[tex]\boxed{ \sf{Answer}} [/tex]
[tex] \sf \: 3(3x - 4) - 5(x + 3) \\ \sf =( 3 \times 3x) - (3 \times 4) + ( - 5 \times x) +( - 5 \times 3 ) \\ \sf = 9x - 12 - 5x - 15 \\ \sf = 9x - 5x - 12 - 15 \\ = \underline{ \bf 4x - 27}[/tex]
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
[tex]\\ \sf\longmapsto 3(3x-4)-5(x+3)[/tex]
[tex]\\ \sf\longmapsto 9x-12-5x-15[/tex]
[tex]\\ \sf\longmapsto 9x-5x-15-12[/tex]
[tex]\\ \sf\longmapsto (9-5)x-27[/tex]
[tex]\\ \sf\longmapsto 4x-27[/tex]
Are 3(3x - y) and 12 ( x - 4y ) equivalent expression?
Answer:
No, they are not.
Step-by-step explanation:
If you distributed 12(x - 4y), you would get 12x - 48y. If you distributed 3(3x-y), you would get 9x- 3y. 12x - 48y and 9x - 3y are not equivalent. Hope this helped!
Tìm diện tích của mặt. Phần mặt x2+y2+z2=9 nằm bên trên mặt phẳng z=1.
If you're familiar with surface integrals, start by parameterizing the surface by the vector-valued function,
r(u, v) = 3 cos(u) sin(v) i + 3 sin(u) sin(v) j + 3 cos(v) k
with 0 ≤ u ≤ 2π and 0 ≤ v ≤ arccos(1/√8).
Then the area of the surface (I denote it by S) is
[tex]\displaystyle\iint_S\mathrm dA = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}\left\|\dfrac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm dv\,\mathrm du \\\\ = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}9\sin(v)\,\mathrm dv\,\mathrm du \\\\ =18\pi \int_0^{\arccos\left(1/\sqrt8\right)}\sin(v)\,\mathrm dv = \boxed{\frac{9(4-\sqrt2)\pi}2}[/tex]
Find the missing segment in the image below
Answer:
Step-by-step explanation:
Select all correct answers
What are the solution to this equation
-7+(x^2-19)^3/4=20
Correct options are -10 and 10
-7 + (-10² - 19)³/⁴ = 20
-7 + (100 - 19)^3/4 = 20
-7 + (81)^3/4 = 20
-7 + 27 = 20
20 = 20
RHS = LHS
-7 + (10² - 19)^3/4 = 20
-7 + (100 - 19)^3/4 = 20
-7 + (81)^3/4 = 20
-7 + 27 = 20
20 = 20
RHS = LHS
Rest options are incorrect
Answered by Gauthmath must click thanks and mark brainliest
Answer:
B and C, so 10 and -10
Step-by-step explanation:
In a residual plot against x that does NOT suggest we should challenge the assumptions of our regression model, we would expect to see a _____. a. parabolic band of points b. band of points having a slope consistent with that of the regression equation c. horizontal band of points centered near 0 d. widening band of points
Answer:
In a residual plot against x that does NOT suggest we should challenge the assumptions of our regression model, we would expect to see a _____.
c. horizontal band of points centered near 0
Step-by-step explanation:
This residual graph or plot shows the residual values (or the difference between the observed y-value (from scatter plot) and the predicted y-value (from regression equation line) on the vertical axis and displays the independent variable on the horizontal axis. A linear regression model becomes appropriate for a dataset when the points are randomly dispersed around the horizontal axis near 0; otherwise, a nonlinear model becomes more appropriate.
Change to cylindrical coordinates. 3∫−3 9-x^2∫0 9−x^2-y^2∫x^2+y^2 dz dy dx
I think the given integral reads
[tex]\displaystyle \int_{-3}^3 \int_0^{9-x^2} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
In cylindrical coordinates, we take
x ² + y ² = r ²
x = r cos(θ)
y = r sin(θ)
and leave z alone. The volume element becomes
dV = dx dy dz = r dr dθ dz
Then the integral in cylindrical coordinates is
[tex]\displaystyle \boxed{\int_0^\pi \int_0^{(\sqrt{35\cos^2(\theta)+1}-\sin(\theta))/(2\cos^2(\theta))} \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta}[/tex]
To arrive at this integral, first look at the "shadow" of the integration region in the x-y plane. It's the set
{(x, y) : -3 ≤ x ≤ 3 and 0 ≤ y ≤ 9 - x ²}
which is the area between a paraboloid and the x-axis in the upper half of the plane. So right away, you know θ will fall in the first two quadrants, so that 0 ≤ θ ≤ π.
Next, r describes the distance from the origin to the parabola y = 9 - x ². In cylindrical coordinates, this equation changes to
r sin(θ) = 9 - (r cos(θ))²
You can solve this explicitly for r as a function of θ :
r sin(θ) = 9 - r ² cos²(θ)
r ² cos²(θ) + r sin(θ) = 9
r ² + r sin(θ)/cos²(θ) = 9/cos²(θ)
(r + sin(θ)/(2 cos²(θ)))² = 9/cos²(θ) + sin²(θ)/(4 cos⁴(θ))
(r + sin(θ)/(2 cos²(θ)))² = (36 cos²(θ) + sin²(θ))/(4 cos⁴(θ))
(r + sin(θ)/(2 cos²(θ)))² = (35 cos²(θ) + 1)/(4 cos⁴(θ))
r + sin(θ)/(2 cos²(θ)) = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))]
r = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))] - sin(θ)/(2 cos²(θ))
Then r ranges from 0 to this upper limit.
Lastly, the limits for z can be converted immediately since there's no underlying dependence on r or θ.
The expression above is a bit complicated, so I wonder if you are missing some square roots in the given integral... Perhaps you meant
[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
or
[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{\sqrt{9-x^2-y^2}} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
For either of these, the "shadow" in the x-y plane is a semicircle of radius 3, so the only difference is that the upper limit on r in either integral would be r = 3. The limits for z would essentially stay the same. So you'd have either
[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]
or
[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{\sqrt{9-r^2}} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]
In how many ways can a committee of 3 men and 2 women can be formed from 7 men and 5 women?
Answer:
in five (5) ways a committee can be formed from 7 men and 5 women
mr albernathy perchases a selection of wrenches for his shop. his bill was $78. he buys the same number of $1.50 wrenches and $2.50 wrenches, and half as may $4 dollars wrenches. the number of $3 wrenches is one more than the number of $4 dollars wrenches. how many of each did he purchase?
Answer:
Mr. Abernathy purchased 10 of $1.50 wrenches, 10 of $2.50 wrenches, 5 of $4 wrenches and 6 of $3 wrenches.
Step-by-step explanation:
Given the data, identity the type of data for each variable. (For example, determine whether the variable Day is categorical or quantitative data). Which variable is most appropriate to summarize using ungrouped frequency distributions
Answer:
Kindly check explanation
Step-by-step explanation:
The variables in the heavenly chocolate dataset is attached below :
Variables are classed as either Categorical or Quantitative.
Categorical variables are used for non - numeric variables which are used to group values based on labels whole quantitative variables are those which are numeric.
Therefore, the variables ;
Customer = Quantitative (represented with number values)
Day = Categorical (Non-numeric)
Browser = Categorical (Non - numeric)
Time = Quantitative (contains numeric values)
Pages viewed = Quantitative (contains numeric values)
Amount spent = Quantitative (contains numeric values)
Quantitative variables are most appropriate to summarize using ungrouped frequency as the attributed of the data can be adequately ibtia Ed without have to seperates or place data into categories.
If 10 wholes are divided into pieces that are one half of a whole each how many pieces are there?
9514 1404 393
Answer:
20
Step-by-step explanation:
A whole can be divided into two pieces that are each 1/2 of the whole.
(10 wholes) × (2 pieces per whole) = 20 pieces
Find the smallest possible value of x+y so that x^2 − y^2 is divisible by 74, where x and y are positive integers.
Answer: 2
Step-by-step explanation:
We know by different of squares, (x-y)(x+y)=74. Since we need to find the smallest possible answer for x+y, we let x+y=2, where both x and y = 1.
Write 55% as a fraction in simplest form
Answer:
11/20
Step-by-step explanation:
What is the value of…
–13
–12
12
13
Answer:
-12
Step-by-step explanation:
that is b
72a^7/-9 as a monomial
Answer:
− 8 a ^7
Step-by-step explanation:
See picture for steps :)
A researcher would like to investigate whether or not there is a difference in IQ between Psychology and History majors. She gathers 16 students (8 whose major is Psychology, and 8 whose major is history) and has them all take an IQ test to test this hypothesis using an alpha level of .01. Below are the data: Psych History
110 90 120 98 100 100 90110 124 100 102 120 110 110 123 120
a. What is the appropriate test?
b. State the null hypothesis:
c. State the alternative hypothesis:
d. Find the critical value:
e. Calculate the obtained statistic:
f. Make a decision:
g. What does your decision mean?
Answer:
Paired t test
H0 : μd = 0
H1 : μd > 0
Critical value = 3.499
Test statistic = 2.230
Reject H0 if test statistic > Critical value
Kindly check explanation.
Step-by-step explanation:
Given the data :
110 90 120 98 100 100 90 110
124 100 102 120 110 110 123 120
The hypothesis :
H0 : μd = 0
H1 : μd > 0
Tcritical value, df = n - 1 = 8 - 1 = 7
Tcritical(0.01, 7) = 3.499
The difference, d = (-14,-10,18,-22,-10,-10,-33,-10)
The test statistic :
Xdbar / Sd/√n
The mean difference, Xdbar = Σx / n = - 11.375
The standard deviation of difference, Sd = 14.431
The test statistic :
-11.375 / (14.431/√8) ;
-11.375 / 5.102
= 2.230
Decison :
Reject H0 if test statistic > Critical value
Since ; 2.230 <3.499 ;
We fail to reject the null
Find the area of a circle with a radius of 6 ft. Round off your answer to one decimal point. (The formula for the area of a circle is A = ar?)
Answer:
Using 3.14 for pi A = 113.0 ft^2
Using the pi button A = 113.1 ft^2
Step-by-step explanation:
The area of a circle is given by
A = pi r^2
A = pi ( 6)^2
A = 36 pi
Using 3.14 for an approximation for pi
A = 36(3.14) = 113.04
To 1 decimal
113.0
Using the pi button
A = 113.0973355
A = 113.1
A researcher wants to better understand the health benefits of eating vegetables. In a study he finds 300 adults aged 45-60 who eat at least 3 servings of vegetables a day on average. He finds another 200 adults who eat less than 3 servings of vegetables a day on average. The researcher looks at rates of cancer and heart disease in each group and compares both groups. In another study, the researcher finds 500 adults aged 45-60 who eat less than 3 servings of vegetables a day on average, and are willing to participate in a study. The researcher randomly assigns 250 of these adults to a diet which includes 4 servings of vegetables a day. The other 250 continue their usual habits. After 4 years, the rates of cancer and heart disease between the two groups are compared
Identify the statement that correctly states the reason for considering the first study as an observational study and second study as an experiment.
a. In the first study, the treatment is not imposed on the subjects, whereas in the second study the treatment is imposed on the subjects.
b. In the first study, the treatment is not imposed on every subject, whereas in the second study the treatment is imposed on every subject.
c. In the first study, the subjects were not randomly chosen, whereas in the second study the subjects were randomly assigned.
Answer:
a. In first study, the treatment is not imposed on the subjects, whereas in the second study the treatment is imposed on subjects.
Step-by-step explanation:
In the first study, observation are made on 300 adults who eat 3 servings of vegetables a day on average. The second study has further intensified the research which imposed treatment on the subjects. The random samples of adults are observed in both studies.
round 12.5478 to the nearest hundredths
Answer:
12.04
Step-by-step explanation:
Find the number in the hundredth place 4 and look one place to the right for the rounding digit 1 . Round up if this number is greater than or equal to 5 and round down if it is less than 5 .
Find mPMA + mCMT. Please help..
PMA = 37
CMT = 101 - 54 =47
Total = 37 + 47 = 84
Answer: A. 84
log13 X + log13 (12x-1)=1
Solve for x by simplifying both sides of the equation, then isolating the variable.
x ≈ 0.13893498
the art club held a show for 2 days a total 269 people attended the show. On the second day, 15 more people attended than had come to the show the first day how many people attended on the first day?
Answer:
127 peopleStep-by-step explanation:
Number of attendees the first day = x.
Solve the following equation for x:
x + (x + 15) = 2692x = 269 - 152x = 254x = 254/2x = 127Is this the correct answer?
Answer:
25.40
Step-by-step explanation:
tickets ( 2 at 10.95 each) = 2* 10.95 = 21.90
popcorn ( 1 at 7.50) = 7.50
Total cost before discount
21.90+7.50=29.40
subtract the discount
29.40-4.00 =25.40
Answer:
Yep! That's correct!
Step-by-step explanation:
We know that Marilyn and her sister are each getting a ticket that cost $10.95. They are also getting a $7.50 popcorn to share. Let's add those values up.
(10.95 * 2) + 7.50 {Multiply 10.95 by 2 to get 21.90.}
21.90 + 7.50 {Add 7.50 to 21.90 to get 29.40}
$29.40 (without the credit) in toal
A credit on a movie reward card functions as a discount, so what we need to do next is subtract 4 from 29.40. That will get us $25.40 as the total cost.
After doing the math, I can deduce that your answer is correct!
Ray’s weight increased by 11% in the last two years. If he gained 16.5 pounds, what was his weight two years ago?
Answer:
Ray weighed 150 pounds two years ago.
Step-by-step explanation:
11/100 = 16.5/x
11x = 16.5(100)
11x = 1,650
(11x)/11 = (1,650)/11
x = 150
About time that he should start going to the gym!
Write the piecewise defined function for the total cost of parking in the garage. That is, state the function C(x), where x is the number of hours a car is parked in the garage.
Answer:
[tex]C(x) = \left[\begin{array}{ccc}4x &0 \le x \le 2& \\4 +2x &2 < x \le 6& \\16 &6<x\le 8& \end{array}\right[/tex]
Step-by-step explanation:
Given
See attachment for question
Required
The piece-wise function
From the attachment, we have:
(1) $4/hr for first 2 hours
This is represented as:
[tex]C(x) = 4x[/tex]
The domain is: [tex]0 \le x \le 2[/tex]
(2) $2/hr for next 4 hours
Here, we have:
[tex]Rate = 2[/tex]
The total cost in the first 2 hours is:
[tex]C(x) = 4x[/tex]
[tex]C(2) = 4*2 = 8[/tex]
So, this function is represented as:
[tex]C(x) = C(2) + Rate * (Time - 2)[/tex] ----- 2 represents the first 2 hours
So, we have:
[tex]C(x) = C(2) + Rate * (Time - 2)[/tex]
[tex]C(x) =8 + 2(x - 2)[/tex]
Open brackets
[tex]C(x) =8 + 2x - 4[/tex]
Collect like terms
[tex]C(x) =8 - 4+ 2x[/tex]
[tex]C(x) =4+ 2x[/tex]
The domain is:
[tex]2 < x \le 2 + 4[/tex]
[tex]2 <x \le 6[/tex]
(3) 0 charges for the last 2 hours
The maximum charge from (2) is:
[tex]C(x) =4+ 2x[/tex]
[tex]C(6) = 4 + 2*6[/tex]
[tex]C(6) = 4 + 12[/tex]
[tex]C(6) = 16[/tex]
Since there will be no additional charges, then:
[tex]C(x) = 16[/tex]
And the domain is:
[tex]6 < x \le 8[/tex] --- 8 represents the limit
So, we have:
[tex]C(x) = \left[\begin{array}{ccc}4x &0 \le x \le 2& \\4 +2x &2 < x \le 6& \\16 &6<x\le 8& \end{array}\right[/tex]
Help please. I need the answer
Answer:
y=-2/3x+6
Step-by-step explanation:
Graph it
Answer:
y= -2/3 x + 6
Step-by-step explanation:
1. In the graph, you can see the points (0,6) and (6,2)
2. Since you have all the available options, you can input both points into all equations.
3. In this case, the correct answer is y= -2/3 x + 6
Which expression is equivalent to 5y^-3?
Answer:
5/y^3
Step-by-step explanation:
which expression is equivalent to 5y^-3
for example a^-1 = 1/a
5y^-3 = 5/y^3
a new automobile cause 11300 which is 100 more than 25 times a certain number what is the number
Answer:
25x + 100 = 11300
25x = 11200
448 = x
Step-by-step explanation:
the certain number is 448
how many itegers from 15 to 85, inclusive are multibles of 8
Answer:
9
Step-by-step explanation:
First multiple of 8 in that range is 8(2)=16.
The last multiple of 8 in that range is 8(10)=80.
So we just need to find how many numbers there are between 2 and 10. inclusive.
10-2+1=9
It's also not that long to write out and count.
1-2
2-3
3-4
4-5
5-6
6-7
7-8
8-9
9-10
9 numbers there are
Multiply those 9 numbers by i you will have all multiples of 8 btw 15 and 85.
8(2)=16
8(3)=24
8(4)=32
8(5)=40
8(6)=48
8(7)=56
8(8)=64
8(9)=72
8(10)=80
What is the domain of the following function?
Answer:
the domain is all real numbers except x=3
Step-by-step explanation:
The domain is the values that x can take
X can be all real number except when the denominators equal zero
x-3 ≠ 0
x≠3
the domain is all real numbers except 3
What is the slope line that passes through the points (10, 8) and (-15, 18)? Write your answer in simplest form
Answer: [tex]y=-\frac{2}{5}x+12[/tex]
y = mx + b
m = slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{18-8}{-15-10}=\frac{10}{-25}=\frac{2(5)}{-5(5)}=-\frac{2}{5}[/tex]
The y-intercept(b) can be found by substituting a point into the function.
[tex]y = -\frac{2}{5}x + b \\\\8=-\frac{2}{5}(10) + b\\\\8=-4+b\\\\b=8+4=12[/tex]
Therefore, the function is:
[tex]y=-\frac{2}{5}x+12[/tex]
