Using permutation, there are 8 ways to arrange the letters of "millimicron" in order.
What is permutation?
A permutation is a way of arranging objects in a specific order. In mathematics, a permutation of a set is a bijection from the set to itself, where a bijection is a function that maps each element of the set to a unique element of the same set and vice versa.
To find the number of distinguishable ways the letters of the word "millimicron" can be arranged in order, we can use the method of example 9.5.11.
First, we count the number of times each letter appears in the word:
There are 2 "m"s
There are 2 "i"s
There are 2 "l"s
There is 1 "c"
There is 1 "r"
There is 1 "o"
There is 1 "n"
Then, we compute the number of permutations for each group of letters with the same count. The number of permutations of n items, where there are k items of one type, l items of another type, and so on, is given by:
n! / (k! l! ...)
Using this formula, we get:
There are 2! = 2 permutations of the "m"s
There are 2! = 2 permutations of the "i"s
There are 2! = 2 permutations of the "l"s
There is 1! = 1 permutation of the "c"
There is 1! = 1 permutation of the "r"
There is 1! = 1 permutation of the "o"
There is 1! = 1 permutation of the "n"
Therefore, the total number of distinguishable ways the letters of the word "millimicron" can be arranged in order is:
(2!)(2!)(2!)(1!)(1!)(1!)(1!) = 8
So there are 8 ways to arrange the letters of "millimicron" in order.
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In a class of 35 pupils, 15 are girls how many are boys
Answer: 20 boys
Step-by-step explanation:
35 - 15 = 20
The average score on the Stats midterm was 76 points with a standard deviation of 6 ​points, and Karl​'s z-score was −1.
How many points did he​ score?
Karl scored 70 points on the Stats midterm.
We can use the formula for calculating z-scores:
z = (x - mu) / sigma
where:
x is the raw score
mu is the population mean
sigma is the population standard deviation
We know that Karl's z-score was -1, which means his score was 1 standard deviation below the mean. We also know that the mean was 76 points and the standard deviation was 6 points. Therefore:
-1 = (x - 76) / 6
Multiplying both sides by 6, we get:
-6 = x - 76
Adding 76 to both sides, we get:
x = 70
Therefore, Karl scored 70 points on the Stats midterm.
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random samples of players for two types of video games were selected, and the mean number of hours per week spent playing the games was calculated for each group. the sample means were used to construct the 90 percent confidence interval (1.5,3.8) for the difference in the mean number of hours per week spent playing the games. the maker of one of the video games claims that there is a difference in the population mean number of hours per week spent playing the two games. is the claim supported by the interval? responses yes, because 0 is not contained in the interval. yes, because 0 is not contained in the interval. yes, because the midpoint of the interval is greater than 1. yes, because the midpoint of the interval is greater than 1. yes, because the margin of error for the estimate is less than 1. yes, because the margin of error for the estimate is less than 1. no, because the margin of error for the estimate is greater than 1. no, because the margin of error for the estimate is greater than 1. no, because 0 is not contained in the interval.
The given confidence interval for the difference in mean number of hours spent playing two types of video games is (1.5, 3.8) at 90% confidence level.
The maker of one of the games claims that there is a significant difference in the population mean number of hours spent playing the two games. To determine if the claim is supported by the interval, we check if the interval contains 0. Since 0 is not in the interval, we can reject the null hypothesis of no difference in population means at 90% confidence level.
Therefore, the claim is supported by the interval and we can conclude that there is a significant difference in the mean number of hours spent playing the two types of video games.
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A coupon bond which pays interest of $60 annually, has a par value of $1,000, matures in 5 years, and is selling today at a $75.25 discount from par value. The current yield on this bond is:
A. 6.00%
B. 6.49%
C. 6.73%
D. 7.00%
The current yield on this bond is 6.49%.
A bond's yearly interest payment, market price, and par value must be known in order to determine the bond's current yield.
In this question, we are given that the bond pays an annual interest of $60, has a par value of $1,000, and is selling at a $75.25 discount from par value.
So, the market price of the bond is the par value minus the discount, which is [tex]$ 1,000[/tex] - [tex]$75.25[/tex] [tex]= $924.75.[/tex]
To calculate the current yield, we use the formula:
Current Yield [tex]=[/tex] (Annual Interest Payment / Current Market Price) x 100%
With our current values substituted, we obtain:
Current Yield [tex]= ($60 / $924.75) × 100%[/tex]
Current Yield [tex]= 0.0649 × 100%[/tex]
Current Yield [tex]= 6.49%[/tex]%
Therefore, (B) 6.49% is the right response.
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The typical level of a low tide at a beach is the zero point on the number line each days high and low tides are measured relative to the typical low tide on Monday morning. Low tide is a -0. 8 feet on Tuesday morning. Low tide is at -0. 4 feet write an any quality to compare the Lodi’s on Monday and Tuesday mornings
As per the inequality -0.4 < 0 which indicates that the low tide on Wednesday is also less than the typical low tide on Monday.
In this case, we can use the symbol < to indicate that the low tide on Tuesday morning is less than the low tide on Monday morning. This can be written as:
-0.8 < 0
The left-hand side of this inequality represents the low tide on Tuesday morning (-0.8 feet) and the right-hand side represents the typical low tide level on Monday morning (0 feet). The inequality indicates that the low tide on Tuesday is less than the typical low tide on Monday.
Similarly, we can compare the low tide on Wednesday morning to the low tide on Monday morning using the same inequality:
-0.4 < 0
In summary, we can use inequalities to compare the low tides on different days relative to a reference point. By using the typical low tide on Monday morning as the reference point, we can see that the low tides on Tuesday and Wednesday mornings are both lower than the typical low tide.
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A grocer mixes trail mix that costs $3.00 per pound with trail mix that costs $1.50 per pound. He makes 15 lb of trail mix that costs $2.50 per pound. How much of each trail mix did the grocer use?
HELP ASAP ITS DUE IN LIKE 10 MINS !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
The grocer used 10 lbs of trail mix that costs $3.00 per pound and 5 lbs of trail mix that costs $1.50 per pound.
What is the number of each mix?The number of each trail mix used by the grocer is calculated as follows
Let the trail mix that costs $3.00 per pound = x
Let the trail mix that costs $1.50 per pound = y
x + y = 15 ---- (1)
3x + 1.5y = 2.5(15)
3x + 1.5y = 37.5 ------- (2)
From equation (1), y = 15 - x
Substitute the value of x as follows;
3x + 1.5(15 - x) = 37.5
3x + 22.5 - 1.5x = 37.5
1.5x = 15
x = 15/1.5
x = 10
Substituting x = 10 in equation 1, we get:
10 + y = 15
y = 15 - 10
y = 5
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7.03 Inscribed Quadrilaterals
pls help
The measures of the angles of cyclic quadrilaterals will be -
Blank 1: 98 degrees
Blank 2: 82 degrees
The sum of the opposite angles of a cyclic quadrilateral is 180 degrees.
Given that, the angles of the cyclic quadrilateral are
angle BAD = 14x
angle ADC = 10x + 5
angle ABC = 15x
Clearly angle ABC and angle ADC are opposite angles of a cyclic quadrilateral. So,
angle ABC + angle ADC = 180
15x + 10x + 5 = 180
25x = 180 - 5
25x = 175
x = 175/25
x = 7
So angle BAD = 14x = 14*7 = 98 degrees
angle ABC = 15x = 15*7 = 105 degrees
angle ADC = 10x + 5 = 10*7 + 5 = 75 degrees
Since we know that the sum of all angles of a quadrilateral is 360 degrees. So, the angle BCD = 360 - (98 + 105 + 75) = 82 degrees.
So Blank 1 will be '98 degrees' and Blank 2 will be '82 degrees'.
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a numerical value used as a summary measure for a sample is known as a sample group of answer choices error. parameter. statistic. value.
A numerical value used as a summary measure for a sample is known as a statistic.
A statistic is a quantity that is calculated from a sample of data and is used to estimate an unknown quantity, such as a population parameter. It is important to note that a statistic is only an estimate of the true population parameter and may vary from sample to sample. Examples of statistics include the sample mean, sample standard deviation, and sample proportion.
what is quantity?
quantity refers to an amount or number of something that can be measured or counted. It can be expressed in numerical or non-numerical terms, and can be used to describe the size, volume, length, weight, or other physical attributes of an object or substance. In mathematics, quantity is often used in conjunction with variables and equations to represent mathematical relationships and solve problems.
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from a group of six people, two individuals are to be selected at random. how many selections are possible? group of answer choices 12 36 15 8
There are a total of six people in the group. To select two individuals at random, we can use the formula for combinations, which is nCr = n!/r!(n-r)!, where n is the total number of individuals in the group and r is the number of individuals to be selected. Therefore, the number of selections possible is:
6C2 = 6!/(2!(6-2)!) = 15
The formula for combinations is used to calculate the number of ways we can select r individuals from a total of n individuals. This formula is nCr = n!/r!(n-r)!. In this case, n is 6 (the total number of individuals in the group) and r is 2 (the number of individuals to be selected). Therefore, we substitute n=6 and r=2 into the formula to obtain the number of selections possible.
The number of selections possible from a group of six people, where two individuals are to be selected at random, is 15. This is obtained by using the formula for combinations, which is nCr = n!/r!(n-r)!, where n is the total number of individuals in the group and r is the number of individuals to be selected.
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estimate the proportion of defectives being produced by the machine if the random sample of size 2 yields 2 defects.
we can estimate that the proportion of defectives being produced by the machine is around 0.316.
What is proportion?
A comparison between the size, number, or amount of one thing or group with that of another. In our class, there are three boys for everyone lady.
If the random sample of size 2 yields 2 defects, that means both items in the sample were defective. Let p be the proportion of defectives being produced by the machine.
The probability of selecting a defective item on the first draw is p, and the probability of selecting a defective item on the second draw is also p (assuming sampling without replacement).
Since both items were defective, the probability of this happening is p * p = p².
So,
p² = (number of samples with 2 defects) / (total number of samples)
We don't know the values of these numbers, but we can use them to estimate p. For example, if we had a total of 100 samples and 10 of them had 2 defects, then:
p² = 10/100 = 0.1
p ≈ √(0.1) ≈ 0.316
Hence, we can estimate that the proportion of defectives being produced by the machine is around 0.316.
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PLEASE HELP!!!!
A 7ft. tall basketball player is walking towards a 17ft tall lamppost at a rate of 4 ft/sec. Assume the scenario can he modeled with right triangles. Find the rate the length of the player’s shadow is changing when he is 12 feet from the lamppost.
Answer: In simple terms
Step-by-step explanation:
At 12ft from the lamppost:
Let's call the length of the shadow S.
We can see part of a right triangle formed by the player's height (7ft), the distance to the lamppost (12ft), and the hypotenuse which is the length of the shadow (S ft).
Using the Pythagorean theorem:
72 + 122 = S2
49 + 144 = 193
Therefore, at 12ft from the lamppost:
The length of the shadow (S) = 13ft
To find the rate at the shadow is changing:
As the player walks closer at 4ft/sec, the distance to the lamppost decreases by 4ft each second.
For each 4ft closer, the shadow length changes by:
Shadow length (13ft) x (4ft/12ft distance) = 2ft
So the shadow length changes by 2ft for each 4ft the player walks closer.
Therefore, the rate at the shadow length is changing at 12ft from the lamppost is:
2ft / 4ft walked closer = 0.5 ft/sec
2. Closing costs are calculated based on
Odown payment made
Oselling price of the house
O loan amount minus down payment
Oselling price of the house minus down payment
(1 point)
Closing costs are calculated based on d) selling price of the house minus down payment.
Closing costs are the additional charges that buyers and sellers incur in order to finalize a real estate transaction. Loan origination fees, discount points, appraisal fees, title searches, title insurance, surveys, taxes, deed recording fees, and credit report charges are examples of these expenditures.
Lenders are required by law to give buyers with a closing disclosure three business days before the planned closing date. Closing fees are incurred when the title to the property is transferred from the seller to the buyer.
Closing costs vary depending on location and property value. Closing fees are typically between 3-6% of the purchase price. At settlement, a $300,000 mortgage will cost between $9,000 and $18,000.
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Correct question:
Closing costs are calculated based on
a) down payment made
b) selling price of the house
c) loan amount minus down payment
d) selling price of the house minus down payment
determune the vectors determine which of these 5 vectors are linearly independent find a basis for the space spanned by them
The vectors [tex]v1[/tex], [tex]v2, v3, v4,[/tex] and [tex]v5[/tex] are linearly independent. The basis for the area covered by [tex]v1, v2, v3, v4,[/tex] and [tex]v5[/tex].
We can construct a matrix with the vectors as its columns and rows reduce it using Gaussian elimination to find out which of the five vectors is linearly independent. The vectors are linearly independent if the row-reduced matrix has a pivot in each row. If not, some of the vectors rely linearly.
The five-vectors will be indicated as follows:
[tex]v1 = [1 2 3 4][/tex]
[tex]v2 = [0 1 2 3][/tex]
[tex]v3 = [1 1 1 1][/tex]
[tex]v4 = [1 0 -1 0][/tex]
[tex]v5 = [0 1 0 -1][/tex]
They can be set up as a matrix's columns:
[tex]A = [1 0 1 1 0; 2 1 1 0 1; 3 2 1 -1 0; 4 3 1 0 -1][/tex]
To get this matrix's reduced row echelon form, we can row reduce it as follows:
[tex]R = [1 0 0 -1/2 1/2; 0 1 0 1/2 -1/2; 0 0 1 -1 2; 0 0 0 0 0][/tex]
The centre point in the row-reduced matrix indicates that the vectors [tex]v1[/tex], [tex]v2, v3, v4,[/tex] and [tex]v5[/tex] are linearly independent.
We can utilize the vectors themselves since they constitute a set that is linearly independent to identify a basis for the space that these vectors cover. The basis for the area covered by [tex]v1, v2, v3, v4,[/tex] and [tex]v5[/tex] is therefore only [tex]v1, v2, v3, v4[/tex], and [tex]v5.[/tex]
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How to find the area of a rhombus with one diagonal and perimeter?.
The area of rhombus can be found using the formula A = (d1 x d2)/2, where d1 and d2 are the lengths of the diagonals. Using area formula, we get A = (24 x 18)/2 the area of the rhombus is 24√(119) square meters.
Let's start by finding the other diagonal of the rhombus.
We know that the perimeter of a rhombus is four times the length of one of its sides. So, if the perimeter is 80 m, then each side has a length of 80/4 = 20 m.
We also know that the diagonals of a rhombus are perpendicular bisectors of each other, and they divide the rhombus into four congruent right triangles. Therefore, each leg of one of these right triangles is half of one of the diagonals of the rhombus.
Let's call the other diagonal of the rhombus d. Then, using the Pythagorean theorem in one of the right triangles, we have
(20/2)² + (d/2)² = 24²
100 + d²/4 = 576
d²/4 = 476
d = 2√(119)
Now that we have both diagonals, we can find the area of the rhombus by multiplying them and dividing by 2
Area = (24 * 2√(119))/2
Area = 24√(119)
Therefore, the area of the rhombus is 24√(119) square meters.
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--The given question is incomplete, the complete question is given
" The area of a rhombus whose perimeter is 80 m and one of whose diagonal is 24 m is ..........."--
Solve this question please because I don’t get it at all.
Answer:
20,908
Step-by-step explanation:
We can represent the amount of people after each year as 103% of the amount from the previous year. Using this logic, we can multiply the town's original population (its principal value) by 103% 7 times, because the increase happens every year. We can represent this in the equation:
P = (og. population) × 103%⁷
We can use an exponent of 7 to indicate repeated multiplication, and when plugging a percentage into a calculator, we have to represent it as a decimal (103% => 1.03).
P = 17,000 × 1.03⁷
P ≈ 20,907.86
P ≈ 20,908
Note that we rounded the population to the nearest whole number as instructed instead of performing a more realistic truncation of the partial person.
Morrison Inc. has decided to use an R-Chart to monitor the changes in the variability of their 44.00 pound steel bars. The operations manager randomly samples 7 steel bars and measures the weight of the sample (in pounds) at 18 successive time periods.
Step 1 of 7:
What is the Center Line of the control chart? Round your answer to three decimal places.
Step 2 of 7: What is the Upper Control Limit? Round your answer to three decimal places.
Step 3 of 7: What is the Lower Control Limit? Round your answer to three decimal places.
Step 4 of 7: Use the following sample data, taken from the next time period, to determine if the process is "In Control" Or "Out of Control".
Step 5 of 7:
Use the following sample data, taken from the next time period, to determine if the process is "In Control" Or "Out of Control".
Observations: 44.04,43.96,44.01,44.02,43.95,44,44.0444.04,43.96,44.01,44.02,43.95,44,44.04 Sample Range: 0.090.09
Step 6 of 7:
Use the following sample data, taken from the next time period, to determine if the process is "In Control" Or "Out of Control".
Observations: 43.99,43.98,44.04,44.13,43.96,44.04,43.9843.99,43.98,44.04,44.13,43.96,44.04,43.98 Sample Range: 0.17
Step 7 of 7:
You, acting as the operations manager, have concluded that the process is "Out of Control". What is the probability that the process is really "In Control" and you have made a Type I Error? Round your answer to three decimal places.
Morrison Inc. is using an R-Chart to monitor the variability of their 44.00-pound steel bars. They have taken 18 samples of 7 steel bars each.
Step 1: The Center Line of the control chart is the average of the sample means. Therefore, the Center Line for this R-chart would be the average of the average weights of the 7 steel bars over the 18 successive time periods. The Center Line can be calculated as follows:
Center Line = (44.04 + 43.96 + 44.01 + 44.02 + 43.95 + 44 + 44.04)/7 = 44.00
Step 2: The Upper Control Limit (UCL) can be calculated as follows:
UCL = Center Line + A2*R-bar
Where R-bar is the average range of the 18 samples and A2 is a constant based on the sample size (n = 7) and the desired level of significance (alpha = 0.05). From the table of constants, A2 = 0.482. The average range can be calculated as follows:
R-bar = (0.09 + 0.17)/2 = 0.13
Therefore, the UCL is:
UCL = 44.00 + 0.482*0.13 = 44.06
Step 3: The Lower Control Limit (LCL) can be calculated as follows:
LCL = Center Line - A2*R-bar
Therefore, the LCL is:
LCL = 44.00 - 0.482*0.13 = 43.94
Step 4: Using the sample data of the first time period, we can calculate the sample mean and sample range as follows:
Sample Mean = (44.04 + 43.96 + 44.01 + 44.02 + 43.95 + 44 + 44.04)/7 = 44.00
Sample Range = 44.04 - 43.95 = 0.09
The sample mean is within the control limits, so the process is in control.
Step 5: Using the sample data of the second time period, we can calculate the sample mean and sample range as follows:
Sample Mean = (44.04 + 43.96 + 44.01 + 44.02 + 43.95 + 44 + 44.04)/7 = 44.00
Sample Range = 44.04 - 43.95 = 0.09
The sample mean is within the control limits, so the process is in control.
Step 6: Using the sample data of the third time period, we can calculate the sample mean and sample range as follows:
Sample Mean = (43.99 + 43.98 + 44.04 + 44.13 + 43.96 + 44.04 + 43.98)/7 = 44.00
Sample Range = 44.13 - 43.96 = 0.17
The sample mean is within the control limits, but the sample range is above the UCL. Therefore, the process is out of control.
Step 7: The probability of making a Type I Error is the level of significance (alpha = 0.05) which represents the probability of rejecting the null hypothesis (process is in control) when it is actually true. Therefore, the probability of making a Type I Error is 0.05 or 5%. The probability that the process is really in control can be calculated using the concept of process capability indices, but it cannot be determined from the information given in this question.
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Determine the total time spent outside by all the children
The total time spent outside by all the children is 5 hours.
Assuming that the school boy's schedule is representative of the average student's schedule, we can use the proportion of time spent on each activity to estimate the average amount of time spent on each activity by all the children.
7 hours on school
4 hours on homework
2 hours on play
8 hours on sleep
3 hours on other activities
Adding these up, we get a total of 24 hours, which is the same as the total number of hours in a day.
Therefore, we can estimate that the average student does spend any time outside, since all 24 hours of the day are accounted for by these activities is
=> Play + others
=> 2 + 3 = 5
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Complete Question:
The data given below shows number of hours spent by a school boy on different activities on a working day.
Activity School Homework Play Sleep Other Total
Number of hours 7 4 2 8 3 24
Determine the total time spent outside by all the children
compare pre (proportional reduction in error) for the two models (the two-group model vs. the regression model). which model has a higher pre?
The model with the higher PRE value is the one that has a greater proportional reduction in error, indicating that it explains more of the variance in the dependent variable and is therefore a better fit for the data.
To compare the pre (proportional reduction in error) for the two models, we need to calculate the pre value for each model and then compare them. The pre value measures the reduction in error achieved by using a model compared to using no model.
In the two-group model, pre can be calculated as the difference between the error rate of using no model and the error rate of using the two-group model, divided by the error rate of using no model. In the regression model, pre can be calculated as the difference between the error rate of using no model and the error rate of using the regression model, divided by the error rate of using no model.
Assuming that the two models are equally well-fitted to the data, the model with the higher pre value is the one that achieves a greater reduction in error. So, we need to compare the pre values for the two models.
If the two-group model achieves a higher pre value than the regression model, then it has a higher pre. Conversely, if the regression model achieves a higher pre value than the two-group model, then it has a higher pre. Without further information or analysis, it is not possible to say which model has a higher pre.
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what is the value of x so that line I is parallel to line m
Answer:
Parallel lines which are intersected by a transversal form congruent corresponding angles.
9x - 14 = 6x + 22
3x = 36, so x = 12
write VII (line over top) CCLIV as a Hindu-Arabic numeral
VII (line over top) CCLIV is equivalent to the Hindu-Arabic numeral 7,254.
The Roman numeral VII (line over top) CCLIV can be rewritten as follows:
VII (line over top) CCLIV = 7,254
The line over the Roman numeral VII signifies that its value should be multiplied by 1,000. Therefore, VII (line over top) represents 7,000. The Roman numerals CCLIV represent 254 in base 10.
Putting these values together, we get:
VII (line over top) CCLIV = 7,000 + 254 = 7,254
Therefore, VII (line over top) CCLIV is equivalent to the Hindu-Arabic numeral 7,254.
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consider the relation r on z given by arb iff a2 = b2. prove that the relation r on z is an equivalence relation.
Since r satisfies all three properties of an equivalence relation (reflexivity, symmetry, and transitivity), we can conclude that r is an equivalence relation on Z.
What is equivalence relation?If and only if a relation R on a set A is reflexive, symmetric, and transitive, then it qualifies as an equivalence relation. On the set, the equivalence relation is a relationship that is typically denoted by the symbol " ∼".
To prove that the relation r on Z is an equivalence relation, we need to show that it satisfies the three properties of an equivalence relation:
1. Reflexivity: For any integer a, we have a² = a², so a is related to itself under r. Therefore, r is reflexive.
2. Symmetry: For any integers a and b, if a is related to b under r, then a² = b². By taking the square root of both sides, we get |a| = |b|. Therefore, b is also related to a under r. Hence, r is symmetric.
3. Transitivity: For any integers a, b, and c, if a is related to b under r and b is related to c under r, then a² = b² and b² = c². By transitivity of equality, we have a² = c². Therefore, a is related to c under r. Hence, r is transitive.
Since r satisfies all three properties of an equivalence relation (reflexivity, symmetry, and transitivity), we can conclude that r is an equivalence relation on Z.
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considerthedata(wines2012)datatable.thesedataareexpertratingsof20differentfrench and american wines by 9 different french and american judges. your goal is to model score, the subjective rating assigned by each judge to each wine. i recommend standardizing it. in this problem, consider only variation among judges and wines. construct index variables of judge and wine and then use these index variables to construct a linear regression model. justify your priors. you should end up with 9 judge parameters and 20 wine parameters. how do you interpret the variation among individual judges and individual wines? do you notice any patterns, just by plotting the differences? which judges gave the highest/lowest ratings? which wines were rated worst/best on average?
The goal of this problem is to create a model for the subjective ratings assigned to 20 different French and American wines by 9 different judges. To start, it is recommended to standardize the scores. For this problem, we only consider the variation among judges and wines. To construct the index variables of judge and wine, we can assign a number to each judge and each wine. Using these index variables, we can construct a linear regression model.
The priors for this problem should be that each judge and wine has a unique effect on the subjective rating. This means that we expect each judge to rate the wines differently and each wine to have its own unique characteristics that affect the rating.
By plotting the differences, we may notice patterns in the data. For example, some judges may consistently give higher or lower ratings compared to the other judges. Some wines may consistently receive higher or lower ratings compared to the other wines.
Based on the model, we can interpret the variation among individual judges and individual wines as the unique effect that each judge and wine has on the subjective rating. This means that the rating assigned by a particular judge may be influenced by their personal preferences and biases, and the rating assigned to a particular wine may be influenced by its unique characteristics.
By analyzing the model, we can identify which judges gave the highest and lowest ratings, and which wines were rated the worst and best on average. This information can be useful for understanding the preferences of the judges and the characteristics of the wines.
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Sara is studying how quickly adults tire after eating turkey. She splits a group of 20 adults into 2 groups. One group is given turkey to eat and the other group is not given anything to eat. Sara asks the adults to start exercising at the same, and to stop when they tire, measuring the time each adult stops exercising. She finds that the adults who did not eat turkey exercised 2 minutes longer than those who did eat turkey. Sara rerandomizes the data, calculates the difference between the means, and creates the dot plot shown below. Based on the data, can sara conclude the difference is significant?.
Yes, Sara can conclude the difference is significant because a 2-minute difference is not likely to happen by chance.
Given, that Sara is studying how quickly adults tire after eating turkey. She splits a group of 20 adults into 2 groups.
One group is given a turkey to eat and the other group is not given anything to eat.
Sara asks the adults to start exercising at the same and to stop when they tire, measuring the time each adult stops exercising.
She finds that the adults who did not eat turkey exercised 2 minutes longer than those who did eat turkey.
We have to determine Sara rerandomizes the data, calculates the difference between the means, and creates the dot plot shown below.
Level of significance measures the unlikeliness of a hypothesis's against the measured reading.
0.05 is a common level of significance which depicts that there are 5% chances of a type I error thereby rejecting a true null hypothesis in a one-way test.
In two way test, it depicts that there are 2.5% chances of a type I error thereby rejecting a true null hypothesis.
It is the probability of rejecting a null hypothesis with a probability of test suffering an error of type based on the data, Sara can conclude that the difference is significant because when we are analyzing data and reach a statistically significant result then nothing or no event happens by chance.
Sara can conclude that the difference is significant because a two minutes difference is not likely to happen by chance.
In analyzing data, a statistically significant result is one that is not attributed to chance, that is, there is no way the event could have occurred by chance.
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Dana buys a plant that is 4 inches tall. After one week the plant is 7 inches tall. After a second week the plant is 10 inches tall. At this rate, how tall will the plant be after the fifth week?
a
22 inches tall
b
3 inches tall
c
14 inches tall
d
19 inches tall
Answer:
We know that the plant grows by 3 inches each week (7 inches - 4 inches = 3 inches, and 10 inches - 7 inches = 3 inches). Therefore, after 5 weeks, the plant will be 4 inches + (3 inches × 5) = 19 inches tall.
Step-by-step explanation:
- The plant is 4 inches tall when Dana buys it.
- After one week, the plant grows by 3 inches to reach a height of 7 inches.
- After a second week, the plant grows by another 3 inches to reach a height of 10 inches.
- So, the plant grows by 3 inches each week.
- After 3 weeks, the plant will be 10 inches + 3 inches = 13 inches tall.
- After 4 weeks, the plant will be 13 inches + 3 inches = 16 inches tall.
- After 5 weeks, the plant will be 16 inches + 3 inches = 19 inches tall.
Therefore, the correct answer is d) 19 inches tall.
Beth has $13.50 and earns $8 per hour. What is Beth’s initial value?
$13.50 - $8 =
$5.50
...............
Please help me on this.
Answer: (1,1)
Step-by-step explanation:
Harley-davidson motorcycles reportedly make up 32% of all motorcycles registered in the united states. you think that is an understatement. you interview a random sample of 600 motorcycle owners and find that 33.8% of them own harleys.the hypotheses are: a. h0: p less or equal than 0.338 h1: p greater than 0.338 b. h0: p with hat on top less or equal than 0.32 h1: p with hat on top greater than 0.32 c. h0: p equals 0.32 h1: p not equal to 0.32 d. h0: p less or equal than 0.32 h1: p greater than 0.32
The correct option is option d). The hypothesis that fits the scenario is option d).
The null hypothesis (H0) is that the proportion of Harley-Davidson motorcycle owners is less than or equal to 0.32, while the alternative hypothesis (H1) is that the proportion is greater than 0.32.
This is because the initial claim is that Harley-Davidson motorcycles make up 32% of all motorcycles registered in the United States, but the researcher believes that this is an understatement. When conducting a random sample of 600 motorcycle owners, 33.8% of them owned Harley-Davidson motorcycles, which supports the alternative hypothesis that the proportion is greater than 0.32.
Therefore, the hypothesis testing is focused on rejecting the null hypothesis in favor of the alternative hypothesis, which is d. H0: p ≤ 0.32 and H1: p > 0.32.
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Justin and Daniel work at a dry cleaners ironing shirts. Justin can iron 40 shirts per hour, and Daniel can iron 20 shirts per hour. Daniel worked 6 more hours than Justin and they ironed 360 shirts between them. Graphically solve a system of equations in order to determine the number of hours Justin worked, x, and the number hours Daniel worked, y.
The number of hours worked by each person is given as follows:
Justin: 4 hours.Daniel: 10 hours.How to obtain the number of hours worked by each person?The variables for the system of equations are given as follows:
x: number of hours worked by Justin.y: number of hours worked by Daniel.Daniel worked 6 more hours than Justin, hence:
y = x + 6.
They ironed 360 shirts between them, hence, considering the rates, we have that:
40x + 20y = 360.
From the graph given at the end of the answer, the intersection point of the two equations is given as follows:
(4, 10).
Hence the number of hours worked by each person is given as follows:
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a tank contains 90 liters of fluid in which 50 grams of salt is dissolved. brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 3 l/min; the well-mixed solution is pumped out at the same rate. find the number a(t) of grams of salt in the tank at time t.
The answer is 50 grams of salt in the tank at all times.
To find the number of grams of salt in the tank at time t, we need to use the formula:
a(t) = a(0) + (r - p) * t
where a(0) is the initial amount of salt in the tank, r is the rate at which brine is being pumped into the tank, p is the rate at which the solution is being pumped out of the tank, and t is the time elapsed.
In this case, a(0) = 50 grams, r = 3 grams per minute (since the brine contains 1 gram of salt per liter and 3 liters are being pumped in per minute, so 3 grams of salt are being added per minute), and p = 3 grams per minute (since the solution is being pumped out at the same rate as it is being pumped in). Therefore, we can simplify the formula to:
a(t) = 50 + 0 * t
a(t) = 50 grams
This means that the amount of salt in the tank remains constant over time, since the rate at which it is being pumped in and out is equal. Therefore, the answer is 50 grams of salt in the tank at all times.
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do pregnant women give birth the week of their due date? a study claims that of the population of all pregnant women actually gave birth the week of their due date. you are a researcher who wants to test this claim, so you will select a random sample of women who have recently given birth. follow the steps below to construct a confidence interval for the population proportion of all pregnant women who gave birth the week of their due date. then state whether the confidence interval you construct contradicts the study's claim.
Our confidence interval is only representative of the sample that we selected, and there could be variation in the true population proportion.
To construct a confidence interval for the population proportion of all pregnant women who gave birth the week of their due date
the following steps can be taken:
1. Determine the sample size: The sample size can be determined based on the desired level of confidence and margin of error. Let's say we want a 95% confidence level and a margin of error of 5%, which means we want to be 95% confident that the true proportion falls within 5% of the sample proportion. Using a confidence interval calculator, the required sample size would be 385.
2. Select a random sample of women who have recently given birth: The sample should be selected randomly to ensure that it is representative of the population of all pregnant women.
3. Calculate the sample proportion: Determine the proportion of women in the sample who gave birth the week of their due date.
4. Calculate the standard error: The standard error can be calculated using the formula SE = √((p*(1-p))/n), where p is the sample proportion and n is the sample size.
5. Calculate the confidence interval: Using a confidence interval calculator, the confidence interval for the population proportion can be calculated. For our example, the confidence interval would be 0.404 to 0.556.
The confidence interval we constructed (0.404 to 0.556) does not contradict the study's claim that a certain proportion of pregnant women give birth the week of their due date, as the interval includes the possibility of this proportion being within the range of 0.40 to 0.56.
Our confidence interval is only representative of the sample that we selected, and there could be variation in the true population proportion.
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