What is Moral subjectivism?

The mass of ice that was initially placed in the vessel of neglected heat capacity was found to be 1.135 kg.

Given that,

Mass of water = 14 kg

Mass of ice = m kg

P = Power of the burner = dQ/dt

Rate of the heat given by the burner is constant.

In the first 45 min,

dQ/dt = mL/t1 = m x (80 x 4.2 x 10³)/45 min.               (1)

From 45 to 60 min,

dQ/dt = (m+14) x δ(Η₂Ο) x Δθ / t2 =(m+14) x (4.2 x 10³) x 2/ 15 min.            (2)

From (1) and (2)

m x (80 x 4.2 x 10³)/45 min = (m+14) x (4.2 x 10³) x 2/ 15 min

80m/3 = (m+14) x 2

80m = 6m + 84

m = 1.135 kg

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The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J

First, we shall obtain the initial kinetic energy. Details below:

KE₁ = ½mu²

= ½ × 1500 × 55²

= 41250 J

Next, we shall final kinetic energy. Details below:

KE₂ = ½mv²

= ½ × 1500 × 65²

= 3168750 J

Finally, we shall determine the net work done. Details below:

W = KE₂ - KE₁

= 3168750 - 41250

= 3127500 J

Thus, the net work done is 3127500 J

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If the distance between two objects is decreased to 1 10 of the original distance, the way it will change the force of attraction between them is (A) It will 100 times larger than the original force.

The force of attraction between two objects is directly proportional to the inverse square of the distance between them and it is shown as:

F ∝ 1/r²

wher:

F is the force

r is the distance between the objects.

If the distance between the objects is decreased to 1/10 of the original distance (or 1/10r), one need to or can substitute this value into the equation. Hence it will be:

F' ∝ 1/(1/10r)²

So by Simplifying this expression, one have:

F' ∝ 1/(1/100r²)

F' ∝ 100r^2

From the above, one can see that the new force, F', is 100 times larger than the original force (F). Therefore, option A is the correct answer.

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See text below

If the distance between two objects is decreased to 1 10 of the original distance, how will it change the force of attraction between them? A. The new force will be 100 times more than the original. B. The new force will be 20 times more than the original. C. The new force will be 1 20 of the original. D. The new force will be 1 100 of the original. E. The new force will be 1 10 of the original.

Answer:

[tex]\tt F=1.63*10^3 N[/tex]

Explanation:

Gravitational force is defined as the force of attraction between two objects with mass. It is a fundamental force of nature, and it is what keeps us on the ground and what keeps the planets in orbit around the Sun.

The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers

For the Question:

We can use the following formula to calculate the gravitational force between the Earth and the satellite:

[tex]\boxed{\tt F =\frac{ G * M * m }{ r^2}}[/tex]

Where:

F is the gravitational force

G is the gravitational constant[tex]\tt (6.673 * 10^{-11} Nm^2/kg^2)[/tex]

M is the mass of the Earth [tex]\tt (6.0 * 10^24 kg)[/tex]

m is the mass of the satellite[tex]\tt (5,400 kg)[/tex]

r is the distance between the satellite and the center of the Earth [tex]\tt (3.6400 * 10^7 m)[/tex]

Plugging in these values, we get the following:

[tex]\tt F = \frac{6.673 * 10^{-11} * 6.0 * 10^{24}* 5,400 }{ (3.6400 * 10^7 )^2}[/tex]

[tex]\tt F=1.63*10^3 N[/tex]

Therefore, answer is [tex]\tt F=1.63*10^3 N[/tex]

The work of forensic engineers who investigate fires involves identifying what started the fire and where it originated, and it does not solely focus on explosions. This process is not relatively simple and is typically conducted by specialized forensic teams rather than firefighting personnel.

Forensic engineers play a crucial role in investigating fires to determine their cause and origin. Their primary objective is to gather evidence and analyze it in order to understand the circumstances surrounding the fire incident.

1. Scene Assessment: Forensic engineers begin by assessing the fire scene. They examine the area to gather initial information about the fire's intensity, pattern, and potential sources.

2. Evidence Collection: Next, the investigators collect physical evidence from the fire scene. This may involve gathering debris, examining burn patterns, and documenting any signs of accelerants or other substances that could have contributed to the fire.

3. Documentation: Forensic engineers meticulously document their findings through photographs, sketches, and written notes. This documentation serves as a crucial reference throughout the investigation process.

4. Laboratory Analysis: Collected evidence is then analyzed in specialized laboratories. Forensic experts employ various techniques such as chemical analysis, microscopy, and other scientific methods to determine the cause of the fire.

5. Report Preparation: Once the analysis is complete, forensic engineers prepare detailed reports outlining their findings. These reports serve as valuable resources for insurance companies, legal proceedings, and future fire prevention efforts.

It is important to note that the work of forensic engineers primarily focuses on identifying the cause and origin of the fire. While they consider various possibilities, including explosions, their investigation is not limited to solely investigating explosions.

Moreover, the process of investigating fires is complex and requires specialized knowledge and expertise. It is typically carried out by dedicated forensic teams rather than the firefighting personnel.

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The elastic potential energy stored in the spring is 0.375 J.

The formula for elastic potential energy is:

E = 1/2 * k * x^2

where:

* E is the elastic potential energy in Joules

* k is the spring constant in N/m

* x is the distance the spring is stretched or compressed from its equilibrium position in meters

In this problem, we have:

* k = 3 N/m

* x = 0.5 m (50 cm)

Substituting these values into the formula, we get:

E = 1/2 * 3 * 0.5^2 = 0.375 J

Therefore, the elastic potential energy stored in the spring is 0.375 J.

In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.

The period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,

Period of oscillation = 1.80s.

From here, finding the frequency is simple as, Frequency = 1/Period. Hence,

Frequency = 1/1.80

= 0.555 Hz (3 sf).

The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.

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Answer:

a) Calculate the change in the radius of the cylinder between 15.0°C and 85.0°C.

Given:

Depth of cylinder = 18.0 cm = 0.180 m

Average linear expansion coefficient for aluminum = 24 x 10^-6 /°C

Temperature change = 85 - 15 = 70 °C

Change in radius = (initial radius) x (linear expansion coefficient ) x (temperature change)

= (0.180/π) x (24 x 10^-6) x (70)

=2.16 x 10^-4 m = 0.0216 mm

b) Calculate the change in volume of the turpentine between 15.0°C and 85.0°C.

Given:

Initial volume of turpentine = 2.000 L

Average volume expansion coefficient for turpentine = 9.0 x 10^-4 /°C

Temperature change = 85 - 15 = 70 °C

Change in volume = (initial volume) x (volume expansion coefficient) x (temperature change)

= 2.000 L x (9.0 x 10^-4) x 70

= 0.126 L

c) Will any turpentine overflow? Explain your reasoning.

No turpentine will overflow because the increase in the radius of the cylinder is greater than the increase in the volume of the turpentine.

The cylinder radius increases by 0.0216 mm (part a) while the volume of turpentine increases by only 0.126 L (part b). This indicates the expanded cylinder can accommodate the increased volume of turpentine, so no overflow will occur.

Explanation:

if wrong im sorry

When paired with copper, the metal plate that will produce a higher voltage is a) Calcium.

The voltage produced in a battery is related to the difference in electron affinity between the two metals used as electrodes. A greater difference in electron affinity results in a higher voltage.

In this case, the electron affinity of copper is +0.34 eV. Among the given options, calcium has the highest electron affinity with -2.87 eV. The difference between the electron affinities of copper and calcium is the greatest among the options, indicating a larger potential difference and thus a higher voltage when paired together.

Therefore, when paired with copper, the calcium plate will produce a higher voltage compared to zinc, lead, or another copper plate. Therefore, Option a is correct.

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The question was incomplete. find the full content below:

A physical science student is building a battery with two metal plates. The table below shows a list of

metals and their electron affinity given in electron volts, eV.

Metal Electron Affinity (electron volts, eV)

Calcium - 2.87

Zinc

-0.76

Lead -0.13

Copper +0.34

The student has a copper plate. When paired with copper, which metal plate will produce a higher

voltage?

A. Calcium

B. Zinc

C. Lead

D. Copper

Answer:

Liberal arts education is important for ensuring continued innovation. It helps students think creatively, solve problems, collaborate effectively, and consider ethical factors. By exploring various subjects and adapting to new situations, liberal arts education equips individuals with the skills needed to generate new ideas and drive progress in different fields.

Answer:

E: More than one option is correct  

Explanation:

Tension, weight, and friction produce torques on the hoop, while the normal force does not.

Answer:

Here are the steps to solve this problem:

Determine the weight of the object in air:

F = ma

Weight (W) = Force (F) x gravitational field strength (g)

W = 5.05 N x 9.8 m/s^2 = 49.5 N

Determine the weight of the object submerged in water:

W' = 3.88 N x 9.8 m/s^2 = 38.0 N

The difference in weight is due to buoyant force:

Fb = Wa - W

Fb = 38.0 N - 49.5 N = 11.5 N

The buoyant force is equal to the weight of the water displaced:

Fb = ρwVg (where ρw is the density of water and V is the volume)

11.5 N = (ρwV)(9.8 m/s^2)

Solve for the volume and density of the object:

V = Fb/( ρwg) = 11.5 N/(1000 kg/m^3)(9.8m/s^2)

= 1.17 x 10^-3 m3

Density of object = mass/volume

ρ = W/V = 49.5 N/(1.17 x 10^-3 m3)

= 4.22 x 104 kg/m3

= 4220 kg/m3

So the density of the object is 4220 kg/m3.

In summary, by using Newton's second law, Archimedes' principle and definitions of weight, buoyant force and density, we were able to determine the density of the object based on measurements in air and water.

Explanation:

The gauge pressure at the new depth is determined as 3.67 atm.

The gauge pressure at the new depth is calculated by applying the following formula.

The absolute pressure at the new depth  is;

abs P = (1/3) x 14 atm

abs P = 4.67 atm

The gauge pressure at the new depth is calculated as;

Gauge pressure = Absolute pressure at the new depth - Atmospheric pressure

G P = 4.67 atm - 1 atm

G P = 3.67 atm

Therefore, the gauge pressure at the new depth is 3.67 atm.

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On March 21, an equinox occurs where the length of the day and night are equal. An equinox happens when the Earth's axis is not tilted towards or away from the sun. During an equinox, the sun's rays are equally distributed across the Earth's surface.

The word equinox is derived from the Latin words "aequus" and "nox," which means "equal night."

The equinox occurs twice a year, around March 21 and September 21. During an equinox, the duration of day and night is equal across the entire world.

It means that every place on the planet experiences almost the same amount of daylight and darkness.  

On March 21, the vernal equinox, marks the beginning of spring in the Northern Hemisphere, while in the Southern Hemisphere, it marks the beginning of autumn.

The equinox has been considered a significant day in many cultures throughout history. In many cultures, the equinox is celebrated as a time of renewal, rebirth, and fertility. It's also been considered a day of balance, where darkness and light are equal, and the world is in harmony.

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The minimum height (h) of the bag needed to infuse glucose into the vein is approximately 0.1235 meters.

The hydrostatic pressure is given by:

P = ρgh

Where:

P is the pressure,

ρ is the density of the fluid,

g is the acceleration due to gravity, and

h is the height of the fluid column.

Then we will have

h = P / (ρg)

h =[tex](1.21 * 10^3 Pa) / (1.01* 10^3 kg/m^3 * 9.8 m/s^2)[/tex]

h = 0.1235 meters

Therefore, the minimum height (h) of the bag needed to infuse glucose into the vein is approximately 0.1235 meters.

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Answer:

Mass of wood = .209^3 m^3 * 655 kg/m^3 = 5.98 kg

area of wood = ,209^2 = .04368 m^3

.04368 * h * 1000 = 5.98     where h is water displaced

h = .137 m = 13.7 cm

a) distance from wood to water = 20.9 - 13.7 = 7.2 cm

Mass of 7.2 cm of wood (wood out of water)

M = 655 kg /m^3 * .209^2 m^2 * .0072 m = .206 kg

.206 kg of Pb must be added to wood for submersion

We can see here that to briefly describe what is happening for each variable during the identified time periods, you can follow these steps:

A variable is a characteristic, property, or quantity that can vary or change in value. In the context of data analysis, research, or experimentation, variables are used to represent the different factors or elements that are being studied or observed.

Variables can take on different types and play various roles in a study or analysis.

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Answer:

Answer 1: The answer is O 0.178 m/s.

Answer 2: True:  But in this specific case where the Celsius temperature is -40, the Fahrenheit temperature will also be -40.

So, in short, the answer is:

-40 Celsius is equal to -40 Fahrenheit

Answer:

The object in motion is deaccelerating in the negative direction.

Explanation:

Interpret the given position-time graph.

Observing the graph we can determine the slope is negative and is gradually flattening out. Thus, we can conclude the object in motion is deaccelerating in the negative direction.

Kepler's three laws are:

The Newton's three laws of motion is one that how momentum works.

Law 1: If an object is not moving, it will stay still, and if it is moving, it will keep moving in the same way unless something outside of it makes it stop or change direction.

Law 2: When you push or pull on an object, the object's momentum changes. The faster you push or pull, the more the momentum changes.

Law 3: When you push or pull something, it pushes or pulls back with the same amount of force.

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Answer:

Explanation:

Stop. Take a 5-10 minute breather, stretch out like you're doing your pre-workout (warmups). Drink some water, lay down for 3 minutes.

Answer: I hope this helps you

Explanation:

If you experience pain during weight training, it’s important to stop the exercise immediately and assess the source of the pain. If the pain is localized and mild, you can try taking a short break and then continuing with a lighter weight or modified exercise. However, if the pain is severe or spreading, you should stop the workout altogether and seek medical attention as soon as possible. Remember to always listen to your body and use proper form and technique to prevent injury.

The weight of the man is approximately 888.6 Newtons.

The velocity of the train is approximately 10 m/s.

The resultant velocity of the man is 11 m/s.

The train has traveled a distance of 6000 meters in ten (10) minutes.

1.5.1 The weight of the man can be calculated using the formula:

Weight = mass * acceleration due to gravity

Given:

Mass of the man (m) = 90.6 kg

Acceleration due to gravity (g) ≈ 9.8 m/s²

Weight of the man = 90.6 kg * 9.8 m/s² ≈ 888.6 N

Therefore, the weight of the man is approximately 888.6 Newtons.

1.5.2 The velocity of the train in m/s can be converted from its given velocity in km/h. Since 1 km/h is equal to 1000/3600 m/s, we can calculate:

Velocity of the train (v) = 36 km/h * (1000/3600) m/s ≈ 10 m/s

Therefore, the velocity of the train is approximately 10 m/s.

1.5.3 By taking into account the relative motion of the man and the train, it is possible to determine the man's final velocity. The resultant velocity will equal the vector sum of the man's walking velocity and the train's velocity because the man is traveling toward the rear of the train, which is moving eastward.

Given:

Velocity of the man relative to the train (v_man) = 1 m/s (backwards)

Resultant velocity of the man (v_resultant) = v_man + v_train

v_resultant = 1 m/s + 10 m/s = 11 m/s

Therefore, the resultant velocity of the man is 11 m/s.

1.5.4 The distance the train has traveled in ten (10) minutes can be calculated using the formula:

Distance = velocity * time

Given:

Time (t) = 10 minutes = 10 * 60 seconds = 600 seconds

Velocity of the train (v) = 10 m/s

Distance = 10 m/s * 600 seconds = 6000 meters

Therefore, the train has traveled a distance of 6000 meters in ten (10) minutes.

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The amount of heat required to heat the ice from -20 °C to water at 30°C is 238,612 J.

The amount of heat required to heat the ice from -20 °C to water at 30°C is calculated as follows;

Q = Q₁ + Q₂ + Q₃

where;

The amount of heat required to heat the ice from -20 °C to water at 30°C is calculated as;

Q = (0.44 x 4186 x 20) + (3.33 x 10⁵ x 0.44) + (0.44 x 4186 x 30)

Q = 238,612 J

Thus, the total quantity of heat required to raise the temperature of the ice to the liquid is 238,612 J.

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Answer:

a) What is the flow speed in the second section? Assume the pressure remains constant.

Given:

Section 1 area = 10.0 cm^2  

Section 1 flow speed = 293 cm/s

Section 2 area = 3.00 cm^2

Pressure = 1.20 x 105 Pa (constant)

Since pressure remains constant, by Bernoulli's equation:    

P1/ρ + 1/2*v12 = P2/ρ+ 1/2*v22

Since P1 = P2 and ρ (density) is constant:

v22 = 2*(v12 - v22)    

v22 = 2*(293^2 - v22)

Solving for v2:    

v2 = √(2*293^2) = 846 cm/s

b) What is the kinetic energy loss per second between the two sections?

Kinetic energy = 1/2 * mass * velocity^2

Mass flow rate = density * area * velocity

= 1.65 g/cm^3 * 10.0 cm^2 * 293 cm/s = 485.5 g/s

Kinetic energy loss = 1/2 * (485.5 g/s) * (293^2 - 846^2) cm^2/s^2        

            = 1/2 * (485.5)*(86124 - 716256)

            = 20617 J/s

So the kinetic energy loss per second between the two pipe sections is 20617 J/s.

Explanation:

The magnitude of the angular acceleration of the roller is approximately 104.2 rad/s^2.

The magnitude of the angular acceleration of the roller can be determined using the torque equation and Newton's second law for rotational motion.
Step 1: Calculate the moment of inertia of the roller.
The moment of inertia (I) of a solid cylinder is given by the formula I = (1/2) * m * r^2, where m is the mass of the object and r is the radius.
In this case, the mass of the roller is 2.4 kg and the radius is 0.038 m.
So, I = (1/2) * 2.4 kg * (0.038 m)^2.
Step 2: Calculate the torque applied to the roller.
Torque (τ) is equal to the force (F) applied multiplied by the perpendicular distance (r) from the axis of rotation.
In this case, the force applied by Joe is 16 N and the distance is equal to the radius of the roller, 0.038 m.
So, τ = F * r.
Step 3: Use the torque equation.
The torque applied to the roller causes an angular acceleration (α) according to the equation τ = I * α.
Rearranging the equation, we get α = τ / I.
Step 4: Substitute the values into the equation.
Using the values we calculated earlier, we can substitute them into the equation α = τ / I.
α = (16 N * 0.038 m) / [(1/2) * 2.4 kg * (0.038 m)^2].
Step 5: Calculate the magnitude of the angular acceleration.
Evaluating the expression, we find that the magnitude of the angular acceleration of the roller is approximately 104.2 rad/s^2.
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The distance traveled by the rollercoaster during the deceleration is 16.1 m.

The distance traveled by the rollercoaster during the deceleration is calculated by applying the following formula.

v² = u² + 2as

where;

When the rollercoaster stops, the final velocity, v = 0

0 = u² + 2as

-2as = u²

s = u² / -2a

s = (15 m/s) ² / (-2 x - 7 m/s²)

s = 225 / 14

s = 16.1 m

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Answer:

the density of the cube is approximately 2016.07 kg/m^3.

Explanation:

The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

Let's first calculate the weight of the crate:

mass of crate = density * volume = density * (side length)^3 = density * 0.25^3 = 0.015625 * density

weight of crate = mass of crate * gravity = 0.015625 * density * 9.81 = 0.1530875 * density

where gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2.

Since the crate is submerged in water, the buoyant force acting on it is:

buoyant force = weight of water displaced = density of water * volume of water displaced * gravity

The volume of water displaced is equal to the volume of the cube, which is 0.25^3 = 0.015625 m^3. Therefore, the buoyant force is:

buoyant force = 1000 kg/m^3 * 0.015625 m^3 * 9.81 m/s^2 = 1.534453125 N

According to the problem, it takes 310 N to lift the crate while it is still submerged. This means that the net force acting on the crate is:

net force = lifting force - buoyant force = 310 N - 1.534453125 N = 308.465546875 N

This net force is equal to the weight of the crate:

net force = weight of crate = 0.1530875 * density

Therefore, we can solve for the density of the crate:

density = net force / 0.1530875 = 308.465546875 / 0.1530875 = 2016.06666667 kg/m^3

Rounding to the nearest hundredth, we get:

density ≈ 2016.07 kg/m^3

Therefore, the density of the cube is approximately 2016.07 kg/m^3

Answer:

Certainly! We can use the formula:

q = mcΔT

where q is the amount of heat absorbed, m is the mass of the aluminum bar, c is the specific heat capacity of aluminum, and ΔT is the change in temperature.

Substituting the given values, we get:

4.73 kJ = (0.525 kg) x c x (10.0°C)

Solving for c, we get:

c = 0.901 kJ/kg · °C

Therefore, the specific heat of aluminum is 0.901 kJ/kg · °C.

Explanation:

The circled vectors represents acceleration.

The last option is correct.

We see in the  first motion diagram the length of velocity vector is increasing this shows that the velocity is increasing in the magnitude with time so this is an accelerated motion in which a uniform acceleration must be in the same direction of velocity must be there.

We also notice in the second motion diagram the length of velocity vector is decreasing with time which shows the velocity is decreasing me magnitude which shows a constant deceleration and the direction of acceleration must be opposite to that of velocity.

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