What expression is equivalent to ten square root five

Answer: m x H = [ -9  36  - 9/2 ]

Step-by-step explanation:

Answer:

Unknown

Step-by-step explanation:

Hi! so you didn't add the ordered pair options but I will do my best :) so if you see the ordered pair (0.7) that could definitely be a solution because using the slope intercept form equation you gave I know that's our y Intercept. the slope is 4/1 so moving up 4 and to the right 1 or down 4 and to the left 1 on a graph could show you more points! If you don't want to draw it you could use Desmos and just put this equation in or give me the ordered pairs and I will give you your answer!

hope this helps :)

Answer:

log x to the base 2 +log x to the base 4 =2

or log x/ log 2+ log x /lig 4 =2

or log x /log2 + log x /2.log 2 = 2

or log x/log 2(1+1/2)= 2

or log x/log 2 = 4/3

or 3.log x =4.log2

or logx^3=log 2^4

or x^3= 2^4

or x =(2)^4/3 or 2.(2)^1/3 ,Answer.

hope this helps

Step-by-step explanation:

Answer:The value of m for the given equation is, 35

Step-by-step explanation:

Given an equation:  https://tex.z-dn.net/?f=x%5E%7B3m%7D%3D(x%5E%7B65%7D)*(x%5E%7B40%7D)

Use the above property on  RHS in equation [1];

Since the base are same i.e, x ; we can add the exponents.

or

Using:  , then a=b.

Therefore, 3m=105.

Divide 3 on both sides of an equation:

Simplify:

m=35

Therefore, the valur of m is, 35.

Answer:

Given - AC is parallel to DE

angle 3y + 28 = angle X ( Vertically opposite angles are equal).

3y + 28 = X

X + Y = 180° ( supplementary angles).

3y - X = (-28)

Solving both the equation we get

multiply eq 1 with 3

3x + 3y = 540

-X + 3y = (-28)

subtracting

4x = 568

x = 142°

3y + 28 = 142

3y = 142 - 28

3y = 114

y = 38°

Considering that the mean of the normal distribution is the same as the median, the median is of 88%.

It states that, for a normally distributed random variable:

For the normal distribution, the median is the same of the mean, that is, the median is of 88%.

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Answer:

[tex]27[/tex]

Step-by-step explanation:

[tex]g(f(0))=g(2(0)+3)=g(3)=3^3=27[/tex]

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(25) - log_{6}(5) [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) {}^{2} - log_{6}(5) [/tex]

[ property : x² = 2 log x ]

[tex]\qquad \tt \rightarrow \: 2 \: log_{6}(5) {}^{} - log_{6}(5) [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The inequality describes the price $375  she can afford for 25

individual box of supplies will be $375 ≥ 25x.

An inequality is comparison of  two values, showing if one is less than, greater than, or simply not equal to another value.

Let the price of each box is $x.

The inequality describes the price can she afford for each

individual box of supplies will be $375 ≥ 25x.

Therefore inequality is $375 ≥ 25x.

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Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

Starting with the left side, we can transform it into the right side.

  [tex]2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}[/tex]

Using the binomial distribution, it is found that the probabilities are given as follows:

a) 0.2036 = 20.36%.

b) 0.0011 = 0.11%.

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

The values of the parameters are given as follows:

p = 0.95, n = 5.

Item a:

The probability is P(X = 4), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{5,4}.(0.95)^{4}.(0.05)^{1} = 0.2036[/tex]

Item b:

The probability is P(X < 3), hence:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2).

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{5,0}.(0.95)^{0}.(0.05)^{5} \approx 0[/tex]

[tex]P(X = 1) = C_{5,1}.(0.95)^{1}.(0.05)^{4} \approx 0[/tex]

[tex]P(X = 2) = C_{5,2}.(0.95)^{2}.(0.05)^{3} = 0.0011[/tex]

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0 + 0.0011 = 0.0011.

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The number of the units were started into production in a period will be 25,375.

A industry's fully prepared kinds of goods, as well as the primary materials needed to make them, are considered to as inventory.

If there were zero units of beginning work in process inventory, 4,714 units of ending work in process inventory, and 20,661 completed and transferred out units.

Completed and transferred out = 20,661

Ending Inventory = 4,714

Units accounted for = 25,375

Beginning Inventory = 0

Units started into production = [Units accounted for – Beginning work in progress Inventory] = 25,375

Units accounted for = 25,375

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The probability that a class attendee is a non-member of the gym and is attending a barre class or is a member of the gym and is attending a boot camp class is 0.009.

Probability refers to a possibility that deals with the occurrence of random events.

The marketing team has gathered data from a random month, in which there were 2039 class attendees.

The probability that a class attendee is a non-member of the gym and is attending a barre class

= 185/2039

= 0.09

The probability that a class attendee is a member of the gym and is attending a boot camp class

= 204/2039

= 0.10004

The probability for both the event would be

= 0.09 x 0.10004

= 0.009

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We know that cos2x=cos²x-sin²x

=cos²x-(1-cos²x)         [since, cos²x+sin²x=1]

=cos²x-1+cos²x

=2cos²x-1

So, cos2x=2cos²x-1

Hence, cos²x= (1+cos2x)/2

Trigonometric Identities are useful whenever trigonometric functions are involved in an expression or an equation. Trigonometric Identities are true for every value of variables occurring on both sides of an equation. Geometrically, these identities involve certain trigonometric functions (such as sine, cosine, tangent) of one or more angles.

Most common trigonometric identities are:

- cos²x + sin²x = 1

- sec²x - tan²x = 1

- cosec²x - cot²x = 1

- cos2x = cos²x - sin²x

Therefore we get that the statement cos² x = (1 - cos 2x)/2 is false.

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Answer:

Is the question even complete ?

Step-by-step explanation:

According to law of cosines if the lengths of triangle are 12,11,6 then the angle will be 114=157-132cos(Y)

Given the length of XZ is 12, length of YZ is 11 and the length of YX=6.

According to law of cosines the angle of a triangle when the length of sides are given can be written as:

[tex]c^{2} =a^{2} +b^{2} -2abcosd[/tex]

where c is the side opposite to the angle which we have to find and a and b are the rest sides.

We have to put the values of sides in the above law:

[tex]12^{2} =6^{2} +11^{2} -2*6*11cosY[/tex]

144=36+121-132 cos Y.

Hence the angle can be written as 144=36+121-132 cos Y.

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Step-by-step explanation:

{-1,2,3,4,5,6,8} is the answer

From the information given, the cost of sales is $65,000. See the explanation below.

Add your initial inventory to the purchases made over the time period, remove that amount from your ending inventory, and that is your cost of sales.

Cost of Sales = (Bi + P) - Ei

Where Bi is Beginning Inventory

P is Purchases; and

Ei is Ending Inventory.

Beginning Inventory = 8,000

(add)          Purchase = 70,000

Bi + P                          = 78,000

Ending Inventory  = 13,000

Cost of sales = 78,000 - 13,000

= $65,000

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This graph represents the equation y = -3

Based on the information given, the correct options will be

y = x + 6 and 3x - 3y = -18 .... Infinitely many solutions.

y = -2x + 5 and 2x + y = -7 .... No solution.

y = -4x + 11 and -6x + y = 11 ... One solution.

Solving equations

y = -4x + 11 ....... equation i

-6x + y = 11 ...... equation ii

Put equation i into ii.

-6x + y = 11

-6x + (-4x + 11) = 11

-6x - 4x + 11 = 11

-6x - 4x = 11 - 11

-10x = 0

x = 0

Therefore, x = 0 and y = 11. This gives a solution for each variable.

y = -2x + 5 ..... i

2x + y = -7 ..... ii

Put equation I into ii

2x + y = -7

2x + (-2x + 5) = -7

2x - 2x = -7 - 5

0 = -12

This indicates no solution.

y = x + 6 ..... i

3x - 3y = -18 ..... ii

Put equation I into ii

3x - 3y = -18

3x - 3(x + 6) = -18

3x - 3x - 18 = -18

3x - 3x = - 18 + 18

0 = 0

This implies that there are infinitely many solutions.

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Answer:

  B.) The only solution is (4, - 1/2)

Step-by-step explanation:

To solve this system of equations using the substitution method, we need to use one equation to find an expression for one of the terms or variables that can be substituted for that term or variable in the other equation.

__

Here, it is convenient to use the second equation to write an expression for x:

  x -2 = -4y

  x = 2 -4y . . . . add 2 to both sides

Using this expression for x, we can write the second equation as ...

  3x +2y = 11

  3(2 -4y) +2y = 11 . . . . . substitute for x

  6 -10y = 11 . . . . . . . . eliminate parenthses

This 2-step equation can be solved in the usual way:

  -10y = 5 . . . . . . . subtract the constant to isolate the variable term

  y = -5/10 = -1/2 . . . . . divide by the coefficient of the variable

  x = 2 -4(-1/2) = 2 +2 = 4 . . . . . find the corresponding x-value

The only solution is (x, y) = (4, -1/2).

The only solution is (x, y) = (4, -1/2). so, the correct option is B.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

we have the system of equations;

3x+2y=11

x−2=−4y

By the substitution method;

use the second equation to write an expression for x:

 x -2 = -4y

 x = 2 -4y

substitute

 3x +2y = 11

 3(2 -4y) +2y = 11

 6 -10y = 11

solve

 -10y = 5

 y = -5/10 = -1/2

 x = 2 -4(-1/2)

x = 2 +2 = 4

Thus, The only solution is (x, y) = (4, -1/2). so, the correct option is B.

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Answer:

B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.

Step-by-step explanation:

1) according to the given coordinates the equations of the sides are:

YZ: y=2; WZ: x=2; WX: y=10; XY: x=10. It means

2) YZ⊥WZ; YZ⊥XY; WX⊥XY; WX⊥WZ. To the additional, WX=WZ=YZ=XY, then

3) the given quadrilateral is sqare (rhombus with angles m∠=90°).

4) finally, the correct answer is

B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.

Answer:

8x + 100

Step-by-step explanation:

Your answer is correct! But because the equation is already set to "y =", you do not need the "f(x)" in your equation.

Answer: 8

Step-by-step explanation:

As corresponding sides of similar triangles are proportional,

[tex]\frac{RX}{RB}=\frac{XE}{BO}\\\\\frac{6}{15}=\frac{a}{20}\\\\a=20\left(\frac{6}{15} \right)=\boxed{8}[/tex]

Answer:

See Pictures

Step-by-step explanation:

(a) X ≈ N (0.10 , 0.02²)

(b) The probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.

(c) The 60th percentile is 11%.

A. X ~ N( , )  

B. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11%.

C. Find the 60th percentile for this distribution.

According to the question,

The random variable X is defined as the THC content for a bag of marijuana that is sold on the street.

(a)The random variable X is Normally distributed with mean, μ = 0.10 and standard deviation, σ = 0.02.

Therefore, X ≈ N (0.10 , 0.02²)

(b) The value of P (X > 0.11) as follows:

P (X > o.11_ = P(X -μ/a > [tex]\frac{0.11-0.10}{0.02} \\[/tex])

= P(Z > 0.50)

= 1 -P (Z <0.50)

= 1- 0.69146

= 0.30854 ≈ 0.31

Hence,

the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.

(c)Let x represent the 60th percentile value.

Then, P (X < x) = 0.60.

⇒ P (Z < z) = 0.60

The value of z is,

z = 0.26.

Now put the value of x as follows:

z = x - μσ

0.26 = x - 0.100.02

x = 0.10+ ( 0.26 x 0.02)

x = 0.1052

x ≈ 0.11

Therefore,

The 60th percentile is 11%

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The number of girls are significantly low.

Probability is the study of likeliness of an event to happen.

It is given that

900 births are randomly selected

The probability of birth of a boy or a girl is 1/2 = 0.5

Total chances of a girl is 900 * 0.5 = 450

The birth of girl observed is 4

Therefore the number of girls are significantly low.

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Answer:

C. 3x - 9

Step-by-step explanation:

3x – y = 9 ___(1)

8x – 4y = 0 ___(2)

From (1) eq.

3x – y = 9

– y = 9 – 3x

y = - (-3x + 9)

y = 3x – 9

Hence, 3x - 9 should be substituted in the second equation to get the required answer.

Answer:

c

Step-by-step explanation:

solve for y in the first equation

y = 3x - 9

when you substitute, you will get a value of 9 for x and 18 for y