what does parallelepiped focus on

The given radical root 84, the simplification is option B; [tex]2\sqrt{21}[/tex].

Usually, simplification involves proceeding with the pending operations in the expression.

Simplification usually involves making the expression simple and easy to use later.

The given radical;

[tex]\sqrt{84} \\\\\sqrt{42 \times 2} \\\\\sqrt{7\times3\times 2 \times 2} \\\\2\sqrt{21} \\[/tex]

Thus, the correct option is B; [tex]2\sqrt{21}[/tex].

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The value of each algebraic expressions are:

1. 16

2. 156

3. 87

4. 3

5. 300

6. 4

7. 68

An algebraic expression is a mathematical statement involving variables and digits. It is evaluated by plugging in the value of the variables.

1. Product of y and 12 is 12y

100 - 12y

Plug in the value of y

100 - 12(7) = 16

2. b(15 + 37) = b(52) = 3(52)

= 156

3. Product of z and 12 is 12z

12z + 27 = 12(5) + 27

= 87

4. 135 ÷ 5c = 135/5(9)

= 3

5. w²(12/4) = 3w²

= 3(10²)

= 300

6. 12d ÷ (25 - 19)

12d/6 = 12(2)/6

= 4

7. 13 + 5x

13 + 5(11)

= 68

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Answer:

B

Step-by-step explanation:

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:f(x)= 9280 - 20x [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{1}{16} x + \cfrac{1}{320} y - 29 = 0[/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{1}{16} x + \cfrac{1}{320} y = 29[/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{20 x+ y}{320} = 29[/tex]

[tex]\qquad \tt \rightarrow \: 20x + y = 29 \sdot320[/tex]

[tex]\qquad \tt \rightarrow \: y = 9280 - 20x[/tex]

[tex]\qquad \tt \rightarrow \: f(x) = 9280 - 20x[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer: 2

Step-by-step explanation:

[tex]{12x+2}=\frac{18+34}{2}\\\\12x+2=26\\\\12x=24\\\\x=\boxed{2}[/tex]

Answer:

[tex]\large\boxed{\sf n^2 \ log \ x }[/tex]

Step-by-step explanation:

Given that ,

[tex]\longrightarrow \log \ x + \log\ x^3 + \log \ x^5\ \dots + \log x^{2n-1} [/tex]

As we know that , [tex] \log x^n = n \log x [/tex] , therefore ;

[tex]\longrightarrow \log x + 3\log x + 5\log_x +\dots + (2n-1)\log x [/tex]

Take out log x as common ;

[tex]\longrightarrow \log x ( 1 + 3+5+...+(2n-1))[/tex]

The terms inside the brackets are the sum of first n odd numbers . And we know that the sum of first n odd numbers in n² . Therefore ;

[tex]\longrightarrow \log x (n^2) \\[/tex]

[tex]\longrightarrow \underline{\underline{\red{{ n^2\log x }}}}[/tex]

Option c is correct!

Answer:

52.50$

Given:

⇒ Emily has 50% in a savings account currently.

⇒ Interest rate is 5% per year and is not compounded

To find:

⇒ How much she will have in 1 year

__

steps

⇒ [tex]5\text{percent} \times50[/tex]

⇒ [tex]=\frac{5}{100} \times50[/tex]

⇒ [tex]=\frac{100}{(5\times50)}[/tex]

⇒ [tex]= \frac{250}{100}[/tex]

⇒ [tex]=2.5[/tex]

Now that we have calculated her interest rate per year, we must calculate that added onto her balance in her account before the interest was applied.

⇒ [tex]2.5+50\[/tex]

⇒ [tex]52.50\[/tex]

Therefore, Emily will have 52 dollars and 50 cents in a year.

The measure of angle 7 is 82°.

A transversal is defined as a line that passes through two lines in the same plane at two distinct points in the geometry

Given:

angle 6= 98°

As, angle 6 and 7 forms a linear pair then

angle 6 + angle 7 = 180

98 +  angle 7= 180

angle= 180-98

angle 7 = 82°

Hence, angle 7 is 82°.

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Answer:

it depends on whether the outlier is a high outlier or a low outlier

Step-by-step explanation:

The mean of a data set is the average of the data set. So if I had the data set {5, 2, 10} the average would be (5+2+10)/3 = 5.667. Now if I added an outlier like 10,000 it would increase the mean significantly. It changes it significantly but I cannot say whether it increases or decreases it without knowing the value of the outlier, since if I had the outlier -10,000 that would decrease the mean, but I had the outlier 10,000 it would increase it. So it depends on whether the outlier is a high outlier or a low outlier

A variation on Momentary Time Sampling that involves counting the number of students in a classroom engaged in a target behaviour at the designated time in the interval is known as Planned Activity Check ( PLACHECK)

Momentary Time Sampling is a method of recording a student's behaviour ,

It helps in understanding clearly the regularity of a student.

This method is used when the behaviour cannot be easily counted or it is difficult for the teacher to focus to get the exact duration in which the student showed severity to the work.

In easy words , a timer is set and from the start to the end of the timer , it is observed whether the required goal is achieved or not and what is the frequency at which that task is being done in the time interval.

Planned Activity Check ( PLACHECK) is when Momentary Time Sampling is done with the group , It provides the measure of a group behaviour.

Therefore ,

A variation on Momentary Time Sampling that involves counting the number of students in a classroom engaged in a target behavior at the designated time in the interval is known as Planned Activity Check ( PLACHECK)

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Answer:

pls yo give the full question

Answer:

Ox=4 is the answer for the question

Solve for x coordinate of solution

Check given value in options and approximate them

So x coordinate is -13/4

Option C is correct as no one contains -13/4 except C

Answer:

[tex]\sf C. \quad \left(-\dfrac{13}{4},\dfrac{5}{2}\right)[/tex]

Step-by-step explanation:

The solution to a system of graphed equations is the point of intersection.

From inspection of the graph:

As the x-coordinate is negative, this eliminates answer options A and B.

Assessing the x-coordinate of answer options C and D:

⇒ C.   -13/4 = -3.25

⇒ D.    -5/2 = -2.5

Therefore, as the x-coordinate of the point of intersection is between -4 and -3, the approximate solution of the system of equations is:

[tex]\sf C. \quad \left(-\dfrac{13}{4},\dfrac{5}{2}\right)[/tex]

The equivalent expression to 7^13/7^7 would be 7^6.

Those expressions that might look different but their simplified forms are the same expressions are called equivalent expressions.

To derive equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.

We have given an expression as  7^13/7^7

The equivalent expression;

[tex]\dfrac{7^{13}}{7^7} \\\\7^{13-7}\\\\7^6[/tex]

Hence, The equivalent expression to 7^13/7^7 would be 7^6.

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Answer:

This mapping isn't a function.

Step-by-step explanation:

A mapping specifies a relation between two sets of items (input and output). For example, a mapping of the form [tex]\lbrace (x_{0},\, y_{0}),\, (x_{1},\, y_{1})\rbrace[/tex] would map the input [tex]x_{0}[/tex] to output [tex]y_{0}[/tex] and map the input [tex]x_{1}[/tex] to output [tex]y_{1}[/tex].

A function is a mapping where each input is associated with exactly one output.

Note that both [tex](2,\, 1)[/tex] and [tex](2,\, 4)[/tex] are in the mapping given in this question. The input [tex]2[/tex] is mapped to more than one outputs. Thus, this mapping isn't a function.

Answer:

18.75 inches

Step-by-step explanation:

Inches:feet

3. : 8

X. : 50

(Cross multiply)

8x=150

X=150÷8=18.75

200 grams of sterling silver is needed to make the 91℅ alloy

An equation is mathematical expression that contains an equals symbol. Equations are contain algebra. Algebra is used in maths when you do not know the exact number in a calculation.

given, x + y =500

The number of grams of pure silver in x plus the number of grams of pure silver in y is equal to the number of grams of pure silver in the 500 grams.

The pure silver is given in percentage forms.

Hence, 92.5% (x) + 90% (y) =91% (500)

Substitute y by 500−x in the last equation to write

92.5% (x) + 90% (500−x) =91% (500)

Simplify and solve

92.5x+45000−90x=45500

x=200 grams.

Hence, 200 grams of Sterling Silver is needed to make the 91% alloy.

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Answer:

centroid

Step-by-step explanation:

medians of the triangle intersect at point H, making this point centroid.

(essentially, it's the center of the triangle)

Methods of describing a set involve using a roster or set-builder notation to outline it.

The two methods of describing a set are:

Roster method describes a set by listing all its elements, separated them by commas and enclosed within brackets.

Set- builder notation method describes a set by describing its elements using mathematical statements

Therefore, methods of describing a set involve using a roster or set-builder notation to outline it.

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The value of composite function (koh)(x) is 1/(5+x) after plugging h(x)  = 5+x in the k(x) option (B) is correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The question is:

if h(x)=5+x and k(x)=1/x which expression is equivalent to (koh)(x)

Answer options are:

We have:

h(x) = 5 + x

k(x) = 1/x

To find the composite function:

(koh)(x):

= k(h(x))

= 1/(5+x)

Thus, the value of composite function (koh)(x) is 1/(5+x) after plugging h(x)  = 5+x in the k(x) option (B) is correct.

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Answer: C

Step-by-step explanation: Substitute the x’s into C’s equation.

2(0) is 0, 0+1 is 1 so the first row is correct. 2(2) is 4, 4+1 is 5, so the second row is correct. 2(4) is 8, 8+1 is 9, so the third row is correct. And lastly, 2(6) is 12, 12+1 is 13 so fourth row is correct as well. Assuming the rest of the rows follow this pattern, the correct answer should be C.

A ratio shows us the number of times a number contains another number. The correct option is C.

A ratio shows us the number of times a number contains another number.

For winning less than $10, a person needs to take out a green ticket or a yellow ticket. Therefore, the odds against winning less than $10 are,

(Number of blue tickets) : (Number of green and yellow tickets)

5: 30

1: 6

Hence, the correct option is C.

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The expression (2 + 3) + 4 = 2 + (3 + 4) illustrates the associative property of addition option (C) is correct.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

As we know with the help of associative property we can group the terms of addition or multiplication.

a + (b + c) = (a + b) + c

Option (C)

= (2 + 3) + 4

After using the associative property:

= 2 + (3 + 4)

Thus, the expression (2 + 3) + 4 = 2 + (3 + 4) illustrates the associative property of addition option (C) is correct.

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Answer:

C

Step-by-step explanation:

given the factors are (x - 7) and (x + 3)

equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 3 = 0 ⇒ x = - 3

Answer:

5x+2x(x-4)=5x+x-10

5x+2x-8=5x+x-10

5x-5x+2x+x=-10+8

x+3x=-2

4x=-2

x=-2

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

[tex]ax^2+bx+c=0[/tex]

Let's find a, b, c:

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}[/tex]

[tex]x=\frac{5\pm\sqrt{121} }{4}[/tex]

[tex]x=4[/tex] or [tex]x=\frac{-3}{2}[/tex]

Answer:

x = 4 or x = -3/2

The t-test might be more useful in actual practice when standard deviation or variance is unknown.

The t-test is used to determine how the averages of various data sets differ from one another.

When variance is not provided, the T-test, a particular kind of parametric test, is used to determine how the means of two sets of data differ from one another. When variance is provided, the Z-test indicates a hypothesis test that determines whether the means of two datasets differ from one another.

Example of t-test: If you flip a coin 1,000 times, for instance, you can discover that the outcome is distributed normally over all trials.

Example of z-test: We are conducting research using information gathered from cohorts of students who have taken Elementary Statistics in the past.

T-tests are typically more suitable when addressing issues with small sample sizes, whereas z-tests are suitable for large sample sizes.

Using the t-test for an ordinal variable, their frequency is not even close to a normal distribution, and the arithmetic mean offers an unsuitable measure of location.

Because we frequently don't know the population standard deviation, Z-Tests have this drawback.

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