Answer:
[tex]6y^1^6[/tex]
Step-by-step explanation:
I hope this has Helped :)
find the value of cosec^2 30 degree - sin^45 - sec^60
For this question, I will be writing 'csc' instead of 'cosec'
[tex]\sin 30^{\circ}=\frac{1}{2} \implies \csc 30^{\circ}=2\\\\\sin 45^{\circ}=\frac{1}{\sqrt{2}}\\\\\cos 60^{\circ}=\frac{1}{2} \implies \sec 60^{\circ}=2\\\\\\\therefore \csc^{2} 30^{\circ}-\sin^{2} 45^{\circ}-\sec^{2} 60^{\circ}=2^{2}-\left(\frac{1}{\sqrt{2}} \right)^{2}-2^{2}=\boxed{-\frac{1}{2}}[/tex]
Which function represents exponential growth?
O f(x) = 3x
O f(x) = x³
Of(x) = x + 3
O f(x) = 3x
Answer:
b step by step explanation
The function that represents exponential growth is:
f(x) = x³
What is Exponential Growth?An exponential function's curve is created by a pattern of data called exponential growth, which exhibits higher increases over time.
y = a(1+r)ˣ,
where a is the initial population and r is the rate in decimals and x is the time period.
Exponential growth is a phenomenon that occurs when the rate of change of a quantity is proportional to its current value. In other words, as the value of the quantity increases, the rate at which it increases also increases. This can be represented mathematically using an exponential function of the form f(x) = abˣ, where a is the initial value, b is the growth factor, and x is the time or number of periods.
The function that represents exponential growth is:
f(x) = x³
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Question 7
points 2
ps
sunshine house cleaners mops 1/5 square feet every 2/3 minute. what is their speed in terms of square feet
tio
per minute?
Their speed in terms of square feet per minute is 3/10 square feet per minute.
We know that the speed formula is the rate at which an object travels a given distance. Speed is defined as the distance traveled by a body in a given amount of time. Speed in the SI is measured in m/s.
Given that the distance = 1/5 square feet.
The time = 2/3 minute.
Speed = distance/time = (1/5)/(2/3) = (1/5)*(3/2) = 3/10
Therefore, we can conclude that their speed in terms of square feet per minute is 3/10 square feet per minute.
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The fuel for a lawn mower is a mixture of 8 parts petrol to one part oil. How much oil is required to make 1 litre of fuel?
The amount of oil required for 1 liter of fuel is 111.11 mL.
Fraction is the portion of a total amount where the above part of the fraction is the denominator and the bottom part of the fraction is called the numerator.
Given that the fuel is the mixture where 8 parts are petrol and 1 part is oil in the whole part of the fuel.
The total part of the fuel is 8+1=9
the portion of the petrol is = parts of petrol/total parts of the fuel= 8/9
the portion of the oil = parts of oil /total parts of the fuel= 1/9
Now we have to calculate the amount of oil required for 1 liter of fuel.
As discussed before, 1/9 parts of the fuel is oil.
So the amount of oil is= (1/9)*1 liter= (1/9)litre= 1/9* 1000 mL= 111.11 mL
Similarly, we can calculate the amount of petrol which will be
the amount of petrol= (8/9)*1 liter= (8/9) liter= 8/9*1000 mL= 888.88 mL
Therefore the amount of oil required for 1 liter of fuel is 111.11 mL.
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PLEASE HELP ASAP
thank you :)
Answer:
y = x/2 -3
Step-by-step explanation:
x - 2y = 6
Slope intercept form is y = mx+b where m is the slope and b is the y intercept
We need to solve for y
Subtract x from each side
x-2y-x = -x+6
-2y = -x+6
Divide each side by -2
-2y/-2 = -x/-2 +6/-2
y = x/2 -3
The slope intercept form is
y = x/2 -3
Answer: slope intercept form is
y = x/2 -3
Step-by-step explanation:
hope this helps ; )
me QR goes through points Q(0, 1) and R(2, 7). Which equation represents line QR?
y-1=6x
y-1=3x
y-7=2x-6
y-7=x-2
We write the equation in the form of directional.
y -1 = 6x ⇔ y = 6x + 1
y - 1 = 3x ⇔ y = 3x + 1
y - 7 = 2x - 6 ⇔ y = 2x - 6 + 7
y = 2x + 1
y - 7 = x - 2 ⇔ y = x - 2 + 7
y = x + 5
Equations cleverly arranged .
Point Q = (0,1)
b factor , not only fits the last equation
In the drawing have engraved points Q and R are tangent linear function appropriate to that point . This graphics solution . y = 3x + 1
Answer b
We check choice by the system of equations , where substitute wartoćsi points Q and R to the model equations linear function
The result of equations confirmed our choice Answer b
the bearing of two points x and y from z are 45° and 135° respectively . if |zx|=8cm and |zy|=6cm, find |xy|.
Answer:
[tex]|{\sf XY}| = 10\; {\rm cm}[/tex].
Step-by-step explanation:
Refer to the diagram attached. The dashed segment attached to [tex]\!{\sf Z}[/tex] points to the north. Rotating this segment clockwise with point [tex]{\sf Z}\!\![/tex] as the fixed center of rotation would eventually align this segment with the one between point [tex]\!\!{\sf Z}[/tex] and point [tex]\!\!{\sf X}[/tex]. The bearing of point [tex]{\sf X}[/tex] from point [tex]{\sf Z}[/tex] is the size of the angle between these two line segments when measured in the clockwise direction.
Subtract the bearing of [tex]{\sf Y}[/tex] from [tex]{\sf Z}[/tex] from the bearing of [tex]{\sf X}[/tex] from [tex]{\sf Z}[/tex] to find the measure of the angle [tex]\angle {\sf YZX}[/tex]:
[tex]\begin{aligned}\angle {\sf YZX} &= 135^{\circ} - 45^{\circ} \\ &= 90^{\circ}\end{aligned}[/tex].
Thus, triangle [tex]\triangle {\sf YZX}[/tex] is a right triangle ([tex]90^{\circ}[/tex]) with segment [tex]{\sf YX}[/tex] as the hypotenuse. It is given that [tex]|{\sf XZ}| = 6\; {\rm cm}[/tex] whereas [tex]|{\sf ZY}| = 6\; {\rm cm}[/tex]. Thus, by Pythagorean's Theorem:
[tex]\begin{aligned}|{\sf ZY}| &= \sqrt{|{\sf ZX}|^{2} + |{\sf ZY}|^{2}} \\ &= \sqrt{(8\; {\rm cm})^{2} + (6\; {\rm cm})^{2}} \\ &= 10\; {\rm cm}\end{aligned}[/tex].
bill $42 , tax 9% , tip 18%
Answer:
Tax 3.78 $ and tip 7.56 $
Step-by-step explanation:
42*0.09 = 3.78
42*0.18 = 7.56
What is 0.000345 expressed in scientific notation?
3.45 × 102
3.45 × 104
3.45 × 10–2
3.45 × 10–4
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
Expression in scientific notation :
[tex]\qquad \tt \rightarrow \:3.45 × {10}^{-4} [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: 0.000345[/tex]
[tex]\qquad \tt \rightarrow \: 0.000345 \times \cfrac{10000}{10000} [/tex]
[tex]\qquad \tt \rightarrow \: (0.000345 \times 10000) \times \cfrac{1}{10000} [/tex]
[tex]\qquad \tt \rightarrow \: 3.45 \times \cfrac{1}{10 {}^{4} } [/tex]
[tex]\qquad \tt \rightarrow \: 3.45 \times{10 {}^{ - 4} } [/tex]
[tex] \textsf{Correct option - D} [/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer:
3.45 x 10-4
Step-by-step explanation:
You have $40.00. You wish to buy a T-shirt costing $14.50. You would also like to buy a pair of jeans. There
is a 6% sales tax on clothing. What is the top tag price (excludes sales tax) you could pay for the jeans?
After how many seconds does the object reach its maximum height? 2 seconds 3 seconds 6 seconds 9 seconds
Answer:
3 seconds
proofi took the test
The object reaches its maximum height after 3 seconds.
The correct option is 3 seconds.
To find the time at which the object reaches its maximum height, we need to determine the vertex of the parabolic function[tex]h(t) = -16t^2 + 96t + 6[/tex] . The vertex form of a parabola is given by [tex]h(t) = a(t - h)^2 + k[/tex], where (h, k) represents the vertex.
In this case, a = -16, so the vertex is given by t = -b/2a. Plugging in the values, we get t = -96/(2 x (-16)) = 96/32 = 3 seconds.
Therefore, the object reaches its maximum height after 3 seconds.
Option B, 3 seconds, is the correct answer.
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The complete Question:
The function [tex]h(t) = -16t^2 + 96t + 6[/tex] represents an object projected into the air from a cannon. The maximum height reached by the object is 150 feet.
After how many seconds does the object reach its maximum height?
A. 2 seconds
B. 3 seconds
C. 6 seconds
D. 9 seconds
how many ounces of a 16% alcohol solution must be mixed with 2 ounces of a 20% alcohol solution to make a 17% alcohol solution?
Answer:
x = 6
Step-by-step explanation:
.16x + 2 * .02 = (x + 2) * .17
.16x + .4 = .17x + .34
.06 = .01x
6 = x
Evaluate:
lim h->0 (√(x+h) - √x) / h
Rationalizing the numerator, it is found the result of the limit is given as follows:
[tex]\lim_{h \rightarrow 0} \frac{(\sqrt{x + h} - \sqrt{x})}{h} = \frac{1}{2\sqrt{x}}[/tex]
What is a limit?A limit is given by the value of function f(x) as x tends to a value.
The first step to find the limit is replace the variable by the value, hence:
[tex]\lim_{h \rightarrow 0} \frac{(\sqrt{x + h} - \sqrt{x})}{h} = \frac{0}{0}[/tex]
Undefined limit, hence we have to find another way. The numerator includes square roots, hence it should be rationalized using the subtraction of perfect squares, as follows:
[tex]\lim_{h \rightarrow 0} \frac{(\sqrt{x + h} - \sqrt{x})}{h} \times \frac{(\sqrt{x + h} + \sqrt{x})}{(\sqrt{x + h} + \sqrt{x})} = \lim_{h \rightarrow 0} \frac{(\sqrt{x + h})^2 - (\sqrt{x})^2}{h(\sqrt{x + h} + \sqrt{x})} = \lim_{h \rightarrow 0} \frac{x + h - x}{h(\sqrt{x + h} + \sqrt{x})} = \lim_{h \rightarrow 0} \frac{h}{h(\sqrt{x + h} + \sqrt{x})}[/tex]
Then we simplify the h, so:
[tex]\lim_{h \rightarrow 0} \frac{1}{\sqrt{x + h} + \sqrt{x}} = \frac{1}{2\sqrt{x}}[/tex]
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What is the range of the function y=-x² +1?
A) y≤ -1
B) y²-1
C) y≤ 1
D) y≥ 1
Answer:
Option (C)
Step-by-step explanation:
The minimum value of x² is 0, and the maximum value is unbounded, so therefore, the maximum value of -x² is 0, and the minimum value is unbounded.
So, this means that adding 1 to this, the range matches with option C.
Select the correct answer.
The cost of renting a community center is $100, with an additional cost of $10 per guest.
Which graph has the most appropriate scales and units for this situation?
О А.
B.
Total Rental Cost ($)
tal Cost ($)
500
400
300
200
100
50
40
30
0
10 20 30 40 50
Number of Guests
The cost of renting a community center for x guest is given as y = 10x + 100
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
The standard linear equation is in the form:
y = mx + b
Where m is the rate of change and b is the y intercept.
Let y represent the cost of renting a community center for x guest. Hence:
y = 10x + 100
The cost of renting a community center for x guest is given as y = 10x + 100
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Answer the following
The set A satisfying the given inequality is A = (-[tex]\infty[/tex], -10].
What are some properties of an inequality relation?Following are some facts which are true for an inequality relation:
Equal numbers can be added or subtracted from both sides of an inequality without affecting the inequality sign.The Inequality sign is unchanged if both sides are multiplied or divided by a positive number, but when multiplied or divided by a negative number the inequality sign is reversed.[tex]\frac{5x-2}{8} - \frac{3x-5}{10} &\ge& x+y\\\\\Rightarrow\;\; \frac{13}{40}x + \frac{1}{4}&\ge& x+y\\\\\Rightarrow\;\;\;\;\;\; -\frac{27}{40}x &\ge & y - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\;\; -x &\ge & \frac{40}{27}\left( y-\frac{1}{4} \right).\hspace{1cm}(1)[/tex]
Since y ∈ B, -2 ≤ y ≤ 7. So,
[tex]\;\;\;\;\;\;\;\,-2 - \frac{1}{4}\; \le\; y - \frac{1}{4} \;\le\; 7 - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\; -\frac{9}{4}\; \le\; y - \frac{1}{4} \;\le\; \frac{27}{4}\\\\\Rightarrow\;\;\; -\frac{9}{4}\cdot \frac{40}{27} \;\le\; \frac{40}{27} \left( y-\frac{1}{4} \right) \;\le \;\frac{27}{4}\cdot \frac{40}{27}\\\\\Rightarrow\;\;\;\;\;\;\;\; -\frac{10}{3} \;\le\; \frac{40}{27}\left( y - \frac{1}{4} \right)\; \le\; 10.[/tex]
The set {-x | inequality (1) holds ∀ y ∈ B} is [10, [tex]\infty[/tex]) i.e.
10 ≤ -x ≤ [tex]\infty[/tex].
Multiplying -1 throughout gives
-10 ≥ x ≥ -[tex]\infty[/tex].
x, thus, lies in the range A = (-[tex]\mathbf{\infty}[/tex], -10}.
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Disclaimer: The question was incomplete. Please find the full content below.
QuestionFind the set A such that for x ∈ A
[tex]\frac{5x - 2}{8} - \frac{3x - 5}{10} \ge x + y[/tex]
∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.
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let g(x) be a vertical shift of f(x)=-x up 4 units followed by a vertical stretch by a factor of 3. Write the rule for g(x).
A function assigns the values. The function g(x) can be written as g(x) = -3x + 12.
What is a Function?A function assigns the value of each element of one set to the other specific element of another set.
Given the function f(x)=-x, now since a transformed function g(x) is produced by shifting the function 4 units upwards and vertical stretch by a factor of 3. Therefore, g(x) can be written as,
Vertical Shift by 4 units,
f(x)+4
Vertical stretch by a factor of 3
g(x) = 3(f(x) + 4)
g(x) = -3x + 12
Hence, the function g(x) can be written as g(x) = -3x + 12.
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The expression 2 (a + b) = -8.1 for certain values of a and b. Find the value of the following expressions for the same values of a and b: 4a+4b
If we put a=0 and b=-4.05 then the expression 4a+4b becomes -16.2 and when we put a=-4.05 and b=0 then the expression becomes -16.2.
Given 2 (a + b) = -8.1
Because no relationship between a and b is given so we can put any value of one variable to determine the value of another variable.
If we put a=0 in 2(a+b) =-8.1 then b=-4.05
If we put b=0 then a =-4.05.
We need to put these values in 4a+4b
when a=0 b=-4.05
4a+4b=4*0+4*-4.5
=-16.2
when b=0 and a=-4.05
4a+4b=4*-4.05+4*0
=-16.2
Hence for a=0,b=-4.5 the value of 4a+4b equals -16.2 and for a=-4.05 and b=0 the function equals -16.2.
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Find sin (ABC + 60) NEED QUICK 100 PPOINTS
Answer:
B
Step-by-step explanation:
using the addition identity for sine
sin(A + B) = sinAcosB + cosAsinB
using the sine and cosine ratios in the right triangle
sinABC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{4}{5}[/tex]
cosABC = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{3}{5}[/tex]
using the exact values
sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] , cos60° = [tex]\frac{1}{2}[/tex]
Then
sin(ABC + 60)
= sinABC cos60 + cosABC sin60
= ( [tex]\frac{4}{5}[/tex] × [tex]\frac{1}{2}[/tex] ) + ([tex]\frac{3}{5}[/tex] × [tex]\frac{\sqrt{3} }{2}[/tex] )
= [tex]\frac{4}{10}[/tex] + [tex]\frac{3}{10}[/tex] [tex]\sqrt{3}[/tex]
= [tex]\frac{2}{5}[/tex] + [tex]\frac{3}{10}[/tex] [tex]\sqrt{3}[/tex]
sin<ABc
Perpendicular/Hypotenuse4/5cos<ABC
Base/Hypotenuse3/5Now
sin(<ABC+60)sin<ABC ×cos60+cos<ABC×sin604/5(1/2)+3/5(√3/2)2/5+3/10√3Write functions for each of the following transformations using function notation. Choose a different letter to
represent each function. For example, you can use R to represent rotations. Assume that a positive rotation occurs in
the counterclockwise direction.
• translation of a units to the right and b units up
reflection across the y-axis
• reflection across the x-axis
• rotation of 90 degrees counterclockwise about the origin, point O
• rotation of 180 degrees counterclockwise about the origin, point O
• rotation of 270 degrees counterclockwise about the origin, point O
Answer:
Step-by-step explanation:
1) = f(x - a) + b
Coordinate change
(x, y) → (x + a, y + b)
2) RFy(x, y) = f(-x)
Coordinate change
(x, y) → (-x, y)
3) RFx(x, y) = -f(x)
Coordinate change
(x, y) → (-y, x)
4) RCCW90(x, y) = f⁻¹(-x)
Coordinate change
(x, y) → (-y, x)
5) RCCW180(x, y) = -(f(-x))
Coordinate change
(x, y) → (-x, -y)
6) A 270 degrees counterclockwise rotation gives;
RCCW270(x, y) = -(f⁻¹(x))
Coordinate change
(x, y) → (y, -x)
Step-by-step explanation:
1) Horizontal translation a units right = f(x - a)
The vertical translation b units up = f(x) + b
Therefore, we get; = f(x - a) + b
The coordinate change
(x, y) → (x + a, y + b)
2) A reflection across the y-axis = RFy(x, y) = f(-x)
The coordinate change
(x, y) → (-x, y)
3) A reflection across the x-axis gives RFx(x, y) → (x, -y)
Therefore, in function notation, we get;
RFx(x, y) = -f(x)
4) A 90 degrees rotation counterclockwise, we get RotCCW90(x, y) → (-y, x)
In function notation RotCCW90(x, y) = INVf(-x) = f⁻¹(-x)
5) A 180 degrees counterclockwise rotation about the origin gives;
(x, y) → (-x, -y)
Therefore, we get;
In function notation RotCCW180(x, y) = -(f(-x))
6) A 270 degrees counterclockwise rotation gives RotCCW270(x, y) → (y, -x)
In function notation RotCCW270(x, y) = -(f⁻¹(x))
Find ZABC
00
A
38⁰
32⁰
Answer:
The answer will be 38° + 32° = 70°
Please mark me as the brainliest
If a = 7 - 4√3, find the value of a + 1/a
Answer:
Step-by-step explanation:
To calculate a+1/a, we first need to calculate for a.
a = 7 - 4 * [tex]\sqrt[2]{3}[/tex]
square root of 3 = 1.73
a = 7 - 4 * 1.73
a = 7 - 6.9
a = 0.1
0.1 + 1 / 0.1 = 0.1 + 10 = 10.1
Now, in case 4 wasn't being multiplied with the square root of 3, and instead, it was four root of 3, I am gonna do the calculations again:
a = 7 - [tex]\sqrt[4]{3}[/tex]
a = 7 - 1.31
a = 5.69
5.69 + 1 / 5.69 = 5.69 + 0.17 = 5.86
Hope I Helped!
Two number cubes are rolled for two separate events:
Event A is the event
that the sum of numbers on
both cubes is less than 10.
Event B is the event that the sum of numbers on both cubes is a multiple of 3.
Complete the conditional-probability formula for
event B given that event A occurs first by writing A and B in the blanks:
Answer:
Good idea for thanks......
Question 2(Multiple Choice Worth 1 points)
(02.02 LC)
If g(x)= x² + 3, find g(4).
11
19
16
8
Answer: 19
Step-by-step explanation:
g(4) = 4² + 3
g(4) = 16 + 3
g(4) = 19
Z varies directly as x and y, z=6 when x=2 and y=6 find the value of z when x=3 and y=8
Answer:
12
Step-by-step explanation:
Direct Variation. I think it's gonna be like this.
SInce Z is not inversely to y , its varies directly to both.
Then it's,
Z=kxy, where k is constant.
subst. Z=6,x=2 and y=6.
6=k×2×6
6=k×12=12k
6=12k=½
the formula connecting them is
Z=½xy
Z=½×3×8
Z= 1×3×8÷2
Z=24÷2
Z=12.
That's my solution.
Select the true statement about triangle ABC.
13
5
12
A. sin C = sin A
B. sin C = cos B
C. sin C = tan A
D. sin C = cos A
Answer:
sin C = cos A
Step-by-step explanation:
sinC = opp/hyp
=12/13
cosA = adj/hyp
12/13
Answer the question in the screen shot
Using the continuity concept, as the value of the function has to be equal to the limit, it is found that the value of k is of k = -4.
When a function is continuous?A function is said to be continuous at x = a if, and only if:
[tex]\lim_{x \rightarrow a} f(x) = f(a)[/tex]
In this problem, we have to check at x = -2, hence:
[tex]\lim_{x \rightarrow -2} f(x) = f(-2)[/tex]
[tex]k = \lim_{x \rightarrow -2} f(x)[/tex]
For the limit, we have to check the lateral conditions, hence:
[tex]\lim_{x \rightarrow -2} f(x) = \lim_{x \rightarrow -2} \frac{x^2 - 4}{x + 2} = \lim_{x \rightarrow -2} \frac{(x - 2)(x + 2)}{x + 2} = \lim_{x \rightarrow -2} x - 2 = -2 -2 = -4[/tex]
Hence, from the continuity condition, k = -4.
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The first term of an arithmetic sequence is 1 and the sum of the first four terms is 100. Find the first four terms
Answer:
1, 17, 33, 49
Step-by-step explanation:
given the first term is 1 then the next 3 terms are
1 + d, 1 + 2d, 1 + 3d ( d is the common difference )
the sum of the first 4 terms is 100 , then
1 + 1 + d + 1 + 2d + 1 + 3d = 100 , that is
4 + 6d = 100 ( subtract 4 from both sides )
6d = 96 ( divide both sides by 6 )
d = 16
1 + d = 1 + 16 = 17
1 + 2d = 1 + 2(16) = 1 + 32 = 33
1 + 3d = 1 + 3(16) = 1 + 48 = 49
the first 4 terms are
1, 17, 33, 49
Answer:
see the file attached!!!!
An experiment consists of rolling a standard six-sided die once. Event A is "rolling a 5{}^{\prime\prime} and event B is "rolling an odd number." Are the events dependent or independent? Why? Select the option that correctly answers both questions.
O Events A and B are independent, because P(B) = P(B|A) = 1/2.
O Events A and B are independent, because P(A) = P(B|A) = 1/12.
O Events A and B are dependent, because P(A) =/ P(B|A).
O Events A and B are dependent, because P(B) =/ P(B|A).
Based on the given probability events, we can calculate that Events A and B are independent, because P(B) = P(B|A) = 1/2.
Is event B independent of event A?Events are independent if P(B) = P(B|A)
The probability of event B is:
= 3 odd numbers / 6 numbers
= 1 / 2
The probability of A is:
= 3 prime numers / 6
= 1/2
P(B|A) = ((1 / 2) x (1 / 2)) / (1 / 2)
= 1/2
So P(B) = P(B|A) = 1/2.
The events are independent.
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Consider the steps for determining the quotient of ¹24 + x4
12
X-4
The quotient will be
expression.
Complete the statements to choose a numerator and denominator to represent the quotient.
The numerator of the simplified quotient is
The denominator of the simplified quotient is
The simplified form of the expression has a numerator (x + 9)(2x + 1) and the denominator (x + 7) and the expression doesn't exist at (x = 9).
How to illustrate the quotient?The given expression is:
= [(3x² - 27x)/(2x² + 13x - 7)]/(3x/4x² - 1)
Firstly, factorize the expression 4x² - 1.
4x² - 1 = (2x - 1)(2x + 1)
Then, factorize 2x² + 13x - 7.
2x² + 13x - 7 = 2x² + 14x - x - 7
2x(x + 7) - 1(x + 7)
= (2x - 1)(x + 7)
Then, factorize the equation 3x² - 27x.
3x² - 27x = 3x(x - 9)
The factorized terms will be substituted into the equation. This will be:
= [3x(x - 9)/(2x - 1)(x + 7)] / 3x[(2x - 1)(2x + 1)]
= (x + 9)(2x + 1)/(x + 7)
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