Which elements are not likely to bond with other elements? Why

Answer: Probably why are you wearing it and why do you have it on

Explanation:

Answer:

remove it, tuck it under ur shirt

Explanation:

Answer:

5 is the correct answer of this

Answer:

m=2.0796kgmass or 20.3938N

Explanation:

m=Fa/K

convert 50N to Kg = 50N( .10197kg/1N) cancel N = 5.0958kgf

m= 5.0958kgf(4m/s²) all over K

k= 9.8066(kgm•m/kgf•s²)

m= 5.0958kgf(4m/s²) all over 9.8066 kgm•m/kgf•s²)

m= 2.0796kgm

in Newton

m= 20.3938N..

sana tama.

To rearomatize the ring system is the driving force for losing a proton as the last step in electrophilic aromatic substitution.

An atom that is connected to an aromatic ring is replaced with an electrophile in electrophilic aromatic substitution processes. Examples of these reactions include Friedel-Crafts reactions, aromatic nitrations, and aromatic sulphonations. An electrophile displaces a functional group in a molecule, which is generally, but not always, aromatic, in an electrophilic substitution process. Aromatic compounds are known for their aromatic substitution reactions, which are frequently used to introduce functional groups into benzene rings.

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Carbon with sp³-hybrid orbitals is the least electronegative.

Electronegativity (χ) is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.

Carbon can form chemical bonds with sp, sp² and sp³-hybrid orbitals.

The more percentage s-orbital in hybrid orbitals of carbon, the greater is the electronegativity of the carbon atom.

sp³-hybrid orbital has 25% character of s-orbital, so it is the least electronegative.

sp²-hybrid orbital has 33% character of s-orbital.

sp-hybrid orbital has 50% character of s-orbital.

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Answer:

Tetravalent atom or tetra-atom

In a sample of dichloromethane intermolecular forces that will be present are dispersion interactions and dipole - dipole forces.

There are two kinds of Van der Waals forces: weak dispersion interactions and stronger dipole-dipole forces.

Intermolecular forces are the forces between molecules or particles.

The London dispersion force is the weakest intermolecular force.

Dispersion force is also called an induced dipole-induced dipole attraction.

The London dispersion force (intermolecular force) is a temporary attractive force between molecules.

There are several types of intermolecular forces: hydrogen bonding, ion-induced dipole forces, ion-dipole forces andvan der Waals forces.

In the molecule of dichlormethane (CH₂Cl₂) there are dipole-dipole forces between negatively charged chlorine atom from one molecule of the compound and positively charged hydrogen atom of another molecule of the compound.

Missing options: dipole-dipole interactions, hydrogen bonding, dispersion forces.

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A 483 L balloon at 42° C is heated to 81° C the balloon's final volume is 604.17.

Volume-temperature (constant pressure) When pressure is constant, the volume of a gas is directly proportional to its temperature. Volume to temperature ratio is constant when pressure stays constant. Charles' law or Gay-law Lussac's are two names for this relationship.

A thermodynamic process known as an isochoric process, also known as a constant-volume process, isovolumetric process, or isometric process, occurs when the volume of a closed system going through the process stays constant.

According to Charles law:

V1/T1 = V2/T2

initial temperature = 42⁰ C

42⁰ C+273 = 315 k

Final temperature = 81⁰ C

81⁰+273 = 354 k

V1/T1 = V2/T2

483L/315k = V2/354k

354 * 483 = 315 * V2

170982/283 = (315)V2/315

V2 = 604.17 L

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The units that are used to measure carbon dioxide (CO₂) are b. parts per billion (ppb) and d. parts per million (ppm).

ppb stands for parts per billion.

Parts per billion (10⁻⁹) is present at one thousand millionth of a gram per gram of sample solution.

Parts-per-million (10⁻⁶) is present at one-millionth of a gram per gram of sample solution. For example 10 mg/kg of CO₂ = 10 ppm CO₂.

Chemists use ppm and ppb because amount of carbon dioxide is so small.

Milibars are units for the pressure.

Percent is too big unit for the amount of carbon dioxide.

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The point during the fall will the potential and kinetic energy be equal is B. 1/2 of the way down.

It should be noted that the point when the potential and kinetic energy be equal will be at the midpoint of the initial height.

Therefore, the object possesses potential energy when at rest and then kinetic energy when in motion.

When KE = PE

We can deduce that KE+PE = MGH and  PE+ PE = MGH

This implies that MGH + MGH= 2MGH and  2H = H

Therefore, the point during the fall will the potential and kinetic energy be equal is B. 1/2 of the way down.

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The volume of a piece of copper is 104.91 liters.

d(copper metal) = 8.96 kg/L; density of a copper metal

m(copper metal) = 940 kg; mass of a copper metal

V(copper metal) = m(copper metal) ÷ d(copper metal)

V(copper metal) = 940 kg ÷ 8.96 kg/L  

V(copper metal) = 104.91 L; the volume of a copper metal

Volume is the amount of space that a substance occupies.

Density is the mass of an object divided by its volume. The SI derived unit for density is the kilogram/cubic meter, but chemist usually use gram per milimeter.

Mass is a fundamental measure of the amount of matter in the object.

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When performing an extraction with between an aqueous solution and organic solution density determines which layer ends up the bottom layer in the separatory funnel.

A separatory funnel is used to separate liquids.

Liquid with greater density will end up the bottom layer in the separatory funnel.

Water is polar substance as the аqueous layer, while organic layer is nonpolar substance.

Water is a “universal" solvent.

Density is the mass of an object divided by its volume. The SI derived unit for density is the kilogram/cubic meter, but chemist usually use gram per milimeter.

Volume is the amount of space that a substance occupies.

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Taking into account the definition of density, the density of the regular solid is 0.84 g/cm³.

Density is defined as the property that indicates the amount of mass in a certain volume of a substance.

The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷ volume

In this case, you know that:

Replacing in the definition of density:

density= 296.3 g÷ 352. 261 cm³

Solving:

density= 0.84 g/cm³

In summary, the density of the regular solid is 0.84 g/cm³.

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One soluble salt, sodium nitrate, and one insoluble salt, barium sulphate, are created when barium nitrate and sodium sulphate react together.

We have a double replacement reaction for this reaction. Balanced Approaches: It is a double replacement reaction in which the positions of the sodium and barium atoms are switched. When dissolved substances react, one (or more) solid products are produced, which is known as a precipitation reaction. These kinds of reactions, which are also occasionally known as double displacement, double replacement, or metathesis reactions, frequently involve the exchange of ions between ionic compounds in aqueous solutions. For a clear solution, replace a group 1 nitrate with barium nitrate. For a white precipitate, replace a group 1 nitrate with magnesium or calcium nitrate.

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4.0 g mass of NaOH is required to react exactly with 25.0 ml of 2.0 m H₂SO₄ which is option (c) .

It is given that volume of solution = 25.0 ml  = 0.025L and molarity of H₂SO₄ = 2.0 M  .

Using molarity , we get

Moles of H₂SO₄ = Volume of solution × Molarity

Moles of H₂SO₄ = 0.025L × 2 = 0.05 moles

2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O

As sulphuric acid is a dibasic acid,so 2 NaOH molecules are require to neutralise 1 sulphuric acid molecule.

Hence, Moles of NaOH require = 0.05 × 2 = 0.1 mol.

Molar mass of NaOH = 40g

Mass of NaOH = mole × molar mass

                        =    0.1 × 40

                        =    4.0 g

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This largely depends on the solubility and polarity of the substance that needs to be recrystallized.

When a substance needs to be recrystallized, the ideal solvent system for the process will not dissolve it at all at low temperatures, it will dissolve it completely at the solvent's boiling point, and the impurities will be dissolved at all temperatures. While both hexane and diethyl ether are considered non-polar solvents, diethyl ether is more polar than hexane so the combination of the two (depending on the ratio) might have all the required properties. It is, however, more common to use a more polar solvent in combination with hexane, such as ethyl acetate.

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This is because while the chilled solvent is saturated and should release some crystal .

The volume of solute that can be dissolved in the solvent grows with temperature. The result becomes less soluble as the solution cools, and the solute molecules cluster to form nuclei, which are tiny stable crystals. This is the nucleation stage in the crystallization process.

Because even through the chilled solvent is saturated and  should start to crystallise , some of the desired material will still be dissolved in the chilled solvent and will be lost when the crystal and solvent are seperated.

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The molecular formula of a compound is C₂H₂O₄.

Take 100 grams of compound:

1) ω(C) = 26.7% ÷ 100% = 0.267

m(C) = ω(C) × m(compound)

m(C) = 0.267 × 100 g.

m(C) = 26.7 g.

n(C) = m(C) ÷ M(C).

n(C) = 26.7 g ÷ 12 g/mol.

n(C) = 2.22 mol; amount of carbon

2) ω(H) = 2.2 % ÷ 100% = 0.022

m(H) = 0.022 × 100 g.

m(H) = 2.2 g.

n(H) = 2.2 g ÷ 1 g/mol.

n(H) = 2.2 mol; amount of hydrogen

3) ω(O) = 71.1 % ÷ 100%.

ω(O) = 0.711

m(O) = 0.711 × 100 g

m(O) = 71.1 g

n(O) = 71.1 g ÷ 16 g/mol

n(O) = 4.4 mol; amount of oxygen

4) n(C) : n(H) : n(O) = 2.2 mol : 2.2 mol : 4.4 mol /2.2 mol.

n(C) : n(H) : n(O) = 1 : 1 : 2

M(CHO₂) = 45 amu; empirical formula

90 amu ÷ 45 amu = 2 CHO₂

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The absolute amount of the discrepancy or simply error between the measured value and the actual value is multiplied by 100 and divided by the actual value to determine the percent error.

Follow these easy procedures to determine the error rate-

1. Don't take into consideration any minus (-) signs when calculating the inaccuracy (by deducting the predicted value from the actual value). take the error's absolute value, etc.

Approximate Value - Exact Value = Absolute Error

2. Subtract the mistake from the accurate figure (sometimes, we may get a decimal number).

3. Relative error is the difference between the precise and approximative values.

4. Add a "%" following the conversion to a percentage (by multiplying by 100).

|Approximate Value - Exact Value|/Exact Value 100% Percent Error

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From the question, we can see that; the wagon has more gravitational potential energy at point Y than point X.

We know that energy is the ability to do work. Work is said to be done when the force applied moves a distance in the direction of the force. In this case, we could say that there are several forms of energy such as;

As such, we can see that the Wagon is at higher elevation at point Y than on point X. Recall that the gravitational potential energy has to do with the height of the object.

Having said all these, it is now possible to conclude that; the wagon has more gravitational potential energy at point Y than point X.

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The model shown should demonstrate why planets do not end up going into the sun as follows: The planets move too fast to go into the sun. (option A).

Planets are the bodies that orbit round the sun. The planets are seven in number as follows:

According to this question, a student looks at an animated model of the planets orbiting the sun. In reality, this planets do not go into the sun because they are far away from the sun.

The Earth as a planet for example is not moving fast enough to escape the sun's gravity and leave the solar system, but it is going too fast to be pulled into the sun. Therefore, it keeps going around and around in an orbital manner.

Therefore, the model shown should demonstrate why planets do not end up going into the sun as follows: The planets move too fast to go into the sun.

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As the sample size gets larger, the size of the correlation necessary for significance gets smaller.

Sample size determination is the process of deciding how many observations or replicates to include in a statistical sample. The sample size is an important consideration in any empirical study that aims to infer information about a population from a sample.

The response depends on the size of your sample. In all other respects, the larger the sample, the more consistent and trustworthy the association is. Correlations based on small samples are frequently very incorrect.

For both the bivariate correlation and the Pearson correlation, sample sizes are estimated to determine the number of persons that must be surveyed, polled, or sampled in order to find the test significant at the chosen level of significance. This is the probability of creating a Type.

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Surface processes such as erosion, movement, weathering, and the deposition of sediment can modify surface features, such as mountains, or create new features, such as canyons.

Have a great day!

The surface of the Earth is constantly changing as a result of geoscience processes such as weathering, erosion, and deposition. Systems on the planet interact to influence Earth's past, present, and future.

Geoscience investigates the processes that shape the Earth's surface, the resources humans utilize, and how water and ecosystems are related. It covers much more than just rocks and volcanoes. Chemistry, physics, biology, and arithmetic, as well as other scientific disciplines, are used in geoscience.

The surface of the Earth is constantly changing as a result of geoscience processes such as weathering, erosion, and deposition. Systems on the planet interact to influence Earth's past, present, and future.

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The valence orbitals of a central atom surrounded by three regions of electron density consist of a set of three sp2 hybrid orbitals.

In sp2 hybridization the one s-orbital mixes with only two 2p-orbitals and form three sp2 hybrid orbitals (see the picture below).

When atomic orbitals hybridize, the valence electrons occupy the hybrid orbitals.

For example, central boron atom in boron hydride (BH3) has three sp2 hybrid orbitals. The molecule of boron hydride is trigonal planar. The boron atom form three single bonds with hydrogen atoms. The approximate H-B-H bond angle is 120°.

Other examples are molecules C2H4 (ethene), ClNO (nitrosyl chloride) and CH2O (formaldehyde).

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Answer:

Explanation:

14.74

The fraction of collisions at 298K are 7.14 x [tex]10^-^1^4[/tex]

Based on the collision theory, effective changes are only produced by a certain number of impacts between suitable reactant components with the right orientation; these successful transformations are referred to as successful fractions of collisions.

According to the collision theory, for a chemical interaction to take place, the reacting molecules must come into contact with one another. The frequency of collisions affects the reaction's rate. According to the idea, responding particles frequently encounter without reacting.

Given:

Ea = 75KJ/mol

R = 8.314J/molK

T = 298K

To find:

Fraction of collisions, f = ?

Formula:

Fraction of Collisions, [tex]f = e^\frac{-Ea}{RT}[/tex]

Calculations:

f = [tex]e ^ \frac{-75000}{8.314 * 298}[/tex]

f = 7.14 x [tex]10^-^1^4[/tex]

Result:

The fraction of collisions having sufficient energy are 7.14 x [tex]10^-^1^4[/tex].

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It is a good idea to keep in mind which solvents can dissolve which solvents by saying "like dissolves like." Purely aromatic hydrocarbon cyclohexane is extremely hydrophobic and nonpolar, therefore it won't dissolve in a solvent that is highly polar or hydrophilic like water.

What is solubility?

The maximum amount of a material that may dissolve in another is known as its solubility. A saturated solution is created when a solvent can hold the most solute while still maintaining equilibrium.

The saying "like dissolves like" is a helpful reminder of which solvents can dissolve which solvents. Cyclohexane, a purely aromatic hydrocarbon, is exceedingly hydrophobic and nonpolar, therefore it won't dissolve in a highly polar or hydrophilic solvent like water.

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