The probability that a randomly selected person said data analysis was a critical skill will be A. 0.50.
How to calculate the probability?The number of critical skilled person will be:
= 253 + 105
= 358
The total number of employees will be:
= 253 + 110 + 105 + 250
= 718
Therefore, the probability will be:
= 358/718 × 100
= 50%
= 0.50
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consider the following hypothesis test, H0, U greater than or equal to 20, Ha less than 20, a sample of 50, provided a mean of 19.4 population standard deviation is 2, compute the value of of the test static, what is the p-value,
Based on the calculations, the value of the test statistic and p-value are equal to -2.1213 and 0.0169 respectively.
Given the following data:
Standard deviation = 2.Sample mean = 19.4.Number of sample = 50.Hypothesized mean = 20.How to compute the test static?Mathematically, the value of the test statistic can be computed by using this formula:
[tex]Z=\frac{\bar{x}\;-\;\mu}{ \frac{\sigma}{\sqrt{n} } }\\\\Z=\frac{19.4\;-\;20}{\frac{2}{\sqrt{50}}}\\\\Z=\frac{-0.6}{0.282842 }[/tex]
zₓ = -2.1213.
From the z-table, the p-value is given by:
P(Z < zₓ) = P(Z < -2.1213)
P(Z < -2.1213) = 0.0169.
Since the p-value is equal to 0.0169 less than α = 0.05, we would reject H₀ : µ equal to 20. Thus, we would conclude that µ < 20.
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