Two different isotopes of an element have different?

Answer:

D. Gravity and inertia

When it happens orbital motion occurs

Answer: nonflowering and flowering

Explanation: i just did the quiz

Seed plants are divided into two groups, are nonflowering and flowering plants. Therefore, option C is correct.

Flowering plants create blooms, which they then use as seeds to develop more of their kind or other plants. Nonflowering plants don't produce flowers; instead, they produce microscopic reproductive components called seeds or spores that can be used to create additional plants that look exactly like them.

Gymnosperms and angiosperms are frequently used as arbitrary divisions for the seed plants. The difference between the two is based on the fact that angiosperms produce blooms, whereas gymnosperms do not.

An ovary surrounds the angiosperm seed. A seed grows on the size of a cone in gymnosperms. Inside an ovary, only an angiosperm seed can grow.

Thus, option C is correct.

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Answer: The first question’s answer is 2 and the second question answer is 3. 12.B, 13.C

Explanation:

Answer:

isostatic adjustment movement

Difference between molecular weight and molar mass

Hint : Molar mass of molecules is also called molecular weight . Its unit is gram per mole. We can calculate molar mass of molecule with the help of following rules; ... Molar mass of nitric acid (HNO3) =atomic mass of hydrogen + atomic mass of nitrogen +3× atomic mass of oxygen .

Answer:

answer

Explanation:

Sorry I do not know the answer, hope you have a great day

Answer:

22.4/3.8=5.89

Explanation:

Answer:Hydrogen and Helium

Explanation: Young stars would contain first hydrogen, then helium.

Young stars, just beginning their life in the galaxy, would contain mostly hydrogen and helium. That is option D.

A young star is a newly formed luminous object that is found in the galaxy.

The young star is mostly made up of two very light elements called hydrogen and helium. They also shine by conversion of hydrogen into more helium.

Therefore, Young stars, just beginning their life in the galaxy, would contain mostly hydrogen and helium.

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Answer:

I know that

Explanation:

nickel is like to and tc is like nickel they both have something

Answer:

Oil

Explanation:

Answer:

Approximately [tex]4.5\; \text{hours}[/tex].

Explanation:

Calculate the ratio between the mass of this sample after [tex]22.5\; \text{hours}[/tex] and the initial mass:

[tex]\displaystyle \frac{5.70\; \rm g}{182.4\; \rm g} \approx 0.03125[/tex].

Let [tex]n[/tex] denote the number of half-lives in that [tex]22.5\; \text{hours}[/tex] (where [tex]n\![/tex] might not necessarily be an integer.) The mass of the sample is supposed to become [tex](1/2)[/tex] the previous quantity after each half-life. Therefore, if the initial mass of the sample is [tex]1\; \rm g[/tex] (for example,) the mass of the sample after [tex]\! n[/tex] half-lives would be [tex]{(1/2)}^{n}\; \rm g[/tex]. Regardless of the initial mass, the ratio between the mass of the sample after [tex]n\!\![/tex] half-lives and the initial mass should be [tex]{(1/2)}^{n}[/tex].

For this question:

[tex]{(1/2)}^{n}} = 0.03125[/tex].

Take the natural logarithm of both sides of this equation to solve for [tex]n[/tex]:

[tex]\ln \left[{(1/2)}^{n}}\right] = \ln (0.03125)[/tex].

[tex]n\, [\ln(1/2)] = \ln (0.03125)[/tex].

[tex]\displaystyle n = \frac{\ln(0.03125)}{\ln(1/2)} \approx 5[/tex].

In other words, there are [tex]5[/tex] half-lives of this sample in [tex]22.5\; \text{hours}[/tex]. If the length of each half-life is constant, that length should be [tex](1/5) \times 22.5\; \text{hours} = 4.5\; \text{hours}[/tex].

Options:

It can be separated into carbon and oxygen using physical methods.

Carbon and oxygen retain their original identity in it.

Carbon and oxygen are chemically bonded in it.

Explanation:

Sorry the guy asking forgot to put in the options so comment below the correct answer and brainy STOP DISABLING COMMENTS YOUR CAUSING SO MANY INCORRECT THINGS

Answer:

b

Explanation:

Answer:

Metals tend to have a low attraction for electrons.

Answer:

Rule 1: All nonzero digits in measurement are significant.

Rule 2: Zeros that appear between other nonzero digits (i.e., "middle zeros") are always significant.

Rule 3: Zeros that appear in front of all of the nonzero digits are called leading zeros. Leading zeros are never significant.

Rule 4: Zeros that appear after all nonzero digits are called trailing zeros. A number with trailing zeros that lacks a decimal point may or may not be significant.

Rule 5: Trailing zeros in a number with a decimal point are significant. This is true whether the zeros occur before or after the decimal point.

The second volume :   V₂= 884.14 L

Given

955 L at 58 C and 108 KPa

76 C and 123 KPa

Required

The second volume

Solution

T₁ = 58 + 273 = 331 K

P₁ = 108 kPa

V₁ = 955 L

P₂ = 123 kPa

T₂ = 76 + 273 = 349

Use combine gas law :

P₁V₁/T₁ = P₂V₂/T₂

Input the value :

108 x 955/331 = 123 x V₂/349

V₂= 884.14 L

Answer:

i think their is amswer key for that

Explanation:

Answer:

  P₄  +  4NaOH  + 2H₂O  →  2PH₃  +  2Na₂HPO₃  

Explanation:

The given reaction expression is given as:

              P₄  +  NaOH  + H₂O  →  PH₃  +  Na₂HPO₃  

To solve this problem, now we put coefficients a, b, c, d and e and we use a mathematical approach to solve this problem;

              aP₄  +  bNaOH  + cH₂O  →  dPH₃  +  eNa₂HPO₃  

Conserving P: 4a  = d + e

                  Na: b  = 2e

                  O:  b + c  = 3e

                  H:   b + 2c  = 3d + e

let b  = 1, e  = [tex]\frac{1}{2}[/tex] , c  =  [tex]\frac{1}{2}[/tex], d =  [tex]\frac{1}{2}[/tex], a = [tex]\frac{1}{4}[/tex]

  Multiply through by 4;

b  = 4, e  = 2, c  = 2, d  = 2, a  = 1

        P₄  +  4NaOH  + 2H₂O  →  2PH₃  +  2Na₂HPO₃  

Answer:

wavelength

Explanation:

Answer:

wavelength

Explanation:

Answer:

The atom resembles plum pudding

Explanation:

The discovery of the electron in 1897 by J. J Thomson and the proton in 1917 by Rutherford most directly refuted or replace the idea that the atom resembles plum pudding.

Answer: cc

Explanation:..

Answer:

Mean rate of reaction produced = 0.533 g/sec (approx.)

Explanation:

Given:

Reaction produced = 1.6 gram

Time taken = 30 sec

Find:

Mean rate of reaction produced

Computation:

Mean rate of reaction produced = Reaction produced / Time taken

Mean rate of reaction produced = 1.6 / 30

Mean rate of reaction produced = 0.533 g/sec (approx.)

Answer:

Frying a hamburger

Explanation:

when frying a hamburger you change the properties of the meat by applying heat and in the other answer choices the element is not changed.

Mass of KCl= 1.08 g

Given

1 g of K₂CO₃

Required

Mass of KCl

Solution

Reaction

K₂CO₃ +2HCl ⇒ 2KCl +H₂O + CO₂

mol of K₂CO₃(MW=138 g/mol) :

= 1 g : 138 g/mol

= 0.00725

From the equation, mol ratio K₂CO₃ : KCl = 1 : 2, so mol KCl :

= 2/1 x mol K₂CO₃

= 2/1 x 0.00725

= 0.0145

Mass of KCl(MW=74.5 g/mol) :

= mol x MW

= 0.0145 x 74.5

= 1.08 g

Answer:

2m/s

Explanation:

2meters/second

Answer:

There are 6 oxygen atoms.

Explanation:

Glucose has a chemical formula of: C6H12O6 That means glucose is made of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms.

hope this helps

The molecular formula of glucose is C₆H₁₂O₆, therefore one molecule of glucose has six oxygen atoms.

A chemical formula is a way of representing information about the chemical proportions of atoms of each element that are present in a molecule or chemical compound. The chemical formula can be written by using chemical symbols, numbers, and other symbols, such as commas, dashes, brackets, and plus (+) and minus (−) signs.

A chemical formula of a compound contains no words but can represent certain simple chemical structures. Chemical formulae are usually more limited in power than structural formulae and chemical names. There are two types of chemical formulas one empirical formula and another molecular formula.

In a molecular formula, more than one atom of the same element can be represented by subscripts. The given formula of glucose is C₆H₁₂O₆ and the total number of oxygen atoms in the formula is equal to six.

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