using distance formula i tried this one for myself and just couldn't get it

Answer:

P(C/R) = 0.4298

Step-by-step explanation:

Missing word "arble, what is the chance it came from box Type C? (Give the decimal answer rounded to at least four places )"

Solution:

Given that P(A) = 75% = 0.75

P(B) = 20% = 0.20

P(C) = 0.05

The chance of drawing a Red marble fro,

P(R/A) = 2% = 0.02

P(R/B) = 25% = 0.25

P(R/C) = 98% = 0.98

If he select Box A than the probability of Red marble drawing

= P(A) * P(R/A)

= 0.75 * 0.02

= 0.015

If he select Box  B than the probability of Red marble drawing

= P(B) * P(R/B)

= 0.20 * 0.25

= 0.5

If he select Box C than the probability of Red marble drawing

= P(C) * P(R/C)

= 0.98 * 0.05

= 0.049

So total probability of drawing Red marble is

P(R) = 0.015 + 0.050 + 0.049

P(R) = 0.114

If the Contestant draw a Red marble. Probability that it comes from box type (C) using Boyes theorem is

P(C/R) = {P(C) * P(R/C)} / P(R)

P(C/R) = 0.049 / 0.114

P(C/R) = 0.429824

P(C/R) = 0.4298

Answer:

The Probability that the GHI is less than $70 in three days is 1% or 0.01

Step-by-step explanation:

Here, we want to find the probability that the GHI is less than $70.

So what we do here is to find the scenarios that could make the $60 less than $70 is three days;

Scenario 1;

Two days decrease and one day increase

That will bring the value to 60 -1-1 + 10 = $68 which is less than 70

Scenario 2;

Three days decrease

That will bring the value to

60-1-1-1 = 57 which is less than 70

Any other possible scenario to make the value of the share less than 70? NO !

For the 1st case scenario;

Two days decrease and one day increase;

The scheduled probabilities will be as follows;

Kindly recall, probability of increase = 90% = 90/100 = 0.9

Probability of decrease = 10% = 10/100 = 0.1

So probability in scenario 1 will be;

P(Two days decrease and one day increase)

= 0.1 * 0.1 * 0.9 = 0.009

Kindly note this can happen in any order and since no order was specified, we do not need to consider other cases

Scenario ii

Three days decrease

That will be;

P(three days decrease) = 0.1 * 0.1 * 0.1 = 0.001

So the addition of both since we will be having either of the two and or means addition in probability will be ;

0.001 + 0.009 = 0.01 = 1%

Answer:

[tex]w = \frac{1}{2}(P - 24)[/tex]

[tex]w = 153\ yards[/tex]

Step-by-step explanation:

Given

[tex]P = 24 + 2w[/tex]

Require

Solving (a):

[tex]P = 24 + 2w[/tex]

Subtract 24 from both sides

[tex]P-24 = 24-24 + 2w[/tex]

[tex]P-24 = 2w[/tex]

Divide both sides by 2

[tex]\frac{1}{2}(P - 24) = \frac{2w}{2}[/tex]

[tex]\frac{1}{2}(P - 24) = w[/tex]

[tex]w = \frac{1}{2}(P - 24)[/tex]

Solving (b):

Substitute 330 for P un the expression in (1)

[tex]w = \frac{1}{2}(330 - 24)[/tex]

Evaluate the bracket

[tex]w = \frac{1}{2}(306)[/tex]

[tex]w = 153\ yards[/tex]

Question c; seem irrelevant

Answer:

2+7+X=12

2+7-12=-X

X=3

Answer:14

Step-by-step explanation:

13+5-4=14 No 1 more person got on.

Answer:

*assuming you know the concept of proportionality*

since L is directly proportional to T, an increase in L will result in an increase in T

so the solution of the first part is increases

in part 2, y is inversely proportional to x

which means that an increase in y will result in a decrease in x and vice-versa

So the answer of the second part is decreases

in part 3, since x is directly proportional to y, an increase in x will result in an increase in y

Answer:

x=16

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2x−8+3x−12=60

2x+−8+3x+−12=60

(2x+3x)+(−8+−12)=60(Combine Like Terms)

5x+−20=60

5x−20=60

Step 2: Add 20 to both sides.

5x−20+20=60+20

5x=80

Step 3: Divide both sides by 5.

5x

5

=80

5

x=16

can I be the brainest please

Answer:

5

Step-by-step explanation:

Plug is 6 for r and 0.25 for s

6(0.25)+14(0.25)

distribute

1.5+3.5=5

Hope this helps

Answer:

-8/15

Step-by-step explanation:

-2 *4 = -8

5 * 3 = 15

So,  -2/3 * 4/5 = -8/15

Answer:

-[tex]\frac{8}{15}[/tex]

Step-by-step explanation:

Hope this helps. Have a great day. Plz give brainliest.

so, here’s the work. Try to change it a bit so it doesn’t look like you copied lol

Answer:

The smaller one is -6, the bigger one is -4.

Step-by-step explanation:

Answer:

A. -6

Step-by-step explanation:

Answer:

[tex]A = \frac{2}{3}[/tex]

[tex]B = \frac{4}{3}[/tex]

Step-by-step explanation:

Given

[tex]X(s) = \frac{2s + 4}{s(s +6)}= \frac{A}{s} + \frac{B}{s + 6}[/tex]

Required

Find A and B

The expression can be rewritten as

[tex]\frac{2s + 4}{s(s +6)}= \frac{A}{s} + \frac{B}{s + 6}[/tex]

Take LCM of the right hand side

[tex]\frac{2s + 4}{s(s +6)}= \frac{A(s + 6 )+ Bs}{s(s +6)}[/tex]

Cancel out the denominators

[tex]2s + 4 = A(s + 6) + Bs[/tex]

Open Bracket

[tex]2s + 4 = As + 6A+Bs[/tex]

Reorder

[tex]2s + 4 = As +Bs+ 6A[/tex]

By direct comparison:

[tex]2s = As + Bs[/tex]

[tex]4 = 6A[/tex]

Solving [tex]2s = As + Bs[/tex]

Divide through by s

[tex]2 = A + B[/tex]

Solve for A in [tex]4 = 6A[/tex]

[tex]\frac{4}{6} = A[/tex]

[tex]A = \frac{4}{6}[/tex]

[tex]A = \frac{2}{3}[/tex]

Substitute [tex]\frac{2}{3}[/tex] for A in [tex]2 = A + B[/tex]

[tex]2 = \frac{2}{3} + B[/tex]

[tex]B = 2 - \frac{2}{3}[/tex]

LCM

[tex]B = \frac{6 - 2}{3}[/tex]

[tex]B = \frac{4}{3}[/tex]

Answer:

A. 85

Step-by-step explanation:

Answer:

I think it would have to be C because 20-13=7

Answer: -7

Step-by-step explanation:

Answer:

1. [tex]f(x)=x^{2}[/tex] and [tex]g(x)=-\sqrt{x}[/tex]

2. Vertical Asymptote: x=-4

    Horizontal Asymptote: y=1

    Zeros: (-2,0)

    Because the graph will have a hole at x=-1. This is, the graph is not defined for that particular x-value.

3.  [tex]f(x)=x^{2}+4[/tex]

It has two complex roots, so there is no place in the graph where it crosses the x-axis.

Step-by-step explanation:

1. If we find the composite function f[g(x)] with the functions:

[tex]f(x)=x^{2}[/tex] and g(x)=-x, we will get the following:

[tex]f[g(x)]=(-\sqrt{x})^{2}[/tex]

which simplifies to

f[g(x)]=x

on the other hand, if we find g[f(x)] we will get the following:

[tex]g[f(x)]=-\sqrt{x^2}[/tex]

which simplifies to:

g[f(x)]=-x

2.

Before finding the asymptotes, it's a good idea to factor both the numerator and denominator of the function, so we get:

[tex]f(x)=\frac{x^{2}+3x+2}{x^{2}+5x+4}[/tex]

[tex]f(x)=\frac{(x+2)(x+1)}{(x+4)(x+1)}[/tex]

we can now see that this function can be simplified. It is important to simplify this function so we don't confuse vertical asymptotes with holes in the graph, so when simplifying we get the following:

[tex]f(x)=\frac{x+2}{x+4}[/tex]

now we can set the denominator equal to zero.

x+4=0

and solve for x:

x=-4 this is our vertical asymptote.

For the horizontal asymptote, there is a rule that tells us that if the polynomials on the numerator and denominator have the same degree (the same greatest power), then the horizontal asymptote is found by dividing the lead coefficient of the polynomial on the numerator by the lead coefficient on the denominator. In this case the lead coefficients are 1 and 1 so the horizontal asymptote is:

[tex]y=\frac{1}{1}[/tex]

so the horizontal asymptote is at:

y=1.

The zeros of the function are located at the x-values that will turn the numerator of the simplified fraction equal to zero, so we get:

x+2=0

x=-2

so the only zero will be located at (-2,0)

x=-1 is not a zero because the original function is not defined for x=-1, there is a hole in the graph at this x-value.

Take a look at the graph of the function (See attached picture)

3.

This will happen when there are no real zeros. Take for example the function:

[tex]f(x)=x^{2}+4[/tex]

In this case this problem has 2 non-real zeros:

[tex]x^{2}+4=0[/tex]

[tex]x^{2}=-4[/tex]

[tex]x=\sqrt{-4}[/tex]

so:

x=2i   or   x=-2i

since they are complex numbers they cannot be graphed on a coordinate axis, so the graph will not cross the x-axis. See attached picture.

Answer:

Step-by-step explanation:

x² - 10x + 25 = 35

Move 35 to the left side of the equation

That's

x² - 10x + 25 - 35 = 0

x ² - 10x - 10 = 0

Using the quadratic formula solve the equation

That's

From the question

a = 1 , b = - 10 , c = - 10

Substitute the values into the above formula and solve

That's

[tex]x = \frac{ - - 10\pm \sqrt{( { - 10})^{2} - 4(1)( - 10) } }{2(1)} \\ = \frac{10\pm \sqrt{100 + 40} }{2} \\ = \frac{10\pm \sqrt{140} }{2} \\ = \frac{10\pm2 \sqrt{35} }{2} \\ = \frac{10}{2} \pm \frac{2 \sqrt{35} }{2} \\ = 5\pm \sqrt{35} [/tex]

We have the final answer as

Hope this helps you

Answer:

84 text messages

Step-by-step explanation:

Set up a proportion and solve:

dollars / texts = dollars / texts

9.8 / 196 + 4.2 / x

9.8 * x = 4.2 * 196

9.8x = 823.2

9.8x / 9.8 = 823.2 / 9.8

x = 84

Brody would have sent 84 messages if he spent $4.20.

A ratio indicates the number of times one number contains another.

Given that, the cost of sending 196 text messages is $9.80.

Therefore,

$9.80 = 196 messages

$1 = 196/9.80 messages

$4.20 = (196/9.80)×4.20 messages

$4.20 = 84 messages

Hence, Brody would have sent 84 messages, if he spent $4.20.

To learn more about ratios, click here:

https://brainly.com/question/13419413

#SPJ3

Answer:

–18 feet

Step-by-step explanation:

Answer:

-18

Step-by-step explanation:

Answer:

k=-4

Step-by-step explanation:

[tex]\frac{6}{5} (8*-4+2) = -36[/tex]

Answer:

k = -4

Step-by-step explanation:

6/5 (8k + 2) = -36

5 x 6/5 (8k + 2) = -36 x 5

6(8k + 2) = -180

48k + 12 = -180

48k = -180 - 12

48k = -192

48k/48 = -192/48

k = -4

Answer:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters.  If your teacher just wants one, it would be the middle one.  (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB.  For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD.  For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO.  For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB.  For OBF, it’s BOC and OCB

Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters.  If your teacher just wants one, it would be the middle one.  (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB.  For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD.  For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO.  For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB.  For OBF, it’s BOC and OCB

10 hundreds or 1 thousand.  

Further explanation

This question is related to place values.

10 times as many as a number is 10 multiplies the number.

Hence, 10 times as many as 1 hundred is

\boxed{ \ 10 \times 1 \ hundred \rightarrow \boxed{ \ 10 \ hundreds \ } \ }

Furthermore, 10 hundreds have the same meaning as 1 multiplies 10 hundreds which can produce 1 thousand.

\boxed{ \ 1 \times 10 \ hundred \rightarrow \boxed{ \ 1 \ thousand \ } \ }

Quick steps

Part-1

\boxed{ \ 10 \times 1 \ hundred = X \ hundred \ }

\boxed{ \ 10 \ hundred = X \ hundred \ }

Thus, \boxed{\boxed{ \ X = 10 \ }}  

Part-2

\boxed{ \ 10 \times 1 \ hundred = Y \ thousand \ }

\boxed{ \ 10 \times 100 = Y \ thousand \ }

\boxed{ \ 1,000 = Y \ thousand \ }

\boxed{ \ 1 \ thousand = Y \ thousand \ }

Thus, \boxed{\boxed{ \ Y = 1 \ }}  

- - - - - - -  

Conclusions

10 times as many as 1 hundred is _10_ hundreds or _1_ thousand.  

Learn more  

9 ten thousands divided by 10 (in unit form) brainly.com/question/4786449

How do you write 770,070 in expanded form? brainly.com/question/4725342  

100 is ¹/₁₀ of what? brainly.com/question/96535  

Keywords: 10 times as many as 1 hundreds, hundreds, thousands, place value, operations, multiply, equal, blank, quick steps

Answer:

your answer is 17

Answer:

[tex]Volume_B = 630in^3[/tex]

Step-by-step explanation:

Given

[tex]Volume_A = 630in^3[/tex]

Required

Determine [tex]Volume_B[/tex]

Volume is calculated as thus:

[tex]Volume = Height * Area[/tex]

From the question, we understand that both prisms have the same height and area;

This implies that

[tex]Volume_B = Volume_A[/tex]

Substitute [tex]630in^3[/tex] for [tex]Volume_A[/tex]

[tex]Volume_B = 630in^3[/tex]

Answer:

e.  630 in³

Step-by-step explanation:

ratio and proportion of volume with the same height:

vol A = 630

h = 21

Vol A = Vol B

   h            h

630 = Vol B

   21         21

Vol B = 630 (21)

               21

Vol B = 630 in³