USING JAVA write the function sumOfDigits(in). This function takes a non-negative integer paramenter n and returns the sum of its digits. No credit will be given for a solution using a loop
Examples:
sumOfDitigts(1234) --> 10
sumOfDitigts(4123) --> 10
sumOfDitigts(999) --> 27

The `sumOfDigits` function recursively adds the last digit of a number to the sum of its remaining digits. This process continues until the number becomes less than 10. The main method demonstrates the function's usage.

public class Main {

   public static int sumOfDigits(int n) {

       if (n < 10) {

           return n;

       }

               return n % 10 + sumOfDigits(n / 10);

   }

       public static void main(String[] args) {

       System.out.println(sumOfDigits(1234)); // Output: 10

       System.out.println(sumOfDigits(4123)); // Output: 10

       System.out.println(sumOfDigits(999));  // Output: 27

   }

}

The sumOfDigits function takes a non-negative integer n as input and recursively calculates the sum of its digits.

In the function, the base case is defined by checking if the number n is less than 10. If n is less than 10, it means that n is a single-digit number, so the function simply returns n.

If n is greater than or equal to 10, the function uses the modulus operator % to obtain the last digit of n (by calculating n % 10) and adds it to the recursive call of sumOfDigits with the remaining digits (by calculating sumOfDigits(n / 10)).

The function continues this process until the number becomes less than 10, at which point the sum of all the digits is returned.

In the main method, the sumOfDigits function is called with different input values to demonstrate its usage. The expected output is shown as comments next to each function call.

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