what is the value of the composite constant (gmer2e) , to be multiplied by the mass of the object mo in the equation above?

Answers

Answer 1

Therefore, in the equation above, the mass of the object mo must be multiplied by the composite constant (Gme/r2e), which has a value of 9.7196 m/s2.

What does a definition of mass mean?

In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the force applied. The change caused by an applied force is smaller the more mass a body has.

For this particular issue, the solution were as follows:

(G Me Mo) / Re2 = F

(G Me) / Re2 = F / Mo

G is equal to 6.67384 * 10-11 m3 kg-1 s-2, or gravitational constant.

Me = 5.972 * 10^24 kg

Re^2 ≈ (6.38 * 10^6)^2 m^2 ≈ 40.7044 * 10^12 architects = 4.07044 * 10^fourteen m^2

G Me/Re2 = (6.67384*10-11*5.972*1024)/(4.0704*1013) = 9.7196 m/s2.

Gravitational acceleration is 9.7196 m/s2.

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Related Questions

a 0.650-kg object is swung in a circular path and in a vertical plane on a 0.500-m-length string. if the angular speed at the bottom is 8.00 rad/s, what is the tension in the string when the object is at the bottom of the circle?

Answers

The tension in the string = 83.2 N

What is tension?

Tension is defined as the pulling force transmitted axially by using a string, a rope, chain, or similar object, or by each end of a rod, truss member, or similar 3-D object; tension might also be expressed as the action-reaction pair of forces acting at each end of said elements. Tension is the opposite of compression. All objects in contact with each other exert forces on each other. The best example of pulling force is seen when pulling on a rope. When a pulling force is applied to a rope, it creates considerable tension.

Given,

Mass of object (m) = 0.650kg

Radius of object (r) =  0.5 m

Angular speed (ω) = 8.00 rad/s

T = mω²/r

T = 0.65 × 8²/0.5

T = 83.2 N

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if one ball's initial speed was 1.50 m/s , and the other's was 2.20 m/s in the opposite direction, what will be their velocities after the collision?

Answers

If one ball's initial speed was 1.50 m/s , and the other's was 2.20 m/s in the opposite direction, There velocities after collision will be - 2.2  m/s and  - 2.9 m/s  

given :

masses of both the balls are same

using conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

m1 ( 1.50 ) + m2 * (-2.20) = m1v1 + m2v2

m (1.50) + m ( -2.20) = mv1 + mv2

-0.7 = v1 + v2         equation 1

since

u1 + v1 = u2 + v2

1.50 + v1 = (-2.20) + v2

v1 - v2 = - 3.7            equation 2

solving equation 1 and 2 we get

v1 = - 2.2  m/s

v2 = - 2.9 m/s

There velocities after collision will be - 2.2  m/s and  - 2.9 m/s  

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a transformer has 620 turns in the primary coil and 68 in the secondary coil. part a what kind of transformer is this? what kind of transformer is this? it's a step-up transformer. it's a step-down transformer.

Answers

A transformer has 620 turns in the primary coil and 68 in the secondary coil. Step-down transformer is the type of transformer utilized.

What is transformer and its type?

In the fields of electricity and electronics, transformers are a common tool. It is an electromagnetic gadget that utilizes the fundamental electromagnetism theory developed by Michael Faraday.

Step up transformer:

Exactly the opposite of a step-down transformer is a step-up transformer. Using a step-up transformer, the low primary voltage is raised to a high secondary voltage. Once more, it is accomplished by the proportion between primary and secondary windings.

Step down transformer:

Reduction in height Both the electrical and electronic fields require transformers. A step-down transformer lowers the voltage across the secondary output from the primary voltage level.

Here,

no. of turns in primary coil = N[tex]_{p}[/tex] = 620

no. of turns in secondary coil = N[tex]_{s}[/tex] = 68

hence, N[tex]_{p}[/tex] > N[tex]_{s}[/tex]

so, the given transformer is step down transformer.

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a fire protection code requires a minimum pressure of 65 psi at the outlet end (2) of a horizontal, 250 ft long, 4 inch diameter hose when the flowrate is 500 gal/min. what is the minimum pressure required at the inlet end (1). assume a roughness of e

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A horizontal, 250-foot-long, 4-inch-diameter hose must have a minimum pressure of 65 psi at the outlet end (2) in order to comply with fire safety regulations.

what is the input end's minimum pressure requirement?The pressure present where the suction pipe connects to the booster pump is known as the inlet pressure, also known as pump intake pressure.The water pressure created if the booster pulls from a break tank or the pressure of the water provider determines the input pressure.Purchasing a pressure gauge from your neighborhood hardware shop and connecting it to a hose faucet is the most precise approach.To acquire a baseline reading, check the pressure when all other faucets and water-using devices are shut off.The ideal pressure range for domestic plumbing is between 30 and 80 psi.

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Think about the ecosystem that you live in. Write a response below describing it in complete sentences. Use each of these terms correctly in your description

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An ecosystem is made of different species of animals, plants and the resources for their living. If we observe our surroundings, we can see many more types of living things with their own peculiarities.

What is ecosystem?

Ecosystems in earth contains the region where living things and major resources exists. There are different ecosystems namely, forests,  aquatic systems, deserts, gralsslands, marshy lands etc.

If we observe around there are various kinds of plants and animals in water bodies as well as in land. They can their characteristic features and adapting powers.  They can be of same species or different, social living or isolated living.

We can classify water bodies as one ecosystem and land area and grass lands as other ecosystems.

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write the differential equation of the system by the 2nd law of newton mechanics or theorem of momentum moment g

Answers

The instantaneous change in momentum brought on by something like a hammer strike is equal to the applied impulse, however the second law of newton did not state that F=ma (i.e., d2xdt2=1mF) in the Principial.

What is the second law of Newton in plain English?

The modifications that a force can cause to a body's motion are quantitatively described by Newton's second law. According to this, the force acting on a body has an equal and opposite magnitude and rate of change in its momentum over time.

The third law of Newton is what?

The formal formulation of Newton's third law is: There is an opposite and equal to every action. According to the statement, each interaction involves two forces acting on the interacting objects. The first object's force is equal to the size of the second object's force.

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HELP PLEASE FAST IT'S ARGENT I'LL GIVE (POINTS)

Answers

Answer:

Secondary succession

Explanation:

if the skater started from rest 4 m above the ground (instead of 7 m ), what would be the kinetic energy at the bottom of the ramp (which is still 1 m above the ground)?

Answers

The kinetic energy at the bottom of the ramp is 2205 J.

The kinetic energy of an object is the electricity that it possesses because of its motion. Tt is defined because the work needed to accelerate a body of a given mass from rest to its stated velocity. Having won this power for the duration of its acceleration, the body maintains this kinetic electricity until its pace adjusts.

Kinetic energy is a form of strength that an object or a particle has by means of the cause of its motion. If work, which transfers electricity, is done on an object by way of applying an internet force, the item quickens and thereby gains kinetic electricity.

Calculation:-

KE = decrease in potential energy

= mg(h2 - h1)

= 75 * 9.81 * ( 4 - 1)

= 2205 J

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a 0.25 m radius grinding wheel is rotating with a constant angular speed of 2.0 rad/s. what is the linear displacement of the wheel after 3.0 s?

Answers

The linear displacement of the wheel will be 1.5m.

Linear displacement is the measure of straight path covered by the object .

Rotating angular speed of the wheel = 2.0 rad/s

Radius of the wheel = 0.25 m

According to the angular speed and linear speed relationship, we can say that linear speed is the product of angular speed and the the radius of the object

Mathematically, v = r * ω

V = linear velocity

r = radius of the wheel

ω = angular velocity

V = 0.25 * 2

V = 0.5 m/s

Also, speed is equal to distance upon time.

V = d/t

Time at wheel the the wheel's linear distance is to be found = 3 s

therefore d = V * t

d = 0.5 * 3

d = 1.5 m

The linear displacement of the wheel after 3.0 s is 1.5 m.

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photons of ulltraviolet radiation with wavelengths that are shorter than those of visible light will have what kind of energy in relation to visible light?

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Ultraviolet radiation has shorter waves than blue or violet light, and thus oscillates more rapidly and carries more energy per photon than visible light does.

Infrared and ultraviolet radiation are the neighbors of visible light in the electromagnetic spectrum.Red light contains shorter waves than infrared radiation, which causes it to oscillate at a lower frequency and carry less energy.

One way energy travels is as visible light.Light waves are an example of electromagnetic (EM) radiation because they are produced by the vibration of electric and magnetic fields.

Although visible light is only one of many different types of electromagnetic radiation and only makes up a very small portion of the entire electromagnetic spectrum, it holds unique relevance for us because we can see it with our eyes.

The wavelength of light is between 400 and 700 nanometers (4,000 to 7,000 angstroms).Our eyes interpret the various light wavelengths as the hues of the rainbow.

Around 700 nm length, the waves of red light are comparatively long.The wavelength of blue and purple light is only 400 nm.

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to advance in time the evolution of temperature of the atmosphere at any given point in the globe, models calculate the temperature changes due to

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The complexity of Earth is beyond the capabilities of computer simulations.Numerous assumptions that must be made by computer models have a big impact on the forecasts they produce.A computer model can incorporate historical climate data, but it is not possible to draw assumptions about future climates using this data in any way.A computer model cannot distinguish between anthropogenic climate change and natural climatic fluctuations.How precise are temperature forecasts made by climate models?

The forecasting of global surface temperatures is one of the most significant results of climate models.

Scientists evaluate the effectiveness of their models by contrasting observations of the Earth's climate with predictions of future temperatures and "hindcasts" of past temperatures. Then, by comparing specific climate models and the average of all models to actual warming, scientists may determine whether temperature projections are accurate.

Researchers can have more faith that models can effectively predict future changes in the same factors if they successfully simulate the climate response in the past.

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Determine the acceleration that results when a 10-N net force is applied to a 5.1 kg object.

Answers

Answer:

1.96 m^2

Explanation:

F = m * a

10 = 5.1 * a

a = 1.96 m/s^2

if an extrasolar planet suddenly became more massive, but kept the same radius and orbit, what would change in the observed doppler shift of the star?

Answers

If an extrasolar planet suddenly became more massive, but kept the same radius and orbit, peak velocity of the star would increase in the observed doppler shift of the star.

fo = [ ( v + vo ) / v + vs ) ] fs

fo = Observer frequency of sound

v = Speed of sound waves

vo = Observer velocity

vs = Source velocity

fs = Actual frequency of sound waves

If an extrasolar planet suddenly became more massive, but kept the same radius and orbit, time between peaks in the velocity of the star would decrease in the observed doppler shift of the star. This means that the peak velocity of the star would increase.

Therefore, the change in the observed doppler shift of the star is that the peak velocity of the star would increase.

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which of the pathways below are in the correct order for the flow of electrons from glucose to oxygen in aerobic respiration? select one: a. glycolysis, citric acid cycle (tca), ets g

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Glycolysis, a pathways for the flow of electrons from glucose to oxygen in aerobic respiration.

The process of obtaining chemical energy for the body in the form of ATP is called respiration. In the process, chemical bond energy stored in various molecules is reduced or oxidized. The most commonly used substrate in this pathway is glucose.

Glucose is first converted to two molecules of pyruvate by a pathway known as glycolysis. The pyruvate produced is converted to acetyl-CoA and enters the Krebs cycle. In the Krebs cycle, acetyl-CoA is oxidized to form CO2, ATP, NADH and FADH2. NADH and FADH2 are used as reducing forces within the electron transport chain or ETC, oxidizing various enzymes and coenzymes within the ETC to synthesize ATP.

Therefore, the correct sequence of processes involved in aerobic cellular respiration is glycolysis, the Krebs cycle, and the electron transport chain.

So the correct answer is "glycolysis, Krebs cycle, electron transport system".

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Suppose two equal mass cars traveling with equal speeds in opposite directions collide head on and stick together. What fraction of the energy is dissipated?.

Answers

A collision which is inelastic is one in which the internal energy changes. The entire kinetic energy is lost. The parameters listed are.

When two cars collide, one car's mass equals the second car's mass, or m.

Inelastic collision is the collision type. Each car's speed before the incident was v and -v. The final velocity following the contact is zero, making the collision a perfect example of an inelastic collision.

The negative symbol represents energy that is given out or provided. The energy lost is equal to mv2 (The total initial kinetic energy). As a result, all of the kinetic energy is lost.

When particles, collections of particles, or solid entities travel in the same direction and get close enough to one other, they collide and exert mutual force.

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An athlete is running a circular track of radius 50m after he completed 2 revolution, what will be.
A, displacement B, distance​

Answers

Answer:

displacement=√50^2+50^2=70.71m

Explanation:

Distance traveled by the athlete=length of the arc

=d(theta)r

Here the athlete runs 3\4of a circle whose radius is 50 m

here, d(theta)=3(pi)/2rad

hence distance=3(pi)/2 x 50

=235.61 m

displacement=the chord between the initial point and the final point. it subtends an angle of 90degrees at the centre of the circle.

it forms a right angled triangle.

hence by Pythagoras theorem,

displacement=√50^2+50^2=70.71m

A 5.0-kg and a 10-kg box are touching each other. A 45.0-N horizontal force is applied to the 5.0-kg box in order to accelerate both boxes across the floor the coefficient of kinetic friction is 0.200 determine the acceleration and the contact force

Answers

Answer:

Below

Explanation:

Fn = Normal force = (5  + 10) ( 9.81 ) = 147.15 N      (Contact force)

Friction force = 147.15 * .2 = 29.43 N

Net force causing boxes to move = 45 - 29.43 = 15.57 N

F = m * a

15.57  = ( 5+10) * a      shows  a = 1.038 m/s^2

a block sits at a ramp with a 35 degree angle to the ground. friction has a magnitude of 41 n as it slides down the ramp with a mass of 13.2 kg. what acceleration does the block have on the ramp?

Answers

The Net acceleration of the block is 5.62104907 m/s².

Given -

A block is positioned at the bottom of a ramp at a 35-degree angle. With a mass of 13.2 kg, it slides down the ramp with a coefficient of friction of 41 n.

Principle-

The resistance that surfaces in contact provide to motion when they pass one another is referred to as friction. The two surfaces in contact are causing friction because of their irregularities. Therefore, these surface irregularities become entangled when one object moves over the other, creating friction. The friction will increase in significance as the roughness increases, creating more irregularities.

Mathematical concept-

[tex]F=ma-----[1]\\\\F=mgsinx----[2]\\\\\\ma=mgsinx[/tex]

cancelling m both sides and finally the equation reduces to [tex]a=gsinx[/tex]

Calculations-

g=9.8m/s² , x= 35

a=9.8 sin 35

a=9.8 x 0.57357

=5.62104907 m/s²

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please answer fast, you'll save my life TY!!!

Answers

Answer:

C  and D

Explanation:

Electrostatic force =  C q1 q2 / r^2

C = coulomb's constant      q = charge    r = distance between charges

   so you can see that   C and D will increase the force

8. a sports car accelerates from 0 to 27 m/s, in 6.3 seconds. the car exerts a force of 3106 n. what is the mass of the car?

Answers

A sports car accelerates from 0 to 27 m/s. The mass of the car is  732.5kg.

initial speed of a car = 0m/s

final speed of the car = 27m/s

time taken = 6.3 seconds

then acceleration is calculated as:

acceleration = velocity / time

acceleration = (27 - 0)/6.3 = 27/6.3 = 4.24m/s²

The force exerted y a car = 3106 N

as we know

F = ma

where

F = force exerted

m = mass of the body

a = acceleration of a car

F = ma

3106N = m x 4.24m/s²

m = 3106 /4.24

m = 732.5kg

A sports car accelerates from 0 to 27 m/s. The mass of the car is  732.5kg.

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During which type of radioactive decay is the mass of the emitted particle the smallest?.

Answers

Answer:

Explanation:

The mass of the emitted particle is the smallest in beta decay.

Beta decay is the flow of electrons, alpha decay is the flow of helium nuclei

During alpha decay, the mass of the emitted particle is the smallest compared to other types of radioactive decay.

In alpha decay, an unstable atomic nucleus emits an alpha particle, which consists of two protons and two neutrons bound together, effectively forming a helium-4 nucleus. This means that the alpha particle has a mass of approximately 4 atomic mass units (AMU).

In contrast, beta decay involves the emission of beta particles, which can be either beta-minus particles (electrons) or beta-plus particles (positrons). These particles have much smaller masses compared to alpha particles. For example, a beta-minus particle (electron) has a mass of approximately 0.00055 AMU, and a beta-plus particle (positron) has the same mass but opposite charge.

Gamma decay, on the other hand, does not involve the emission of particles with mass but instead releases high-energy photons (gamma rays) to stabilize the nucleus.

Hence, the alpha particle emitted during alpha decay has the smallest mass among the particles emitted during radioactive decay processes.

During alpha decay, the mass of the emitted particle is the smallest compared to other types of radioactive decay.

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A vibrating structural beam in a spacecraft can cause problems ifthe frequency of vibration is fairly high. Even if the amplitude ofvibration is only a fraction of a millimeter, theacceleration of the beam can be several times greater than theacceleration due to gravity. As an example, find the maximumacceleration of a beam that vibrates with an amplitude of 0.25 mmat the rate of 110 vibrations per second. Give your answer as amultiple of g.

Answers

The maximum acceleration of the beam is 12.18 g.

What is the maximum acceleration of the beam?

Centripetal acceleration is defined as the property of the motion of an object, traversing a circular path. The maximum centripetal acceleration is the rate at which the maximum angular velocity changes with time.

The centripetal acceleration is obtained by multiplying the radial acceleration by amplitude of the motion.

The maximum acceleration of the beam is calculated as follows;

a = ω²r

where;

ω is the angular speed of the vibrating objectr is the radius of the path

maximum acceleration = ω²A

where;

A is the amplitude of the motion

The given parameters;

angular speed of the vibrating beam = 110 rev/s = (110 x 2π rad)/s = 691.1 rad/sthe amplitude of the vibration, A = 0.25 mm

a(max) = (691.1²) x (0.25 x 10⁻³)

a(max) = 119.4 m/s²

In multiple of acceleration due to gravity (g) = 119.4 / 9.8 = 12.18 g

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A spherical balloon is increasing in volume at 3 24 cm s π. How fast is the radius of the balloon increasing when the surface area of the balloon is 2 30π cm ?.

Answers

The rate of increase in balloon radius is 0.12 cm/s.

Solution:

r^3 = 24×3/4

r^3= 18

r= √18

r= 2.62cm

∴ the rate of change in radius here is 2.62cm/s since π is constant.

The surface area of the sphere= 4πr^2

the surface area of the balloon is 30πcm^2

therefore 30π= 4πr^2

divide both sides by 4π

r^2= 30/4

r^2= 7.5

r=√7.5

r= 2.74cm

The rate of change in radius here is 2.74cm/s

As altitude increases atmospheric pressure decreases. The pressure on the outside of the balloon then drops. In order to balance the external pressure, the gas inside expands and lowers the pressure. Therefore, the size of the balloon increases. Gas particles exert pressure on the walls of the gas-filled container. When you inflate a balloon the air inside expands and exerts pressure on the walls of the balloon. This will increase the size of the balloon.

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What makes cells. Dont answer that I already know what it is. I just wanted to give people some points. lol have a nice day.✌

Answers

Thank you for the pointsss

Thanks for the point






A laser beam from Earth is reflected back from a mirror on the Moon in 2.60 s. If the distance between Earth and the Moon is 3.85 × 108 m, calculate the speed of light. Please show all work. (ref: p.438-446)

Answers

The formula used is related to echo formula under sound. The speed of light V is 2.9 × 10^8 m/s

What is Speed ?

Speed can simply be defined as distance travelled per time taken. it is a scalar quantity and it is measured in m/s

Given that a laser beam from Earth is reflected back from a mirror on the Moon in 2.60 s. If the distance between Earth and the Moon is 3.85 × 108 m.

The speed of light V = 2d/T

Where

d = 3.85 × 10^8 mT = 2.6 sV = ?

Substitute all parameters into the formula

V = (2 × 3.85 × 10^8) / 2.6

V = 7.7 × 10^8 / 2.6

V = 296153846.2

V = 2.9 × 10^8 m/s

Therefore, the speed of light is  2.9 × 10^8 m/s

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How much does A car of mass 1110 kg weigh

Answers

⇒ In Earth the gravitational Constant is ≅9.81

To get the weight of the car we use the formula W=m×g

where W is the letter that represents the weight

m represents the mass of the car and g represents the gravitational constant.

[tex]W=1110*9.81\\W=10889.1[/tex]

⇒Weight is a force, therefore the unit of measurement is N which stands for Newtons.

⇒The car with a mass of 1110kg weighs 10889.1 N on Earth.

Answer:

Explanation:

A car of mass 1110 kg weigh:

F = m·g

F = 1110·10 = 11100 N = 11.1 mN

The star wemadeit shows a stellar parallax angle of 0. 2 seconds of arc while the star waytoofar shows a stellar parallax angle of 0. 3 seconds of arc. From this, you can conclude that?.

Answers

We can conclude that Wemadeit is closer to our Sun than Waytoofar.

What is parallax angle ?

The parallax angle is the angle between the Earth one season of the year and the Earth six months later, as measured from a nearby star. Astronomers use this angle to determine the distance of this star from Earth. How do scientists measure this angle and from this information how do they know the distance to the star?

Since the earth revolves around the sun every year, every half year (6 months) it will be on the opposite side of what it was half a year ago. Because of this, nearby stars appear to move relative to distant "background" stars. You can see this effect when driving in the countryside. Nearby traffic signs appear to be moving fast, while distant buildings/trees, etc. appear to be moving slowly, but the sun is not moving at all! It wouldn't have happened otherwise.) Another example:

Hold the pencil at arm's length and look with one eye, then the other. Note that it changed position but didn't actually move. Your eyes model different locations on the earth. First on one side of the sun (nose), then on the other. Astronomers look up at the sky on a specific date and six months later to see how far nearby stars appear to be moving against the background. The angles at which these astronomers measure the motion of stars are actually the same angles they would see the motion of the Earth if they could travel to the stars. Scientists know how far the Earth has traveled in her six months (twice as much as the Sun does), so they have all the information they need to determine the distance to a star.

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if the mass of the ladder is 12.0 kg , the mass of the painter is 55.0 kg , and the ladder begins to slip at its base when her feet are 70% of the way up the length of the ladder, what is the coefficient of static friction between the ladder and the floor? assume the wall is frictionless.

Answers

If the painter weighs 55.0 kg and the ladder weighs 12.0 kg, and the ladder starts to slide at the base when her feet are 70% of the way up the length of the ladder, The coefficient of static friction between the ladder and the floor is 0.5.

What do you mean by static friction?

The resistance people feel when they try to move something that is stationary on a surface without actually moving their bodies or the surface they are trying to move it on.

n = F[tex]_{GY}[/tex]

F[tex]_{s} ^{max}[/tex] = F[tex]_{GX}[/tex]

F[tex]_{GY}[/tex] = μ[tex]_{s}[/tex] n

F[tex]_{GX}[/tex] = μ[tex]_{s}[/tex] F[tex]_{GY}[/tex]

Sum of horizontal forces is 0 = F[tex]_{GX}[/tex] -F[tex]_{W}[/tex] = 0

∴ F[tex]_{GX}[/tex] = F[tex]_{W}[/tex]

Sum of vertical forces is 0 = F[tex]_{GY}[/tex] - mg -Mg = 0

F[tex]_{GY}[/tex] = g (m+M)

Total torque at point a (foot of ladder) = 0

hence,

mg (1.5) + Mg(2.1) - F[tex]_{W}[/tex](4) =0

mg (1.5) + Mg(2.1) = F[tex]_{W}[/tex](4)

mg (1.5) + Mg(2.1) = F[tex]_{GX}[/tex](4)

mg (1.5) + Mg(2.1) = μ[tex]_{s}[/tex] F[tex]_{GX}[/tex](4)

mg (1.5) + Mg(2.1) = μ[tex]_{s}[/tex] g(m+M) (4)

μ[tex]_{s}[/tex] = [tex]\frac{mg (1.5) + Mg(2.1)}{4g(m+M)}[/tex]

μ[tex]_{s}[/tex] = [tex]\frac{12 (1.5) + 55(2.1)}{4(12+55)}[/tex]

μ[tex]_{s}[/tex] = 0.5

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Physics: Please Help

Answers

Answer:

6a.

7c.

8c.

9a.

10b.

11d.

Explanation:

Let me know if I made any mistakes or if you want clarification :)

) if the elevator's acceleration had a magnitude of g in the upward direction, what would the normal force fn2 be in newtons?

Answers

The reaction force applied by the floor of the elevator on the cardboard box is 93.1N.

The mass of the cardboard box is 4.75 kg.

The elevator is moving in the upward direction with an acceleration of g.

According to Newton's law of motion, each and every action has an equal and opposite reaction.

Now, the reaction force that is going to be applied on the box by the floor of the accelerating elevator will be equal to that of the weight of the box felt by the floor of the elevator.

The net acceleration of the box is (g+g),

Net acceleration = 2g.

Now, the weight W of the boc,

W =4.75(2g)

W = 4.75 x 2 x 9.8

W = 93.1 N.

The reaction force Fₙ₂ on the box is 93.1 N.

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Complete question-A cardboard box rest on the floor of the elevator. The box has a mass m = 4.75 kg and the elevator has an upward acceleration a,  if the elevator's acceleration had a magnitude of g in the upward direction, what would the normal force fn2 be in newtons?

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