what is 4.50+3.4+12.09 ?​

Answer:

The products would not be formed or the reaction could not be carried out.

Explanation:

Sometimes in these situations it is chosen to place a chemical compound that accelerates the reaction and increases the kinetic energy of the reactants, without altering their chemical composition, and this is called a catalyst, which can be anything from a protein to a macromolecule.

Answer:

Copper oxide is the only product, and it contains copper and oxygen.

One of the reactants is copper, so the other reactant must be oxygen.

The copper metal must have combined with something in the air.

Explanation:

Answer:

A double covalent bond

Explanation:

A double covalent bond is a situation where we have two pairs of electrons shared together between the atoms instead of just one pair. Oxygen gas is an example of a simple molecule that contains double bonds.

In other words, it is a type of chemical bond that has 2 electron pairs shared between two atoms.

Answer: my epic on fortnite is

Explanation:Bookboy24 ok add me and arena or creative

Answer:

8.2mL of the concentrated solution must be taken diluting to 1.30L with water

Explanation:

The concentrated HNO₃ comes in a presentation of 70% = 15.8M

As the concentrated solution is of 15.8M and we want to obtain a 0.100M, the dilution must be of:

15.8M / 0.100M = 158 times must be the concentrated solution diluted

As the total volume we want to prepare is 1.30L, the volume of the concentrated solution must be:

1.30L / 158 = 8.2x10⁻³L =

Answer:

5

Explanation:

Answer: B) 2 (as indicated by electron distribution shown), but taking into account the real properties of this element, 4,7,8 also occur (see below).

Explanation:

This is the electron complement/atomic number of ruthenium, which actually has the structure [Kr] 5s1 4d7

Nevertheless, Ru does not form Ru(I) compounds and few Ru(II) compounds (RuCl2, RuBr2, RuI2). It also forms Ru(III)Cl3 and a larger number of Ru(IV) compounds, e.g. RuO2, RuS2. It also forms RuO4

Hi there!

[tex]\large\boxed{\text{B. Producer}}[/tex]

The only organisms in a food web that do not get energy from other organisms are producers. These are autotrophs (ex: plants or phytoplankton) that use photosynthesis to produce energy. This means that these organisms only intake water and sunlight rather than nutrients from other organisms (consumers).

Answer:

Explanation:

The answer is (4) 4.0 mol. This is a stoichiometry problem. You start with 2.0 mol of C2H6 and obtain the moles of C by multiplying 2.0 by the mole ratio, in this case 2. 2.0*2=4.0mol.

Answer:

3.41 g

Explanation:

A chemist adds 260.0 mL of a 0.0832 M potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate the chemist has added to the flask.

Step 1: Given data

Step 2: Calculate the moles (n) of potassium permanganate added

We will use the following expression.

n = C × V

n = 0.0832 mol/L × 0.2600 L = 0.0216 mol

Step 3: Calculate the mass corresponding to 0.0216 moles of potassium permanganate

The molar mass of potassium permanganate is 158.03 g/mol.

0.0216 mol × 158.03 g/mol = 3.41 g

Answer:

25.39

Explanation:

Given parameters:

Abundance of X-25  = 80.5%

Abundance of X - 27  = 19.5%

Unknown:

Average atomic mass of X  = ?

Solution:

The average atomic mass of X can be derived using the expression below:

Average atomic mass = (abundance x mass of X - 25) + (abundance x mass of X - 27)

Average atomic mass  =  (80.5%  x 25) +   (19.5% x 27)  = 25.39

Answer:

w₁ = 0 J

w₂ = -297 J

Explanation:

Step 1: Given data

Initial volume: 266 mL (0.266 L)

Final volume: 983 mL (0.983 L)

Step 2: Calculate the work done (in joules) by the gas if it expands against a vacuum

We will use the following expression.

w₁ = -P₁ × ΔV

Since the gas expands against a vacuum, P₁ = 0. Thus, w₁ = 0 J

Step 3:  Calculate the work done (in joules) by the gas if it expands against a constant pressure of 4.09 atm

We will use the following expression.

w₂ = -P₂ × ΔV

w₂ = -4.09 atm × (0.983 L-0.266 L) = -2.93 atm.L

Then, we convert w₂ to Joule using the conversion factor 1 atm.L = 101.325 J.

-2.93 atm.L × 101.325 J/1 atm.L = -297 J

Answer:

C.) A new compound is formed - salt

Explanation:

Na is a metal

Cl is a nonmetal

When they are combined, they form ionic bonds as they seek to fill their octets. Salts are ionic compounds.

When sodium undergoes a chemical reaction with chlorine, a new compound is formed known as sodium chloride or common table salt. The correct option is C.

Chemical reaction is a chemical process, which involves the transformation of one or more substances, called reactants, into new substances, called products. These reactions occur when atoms or ions or molecules rearrange their bonds to form different chemical compounds.

 The reaction between sodium and chlorine is highly exothermic (releases heat energy) and produces a violent reaction, resulting in the formation of a stable ionic compound.

The balanced chemical equation for this reaction is:

[tex]2Na + Cl_2\rightarrow 2NaCl[/tex]

In this reaction, the sodium atoms (Na) lose one electron each to achieve a stable electron configuration, forming sodium ions (Na+), while the chlorine molecules [tex](Cl_2)[/tex] gain one electron each to form chloride ions (Cl-). The resulting sodium ions and chloride ions attract each other due to their opposite charges, forming a three-dimensional crystal lattice of sodium chloride.

Therefore, when sodium undergoes a chemical reaction with chlorine, a new compound is formed that is salt. Option C is the correct answer.

Learn more about chemical reactions here:

https://brainly.com/question/29762834

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Answer: D

Explanation: Hope this helps!

Answer:

volcanoes and volcanic activity

Explanation:

I had the same Question and I got that.

Answer: Volcanoes and Volcanic Activity :)

Explanation: I got the same question :D

Answer:

2

[tex]0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]

Explanation:

Half-life

[tex]{t_{1/2}}A=2\ \text{min}[/tex]

[tex]{t_{1/2}}B=4\ \text{min}[/tex]

Concentration

[tex]{[A]_0}_A=1.2\ \text{M}[/tex]

[tex]{[A]_0}_B=0.6\ \text{M}[/tex]

We have the relation

[tex]t_{1/2}\propto \dfrac{1}{[A]_0^{n-1}}[/tex]

So

[tex]\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}[/tex]

Comparing the exponents we get

[tex]1=n-1\\\Rightarrow n=2[/tex]

The order of the reaction is 2.

[tex]t_{1/2}=\dfrac{1}{k[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{t_{1/2}[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{2\times 1.2^{2-1}}\\\Rightarrow k=0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]

The rate constant is [tex]0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]

Answer:

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Contents Home   Bookshelves   Physical & Theoretical Chemistry   Supplemental Modules (Physical and Theoretical Chemistry)   Electronic Structure of Atoms and Molecules Expand/collapse global location

Predicting the Hybridization of Simple Molecules

Last updatedAug 16, 2020

Predicting the Bond-Order of Oxides based Acid Radicals

Prediction of Aromatic, Anti Aromatic and Non Aromatic Character of Heterocyclic Compounds along with their Omission Behavior- Innovative Mnemonics

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Prof. Linus Pauling (1931) first developed the Hybridization state theory in order to explain the structure of molecules such as methane (CH4).1This concept was developed for simple chemical systems but this one applied more widely later on and from today’s point of view it is considered an operative empirical for excusing the structures of organic and inorganic compounds along with their related problems. An innovative method proposed for the determination of hybridization state on time economic ground 2,3,4.

Prediction of sp, sp2, sp3 Hybridization state

We Know, hybridization is nothing but the mixing of orbital’s in different ratio to form some newly synthesized orbitals called hybrid orbitals. The mixing pattern is as follows:

s + p (1:1) - sp hybrid orbital; s + p (1:2) - sp2 hybrid orbital ; s + p (1:3) - sp3 hybrid orbital

Formula used for the determination of sp, sp2 and sp3 hybridization state:

Power on the Hybridization state of the central atom = (Total no of σ bonds around each central atom -1)

All single (-) bonds are σ bond, in double bond (=) there is one σ and 1π, in triple bond (≡) there is one σ and 2π. In addition to these each lone pair (LP) and Co-ordinate bond can be treated as one σ bond subsequently.

Eg.:

a. In NH3: central atom N is surrounded by three N-H single bonds i.e. three sigma (σ) bonds and one lone pair (LP) i.e. one additional σ bond. So, in NH3 there is a total of four σ bonds [3 bond pairs (BPs) + 1 lone pair (LP)] around central atom N. Therefore, in this case power of the hybridization state of N = 4-1 = 3 i.e. hybridization state = sp3.

b. In H2O: central atom O is surrounded by two O-H single bonds i.e. two sigma (σ) bonds and two lone pairs i.e. two additional σ bonds. So, altogether in H2O there are four σ bonds (2 bond pairs + 2 lone pairs) around central atom O, So, in this case power of the hybridization state of O = 4-1 =3 i.e. hybridization state of O in H2O = sp3.

c. In H3BO3:- B has 3σ bonds (3BPs but no LPs) and oxygen has 4σ bonds (2BPs & 2LPs) so, in this case power of the hybridization state of B = 3-1 = 2 i.e. B is sp2 hybridized in H3BO3. On the other hand, power of the hybridization state of O = 4-1= 3 i.e. hybridization state of O in H3BO3 is sp3.

d. In I-Cl: I and Cl both have 4σ bonds and 3LPs, so, in this case power of the hybridization state of both I and Cl = 4 - 1 = 3 i.e. hybridization state of I and Cl both are sp3.

e. In CH2=CH2: each carbon is attached with 2 C-H single bonds (2 σ bonds) and one C=C bond (1σ bond), so, altogether there are 3 sigma bonds. So, in this case, power of the hybridization state of both C = 3-1 = 2 i.e. hybridization state of both C’s are sp2.

Prediction of sp3d, sp3d2, and sp3d3 Hybridization States

Answer:

Aldonic acids

Explanation:

Aldonic acids are a group of sugar acids which are derived from the oxidation of the aldehyde group (-CHO) of an aldose to a carboxylic acid group (-COOH).

The aldehyde group of monosaccharides is easily oxidized to the carboxylic acid group by relatively mild oxidizing agents such as copper (ii) ions and the products are called aldonic acids. This oxidation of monosaccharides such as glucose and other reducing sugars is the basis for the test for reducing sugars using the Fehling's reagent, whereby blue copper (ii) ions in solution are reduced to red copper (i) oxide which precipitate out of solution. The most common oxidizing agent used in preparation of aldonic acids is bromine. For example, oxidation of D-glucose by bromine water at C1 yields D-gluconic acid.

Aldonic acids do not usually exist in hemiacetal ring forms but are generally found in their lactone form which are cyclic structures formed by an ester linkage between the carboxylic group and one of the hydroxyl groups of the same molecule.

The distance of the earth to the sun in Mm = 1.5 x 10⁵

Given

The distance of the earth to the sun : 1.50 x 10⁸ km

Required

The distance in Mm

Solution

In converting units we must pay attention to the conversion factor.

the conversion factor :

1 kilometer(km) = 10⁻³ megameter(Mm)

So the distance conversion :

1.5 x 10⁸ x 10⁻³ = 1.5 x 10⁵ Mm

Answer:

C

Explanation:

Answer:

If Earth were to change its orbit – maybe because the sun somehow disappeared or another, larger object entered the solar system and exerted a stronger pull – it would very likely mean the end of life as we know it. Without any orbit, Earth would likely go crashing directly into the sun.

Explanation:

Hope this helped! Please give brainly if you want!

Explanation:

If Earth were to change its orbit – maybe because the sun somehow disappeared or another, larger object entered the solar system and exerted a stronger pull – it would very likely mean the end of life as we know it. Without any orbit, Earth would likely go crashing directly into the sun.

Answer: i’m taking a test w this question rn and i think the best answer is D. When the water begins to boil, some of the water molecules will gain enough energy to change into a gas. i could def be wrong tho

Answer:

Explanation:

It changes from a liquid to a solid. This change occurred due to the change in temperature. As the mixture cooled, the molecules condensed and the mixture formed a solid shape.Which formed the jelly.

Answer:

0.448 atm

Explanation:

So, we have;

n = 2 moles

V = 126 L

T = 346 K

a = 6.20 atmL^2/mol^2

b = 0.0852 L/mol

R = 0.082 atmLK-1mol-1

P = nRT/V -nb - an^2/V^2

Substituting values;

P=2 * 0.082 * 346/126 -(2 * 0.0852) - 6.20 * 2^2/126^2

P=56.744/125.8296 -24.8/15876

P= 0.45 - 0.001562

P= 0.448 atm

Answer:

Valence electrons are the electrons in the outermost shell, or energy level, of an atom.

Answer: The outermost shell

Explanation:

Valence electrons are located in the outermost shell of the atom, or the energy level as it is also known.

Answer:

208 grams

Explanation:

Half life is the time it takes for a sample to reduce to half it's initial concentration.

In this question, 3 half lives go by. This is given as;

Let original mass be represented by x

First Half life;

Starting mass = X

Remaining mass = X/2

Second Half life;

Starting mass = X/2

Remaining mass = (X/2) / 2 = x/4

Third Half life;

Starting mass = X/4

Remaining mass = (X/4) / 2 = X/8

Since 26g was left, it means;

X/8 = 26

X = 26 * 8  = 208 grams

Explanation:

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