Which equation describes a relationship that is directly proportional?
(A) y = 9
(B) y = 1/5
(C) y = 3x
(D) y = x + 4

Answer:

The answer is (-2 , 1 ) or D on Edge

Step-by-step explanation:

The coordinates of vertex A of square ABCD is (-1, -2).

Coordinates are two numbers (Cartesian coordinates), or sometimes a letter and a number, that locate a specific point on a grid, known as a coordinate plane.

Given:

A(-5, -3), B(-3, -1), C(-1, -3) and D(-3, -5)

By using the rule

T(-4, -1)

So, the coordinate of Vertex A will be

A( -5 + 4, -3 + 1)

=A(-1, -2)

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Answer:

8n x n x n x n x n x n x n

Step-by-step explanation:

(2n^2)^3 = 8n^ 6

Now just write "n" 6 times and there you go

The given expression without exponents can be written as 8×n×n×n×n×n×n.

The given expression is (2n²)³.

We need to write the given expression without exponents.

The exponent of a number shows how many times the number is multiplied by itself. For example, 2×2×2×2 can be written as 24, as 2 is multiplied by itself 4 times.

Now, the given expression can be simplified as follows:

(2n²)³=2³×(n²)³

=2×2×2×[tex]n^{6}[/tex]  (∵[tex](a^{m}) ^{n}=a^{m\times n}[/tex])

=8×n×n×n×n×n×n

Therefore, the given expression without exponents can be written as 8×n×n×n×n×n×n.

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Answer:

  c)  x = 6, y = 9

Step-by-step explanation:

The figure is a parallelogram. The diagonals of a parallelogram bisect each other, so each part of a given diagonal is equal to the other part.

  3x = 2y

  2x = y+3

__

Solving the second equation for y, we have ...

  y = 2x -3

Substituting into the first equation gives ...

  3x = 2(2x -3)

  3x = 4x -6 . . . . simplify

  6 = x . . . . . . . . .add 6 -3x

  y = 2(6) -3 = 9 . . . . use the above expression for y

The values of x and y are (x, y) = (6, 9).

Answer:

[tex] m=\frac{y_2 -y_1}{x_2 -x_1}[/tex]

And replacing we got:

[tex] m=\frac{1-(-3)}{3-(-3)}= \frac{4}{6}=\frac{2}{3}[/tex]

And we can use one of the points in order to find the intercept like this:

[tex] -3= \frac{2}{3} (-3) +b[/tex]

[tex] b =-3 +2=-1[/tex]

And the equation would be given by:

[tex] y= \frac{2}{3}x -1[/tex]

Step-by-step explanation:

We want an equation given by:

[tex] y=mx+b[/tex]

where m i the slope and b the intercept

We have the following two points given:

[tex] (x_1 = -3, y_1 =-3), (x_2=3, y_2 =1)[/tex]

We can find the slope with this formula:

[tex] m=\frac{y_2 -y_1}{x_2 -x_1}[/tex]

And replacing we got:

[tex] m=\frac{1-(-3)}{3-(-3)}= \frac{4}{6}=\frac{2}{3}[/tex]

And we can use one of the points in order to find the intercept like this:

[tex] -3= \frac{2}{3} (-3) +b[/tex]

[tex] b =-3 +2=-1[/tex]

And the equation would be given by:

[tex] y= \frac{2}{3}x -1[/tex]

Answer:

Band: 30%

Chorus: 18%

Painting: 21%

Robotics: 14%

Coding: 17%

Answer:

the answer is E the number at the top tells you which position it falls under in the alphabet

Step-by-step explanation:

a.It is a controlled experiment because it is clearly seen that an established hypothesis or study is being verified through an experiment, now in this case the hypothesis is tested through an experiment where excessive stress is placed on the Participants during their math exam to effectively verify that people in urban or city areas live with more stress than people in rural areas.

2..As now that the previously established hypothesis has been verified, it is concluded that people who live in the city live with more anxiety and stress than people who live in rural areas.

Complete Question

Calculating conditional probability

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom.

Here are the results:

Bride :29

Groom :30

BOTH : 20

Given that a randomly selected guest is a friend of the groom, find the probability they are a friend of the bride.

P (bride | groom)​

Answer:

The probability is [tex]P(B|G) = \frac{2}{3}[/tex]

Step-by-step explanation:

The sample size is [tex]n = 80[/tex]

The friend of the groom are [tex]G = 30[/tex]

 The friend of the groom are [tex]B = 29[/tex]

 The friend of both bride and groom are [tex]Z = 20[/tex]

The probability that a guest is a friend of the bride is mathematically represented as

      [tex]P(B) = \frac{29}{80}[/tex]

The probability that a guest is a friend of the groom is mathematically represented as

       [tex]P(G) = \frac{30}{80}[/tex]

The probability that a guest is both a friend of the bride and a friend of the groom is mathematically represented as

       [tex]P(B \ n \ G) = \frac{20}{80}[/tex]

Now

    [tex]P(B|G)[/tex] is mathematically represented as

     [tex]P(B|G) = \frac{P(B \ n \ G)}{P(G)}[/tex]

     Substituting values

       [tex]P(B|G) = \frac{\frac{20}{80} }{\frac{30}{80} }[/tex]

      [tex]P(B|G) = \frac{2}{3}[/tex]

Answer:

the answer is 3/5

Step-by-step explanation:

on Khan

Due to the symmetry of the paraboloid about the z-axis, you can treat this is a surface of revolution. Consider the curve [tex]y=x^2[/tex], with [tex]1\le x\le2[/tex], and revolve it about the y-axis. The area of the resulting surface is then

[tex]\displaystyle2\pi\int_1^2x\sqrt{1+(y')^2}\,\mathrm dx=2\pi\int_1^2x\sqrt{1+4x^2}\,\mathrm dx=\frac{(17^{3/2}-5^{3/2})\pi}6[/tex]

But perhaps you'd like the surface integral treatment. Parameterize the surface by

[tex]\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k[/tex]

with [tex]1\le u\le2[/tex] and [tex]0\le v\le2\pi[/tex], where the third component follows from

[tex]z=x^2+y^2=(u\cos v)^2+(u\sin v)^2=u^2[/tex]

Take the normal vector to the surface to be

[tex]\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial u}=-2u^2\cos v\,\vec\imath-2u^2\sin v\,\vec\jmath+u\,\vec k[/tex]

The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:

[tex]\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|=u\sqrt{1+4u^2}[/tex]

Then the area of the surface is

[tex]\displaystyle\int_0^{2\pi}\int_1^2\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\int_0^{2\pi}\int_1^2u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv[/tex]

which reduces to the integral used in the surface-of-revolution setup.

Answer:

y=-5/3x+8/3

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(-2,6) and (1,1).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-2,6), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-2 and y1=6.

Also, let's call the second point you gave, (1,1), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=1 and y2=1.

Now, just plug the numbers into the formula for m above, like this:

m=  

1 - 6

1 - -2

or...

m=  

-5

3

or...

m=-5/3

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-5/3x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-2,6). When x of the line is -2, y of the line must be 6.

(1,1). When x of the line is 1, y of the line must be 1.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-5/3x+b. b is what we want, the -5/3 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-2,6) and (1,1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(-2,6). y=mx+b or 6=-5/3 × -2+b, or solving for b: b=6-(-5/3)(-2). b=8/3.

(1,1). y=mx+b or 1=-5/3 × 1+b, or solving for b: b=1-(-5/3)(1). b=8/3.

Answer:

The bottom left table

Step-by-step explanation:

the same x value cannot have different y values

Answer:

  209 : 40  or  5.225 : 1

Step-by-step explanation:

Your calculator can tell you the ratio 8.36/1.60 is 5.225. Writing that decimal as a fraction, you can factor out 25 to get ...

  8.36 : 1.6 = 5.225 : 1 = 5225 : 1000 = (25)(209) : (25)(40) = 209 : 40

Answer:

Step-by-step explanation:

The confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of low-tech industry

x2 = sample mean of consumer products industry

s1 = sample standard deviation low-tech industry

s2 = sample standard deviation for consumer products industry

n1 = number of samples of low-tech industry

n2 = number of samples of consumer products industry

a) x1 - x2 is the point estimate of the difference between the means of the two populations

Therefore,

Point estimate = 157 - 218 = - 61

b) the formula for standard error is expressed as

√(s1²/n1 + s2²/n2)

Variance = standard deviation²(s²)

s1² = 1563

s2² = 1602

Standard error = √(1563²/14 + 1602²/12) = 623.2

c) Degree of freedom =

(n1 - 1) + (n2 - 1) = (14 - 1) + (12 - 1) = 24

t-distribution with 24 degrees of freedom

According to the data given, we have that:

a) 61

b) 15.65

c) t-distribution with 24 degrees of freedom

Item a:

The point estimate is the difference between the two sample means, hence:

218 - 157 = 61.

Item b:

For each sample, the standard errors are:

[tex]s_l = \sqrt{\frac{1563}{14}} = 10.57[/tex]

[tex]s_h = \sqrt{\frac{1602}{12}} = 11.54[/tex]

For the difference of the two means, it is:

[tex]s = \sqrt{s_l^2 + s_h^2} = \sqrt{10.57^2 + 11.54^2} = 15.65[/tex]

Item c:

Samples of 14 and 12, hence 14 + 12 - 2 = 24 df.

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Answer: see below

Step-by-step explanation:

To find a coterminal angle, add or subtract 360° to the given angle as many times as needed to get a positive or negative angle.

I should mention that there are an infinite number of answers!

4) 400°

I can subtract 360° to get a positive angle of 40°

I can subtract another 360° to get a negative angle of -320°

5) -360°

I can subtract 360° to get a negative angle of -720°

I can add 360° twice to get a positive angle of 360°

6) -1010°

I can add 360° to get a negative angle of -650°

I can add 360° another 3 times to get a positive angle of 720°

7) 567°

I can subtract 360° to get a positive angle of 207°

I can subtract another 360° to get a negative angle of -153°

8) -164°

I can subtract 360° to get a negative angle of -524°

I can add 360° to get a positive angle of 194°

9) 358°

I can subtract 360° to get a negative angle of -2°

I can add 360° to get a positive angle of 718°

Answer:

y=-4x+1

Step-by-step explanation:

You want to find the equation for a line that passes through the point (-1,5) and has a slope of -4.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was -4. So you can right away fill in the equation for a line somewhat to read:

y=-4x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-1,5). When x of the line is -1, y of the line must be 5.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the -4 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-1,5).

So, why not plug in for x the number -1 and for y the number 5? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-1,5). y=mx+b or 5=-4 × -1+b, or solving for b: b=5-(-4)(-1). b=1.

The equation of line passes through the point (-1, 5) will be;

⇒ y = - 4x - 2

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

The point on the line are (-1, 5).

And, The slope of line is,

⇒ m = - 4

Now,

Since, The equation of line passes through the point (- 1, 5).

And, Slope of the line is,

m = - 4

Thus, The equation of line with slope - 4 is,

⇒ y - 5 = - 4 (x - (-1))

⇒ y - 2 = - 4 (x + 1)

⇒ y - 2 = - 4x - 4

⇒ y = - 4x - 4 + 2

⇒ y = - 4x - 2

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[tex]the \: answer \: is \: 10 \\ please \: see \: the \: attached \: picture \: for \\ full \: solution \\ hope \: it \: helps[/tex]

Answer:

10 is the answer for this question.

Answer:

  IV

Step-by-step explanation:

Cosine is positive in quadrants I and IV.

Cosecant (also sine) is negative in quadrants III and IV.

The quadrant where cos > 0 and csc < 0 is quadrant IV.

First number = [tex]x[/tex]

Second number = [tex]x-11[/tex]

[tex]x+x-11+8=71[/tex]

[tex]2x-3=71[/tex]

[tex]2x=71+3[/tex]

[tex]2x=74[/tex]

[tex]x=37[/tex]

First number = [tex]x=37[/tex]

Second number =  [tex]x-11=37-11=26[/tex]

Answer:

a. [tex]x^2-6x-8=0[/tex]

b. [tex]x^2-6x=8[/tex]

c.

[tex]\frac{1}{2}[/tex] (Coefficient of x) = [tex]\frac{-6}{2}=-3[/tex]

Also, [tex](-3)^2=9[/tex]

d. [tex]x^2-6x+9=17[/tex]

e. [tex](x-3)^2=17[/tex]

f, g. [tex]x=3\pm \sqrt{17}[/tex]

Step-by-step explanation:

Given: [tex]2x^2-12x-16=0[/tex]

To solve: the given equation

Solution:

a.

[tex]2x^2-12x-16=0[/tex]

Coefficient of [tex]x^2=2[/tex]

Divide both sides by 2

[tex]x^2-6x-8=0[/tex]

b.

[tex]x^2-6x=8[/tex]

c.

Coefficient of x = -6

[tex]\frac{1}{2}[/tex] (Coefficient of x) = [tex]\frac{-6}{2}=-3[/tex]

Also, [tex](-3)^2=9[/tex]

d.

Add 9 to both sides of the equation: [tex]x^2-6x=8[/tex]

[tex]x^2-6x+9=8+9\\x^2-6x+9=17[/tex]

e.

[tex]x^2-6x+9=17\\x^2-2(3)x+3^2=17\\(x-3)^2=17\,\,\left \{ \because (a-b)^2=a^2+b^2-2ab \right \}[/tex]

f.

[tex](x-3)^2=17\\x-3=\pm \sqrt{17}\\x=3\pm \sqrt{17}[/tex]

g.

[tex]x=3\pm \sqrt{17}[/tex]

Answer:

Step-by-step explanation:

Answer:

S = ⅙ π (65^³/₂ − 5^³/₂)

Step-by-step explanation:

z = x² + y², 1 < z < 4

Surface area is:

S = ∫∫√(1 + (fₓ)² + (fᵧ)²) dA

where fₓ and fᵧ are the partial derivatives of f(x,y) with respect to x and y, respectively.

fₓ = 2x, fᵧ = 2y

S = ∫∫√(1 + (2x)² + (2y)²) dA

S = ∫∫√(1 + 4x² + 4y²) dA

For ease, convert to polar coordinates.

S = ∫∫√(1 + 4r²) dA

S = ∫∫√(1 + 4r²) r dr dθ

At z = 1, r = 1.  At z = 4, r = 4.

So 1 < r < 4, and 0 < θ < 2π.  These are the limits of the integral.

S = ∫₀²ᵖⁱ∫₁⁴√(1 + 4r²) r dr dθ

To integrate, use u-substitution.

u = 1 + 4r²

du = 8r dr

⅛ du = r dr

When r = 1, u = 5.  When r = 4, u = 65.

S = ∫₀²ᵖⁱ∫₅⁶⁵√u (⅛ du) dθ

S = ∫₀²ᵖⁱ (⅛ ∫₅⁶⁵√u du) dθ

S = ∫₀²ᵖⁱ (¹/₁₂ u^³/₂ |₅⁶⁵) dθ

S = ∫₀²ᵖⁱ (¹/₁₂ (65^³/₂ − 5^³/₂)) dθ

S = (¹/₁₂ (65^³/₂ − 5^³/₂)) θ |₀²ᵖⁱ

S = (¹/₁₂ (65^³/₂ − 5^³/₂)) (2π)

S = ⅙ π (65^³/₂ − 5^³/₂)

Answer:

Lower class Limit: 20,25,30,35,40,45,50

Upper class limit: 24,29,34,39,44,49,54

Class width: 4

Class Midpoints : 22,27,32,37,42,47,52

Class Boundries : 19.5,24.5,29.5,34,5,39.5,44.5,49.5,54.5

Total Individuals: 93

Step-by-step explanation:

Lower class limit is the lowest value of a class e.g in the first class, the lowest value is 20. Similarly find lower class limit of othere classes.

Upper class limit is the highest value of a class e.g in the first class, the highest value is 24. Similarly find upper class limit of othere classes.

Class width is the difference between highest and lowest value of a class e.g 24-20=4

Class Midpoints can be found by adding lowest and highest value of a class and dividing it by 2 e.g (20+24)/2 = 22

Class boundaries are the halfway point which seperates the classes e.g for first classes, clasee boundry is (19.5,24.5)

Total individuals are founf by adding all the frequencies.

Answer:

2

Step-by-step explanation:

as you can see the slope of the line y = -1/2x + 5 is -1/2

the slope m of any line perpendicular to it should verify : -1/2×m = -1

-1/2×m = -1

→ multiply both sides by -2

m = 2

Answer:

1) cpk < 1.33, therefore it is not capable

b) cpk = 1.33, therefore it is capable

c) cpk < 1.33, therefore it is not capable

2) Cpk can never be greater than the Cp, but can be equal to it

Step-by-step explanation:

Upper limit (USL) = 47 minutes and Lower limit (LSL) = 30 minutes

1)

a) mean (μ) = 37 minutes, standard deviation (σ) = 3 minutes

[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-37}{3*3},\frac{37-30}{3*3} )=min(1.11,0.78)=0.78[/tex]

[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*3}=0.94[/tex]

cpk < 1.33, therefore it is not capable

b) mean (μ) = 38 minutes, standard deviation (σ) = 2 minutes

[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-38}{3*2},\frac{38-30}{3*2} )=min(1.5,1.33)=1.33[/tex]

[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*2}=1.42[/tex]

cpk = 1.33, therefore it is capable

c) a) mean (μ) = 38.5 minutes, standard deviation (σ) = 2.9 minutes

[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-38.5}{3*2.9},\frac{38.5-30}{3*2.9} )=min(0.98,0.98)=0.98[/tex]

[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*2.9}=0.98[/tex]

cpk < 1.33, therefore it is not capable

2) Cpk can never be greater than the Cp, but can be equal to it

Answer:

Step-by-step explanation:

George Fox university = 10,000,000 + 10,000,000

                                    = full bag + full bag

                                    ( click 2 full bag}

Rockhurst university = 10,000,000 +10,000,000 +10,000,000 + 5,000,000

                                  = full bag + full bag + full bag + half bag

       (click 3 full bag and 1 half bag}

Lebanon Valley college = 10,000,000 +10,000,000 +10,000,000 +10,000,000+5,000,000

( click 4 full bag and 1 half bag)

Grand view college = 10,000,000

 (click 1 full bag}

Answer:

a) The 95% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day is (1.49, 1.57).

d) The nutritionist is 95% confident that the mean amount of time spent eating or drinking per day for any individual is between 1.49 and 1.57 hours.

(c and b can not be concluded from the confidence interval)

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=1.53.

The sample size is N=1082.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.71}{\sqrt{1082}}=\dfrac{0.71}{32.89}=0.022[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=1082-1=1081[/tex]

The t-value for a 95% confidence interval and 1081 degrees of freedom is t=1.962.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=1.962 \cdot 0.022=0.042[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 1.53-0.042=1.49\\\\UL=M+t \cdot s_M = 1.53+0.042=1.57[/tex][tex]LL=M-t \cdot s_M = 1.53-0.042=1.49\\\\UL=M+t \cdot s_M = 1.53+0.042=1.57[/tex]

The 95% confidence interval for the mean is (1.49, 1.57).

Answer:use mathematic pathway to calualte

Step-by-step explanation:

Answer:

There should be no pattern in the residual plot.

Step-by-step explanation

Remember a residual plot is calculating if a linear model is appropriate or not and since the engineer is trying to find a linear relationship with his air filters then he should be looking for no pattern.

Here, we are required to determine what should be apparent in the residual plot.

The residual plot will have a negative slope, i.e the residual plot descends from the top left to the bottom right.

According to the Engineer's believe, the thicker the air filter, the less pollution that gets through it.

By plotting each of the quantities on either of x and y axis on the residual plot, The residual plot therefore, has a negative slope.

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Answer:

11449/160000

Step-by-step explanation:

The probability of selecting a single adult that thinks most celebrities are good role models is 214/800 = 107/400

The probability that both do is

(107/400)^2 =. 11449/160000

Answer:

[tex] \bar X = \frac{\sum_{i=1}^{42} X_i}{n}[/tex]

And for this case the sample mean is

[tex]\bar X = 127.1[/tex]

And this value is calculated from a sample so then can't represent a population parameter. Then the value 127.1 represent a statistic called the sample mean unbiased for the true population mean since [tex] E(\bar X) =\mu[/tex], and the best option would be:

D) The given value is a statistic for the year because the data collected represent a sample.

Step-by-step explanation:

For this case we know that a homeowner take a random sample of 42 voltage values ina year and he calculate the sample mean with this formula:

[tex] \bar X = \frac{\sum_{i=1}^{42} X_i}{n}[/tex]

And for this case the sample mean is

[tex]\bar X = 127.1[/tex]

And this value is calculated from a sample so then can't represent a population parameter. Then the value 127.1 represent a statistic called the sample mean unbiased for the true population mean since [tex] E(\bar X) =\mu[/tex], and the best option would be:

D) The given value is a statistic for the year because the data collected represent a sample.

Answer:

Step-by-step explanation:

Rational numbers are the result of dividing two integers. Intergers cannot be fractions. So 1.5 is rational but 3/2 is not.

Five rational numbers: 1.5, 6, 24.7, 384, 404.4, 1,980

I'm always happy to help :)