What similarity property, if any, can be used to show that the following two triangles are similar
A. Not enough information given
B. AA
C. SAS
D. SSS
Please answer this
Answers
Related Questions
Differentiate the function.
y = (4x − 1)^2 (4 -x^5)^4
dy/dx=
Answers
Answer:
[tex]\displaystyle y' = -4(4x - 1)(4 - x^5)^3(22x^5 - 5x^4 - 8)[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightDistributive Property
Algebra I
Terms/CoefficientsFactoringCalculus
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]: [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
Step 1: Define
Identify
y = (4x - 1)²(4 - x⁵)⁴
Step 2: Differentiate
Product Rule: [tex]\displaystyle y' = \frac{d}{dx}[(4x - 1)^2](4 - x^5)^4 + (4x - 1)^2\frac{d}{dx}[(4 - x^5)^4][/tex]Chain Rule [Basic Power Rule]: [tex]\displaystyle y' = [2(4x - 1)^{2 - 1} \cdot \frac{d}{dx}[(4x - 1)]](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^{4 - 1} \cdot \frac{d}{dx}[(4 - x^5)]][/tex]Simplify: [tex]\displaystyle y' = [2(4x - 1) \cdot \frac{d}{dx}[(4x - 1)]](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot \frac{d}{dx}[(4 - x^5)]][/tex]Basic Power Rule: [tex]\displaystyle y' = [2(4x - 1) \cdot 4x^{1 - 1}](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot -5x^{5 - 1}][/tex]Simplify: [tex]\displaystyle y' = [2(4x - 1) \cdot 4](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot -5x^4][/tex]Multiply: [tex]\displaystyle y' = 8(4x - 1)(4 - x^5)^4 - 20x^4(4x - 1)^2(4 - x^5)^3[/tex]Factor: [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 2(4 - x^5) - 5x^4(4x - 1) \bigg][/tex][Distributive Property] Distribute 2: [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 8 - 2x^5 - 5x^4(4x - 1) \bigg][/tex][Distributive Property] Distribute -5x⁴: [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 8 - 2x^5 - 20x^5 + 5x^4 \bigg][/tex][Brackets] Combine like terms: [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3(-22x^5 + 5x^4 + 8)[/tex]Factor: [tex]\displaystyle y' = -4(4x - 1)(4 - x^5)^3(22x^5 - 5x^4 - 8)[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
In your own words, explain the steps you would need to take to find slope from data in a table.
Answers
Answer:
Sample Answer: Start by choosing two data points. Calculate the difference between the second y value and the first y value. Then divide that by the difference between the second x value and the first x value.
PLEASE I NEED A LOT OF HELP
Answers
Answer:
x = 45°
Step-by-step explanation:
Look at the picture*
multiply: (sqrt10 +2 sqrt8)(sqrt10-2 sqrt8)
Answers
Answer:
(√10 +2√8)(√10 -2√8)=
(10 -8√5 + 8√5 -32)
10+0-32
10-32
= -22
Hope this helps.
Answer:
The other person is right, A. -22
Step-by-step explanation:
Rod has to read a book which has p pages. He plans to read r pages each day for d days.
Write an equation for the number of pages left, b, in the book, after d days.
Answers
Answer:
Look at the attachment
The equation is an illustration of a linear function.
The equation for the number of pages left in the book is [tex]b =p- rd[/tex]
The total number of pages is:
[tex]Total = p[/tex]
The daily rate is:
[tex]Rate = r[/tex]
So, the number of pages read in d days is:
[tex]Pages = Rate \times Days[/tex]
This gives
[tex]Pages = r \times d[/tex]
Multiply
[tex]Pages = rd[/tex]
The number of pages left (b) is then calculated as:
[tex]b =Total - Pages[/tex]
So, we have:
[tex]b =p- rd[/tex]
Hence, the equation for the number of pages left in the book is [tex]b =p- rd[/tex]
Read more about linear equations at:
https://brainly.com/question/14323743
An initial population of 895 quail increases at an annual rate of 7%. Write an exponential function to model the quail population.
