-intercept.
Slope (m) = 1/7, and the line passes through (-4, 1), therefore, substitute (x, y) = (-4, 1) and m = 1/7 into y = mx + b:
1 = 1/7(-4) + b
1 = -4/7 + b
1 + 4/7 = b
11/7 = b
b = 11/7
Plug in the values of m and b into y = mx + b:
y = 1/7x + 11/7
The equation of the linear function is: y = 1/7x + 11/7
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Which expression has a value of 16 when n = 5?
StartFraction 25 Over n EndFraction + 7
30 minus 3 n
7 + StartFraction 45 Over n EndFraction
n cubed minus 114
Answer:
7+45/n or 5
Step-by-step explanation:
45 divided by n or technically 5 is 9 plus 7 is 16 :)
Answer:7+45/n or 5
Step-by-step explanation:
Solve for h in A = ½ ah - ½ bh. Solve for h in A = ½ ah - ½ bh .
Answer:
h = A / ( 1/2 a - 1/2 b)
Step-by-step explanation:
A = ½ ah - ½ bh
Factor out an h
A = h( 1/2 a - 1/2 b)
Divide each side by ( 1/2 a - 1/2 b)
A / ( 1/2 a - 1/2 b) = h ( 1/2 a - 1/2 b)/ ( 1/2 a - 1/2 b)
A / ( 1/2 a - 1/2 b) = h
h = A / ( 1/2 a - 1/2 b)
The diagram below shows a square inside a regular octagon. The apothem of the octagon is 15.69 units. To the nearest square unit, what is the area of the shaded region? 13 U 13 U Apothem length: 15.69 O A. 1463 square units B. 816 square units C. 647 square units OD. 764 square units
perimeter of octagon
8(13)104unitsNow area
perimeter×apothem /2104(15.69)/252(15.69)815.88units²Area of square
13²169units²Area of shaded region
815.88-169646.88units²647units²Answer:
C. 647 square units
Step-by-step explanation:
To find the shaded area, subtract the area of the unshaded square from the area of the octagon.
Area of the octagon
[tex]\textsf{Area of a regular polygon}=\dfrac{n\:l\:a}{2}[/tex]
where:
n = number of sidesl = length of one sidea = apothemGiven:
n = 8l = 13a = 15.69Substitute the given values into the formula and solve for A:
[tex]\implies \textsf{Area}=\sf \dfrac{8 \cdot 13 \cdot 15.69}{2}[/tex]
[tex]\implies \textsf{Area}=\sf \dfrac{1631.76}{2}[/tex]
[tex]\implies \textsf{Area}=\sf 815.88\:\:square \:units[/tex]
Area of the square
[tex]\implies \textsf{Area}=\sf 13^2=169 \:\:square \:units[/tex]
Area of the shaded region
= area of the octagon - area of the square
= 815.88 - 169
= 646.88
= 647 square units (nearest square unit)
Find the distance between the point (3, 5) and a line with the equation 5 x - 3 y + 10 = 0
The distance between the point (3, 5) and a line with the equation 5x – 3y + 10 = 0 will be 10 / √(34) units.
What is the distance between a point and a line?Let (x₁, y₁) be the point and ax + by + c = 0 be the line.
Then the distance between a point and a line will be
[tex]\rm d = \dfrac{|ax_1 + by_1 + c|}{\sqrt{a^2 + b^2}}[/tex]
The point (3, 5) and a line with the equation 5x – 3y + 10 = 0.
Then the distance between them will be
[tex]\rm d = \dfrac{|5 *3 - 3 *5 + 10|}{\sqrt{5^2 + (-3)^2}}\\d = \dfrac{10 }{\sqrt{34}} \ units[/tex]
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There is a lighthouse that is 25 meters tall and a boat is sinking 204 meters away from the lighthouse. To the nearest whole degree, what is the angle of depression from the top of the lighthouse to the sinking boat?
The angle of depression from the top of the lighthouse to the sinking boat is 6.9°.
What is trigonometry?Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.
From ΔABC it is obtained that;
Height of lighthouse, AC = 25 meters
Distance of boat from the lighthouse, BC = 204 meters
The angle of depression from the top of the lighthouse to the sinking boat is;
[tex]\rm tan \theta = \frac{P}{B} \\\\ \rm tan \theta = \frac{AC}{BC} \\\\ tan \theta = \frac{25}{204} \\\\ \theta = tan^{-1}(0.12)\\\\ \theta = 6.9 ^0[/tex]
Hence, the angle of depression from the top of the lighthouse to the sinking boat is 6.9°
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The enrollment for a new program is 1,500 students. the program is expected to grow at a rate of 0.03. what is the expected enrollment in 7 years? round to the nearest whole number.
The expected enrolment in 7 years is 1845.
What is the expected enrolment?The formula for calculating future value of the number of students is an exponential equation with this form:
FV = P (1 + r) ^n
FV = Future populationP = Present populationR = rate of growth of the populationN = number of years1500 x (1.03)^7 = 1845
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if cospheta =3/5 and pheta is located in the fourth quadrant, then sin2pheta=_____
-8/25
24/5
-24/25
8/25
Step-by-step explanation:
if cospheta =3/5 and pheta is located in the fourth quadrant, then sin2pheta=_____
-8/25
24/5
-24/25
8/25
The correct answer for this question is 8/25
The set of life spans of an appliance is normally distributed with a mean mu = 48 months and a standard deviation sigma = 8 months. what is the z-score of an appliance that stopped working at 64 months?
The z-score of an appliance that stopped working at 64 months is 2.
What is mean?The mean of observations is equal to the ratio of sum of all the observations and the number of observations.
Given, the set of life spans of an appliance is normally distributed with a mean mu = 48 months and a standard deviation sigma = 8 months
The z-score is then calculated as
z = x - μ /σ
For an appliance that stopped working at 64 months, we have
x = 64
On substituting the values, we get
z = 64-48/8
z = 2
Hence, the z-score of an appliance that stopped working at 64 months is 2
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Answer:
D on edge
Step-by-step explanation:
2
