Where is UTC the local time?

In the gaseous state,  particles transfer significant amounts of energy by both conduction and convection.

The term convection refers to a pattern of heat transfer in which there is the movement of a significant amount of matter. In convection, the particles of a fluid are moved from one point to another.

Thus, in the gaseous state,  particles transfer significant amounts of energy by both conduction and convection.

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Answer:

two wavelength are present

as wavelength is counted either from crest to crest or trough to trough and there are only 2

The cut off frequency of the magnesium atom is obtained as 8.9 * x 10^18 Hz.

The cut off frequency is the lowest frequency of the incident ray at which photoelectric effect occurs.

Given that;

1 eV  gives 1.60 x 10-19 J

3.70 eV  gives 3.70 eV * 1.60 x 10-19 J/1 eV

= 5.92x 10^-19 J

Now;

Wo = hfo

fo = Wo/h

fo = 5.92x 10^-19 J/6.6 * 10^-34

fo = 8.9 * x 10^18 Hz

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Explanation:

Light Light from a moving source travels at 300,000 km/sec (186,000 miles/sec).

Note:

The Speed of Light Is Constant.

Explanation:

LIGHT TRAVELS AT A CONSTANT VELOCITY OF 300,000 km/sec.

b. The wavelength of light emitted by the object is 233 nm

c. The type of radiation originally emitted by the object is ultraviolet radiation.

To find the wavelength, we need to know what redshift is.

Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.

Redshift is given by z = λ'/λ - 1 where

Making λ subject of the formula, we have

λ = λ'/(1 + z)

Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).

So,

Substituting the values of the variables into the equation, we have

λ = λ'/(1 + z)

λ = 2μm/(1 + 7.6)

λ = 2μm/8.6

λ = 0.233 μm

λ = 233 nm

So, the wavelength of light emitted by the object is 233 nm

Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.

So, the type of radiation originally emitted by the object is ultraviolet radiation.

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Answer:

Correct option is A)

Weight on earth = 600N

Let g= 10m/s2 on earth

Mass on earth = 10600=60 kg

Now, since mass is a constant quantity so, it will remain 60 kg on the moon also.

Now, weight on moon = mg′

m= mass =60 kg

g′ = acc. due to gravity on moon = 61th the value on earth

So, Weight on moon = 61th of the weight on earth 

⇒ Weight on the moon =600×61=100 N

The quantity of heat required to raise the temperature of the water is approximately 35,500 J.

The quantity of heat required to raise the temperature of the water is calculated as follows;

H = mcΔθ

H = 100 x 4.18 x 85

H = 35,530 J

Thus, the quantity of heat required to raise the temperature of the water is approximately 35,500 J.

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Answer:

[tex]\fbox {F: +3C, G: +3C}[/tex]

Explanation:

When two conducting spheres come in contact, their charges will become the mean of their charges. This takes place by the transfer of charges from the greater charged sphere to the lesser charged one.

Then :

⇒ F + G / 2

⇒ -14 + 20 / 2

⇒ 6/2

⇒ 3C

∴ Hence, both sphere F and sphere G will have a charge of +3 C.

Human response times are eliminated from time measurement using light gates. if the stopwatch is damaged, the data logger terminates it.

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its si unit is m/sec.

To measure the speed of a toy automobile, it is preferable to utilize light gates and a computer as opposed to a stopwatch and a ruler.

Because Light gates eliminate the effects of human reaction delays for measuring time. is damaged,

The stopwatch is stopped by the data logger. With no reaction time, the uncertainty is substantially reduced.

The average speed may be determined by measuring the distance between the two light gates.

Hence, it is better to use light gates and a computer than to use a stopwatch and a ruler to measure the speed of a toy car.

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19.8 N force is tending to lift Rover vertically off the ground.

The horizontal velocity component ([tex]v_{x}[/tex]) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component ([tex]v_{y}[/tex]) describes the influence of the velocity in displacing the projectile vertically.

According to the question,

The women pulls the dog with a force of 30 N at an angle of  29° from the horizontal.

Horizontal component=  30cos(29°) = 22.2 N

Vertical component = 30sin(29°) = 19.8 N

Therefore,

The horizontal component would tend to make the dog move forward and the vertical component would tend lift it off the ground.

Hence,

19.8 N force is tending to lift Rover vertically off the ground.

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Answer:

calcite

Explanation:

The cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.

The height of the cliff = 57m

The horizontal distance from the cliff = 2.15m

The time is taken = 4.3s

The acceleration due to gravity g = 9.81m/s²

Consider the vertical y-axis

                    d = ut +1/2gt²

                   57 = u (4.3) + 1/2 (9.81) (4.3)²

                   57 = 4.3u + 90.69

                    u = -7.836m/s

The y component of initial velocity is in the upwards direction

Consider the horizontal x-axis

                    d = ut

                    2.15 = u (4.3)

                    u = 0.5 m/s

The net velocity is the square root of the summation of the squares of the x and y components of velocity

Net velocity = 7.85m/s

For the direction, tan θ = y/x = 15.67

θ= 86°

So the cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.

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The upthrust experienced by the cube of metal is determined as 7.84 N.

The upthrust experienced by the body is calculated as follows;

Fu = ρVg

where;

S.G = density of the body / density of water

density of the body = S.G x density of water

ρ = 0.8 x 1000 kg/m³

ρ = 800 kg/m³

V = L³

V = (0.1)³

V = 0.001 m³

Upthrust = ρVg

Upthrust = 800 x 0.001 x 9.8

Upthrust = 7.84 N

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The initial velocity and the height of this building are 29 m/s and 780 meters respectively.

In order to calculate the initial velocity, we would apply the second equation of motion:

S = ut - ½at²

200 = u10 - ½(9.8 × 10²)

200 = u10 - 490

u10 = 490 - 200

u10 = 290

u = 290/10

Initial velocity, u = 29 m/s.

Next, we would determine the height of the building:

H = ut + ½at²

H = 29(10) + ½(9.8 × 10²)

H = 290 + 490

Height, H = 780 meters.

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Answer:

a. Displacement=30²+5²=925= 30.4m

b. Total distance=30m+5m=35m

c. V=s/t. = 30.4/45=0.6m/s

Answer:

C

Explanation:

velocity is a vector unit, meaning it isn't scalar so also gives direction, same as distance vs. displacement.

Answer:

B.1/2v1 that's the answer

As the mass of the central star increases, the distance to the habitable zone increases and the size (width) of the habitable zone increases.

A star is a large luminous object found in space which produces heat and light energy as well as electromagnetic radiation.

The habitable zone of a star is the zone or area where liquid water can be found.

The distance habitable zone of a star increases with increase in mass of the star.

Therefore, as the mass of the central star increases, the distance to the habitable zone increases and the size (width) of the habitable zone increases.

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Answer:

Weight it in beam balance or any other weight mesuring device

Answer:

See below

Explanation:

vertical velocity=13.9 sin 25

When it hits the ground  y = 0

0 = vo t - 1/2 a t^2

0    =  13.9 sin 25  t   - 1/2 (9.81)t^2  

0 = 13.9 sin 25 - 1/2 (9.81) t        shows t = 1.1976  ~ 1.2 sec

horizontal speed x time = distance

13.9 cos 25   x   1.1976 =15 .1 meters    

At any crime scene, the two greatest challenges to the physical evidence are contamination and loss of continuity.

In evidence law, physical evidence (also called real evidence or material evidence) is any material object that plays some role in the matter that gave rise to the litigation, introduced as evidence in a judicial proceeding (such as a trial) to prove a fact in issue based on the object's physical characteristics.

The two types of evidence at crime scenes:

Biological evidence (e.g., blood, body fluids, hair and other tissues)

Latent print evidence (e.g., fingerprints, palm prints, footprints)

The biggest impediment to an investigation is the removal or loss of a piece of evidence from the scene of a crime.

Hence, at any crime scene, the two greatest challenges to the physical evidence are contamination and loss of continuity.

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The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²

The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

[tex]B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}[/tex]

where;

m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)

m = 1.2 Am²

The complete question is below:

What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.

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Answer:

5.15 when the angle of incidence is equal to critical angle the angle of reflection is equal to 90 if the angle of incidence is bigger than the critical anger the reflected ray will not emerge from the medium but will be reflected back into the medium this is called total internet reflection

Explanation:

hope it's helpful

The centripetal acceleration of the tip of the fan blade is 96.23 m/s²

The acceleration developed when a body is moving in circular way, directed towards the center of the circular path.

The tip of a fan blade is 0.61 m from the center of the fan. the fan turns at a constant speed and completes 2 rotations every 1.0 s

ac = ω²r

where ω = angular speed = 2πN/60, N = Rotation per minute

From the question, N = 2 x 60/1 = 120  RPM

So, the angular speed will be

ω = 2π x 120 /60

ω  = 12.56 rad/s

Then, the centripetal acceleration is

ac =  (12.56)² x   0.61 m

ac = 96.23 m/s²

Thus, centripetal acceleration of the tip of the fan blade is 96.23 m/s²

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Answer:

B. Use oxygen to convert a fuel to heat and light energy.

What is combustion?

Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives off heat. The original substance is called the fuel, and the source of oxygen is called the oxidizer.

The fuel can be a solid, liquid, or gas, although for airplane propulsion the fuel is usually a liquid.

For example, charcoal is combining with oxygen.

Combustion is commonly called burning, and the substance that burns is usually referred to as fuel.

To summarize,

For combustion to occur three things must be present:

As a result of combustion, exhausts are created and heat is released. You can control or stop the combustion process by controlling the amount of the fuel available, the amount of oxygen available, or the source of heat.

Therefore,

Combustion is when you use oxygen to convert a fuel to heat and light energy.

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The velocity of the ball going when it reaches the base of the hill will be 5.5 m/sec.

The change of distance concerning time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The complete question is;

A 10 kg ball is released from the top of a hill. How fast is the ball going when it reaches the base of the hill? Approximate g as 10 m/s2 and round the answer to the nearest tenth.

hy = 2 m

h = 0.5 m

The given data in the problem is

m is the mass of block =  10 Kg

u is the initial velocity of fall = 0 m/sec

h is the distance of fall =  2.5 m

g is the acceleration of free fall =10 m/sec²

v is the hitting velocity of =?

According to Newton's third equation of motion;

[tex]\rm v^2=u^2+2g(h_2-h_1) \\\\ \rm v^2=0+2g(h_2-h_1) \\\\ v = \sqrt{2g(h_2-h_1)}\\\\ v = \sqrt{2 \times 9.81 \times (2-0.5)|}\\\\ v =\sqrt{2 \times 9.81 \times 1.5 } \\\\ v = 5.5 \ m/sec[/tex]

Hence, the velocity of the ball going when it reaches the base of the hill will be 5.5 m/sec.

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Virtual reality is the observation method that exposes people to frustrations, temptations, pressure, and boredom in a controlled environment, and is used for firearms training in police departments.

Virtual reality is an observation technique that is utilized in police agencies for weapons training. It exposes individuals to frustrations, temptations, pressure, and boredom in a controlled setting.

Police officers' psychophysiological reactions are impacted when participating in virtual reality weapons training exercises.

Electroencephalographic (EEG) and heart rate variability (HRV) measurements, as well as VR simulator performance metrics, are used as outcome measures.

In order to facilitate the design of a biocybernetic adaption layer that generates real-time modulations in simulation difficulty based on specific physiological responses, we propose a psychophysiological model.

Hence, virtual reality is the observation method that exposes people.

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Adlerian therapy is a method in which a therapist collaborates with a client to pinpoint challenges and develop successful solutions for achieving their objectives.

Key Takeaways: Adlerian Therapy

Individual therapy, often known as Adlerian therapy, places an emphasis on the patient's capacity to effect good change in his or her own life.

Adlerian therapy consists of four stages: engagement, assessment, insight, and reorientation.

In Adler’s theory, individuals work to overcome feelings of inferiority and to act in ways that benefit the social interest.

Four Stages of Adlerian Therapy :

Engagement

Assessment

Insight

Reorientation

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When the forces are said to be balance, it means that net force is zero.

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

The resultant of all the forces in horizontal and vertical direction is zero, when the forces are balanced.

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