What are the effects of gravity on earth?​

Answer:

Explanation:

The two examples of contact forces are frictional force and applied force. The two examples of noncontact forces are gravitational force and magnetic force.

The air space would be half the size it was at the surface.

It should be noted that airspace means the portion of the atmosphere controlled by a country that's above its territory.

Based on the information given, the The air space would be half the size it was at the surface.

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Answer:

I think its either A or B. I’m not really sure, don’t listen to me. Read my explanation and it should help you.

Explanation:

When the two conducting spheres are brought together to touch, it is as though they become one single big conductor and the total charge of the two spheres spreads out across the whole surface of the touching spheres. When the spheres are moved apart again, each one is left with half of the total original charge…

X and Y are two identical conducting spheres separated by a distance d. X has a charge of +6µC and Y has a charge of -2µC. The electric force between them is +F (i.e. attractive). The spheres are touched together and are then returned to their original separation d. What is the new value of the force between them? Any help is greatly appreciated. I assumed that since the net charge should remain the same after, there would be no change in the value of the force, but the answer scheme gives the answer as -F/3…

Answer:

2.24 seconds

Explanation:

xf = xo + vo t + 1/2 at^2

45 = 0 + 15 t  + 1/2 (4.5) t^2

   2.25 t^2 + 15t - 45 = 0              Quadratic formula shows  t = 2.24 seconds

The car takes approximately 2.25 seconds to cover a distance of 45.0 meters under the given conditions of constant acceleration.

Given data:

Initial velocity (u) = 15.0 m/s

Acceleration (a) = 4.50 m/s²

Distance (s) = 45.0 m

We can use the kinematic equation to solve for time (t) when the car covers a certain distance under constant acceleration:

S = ut + 1/2at²

Where:

s = distance

u = initial velocity

a = acceleration

t = time

Plugging in the given values:

45.0 = 15.0t + 1/2 m/s²t²

2.25t² +15t - 45 = 0

t = 2.25sec and -8.92sec

Since time cannot be negative in this context, we discard the negative solution.

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The portions of Earth's fresh water are located in lakes and streams.  The options A and D are correct.

The freshwater is the one which does not contains any harmful chemical and saltiness.

The oceans contains salt water and the lakes and the streams have fresh water.

So, the option A and D are correct.

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The answer to the correct number of significant figures is 6.774.

When a number(big) divided smaller number, the answer obtained greater than zero is called a quotient.

Divide 143.6 ÷ 21.2

143.6/21.2 = 1436/212

                  =6.77358

The quotient is rounded to three significant figures after decimal

143.6 ÷ 21.2 = 6.774

Thus, the answer to the correct number of significant figures is 6.774

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The block will travel 2.038 m before stopping. Newton's third equation of motion is applied in the given problem.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration. Mathematically in the different components and balancing the equation gets.Components in the x-direction.

From Newton's third equation of motion;

v²=u²+2as

0 =u²+2(-a)s

u²=2as

u²=2×(2×μg)s

4.00 m/sec = √2×(2 ×0.2 ×9.81 s

16 = 7.848 s

s = 2.038 m

Hence, the block will travel 2.038 m before stopping.

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Answer:

Approximately [tex]122.625\; {\rm m}[/tex] (assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], the ball was launched from ground level, and that the drag on the ball is negligible.)

Explanation:

Let [tex]v_{0}[/tex] denote the velocity at which the ball was thrown upward.

If the drag (air friction) on the ball is negligible, the ball would land with a velocity of exactly [tex](-v_{0})[/tex]. The velocity of the ball would be changed from [tex]v[/tex] to [tex](-v_{0})\![/tex] (such that [tex]\Delta v = (-v_{0}) - v_{0} = (-2\, v_{0})[/tex]) within [tex]t = 10\; {\rm s}[/tex].

Also because the drag on the ball is negligible, the acceleration of the ball would be [tex]a = -g = -9.81\; {\rm m\cdot s^{-2}}[/tex]. Thus:

[tex]\Delta v = a\, t = 10\; {\rm s} \times (-9.81\; {\rm m\cdot s^{-2}}) = -98.1\; {\rm m\cdot s^{-1}}[/tex].

Since [tex]\Delta v = (-2\, v_{0})[/tex]:

[tex]-2\, v_{0} = \Delta v = -98.1\; {\rm m\cdot s^{-1}[/tex].

[tex]\begin{aligned}v_{0} &= \frac{-98.1\; {\rm m\cdot s^{-1}}}{-2}= 49.05\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].

The ball reaches maximum height when its velocity is [tex]v_{1} = 0\; {\rm m\cdot s^{-1}}[/tex]. Apply the SUVAT equation [tex]x = ({v_{1}}^{2} - {v_{0}}^{2}) / (2\, a)[/tex] to find the displacement [tex]x[/tex] between the original position (ground level, where [tex]v_{0} = 49.05\; {\rm m\cdot s^{-1}}[/tex]) and the max-height position of the ball (where [tex]v_{1} = 0\; {\rm m\cdot s^{-1}}[/tex].)

[tex]\begin{aligned}x &= \frac{(0\; {\rm m\cdot s^{-1}})^{2} - (49.05\; {\rm m\cdot s^{-1}})^{2}}{2 \times (-9.81\; {\rm m\cdot s^{-2}})} \\ &\approx 122.625\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Answer:

1.1111111

Explanation:

The formula for magnification (M) as already given is:

M= V/U

Where V is anything that has to do with image . such as image height or image distance And U is anything that has to do with object such as object height or object distance .

Image height (V) = 2m

Object height(U) = 1.8m

M = V/U

M= 2/1.8

M= 1.111111

If you float a piece of wood in a container half-full of water that rests on a weighing scale, the weight reading on the scale will increase.

Buoyancy is the force through your fluids or total or submerged bodies. Also known as Archimedes' theorem. The fluid of the direction on the body produces a resultant force but with the direction of the weight, with the opposite direction, upwards.

All material submerged in a liquid under the action of buoyancy, for this reason we have that the value on the scale will be increased with a system of a wood floating in water.

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Answer:

first answer:He can promote healthier start in the children's life by trying to avoid what he encounter when he has no access to health care.

Answer:

Yes

Explanation:

If lamp A burnt out there would still be a wire above it that connects lamp B and C to the power source

Answer:

B

Explanation:

Suppose the resistance of a copper wire is 1.05 ohms at 30°C. the temperature is mathematically given as

T=139.89

Generally, the equation for the coefficient of change is mathematically given as

[tex]\mu_k= 0.2+(0.043)3\\\\\mu_k=0.2+(0.043)(4.343)[/tex]

[tex]\mu_k=0.387[/tex]

In conclusion, the Temperature of copper

[tex]R=R_0( 1+ \alpha(T-T1))[/tex]

1.5(1+0.005(T-30))

T=139.89

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Answer:The amount of current flowing

Explanation:this derives from amperes law of maxwell’s equations. It’s easiest to see in differential form. The curl of the magnetic field is proportional to the current plus the change (time derivative) in electric field

Answer:

75%

Explanation:

Efficiency=MA/VR*100

=3/4*100

=0.75*100

=75%

Explanation:

1. the potential difference across the combination is the algebraic sum of yhe potential differences across the individual capacitors

2. the equivent capacitance of the combination is less than the capacitance of any of the capacitors..

The beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has been explained above will be,[tex]\rm Re_{104}^{287} + \beta_0^{-1} \rightarrow Re_{104}^{286}[/tex]  

The reduction in the number of radionuclides per unit time is the rate of decay.

The beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has 104 protons and 183 neutrons.

Atomic weight = 104+183 = 287

Atomic number  = 104

The beta decay equation is;

[tex]\rm Re_{104}^{287} + \beta_0^{-1} \rightarrow Re_{104}^{286}[/tex]

Hence the beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has been explained above.

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electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.

b gained electrons

Answer:

it is c

Explanation: i just did it

Answer:

1). Brake pedal or lever

2). A pushrod also called an actuating rod

From the calculations, the force required is 0.437 N.

The term force is defined a the product of mass and acceleration. The force is required to move the sling the required distance.

If mass = 0.019 kg and acceleration =  23 m/s2 then we know that F = ma

It then follows that the required force is;

F = 0.019 kg  *  23 m/s2= 0.437 N

Missing parts

You plan to use a slingshot to launch a ball that has a mass of 0.019 kg. You want the ball to accelerate straight toward your target at 23 m/s2. How much force do you need to apply to the ball?

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True, the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

Electric field is the region of space at which electric force is felt.

E = kq/r²

where;

at infinite plane, r → ∞, and E = 0

Thus, the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

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Answer:

Density is defined as mass per unit volume. its SI unit is: kg/m³

Explanation:

Answer:

Density is defined as mass per unit volume. its SI unit is: kg/m³

Explanation:

from answer above

i know it is c

here is the answer

The area would be 13.1429 Meter².

Answer:

[tex]\boxed {Area = 13.14 m^{2}}[/tex]

Explanation:

Formula applied :

[tex]\boxed {Area = \frac{Pressure}{Force}}[/tex]

Given :

Solving :

In a longitudinal wave, the propagation of energy is in the direction of the motion, while in a transverse wave the propagation of energy is perpendicular to the direction of motion.

Longitudinal wave is a wave which moves in the direction from where it was started. It has a compression (increased intensity) of the medium particles and a rarefaction ( reduced intensity).

Transverse wave is wave that travels perpendicular or at right angles to the direction from where it was started.

The main differences between longitudinal wave and Transverse wave are:

Therefore,

The propagation of energy is in the direction of the motion, while in a transverse wave the propagation of energy is perpendicular to the direction of motion.

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The mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.

Electric current is defined as the ratio of the charge flow in a given time interval. It is denoted by I. It has the unit is ampere.

Given data;

Electric current,I= 25 A

Thickness  = 0.1 mm

Length = 3 mm

Flux  = 1.4 w/m²

The charge density is found as;

[tex]\rm \rho =- \frac{1}{R_H} \\\\ \rho = 0.119 \times 10^{11} C/m^3[/tex]

The value of the hall voltage is;

[tex]\rm V_H = BVd \\\\ V_H = B \frac{I}{\rho dt} d \\\\ V_H = \frac{BI}{\rho t } \\\\ V_H = \frac{0.14 \times 25 }{0.119 \times 10^{11} \times 0.1 \times 10^{-3}} \\\\ V_H = \frac{3.5 }{0.119 \times 10^7} \\\\ V_H = 29.41 \times 10^{-6} \ v[/tex]

The mobility of electrons is;

[tex]\rm \mu_e = \frac{\rho}{n_e}\\\\ \mu_e = \frac{6.848 \times 10^7}{13.5 \times 10^{-30}\times 1.607 \times 10^{-19}} \\\\ \mu_e = 57.7 \times 10^{-4}[/tex]

Hence the mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.

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Answer:

Sonam will jump further than wangchuck