Which of the following industries is leaching used in?
To separate a metal from its ore using acid and preserving desirable products such as gold.
To separate a mixture of ethanol and water
To separate a slurry containing chalk and water
None of the above.

The sulfuric acid can be constituted into different concentrations using distilled water as a diluent.

Dilution of acid is defined as the decrease in the concentration of an acid using water.

For sulfuric acid to be diluted, it is slowly added to distilled water using the following guidelines:

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(CH₂)n=42

(14)n=42

n=3

C₃H₆

Answer: I think 82.46

Explanation: The atomic number for strontium, or Sr on the periodic table, is 38. With knowing the atomic number, I multiplied that by the number of moles given.

38 × 2.17 = 82.46

I hope this helps!!

The number of atoms present in 2.17 moles of strontium are  [tex]1.306774 \times 10^{24}[/tex].

An atom is the smallest indivisible unit of a chemical element that retains the chemical properties of that element. It is the basic building block of matter.

To determine the number of atoms in a given number of moles, we can use Avogadro's number, which is approximately [tex]6.022 \times 10 ^{24}[/tex] atoms per mole.

In this case, we have 2.17 moles of strontium. To find the number of atoms, we multiply the number of moles by Avogadro's number:

Number of atoms = [tex]2.17 moles\times6.022\times 10^{23}[/tex][tex]atoms/mole[/tex]

On calculating this expression:

Number of atoms =[tex]1.306774 \times 10^{24}[/tex]

Therefore, there are approximately [tex]1.306774 \times 10^{24}[/tex] atoms in 2.17 moles of strontium.

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Avogadro's law states that in a mole of any substance, there are [tex]6.022 \times 10^{23}[/tex] atoms. This means that in the given sample, there are

[tex]\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}[/tex]

So, the atomic mass of sulfur dioxide is

[tex]32.06+2(15.9994=64.0588 \text{ g/mol}[/tex]

Therefore, the mass is:

[tex](64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}[/tex]

Answer: A. Wearing loose comfortable clothing so you can concentrate on the lab.

Explanation:

Wearing loose clothing can make it cling onto certain things, which could create a spill or a different hazard. B, C, and D are all things you SHOULD be doing to achieve safe lab behavior.

I hope this helps! Pls give brainliest!! :)

C= 87.8 : 12 = 7.316

H= 12.2 : 1 = 12.2

C : H = 1 : 1.667 =  3 : 5

C₃H₅

Answer:

D.) It has a negative charge and is located in orbitals around the nucleus.

Explanation:

Electrons always have a negative charge. Since electrons can be shared or donated/received, they must be located in the orbitals around the nucleus. Protons, which have a positive charge, and neutrons, which are neutral, are  located in the nucleus.

M = n/V

V = n/M

V = (14.5 : 56.1056)/2.8

V = 0.0923 L = 92.3 mL

Running blades is the controversial prosthetics which may confer an athletic advantage over able-bodied runners.

This is also referred to as running prosthetics which allows someone move faster with less effort.

This happens when top speed has been achieved and offers an advantage over able-bodied runners.

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350 Kcal is equals to 350000 calorie and 1464400 Joule.

The equation for calculating the energy content of a food source via calorimetry is as follows: Energy (joules) = Mass of water (g) × 4.2 (J/gºC) × Temperature increase (ºC)

1 Kcal = 1000 calorie

Therefore,

35 Kcal = 350 x 1000

            = 350000 calorie

Now,

1 calorie = 4.184 joule

Therefore,

35000 calorie = 350000 x 4.184

                        = 1464400 joule

Hence, 350 Kcal is equals to 350000 calorie and 1464400 Joule.

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Answer:

The time required to decompose the substance is 360 seconds.

The error caused will lower the number of moles when he did not do the second heating.This question is related to the empirical formula.

A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

The empirical formula is the simplest ratio of atoms in a given compound.

we know that heating is used to eliminate most of the water molecules which are attached to the compound in the question, it's given that the second heating was not performed by the students.

This means that there are still some water molecules attached to the compound. This will imply that higher mass will be calculated for the compound because the water molecules are also considered.

So now, if we look at the calculation for the number of moles of water in this, we can say that this will be lower than the actual amount.

This is because there are some unaccounted moles of water which are still attached to the compound and these will be accounted in the compound mass rather than the waters. Therefore, the number of moles will be lower.

Hence, The error caused will lower the number of moles when he did not do the second heating.

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Answer:

The two that are true are, "this represents a pure compound in two different states" and "it represents a mixture a solid and a gas".

Explanation:

This two are concluded only from the picture and the use of uniform colors throughout the picture (Showing the same element).

To determine the percentage yield, do the following:

Stoichiometry simply defined the relationships of the various quantities as they react in a chemical reaction

Scientist are mostly inquisitive and as such may want to determine the percentage yield of a reaction even before carrying it out.

To determine the percentage for a given reaction, we must set up the following:

From the above, we can conclude that option A gives the right steps if we must successfully determine the percentage yield of a reaction.

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Answer:

A

Explanation:

Edge 2022

The variable "air pressure inside the football" in this experiment is quantitative and dependent variable. Hence, option D is correct.

The dependent variable is the variable that is being measured or tested in an experiment.

In the experiment, the scientist filled the footballs with fix quantity of pressure which was then kept for 12 hours. After 12 hours the pressure inside the footballs was again measured. Pressure here is a quantitative variable.

Since the air temperature is an independent variable. The pressure being the dependent variable depends upon the temperature of the air.

Independent variable; The variable which does not depends upon any other variable.

Dependent variable; The variable which depends upon the independent variable or varies with the change independent variable.

Qualitative variables are variables which cannot be expressed in form of numbers. They generally convey the characteristic, category, quality or type.

Whereas Quantitative variables are the variables which can be expressed in the form of numbers. These are the variables which exist along the continuous sequence.

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Answer:

4.458 L

Explanation:

Assuming the pressure remains constant  and assuming 24° C and 58° C

V1/T1  = V2/T2       Where T is in Kelvin

V1/T1  *  T2  = V2

4 / ( 273.15 +24)    *    ( 273.15 + 58)    =  4.458 L

Answer:

[tex]a. \ \ \ \text{The mass of ethylene is 11.375 g}. \\ \\ b. \ \ \ \text{The volume of water produced is 7.875 ml}.[/tex]

Explanation:

a. According to the chemical equation for the combustion of ethylene, 5

   moles of oxygen are required to react with 2 moles of ethylene, hence

           [tex]m_{C_{2}H_{2}} \ = \ 35 \ \text{g} \ \times \ \displaystyle\frac{1 \ \text{mol}}{\left(2 \times 16 \right) \text{g}} \ \times \ \displaystyle\frac{2 \ \text{mol}}{5 \ \text{mol}} \ \times \ \displaystyle\frac{\left(12 \ \times \ 2 \ + \ 1 \ \times \ 2 \right) \ \text{g}}{1 \ \text{mol}} \\ \\ m_{C_{2}H_{2}} \ = \ 11.375 \ \text{g}[/tex]

b. Similarly, 5 moles of oxygen are required as a reactant to produce 2  

    moles of water, thus

             [tex]m_{H_{2}O} \ = \ 35 \ \text{g} \ \times \ \displaystyle\frac{1 \ \text{mol}}{\left(2 \times 16 \right) \text{g}} \ \times \ \displaystyle\frac{2 \ \text{mol}}{5 \ \text{mol}} \ \times \ \displaystyle\frac{\left(1 \ \times \ 2 \ + \ 16 \right) \ \text{g}}{1 \ \text{mol}} \\ \\ m_{H_{2}O} \ = \ 7.875 \ \text{g}[/tex]

      Given that the density of water is [tex]1.0 \ \text{g ml}^{-1}[/tex], therefore

                                               [tex]\rho_{H_{2}O} \ = \ \displaystyle\frac{m_{H_{2}O}}{V_{H_{2}O}} \\ \\ V_{H_{2}O} \ = \ \displaystyle\frac{m_{H_{2}O}}{\rho_{H_{2}O}} \\ \\ V_{H_{2}O} \ = \ \displaystyle\frac{7.875 \ \text{g}}{1.0 \ \text{g ml}^{-1}} \\ \\ V_{H_{2}O} \ = \ 7.875 \ \text{ml}[/tex]

11.375 g ethylene is consumed if 35.0 grams of oxygen is allowed to react and 7.875 ml of water will be produced when the 35.0 grams of oxygen is allowed to react.

A mole is defined as 6.02214076 ×[tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

According to the chemical equation for the combustion of ethylene, 5

moles of oxygen are required to react with 2 moles of ethylene, hence

[tex]m_{_C_2_H_2}[/tex]  [tex]= 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{26g}{1 mol }[/tex]

[tex]m_{_C_2_H_2} = 11.375 g[/tex]

Similarly, 5 moles of oxygen are required as a reactant to produce 2 moles of water, thus

[tex]m_{_H_2_O} = 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{18g}{1 mol }[/tex]

[tex]m_{_H_2_O} = 7.875 g[/tex]

Given that the density of water is [tex]1.0g ml^{-1}[/tex], therefore

[tex]Density = \frac{Mass \;of \;water}{Volume \;of \;water}[/tex]

[tex]Volume \;of \;water = \frac{7.875}{1.0 g ml^{-1}}[/tex]

The volume of water = 7.875 ml

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The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of [tex]SO_2[/tex] molecules in 9.87 moles  [tex]SO_2[/tex] is 59.43 molecules.

The moles of Fe in 1.40 x [tex]10^{22}[/tex] atoms of Fe is 0.23 x [tex]10^{-1}[/tex]

The moles of [tex]C_2H_6O[/tex] in 2.30x[tex]10^{24}[/tex] molecules of [tex]C_2H_6O[/tex] is 3.81.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × [tex]10^{23}[/tex] x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of [tex]SO_2[/tex] molecules in 9.87 moles of [tex]SO_2[/tex]:

6.02214076 × [tex]10^{23}[/tex] x 9.87

59.4385293 molecules= 59.43 molecules

C. The moles of Fe in 1.40 x [tex]10^{22}[/tex] atoms of Fe:

1.40 x [tex]10^{22}[/tex] ÷ 6.02214076 × [tex]10^{23}[/tex]

0.2324754694 x [tex]10^{-1}[/tex] moles.

0.23 x [tex]10^{-1}[/tex] moles.

D. The moles of [tex]C_2H_6O[/tex] in 2.30x[tex]10^{24}[/tex] molecules of [tex]C_2H_6O[/tex]:

2.30x[tex]10^{24}[/tex] ÷ 6.02214076 × [tex]10^{23}[/tex]

3.819239854 moles=3.81 moles

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Answer:

A

Explanation:

Answer: The true volume of the gas will be lower than predicted by the ideal gas law because the volume of the actual particles is more significant under high pressure.

2Li + 2H2O____ 2LiaOH + 2H2

Answer:

2 Li + 2 H2O --> 2 LiaOH + 1 H2

Assuming pressure is held constant,

[tex]\frac{8}{3}=\frac{V_{2}}{4}\\\\V_{2}=4\left(\frac{8}{3} \right) \approx \boxed{10.7 \text{ L}}[/tex]

Answer:

2 Hg (g) + o2 ---> 2 H2o

equilibrium constant

K = (c) (d) / (a)(b)

K= ( H2o)²/(He) ²(o2)

Oven cleaners typically contain a layer of sodium hydroxide, which converts the greases and oils on the oven walls into soap, which can then be cleaned away more easily.

A chamber used for baking, heating, or drying.

Self-cleaning ovens emit dangerous fumes into the air with an unpleasant burning smell. Self-cleaning ovens reach high temperatures and produce fumes from the cooking of food particles. These fumes circulate with the air and can affect the home substances.

Spray-on oven cleaner ovens contain a layer (sodium hydroxide), which converts the greases of the oven walls into soap, which can then be cleaned away more easily.

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2.73 atm is the pressure in the vessel. Hence, option B is correct.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= ?

V= 25.1 L

[tex]n= \frac{m}{molar \;mass \;of \;nitrogen} + \frac{m}{molar \;mass \;of \;hydrogen } +\frac{m}{molar \;mass \;of \;argon}[/tex]

[tex]n= \frac{2.80 g}{14} + \frac{0.605 g}{1} +\frac{79.9 g}{40}[/tex]

n= 2.8025

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=25°C + 273= 298 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]2.8025 = \frac{P\; X \;25.1 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]

P = 2.73 atm

2.73 atm is the pressure in the vessel. Hence, option B is correct.

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Answer:

b

Explanation:

because it freezer in temperature