31. Divide 4.2 × 10³ m/s by 0.57 ms, and express your answer in m/s².
The acceleration of the given is a = 7.368 × 10³ m/s².
Equation :To calculate the equation we use acceleration formula,
So,
a = Δv/Δt
where,
a is acceleration
Δv is velocity
Δt is time
Now putting the values,
We get,
a = 4.2 × 10³ m/s / 0.57 s
a = 7.368 × 10³ m/s²
What is the speed-time graph acceleration formula?The particle's acceleration is represented by the gradient of the line of the speed-time graph (for straight lines acceleration is constant). Line gradient = change in velocity, time = v ut = a. Line gradient is equal to the change in velocity over time, or v u t, or a. The distance traveled by a particle is indicated by the area under the speed-time graph.
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What are five different types of objects that orbit the sun in the solar system?
Need help answering these problems
The acceleration is obtained from the net force and the mass of a body.
What is the force?According to the Newton second law, we know that force is the product of the mass and the acceleration of a body. Given the fact that the force applied on the body is in opposite direction to the friction, we can be able to obtain the friction from the images shown in the problem.
In the first case;
Force = mass * acceleration
acceleration= force/mass
acceleration= 175 N/50 = 3.5 m/s^2
In the seconds case;
Net force = 330 N - 196 N = 134 N
acceleration= force/mass
acceleration= 134 N/200 Kg = 0.67 m/s^2
In the third case;
Net force = 373 N - 147 N = 226 N
acceleration= force/mass
acceleration= 226 N/50 Kg
= 4.52 m/s^2
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A car travels 500 km in 4 hours. Another car travels the same 500 km in 5 hours. The cars have the same
A . Acceleration
B . Speed
C . Average Velocity
D . Displacement
A car traveling 500km in 4 hours and another car traveling 500km in 5 hours, both the cars have the same displacement. Thus, the correct option is D.
What is Displacement?The displacement is a vector quantity because is has both the magnitude and direction. Displacement is the quantity whose length is the shortest distance from the initial position to the final position of a point which is undergoing motion. Displacement quantifies both the distance and direction of the net or the total motion of an object along the direction of a straight line from the initial position to the final position of the point trajectory of the object. A displacement may be identified with the translation which maps the initial position to the final position of an object.
A displacement may be also described as a relative position, that is, as the final position of an object relative to its initial position. The corresponding displacement vector can be defined as the difference between these two that is the final position and initial position of the object.
Therefore, the correct option is D.
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10. A 4.5 kg block is pulled across a horizontal surface that has a
coefficient of kinetic friction of 0.40. a). Draw a free-body diagram that
includes the vertical and horizontal forces. b) What is the normal force? c)
What is the force of friction exerted by the surface on the block? d). If the
block is pulled by a 25 N force, what is the net force acting on the block?
e). What is the acceleration of the block? Be sure to draw
The acceleration is 4.24 m/s² and the force of friction is 17.64.
Equation :To calculate normal force,
use formula,
F = ma
where,
F is normal force
m is mass
a is acceleration due to gravity
Given,
m = 4.5kg
a = 9.8 m/s²
F = 4.5 kg x 9.8 m/s²
F = 44.1 N
Now, as we calculate the normal force
To calculate the force of friction
Using the formula,
μ = N / F
where,
μ is coefficient of friction
N is force due to friction
F is normal force
Given,
μ = 0.40
F = 44.1 N
So, putting values,
We have,
0.40 = N / 44.1
N = 0.40 x 44.1
N = 17.64
Net force = F - Fₙ
So,
Net force = 44.1 N - 25 N
Net force = 19.1
Now we know the net force so to calculate acceleration
Using formula,
F = ma
a = F / m
a = 19.1 / 4.5
a = 4.24 m/s²
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ASAP!!! will give brainlest!
A stone is dropped into a deep well and hits the water 2.41 s after being dropped. Determine the depth of the well. Use g = -10 m/s/s and enter your answer as a POSITIVE number since it is asking for the depth of the well and not how far the stone fell. ROUND your answer to the nearest tenth.
A race car rounds a curve at 55 m/s. The radius of the curve is 434 m, and the car's mass is 685 kg. (Assume the car's speed remains constant. Take the radially inward direction to be positive. Indicate the direction with the sign of your answer.)
(a) What is the car's (centripetal) acceleration?
______m/s2
What is it in g's?
____g
(b) What is the centripetal force acting on the car?
____N
PLEASE HELP!!!
The car's (centripetal) acceleration would be 6.97 meters / second², its value in terms of acceleration due to gravity would be 0.71 g and the centripetal force acting on the car would be 4774.5 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem a race car rounds a curve at 55 m/s. The radius of the curve is 434 m, and the car's mass is 685 kg. (Assume the car's speed remains constant. Take the radially inward direction to be positive.
The centripetal acceleration of the car = v² / r
=55² / 434
= 6.97 meters / second²
The centripetal force acting on the car = m×v² / r
=685× 6.97
=4774.50 Newtons
Thus, the centripetal force acting on the car would be 4774.5 Newtons.
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What size force accelerates a 0.010 kg bullet from a rest to a speed of 1100 m/s in a distance of 1 meter?
The force that accelerates a 0.010 kg bullet from rest to a speed of 1100 m/s in a distance of 1 meter is 11 newton.
What is force?Force is the entity that changes the motion of an object. It is calculated by multiplying the mass by acceleration.
Mass is the weight of an object per unit. Acceleration is a change in the rate of velocity.
F = ma
The mass is 0.010 kga change
convert into grams = 10 grams
The acceleration is 1100 m/s
putting the value in the formula
1100 x 10 = 11, 000
convert into kg = 11
Thus, the size force accelerates is 11 N.
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What do these changes have in common rain forming in a cloud and water evaporation
Answer:
Both of these involve water changing states.
Explanation:
Clouds forming rain is water changing from a gas to a liquid and evaporation is water changing from a liquid to a gas.
what is the density of copper if 21.4 g of it occupies 2.40 cm3
Answer:
D=157g/12cm cubed
Explanation:
D=M/V
D=)21.4)g(/2.40)cm cubed
D=157g/12cm cubed
Need help with my homework assignment. Thank you!
According to research, development is always towards complexity.
What is the meaning of research?The term research has to do with the process that we have to go through to obtain new knowledge or to confirm a piece of information. Let us say that we have some disconnected pieces of evidence that tend to point towards a particular fact, we would need to use the process of research to establish the truth in the research.
Now we can see that there is a movement towards the complexity of organisms at each particular level in the developmental process. We can then conclude that according to research, development is always towards complexity.
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Which of the following is NOT one of the functions of glial cells?
Select one:
O a. They provide nourishment to neurons.
O b. They help repair damage that might occur to neurons.
O c. They nourish nerve cells.
Od. They communicate messages within the nervous system.
Answer:
D they communicate messages within the nervous system.
Explanation:
just feel it's D
Answer:
The answer to this question is D. They communicate messages within the nervous system.
1) A satellite in orbit around Earth is in uniform circular motion. What is the angle between the velocity vector and acceleration vector at any given point on the orbit?(1 point)
0º
0º
45º
45º
180º
180º
90º
2) A hammer thrower spins a hammer in a circle. What happens when the centripetal force drops to 0?(1 point)
The centripetal force cannot drop to 0.
The centripetal force cannot drop to 0.
The hammer continues in the circular motion.
The hammer continues in the circular motion.
The hammer drops straight to the ground.
The hammer drops straight to the ground.
The hammer flies off at a tangent to its circular path.
3) A bike racer follows a circular indoor track, racing at constant speed. In what direction is their acceleration, and why?(1 point)
In the direction of motion, accelerating their speed.
In the direction of motion, accelerating their speed.
Counter to the direction of motion, keeping her speed constant.
Counter to the direction of motion, keeping her speed constant.
Inward to the center of the track, the direction of the force needed to keep her on this path.
Inward to the center of the track, the direction of the force needed to keep her on this path.
Outward, the direction she would go if not constrained by the track.
4)A diagram shows the velocity vector for an object in uniform circular motion. Why is the vector tangential to the circle?(1 point)
The vector approximates the curved path at that point.
The vector approximates the curved path at that point.
The vector indicates the direction of the force on the object.
The vector indicates the direction of the force on the object.
The vector shows the path the object would follow if the net force acting on it stopped.
The vector shows the path the object would follow if the net force acting on it stopped.
The vector shows how the object pulls against the centripetal force.
5) A satellite is in uniform circular motion around the Moon. What happens to the direction of the acceleration vector during one full orbit?(1 point)
The acceleration vector always points in the direction of motion.
The acceleration vector always points in the direction of motion.
The acceleration vector always points outward.
The acceleration vector always points outward.
The acceleration vector oscillates back and forth.
The acceleration vector oscillates back and forth.
The acceleration vector always points inward.
Answer:90
Explanation: bc i looked it up
Would "throwing" the picket fence up or down prior to its passing through the photogate affect the experimentally deter-
mined g value?
If you throw the picket fence down instead of dropping it, the graphs and values will change due to forces other than gravity acting on it. When you throw it, gravity works against it, so they change too, and eventually return tends to decrease. acceleration due to gravity by quadratic curve fitting for the given data is 9.726 m/s2.
The purpose of this exercise was to measure the acceleration of a free-falling object using the slope of a velocity versus time plot. If you drop the picket fence from the same height each time, the photogate will read a slope of 9.8 each time.
The photogate has a beam of infrared light that moves left and right. You can detect whenever that beam is blocked. They drop clear plastic strips with evenly spaced black bars called picket fences. As the mass of an object increases, the object's acceleration decreases.
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They drop picket fences, which are clear plastic strips with neatly spaced black bars. The acceleration of an item decreases as its mass increases.
The photogate emits an infrared light beam that travels left and right. When the beam is obstructed, you can detect it. The graphs and numbers will vary if you fling the picket fence down instead of dropping it owing to factors other than gravity acting on it. Gravity works against it as you toss it, thus they vary as well, and ultimately return tends to diminish. For the given data, the acceleration due to gravity calculated using quadratic curve fitting is 9.726 m/s2.
The goal of this exercise was to use the slope of a velocity vs time plot to calculate the acceleration of a free-falling object. If you drop the picket fence from the same height each time, the photogate will always report a slope of 9.8.
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As a 2.0-kg block travels around a 0.50-m radius circle it has an angular
speed of
12 rad/s. The circle is parallel to the xy plane and is centered on the z axis, a
distance of 0.75m from the origin. The z component of the angular
momentum
around the origin is:
The z component of the angular momentum around the origin is 9 kg-m²/s.
What is angular momentum?
Angular momentum is the property of any rotating object given by moment of inertia times angular velocity.
The z component of the angular momentum around the origin is is calculated as follows;
L = mvr
where;
m is the massv is the linear speedr is the distance from the originv = ωr
where;
ω is angular speed = 12 rad/sr is radius of the circlev = 12 rad/s x 0.5 m
v = 6 m/s
Substitute the given parameters' and solve for the z component of the angular momentum around the origin is;
L = (2 kg) x (6 m/s) x (0.75 m)
L = 9 kg-m²/s
Thus, the z component of the angular momentum around the origin is 9 kg-m²/s.
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Answer: 6.0
Explanation:
v = 0.5 * 12 = 6
l = m * r *v
l = 2 * 0.5 * 6
l= 6
Find the average speed from home plate to second base in 8.2 seconds, using the 60 feet for base distance
The correct answer is 2.9 m/s.
Average speed combines two concepts into a single word: speed, which is a change in position, and average, which refers to a mean determined from many different data points.
By dividing the distance an object travels in one unit by the amount of time it takes to travel that distance, one may determine the speed of the object. The speed of the item on this voyage, denoted by the letter "s," is equal to s = D/T if "D" is the distance traveled in some time "T."
Given,
time = 6.2 seconds
distance = 60 feet
speed = distance/time
speed = 60/6.2
speed = 9.67 feet/s
speed = 2.9 m/s
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5. Look at Figure 7.8 which shows Rigan touching the negatively charged dome of an instrument called the Van de Graaff generator. a) Why did Rigan have to stand on a plastic chair?
Answer:
Rigan stood on a plastic chair to provide insulation between Rigan and the environment.
If Rigan was connected electrically to the environment, then no net charge would be accumulated by Rigan and no effect would be noted.
A runner is jogging in a straight line at a steady v, 3.5 km/hr. When the runner is L= 3.1 km from the finish line, a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr (5 times as fast as the runner). When the bird reaches the finish
line, it turns around and flies directly back to the runner. finish line What cumulative distance does the bird travel? Even though the bird is a dodo, assume that it occupies only one point in space (a "zero" length bird), travels in a straight line, and that it can turn without loss of speed.Answer in units of km.
If a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr, the bird would reach the finish line in 10 minutes and 37.71 seconds.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
As given in the problem A runner is jogging in a straight line at a steady v, 3.5 km/hr. When the runner is L= 3.1 km from the finish line, a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr (5 times as fast as the runner).
The time is taken by the bird to reach the finish line = 3.1 km /17.5 km/hour
=0.177 hours
= 10 minutes 37.71 seconds
Thus, the bird would reach the finish line in 10 minutes and 37.71 seconds.
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What is centripetal force used for?
Centripetal force is used for making an object move in a circular path.
What is centripetal force?Centripetal force is the force on a rotating or orbiting body in the direction of the centre of rotation.
In other words, centripetal force is the force that makes an object move in a circular pattern.
Centripetal force is denoted by "F" and can be calculated by dividing the product of the mass and velocity squared by radius as follows:
F = mv²/r
Where;
F = forcem = massv = velocityr = radiusTherefore, it can be said that Centripetal force is used for making an object move in a circular path.
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PHYSICS : MODULE 01 GALILEO GARDENS : 01.02 GRAPHING DATA
Graphing Activity
Let’s take another look at the experimental data given to you in the exploratory activity. Graph the data once again, applying the knowledge and skills you have learned.
Procedure:
Table 1 shows some data that Rafael and Cristine collected during an experiment to measure the stretch of a spring as more force was applied.
Graph the data from Table 1 on your graph paper. Do not use a graphing program.
The experimental value of the expression due to gravity through the experiment will come out to be 8.41u, the error in the value has Accord because of air friction.
What is acceleration due to gravity?Acceleration due to gravity is a form of acceleration that is exercised by the gravitational pull of the earth its value is fixed at the surface n is equal to 9.8u.
What is air friction?Aries composed of molecules and their food when an object passes through air strikes the a molecules they are molecules according to Newton's third law strike back at the object therefore reducing its speed. This force by the molecule is known as air friction.
The setup of the given experiment consists of:
A bob of mass m
A stopwatch with high accuracy
An inch tape
A speedometer
Experiment is conducted in the following manner:
First the bob will be released and from the point that it is being released we will measure the distance using the inch tape we will also calculate the time it takes for the bob to hit the ground.Using the speedometer will measure the final velocity before it is the ground.Now using Newton's first law of motion we can derive the acceleration due to gravity we know the final velocity using the speedometer the distance it has covered and the time it has taken to complete that distance.Using Newton's first law of motion
i.e. v = u + a × t
Where,
u is initial velocity
v is final velocity
a is acceleration due to gravity
t is time taken to cover distance
From the data given v = 16.82m/s
t is 2 seconds
Substituting value in Newton's first law of motion we get
Value of acceleration due to the gravity = 8.41
Therefore, The experimental value of the expression due to gravity through the experiment will come out to be 8.41u, the error in the value has Accord because of air friction.
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You are conducting an experiment to find out whether the time a person wakes up affects his or her
mood. You have one third of your participants wake up at 6:00, another third at 7:00, and another
third at 8:00. Then you give a questionnaire to them to determine their mood.
What is the independent variable and what is the dependent variable in this experiment?
The dependent and the independent variable in this experiment is mood and time, respectively.
What are Independent and dependent variables?The Independent variables are that variables whose value does not depend on any other variable. And it causes the change in other variables.
The dependent variable is those variables whose value is not independent and change in this variable is dependent on the change of the independent variable.
Given that You are conducting an experiment to find out whether the time a person wakes up affects his or her mood. Therefore, we want to know whether the mood of a person is dependent on the time he or she wakes up or not.
Now, since mood is dependent on time, therefore, mood is the dependent variable in the experiment and time is the independent variable in the experiment.
Hence, the dependent and the independent variable in this experiment is mood and time, respectively.
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Which graph below represents how the velocity of the sphere changes over time when falling with constant acceleration?
Justify your choice.
Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.
Acceleration is the measure of how quickly a body's velocity varies with regard to time, and constant acceleration occurs when a body's velocity changes proportionately over a period of time, or at a constant rate. It measures in m/s2.It is claimed that a body has continual positive acceleration when it begins to move with an initial velocity of zero and gradually increases to a positive value over time.Constant positive acceleration is demonstrated by a ball falling freely in a vertical direction.To know more about constant acceleration. visit : brainly.com/question/9754169
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a body of mass 12.0kg is placed on an orange tree 13m above the ground. .....1. calculate the potential energy .......2. if the body is released from this height what will be the kinetic energy just before it hits the ground.(g = 10 m/s)
Answer:
Given , mass = 12.0kg
height = 13m
acceleration due to gravity = 10m/s
1.ans
Potential energy = mass×acceleration due to gravity×height
Potential energy = 12kg×10m/s×13m
Potential energy = 1,560J
2.ans
Remember this when a body is above the ground potential energy is equal to kinetic energy.
Potential energy = kinetic energy
kinetic energy = ½× mass×(velocity)²
1560J = ½×12kg×v²
1560J = 6kg× v²
1560kgms-2 - 6kg = v²
v² = 1,554m/s²
K.E = ½×m×v²
K.E =( ½)(12kg)(1,554m/s²)
K.E = 9,324J
what are harmful micro-organismo and what are useful micro products
Answer:
Microorganisms are used in various industries for the production of various metabolites such as ethanol, riboflavin, lactic acid, and butanol. There are a number of microorganisms that are responsible for food spoilage, diseases and infections. Such microorganisms are known as harmful microorganisms
Explanation:
A person 1.8 m tall is photographed with a 35-mm camera, and the film image is 20 mm. Under the same conditions, how tall is a person whose film image is 16 mm?
Under the same conditions, the height of a person whose film image is 16 mm is 1.44 m.
What is magnification of a lens?
The magnification of a lens is defined as the ratio of the height of an image to the height of an object.
The formula for magnification of a lens is given as;
M = v/u = hi/h
where;
v is image distanceu is object distance hi is image heighth is object heightUnder the same conditions, the height of a person whose film image is 16 mm is calculated as follows
M = 20 mm / 1.8 m = 16 mm/h
20 mm / 1.8 m = 16 mm/h
h = (16 mm / 20 mm) x 1.8 m
h = 1.44 m
Thus, under the same conditions, the height of a person whose film image is 16 mm is 1.44 m.
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What is the direction
Answer:
Explanation:
[tex]tan^{-1} (4/3) = 53.3[/tex]
If the velocity versus time graph of an object is a horizontal line the object is
If an object's velocity versus time graph is a horizontal line the object is travelling at constant velocity which means the object is not accelerating at all.
the gravitation force between any two building is negible ? why
It is true that between any two massive bodies. But, the masses of building and a person are very very small as compare to planets and stars. Hence, the gravitational pull is very weak, comparatively negligible.
Answer:
Yes they are negligible
Explanation:
Why- The gravitational force between 2 massas is independent of their sizes or distribution of mass of the bodies. The gravitational force between 2 bodies does not depend upon the presence or the absence of other bodies. If the masses of the body are small, the gravitational force between them is negligible.
What in front of a car does NOT absorb substantial force?
A- airbag
B- windshield
C- bumper
D- engine
The front of a car which does not absorb substantial force is referred to as engine and is denoted as option D.
What is Force?This is referred to as an external agent which could be in the form of push or pull and is capable of influencing the motion of an object or a body. The formula of force can be seen below:
F = ma where m is mass and a is acceleration
The engine of a car is contained in a compartment in the bonnet and has less substantial force acting on it while the remaining options are exposed to various types of forces.
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a) d = 24 g/mL
v = 1.2 L =
m=? 28.1
? 23.03
mL
Density calculations are 1.2L = 1200mL m = 2.9 x 10^4 g
Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimetre are a typical unit of measurement for density. Another way to state density is in kilogrammes per cubic metre (in metre-kilogram-second or SI units).
For instance, air weighs 1.2 pounds per cubic metre. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated. The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).
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