The difference between an sa and sb galaxy is Sa has a larger nucleus and more tightly wound arms than an Sb.
What is sa Galaxy?Sa galaxies are normal spirals that have narrow, tightly wound arms, which usually are visible because of the presence of interstellar dust and, in many cases, bright stars.
What is sb Galaxy?The arms of sb galaxy are more widely spread than those of the Sa variety and appear less smooth.
Thus, the difference between an sa and sb galaxy is Sa has a larger nucleus and more tightly wound arms than an Sb.
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a note of frequency 200Hz has a velocity of 400m/s. what is the wavelength of the note
Answer:
[tex]\huge\boxed{\sf \lambda = 2 m}[/tex]
Explanation:
Given data:Frequency = f = 200 Hz
Velocity = v = 400 m/s
Required:Wavelength = λ = ?
Formula:v = fλ
Solution:Put the givens in the formula
400 = (200)λ
Divide 200 to both sides
400/200 = λ
2 m = λ
λ = 2 m
[tex]\rule[225]{225}{2}[/tex]
what are the classification of rectifier?
Thank uh ☘️
Explanation: A) half wave rectifier
B) Full wave rectifier :
1) central tapped
2) bridge rectifier
i hope this was helpful to you
Tabitha knows the redshift value of a particular celestial object. What can she use this information most directly to find out?
the age and distance of the object
the volume and mass of the object
the material composition of the object
the life expectancy of the object
She can use the information of redshift of a celestial body is to find the age and distance of the object.
What is red shift?'Red shift' is a critical idea for astronomers. The frequency of the light is increased, so the light is observed as moving towards the red side of the range.
Tabitha knows the redshift value of a particular celestial object. She uses this information to observe the consequence of the redshift.
Thus, the red shift value is used to determine the age and distance of the object.
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Answer:
A (the age and distance of the object)
Explanation:
Question 4 of 25
Which two chemical equations are balanced?
A. Na+ MgCl₂ → NaCl + Mg
B. 2LIOH + H₂S → Li₂S + 2H₂O
C. AgNO3 + NaCl → NaNO3 + AgCl
-
D. 3PBr3 + 2Cl2 → 3PCl3 + 2Br2
Answer:
To check whether a chemical equation is balanced or not we usually look if elements on the product side are numerically equal to the reactant side or not.
A. Na + MgCl₂ → NaCl + Mg
Reactant Product
Na = 1 1
Mg = 1 1
Cl = 2 1
Unbalanced
B. 2LiOH + H₂S → Li₂S + 2H₂O
Reactant Product
Li = 2 2
S = 1 1
O = 2 2
H = 4 4
Balanced
C. AgNO₃ + NaCl → NaNO₃ + AgCl
Reactant Product
Ag = 1 1
N = 1 1
Na = 1 1
Cl = 1 1
O = 3 3
Balanced
D. 3PBr₃ + 2Cl₂ → 3PCl₃ + 2Br₂
Reactant Product
P = 3 3
Br = 9 4
Cl = 4 9
Unbalanced
Therefore, equations B and C are balanced chemical equations.
An electric motor rated 2.5kw is used to lift bales of hay to a store in a dairy farm. A single bale has a mass of 5kg. If the store is 4 meters above the ground, how many bales can the motor raise in 2 minutes.
A boy threw a ball upward and it took 3 sec to reach the highest point. Determine the initial velocity of the ball.
Answer:
V initial = 29.4 m.s²
Explanation:
( Using the laws of motion)
V final = V initial + Acceleration × time
0 = V initial + ( -9.8)(3)
29.4 = V initial
* I took upward as positive that's why I substituted -9.8 *
* for V final we know that at maximum height the ball is not moving thats why is = 0 *
Two 2.0-mm diameter beads, c and d, are 12mm mm apart, measured between their centers. bead c has mass 1.0 g and charge 2.5nc nc . bead d has mass 1.7g g and charge -1.0 nc. if the beads are released from rest.
a. what is the speed vc at the instant the beads collide?
b. what is the speed vd at the instant the beads collide?
The speed of Vc at the instant bead collide is 1.38 m/s and the instant speed of Vd at the instant bead collide is 0.106 m/s.
The force of attraction on the beads are due to both gravitational force and electrostatic force
As gravitational force is very weak force as compared to electrostatic force the net force will be due to electrostatic force only.
Net Force = Electrostatic force
Net Force = K q1 q2 / r²
Net Force = (9 × 10⁹) (2.5 × 10⁻⁹) (1 × 10⁻⁹) / (14 × 10⁻³) (as distance between there centre of mass is 14 mm)
Net Force = (9 × 2.5 × 10⁻⁶) / 14
Net Force = 1.6 × 10⁻⁶
For bead c
Force = Mc × Ac = 1.6 × 10⁻⁶
(1 × 10⁻³) × Ac = 1.6 × 10⁻⁶
Ac = 1.6 × 10⁻³
Acceleration of bead C is 1.6 × 10⁻³ m/s²
For bead d
Force = Md × Ad = 1.6 × 10⁻⁶
(1.7 × 10⁻³) × Ad = 1.6 × 10⁻⁶
Ad = 0.94 × 10⁻³
Acceleration of bead D is 0.94 × 10⁻³ m/s²
Let us suppose bead C travels y distance before collision
So bead D should travel 12-y distance before collision
So speed of both the beads before the collision can be find out by using newton third law of motion
For bead C
Vc² - Uc² = 2 Ac s
Vc² = 2 × 1.6 × 10⁻³ × y
Vc² = 3.2 × 10⁻³ × y
Vc = √(3.2 × 10⁻³ × y)
For bead D
Vd² - Ud² = 2 Ad s
Vd² = 2 × 0.94 × 10⁻³ × (12-y)
Vd² = 1.88 × 10⁻³ × (12-y)
Vd = √(1.88 × 10⁻³ × (12-y))
Applying energy conservation
initial = final
0 + 0 = (1/2)McVc² - (1/2)MdVd²
(1/2)McVc² = (1/2)MdVd²
McVc² = MdVd²
1 × 10⁻³ × 3.2 × 10⁻³ × y = 1.7 × 10⁻³ × 1.88 × 10⁻³ × (12-y)
3.2 × y = 3.2 × (12-y)
y = 12-y
2y = 12
y = 6
Putting the value of y in Vc and Vd
Vc = √(3.2 × 10⁻³ × y)
Vc = √(3.2 × 10⁻³ × 6)
Vc = √(19.2 × 10⁻³)
Vc = √0.0192
Vc = 1.38 m/s (approximately)
Vd = √(1.88 × 10⁻³ × (12-y))
Vd = √(1.88 × 10⁻³ × (12-6))
Vd = √(1.88 × 10⁻³ × 6)
Vd = √(11.28 × 10⁻³)
Vd = √0.01128
Vd = 0.106 m/s (approximately)
So the speed of Vc at the instant beads collide will be approximately 1.38 m/s and Vd at the instant speed the beads collide will be approximately 0.106 m/s.
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The ball is in contact with the bat for 0.001s use the equation in the box to caluclate the force exerted by the bat on the ball
Answer:
Force = 9600N
Explanation:
If this is the right question, there should have been a question before about the what the change in the momentum of the ball was. The answer to that was 9.6kg m/s. For this part, we divide this by the time taken which was 0.001s which give us the resultant force.
resultant force = change in momentum ÷ time
= 9.6kgm/s ÷ 0.001s
= 9600N
The Volume Of a Body weighing is 1200 kg is 250000 [tex]cm^{3}[/tex] Find ITs density.
Write With Formula
Answer:
[tex]\boxed {Density = 4800 kg/m^{3}}[/tex]
Explanation:
Formula :
[tex]\boxed {Density = \frac{Mass (kg)}{Volume (m^{3})}}[/tex]
Convert volume into standard unit :
⇒ 250000 cm³ × 10⁻⁶
⇒ 0.25 × 10⁶ × 10⁻⁶
⇒ 0.25 m³
Solve for density :
⇒ Density = 1200 kg / 0.25 m³
⇒ Density = 1200 × 4 kg/m³
⇒ Density = 4800 kg/m³
The ability to provide for our needs without damaging Earth's resources is called _______.
A. Acid Rain
B. Sustainability
C. Degradation
D. Pollution
Answer = B
Explanation:
Sustainability is the most appropriate as it means meeting our own needs without compromising the ability of future generations to meet their own needs.
a protostar will continue to collapse due to gravity until it reaches the main sequence, and then gravitational collapse will stop when _____ begins.
a protostar will continue to collapse due to gravity until it reaches the main sequence, and then gravitational collapse will stop when fusion of hydrogen begins.
What is a protostar and how does gravity affect it?A protostar serves as a very young star which is very small in mass and still developing its mass from parent molecular cloud.
However, it can be affected by gravity because , when there is not collapse on the gravity, if there is fusion of hydrogen begins in it.
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The Voyager spacecraft is moving at 17 000 m/s. How far will it travel in one year? Give your answer in km.
Explanation:
first change m/s to km/hr and time 1 year to hour b/c we are asked the to give in km. so,
v=17,000 m/s = 17000×3600/1000 = 61,200 km/hr
t= 1 year= 365 days =365day×24 hr/day = 8,760hr
therefore, V = s/t from this s = v×t =61200×8760 =536,112,000 Km
where do automatically generated statements that set the properties of the labels, buttons, and forms end up?
The generated statements that set the properties of the labels, buttons, and forms end up automatically within the InitializeComponent() method.
What is InitializeComponent?The InitializeComponent method in programming is the that have code that works with codes that creates and initializes the creates and initializes the user interface objects .
Conclusively, when a statement is generated, to when set the properties of the labels , it will definitely been felt in the InitializeComponent() method automatically.
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You are ask to bring a cylindrical rod of length 45cm and diameter of 4.53cm to a mechanic. what is the weight of the aluminum rod if the density is 3.7*10^3kg/m^3
26.676 × 10³ kg is the weight of the aluminum rod.
To calculate specific weight:Given:
Length of cylindrical rod (h) = 45 cm
Diameter of a cylindrical rod = 4.53 cm
Radius of a cylindrical rod (r) = 2.3 cm
The density = 3.7*10^3kg/m^3
Volume of a cylindrical rod = πr²h
= 3.14× (2.3)² × 45
= 747.89 cm
= 7.4789 m
To find weight ;
ρ = [tex]\frac{Mass}{Volume}[/tex] ; ρ = Density
Mass = ρ × Volume
= 3.7 × 7.48 × 10³
=27.676 × 10³ kg
Therefore, the weight of the aluminum rod is 27.676 × 10³ kg.
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What local group of galaxies is the Milky Way part of?
Quasar Cluster
Andromeda Mini-Cluster
Virgo Supercluster
Hubble Open Cluster
The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C
What are Virgo Supercluster?The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.
Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.
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a compact car is about 1289 kg and its engine has the ability to generate 183831 W. if all that power is applied from a stand still and no energy is dissipated, how fast will the car be moving after 7 seconds.
The speed of the car moving after 7 seconds will be 31.5 m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
m is the mass of the car = 1289 Kg.
u is the initial velocity = 0 m/sec
a is the acceleration in m/sec²
v is the velocity after 7 seconds =?
The power developed is;
P =FV
F=ma
P=maV
183831=1289 kg × a × V
a = 142.61 / V
From Newton's second equation of motion;
V=u+at
V=0+at
V=(142.61/V)t
V²=142.61 × 7
V=31.5 m/sec
Hence, the speed of the car moving after 7 seconds will be 31.5 m/sec.
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how can you tell the difference between an expression of speed and an expression of velocity?
A. velocity has unit expressed as distance/time; speed does not.
B. speed has units expressed as distance/time; velocity does not.
C. speed includes a direction; velocity does not.
D. velocity includes a direction; speed does not.
The quotient of 8.4x10° and a number n results in 5.6x 1027. What is the value of n?
1.5x10-18
O 1.5x10
O 1.5x10³
1.5x10¹8
Against the park ranger's advice, a visitor at a national park throws a stone horizontally off the edge of a 86 m high cliff and it lands a distance of 89 m from the edge of the cliff, narrowly missing a visitor below.
What was the initial horizontal velocity of the rock, in m/s? You can round your answer to the hundredth place and use g ≈ 10 m/s2.
The initial horizontal velocity of the rock, in m/s is 21.241 m/s.
What is projectile?When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.
Time taken by the stone to reach the ground is
t = √2h/g
t = √(2x 86)/9.81
t = 4.19s
The horizontal velocity is
V(x) = Horizontal distance traveled / Time taken t
Put the values, we get
V(x) = 89 m/4.19 s
V(x) = 21.241 m/s
Thus, the horizontal velocity is 21.241 m/s
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In a game of Tug-of-War,
when are the forces
unbalanced?
A. when one side lets go of the rope
B. when the net force is o N
C. when both sides pull with 55 N
Refer to the attached image!!!
The time of motion of the track star is determined as 0.837 s.
Time of motion of the track star
The time of motion of the track star is calculated as follows;
T = (2u sinθ)/g
where;
T is time of motiong is acceleration due to gravityθ is angle of projectionT = (2 x 12 x sin20)/9.8
T = 0.837 s
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when a boy jumps into a pool
Answer:
energy only
Explanation:
Water waves transfer energy via oscillations of the water molecules, but the the water molecules themselves do not move along the wave.
This is why when the boy jumps into the water, his kinetic energy is transferred by the water molecules across the pool, but neither the boy nor the water particles move along with the wave.
A body at rest is given an initial uniform acceleration of 8m/s2 for 30s after which the acceleration is reduced to 5m/s2 for the next twenty seconds. The body maintains the speed attained for 60s, after which it is brought to rest in 20s.
Explanation:
v=u+at, where v,u,a and t are the final velocity, initial velocity, acceleration and time, respectively.
For t=0 s to t=30 s , a =8 m/s 2.
For t=30 s to t=50 s , a = 5 m/s 2.
For t=50 s to t=110 s , a = 0 m/s 2.
For t=110 s to t=130 s , a is such that the body comes to rest at the end of this period.
For t=0 s to t=30 s ,v=0+8t⇒v=8t m/s.
At t=30s,v=8×30=240 m/s.
For t=30 s to t=50 s ,v=240+5(t−30)⇒v=90+5t m/s
At t=50s,v=90+5×50=340 m/s.
For t=50 s to t=110 s ,v=340 m/s.
For t=110 s to t=130 s ,v=340+a(t−110).
The body comes to a halt at t=130 s ⇒0=340+a(130−110).
0=340+20a⇒a=−34020=−17 m/s2.
For t=110 s to t=130 s ,v=340−17(t−110)=2210−17t m/s.
How many degrees is the maximum and minimum variation between the true and magnetic poles?
The maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.
What are the true and magnetic poles?The poles of the earth are the North and South poles.
The North is taken as the reference point.
The true north is a fixed point on the globe and gives the true North and South poles.
The Magnetic north is the direction that a compass needle points to as it aligns with the Earth's magnetic field and gives the magnetic North and South poles.
The maximum maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.
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Draw a ray diagram for a diverging lens that has a focal length of -10 cm when an object is placed 30 cm from the lens's surface. Calculate the position of the image and list the characteristics of the image.
Explanation:
Hello, nice to meet you.
this answer will help for you
According to Newton's 2nd law of motion, if you hit a baseball with a bat it will
-hurt your hand from the reaction force
-accelerate according to the applied force
-fly in a straight line unless an outside force changes its course
-fall to the ground because of gravitational pull
Answer:
Newton's second law states that force is directly proportional to the product of mass and acceleration.
so if you hit a baseball with a bat it will accelerate according to the applied force.
calculate the heat energy required to increase the temperature of 10 kg of water from 25 degrees Celsius to 115 degrees Celsius
Answer:
3 767 400 joules
Explanation:
4.186 J/g-C is the specific heat of water
25 to 115 is 90 degrees C change
10 000 g is 10 kg of water
10 000 * 90 * 4.186 = 3 767 400 Joules
what is the speed of a wave that has a frequency of 11.5Hz and a wavelength of 1.7m?
Answer:
19.55 m/s
Explanation:
Here is HOW to get the answer:
Speed = wavelength * freq
= 1.7 * 11.5 = 19.55 m / s
When does a driver have to stop for a school bus
A driver have to stop for a school bus when the red lights are flashing and there is no barrier between his/her vehicle and the bus.
What are traffic rules?Traffic rules are rules that are expected to follow by the road users for the safety of everyone using the road.
For instance, when the red lights are flashing , it simply means to stop, while the green light means that the vehicle can continue to move, and yellow light means to be at alert to move.
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Find the energy u of the capacitor in terms of c and q by using the definition of capacitance and the formula for the energy in a capacitor
The formula for the energy in a capacitor , u in terms of q and c is q²/2c
What is the energy of a capacitor?The energy of a capacitor u = 1/2qv where
q = charge on capacitor and v = voltage across capacitor.What is the capacitance of a capacitor?Also, the capacitance of a capacitor c = q/v where
q = charge on capacitor and v = voltage across capacitor.So, v = q/c
The formula for energy of the capacitor in terms of q and c
Substituting v into u, we have
u = 1/2qv
= 1/2q(q/c)
= q²/2c
So, the formula for the energy in a capacitor , u in terms of q and c is q²/2c
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