Answer:
A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions.
Explanation: hope it helps :)
A fairly efficient steam turbine engine fired by coal is used to drive an electric generator. The generator operates between 2100°C and 385°C.
(a) Determine the maximum possible efficiency of the engine.
Answer: 72.3 %
Formula:
e = 1 - (Tc / Th) = 1 - (Qc / Qh) = ( W / Qh)
Explanation: Unsure??
(b) The engine absorbs 1.15 105 J from the hot reservoir every second. If the actual efficiency of the engine is 40.3%, determine the mechanical power the engine delivers.
Answer: 46 kW
Explanation:
Energy absorbed by the engine (J) * actual efficiency of the engine (%) = mechanical power the engine delivers (kW)
How does 1 - (385/2100) = 72.3 % ?
What do I Plug in to make e = 72.3 %
Use kelvin not celsius
C + 273 = K
This will fix my problem of the equation not making sense.
Hello guys! Can you please help me with physics. I translated it in English. Can yall help me please how much you can!!
A body 60 m above the ground shall be thrown vertically upwards at an initial speed of 20 m / s. Air resistance can be ignored!
1. How high will the body fly from the point of ejection?
2. What is the maximum height it will reach above the ground?
3. How long does it take for the body to reach its highest point from the moment of expulsion?
4. After how long after the expulsion will the body fall to the ground?
5. What is the speed of the body at the moment of falling to the ground?
Answer:
1. 60m
4. its speed is 20m/s . gravity is 10m/s . 20 ÷ 10 = 2 seconds after these 2 sec are over the velocity will be zero thus it would have fallen.
Explanation:
Am sorry these is what i could answer but i will try to research and get answers for the rest of the questions, hope this helps
Plzzzzzzzzz
Help
Will give brainlessness
Answer:
1. A
2. A; distance is scalar, displacement is vector
3. C ; position is on the y-axis
when a mechanical wave travels through a medium, how does the wave affect the medium's particles?
thanks ;w;
Answer:
PLEASE MAARK ME BRAINLEST!!!
Explanation:
The particles of the medium just vibrate in place. As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Jose’s doctor recommends that he add more cardio to his exercise routine. Which exercise would be the BEST choice?
A.
ballet
B.
jogging
C.
bowling
D.
volleyball
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
jogging
Explanation:
Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.
A cyclist is coasting at 12 m/s when she comes to a muddy stretch with an effective coefficient of friction of 0.60. Will the cyclist be able to get out of the muddy stretch without having to pedal if it lasts 10 meters
The cyclist will make it since the distance traveled by the cyclist is greater than the length of the muddy stretch.
The given parameters;
speed of the cyclist, u = 12 m/scoefficient of friction, μ = 0.6length of the muddy stretch, L = 10 mThe effective acceleration of the cyclist at the given coefficient of friction is calculated as follows;
[tex]a = \ \mu g\\\\a = 0.6 \times 9.8\\\\a = 5.88 \ m/s^2[/tex]
The distance traveled by the cyclist at the give speed and acceleration is calculated as;
[tex]v^2 = u^2 + 2as\\\\12^2 = 0 + 2(5.88)s \\\\ 11.76 s = 144\\\\ s = \frac{144}{11.76} \\\\a = 12.24 \ m[/tex]
Thus, we can conclude that the cyclist will make it since the distance traveled by the cyclist is greater than the length of the muddy stretch.
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Calculate the weight of an object that displaces 3 m2 of water and exerts a pressure of 500 Pa (500 N/m ).
The weight of the object from the information provided in the question is 1500 N.
We know that pressure = Force/area. We have the following information from the question;
Pressure =500 Nm-2
Area = 3 m2
Hence;
Force = Pressure × area
Force = 500 Nm-2 × 3 m2
Force = 1500 N
Hence, the weight of the object is 1500 N
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What factors determine climate?
Answer:
here
Explanation:
Climate is determined by the temperature and precipitation characteristics of a region over time. The temperature characteristics of a region are influenced by natural factors such as latitude, elevation and the presence of ocean currents.
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
[tex]dl'=3.621*10^{-4}m[/tex]
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
[tex]dl=\frac{Flo}{yA}[/tex]
[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=1.19064778*10^-^4[/tex]
Generally the equation for brass cylinder is mathematically given as
[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=2.43*10^{-4}[/tex]
Therefore Total change in length
[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]
[tex]dl'=3.621*10^{-4}m[/tex]
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Calculate the charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts.
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
Potential difference is the amount of work needed to move a unit charge from one point to another. It is given by:
V = E/Q
Where V is potential difference, E is energy and Q is charge. Given that:
V = 15 V, E = 5.25 kJ = 5.25 * 10³ J.
V = E/Q
15 = 5.25 * 10³ /Q
Q = 350 Coulomb
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
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If an automobile slows from 26 m/s to 18 m/s in a period of 4.0 s, what was the average acceleration?
Answer: -2m/s²
Explanation:
Each second, the acceleration decreases of 2m/s²
N.B.: in physics, deceleration is also acceleration.
If the acceleration of an object increases, what effect does this have on the Force and Mass?
A Force Increases, Mass Increases
B Force Decreases, Mass Decreases
C Force increases, Mass remains the same
D Force Decreases, Mass remains the same
Answer:
Force Increases and Mass remains the same.
Explanation:
The wavelength is 1. 87 x 10-7 m. What is the frequency?.
Answer:
11.7 im pretty sure. i did the work so it should be correct
what metaphor most closely describes the nature of space-time?
a. chemistry formula
b.fabric
c. sine wave
d. moebius strip
Answer:
b.fabric
Explanation:
Nowadays, when people talk about space-time, they often describe it as resembling a sheet of rubber. This, too, comes from Einstein, who realized as he developed his theory of general relativity that the force of gravity was due to curves in the fabric of space-time.
Answer:
B. fabric
Explanation:
What decides free energy.
Answer: when free energy is extensive property that means its magnitude depends on the amount of a substance.
Explanation:
srry if im wrong :( .
Answer:
state of the system
Explanation:
Gold density = 19.30,
Silver density = 10.49,
Lead density = 11.34.
They have the same mass but are made of different metals. Each one is lowered into a beaker of water. Use the data above to decide which one will cause the biggest rise in water level.
A) Gold
B) Silver
C) Lead
D) All will cause the same rise in water level
Density of water=1g/cm^3
Now all metals has greater mass in comparison to water.
Higher the mass higher the rise[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]
[tex]\\ \sf\longmapsto Density\propto Mass[/tex]
Higher the density higher the massGold has higher mass hence it will cause the biggest rise.
Option A
Silver will cause biggest rise in water
What is density ?Density of an object is a measure of its mass per unit volume.
density = mass / volume
since all have same mass , so metal which have higher volume will cause the biggest rise in water level .
since , density is inversely proportional to volume , hence material having low density will have higher volume
hence , silver will cause biggest rise in water
correct option B) Silver
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In general, a _______ intake manifold produces high torque at _______ engine rpm because of the increased amount of time between the air pulses due to the inertia of the long column of air.
There are two major types of intake manifold. In general, A long intake manifold produces high torque at lower engine rpm because of the increased time between the air pulses.
Intake Air Heating is made up of different methods that manufacturers do use to heat intake manifolds.
This Heating system on vehicles are often with emission controls, air cleaners use a thermostatic valve to control how much hot air enters the air cleaner.
Conclusively there are two forms of intake manifold. They are the long and short intake manifold.
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Can anyone help me with this question? I’ll give BRAINLIEST to whoever answers first
Answer:
a) F = 84.64N
b) The force has to increase.
Explanation:
First of all, let's convert everything to the same unit system:
Vo = 0 m/s Vf = 98 mi/h * 1609.34 m / 1mi * 1h / 3600s = 43.8m/s
d = 1.7m m = 0.15kg
We can calculate force as:
F = m*a where a is the acceleration experiencd by the ball and m is its mass.
In order to calculate acceleration, we can use this formula:
Solving for a:
Now, the force will be:
F = m * a = 84.6N
As we can see in that previous equation, the force is directly proportional to the mass of the ball, so, assuming the final speed of the ball is the same as before (that is, the acceleration is the same), the force will increase in the same proportion as the mass does.
Calculate the acceleration of a bottle rocket that is traveling at a speed of 74 m/s, and then descends at a speed of 89 m/s. It takes the rocket 5 seconds to change its speed.
a) 1 m/s/s
b) 2 m/s/s
c) 3 m/s/s
d) 4 m/s/s
Answer:Falling objects form an interesting class of motion problems. For example, we can estimate the depth of a vertical mine shaft by dropping a rock into it and listening for the rock to hit the bottom. By applying the kinematics developed so far to falling objects, we can examine some interesting situations and learn much about gravity in the process.
Explanation:
You throw a can of cranberry sauce straight up in the air with an initial velocity of 12 m/s. What is the maximum height the baseball reaches above your head.
Answer:
Δx=7.35m
Explanation:
This is a free fall problem (g= -9.8 m/s²).
Displacement: ? <--- what you're trying to find (max height)
Initial Velocity: 12 m/s
Final Velocity: 0 m/s <-- since the can will land back in your hands
Time: Missing <-- not needed to solve
Acceleration: -9.8 m/s²
The equation that you will use is vf²=vi²+2aΔx
Now plug the information into the equation!
(0m/s)²=(12m/s)²+2(-9.8m/s²)Δx
Multiply the 2 with the acceleration (-9.8m/s²)
(0m/s)²=(12m/s)²-19.6m/s²Δx
Now you need to square the final and initial velocity
0m/s=144m/s-19.6m/s²Δx
Move 144 to the other side of the equal sign
-144m/s=-19.6m/s²Δx
Divide both sides by -19.6m/s²
7.346m=Δx
You can round it to the tenth or hundreth place, up to you!
For this example, I'll round to the hundredth...
Δx=7.35m
I would double check this answer or review it yourself to see if it's correct.
Good luck with your studies!
How to find average velocity on a graph.
Answer:
Answer is below….
Explanation:
The velocity is represented by the slope of a position-time graph. The faster the motion changes, the steeper the slope. The change in position divided by the corresponding change in time may be used to compute average velocity from a position-time graph.
_________________________________________________________
(hope this helps can I pls have brainlist (crown)☺️
What is the half-life for the radioactive decay of particle that
starts with 400.00 g and ends up with 12.50 g if the total time
was 50 minutes for the decay to occur?
Answer:
ytyug
Explanation:
A block of mass =4.20 kg slides along a horizontal table with velocity 0=3.50 m/s . At =0 , it hits a spring with spring constant =26.00 N/m and it also begins to experience a friction force. The coefficient of friction is given by =0.250 . How far has the spring compressed by the time the block first momentarily comes to rest? Assume the positive direction is to the right.
The distance in which the spring is compressed is 1.065 m.
The given parameters;
mass of the block, m = 4.2 kgvelocity of the block, v = 3.5 m/sspring constant, k = 26 N/mcoefficient of friction, μ = 0.25Apply the principle of conservation of energy to determine the distance in which the spring is compressed.
[tex]K.E = W + U\\\\\frac{1}{2} mv^2 = \mu Fx \ + \ \frac{1}{2} kx^2\\\\\frac{1}{2}(4.2)(3.5)^2 = 0.25(4.2 \times 9.8)(x) \ + \frac{1}{2} (26)(x^2)\\\\25.725 = 10.29x \ + \ 13x^2\\\\13x^2 + 10.29x - 25.725 = 0\\\\[/tex]
solve the quadratic equation using formula method;
a = 13, b = 10.29, c = -25.725
[tex]x = \frac{-b \ \ +/- \ \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-(10.29) \ \ +/- \ \sqrt{(10.29)^2 \ - \ 4(13\times 25.725)} }{2(13)} \\\\x = 1.065 \ m, \ \ or \ -1.86 \ m[/tex]
choose positive distance, x = 1.065 m.
Thus, the distance in which the spring is compressed is 1.065 m.
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A mass 25kg is attached to a spring which is held stretched a distance 120 cm by a force F=300N (Fig. 7-28), and then released. The spring compresses, pulling the mass. Assuming there is no friction, determine the speed of the mass m when the spring returns: (a) to its normal length (x = 0). (b)find the spring constant k?
Explanation:
Spring is stretched by force f to distance
"X"
now here by force balance we can say
f = kx
k = !
now here we will we say that energy stored in the spring will convert into kinetic energy
kx² = mv²
(x² = mv²
now solving above equation we will have
PART 2)
now for half of the extension again we can use energy conservation
ka²-k(x/2)² = 1 {mv²
¾fx=mv²
now the speed is given as
3 fr 4m V=
A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?
Answer:
35N
Explanation:
force=mass×gravity
the mass is 5 and the gravity is 7 therefore:
force=7×5
=35N
I hope this helps
What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod
Answer:
C) 5ML^2
Explanation:
2 Spheres of mass M
Bug's mass 3M
Rod length 2L, radius L
Find Rotational Inertia I
I=Σmr^2
I=(3M+M+M)L^2
I=5ML^2
The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Rotational inertia of the systemThe rotational inertia of the system is determined by summing all the masses together and multiply with the radius.
I(t) = Σmr²
Where;
m is the massr is the radiusI(t) = Inertia of the 2 spheres + inertia of the bug
I(t) = (M + M)L² + (3M)L²
I(t) = 2ML² + 3ML²
I(t) = 5ML²
Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Complete question is below:
There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.
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Suppose that a cart is moving along a road at a constant velocity. Give two examples of ways to cause the cart to decelerate, explaining how the net force is affected. (2 points)
The cart moving at a constant velocity will decelerate when a braking force is applied or the road is made to become rougher.
Deceleration is also known as negative acceleration. It occurs when velocity decreases with time. There are two ways by which the cart moving at constant velocity can be made to decelerate. These two ways are;
By applying a braking force: A braking force causes the velocity to decrease with time. When a braking force is applied the frictional force exceeds the forward force hence the net force decreases.By increasing the roughness of the road: When the roughness of the road is increased, the frictional force also increases causing the net force on the cart to decrease hence it decelerates.Learn more: https://brainly.com/question/14281129
l. amount of liquid
ll. initial mass of the bone
lll. temperature of liquid
A.
l and lll
B.
II and III
C.
ll only
D.
l only
A.l and lll
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The amount of heat that is needed to raise the temperature of 1
kg of some material by 1°C is called the of the material.
a. specific heat
b. state
c. temperature
d. charge
Answer:
a. specific heat
Explanation:
a. specific heat
If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)
Answer:
10s
Explanation: