Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelength of d/15. The lasers produce separate interference patterns on a screen a distance 6.00 m away from the slits.A. Which laser has its first maximum closer to the central maximum?B. What is the distance delta ymax-min between the first maxima (on the same side of the central maximum) of the two patterns?C. What is the distance Delta ymax-min between the second maximum of laser 1 and the third minimum of laser 2, on the same side of the central maximum?

Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.

Explanation: I think I'm very stupid

Answer:

hello your question lacks the required diagram attached below is the complete question with the required diagram

answer : Qtotal = 807.4 Mw

Explanation:

Given Data :

disk properties :

∈ = 0.65

D = 200 mm

Ts = 400⁰c

attached below is the detailed solution

The total rate of Heat transferred from the disk

Qtotal = 807.4 Mw

Answer:

V = 0.15m

H = 0.85m

Explanation:

We will be using the conservation of momentum to solve the problem.

m(i).v(i) = m(f).v(f) where

0.028 * 190 = 3.1 * v(f)

v(f) = 5.32/3.1

v(f) = 1.72 m/s

next, we use the conservation of energy to find the vertical displacement.

½mv² = mgh

½v² = gh, making h the subject of formula, we have

h = v²/2g

h = 1.72²/ 2 * 9.81

h = 2.9584 / 19.62

h = 0.15 m

The height, h is the vertical displacement.

Next, we find the angle of the pendulum at the top of the swing.

Φ = cos^-1 [(2.5 - 0.15)/2.5] *the height at which the pendulum is hanging is not given, so I assumed it to be 2.5m, yo can substitute that for whatever it is

Φ = cos^-1(2.35/2.5)

Φ = cos^-1 (0.94)

Φ = 19.95°

This gotten angle is used to find the horizontal displacement

x = 2.5 sinΦ

x = 2.5 sin 19.95

x = 2.5 * 0.34

x = 0.85 m

Answer:

B

Explanation:

EDGE 2020

The rod photoreceptor cell type, which is found in the retina, transmits low-light vision and is primarily in charge of the neural transmission of night vision. Thus, option B  is correct.

We can see at night thanks to rods, and we can see color during the day thanks to cones. Although daylight vision is far more important for us, the topic of why there are roughly 20 times more rods than cones in a human retina has typically been met with a shrug.

Rods function in extremely dim lighting. Because just some light particles (photons) may trigger a rod, we employ these for night vision. Because rods hinder color vision, we experience a grayscale world at night. More than 100 million rod cells make up the human eye.

Therefore, The retina's rod photoreceptor cell type conveys vision in low light and is principally in charge of the neuronal activity of night vision.

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Answer:

3.57

Explanation:

22.2-8.50=13.7                                                                                                                      

13.7/3.84=3.57

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.

Answer:

(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East

(b)  When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West

Explanation:

Given;

a force vector points due east, [tex]F_1[/tex] = 140 N

let the second force = [tex]F_2[/tex]

let the resultant of the two vectors = F

(a) When the resultant force is pointing along east line

the second force must be pointing due east

[tex]F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N[/tex]

[tex]F_2 = 280 \ East[/tex]

(b) When the resultant force is pointing along west line

the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.

[tex]F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N[/tex]

[tex]F_2 = 560 \ West[/tex]

Answer:

152.

Explanation:

2 x 76 = 152

bruh its not that hard

Answer:

152 m

Explanation:

Distance = Speed x Time

[tex]2 \times 76 \\ 152[/tex]

Thus the distance is equal to 152 m.

Answer: 4.7× 10-8 gigameter.

Exgiga meter. Hope this helps :)

Answer:

Angular diameter of Mars = 15.80 * 10^5 arc seconds

The Angular diameter of Mars is 3 times the angular diameter of Jupiter

Explanation:

Average distance of the earth from sun = 150.67 * 10^6 km

assuming the radius of Mars ( average distance from sun) = 209.33 * 10^6 km

assuming the radius of Jupiter(average distance from sun) = 768.71 * 10^6 km

The small-angle formula for mars

angular diameter = ( linear diameter / distance ) * (2.06 * 10^5 )

distance between earth and mars = 54.6 * 10^6 km

linear diameter = 2 * radius = 418.66 * 10^6 km

angular diameter = ( 418.66 / 54.6 ) * 2.06 * 10^5

                             = 15.80 * 10^5 arc seconds

small angel formula for Jupiter

Angular diameter = ( linear diameter / distance ) * (2.06 * 10^5)

distance between Jupiter and earth = 588 * 10^6 km

linear diameter = 2 * radius = 1537.42 * 10^6 km

Angular diameter = ( 1537.42 / 588) * 2.06*10^5

                             = 5.39 * 10^5 arc seconds

comparing the angular diameter of the Mars and that of Jupiter :

The angular diameter of mars / angular diameter of Jupiter

= 15.80 / 5.39 = 2.931 ≈ 3

The correct answer is 36 miles per hour

Explanation:

To find the average speed, the first step is to find the total time and the total distance Lucy covered because the formula for average speed is the total distance divided into the total time.

Total Distance

It is known Lucy covered 2/3 of the total distance first, and then she completed the remaining distance (60 miles). According to this, the last distance or 60 miles represents 1/3 of the total distance.

[tex]\frac{2}{3} + \frac{1}{3} = \frac{3}{3}[/tex]  (Total distance)

Also, if 60 miles is equivalent to 1/3 this number can be used to find the total distance. In this case, just multiply 60 by 3 = 180 miles as 60 is one-third.

This means the total distance is 180 miles

Total Time

It is known the first part of this journey took 3 hours and the second took 2 hours. This means the total time was 5 hours (3 + 2 = 5)

Find the average speed

[tex]Average speed =\frac{Distance}{time}[/tex]

[tex]Average speed = \frac{180 m}{5 h}[/tex]

[tex]Average speed = 36m/h[/tex]

Answer:

YES!

PLEASE I NEED A BRAINLIEST

Answer:

C.  Mass is independent of the force acting on the mass.

Weight depends on the gravitational force acting on the mass.

Example:  A mass of 1 kg on the earth still has a mass of 1 kg on the moon;

whereas the weight of that mass on earth is 9.8 N and only 1/6 of that amount on the moon.

Answer:

a) 0, = -0.33 us

b) 140m

c) No, The event are not simultaneous i.e they did not occur at the same time, the second even (-0.33 usec) occurs 0.33 usec earlier than the first event.

Explanation:

a)

the lorentz factor expression is written as;

y = 1₀ / √(1 - (v²/c²))

where v  is the relative speed of an observer and c is the speed of light

so we were given that relative speed to be o.7c

therefore

y = 1 / √(1 - ((0.7c)² / c²))

y = 1 / √(1 - (0.49c² / c²))

y = 1 / √(1 - 0.49)

y = 1 / 0.7141

y = 1.4

1 - the coordinates  of the first event, the s' frame of reference is,

x1 ' = y(x1 - vt1) = 0

y1 ' = y1, z1' = z1 and

t1 ' = y [t1 - v/c²x1]

= 0

2 - the coordinates of the second event, the s ' frame of reference is'

x2 ' = y(x2-vt2)

= 1.4(100m - 0)

= 140m

y2 ' = y2, z2 ' = z2

t2 ' = y [ t2 - v/c²x2 ]

= 1.4 [ 0 - 0.7c/c²(100) ]

using speed of light c as 3*10^8

1.4 [ 0 - (0.7*3*10^8) / (3*10^8)²(100) ]

= -0.33 us

b)

distance between

delltaX' = X2' - X1'

= 140m - 0

= 140m

c)

No, The event are not simultaneous i.e they did not occur at the same time.

the second even (-0.33 us) occurs 0.33 us earlier than the first event.

Answer:

The. Machine must detect a shift of

1 Hz

Explanation:

Frequency shift is given as

={ ( Vsound +V/ V sound -V) -1}f emitted

So by substitution we have

= { 1540+4E-4/1540-4E)-1) 2*10^6

= 1Hz

Answer:

Explanation:

We shall represent the velocity of cruise ship and coast guard petrol boat in vector form .

velocity of cruise ship

Vcs = - 2.5 j

Vpb =  - 4.8 cos 19 i + 4.8 sin 19 j = - 4.54 i + 1.56 j

velocity of the cruise ship relative to the patrol boat

= Vcs - Vpb

=  - 2.5 j - ( - 4.54 i + 1.56 j  )

=  - 2.5 j  +  4.54 i -   1.56 j  

= 2.04 i - 1.56 j .

x-component of the velocity of the cruise ship relative to the patrol boat

= 2.04 m /s

y-component of the velocity of the cruise ship relative to the patrol boat

= - 1.56 m /s .

Answer:

Time=120seconds

Explanation:

S=300m

V=2.5m/s

t=?

V=S/t

t=S/V

t=300/2.5

t=120 second

Answer:

120 seconds

Explanation:

.....

...

.....

Answer:

Approximately [tex]3.1\; \rm m \cdot s^{-1}[/tex].

Explanation:

The content of this pail is in a centripetal motion because its path forms part of a vertical circle. Let [tex]m[/tex] denote the mass of the contents of this pail, let [tex]v[/tex] denote the (linear) velocity of the content, and let [tex]r[/tex] denote the radius of this circle. The net force on the contents of this pail will thus be:

[tex]\displaystyle F(\text{net}) = \frac{m\, v^2}{r}[/tex] towards the center of the circle.

Assume that there is no friction between the content and walls of the pail. The only two possible forces on the contents pail towards the center would be:

Note that at the top of the circle, both the gravitational pull and the normal force from the bottom point towards the center of the circle. On the other hand, the normal force from the walls of the pail would be perpendicular to the line towards the center of the circle. At that point in the circle, there's no upward force to support the content of the pail. The uniform rotation will be sufficiently fast if it could allow the content to stay in the pail at the top of the circle.

Let [tex]g[/tex] denote the gravitational field strength at the top of this circle. The size of the gravitational pull on the content would be [tex]m\cdot g[/tex]. Let [tex]F(\text{normal})[/tex] denote the normal force from the bottom of the pail on the contents. The sum of these two forces should be equal to the vertical net force on the contents of this pail. That is:

[tex]F(\text{net}) = m\cdot g + F(\text{normal})[/tex].

From the centripetal motion of the content:

[tex]\displaystyle \frac{m\, v^2}{r} = m\cdot g + F(\text{normal})[/tex].

Rearrange to obtain an expression for the normal force:

[tex]\displaystyle F(\text{normal}) = \frac{m\, v^2}{r} - m\cdot g[/tex].

Note, that the normal force the bottom of the pail exerts on the contents should be greater than or equal to zero. While the pail is at the top of the circle, the normal force from the bottom of the pail cannot pull the contents upwards. Hence:

[tex]\displaystyle \frac{m\, v^2}{r} - m\cdot g = F(\text{normal}) \ge 0[/tex].

[tex]\displaystyle \frac{m\, v^2}{r} - m\cdot g \ge 0[/tex].

Rearrange and simplify to obtain:

[tex]\displaystyle \frac{v^2}{r} - g \ge 0[/tex].

[tex]v^2 \ge g\cdot r[/tex].

[tex]v \ge \sqrt{g \cdot r}[/tex].

In other words, if the gravitational field strength is [tex]g[/tex] and the radius of the circle is [tex]r[/tex], the minimum linear velocity required to keep the content in the pail at the top of the circle is [tex]\sqrt{g \cdot r}[/tex].

If [tex]g = 9.81\; \rm N \cdot kg^{-1} = 9.81\; \rm m \cdot s^{-2}[/tex] and [tex]r = 0.82 \; \rm m + 0.185\; \rm m \approx 1.005\; \rm m[/tex], then the minimum value of [tex]v[/tex] would be approximately:

[tex]\sqrt{9.81 \; \rm m \cdot s^{-1} \times 1.005\; \rm m} \approx 3.1\; \rm m \cdot s^{-1}[/tex].

Answer:

v = (1500/10) = 150 [miles/h]

Explanation:

The velocity can be easily calculated using the following kinematics expression:

v = x/t

where:

v = velocity [miles/h]

t = time = 10 [hr]

x = distance = 1500 [miles]

v = (1500/10) = 150 [miles/h]

Answer:

False

Explanation:

It would be a screw

Explanation:

(a)

F = (GM1M2)/r²

F = (6.7 X 10^-11 x 30.3 x 40.17)/0.5²

F = 326.197 x 10^-⁹N

(b)

F =750N

G = 6.7 x 10^-11

M1 = 2050kg

r = 70.3m

M2 = ?

F = (GM1M2)/r²

F x r² = GM1M2

(F x r²)/GM1 = M2

M2 = (750 x 70.3²)/(6.7 x 10^-11 x 2050)

M2 = 26.99kg

Answer:

Explanation:

W=?

Mass=1800kg

g=(9.8m/s^2 constant)

W=mg

W=1800*9.8

W=17649N

Answer:

Explanation:

One of the major differences between nuclear reactions and chemical reactions is that nuclear reactions involve larger amount of energy than chemical energy. This is because the force between the protons and neutrons in the nucleus of an atom is much higher than the force of attraction between electrons and the positively charged nucleus, hence nuclear reactions involves/requires a larger amount of energy (because it's reactions involve the nucleus) than chemical reactions (because it's reactions involve the electrons).

Thus, during nuclear fusion, two light nuclei are bombarded against one another to produce a larger/heavier nuclei with the release of large amount of energy (because the forces between the protons and neutrons are much higher) unlike when two atoms/molecules are chemically combined together to form a new molecule with the rearrangement of electrons in the valence shells of the participating molecules.

The measurement of distance is the length between two places. To measure is to establish the distance between two geometric objects. With a ruler, you can measure distance the most frequently. Ordinarily, eighth-inch (or 0.125 in) segments make up inch rulers.

When calculating the distance to stars, many astronomers choose to use parsecs (abbreviated pc). This is due to the definition's tight connection to a technique for determining the separation between stars. The distance at which 1 AU subtends an angle of 1 arc sec is measured in parsecs.

A unit of measurement is a specific magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind.

Therefore, Any additional amount of that type can be stated as a multiple of the measurement.

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Answer:

BELTS

Explanation:

why would you need belts for running and stuff

Belts are not an important part of exercise clothing.

An exercise is a physical activity performed to increase strength and agility of the muscles as well as to enhance fitness.

During an exercise, it is important to wear clothes that will not hinder movement or cause injury.

Some items of clothing needed in exercise include:

Therefore, belts are not important during exercise.

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Answer:

Explanation:

The velocity of the wrench must be equal to the velocity of the truck . So momentum of the wrench before it hits the wall

= mv = 6 x 13.3 = 79.8 kg m /s

If resisting force of wall be F , impulse on the wrench = F x time

= F x .07

Impulse = change in momentum of the wrench = mv - 0 = mv = 79.8 kgm/s

So F x .07 = 79.8

F = 1140 N .

Answer:

The value is [tex]W_N = 11849 \ J [/tex]

Explanation:

From the question we are told that

The mass of the external weight is [tex]m = 51 \ kg[/tex]

The height through which the mass drops is [tex]h = 5.6 \ m[/tex]

     The  number of revolution made is   [tex]N  = 10100 \  kg[/tex]

    The  diameter of the free moving piston is     [tex]d  = 0.51 \  m \  kg[/tex]

     The distance moved by the free moving piston is   [tex]s  = 0.71 \  m \  kg[/tex]

     The  atmospheric pressure is  [tex]P  = 101 \ kPa = 101*10^{3}\ Pa [/tex]

Generally the workdone by the  external weight is mathematically represented as

      [tex]W_w  =m *  g   *  h[/tex]

=     [tex]  51 *  9.8  *  5.6 [/tex]

=     [tex]2799 N  [/tex]

Generally the workdone by the free moving piston  is mathematically represented as  

        [tex]W_p  =P *  A  *  s[/tex]

Here   A is the cross-sectional area with value  

        [tex] A  =  \pi *  \frac{d^2}{4}[/tex]

        [tex] A  =  3.142 *  \frac{0.51^2}{4}[/tex]

So

       [tex]W_p  =101*10^{3} * 3.142 *  \frac{0.51^2}{4}  *  0.71[/tex]

=>       [tex]W_p  = 14651 [/tex]

So

   The net workdone is mathematically evaluated as

        [tex]W_N   = -W_w+W_p  [/tex]

The negative sign shows that it is acting in opposite direction to [tex]W_N[/tex]

So

       [tex]W_N   = -2799+14651  [/tex]

      [tex]W_N   = 11849 \ J   [/tex]

Answer:

Nearly all frequencies and wavelengths of electromagnetic radiation can be used for spectroscopy. Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.

Explanation:

Answer:

The SI units of the “A” is m (meters)

The SI units of the “B” is m/s^2

Explanation:

Given the distance = d meters.

Time taken to travel = t (seconds)

Function of the distance, d = A + Bt^2

Now we have given the above information and from the given distance function, we have to find the SI units of the A and B. Here, below are the SI units.

Thus, the SI units of the “A” is = m (meters)

The SI units of the “B” is = m/s^2