Answer:
p = 6x
Step-by-step explanation:
Perimeter is the distance around a figure.
p = 2x + 1/2x +1/2x + 2x + x if we combine all of the x's we get
p = 6x
find the measures of the labeled angles :)
3x =
second answer =
simplified =
please help im struggling !! this is my last question :) ill mark brainliest
Answer: 54
Step-by-step explanation:
3x=72-x ==> 3x and 72-x are both congruent angles, so they're equal
3x+x=72-x+x
4x=72
x=18
3x=
3(18)=54 degrees
In ΔXYZ, ∠Y=90° and ∠X=60°. ∠ZWY=83° and XW=1.5. Find the length of ZY to the nearest 100th.
Applying the law of sines, the length of ZY to the nearest hundredth is: 3.30 units.
How to Apply the Law of Sines?sin X/x = sin W/w = sin Z/z [according to the law of sines].
Given:
Measure of angle X = 60°
Measure of angle Z (∠XZW) = 180 - 60 - (180 - 83) = 23°
x = WZ = ?
z = XW = 1.5
Plug in the values into sin X/x = sin Z/z
sin 60/WZ = sin 23/1.5
WZ = (sin 60 × 1.5)/sin 23
WZ = 3.32
Find ZY using the sine ratio;
sin ∅ = opp/hyp = ZY/WZ
sin 83 = ZY/3.32
ZY = (sin 83)(3.32)
ZY = 3.30
Therefore, applying the law of sines, the length of ZY to the nearest hundredth is: 3.30 units.
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Monique has $48, then the following events happen, in order: • She earns $20 babysitting. • She spends $32. • She doubles her money doing chores.
Answer:
72
Step-by-step explanation:
$48 + $20 = $68
$68 - $32 = $36
$36 × 2 = $72
For the season, a basketball player made 279 free throws out of 313 attempts. What percent is this?
Answer:
89.14%
Step-by-step explanation:
279 Out of 313 is 89.14%. Follow the below steps to calculate what percent is 279 out of 313 or how to write 279/313 as a percentage.
Step 1: Percentage Formula = Number 1/Number 2 x 100
Step 2: plugin the 279 and 313 to the percentage formula and we get 279/313 x 100 = 89.14%
Please help! Brainliest to whoever correct first!!! THANK YOU!
An equivalent expression for 4d⁻³/22d⁹ is: B. 2d⁻³/11d⁻⁹
What is an expression?An expression can be defined as a mathematical equation which is used to show the relationship existing between two or more variables and numerical quantities.
What is an exponent?An exponent can be defined as a mathematical operation that is used to raise a quantity to the power of another and it is generally written as bⁿ.
Next, we would write the equation as a quotient:
Expression = 4d⁻³/22d⁹
Expression = 2d⁻³/11d⁹
By applying the law of indices, we have:
Expression = 2 × 1/11d(⁹ ⁻ ⁽⁻³⁾)
Expression = 2/11d¹²
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Enter an inequality that represents the graph in the box.
Graph of a linear inequality on a coordinate plane. The horizontal x-axis ranges from negative 8 to 8 in increments of 2. The vertical y-axis ranges from negative 8 to 8 in increments of 2. A solid line passes through begin ordered pair 0 comma negative 6 end ordered pair and begin ordered pair 2 comma 2 end ordered pair. The region above the solid line is shaded.
The linear inequality represented by the given graph in the attached image is y > -3x + 6.
What is inequality?Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.
The graph of the linear inequality. Let's pick two points from the graph to frame the linear equation
The slope-intercept form of the equation is Where m is the slope and b is the y-intercept is (0,6) from the graph so b=6.
Find out slope m by using the general formula. Pick two points (0,6) and (2,0).
Slope = ( y₂ - y₁) / ( x₂ - x₁ )
Slope = ( 0 - 6 ) / ( 2 - 6 )
Slope = -3
m = -3
So the equation is y = -3x + 6
Now we check the inequality sign by testing any point on the shaded area let's pick (4,0). let's plug in 4 for x and 0 for y
y= -3x + 6
0 = -3(4) + 6
0 > -6
Inequality: y > -3x + 6.
Therefore, the inequality represented by the given graph is y > -3x + 6.
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Answer: y≥4x−6
Step-by-step explanation: I took the test and this was the right answer for me.
Please help ASAP! Help greatly appreciated with step by step solutions
The nth terms of the arithmetic sequences;
I. Tn = 3 + √2 + ( n - 1) √2
ii. Tn = 2/ √3 + ( n - 1) 1/ √3
How to determine the nth termThe formula for the nth term of an arithmetic sequence is expressed as;
Tn = a + ( n - 1)d
Where;
Tn is the nth terma is the first term n is the number of termsd is the common differencei. a = 3 + √2
d = √2
Substitute the values, we have;
Tn = 3 + √2 + ( n - 1) √2
ii. a = 2/ √3
d = 1/ √3
Substitute the value, we have;
Tn = 2/ √3 + ( n - 1) 1/ √3
Thus, the nth terms of the arithmetic sequences are Tn = 3 + √2 + ( n - 1) √2 and Tn = 2/ √3 + ( n - 1) 1/ √3 respectively
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Part C
Which investment would you choose if you were Sam or Julia?
In two to three sentences, state your choice of investment and the reasoning for your decision using concepts you've
learned in this lesson.
Answer:
i would choose investment A
Step-by-step explanation:
A is simply the best anwser choice
Answer:
If I were Sam, I would buy the bond with a 3% interest rate since selling at any time is not a priority. The bond would provide a steady income from the investment, which is what he his needing.If I were Julia, I would invest in the stock, which has long-term growth potential. This would allow her to sell the investment at any time in the future.
Step-by-step explanation:
SAMPLE ANSWER!!!
(3x^-4)6/9x^-12 can you please solve? I’ll give brainly
The answer to this given simplification (3x^-4)6/9x^-12 is 2 x^8.
What are exponents?
The exponent of a number indicates how many times a number has been multiplied by itself. For instance, 34 indicates that we have multiplied 3 four times. Its full form is 3 3 3 3. Exponent is another name for a number's power. It could be an integer, a fraction, a negative integer, or a decimal. In this essay, let's study more about exponents.
given:
(3x^-4)6/9x^-12
=x^-4 . 3 . 6 / 9 . x^-12
= 2. x^-4 / x^-12
=2 x^8
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13 square kilometers to square mile? Round to nearest tenth as needed
Answer:
5 square mile
Step-by-step explanation:
1 square km = 0.3 square mile
13 square km = 5.01 square mile
5.01 rounded equals 5
hope that helps <3
Use the graph below to answer. Find f(1)
Answer:
f(1) = 9
Step-by-step explanation:
where x is 1, y is 9
A piece of wood was 12 feet long. Kendra cut the wood into pieces __
2
3 foot
long. How many pieces did Kendra make? State what strategy you will use
to answer the question, explain your choice, and then find the answer.
The number of pieces are 18 if the piece of wood was 12 feet long. Kendra cut the wood into pieces 2/3 foot.
What is a fraction?Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
It is given that:
A piece of wood was 12 feet long. Kendra cut the wood into pieces __
2/3 foot.
Let x be the number of pieces:
12/x = 2/3
x = 36/2
x = 18
Thus, the number of pieces are 18 if the piece of wood was 12 feet long. Kendra cut the wood into pieces 2/3 foot.
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Each marble bag sold by bill marble company contains 8 purple marbles for every 5 yellow marbles. If a bag has 64 purple marbles how many yellow marbles does it contain
Answer:
40 yellow marbles
Step-by-step explanation:
1. Divide 64 by 8 (Determine how many sets there are)
64/8 = 8
2. Multiply 8 by 5 (Because for every 8 purple marbles there are 5 yellow ones)
8*5 = 40
Solve for [x]. Each figure is a trapezoid.
*
Question 1
Opposite sides of a trapezoid are parallel. So, by the same-side interior angles theorem,
[tex]-16x+10x+86=180 \\ \\ 10x+70=180 \\ \\ 10x=110 \\ \\ x=11[/tex]
Question 2
Opposite sides of a trapezoid are parallel. So, by the same-side interior angles theorem,
[tex]9x+30+7x-10=180 \\ \\ 16x+20=180 \\ \\ 16x=160 \\ \\ x=10[/tex]
the spread of data set X is greater than the spread of data set Y, and the data sets are normally distributed. Which statement is true? A. The mean of data set X is greater than the mean of data set Y. B. The median of data set X is less than the median of data set Y. C. The standard deviation of data set X is greater than the standard deviation of data set Y. D. The range of data set X is less than the range of data set Y. E. The mode of data set X is greater than the mode of data set Y.
here u go I hope this is the answer ur looking for!
A used car dealership reduced the price of a used compact car by 10%. If the price of the car before
discount was $18,500, find the discount and the new price.
The discount in price is $
Hint: Discount = Original Price x Percentage
Answer:1/1850
Step-by-step explanation: Davide 10% from 18500
Y= |x-1|-5 find points and graph
Step-by-step explanation:
(-4,0)
(0, -4)
(1, -5)
(6, 0)
Triangle PQR has vertices P (3,8), Q (-5, 7), and R (0, 2). What are the coordinates of the vertices of the image after a reflection in the y-axis?
A) P' (3,-8)
B) P (-3,8)
□C) Q' (5,7)
□D) Q' (5-7)
□E) R¹ (-2,0)
OF) R¹ (0,2)
After the picture is reflected along the y-axis, its vertices will have the coordinates P'Q'R.:
[tex]P' = (-3,8)\\Q' = (5,7)\\R'=(0,2)[/tex]
What is coordinates of the vertices?
The triangle's vertices' coordinates are [tex](x_{1} ,y_{1} )[/tex], [tex](x_{2},y_{2})[/tex], and [tex](x_{3},y_{3} )[/tex]. The line that connects the first two is split in the ratio l:k, and the line that runs from the division point to the opposing angular point is divided in the ratio m:k+l.
Given:
Triangle PQR and vertices of triangle are
[tex]P=(3,8)\\Q=(-5,7)\\R=(0,2)[/tex]
The following rule results in a reflection about the y-axis:
[tex](x, y) ---- > (-x, y)[/tex]
Using the rule on each of our vertices, we have:
[tex](3, 8) ---- > (-3, 8)\\(-5, 7) ---- > (5, 7)\\(0, 2) ---- > (0, 2)[/tex]
Therefore,
After the picture is reflected along the y-axis, its vertices will have the coordinates P'Q'R.
[tex]P' = (-3,8)\\Q' = (5,7)\\R'=(0,2)[/tex]
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Gruman Company purchased a machine for $198,000 on January 2, 2017. It made the following estimates:
Service life 5 years or 10,000 hours
Production 180,000 units
Residual value $18,000
In 2016, Gruman uses the machine for 1,700 hours and produces 40,000 units. In 2017, Gruman uses the machine for 1,200 hours and produces 34,000 units. If required, round your final answers to the nearest dollar.
Required:
Compute the depreciation for 2016 and 2017 under each of the following methods:
a. Straight-line method
b. Sum-of-the-years'-digits method
c. Double-declining-balance method
d. Activity method based on hours worked
e. Activity method based on units of output
a. Straight-line method: $36,000 $36,000
b. Sum-of-the-years'-digits method: $60,000 $48,000
c. Double-declining-balance method: $79,200, $47,520
d. Activity method based on hours worked: $30,600, $21,600
e. Activity method based on units of output $40,000 $34,000
Straight-line methodb. Straight line method
Depreciation expense = (Cost of asset - Salvage value) / Useful life
Depreciation expense=( $198,000 - $18,000 ) / 5
Depreciation expense = $36,000
b. Sum-of-the-years'-digits method
Sum-of-the-year digits = (Remaining useful life / Sum of the years ) x (Cost of asset - Salvage value)
Sum of the years = (1 +2 +3 +4 + 5 )
Sum of the years = 15
Year 1 Depreciation expense = (5/15) × ( $198,000 - $18,000 )
Year 1 Depreciation expense = $60,000
Year 2 Depreciation expense = (4/15) x ( $198,000 - $18,000 )
Year 2 Depreciation expense = $48,000
c. Double-declining-balance method
Depreciation factor = 2 x (1/Useful life)
Depreciation factor =2 x(1/5)
Depreciation factor = 0.4
Year 1 Depreciation expense = 0.4 x $198,000
Year 1 Depreciation expense= $79,200
Year 1 Book value = $198,000 - $79,200
Year 1 Book value= $118,800
Year 2 Depreciation expense= 0.4 x $118,800
Year 2 Depreciation expense= $47,520
d. Activity method based on hours worked
Activity method = (Hours worked / Total machine hours) x (Cost of asset - Salvage value)
Year 1 Depreciation expense = (1,700 / 10,000) x ( $198,000 - $18,000 )
Year 1 Depreciation expense = $30,600
Year 2 Depreciation expense = (1,200 / 10,000) x ( $198,000 - $18,000 )
Year 2 Depreciation expense = $21,600
e. Activity method based on units of output
Activity method = (Output produced / Total machine output capacity) x (Cost of asset - Salvage value)
Year 1 Depreciation expense = ( 40,000 / 180,000) x ( $198,000 - $18,000 )
Year 1 Depreciation expense = $40,000
Year 2 Depreciation expense= ( 34,000 / 180,000) x ( $198,000 - $18,000 )
Year 2 Depreciation expense = $34,000
Therefore the Straight-line method is $36,000 $36,000.
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Pleaseeee
help me solve this
Answer:
x = 155°
Step-by-step explanation:
Given hexagon ABCDEF, you want to find the measure of interior angle E. Angles at vertices A, B, C, D, and F are specified.
Angle sumThe sum of the interior angles of an n-sided polygon is ...
angle sum = (n -2)180°
For the 6-sided polygon given, the sum of interior angles is ...
(6-2)180° = 720°
ApplicationThe interior angle at vertex B is 360° -80° = 280°.
The interior angle at vertex D is 180° -115° = 65°.
Then the sum of interior angles is ...
A +B +C +D +E +F = 720°
85° +280° +30° +65° +x +105° = 720° . . . . . substitute known values
565° +x = 720° . . . . . . . collect terms
x = 155° . . . . . . . . . . subtract 565°
__
Additional comment
The angles in the attached figure are drawn to scale.
An alternate solution might draw segment CX through vertex B so that the figure containing angle x has no reflex interior angles. Then the interior angles of pentagon ABXEF will total 540°. Known angles in that figure are A=85°, B=100°, X=95°, F=105°. Then E=x=540° -385° = 155°.
We took this approach initially, to verify that the angle sum of the given hexagon remained 720° even with the reflex interior angle at B.
Louisa made a purchase at her local convenience store for $6.65. She wanted to use up her change so she used
quarters and dimes to pay the clerk. If she used a total of 29 coins, how many fewer dimes than quarters did she
use?
Louisa used Number
fewer dimes.
Answer:
25 quarters and 4 dimes. Louisa used 21 more quarters than she did dimes.
Step-by-step explanation:
q=number of quarters
d=number of dimes
6.65=.25q+.10d 6.65 (the total) is equivalent to the amount of quarters times .25 (the value of a quarter) plus the amount of dimes times .10 (the value of a dime)
Now divide 6.65 by .25.
26 quarters can be used.
26 times .25 = 6.50
26 quarters is $6.50
29-26=3
3 times .10 = .30
.30+6.50=6.80
This is too much. Let's try taking off one quarter.
Now we have 25 quarters. .25 times 25 = 6.25
29-25=4 (This means there will be 4 dimes if she used 25 quarters, but let's see)
4 times .10 = .40
.40 + 6.25=6.65
6.65 is the total amount she had to pay, so we did it. Solving this showed us that she used 25 quarters and 4 dimes. This equals $6.65, the amount she paid, uses only quarters and dimes, and uses a total of 29 coins.
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how many terms are in the sequence given of the following d=5,a1=-9 and an=141
The number of terms in the sequence with d=5 , a₁ = -9 and aₙ=141 is 31 terms.
Arithmetic Sequence
The nth term of the sequence { a , a+d , a+2d , ... , a+(n-1)d } is given by
aₙ=a+(n-1)d ...(i)
where , a = first term ,
d = common difference ,
n = number of terms ,
aₙ = nth term of the sequence .
It is given in the question that
first term (a) = -9
common difference (d) = 5
and nth term (aₙ) = 141
Substituting the values in equation (i) we get ,
141 = -9 + (n-1)5
simplifying further we get
141+9=(n-1)5
150 = 5n - 5
150+5 = 5n
155 = 5n
n=155/5
n=31.
Therefore , There are 31 terms in the sequence with d=5 , a1 = -9 and aₙ=141 .
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18 acres of land is for sale at $11001.
What is the cost per acre?
Answer in units of dollars/acre.
Answer:
$611.17 per acre
Step-by-step explanation:
11001 ÷ 18 = 611.16666...
So, the answer is an infinite decimal, so we round it to the nearest hundredth.
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The admission fee at an amusement park is $ 3.00 for children and $ 7.00 for adults. On a certain day, 297 people entered the park, and the admission fees collected totaled $ 1551 . How many children and how many adults were admitted?
There were _________________ children admitted.
There were _________________ adults admitted
Answer:
There were 132 children admitted.
There were 165 adults admitted.
Step-by-step explanation:
Given information:
Child admission fee = $3.00Adult admission fee = $7.00Total admissions = 297 peopleTotal admission fees collected = $1,551Define the variables:
Let x = number of children admitted to the park.Let y = number of adults admitted to the park.Create two equations from the given information and defined variables:
[tex]\textsf{Equation 1}: \quad x+y=297[/tex]
[tex]\textsf{Equation 2}: \quad 3x+7y=1551[/tex]
Solve the first equation for y:
[tex]\implies x+y=297[/tex]
[tex]\implies x+y-x=297-x[/tex]
[tex]\implies y=297-x[/tex]
Substitute the found expression for x into the second equation and solve for y:
[tex]\implies 3x+7y=1551[/tex]
[tex]\implies 3x+7(297-x)=1551[/tex]
[tex]\implies 3x+2079-7x=1551[/tex]
[tex]\implies 2079-4x=1551[/tex]
[tex]\implies 2079-1551-4x=1551-1551[/tex]
[tex]\implies 528-4x=0[/tex]
[tex]\implies 528-4x+4x=0 + 4x[/tex]
[tex]\implies 528= 4x[/tex]
[tex]\implies \dfrac{528}{4}= \dfrac{4x}{4}[/tex]
[tex]\implies x=132[/tex]
Substitute the found value of x into the expression for y and solve for y:
[tex]\implies y=297-x[/tex]
[tex]\implies y=297-132[/tex]
[tex]\implies y=165[/tex]
Therefore:
There were 132 children admitted.There were 165 adults admitted.Macy jogs 27 miles a month.
Part A
Explain how to use compensation to find how many miles Macy jogs in 6 months.
BD bisects AC at point E. if AE is 2x²- 8 and AC is 5x^2-25
find the length of EC
The length of EC will be 154 units.
We have the data that:
BD is the bisector of AC at point E.
This means that AE = EC
Also, AE + EC = AC
AE + AE = AC
2 AE = AC
Now,
AE = 2x² - 8 and AC is 5x² - 25
Substituting the values, we get that:
2 (2x² - 8) = 5x² - 25
4x² - 16 = 5x² - 25
5 x² - 4 x² = 25 - 16
x² = 9
x = 3 ( as length cannot be negative)
AE = EC = 2x² - 8
EC = 2 (9)² - 8
EC = 162 - 8
EC = 154 units.
Therefore, we get that, the length of EC will be 154 units.
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The following trial balance of Reese Corp. at December 31, 2014 has been properly adjusted except for the income tax expense adjustment. Reese Corp. Trial Balance December 31, 2014 Dr. Cr. Cash $ 775,000 Accounts receivable (net) 2,695,000 Inventory 2,085,000 Property, plant, and equipment (net) 7,566,000 Accounts payable and accrued liabilities $ 1,701,000 Income taxes payable 654,000 Deferred income tax liability 85,000 Common stock 2,350,000 Additional paid-in capital 3,680,000 Retained earnings, 1/1/14 3,450,000 Net sales and other revenues 13,560,000 Costs and expenses 11,180,000 Income tax expenses 1,179,000 $25,480,000 $25,480,000 07. The current assets total is: A. $6,080,000 C. $5,405,000 B. $5,555,000 D. $4,955,000
Based on the balances in Reese Corp's trial balance, the current assets total can be found to be B. $5,555,000
What is the total current assets?The total of the current assets can be found by the formula:
= Inventory + Accounts Receivable + Cash
Solving then gives:
= 775,000 + 2,695,000 + 2,085,000
= $5,555,000
In conclusion, the current assets for Reese Corp is $5,555,000 .
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Solve the following system of equations using either Gaussian elimination or a matrix. Write your answer as a point and explain how you would check your work:
By using Matrix method it denotes that the equations are consistent and have a single solution.
Matrix method, we will use the formula, [tex]X=A^{-1} B[/tex] where,
[tex]\[{\rm{X}} = \left[ {\begin{array}{*{20}{l}}x\\y\\z\end{array}} \right]\][/tex]
[tex]\[{A^{ - 1}} = \frac{{adjA}}{{|A|}}\][/tex]
[tex]\[{\rm{B}} = \left[ {\begin{array}{*{20}{c}}{33}\\{ - 26}\\{23}\end{array}} \right]\][/tex]
So, we will have to find [tex]A^{-1}[/tex], for that, we will first find the determinant of matrix A, that is |A|, then we will find the cofactors of matrix A, take its transpose, and that will be Adj A.
Therefore, we will be able to get the inverse of matrix A using
[tex]A^{-1}[/tex] =Adj A|A|
and hence We then substitute all the obtained values of [tex]A^{-1}[/tex] and B in the main formula and do necessary calculations to get the value of x, y and z accordingly.
Complete step-by-step answer:
It is given in the question that, we have to solve the system of equations,
2x-y+4z=33
X+2y-3z=−26
-5x−3y+5z=23
Applying the matrix approach.
Therefore, the first step is to convert the supplied equations into matrix form. Thus, it can be expressed as follows.
[tex]\[\left[ {\begin{array}{*{20}{c}}2&{ - 1}&4\\1&2&{ - 3}\\{ - 5}&{ - 3}&5\end{array}} \right]\left[ {\begin{array}{*{20}{l}}x\\y\\z\end{array}} \right]\]\[[/tex][tex]= \left[ {\begin{array}{*{20}{c}}{33}\\{ - 26}\\{23}\end{array}} \right][/tex]
[tex]\[|{\rm{A}}| = \left[ {\begin{array}{*{20}{c}}2&{ - 1}&4\\1&2&{ - 3}\\{ - 5}&{ - 3}&5\end{array}} \right]\][/tex]
= 2(10+9) + 1(5-15) + 4(-3+10)
= 38-10+28
=56
Since we have |A|≠0.
Hence, it denotes that the equations are consistent and have a single solution.
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100000000000000000000000000000000000000000000 x 22222222222222 =
Scientific e Notation: 2.2222222e+57
Scientific Notation: 2.2222222 x 10^57
Answer:
I am pretty sure the answer is 2.2222222e+57.
3x^2+7-6+1+3+7 add , sub, mult, what is the answer
Answer:
If just combining like terms: 3x^2 + 12
If solving for x: 2i, -2i
Step-by-step explanation: Combine like terms, so 3x^2 + 12 = 0; move the 12 to the other side by subtracting (3x^2 = -12), then divide both sides by 3, which gives x^2 = -4. Then get the square root of both sides to cancel out the power on the x. Since -4 is negative, use imaginary numbers, which makes x = 2i and x = -2i