what are x and 8 in the linear equation? 8/x+5=50/25

A.One is variable and one is a coefficient

B.One is a constant and one is a coefficient?

C.Both are variables.

D.both are constants.

The equation of the line that passes through the given points is            y= -4x+23.

A line can be represented by a linear function. The standard form for the linear equation is: ax+b , for example, y=2x+7. Where:

a= the slope

b=constant term that represents the y-intercept.

From the stardard form equation:

Solving the system for equations 1 and 2.

3=5a+b

-13=9a+b * (-1)

3=5a+b

13=-9a-b * (-1)

16= -4a

4= -a

a= -4

If a= -4 from equation 1, you have

3= 5 * (-4)+b

3= -20+b

b=23

Therefore, the line equation is y= -4x+23.

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Answer:

It's +2

Step-by-step explanation:

As the positive occurs on the right side of the negatives in the number line so if we keep extending on the right side so we get +2

Probability helps us to know the chances of an event occurring. The probability of pulling a green or red card is 9 / 100.

Probability helps us to know the chances of an event occurring.

P =  [tex]\dfrac{Desired \ outcomes}{Posiible \ outcomes}[/tex]

The probabilities of different color cards being pulled are 1/25 for red, 1/20 for green, 1/15 for purple, and 1/10 for black Therefore, the probability of pulling  a green or red card is,

Probability = 1/20 + 1/25

                 = (5 + 4) /100

                 = 9 / 100

Hence, the probability of pulling a green or red card is  9 / 100.

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The process of Graphing a exponential decay function is shown in detail below.

There are two types of exponential equations: exponential decay and exponential growth. The fundamental shape of an exponential function and its corresponding graphs must be understood in order to fully comprehend the distinctions between exponential growth and decay. The fundamental distinction between the two is that in an exponential decay connection, the output values rise quickly as the input value rises, but in an exponential growth relationship, the output rises noticeably faster as the input value rises. Furthermore, neither of the two functions is linear, hence their rate of change is not constant. What distinguishes one equation from the other when they both have the same precise form, y = abx?

The value of the constant "b" is the fundamental factor in deciding whether the exponential function is one of growth or decay:

In this way we can graph a exponential decay function

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The confidence interval estimates that the confidence interval limits contain 0., suggesting that the garlic treatment did not affect the LDL cholesterol levels.

A confidence interval is a range of estimates for an unknown parameter in frequentist statistics. The 95 percent confidence level is the most common, but other levels, like 90 percent or 99 percent, are occasionally used when computing a confidence interval.

Given in a test of effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form.Both before and after the therapy, cholesterol levels were assessed.

LDL cholesterol variations had a mean of 4.4 and a standard deviation of 19.4 (in mg/dL). The best point estimate is 4.4.

We have to find 95% confidence interval estimate of the population mean

So,

x-bar = 4.4

ME = 1.96 = 5.27

H: no difference

Ha: is a difference

We fail to reject H since 0 is in the CI.

Hence the confidence interval estimates that the confidence interval limits contain 0., suggesting that the garlic treatment did not affect the LDL cholesterol levels.

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Answer:

[tex] {( \sqrt{ {x}^{ - 3} }) }^{5} = ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5} \\ \\ = {x}^{ - 3 \times \frac{1}{2} \times 5} = {x}^{ - \frac{15}{2} } = \frac{1}{ {x}^{ \frac{15}{2} } } [/tex]

Or ;

[tex] {( \sqrt{ {x}^{ - 3} } )}^{5} = {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5} = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5} \\ \\ = ( { \frac{1}{ \sqrt{x} \sqrt{ {x}^{2} } } })^{5} = ({ \frac{1}{ x\sqrt{x} }})^{5} \\ \\ = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) = \frac{1}{ {x}^{5} \times {x}^{ \frac{1}{2} \times 5 } } \\ \\ = \frac{1}{ {x}^{5} \times {x}^{ \frac{5}{2} } } = \frac{1}{ {x}^{5} \sqrt{ {x}^{5} } } \\ \\ = \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1} } } = \frac{1}{ {x}^{5} \sqrt{x} \sqrt{( { {x}^{2} })^{2} } } \\ \\ = \frac{1}{ {x}^{5} {x}^{2} \sqrt{x} } = \frac{1}{ {x}^{7} \sqrt{x} } = \frac{ \sqrt{x} }{ {x}^{8} } [/tex]

Answer:

1650 Cubic Centimeters

Step-by-step explanation:

To get the volume of the cereal boxes, you must multiply their 3 dimensions together.

Box A:

25×20=500

500×9=4500

Box B:

25×19=475

475×6=2850

Now, to find the difference of these volumes, you want to subtract the smaller volume from the larger volume.

4500-2850=1650

The answer is 1650 cubic centimeters.

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: x = 25°[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: 4x - 13 = 2x + 37[/tex]

[ Alternate Exterior Angle ]

[tex]\qquad \tt \rightarrow \: 4x - 2x = 37 + 13[/tex]

[tex]\qquad \tt \rightarrow \: 2x = 50[/tex]

[tex]\qquad \tt \rightarrow \: x = \cfrac{50}{2} [/tex]

[tex]\qquad \tt \rightarrow \: x = 25 \degree[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

A

Step-by-step explanation:

[tex]s=\frac{a+b+c}{2}[/tex]

multiply both sides by 2

[tex]2s = a + b +c[/tex]

substract b and c from both sides to get a by itself

[tex]a = 2s - (b + c)\\a = 2s - b - c[/tex]

so the answer is A.

If the scale factor is 1/2. Then the coordinate of the pre-image will be (-1, 1), (0, 1), (1, 0), (0, -1), and (-1, -1).

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Dilation does not change the shape, but changes the size of the geometry.

On a coordinate plane, an image has points (-2, 2), (0, 2), (2, 0), (0, -2), and (-2, -2).

The scale factor is 1/2. Then the coordinate of the pre-image will be

(-1, 1), (0, 1), (1, 0), (0, -1), and (-1, -1).

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Answer:D (-4) (-4)

Step-by-step explanation:

Answer:

[tex]=\frac{4y^2}{x^2}[/tex]

Step-by-step explanation:

[tex]\frac{(8x^2y^3)}{(2x^4y)}[/tex]

[tex]=\frac{(8x^2y^3)}{(2x^4y)}\\[/tex]

[tex]=\frac{8y^2}{2x^2}[/tex]

[tex]=\frac{4y^2}{x^2}[/tex]

I Hope This helps :)

Answer:

B: 2005

Step-by-step explanation:

Worked on edge 2022

The value of the height of the prism is 8.68 inches

The surface area is the sum of the area of the faces.

The formula for calculating the surface area of the pyramid is;

TSA  = [tex]a^2+2a\sqrt{\frac{a^2}{4} + h^2}[/tex]

where

a is the side length. = 7in

h is the height

Substitute

[tex]189=7^2+2(7)\sqrt{\frac{7^2}{2} + h^2} \\189=49+14\sqrt{\frac{49}{2} + h^2}\\140=14\sqrt{\frac{49}{2} + h^2}\\10=\sqrt{\frac{49}{2} + h^2}\\[/tex]

Square both sides to have

100 = 49/2 + h²

h² = 100 - 49/2

h² = 151/2

h² = 75.5

h = 8.68in

Hence the value of the height of the prism is 8.68 inches

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Answer:

∠A ≅ ∠D

Step-by-step explanation:

When writing a triangle congruency like ΔABC ≅ ΔDEF, the angles are congurent based on the orders listed. For example the first angle A is congruent with the first angle of the other triangle D.  

∠A ≅ ∠D

∠B ≅ ∠E

∠C ≅ ∠F

Adding 2x to both sides, we get [tex]\boxed{2x+y=5}[/tex]

Answer:

A. $60.25

B. 76 miles

C. 216 miles

Step-by-step explanation:

x is miles

y is total amount spent

For A, 57 miles is the x value. Plug that in to x.

y= 46 + .25(57)

y= 60.25

For B, the total is the y. So plug 65 in for y.

65 = 46 + .25x   Subtract 46 from both sides

19 = .25x             Divide by .25

76 = x

For C, the maximum you can spend is $100. Plug that in for y.

100 = 46 + .25x   Subtract 46 from both sides

54 = .25x             Divide by .25

216 = x

The answer for part a is $60.25, for part b the answer is 76 miles, and for part c the answer is 216 miles.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The equation to represent the cost would be y=46+0.25x

x is the number of miles.

a) What is your cost if you travel 57 miles?

Plug x = 57 in the above equation:

y = 46 + 0.25(57)

y = $60.25

b) If your cost was $65.00, how many miles were you charged for traveling?

Plug y = 65 in the equation:

65 = 46 + 0.25x

x = 76 miles

c) Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?

Plug y = 100 in the equation:

100 = 46 + 0.25x

x = 216 miles

Thus, the answer for part a is $60.25, for part b the answer is 76 miles, and for part c the answer is 216 miles.

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Using the z-distribution, it is found that 3,007 passengers must be surveyed.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

In this problem, we desired a margin of error of M = 0.015, with no prior estimate, hence [tex]\pi = 0.5[/tex], then we solve for n to find the minimum sample size.

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.015 = 1.645\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.015\sqrt{n} = 1.645(0.5)[/tex]

[tex]\sqrt{n} = \frac{1.645(0.5)}{0.015}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.645(0.5)}{0.015}\right)^2[/tex]

n = 3007.

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Answer:

m=0 , b=41

Step-by-step explanation:

Answer:

16.19

Step-by-step explanation:

Use the cosine rule:

[tex]\sqrt{a^{2} +b^{2} -2abcosy} \\\\\sqrt{16^{2} +20^{2} -(2)(16)(20)cos(52)} \\\\\\= 16.19cm[/tex]

Answer:

[tex]1)\text{ Friday}\\2)\text{ }7:00\\3a)\text{ }0\\3b)\text{ }4\\3c)\text{ }0\\4a)\text{ }6\\4b)\text{ }4\\4c)\text{ }2[/tex]

Answer:

740

Step-by-step explanation:

$415-$230=$185

$185×0.25=740 max miles

Answer:

A. 4/5

Step-by-step explanation:

Answer:

4/5  (option a)

Step-by-step explanation:

by following the exponent rule of [tex]a^1 = a[/tex], we know that

[tex](\frac{4}{5} )^1[/tex] = [tex]\frac{4}{5}[/tex]

So, the value of

[tex]\frac{4}{5}^{1}[/tex]  is  4/5

The graph is shown below:

A graph is a mathematical diagram which shows the relationship between two or more sets of numbers or measurements.

Given function: f(x) = x

We have to draw the graph for the function ,f(x) =x with two cases.

For x<2 and for x ≥ 2

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Answer:

4/2 is the wrong answer

Step-by-step explanation:

because it is

Using a trigonometric identity, it is found that the equivalent expression is given by 1.

Relating sine and cosine, we have that:

[tex]\sin^{2}{\beta} + \cos^{2}{\beta} = 1[/tex]

Then:

[tex]\cos^{2}{\beta} = 1 - \sin^{2}{\beta}[/tex]

For the tangent, we have that:

[tex]\tan{\beta} = \frac{\sin{\beta}}{\cos{\beta}}[/tex].

For the secant, we have that:

[tex]\sec{\beta} = \frac{1}{\cos{\beta}}[/tex].

In this problem, the expression is:

[tex]\frac{(1 - \sin{\beta})(1 + \sin{\beta})}{\cos^{2}{\beta}} = \frac{1 - \sin^2{\beta}}{\cos^2{\beta}} = \frac{\cos^2{\beta}}{\cos^2{\beta}} = 1[/tex]

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The flux is 9.

Flux is the presence of a force field in a specified physical medium, or the flow of energy through a surface.

Given:

2x+2y+z= 1

F = 2i+2j + 2k

Now,

r = xi + yj + z( 1-2x-2y) K

dr/dx= i - 2k

dr/dy = j-2k

dr/dx* dr/dy

= ( i - 2k) * (j-2k)

= 2i + 2j + k

F(x)= 2i+2j + 2k

F(x). da = 4 +4 +2 = 10 dxdy

Hence, flux

= [tex]\int\limits^1_0 {\int\limits^{1-2y}_0 {10 } \, dx dy } \,[/tex]

=  [tex]\int\limits^1_0[/tex]  10(1-2y) dx

= [tex]\int\limits^1_0[/tex] 10-2y

= 10(1) - (1)²

=9

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The plane has intercepts (1/2, 0, 0), (0, 1/2, 0), and (0, 0, 1). Parameterize [tex]S[/tex] by the vector function

[tex]\vec s(u,v) = \dfrac{(1-u)(1-v)}2 \, \vec\imath + \dfrac{u(1-v)}2 \, \vec\jmath + v \,\vec k[/tex]

with [tex]0\le u\le1[/tex] and [tex]0\le v\le1[/tex]. (More explicitly, we have the parameterization

[tex]\vec s(u,v) = (1-v)((1-u) p_1 + u p_2) + v p_3[/tex]

where [tex]p_i[/tex] denote the given points.)

The normal vector to [tex]S[/tex] is

[tex]\vec n = \dfrac{\partial\vec s}{\partial u} \times \dfrac{\partial\vec s}{\partial v} = \dfrac{1-v}2\,\vec\imath + \dfrac{1-v}2\,\vec\jmath + \dfrac{1-v}4\,\vec k[/tex]

Then the flux of [tex]\vec F = 2\,\vec\imath+2\,\vec\jmath+2\,\vec k[/tex] across [tex]S[/tex] is given by the surface integral,

[tex]\displaystyle \iint_S \vec F \cdot d\vec\sigma = \iint_S \vec F \cdot \vec n \, dA[/tex]

[tex]\displaystyle = \int_0^1 \int_0^1 \left(2\,\vec\imath+2\,\vec\jmath+2\,\vec k) \cdot \left(\frac{1-v}2\,\vec\imath + \frac{1-v}2\,\vec\jmath + \frac{1-v}4\,\vec k\right) \, du \, dv[/tex]

[tex]\displaystyle = \frac52 \int_0^1 \int_0^1 (1-v) \, du \, dv[/tex]

[tex]\displaystyle  = \frac52 \int_0^1 (1-v) \, dv = \boxed{\frac54}[/tex]

My theorems include the Pythagoras theorem, midpoint theorem, and angle bisector theorem.

The Pythagoras theorem is used to find the length in a right angle.

The midpoint theorem states that the line segment in a triangle is parallel to the third side and is half the length.

The angle bisector theorem is concerned with the lengths of the two segments that the triangle side is divided into by a line which bisects the opposite angle.

I like them because they're important when solving triangle related problems.

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