When is a Pythagorean theorem true for all triangles?

Answer:

21 as a decimal: 21.00;  4/5 as a decimal: .8, 0.80

Step-by-step explanation:

Hope i helped, SJ

2 km = 1 cm

The length of the road of 15 km.

2 km = 1 cm

1 km = 1/2 = 0.5 cm

15 km = 0.5 × 15 = 7.5

The length of the road is 7.5 cm.

Therefore, Option D. 7.5 cm is correct.

Answer:

[tex]x<5[/tex]

Step-by-step explanation:

So we have the inequality:

[tex]3x-1<2x+4[/tex]

First, let's subtract 2x from both sides. The right cancels:

[tex]x-1<4[/tex]

Add 1 to both sides:

[tex]x<5[/tex]

And we're done!

Our solution is all number less than 5.

Answer:

-3 ≤ W ≤ 4

I hope this helps!

Answer:

12 3/5

Step-by-step explanation:

Answer:

12 3/5

Step-by-step explanation:

Got it right on my test.

Answer:

B) Stan made a mistake in step one.

Step-by-step explanation:

B) Stan made a mistake in step one.

When he multiplied 8(n+20), he should have gotten 8n+160, not 8n+20.

Answer:

B

Step-by-step explanation:

He made a mistake in Step: 1

it's supposed to be

n+8n+8(20)=110

distributive property

Hope this helps :)

Answer:

Kindly check explanation

Step-by-step explanation:

Given the models for the median height of biys and giels:

BOY:

f(x) = 2.9√x + 20.1

GIRL:

f(x) = 3.1√x + 19

If x = 24 months

BOY:

HEIGHT = 2.9√24 + 20.1

= 2.9× 4.8989794 + 20.1

= 14.207040 + 20.1

= 34.307 inches

GIRL:

HEIGHT = 3.1√24 + 19

= 3.1 × 4.8989794 + 19

= 15.186836 + 19

= 34.1868 inches

If x = 48

Boy:

HEIGHT = 2.9√48 + 20.1

= 2.9× 6.9282032 + 20.1

= 20.091789 + 20.1

= 40.19 inches

Actual median height = 40.8

Hence, model underestimates by (40.80 - 40.19) = 0.61 inches

Girl:

HEIGHT = 3.1√48 + 19

= 3.1 × 6.9282032 + 19

= 21.477430 + 19

= 40.48 inches

Actual median height = 40.20

Hence, model overestimates by (40.48 - 40.20) = 0.28 inches

Answer:

35,900

Step-by-step explanation:

92 is higher than 50

Answer:

People who buy the company's products or services (customers)

Step-by-step explanation:

Answer:

[tex]Area = 4x^2 - 14x + 10[/tex]

Step-by-step explanation:

See Attachment for Complete Question

Given

[tex]Width = 5mi[/tex] --- For the forest

[tex]Length = 2mi[/tex] -- --- For the forest

Required

Determine the area of the habitat

Since the distance between the animal's habitat is x mi on both sides;

The length and width of the habitat is:

[tex]Width = 5 - (x + x)[/tex]

[tex]Width = 5 - 2x[/tex]

[tex]Height = 2 - (x +x)[/tex]

[tex]Height = 2 - 2x[/tex]

The area is then calculated as follows;

[tex]Area = Width * Height[/tex]

[tex]Area = (5 - 2x) * (2 - 2x)[/tex]

Expand

[tex]Area = 5(2 - 2x) -2x(2 - 2x)[/tex]

Open Brackets

[tex]Area = 10 - 10x - 4x + 4x^2[/tex]

[tex]Area = 10 - 14x + 4x^2[/tex]

Reorder

[tex]Area = 4x^2 - 14x + 10[/tex]

Hence; the required polynomial for the habitat area is:

[tex]Area = 4x^2 - 14x + 10[/tex]

Answer:

Step-by-step explanation:

Answer:

x = 3.4

Step-by-step explanation:

[tex]10x-4.5+3x=12x-1.1\\\\10x+3x-4.5=12x-1.1\\\\13x-4.5=12x-1.1\\\\13x-4.5+4.5=12x-1.1+4.5\\\\13x=12x+3.4\\\\13x-12x=12x-12x+3.4\\\\\boxed{x=3.4}[/tex]

Hope this helps.

Answer:

i solved it .I hope you got it too

plz mark brainliest.

Answer:

Step-by-step explanation:

[tex]5^5 - 2^3\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:exponents}\:5^5\::\quad 3125\\\\=3125-2^3\\\\\mathrm{Calculate\:exponents}\:2^3\::\quad 8\\\\=3125-8\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:3125-8\:\\\\:\quad 3117[/tex]

Answer: I think it would be a 50/50 chance of getting 2 even numbers.

Answer:

The correct answer is centimeter.

Answer:

720

Step-by-step explanation:

6!/(6-6)! = 6!/0! or 6!/1

6! =720

Answer:

-2x + 6 > 10

Step-by-step explanation:

Let the unknown number be x

the product of x and -2 is -2x

6 more than -2x is written as

-2x + 6

if the result of the above is greater than 10, then

-2x + 6 > 10

Answer:

(3^2) - n

Step-by-step explanation:

For this problem we will take it step by step to build the expression:

raise 3 to the 2nd power

= 3^2

then find the difference of the result and n

= (3^2) - n

Hence, your final expression should be (3^2) - n.

Cheers.

Answer and Step-by-step explanation:

a) Statistic -the proportion of the 65 randomly selected customer

Statistic refers to the practice of gathering and examination data of numerical in a higher number of quantities, mainly for the motive of proportions inferring in a full form for that in a representative sample.

b) variable: the answer yes or no to weather.

The Variable is never being constant or a pattern of fixed; liable to change.

c) sample: The 65 customers of the hotel whose receipts the owner noticed.

Sample refers to the small part that is applied to present the whole thing

d) Data: the list of the 65 yes or no answers.

The data is the facts and the figures that are collected simultaneously

e) Population: all customer who comes to the restaurant

Population refer to a whole group of people and events

f) Parameter: the proportion of all customer who orders desert

The parameter refers to an average of a population that represents the whole population

Answer:

Length of the rectangle is 8 inches.

Step-by-step explanation:

Perimeter of rectangle = 2L + 2W

(8x+4) = 2L + 2(3x-4)  where x = 2

(8(2)+4) = 2L + 2(3(2)-4)

20 = 2L + 4

16 = 2L

8 = L

Answer:

The length of the perimeter is 8

Step-by-step explanation:

Answer:

Q2

a) 8 + - 8 = 0

b) -20 + 20 = 0

c) a+ - a = 0

Q3

3) Identity property

Answer:

1) 8 + - 8 = 0

2) -20 + 20 = 0

3) a+ - a = 0

Q3

3) Identity property

Step-by-step explanation:

Answer:

5x-10=20

5x=20-10

x=10:5

x=2

Answer:

x = 6.

Step-by-step explanation:

5x - 10 = 20

5x - 10 + 10 = 20 + 10

5x = 30

5x/5 = 30/5

x = 6.

Answer:

0.04734848484

Step-by-step explanation:

The 6.25 divided by 132 equals 0.235 (rounded to three decimal places).

To calculate 6.25 divided by 132, perform the following steps:

Step 1: Divide the whole number part.

Divide 6 by 132, which equals 0 with a remainder of 6.

Step 2: Convert the remainder to a fraction.

The remainder 6 becomes 6/132.

Step 3: Divide the fractional part.

Divide 25 by 132, which gives the fraction 25/132.

Step 4: Add the results from Step 2 and Step 3.

Combine the fractions obtained in Step 2 and Step 3: 6/132 + 25/132 = 31/132.

The final result is 0 31/132, which can be simplified to 0 7/44 or written as a decimal as approximately 0.235. Therefore, 6.25 divided by 132 equals 0.235 (rounded to three decimal places).

To know more about divided:

https://brainly.com/question/15381501

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Answer:

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let [tex]\mu[/tex] be the random variable that follows a Poisson distribution, then mean [tex]\mu = \dfrac{10}{500}= 0.02[/tex]

and the mean that the random selection of 50 pages will contain no error is [tex]\lambda = 50 \times 0.02 =1[/tex]

∴

[tex]Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}[/tex]

Pr(q =0) = 0.368

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )]    since it is less than 2

[tex]P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ][/tex]

[tex]P(X \geq 2) = 1 - [0.3678 +0.3678][/tex]

[tex]P(X \geq 2) = 1 -0.7356[/tex]

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

The possibility of a random selection of 50 pages will contain at least two errors is [tex]0.264242[/tex].

To understand the calculations, check below

Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur i.e., how likely they are to happen, using it.

Let [tex]X[/tex] denotes the number of errors on [tex]50[/tex] randomly selected pages.

[tex]X\sim Poisson(\frac{50}{500}\ast 10)[/tex] or [tex]X\sim Poisson(1)[/tex]

The probability mass function of [tex]X[/tex] is,

[tex]P\left ( X=x \right )=\frac{e^{-1}\ast 1^{x}}{x!}=0,1,2...[/tex]

Now,

The probability that a random selection of [tex]50[/tex] pages will contain no errors,

[tex]=P\left ( X=0 \right ) \\ =\frac{e^{1}\ast 1^{0}}{0!} \\ =0.367879[/tex]

Learn more about the topic of Probability: https://brainly.com/question/19032615

Answer:

(3/2)x=4

Step-by-step explanation:

Pretty self explanatory. X is the number.

Answer:

1200% I think hats what the calculator says

Step-by-step explanation:

Answer:

We conclude that the proportion has increased owing to decreased parking spaces in the downtown district.

Step-by-step explanation:

We are given that the department of transportation in a particular city knows from past records that 27% of workers in the downtown district use the subway system each day to commute to and from work.

A random sample of 130 workers in the downtown district showed that 49 used the subway daily.

Let p = population proportion of workers in the downtown district use the subway system each day to commute to and from work.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]p \leq[/tex] 27%    {means that the proportion has decreased or remain equal owing to decreased parking spaces in the downtown district}

Alternate Hypothesis, [tex]H_A[/tex] : p > 27%    {means that the proportion has increased owing to decreased parking spaces in the downtown district}

The test statistics that will be used here is One-sample z-test statistics for proportions;

                           T.S.  = [tex]\frac{\hat p-p}{\sqrt{\frac{p(1- p)}{n} } }[/tex]  ~  N(0,1)

where, [tex]\bar X[/tex] = sample proportion of workers who used the subway daily = [tex]\frac{49}{130}[/tex] = 0.38

n = sample of workers = 130

So, the test statistics =  [tex]\frac{0.38-0.27}{\sqrt{\frac{0.27(1-0.27)}{130} } }[/tex]

                                     =  2.825  

The value of z-test statistics is 2.825.

Now, at a 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 2.825 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the proportion has increased owing to decreased parking spaces in the downtown district.