The binding energy per nucleon for silver-109 is 1.285 × 10⁻¹¹ kJ/mol.
In order to calculate the binding energy per nucleon, which is expressed in units of energy per mole of nuclei (kJ/mol), we need to use the following equation:
BE/A = (Δmc²)/A
where BE/A is the binding energy per nucleon, Δm is the mass defect (the difference between the actual mass of the nucleus and the sum of the masses of its constituent nucleons), c is the speed of light, and A is the mass number (the total number of protons and neutrons) of the nucleus.
The atomic mass of silver-109 is 108.90585 g/mol, so its mass number is 109. We also have the required masses of its constituent nucleons, which are 47 for protons and 62 for neutrons.
Using the atomic masses of silver-109 and its constituent nucleons, we can calculate the mass defect as follows:
Δm = (108.90585 g/mol - (47 × 1.007825 g/mol + 62 × 1.008665 g/mol)) = 0.008601 g/mol
where 47 and 62 are the numbers of protons and neutrons in the nucleus, respectively.
Converting the mass defect to energy using Einstein's famous equation E = mc² we get:
ΔE = Δmc² = (0.008601 g/mol) × (299792458 m/s)² = 7.732 × 10⁻⁴ J/mol
Finally, we convert the energy per nucleus to energy per mole of nuclei and then to kilojoules per mole by dividing by the Avogadro constant and multiplying by 10⁻³:
BE/A = ΔE/A × N_A × 10⁻³ = (7.732 × 10⁻⁴ J/mol)/(6.022 × 10²³ mol⁻¹) × 10⁻³ = 1.285 × 10⁻¹¹kJ/mol
Therefore, the binding energy per nucleon for silver-109 is 1.285 × 10⁻¹¹kJ/mol.
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what is the no.of moles of o-atoms in 126amu of hno3
There are 6 moles of O-atoms in 126 amu of HNO3.
To find the number of moles of O-atoms in 126 amu of HNO3, we need to first calculate the number of moles of HNO3 in 126 amu and then multiply it by the number of O-atoms per molecule of HNO3.
The molecular weight of HNO3 is 63 g/mol (1+14+48=63), which means that 1 mole of HNO3 has a mass of 63 g. To find the number of moles of HNO3 in 126 amu, we divide 126 by the molar mass of HNO3:
126 amu / 63 g/mol = 2 moles
So, there are 2 moles of HNO3 in 126 amu.
Each molecule of HNO3 contains 3 O-atoms, so the total number of O-atoms in 2 moles of HNO3 is:
2 moles x 3 O-atoms/mole = 6 moles of O-atoms
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calculate the ph of an acetate buffer that is a mixture of equal volumes of 0.33 m acetic acid and 0.15 m sodium acetate.
The pH of the acetate buffer solution, which is a mixture of equal volumes of 0.33 M acetic acid and 0.15 M sodium acetate, is approximately 4.42.
To calculate the pH of an acetate buffer solution, we can use the Henderson-Hasselbalch equation;
pH = pKa + log([A⁻]/[HA])
where; pH is the pH of the buffer solution
pKa will be the acid dissociation constant of the weak acid (acetic acid in this case)
[A⁻] will be the concentration of the conjugate base (acetate ion)
[HA] will be the concentration of the weak acid (acetic acid)
Given; Concentration of acetic acid (HA) = 0.33 M
Concentration of sodium acetate (A⁻) = 0.15 M
We need to determine the pKa of acetic acid to proceed. The pKa value of acetic acid is 4.76.
Now, let's substitute the given values into the Henderson-Hasselbalch equation;
pH = 4.76 + log(0.15/0.33)
pH = 4.76 + log(0.4545)
To calculate the pH, we can evaluate the logarithm;
pH = 4.76 + (-0.343)
pH ≈ 4.42
Therefore, the pH of the acetate buffer solution will be 4.42.
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An element has 2 stable isotopes. One has 13 amu and 1. 07% abundant. The second has 12 amu and 98. 93 abundant. What is the average atomic mass?
The average atomic mass of this element is 12.0107 amu.Therefore, the average atomic mass of this element is 12.0107 amu.
To find the average atomic mass, we need to take into account the abundance and mass of each isotope. We can use the following formula:
Average atomic mass = (abundance of isotope 1 x mass of isotope 1) + (abundance of isotope 2 x mass of isotope 2)
Plugging in the values given in the question, we get:
Average atomic mass = (0.0107 x 13) + (0.9893 x 12)
Average atomic mass = 0.1391 + 11.8716
Average atomic mass = 12.0107 amu
Therefore, the average atomic mass of this element is 12.0107 amu.
To calculate the average atomic mass of an element with two stable isotopes, you need to multiply the mass of each isotope by its abundance (in decimal form) and then add the results together. Here's the calculation:
Isotope 1: 13 amu * 0.0107 = 0.1391
Isotope 2: 12 amu * 0.9893 = 11.8716
Average atomic mass = 0.1391 + 11.8716 = 12.0107 amu
So, the average atomic mass of this element is 12.0107 amu.
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The process in which a nucleus spontaneously breaks down by emitting radiation is known as ______. A) transformation. B) translation. C) fusion
The process in which a nucleus spontaneously breaks down by emitting radiation is known as radioactive decay.
During this process, the unstable nucleus emits radiation in the form of alpha particles, beta particles, or gamma rays until it becomes stable. Radioactive decay is a random process and occurs at a specific rate, known as the half-life, which varies for each radioactive substance.
This process is used in many applications, including carbon dating and medical imaging. It is important to note that fusion and transformation are not related to radioactive decay, as they refer to the process of combining two nuclei to form a heavier nucleus and the process of changing one element into another, respectively. Answering more than 100 words, we can say that radioactive decay is a fundamental process that helps us understand the behavior of atoms and how they change over time.
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how much potassium hydroxide is needed to make 1.00 liter of a 1 molar solution of potassium hydroxide ?
we need 56.11 grams of KOH to make 1.00 liter of a 1 molar solution of potassium hydroxide.
To make a 1 molar solution of potassium hydroxide (KOH), we need to dissolve enough KOH in water to make a solution where the concentration of KOH is 1 mole per liter of solution. The molarity (M) is defined as the number of moles of solute (KOH in this case) per liter of solution, so we can use this equation:
M = moles of solute / liters of solution
We can rearrange this equation to solve for the moles of solute:
moles of solute = M x liters of solution
Since we want to make 1.00 liter of a 1 molar solution of KOH, we can substitute those values into the equation:
moles of solute = 1.00 mol/L x 1.00 L = 1.00 mol
So we need 1.00 mole of KOH to make 1.00 liter of a 1 molar solution. To find the mass of KOH needed, we need to use its molar mass:
KOH molar mass = 39.10 g/mol (for K) + 16.00 g/mol (for O) + 1.01 g/mol (for H) = 56.11 g/mol
So, the mass of KOH needed to make 1.00 liter of a 1 molar solution is:
mass of KOH = moles of KOH x molar mass of KOH
= 1.00 mol x 56.11 g/mol
= 56.11 g
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demonstrate and record observations of how potassium permanganate decomposes into elements by heating. record what you observe .please help question 1-7
When heated, potassium permanganate (KMⁿO4) decomposes into:
potassium manganate (K2MⁿO4)manganese dioxide (MⁿO2)oxygen (O2).How does potassium permanganate decompose when heated?Potassium permanganate is a strong oxidizing agent that decomposes when heated and releases oxygen gas. The reaction is observed by placing small amount of potassium permanganate in a test tube and gently heating it over a Bunsen burner.
As the temperature increases, the purple color of the potassium permanganate fades and brown-black manganese dioxide is formed. Oxygen gas can be seen bubbling out of the test tube and can be confirmed with a glowing splint test.
After the reaction is complete, the residue left in the test tube is potassium manganate which can be identified by its green color.
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write a balanced nuclear equation for the following: the nuclide polonium-218 undergoes alpha emission to give lead-214 .
The balanced nuclear equation for the alpha decay of polonium-218 to give lead-214 is,
[tex]^218Po[/tex] -> [tex]^214Pb[/tex] + [tex]^4He[/tex]
How to balance the nuclear equation?In the given nuclear equation, the nuclide polonium-218 (symbolized as [tex]^218Po[/tex]) undergoes alpha emission, which means it releases an alpha particle. An alpha particle consists of two protons and two neutrons, which is symbolized as [tex]^4He[/tex].
After the alpha emission, the resulting nuclide is lead-214 (symbolized as [tex]^214Pb[/tex]). Lead-214 is formed by subtracting the alpha particle ([tex]^4He[/tex]) from the original polonium-218 nucleus.
Overall, the nuclear equation represents the radioactive decay process where polonium-218 emits an alpha particle, resulting in the formation of lead-214.
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kim bought some fireworks to shoot off on the 4th of july. she noticed several different powders mixed together in the tube. as the fireworks were ignited, what evidence best indicates a chemical reaction had occurred?
The best evidence that a chemical reaction occurred during the ignition of fireworks is the release of light, heat, and new colored substances.
When fireworks are ignited, several chemical reactions take place that result in the release of energy in the form of light, heat, and the formation of new substances. The different colored powders mixed together in the tube contain metal salts, which produce specific colors when heated.
As the heat energy causes these metal salts to react, they release energy in the form of light and heat, producing the bright and colorful display we associate with fireworks. Additionally, the formation of new substances, such as gases and solid particles, is a key indicator that a chemical reaction has taken place during the ignition of the fireworks.
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Directly following reflux the reaction mixture needs to be filtered while warm. Why?
The reaction mixture needs to be filtered while warm after reflux because the product may solidify and become difficult to filter if left to cool.
During reflux, the reaction mixture is heated to boiling and maintained at that temperature for a period of time. This process can cause the product to dissolve in the solvent and react with other components in the mixture. After reflux, the reaction mixture needs to be filtered to separate the solid product from the solvent and other components.
Filtering the mixture while it is still warm prevents the product from solidifying and becoming difficult to filter. If left to cool, the product may form crystals that clog the filter and slow down or even stop the filtration process. By filtering the mixture while it is still warm, the product remains in a liquid state and is easier to separate from the rest of the mixture. This ensures that the product is obtained in the desired form and purity.
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nitrogen boils at -196°c. what is the corresponding temperature in the fahrenheit scale?
To convert -196°C to Fahrenheit, you can use the formula: F = (C x 1.8) + 32. Plugging in -196 for C, you get:
F = (-196 x 1.8) + 32
F = -320.8
Therefore, nitrogen boils at -320.8°F. It's important to note that Fahrenheit and Celsius scales have different zero points and different degrees of size. This means that -196°C is a much lower temperature than -320.8°F, as the Fahrenheit scale has a smaller degree of size. This conversion is useful for comparing temperatures across different measurement systems, and for understanding the temperature ranges of different substances and materials.
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Calculate the freezing point and boiling point of a solution containing 10.6 g of naphthalene (C10H8) in 114.0 mL of benzene. Benzene has a density of 0.877 g/cm3.
Calculate the freezing point of a solution. (Kf(benzene)=5.12?C/m.)
Calculate the boiling point of a solution. (Kb(benzene)=2.53?C/m.)
First, we need to calculate the moles of naphthalene and benzene in the solution:
Molar mass of naphthalene (C10H8) = 128.17 g/mol
Moles of naphthalene = 10.6 g / 128.17 g/mol = 0.0827 mol
Density of benzene = 0.877 g/cm3 = 0.877 g/mL
Volume of benzene = 114.0 mL
Mass of benzene = Density x Volume = 0.877 g/mL x 114.0 mL = 99.9 g
Molar mass of benzene = 78.11 g/mol
Moles of benzene = 99.9 g / 78.11 g/mol = 1.28 mol
Next, we can use the freezing point depression equation and boiling point elevation equation to calculate the respective temperature changes:
ΔTf = Kf x molality
molality = moles of solute / mass of solvent (in kg)
molality = 0.0827 mol / 0.0999 kg = 0.827 m
ΔTf = 5.12°C/m x 0.827 m = 4.23°C
Freezing point of solution = freezing point of pure benzene - ΔTf = 5.5°C - 4.23°C = 1.27°C
ΔTb = Kb x molality
ΔTb = 2.53°C/m x 0.827 m = 2.09°C
Boiling point of solution = boiling point of pure benzene + ΔTb = 80.1°C + 2.09°C = 82.19°C
Therefore, the freezing point of the solution is 1.27°C and the boiling point is 82.19°C.
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the ph of a 0.30 m solution of a weak base is 10.66. what is the kb of the base?
The pH of a 0.30 M solution of a weak base is 10.66. We can use this information to calculate the pOH of the solution, which is the negative logarithm of the hydroxide ion concentration. The pOH can then be used to calculate the pKb, which is the negative logarithm of the base dissociation constant, Kb. By taking the antilog of the pKb value, we can determine the value of Kb for the weak base.
To calculate the pOH of the solution, we use the equation: pOH = 14 - pH. Therefore, pOH = 14 - 10.66 = 3.34. Using the relationship between pOH and Kb, we have pKb = 14 - pOH = 10.66. Taking the antilog of pKb, we have Kb = 2.5 x 10^-4.
Therefore, the Kb of the weak base in the 0.30 M solution is 2.5 x 10^-4. This value indicates the strength of the base as a proton acceptor in solution. A higher value of Kb indicates a stronger base, which means it is more likely to accept a proton from water and generate hydroxide ions. The calculation of Kb is an essential step in understanding the properties of weak bases and their behavior in solution.
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Symbols such as (s) or (aq) written in parentheses next to an atom, ion, or a compound indicate f 1.00 Select one: Flag O a. the charge of the atom, ion, or compound. b. the physical state of the atom, ion, or compound. c. the molarity of the atom, ion, or compound. O d. the solubility of the atom, ion, or compound. O
Answer: B
Explanation:
(s) means the compound is in its solid form, and (aq) means that the compound is dissolved in a solvent (the solvent is often water).
which linkage best describes the covalent bond between an amino acid (aa) and its trna?
The covalent bond between an amino acid and its tRNA is a specific type of covalent bond called an ester linkage.
The covalent bond between an amino acid and its tRNA is formed through a specific type of covalent bond called an ester linkage. This linkage is formed between the carboxyl group of the amino acid and the 3' hydroxyl group of the tRNA.
The process of forming this bond is called aminoacylation, and it is catalyzed by an enzyme called aminoacyl-tRNA synthetase.
Each amino acid has a specific aminoacyl-tRNA synthetase enzyme that catalyzes the formation of the ester bond between the amino acid and the tRNA molecule with the corresponding anticodon.
Once the amino acid is attached to the tRNA, the resulting aminoacyl-tRNA can then be used in protein synthesis, where the tRNA delivers the amino acid to the ribosome and the amino acid is incorporated into the growing polypeptide chain.
Therefore, the correct answer is an ester linkage, which is formed between the carboxyl group of the amino acid and the 3' hydroxyl group of the tRNA during the process of aminoacylation.
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which molecules can form a hydrogen bond with another identical molecule? hooh ch2ch2nh2 hi sih4 ch3ch2f
The molecules that can form hydrogen bonds with another identical molecule are HOOH (hydrogen peroxide), CH₃CH₂NH₂(ethylamine), and CH₃CH₂F (ethyl fluoride).
Hydrogen bonding occurs between a hydrogen atom bonded to an electronegative atom (such as oxygen, nitrogen, or fluorine) and another electronegative atom in a different molecule. Based on this criterion, the molecules that can form hydrogen bonds with another identical molecule are:
HOOH (Hydrogen peroxide): The oxygen atom in one molecule can form a hydrogen bond with the hydrogen atom in another molecule.CH₃CH₂NH₂ (Ethylamine): The nitrogen atom can form a hydrogen bond with the hydrogen atom in another ethylamine molecule.CH₃CH₂F (Ethyl fluoride): The fluorine atom can form a hydrogen bond with the hydrogen atom in another ethyl fluoride molecule.Learn more about Hydrogen Bond
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fluorine's atomic number is 9 and its atomic mass is 19. how many neutrons does fluorine have? fluorine's atomic number is 9 and its atomic mass is 19. how many neutrons does fluorine have? 9 19 10 81 28
What volume does 40.5 g of N2 occupy at STP?
A)
64.8 L
B)
1.81 L
C)
32.4 L
D)
50.7 L
E)
none of these
40.5 g of N2 occupies 32.7 L at STP. The correct answer is (C) 32.4 L.
We can use the ideal gas law to solve this problem:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
At STP, the pressure is 1 atm and the temperature is 273.15 K. The ideal gas constant is 0.08206 L·atm/(mol·K). We can calculate the number of moles of N2 using its molar mass, which is 28.02 g/mol:
n(N2) = 40.5 g / 28.02 g/mol = 1.446 mol
Substituting these values into the ideal gas law equation:
V = nRT / P = (1.446 mol)(0.08206 L·atm/(mol·K))(273.15 K) / 1 atm = 32.7 L
Therefore, 40.5 g of N2 occupies 32.7 L at STP.
The correct answer is (C) 32.4 L.
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which of the following properties would be least useful for identifying a sample of calcite?
Answer:
Out of the following properties, the least useful for identifying a sample of calcite would be its color. Calcite is a mineral that can be found in a variety of colors, including white, gray, black, brown, red, orange, yellow, green, and blue. This means that its color is not a reliable indicator of its identity.
Other properties that can be used to identify calcite include its hardness (3 on the Mohs scale), specific gravity (2.71), and cleavage (rhombohedral). Calcite is also a birefringent mineral, which means that it splits light into two rays of different polarization when viewed through a polarizing filter.
Explanation:
Jose and Richie were responsible for recording the class weather data each day in March. This is how the wind sock looked when they went out this morning. What direction is the wind blowing from? Responses north
Answer:
answer is a
Explanation:
I just did that question
the following reaction follows second-order kinetics with a rate constant of 0.566 m-1s-1. suppose a vessel initially contains h3po4 at a concentration of 1.02 m. how much is left 5.20 seconds later? 2h3po4 ----> p2o5 3h2o group of answer choices 0.25 m 0.51 m 0.56 m 0.91 m
The concentration of [tex]2H_3PO_4[/tex] remaining after 5.20 seconds is approximately 0.254 M, the correct option is A.
To determine how much [tex]2H_3PO_4[/tex] is left after 5.20 seconds, we can use the integrated rate equation for a second-order reaction:
1/[A]t - 1/[A]0 = kt,
where;
[A]t = concentration of [tex]2H_3PO_4[/tex] at time t
[tex][A]_0[/tex] = initial concentration
k = rate constant
t = time elapsed.
Substituting the given values:
1/[A]t - 1/1.02 = (0.566 [tex]M^{-1}s^{-1}[/tex]) × 5.20 s,
Simplifying the equation:
1/[A]t = 1/1.02 + (0.566 [tex]M^{-1}s^{-1}[/tex]) × 5.20 s,
Calculating the right side:
1/[A]t = 0.9804 [tex]M^{-1}[/tex] + 2.9452 [tex]M^{-1}[/tex],
1/[A]t = 3.9256 [tex]M^{-1}[/tex].
Taking the reciprocal of both sides:
[A]t = 1 / (3.9256 [tex]M^{-1[/tex]),
[A]t = 0.254 M.
Thus, the correct option is A.
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The complete question is:
The following reaction follows second-order kinetics with a rate constant of 0.566 [tex]M^{-1}s^{-1}[/tex]. Suppose a vessel initially contains [tex]2H_3PO_4[/tex] at a concentration of 1.02 m. How much is left 5.20 seconds later?
[tex]2H_3PO_4[/tex] → [tex]P_2O_5+ 3H_2O[/tex]
(group of answer choices)
A. 0.25 M
B. 0.51 M
C. 0.56 M
D. 0.91 M
In the recrystallization of product, a mixed solvent of EtOH and water is used rather than a single solvent system of water or ethanol. Why?
A mixed solvent of EtOH and water is used in recrystallization to improve solubility and selectivity, resulting in better product purity and yield.
A mixed solvent system of EtOH and water is preferred over a single solvent system of water or ethanol in recrystallization because it can improve solubility and selectivity, leading to better product purity and yield. EtOH is a good solvent for organic compounds, while water is a good solvent for polar compounds.
When these two solvents are mixed, they can dissolve a wider range of compounds than either solvent alone. Additionally, the ratio of EtOH to water can be adjusted to fine-tune the solubility and selectivity of the mixed solvent system. This allows for better control over the recrystallization process, resulting in higher-quality products.
In summary, the use of a mixed solvent system in recrystallization can enhance the efficiency and effectiveness of the process, ultimately leading to improved product quality.
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1 valence electron, 4 energy levels
*
The majority of valence electrons are negatively charged particles, and they are all grouped in various orbitals or shells. Additionally, these electrons are in charge of how atoms interact with one another and create chemical bonds.
An element is defined as the pure substance which consists of only one type of atom which all have the same numbers of protons in their nuclei. Elements are the simplest chemical forms which cannot be broken down through chemical reactions.
Here the element potassium has the atomic number 19 and its electronic configuration is 2, 8, 8, 1. It contains the four energy levels, they are 'K', 'L', 'M' and 'N'. The number of valence electrons in potassium is 1.
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Your question is incomplete, most probably your full question was:
Which element has 1 valence electron and 4 energy levels?
PLEASE HELP ME WITH THIS CHEMISTRY HOMEWORK!!! WILL GIVE BRAINLIEST!!! :)
Explanation:
Plugging into the following equations will give you the answer (the answer is the attached image):
[tex]pH+pOH=14[/tex]
[tex]pH=-log_{10}([H^+])[/tex]
[tex]pOH=-log_{10}([OH^-])[/tex]
[tex][H^+][OH^-]=10^{-14}[/tex]
[tex][H^+]=10^{-pH}[/tex]
[tex][OH^-]=10^{-pOH}[/tex]
an oxide of iron has the formula fe3o4. what mass percent of iron does it contain?
Fe3O4 contains 72.4% iron by mass.The formula of the oxide of iron is Fe3O4, which means it contains 3 atoms of iron and 4 atoms of oxygen.
To calculate the mass percent of iron in Fe3O4, we need to first determine the molar mass of Fe3O4:
Molar mass of Fe3O4 = (3 x molar mass of Fe) + (4 x molar mass of O)
= (3 x 55.845 g/mol) + (4 x 15.9994 g/mol)
= 231.5332 g/mol
Next, we need to determine the mass of iron in one mole of Fe3O4:
Mass of iron in one mole of Fe3O4 = 3 x molar mass of Fe
= 3 x 55.845 g/mol
= 167.535 g/mol
Finally, we can calculate the mass percent of iron in Fe3O4:
Mass percent of iron = (mass of iron ÷ total mass of Fe3O4) x 100%
= (167.535 g/mol ÷ 231.5332 g/mol) x 100%
= 72.4%
Therefore, Fe3O4 contains 72.4% iron by mass.
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what net charge would you place on a 247 g piece of sulfur if you put an extra electron on 1 in 1012 of its atoms? (sulfur has an atomic mass of 32.1.)
The net charge on the 247 g piece of sulfur would be -1.84 x 10^13 elementary charges.
To solve this problem, we first need to calculate the number of sulfur atoms in the 247 g piece of sulfur:
number of sulfur atoms = (mass of sulfur / atomic mass of sulfur) x Avogadro's number
number of sulfur atoms = (247 g / 32.1 g/mol) x 6.022 x 10^23 atoms/mol
number of sulfur atoms = 1.84 x 10^25 atoms
Next, we need to determine how many atoms have an extra electron:
number of atoms with an extra electron = (1 / 1 x 10^12) x number of sulfur atoms
number of atoms with an extra electron = (1 x 10^12)^-1 x 1.84 x 10^25
number of atoms with an extra electron = 1.84 x 10^13 atoms
Each of these atoms with an extra electron has a net charge of -1, so the total net charge on the sulfur piece would be:
total net charge = -1 x number of atoms with an extra electron
total net charge = -1 x 1.84 x 10^13
total net charge = -1.84 x 10^13
Therefore, the net charge on the 247 g piece of sulfur would be -1.84 x 10^13 elementary charges.
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a solution contains 0.10 m sodium hydroxide and 0.10 m sodium cyanide. solid zinc nitrate is added slowly to this mixture. what is the formula of the substance that precipitates first?
The solution that contains the 0.10 M sodium hydroxide and the 0.10 M sodium cyanide. The formula of the substance which will precipitates first is the Zn(OH)₂.
The chemical equation for the reaction of the zinc acetate with the solutions and with the solubility products is as :
Zn(C₂H₃O₂)₂ + 2KOH ---> Zn(OH)₂ + 2KC₂H₃O₂
The ksp of the Zn(OH)₂ = 1.2 × 10⁻¹⁷
Zn(C₂H₃O₂)₂ + 2NaCN --> Zn(CN)₂ + 2C₂H₃O₂Na
The ksp of the Zn(OH)₂ = 2.6 × 10⁻¹³
The higher the value of the Ksp of the solute, then the more soluble the solute in the solvent.
The Ksp value of the Zn(OH)₂ is less as compared to the Ksp of the Zn(CN)₂, Therefore, the Zn(OH)₂ precipitates first.
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strategic solvingequations with variables on both sides 1 c03_se_m03_t01_l01.indd 7c03_se_m03_t01_l01.indd 7 14/01/19 9:45 pm14/01/19 9:45 pm
Solving equations with variables on both sides requires a strategic approach to ensure that the correct steps are taken to isolate the variable on one side of the equation.
One key strategy is to simplify the equation by combining like terms on each side. This can be done by adding or subtracting terms as necessary, while ensuring that the equation remains balanced.
Another strategy is to move all the variable terms to one side of the equation and all the constant terms to the other side. This can be done by adding or subtracting terms to both sides as necessary.
It's important to remember that when adding or subtracting terms, the operation must be applied to both sides of the equation to keep it balanced.
Once the variable terms are on one side of the equation and the constant terms are on the other, the equation can be solved by isolating the variable and determining its value.
It's important to check the solution by substituting the value back into the original equation and verifying that both sides are equal.
By following a strategic approach, equations with variables on both sides can be successfully solved.
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which of the following statements about disulfide bond formation is false? . group of answer choices (a) disulfide bonds do not form under reducing environments grow from both ends, the growth rate is faster at the plus ends. (b) disulfide bonding occurs by the oxidation of pairs of cysteine side chains on the protein. (c) disulfide bonding stabilizes the structure of proteins. (d) disulfide bonds form spontaneously within the er because the lumen of the er is oxidizing
The false statement about disulfide bond formation is (d) disulfide bonds form spontaneously within the ER because the lumen of the ER is oxidizing. Disulfide bonds do form within the ER, but not spontaneously.
Instead, they are formed by the action of enzymes called protein disulfide isomerases (PDIs). PDIs catalyze the oxidation of cysteine residues to form disulfide bonds. Disulfide bonding (b) stabilizes the structure of proteins, and (a) disulfide bonds do not form under reducing environments. Additionally, disulfide bonds do not (c) grow from both ends, the growth rate is faster at the plus ends. Instead, they are formed between two cysteine residues on the same polypeptide chain or between different polypeptide chains.
The false statement about disulfide bond formation among the given choices is (a) disulfide bonds do not form under reducing environments grow from both ends, the growth rate is faster at the plus ends. This statement is unrelated and incorrect. In reality, disulfide bonds (b) form by oxidation of cysteine pairs, (c) stabilize protein structures, and (d) form spontaneously within the ER due to its oxidizing environment. Disulfide bonds play a vital role in maintaining the proper folding and stability of proteins, especially those secreted or located in extracellular environments.
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Describe how acid deposition forms from sulfur dioxide.
Acid deposition forms from sulfur dioxide when it combines with oxygen and water in the atmosphere, producing sulfuric acid.
Sulfur dioxide is a gas that is emitted from the burning of fossil fuels, particularly coal and oil. When it is released into the atmosphere, it can react with oxygen and water to form sulfuric acid. This chemical reaction occurs naturally in the atmosphere, but it can be accelerated by human activities such as industrial processes and transportation.
Once formed, the sulfuric acid can be carried by wind and deposited on the ground as acid rain or snow. Acid deposition can have significant negative impacts on the environment, including harming plants, animals, and aquatic life. It can also contribute to the deterioration of buildings and monuments made of stone or metal. Therefore, it is important to reduce sulfur dioxide emissions through policies and technologies that promote cleaner energy sources and reduce pollution.
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The volume of a gas originally at standard temperature and pressure was recorded
as 488.8 mL. What volume would the same gas occupy when subjected to a
pressure of 100.0 atm and temperature of minus 245.0 °C?
The volume of a gas originally at standard temperature and pressure was recorded as 488.8 mL, the gas would occupy a volume of 5.97 mL at a pressure of 100.0 atm and temperature of -245.0 °C.
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:
(P₁V₁)/T₁ = (P₂V₂)/T₂
where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, respectively, and P₂, V₂, and T₂ are the final pressure, volume, and temperature, respectively.
We can first convert the initial temperature to Kelvin:
T₁ = 273.15 K (since it is at standard temperature)
Next, we can convert the final temperature to Kelvin:
T₂ = (-245.0 °C + 273.15) K = 28.15 K
We can then plug in the values and solve for V₂:
(1 atm x 488.8 mL) / 273.15 K = (100.0 atm x V₂) / 28.15 K
V₂ = (1 atm x 488.8 mL x 28.15 K) / (100.0 atm x 273.15 K) = 5.97 mL
Therefore, the gas would occupy a volume of 5.97 mL at a pressure of 100.0 atm and temperature of -245.0 °C.
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