Suppose you have a job teaching swimming lesson and get paid $6 an hour you also have a job as a chasier and get pay $8 and hour if you cannot work more than 15 hours a week what are the number you f hours you can work at each job and still make at least $100
Answer:
You can work no more than 10 hours teaching, and must work at least 5 hours cashiering. The remaining hours can be worked at the other job until the goal is reached.
Step-by-step explanation:
The restrictions give rise to two inequalities. If we ...
let x represent teaching hours
let y represent cashiering hours
then the restrictions are ...
x + y ≤ 15 . . . . total hours cannot exceed 15
6x +8y ≥ 100 . . . . you want to earn at least $100
The solution set for these inequalities is a triangular area on a graph with vertices at ...
(x, y) = (10, 5), (0, 12.5), (0, 15)
You must work at least 5 hours cashiering, and the remainder of necessary time at teaching.
12 and 3/6 -5 and 2/12
Answer:
7.33333333333 I think. Hope this helped.
Use Greens Theorem to evaluate integral x^2ydx - xy^2dy, where C is 0 ≤ y ≤ √9-x^2 with counterclockwise orientation
Answer:
Step-by-step explanation:
a circle will satisfy the conditions of Green's Theorem since it is closed and simple.
Let's identify P and Q from the integral
[tex]P=x^2 y[/tex], and [tex]Q= xy^2[/tex]
Now, using Green's theorem on the line integral gives,
[tex]\oint\limits_C {x^2ydx-xy^2dy } =\iint\limits_D {y^2-x^2} \, dA\\\\[/tex]
After the accounts have been adjusted at December 31, the end of the fiscal year, the following balances were taken from the ledger of Pioneer Delivery Services Co.:
Kerry Buckner, Capital. $9,556,300
Kerry Buckner, Drawing 80,000
Wages Expense 1,878,400
Rent Expense 1,415,500
Supplies Expense 125,000
Fees Earned 30,600
Miscellaneous Expense 22,100
Journalize the two entries required to close the accounts.
Jan's All You Can Eat Restaurant charges $9.10 per customer to eat at the restaurant. Restaurant management finds that its expense per customer, based on how much the customer eats and the expense of labor, has a distribution that is skewed to the right with a mean of $8.10 and a standard deviation of $4.
A. If the 100 customers on a day have the characteristics of the random sample from their customer base, find the mean and standard error of the sampling distribution of the restaurant's sample mean expense per customer.
B. Find the probability that the restaurant makes a profit that day, with the sample mean expense being
less than $8.95.
Answer:
Step-by-step explanation:
From the given question;
Given that:
Jan's All You Can Eat Restaurant charges $9.10 per customer to eat at the restaurant.
Distribution is skewed and and has a mean of $8.10 and a standard deviation of $4.
A. If the 100 customers on a day have the characteristics of the random sample from their customer base, find the mean and standard error of the sampling distribution of the restaurant's sample mean expense per customer.
the mean by using the central limit theorem is 8.10
the standard error of the sampling distribution = [tex]\dfrac{\sigma}{\sqrt{n}}[/tex]
the standard error of the sampling distribution = [tex]\dfrac{4}{\sqrt{100}}[/tex]
= 4/10
= 0.4
B.
P(X > $8.95) = P (Z > 8.95 - 8.10/0.4)
P(X > $8.95) = P (Z > 2.1)
P(X > $8.95) = 1 - P (Z < 2.1)
P(X > $8.95) = 1 - 0.9821
P(X > $8.95) = 0.0179
Please give answer with explanation of formula. Please reply fast I have exam.
Answer:
D
Step-by-step explanation:
3/40 * 2.5/2.5 = 7.5/100 = 0.075
• Write this number as a fraction:178.25
Answer: 178 1/4 or 713/4
Step-by-step explanation:
178.25 = 178+0.25 = 178+25/100
gcd(25,100) = 25
178.25 = 178+(25/25)/(100/25) = 178+1/4 = 713/4
The mean of 3 numbers is 4
The two numbers are 1,9
what is the missing number?
Answer:
2
Step-by-step explanation:
1+9+2 = 12
12/3= 4
Answer:2
Step-by-step explanation:9+2+1=12
So 12/3=4
ANSWER=2
which rule represents the translation from the pre-image ABCD, to the image, a’b’c’d’
Answer:
Pre-image ABCD has been shifted 2 units right and 1 unit upwards.
Step-by-step explanation:
Coordinates of the points A,B,C and D of the pre-image ABCD,
A(-4, 4), B(-1, 4), C(-5, 1), D(-2,1)
Coordinates of the points A', B', C' and D' of the image A'B'C'D'.
A'(-2, 5), B'(1, 5), C'(-3, 2), D'(0, 2)
Now we choose points A from the pre-image and A' from the image,
A(-4, 4) → A'(-2, 5)
Rule for the translation will be,
A(-4, 4) → A'(-4+2, 4+1)
Or A(x, y) → A'(x+2, y+1)
Therefore, pre-image ABCD has been shifted 2 units right and 1 unit upwards to form image A'B'C'D'.
Answer: It's D
Step-by-step explanation:
the last one I just took the quiz
The diameter of a circle is 5 ft. Find its area to the nearest tenth.
Answer:
A = 19.6 ft²
Step-by-step explanation:
A = πr² Use this equation to find the area of the circle
A = π(2.5)² Multiply
A = π(6.25) Multiply
A = 19.6 ft²
Please answer this correctly
Answer:
174
Step-by-step explanation:
l x w
5x20
8x4
6x7
174
15=3(2x+4)-3 prove x=1
Answer:
X=1
Step-by-step explanation:
6x+12-3=15
6x+9=15
6x+9-9=15-9
6x=6
X=1
Answer:
see below
Step-by-step explanation:
15=3(2x+4)-3
Distribute
15 = 6x +12 - 3
Combine like terms
15= 6x +9
Subtract 9 from each side
15 -9 = 6x+9-9
6 = 6x
Divide each side by 6
6/6 = 6x/6
1 =x
Which of the given shapes has a larger area?
Answer:
Rectangle
Step-by-step explanation:
Count the units. For the triangle, A=0.5bh. 0.5(4)(6)=A. A=12
Now, for the rectangle, A=bh. A=(3)(5). A=15. The rectangle is larger
The perimeter of a rectangular parking lot is 320 m.
If the length of the parking lot is 97 m, what is its width?
Answer:
63 metres
Step-by-step explanation:
A rectangle has 4 sides
2 of these sides are the lengths
The other 2 sides are the width
If the length of one side is 97 metres, the other side length must also be 97 metres
The two lengths then add together (97 + 97) to become 194 metres
Now we can use this information to calculate the width
320 (the total perimeter) subtract 194 (The total length) = 126 metres
This means that 126 metres is the total width
Because there are two sides which add up to the total width we divide 126 by 2
This allows us to get the measurement of the width
126 divided by 2 = 63 metres
For the given set, first calculate the number of subsets for the set, then calculate the
{5, 13, 17, 20}
The number of subsets is ]
The number of proper subsets is .
Answer:
[tex]\fbox{\begin{minipage}{14em}Number of subsets: 16\\Number of proper subsets: 15\end{minipage}}[/tex]
Step-by-step explanation:
Given:
The set A = {5, 13, 17, 20}
Question:
Find the number of subsets of A
Find the number of proper subsets of A
Simple solution by counting:
Subset of A that has 0 element:
{∅} - 1 set
Subset of A that has 1 element:
{5}, {13}, {17}, {20} - 4 sets
Subset of A that has 2 elements:
{5, 13}, {5, 17}, {5, 20}, {13, 17}, {13, 20}, {17, 20} - 6 sets
Subset of A that has 3 elements:
{5, 13, 17}, {5, 13, 20}, {5, 17, 20}, {13, 17, 20} - 4 sets
Subset of A that has 4 elements:
{5, 13, 17, 20} - 1 set
In total, the number of subsets of A: N = 1 + 4 + 6 + 4 + 1 = 16
The number of proper subsets (all of subsets, except subset which is equal to original set A): N = 16 - 1 = 15
Key-point:
The counting method might be used for finding the number of subsets when the original set contains few elements.
The question is that, for a set that contains many elements, how to find out the number of subsets?
The answer is that: there is a fix formula to calculate the total number ([tex]N[/tex]) of subsets of a set containing [tex]n[/tex] elements: N = [tex]2^{n}[/tex]
With original set A = {5, 13, 17, 20}, there are 4 elements belonged to A.
=> Number of subsets of A: N = [tex]2^{4} = 16[/tex]
(same result as using counting method)
Brief proof of formula: N = [tex]2^{n}[/tex]
Each element of original set is considered in 2 status: existed or not.
If existed => fill that element in.
If not => leave empty.
For i.e.: empty subset means that all elements are selected as not existed, subset with 1 element means that all elements are selected as not existed, except 1 element, ... and so on.
=> From the point of view of a permutation problem, for each element in original set, there are 2 ways to select: existed or not. There are [tex]n[/tex] elements in total. => There are [tex]2^n}[/tex] ways to select, or in other words, there are [tex]2^{n}[/tex] subsets.
Hope this helps!
:)
What’s the correct answer for this question?
Answer: 3/20
Step-by-step explanation:
p(A)=the day selected in Monday =1/5
p(B)=student is absent
P(A∩B)=it is Monday AND a student is absent =3/100
Events A and B are independent so
P(A∩B) = P(A) · P(B)
3/100=1/5*p(B)
p(B)=3/20
In △DEF, d = 25 in., e = 28 in., and f = 20 in. Find m∠F. Round your answer to the nearest tenth.
Answer:
∠F ≈ 43.9°
Step-by-step explanation:
The Law of Cosines is used to find an angle when all triangle sides are known.
f² = d² +e² -2de·cos(F)
cos(F) = (d² +e² -f²)/(2de) = (25² +28² -20²)/(2·25·28) = 1009/1400
F = arccos(1009/1400)
F ≈ 43.9°
Which answer is equivalent to the equation shown below?
7c = 49
A.log7 c = 49
B.c = log49 7
C.logc49 = 7
D.c = log7 49
Answer:
D.
Step-by-step explanation:
The base of a log is also the base of an exponent. So 7 to the c power, our 7 would be the base. To find c, we simply just do log base 7 of 49, which comes out to be 2.
Solve.
3^x+1 = 9^ 5x
a. x=3
b. x = 1/3
c. x=9
d. x= 1/9
Answer:
x = 1/9
Step-by-step explanation:
3^ (x+1) = 9 ^ (5x)
Replace 9 with 3^2
3^ (x+1) = 3^2 ^ (5x)
We know that a^b^c = a ^(b*c)
3^ (x+1) = 3^(2 * (5x))
3^ (x+1) = 3^(10x)
The bases are the same so the exponents are the same
x+1 = 10x
Subtract x from each side
x+1-x = 10x-x
1 = 9x
Divide each side by 9
1/9 = 9x/9
1/9 =x
Parker marks sixths on number line. He writes 5/6 just before 1. What fraction does he write on the first mark to the right of 1?
Answer: 7/6
Step-by-step explanation:
If he is writing sixths, then we have multiples of 1/6.
this is:
0*(1/6) = 0
1*(1/6) = 1/6
.
.
.
5*(1/6) = 5/6 (the numer he wrote at the left of 1)
6*(1/6) = 6/6 = 1
7*(1/6) = 7/6
So the number next to 1, (at the right of 1) must be 7/6.
You also can find it by adding 1/6 to 1.
1/6 + 1 = 1/6 + 6/6 = 7/6.
Answer:
[tex]7/6[/tex]
Explanation:
[tex]1/6 \approx 0.16666[/tex]
[tex]2/6 \approx 0.33333[/tex]
[tex]3/6 = 0.5[/tex]
[tex]4/6 \approx 0.66666[/tex]
[tex]5/6 \approx 0.83333[/tex]
[tex]6/6=1[/tex]
[tex]7/6 \approx 1.16666[/tex]
Find the value of y when equals zero. -7x+3y=30
Answer:
x = -30/7
Step-by-step explanation:
-7x+3y=30
Let y=0
-7x +0 = 30
Divide by -7
-7x /-7 = 30/-7
x = -30/7
Answer:
[tex]-\frac{30}{7}[/tex]
Step-by-step explanation:
y equals zero => y = 0
-7x+3y=30
-7x +3.0 = 30
-7x + 0 = 30
-7x = 30
-7x/-7 = 30/-7
x = -30/7
Hope this helps ^-^
Simplify the following expression:
-5[(x^3 + 1)(x + 4)]
Answer:
[tex]-5x^{4} -20x^{3} -5x-20[/tex]
Step-by-step explanation:
[tex]-5[(x^{3} +1)(x+4)][/tex]
Use the FOIL method for the last two groups.
[tex]-5(x^{4} +4x^{3} +x+4)[/tex]
Now, distribute the -5 into each term.
[tex]-5x^{4} -20x^{3} -5x-20[/tex]
Help asap giving branlist!!!
Answer:
Option 2
Step-by-step explanation:
The first statement is false because the price for 10 gallons is about $37 from the graph. Using this same reasoning, the third statement is also false. The last statement doesn't make sense because the graph has nothing to do with the amount of miles driven. Therefore, the answer is the second statement. We can prove it by looking at the point (4, 15). This means that it costs $15 for 4 gallons, so then the price for one gallon will be 15 / 4 = $3.75.
what is the value of x?
Answer:
solution
Step-by-step explanation:
x=5
y=4
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 5% of the employees suffered lost-time accidents last year. Management believes that a special safety program will reduce such accidents to 4% during the current year. In addition, it estimates that 15% of employees who had lost-time accidents last year will experience a lost-time accident during the current year. a. What percentage of the employee will experience a lost-time accident in both years (to 1 decimal)?
Answer:
The percentage of the employee will experience a lost-time accident in both years is 0.0%
Step-by-step explanation:
Let A denote events that employees suffered lost-time accidents during the last year
Let B denote events that employees suffered lost-time accidents during the current year
P(A) = 5% = 0.05
P(B) = 4% = 0.04
P(B | A) = 15% = 0.15
(a) P (A ∩ B) = P(B | A) × P(A)
= 0.15 × 0.05
= 0.0075
= 0.0 (1 decimal place)
The probability that an employee will experience a lost- time accident in both years is 0.0
Lester worked 12 hours last week at the grocery store and earned $93.00. If he continues to earn the same hourly pay, how many additional hours must he work to earn another $62.00?
A. 9 hours
B. 10 hours
C. 11 hours
D. 8 hours
Answer:
8 hours
Step-by-step explanation:
We can use a ratio to solve
12 hours x hours
---------- = ------------
93 dollars 62 dollars
Using cross products
12 * 62 = 93x
Divide each side by 93
12*62/93 = 93x/93
8 = x
8 hours
To determine the density of grains, a student uses a 50ml beaker graded by 5ml increments and a scale with 1g absolute uncertainty. The measurement of the volume results in 3 full beakers and 1 beaker filled up to 30ml. Measured mass of a plastic container with all the grains is 185 grams; measured mass of the same container without grains is 65 grams. What is the mass of the grains
Answer:
The mass of the grains = 120 ± 1 g
Step-by-step explanation:
we are given the following:
Total mass of container + grains = 185 grams
Mass of container = 65 grams
Therefore, mass of grains is calculated as follows:
Mass of grains = ( Mass of container + grains) - mass of container
= 185 - 65 = 120 grams.
since the scale has an absolute uncertainty of 1 g, the mass of the grains is written as 120 ± 1 g
Two samples are randomly selected from each population. The sample statistics are given below.
n1 = 150 n2 = 275
x1 = 72.86 -x2 = 67.34
s1 = 15.98 s2 = 35.67
The value of the standardized test statistic to test the claim that μ1 > μ2 is _________.
-2.19
2.19
3.15
-3.15
Answer:
Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]
Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]
The statistic is given by:
[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]
And replacing we got:
[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]
And the best option would be:
2.19
Step-by-step explanation:
We have the following info given:
n1 = 150 n2 = 275
[tex]\bar x_1 = 72.86, \bar x_2 = 67.34[/tex]
s1 = 15.98 s2 = 35.67
We want to test the following hypothesis:
Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]
Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]
The statistic is given by:
[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]
And replacing we got:
[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]
And the best option would be:
2.19
Help me, please ?? :)
Answer:
a) 11
b) 16
c) between 5 and 6
d) 16
Step-by-step explanation:
[tex]\text{a. }\quad\sqrt{121}=\sqrt{11^2}=\boxed{11}\\\\\text{b. }\quad 8\sqrt{4}=8\sqrt{2^2}=8\cdot 2=\boxed{16}\\\\\text{c. }\quad\sqrt{35}\ \dots\ \sqrt{25}<\sqrt{35}<\sqrt{36}\\\\\text{ }\qquad\sqrt{5^2}<\sqrt{35}<\sqrt{6^2}\\\\\text{ }\qquad \boxed{5<\sqrt{35}<6}\\\\\text{d. }\quad\dfrac{.8}{.05}=\dfrac{0.80\cdot 20}{.05\cdot 20}=\dfrac{16}{1}=\boxed{16}[/tex]
Name the numerator and the denominator in each fraction 11⁄12
. 7⁄512
. 12⁄10
0⁄78
Answer:
numerators: 11 7. 12. 0
_ _ _. _
denominators. 12 512. 10. 78
Step-by-step explanation:
Answer:
11/12 n:11 d:12
7/512 n:7 d:512
12/10 n:12 d:10
0/78 n:0 d:78
Step-by-step explanation:
n=numerator
d=denominator