Which statement correctly compares the values in the statement? StartAbsoluteValue negative 0.45 EndAbsoluteValue blank box StartAbsoluteValue negative 0.0045 EndAbsoluteValue 0.45 greater-than 0.0045 Negative 0.45 less-than 0.0045 0.45 less-than 0.0045 0.45 = 0.0045

Answers

Answer 1

Answer:

The correct statement that compares the values is:0.45 greater-than 0.0045

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Related Questions

y =
cos^-4x-7(x)
Find the derivative of y=cos ^{-4 x-7}(x) , Be sure to include parentheses around the arguments of any logarithmic or trigonometric functions in your answer: Sorry, that's incorrect. Try again?

Answers

The derivative of y = cos^{-4x-7}(x) is -4x-7 * cos(x)^{-4x-8} * (-sin(x)).

To find the derivative of y = cos^{-4x-7}(x), we need to use the chain rule and the power rule. The chain rule allows us to differentiate composite functions, while the power rule applies when we have a function raised to a constant power.

Let's rewrite the function as y = cos(x)^{-4x-7} to make it easier to work with.

Apply the chain rule by considering the derivative of the outer function and the derivative of the inner function.

The derivative of the outer function cos(x)^{-4x-7} is -4x-7 * (cos(x)^{-4x-7-1}) * (-sin(x)).

Simplify the derivative of the outer function to obtain -4x-7 * cos(x)^{-4x-8} * (-sin(x)).

Now, we need to find the derivative of the inner function, which is simply 1.

Multiply the derivative of the outer function (-4x-7 * cos(x)^{-4x-8} * (-sin(x))) by the derivative of the inner function (1) to obtain the overall derivative.

The final derivative of y = cos^{-4x-7}(x) is -4x-7 * cos(x)^{-4x-8} * (-sin(x)).

Note: In the final answer, it is essential to use parentheses around the arguments of the trigonometric functions to avoid any confusion or ambiguity in the notation.

Therefore, the derivative of y = cos^{-4x-7}(x) is -4x-7 * cos(x)^{-4x-8} * (-sin(x)).

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examine the following table, and select the most appropriate response: b1 b1 a1 35 60 a2 60 35 hint: remember to calculate row means and column means!!!

Answers

The most appropriate response is 47.5.

We are given that;

The table  b1 b1 a1 35 60 a2 60 35

Now,

According to 1, a row is a series of data placed horizontally in a table or spreadsheet, while a column is a vertical series of cells in a table or spreadsheet. A row mean is the average of the values in a row, while a column mean is the average of the values in a column.

To calculate the row means and column means for the given table, we can use the following formulas:

Row mean for a1 = (35 + 60) / 2 = 47.5

Row mean for a2 = (60 + 35) / 2 = 47.5

Column mean for b1 = (35 + 60) / 2 = 47.5

Column mean for b2 = (60 + 35) / 2 = 47.5

One possible response is:

The row means and column means are equal for this table, which suggests that there is no difference between the levels of a or b.

Therefore, by rows and column answer will be 47.5.

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What is the algebraic expression for half of a number?

Answers

The algebraic expression for half of a number is x/2.

What is the algebraic expression for half of a number?

When we are working in algebra and we want to represent "a number", we use a variable for it.

We do this because "a number" can be any real number.

For example, we can say that a number is represented by the variable x.

Now, to write half of a number, we just need to divide our variable by 2, then we will get:

x/2

That is the algebraic expression.

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What is the radius of convergence at x=0?
x(x²+4x+9)y"-2x²y'+6xy=0
a.2
b.3
c.1
d.infinite

Answers

The radius of convergence at x=0 is 6. The correct option is d. infinite

x(x²+4x+9)y"-2x²y'+6xy=0

The given equation is in the form of x(x²+4x+9)y"-2x²y'+6xy = 0

To determine the radius of convergence at x=0, let's consider the equation in the form of

[x - x0] (x²+4x+9)y"-2x²y'+6xy = 0

Where, x0 is the point of expansion.

Thus, we can consider x0 = 0 to simplify the equation,[x - 0] (x²+4x+9)y"-2x²y'+6xy = 0

x (x²+4x+9)y"-2x²y'+6xy = 0

The given equation can be simplified asx(x²+4x+9)y" - 2x²y' + 6xy = 0

⇒ x(x²+4x+9)y" = 2x²y' - 6xy

⇒ (x²+4x+9)y" = 2xy' - 6y

Now, we can substitute y = ∑an(x-x0)n

Therefore, y" = ∑an(n-1)(n-2)(x-x0)n-3y' = ∑an(n-1)(x-x0)n-2

Substituting the value of y and its first and second derivative in the given equation,(x²+4x+9)y" = 2xy' - 6y

⇒ (x²+4x+9) ∑an(n-1)(n-2)(x-x0)n-3 = 2x ∑an(n-1)(x-x0)n-2 - 6 ∑an(x-x0)n

⇒ (x²+4x+9) ∑an(n-1)(n-2)xⁿ = 2x ∑an(n-1)xⁿ - 6 ∑anxⁿ

On simplifying, we get: ∑an(n-1)(n+2)xⁿ = 0

To find the radius of convergence, we use the formula,

R = [LCM(1,2,3,....k)/|ak|]

where ak is the non-zero coefficient of the highest degree term.

The highest degree term in the given equation is x³.

Thus, the non-zero coefficient of x³ is 1.Let's take k=3

R = LCM(1,2,3)/1 = 6

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In reality how many Scopes can be manifested through different means of creating variables? 4+ - Local, Global, Block ... and other forms of Globalness depending on what you're working with and how you make things 2- Global and Local 3- Global, Local and Block 1 - There is only global scope

Answers

In reality, multiple scopes can be manifested through different means of creating variables. The most common types of scopes include local, global, and block scopes.

The scope of a variable determines its visibility and accessibility within a program. The different types of scopes include:

Local Scope: Variables declared within a specific block or function have local scope. They are accessible only within that block or function and are not visible to the rest of the program.

Global Scope: Variables declared outside of any function or block have global scope. They are accessible from anywhere within the program and can be accessed by any function or block.

Block Scope: Some programming languages, such as Java, introduce block scope, which is a subset of local scope. Variables declared within a block, such as within loops or conditional statements, have block scope and are only accessible within that block.

In addition to these common scopes, there may be variations or additional forms of scope depending on the programming language and specific context.

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Answer the following questions. Show all your work. If you use the calculator at some point, mention its use. 1. The weekly cost (in dollars) for a business which produces x e-scooters and y e-bikes (per week!) is given by: z=C(x,y)=80000+3000x+2000y−0.2xy^2 a) Compute the marginal cost of manufacturing e-scooters at a production level of 10 e-scooters and 20 e-bikes. b) Compute the marginal cost of manufacturing e-bikes at a production level of 10 e-scooters and 20-ebikes. c) Find the z-intercept (for the surface given by z=C(x,y) ) and interpret its meaning.

Answers

A) The marginal cost of manufacturing e-scooters at a production level of 10 e-scooters and 20 e-bikes is 2200 .B) The marginal cost of manufacturing e-bikes at a production level of 10 e-scooters and 20 e-bikes is 1800 .C) The z-intercept is (0,0,80000).

A) Marginal cost of manufacturing e-scooters = C’x(x,y)First, differentiate the given equation with respect to x, keeping y constant, we get C’x(x,y) = 3000 − 0.4xyWe have to compute the marginal cost of manufacturing e-scooters at a production level of 10 e-scooters and 20 e-bikes. Putting x=10 and y=20, we get, C’x(10,20) = 3000 − 0.4 × 10 × 20= 2200Therefore, the marginal cost of manufacturing e-scooters at a production level of 10 e-scooters and 20 e-bikes is 2200.

B) Marginal cost of manufacturing e-bikes = C’y(x,y). First, differentiate the given equation with respect to y, keeping x constant, we get C’y(x,y) = 2000 − 0.4xyWe have to compute the marginal cost of manufacturing e-bikes at a production level of 10 e-scooters and 20 e-bikes. Putting x=10 and y=20, we get,C’y(10,20) = 2000 − 0.4 × 10 × 20= 1800Therefore, the marginal cost of manufacturing e-bikes at a production level of 10 e-scooters and 20 e-bikes is 1800.

C) The z-intercept (for the surface given by z=C(x,y)) is given by, put x = 0 and y = 0 in the given equation, we getz = C(0,0)= 80000The z-intercept is (0,0,80000) which means if a business does not produce any e-scooter or e-bike, the weekly cost is 80000 dollars.

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a statistical procedure used to describe the strength and direction of the linear relationship between two factors is called ______

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The statistical procedure used to describe the strength and direction of the linear relationship between two factors is called correlation analysis.

Correlation analysis is a statistical technique that examines the relationship between two variables to determine the strength and direction of their association. It focuses specifically on the linear relationship between the variables, which means it assumes that the relationship can be represented by a straight line.

The result of a correlation analysis is often expressed as a correlation coefficient, which measures the degree of association between the variables. The correlation coefficient ranges from -1 to 1, where:

A correlation coefficient of -1 indicates a perfect negative correlation, meaning that as one variable increases, the other variable decreases in a consistent manner.

A correlation coefficient of 1 indicates a perfect positive correlation, meaning that as one variable increases, the other variable also increases in a consistent manner.

A correlation coefficient close to 0 indicates a weak or no linear correlation between the variables.

Correlation analysis helps to understand the relationship between variables and can provide insights into patterns, trends, and dependencies in the data. However, it is important to note that correlation does not imply causation, meaning that a strong correlation between two variables does not necessarily imply that one variable causes the other to change.

In addition to determining the correlation coefficient, correlation analysis can also involve generating a scatter plot to visualize the relationship between the variables and conducting hypothesis tests to assess the statistical significance of the correlation.

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Find the grammar for Σ={a,b} that generates the following language where n a

(w) is the number of a's in w: {w:n a

(w)≥n b

(w)}

Answers

The grammar for Σ={a,b} that generates the following language where na(w) is the number of a's in w: {w:na(w)≥nb(w)} is as follows:

We need to design a grammar for the language L, which contains all those strings in Σ = {a,b} where na(w) ≥ nb(w).

Let's assume that the grammar has a start symbol of S.

The grammar rules are defined as follows:

S → ASB | ε

Here, A and B are two non-terminal symbols. The ε symbol denotes the empty string.

The first rule means that we may add both an A and a B to the string to keep it in the language, or we may do nothing and produce the empty string.

The second rule indicates that we can append an A to the string or a B can be removed from the string.

In the initial phase, we have S and we can either apply rule 1 or rule 2.

Then, we apply the rules again and again until the final string is obtained.

We can generate various strings using these rules.

Here are some examples:

w = ε,

S ⇒ εw = aaabbb,

S ⇒ ASB ⇒ aASBb ⇒ aaASBBbb ⇒ aaaABBBBbb ⇒ aaabbbw = bbaaa,

S ⇒ ASB ⇒ ASABb ⇒ ASASBBb ⇒ AASASBBbb ⇒ AAASASBBbbb ⇒ AAASASbbb

(Since the number of a's is more than b's, the last b is discarded.)

Thus, we've demonstrated how the grammar given in the solution generates the language.

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determine where each function is continuous. 1. f(x, y)=3x²y-4x²y²+10xy²-9 2. f(x, y) =x³+ 2x²y+xy²-4y³ = 3. f(x, y) =(x²-y²)/x-y

Answers

The function is continuous for all (x, y) in R except x = y.

To determine where each function is continuous, we need to calculate its domain. For a function to be continuous, its domain must be continuous or connected. Below are the domain and continuity of the given functions:

1. The domain of f(x, y) = 3x²y - 4x²y² + 10xy² - 9 is all real numbers. Since the function is a polynomial, it is continuous for all real numbers. Therefore, the function is continuous for all (x, y) in R.

2. The domain of f(x, y) = x³ + 2x²y + xy² - 4y³ is all real numbers. Since the function is a polynomial, it is continuous for all real numbers. Therefore, the function is continuous for all (x, y) in R.

3. The domain of f(x, y) = (x² - y²) / (x - y) is all real numbers except x = y. We know this because we can simplify the function: f(x, y) = (x + y)(x - y) / (x - y) = x + y. This function is a plane, and it is continuous for all real numbers except x = y. Therefore, the function is continuous for all (x, y) in R except x = y.

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Does listening to music affect how many words you can memorize? Student researchers tried to answer this question by having 20 subjects listen to music while trying to memorize words and also had the same 20 subjects try to memorize words when not listening to music. They randomly determined which condition was done first for each of their subjects. Here are their hypotheses:Null: The average of the difference in number of words memorized (no music − with music) is 0 (μd = 0).Alternative: The average of the difference in number of words memorized (no music − with music) is greater than 0 (μd > 0).The students found the following results in terms of number of words memorized:No music With music DifferenceMean 13.9 10.2 3.7Standard deviation 3.15 3.07 3.08

Answers

The experiment provides evidence to support the alternative hypothesis that the average difference in the number of words memorized (no music - with music) is greater than 0.

To evaluate the effect of music on word memorization, the researchers compared the mean number of words memorized under the two conditions: with music and without music. The mean number of words memorized without music was found to be 13.9, while with music it was 10.2. By subtracting the mean number of words memorized with music from the mean number of words memorized without music, we get a difference of 3.7.

Additionally, the researchers calculated the standard deviations for both conditions. The standard deviation for the "no music" condition was 3.15, while for the "with music" condition it was 3.07.

To determine whether the null hypothesis should be rejected in favor of the alternative hypothesis, we can perform a statistical test. In this case, since the sample size is small (20 subjects), we can use a paired t-test.

Running the paired t-test using the given data, we find that the t-value is calculated as (3.7 - 0) / (3.08 / √(20)) ≈ 4.66.

Looking up the critical value for a one-tailed test with 19 degrees of freedom (n - 1 = 20 - 1 = 19) at a significance level of 0.05, we find it to be approximately 1.73. Since our calculated t-value (4.66) is greater than the critical value (1.73), we can reject the null hypothesis.

Therefore, based on the results of the experiment and the statistical analysis, we can conclude that listening to music does indeed affect the ability to memorize words, as the subjects in this study were able to memorize significantly more words without music compared to when they were listening to music.

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a population has a standard deviation a=24.9.How large a sample must be drawn so that a 95% confidence interval foru will have a margin of error equal to 4.4

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A sample size of at least 107 must be drawn in order to obtain a 95% confidence interval with a margin of error equal to 4.4, assuming a population standard deviation of 24.9.

To determine the sample size required for a 95% confidence interval with a specific margin of error, we can use the formula:

n = (Z * σ / E)^2

where:

n = required sample size

Z = Z-score corresponding to the desired confidence level (in this case, for a 95% confidence level, Z ≈ 1.96)

σ = population standard deviation

E = margin of error

Given:

σ = 24.9

E = 4.4

Plugging in these values into the formula, we get:

n = (1.96 * 24.9 / 4.4)^2 ≈ 106.732

Rounding up to the nearest whole number, the sample size required is approximately 107.

Therefore, a sample size of at least 107 must be drawn in order to obtain a 95% confidence interval with a margin of error equal to 4.4, assuming a population standard deviation of 24.9.

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Find ∣z∣, the absolute value (or magnitude, or modulus) of the complex number z=2−3i. ∣z∣=2 None of the options displayed. ∣z∣=5 ,∣z∣=sqrt(13), ∣z∣=13, ∣z∣=±sqrt(13), ∣z∣=−1 ∣z∣=1 ∣z∣=−sqrt(13)

Answers

The absolute value (magnitude) of the complex number z = 2 - 3i is ∣z∣ = sqrt(13).

To find the absolute value (magnitude) of the complex number z = 2 - 3i, we use the formula:

∣z∣ = sqrt(a^2 + b^2), where a and b are the real and imaginary parts of z, respectively.

In this case, a = 2 and b = -3. Substituting these values into the formula:

∣z∣ = sqrt(2^2 + (-3)^2)

= sqrt(4 + 9)

= sqrt(13)

Therefore, the absolute value (magnitude) of the complex number z = 2 - 3i is ∣z∣ = sqrt(13).

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Calculate the numerical value of the midpoint m of the interval (a, b), where a=0.696 and b=0.699, in the following finite precision systems F(10,2,-[infinity], [infinity]), F(10,3, -[infinity], [infinity]) and F(10,4, -[infinity], [infinity]) Using truncation and rounding as approximation methods.

Answers

Using truncation and rounding as approximation methods, the numerical value of the midpoint is approximately 0.6975 in the specified finite precision systems F(10,3,-∞,∞) and F(10,4,-∞,∞).

To calculate the midpoint of the interval (a, b), we use the formula:

m = (a + b) / 2.

Using truncation as an approximation method, we will truncate the numbers to the specified precision.

In the F(10,2,-∞, ∞) system:

a = 0.696 → truncate to 0.69

b = 0.699 → truncate to 0.69

m = (0.69 + 0.69) / 2 = 1.38 / 2 = 0.69

In the F(10,3,-∞, ∞) system:

a = 0.696 → truncate to 0.696

b = 0.699 → truncate to 0.699

m = (0.696 + 0.699) / 2 = 1.395 / 2 = 0.6975

In the F(10,4,-∞, ∞) system:

a = 0.696 → truncate to 0.6960

b = 0.699 → truncate to 0.6990

m = (0.6960 + 0.6990) / 2 = 1.3950 / 2 = 0.6975

Using rounding as an approximation method, we will round the numbers to the specified precision.

In the F(10,2,-∞, ∞) system:

a = 0.696 → round to 0.70

b = 0.699 → round to 0.70

m = (0.70 + 0.70) / 2 = 1.40 / 2 = 0.70

In the F(10,3,-∞, ∞) system:

a = 0.696 → round to 0.696

b = 0.699 → round to 0.699

m = (0.696 + 0.699) / 2 = 1.395 / 2 = 0.6975

In the F(10,4,-∞, ∞) system:

a = 0.696 → round to 0.6960

b = 0.699 → round to 0.6990

m = (0.6960 + 0.6990) / 2 = 1.3950 / 2 = 0.6975

Therefore, the numerical value of the midpoint (m) using truncation and rounding as approximation methods in the specified finite precision systems is as follows:

Truncation:

F(10,2,-∞, ∞): m = 0.69

F(10,3,-∞, ∞): m = 0.6975

F(10,4,-∞, ∞): m = 0.6975

Rounding:

F(10,2,-∞, ∞): m = 0.70

F(10,3,-∞, ∞): m = 0.6975

F(10,4,-∞, ∞): m = 0.6975

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Find ∫15f(X)Dx If Given That ∫15(F(X)−3g(X))Dx=4,∫71g(X)Dx=1 And ∫75g(X)Dx=2

Answers

Let's solve the integral ∫15f(X)dX using the given information.

We know that ∫15(F(X)−3g(X))dX = 4. We can rewrite this as ∫15F(X)dX - 3∫15g(X)dX = 4.

From the given information, we have ∫71g(X)dX = 1 and ∫75g(X)dX = 2. By subtracting these two equations, we get ∫75g(X)dX - ∫71g(X)dX = 2 - 1, which simplifies to ∫75g(X)dX - ∫71g(X)dX = 1.

Substituting these values back into the equation ∫15F(X)dX - 3∫15g(X)dX = 4, we have ∫15F(X)dX - 3(1) = 4.

Simplifying further, we have ∫15F(X)dX = 7.

Therefore, ∫15f(X)dX = 7.

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If P(A)=0.19,P(B)=0.31, and P(A and B)=0.18, then P(A∣B)= Type numbers so points (Please round to two decimal places.) If P(A)=0.18,P(B)=0.89, and P(A or B)=0.91, then P(A∣B)= Type numbers topoints (Please round to two decimal places.)

Answers

For (1) calculated probability P(A|B) = 0.582.

For (2) calculated probability P(A|B) = 0.16

1. If P(A)=0.19,

P(B)=0.31, and

P(A and B)=0.18,

then P(A∣B)= Type numbers to points (Please round to two decimal places.)

We have the following information:

P(A) = 0.1

9P(B) = 0.31

P(A and B) = 0.18

We need to find P(A|B)

Using conditional probability formula,

P(A|B) = P(A and B) / P(B)

= 0.18 / 0.31

= 0.58 (rounded to two decimal places)

Therefore, P(A|B) = 0.58

2. If P(A)=0.18,

P(B)=0.89, and

P(A or B)=0.91,

then P(A∣B)=

Type numbers to points (Please round to two decimal places.)

We have the following information:

P(A) = 0.18

P(B) = 0.89

P(A or B) = 0.91

We need to find P(A|B)

Using the formula,

P(A|B) = P(A and B) / P(B)

= P(A or B) / P(B)

= (P(A) + P(B) - P(A and B)) / P(B)

= (0.18 + 0.89 - 0.91) / 0.89

= 0.16 (rounded to two decimal places)

Therefore, P(A|B) = 0.16

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1. Let V be a real inner product space over R. Show that for any vectors u and v in V , || u+v||^{2}+|| u-v||^{2}=2|| u||^{2}+\left.2|| v\right|^{2} 2. Consider the vector

Answers

For any vectors u and v in V, ||u+v||^2 + ||u-v||^2 = 2||u||^2 + 2||v||^2.

Let V be a real inner product space over R. Show that for any vectors u and v in V, ||u+v||^2 + ||u-v||^2 = 2||u||^2 + 2||v||^2.

Here's the solution for the above question. Since V is a real inner product space over R, it follows that u and v are vectors in V. Then, by definition of an inner product space, for u and v in V: ||u+v||^2 + ||u-v||^2 = 2||u||^2 + 2||v||^2.

To prove the above, we will use the properties of inner products. First, we can use the property of linearity of the inner product and the distributive law of scalar multiplication over vector addition, then we get the following:

||u+v||^2 + ||u-v||^2 = <u+v, u+v> + <u-v, u-v> = <u,u> + <v,v> + <u,v> + <v,u> + <u,u> - <v,v>

||u+v||^2 + ||u-v||^2 = 2||u||^2 + 2||v||^2

Therefore, for any vectors u and v in V, ||u+v||^2 + ||u-v||^2 = 2||u||^2 + 2||v||^2.

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Sasha gives clues to her favorite number. She says her favorite number is 13 units from 20 and 15 units from -8 on the number line. What is Sasha's favorite number? Show your work and explain your rea

Answers

Sasha's favorite number is 7.

To find Sasha's favorite number, we can use the clues given: her favorite number is 13 units from 20 and 15 units from -8 on the number line.

Let's denote Sasha's favorite number as "x." According to the clues, we have the following equations:

x - 20 = 13 (Equation 1)

x - (-8) = 15 (Equation 2)

Simplifying Equation 1:

x = 13 + 20

x = 33

Simplifying Equation 2:

x + 8 = 15

x = 15 - 8

x = 7

We have obtained two different values for x: x = 33 and x = 7. However, only one of these values can be Sasha's favorite number.

By analyzing the clues, we can determine that Sasha's favorite number is the one that is 13 units from 20 and 15 units from -8. Among the two values we found, only x = 7 satisfies both conditions.

Therefore, Sasha's favorite number is 7.

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Milan rented a truck for one day. There was a base fee of $19.95, and there was an additional charge of 97 cents for each mile driven. Milan had to pay $162.54 when he returned the truck. For how many

Answers

Milan drove the truck for 147 miles.

Based on the given information, Milan rented a truck for one day. The base fee was $19.95, and there was an additional charge of 97 cents for each mile driven. Milan had to pay $162.54 when he returned the truck.

To find the number of miles Milan drove, we can subtract the base fee from the total amount paid and divide the result by the additional charge per mile.

Total amount paid - base fee = additional charge for miles driven
$162.54 - $19.95 = $142.59 (additional charge for miles driven)

additional charge for miles driven ÷ charge per mile = number of miles driven
$142.59 ÷ $0.97 ≈ 147.07 (rounded to the nearest mile)

Milan drove approximately 147 miles.

COMPLETE QUESTION:

Milan rented a truck for one day. There was a base fee of $19.95, and there was an additional charge of 97 cents for each mile driven. Milan had to pay $162.54 when he returned the truck. For how many miles did he drive the truck? miles

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Write a function called square _odd that has one parameter. Your function must calculate the square of each odd number in a list.
Return a Python list containing the squared values.
### START FUNCTION
def square_odd(pylist):
# your code here
return
### END FUNCTION

Answers

Here's the modified function called `square_odd` that squares each odd number in a given list and returns a new list containing the squared values:

```python

def square_odd(pylist):

   squared_list = []

   

   for num in pylist:

       if num % 2 != 0:  # Check if the number is odd

           squared_list.append(num ** 2)  # Square the odd number and add it to the new list

   

   return squared_list

```

In this function, we initialize an empty list called `squared_list`. Then, for each number (`num`) in the input list (`pylist`), we check if it is odd by using the modulo operator `%`. If the number is odd, we square it using the exponentiation operator `**` and append the squared value to the `squared_list`. Finally, we return the `squared_list` containing the squared values of all the odd numbers in the original list.

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What is the value of x in the triangle? use a² b²=c² to solve. question 2 options: 4624 68 3600 1024

Answers

The value of x in the triangle is 48.37 units.

What is Pythagorean theorem?

In Mathematics and Geometry, Pythagorean's theorem is modeled or represented by the following mathematical equation:

c² = a² + b²

Where:

a, b, and c are the side lengths of a right-angled triangle.

In order to determine the length of side x or side length x, we would have to apply Pythagorean's theorem as follows;

c² = a² + b²

58² = x² + 32²

x² = 3364 - 1024

x² = √2340

x = 48.37 units.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Suppose a jar contains 9 red marbles and 13 blue marbles. If you reach in the jar and pull out 2. marbles at random, find the probability that both are red. Enter a fraction or decimal rounded to 4 decimal places.

Answers

the probability of pulling out two red marbles from the jar is approximately 0.1742.

To find the probability of pulling out two red marbles, we need to calculate the probability of selecting one red marble on the first draw and then another red marble on the second draw.

The probability of selecting a red marble on the first draw is 9 red marbles out of a total of 22 marbles:

P(Red on 1st draw) = 9/22

After the first marble is drawn, there are 8 red marbles left out of 21 total marbles. So, the probability of selecting a second red marble on the second draw, given that the first marble was red, is:

P(Red on 2nd draw | Red on 1st draw) = 8/21

To find the probability of both events happening (selecting a red marble on the first draw and then another red marble on the second draw), we multiply the probabilities:

P(Both red marbles) = P(Red on 1st draw) * P(Red on 2nd draw | Red on 1st draw)

P(Both red marbles) = (9/22) * (8/21)

P(Both red marbles) ≈ 0.1742 (rounded to 4 decimal places)

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Find the indicated limit.
lim (8t2 − 3t + 1)
t→4

Answers

lim (8t^2 - 3t + 1) as t approaches 4 = 117.This means that as t gets closer and closer to 4, the function (8t^2 - 3t + 1) approaches the value of 117.

To find the limit of the function (8t^2 - 3t + 1) as t approaches 4, we can evaluate the function at t = 4.

Plugging in t = 4 into the function, we have:

(8(4^2) - 3(4) + 1) = (8(16) - 12 + 1) = (128 - 12 + 1) = 117.

Hence, the value of the function at t = 4 is 117.

Now, to determine the limit, we need to see if the function approaches a particular value as t gets arbitrarily close to 4.

By evaluating the function at t = 4, we find that the function is defined and continuous at t = 4. Therefore, the limit of the function as t approaches 4 is equal to the value of the function at t = 4, which is 117.

In summary, we have:

lim (8t^2 - 3t + 1) as t approaches 4 = 117.

This means that as t gets closer and closer to 4, the function (8t^2 - 3t + 1) approaches the value of 117.

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Identify surjective function
Identify, if the function \( f: R \rightarrow R \) defined by \( g(x)=1+x^{\wedge} 2 \), is a surjective function.

Answers

The function f is surjective or onto.

A surjective function is also referred to as an onto function. It refers to a function f, such that for every y in the codomain Y of f, there is an x in the domain X of f, such that f(x)=y. In other words, every element in the codomain has a preimage in the domain. Hence, a surjective function is a function that maps onto its codomain. That is, every element of the output set Y has a corresponding input in the domain X of the function f.

If we consider the function f: R → R defined by g(x)=1 + x², to determine if it is a surjective function, we need to check whether for every y in R, there exists an x in R, such that g(x) = y.

Now, let y be any arbitrary element in R. We need to find out whether there is an x in R, such that g(x) = y.

Substituting the value of g(x), we have y = 1 + x²

Rearranging the equation, we have:x² = y - 1x = ±√(y - 1)

Thus, every element of the codomain R has a preimage in the domain R of the function f.

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Let A=⎣⎡​000​39−9​26−6​⎦⎤​ Find a basis of nullspace (A). Answer: To enter a basis into WeBWorK, place the entries of each vector inside of brackets, and enter a list of these vectors, separated by commas. For instance, if your basis is ⎩⎨⎧​⎣⎡​123​⎦⎤​,⎣⎡​111​⎦⎤​⎭⎬⎫​, then you would enter [1,2,3],[1,1,1] into the answer blank.

Answers

The basis for the nullspace of matrix A is {[3, 0, 1], [-3, 1, 0]}. In WeBWorK format, the basis for null(A) would be entered as [3, 0, 1],[-3, 1, 0].

The set of all vectors x where Ax = 0 represents the zero vector is the nullspace of a matrix A, denoted by the symbol null(A). We must solve the equation Ax = 0 in order to find a foundation for the nullspace of matrix A.

Given the A matrix:

A = 0 0 0, 3 9 -9, 2 6 -6 In order to solve the equation Ax = 0, we need to locate the vectors x = [x1, x2, x3] in a way that:

By dividing the matrix A by the vector x, we obtain:

⎡ 0 0 0 ⎤ * ⎡ x₁ ⎤ ⎡ 0 ⎤

⎣⎡ 3 9 - 9 ⎦⎤ * ⎣⎡ x₂ ⎦ = ⎣⎡ 0 ⎦ ⎤

⎣⎡ 2 6 - 6 ⎦⎤ ⎣⎡ x₃ ⎦ ⎣⎡ 0 ⎦ ⎦

Working on the situation, we get the accompanying arrangement of conditions:

Simplifying further, we have: 0 * x1 + 0 * x2 + 0 * x3 = 0 3 * x1 + 9 * x2 - 9 * x3 = 0 2 * x1 + 6 * x2 - 6 * x3 = 0

0 = 0 3x1 + 9x2 - 9x3 = 0 2x1 + 6x2 - 6x3 = 0 The first equation, 0 = 0, is unimportant and doesn't tell us anything useful. Concentrate on the two remaining equations:

3x1 minus 9x2 minus 9x3 equals 0; 2x1 minus 6x2 minus 6x3 equals 0; and (2) these equations can be rewritten as matrices:

We can solve this system of equations by employing row reduction or Gaussian elimination.  3 9 -9  * x1 = 0  2 6 -6  x2 0  Row reduction will be my method for locating a solution.

[A|0] augmented matrix:

⎡​3 9 -9 | 0​⎤​

⎣⎡​2 6 -6 | 0​⎦⎤​

R₂ = R₂ - (2/3) * R₁:

The reduced row-echelon form demonstrates that the second row of the augmented matrix contains only zeros. This suggests that the original matrix A's second row is a linear combination of the other rows. As a result, we can concentrate on the remaining row instead of the second row:

3x1 + 9x2 - 9x3 = 0... (3) Now, we can solve equation (3) to express x2 and x3 in terms of x1:

Divide by 3 to get 0: 3x1 + 9x2 + 9x3

x1 plus 3x2 minus 3x3 equals 0 Rearranging terms:

x1 = 3x3 - 3x2... (4) We can see from equation (4) that x1 can be expressed in terms of x2 and x3, indicating that x2 and x3 are free variables whose values we can choose. Assign them in the following manner:

We can express the vector x in terms of x1, x2, and x3 by using the assigned values: x2 = t, where t is a parameter that can represent any real number. x3 = s, where s is another parameter that can represent any real number.

We must express the vector x in terms of column vectors in order to locate a basis for the null space of matrix A. x = [x1, x2, x3] = [3x3 - 3x2, x2, x3] = [3s - 3t, t, s]. We have: after rearranging the terms:

x = [3s, t, s] + [-3t, 0, 0] = s[3, 0, 1] + t[-3, 1, 0] Thus, "[3, 0, 1], [-3, 1, 0]" serves as the foundation for the nullspace of matrix A.

The basis for null(A) in WeBWorK format would be [3, 0, 1], [-3, 1, 0].

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How do you know how many solutions a function has?

Answers

The number of solutions of a function depends on various factors, including the type of function and the domain in which it is defined.

1. Degree of the Polynomial: For polynomial functions, the degree of the polynomial determines the maximum number of solutions. A polynomial of degree n can have at most n solutions in the complex numbers. For example, a quadratic equation (degree 2) can have up to two solutions.

2. Function Type: Different types of functions have different properties regarding the number of solutions. For example:

  - Linear Functions: A linear equation (degree 1) has exactly one solution unless it is inconsistent (no solution) or degenerate (infinite solutions).

  - Quadratic Functions: A quadratic equation (degree 2) can have zero, one, or two solutions.

  - Exponential and Logarithmic Functions: Exponential and logarithmic equations can have one or more solutions, depending on the specific equation.

3. Intersections and Intercepts: The number of solutions can be related to the intersections of a function with other functions or with specific values (e.g., x-intercepts or roots). The number of intersections or intercepts gives an indication of the number of solutions.

4. Constraints and Domain: The domain of the function may impose constraints on the number of solutions. For example, if a function is defined only for positive values, it may have no solutions or a limited number of solutions within that restricted domain.

5. Graphical Analysis: Graphing the function can provide insights into the number of solutions. The number of times the graph intersects the x-axis can indicate the number of solutions.

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Find the Derivative, y':
(a) y = x³e-1/x

Answers

The derivative of y = x³e^(-1/x) is y' = 3x²e^(-1/x) - e^(-1/x) / xTo find the derivative of y = x³e^(-1/x), we can use the product rule and the chain rule.

Let's break down the function into its constituent parts:

f(x) = x³

g(x) = e^(-1/x)

Applying the product rule, the derivative of y = f(x) * g(x) is given by:

y' = f'(x) * g(x) + f(x) * g'(x)

Now, let's find the derivatives of f(x) and g(x):

f'(x) = d/dx(x³) = 3x²

To find g'(x), we need to apply the chain rule. Let u = -1/x, then g(x) = e^u. The derivative of g(x) can be calculated as follows:

g'(x) = d/dx(e^u) * du/dx

      = e^u * (-1/x²)

      = -e^(-1/x) / x²

Now, we can substitute the derivatives into the derivative expression:

y' = f'(x) * g(x) + f(x) * g'(x)

  = 3x² * e^(-1/x) + x³ * (-e^(-1/x) / x²)

Simplifying further:

y' = 3x² * e^(-1/x) - (x * e^(-1/x)) / x²

  = 3x² * e^(-1/x) - e^(-1/x) / x

Therefore, the derivative of y = x³e^(-1/x) is y' = 3x²e^(-1/x) - e^(-1/x) / x.

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The volume V(r) (in cubic meters ) of a spherical balloon with radius r meters is given by V(r)=(4)/(3)\pi r^(3). The radius W(t) (in meters ) after t seconds is given by W(t)=8t+3. Write a foula for the volume M(t) (in cubic meters ) of the balloon after t seconds.

Answers

The formula for the volume M(t) of the balloon after t seconds is (4/3)π(8t + 3)³.

Given, The volume of a spherical balloon with radius r meters is given by:            V(r) = (4/3)πr³

The radius (in meters) after t seconds is given by:

               W(t) = 8t + 3

We need to find a formula for the volume M(t) (in cubic meters) of the balloon after t seconds. The volume of the balloon depends on the radius of the balloon. Since the radius W(t) changes with time t, the volume M(t) of the balloon also changes with time t.

Since W(t) gives the radius of the balloon at time t, we substitute W(t) in the formula for V(r).

V(r) = (4/3)πr³V(r)

      = (4/3)π(8t + 3)³M(t) = V(r)

(where r = W(t))M(t) = (4/3)π(W(t))³M(t) = (4/3)π(8t + 3)³

Hence, the formula for the volume M(t) of the balloon after t seconds is (4/3)π(8t + 3)³.

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Select True or False for each statement.
log_2 4= log_8 8+.5 log_4 16
log_a b2 = (log,_ab)^2
In(3a^b) = blna + In 3 =
(Ina)^3b = 3b lna

Answers

The statement log_2 4= log_8 8+.5 log_4 16 is true, log_a b2 = (log,_ab)^2 is false,  In(3a^b) = blna + In 3 = is true and (Ina)^3b = 3b lna is false.

1. True: Using the properties of logarithms, we can simplify the equation as log_2 4 = log_8 8 + 0.5 log_4 16. Since 2^2 = 4, 8^1 = 8, and 4^2 = 16, the equation holds true.

2. False: The correct equation should be log_a b^2 = (log_a b)^2. The exponent of 2 should be inside the logarithm, not outside.

3. True: Using the properties of logarithms, we have In(3a^b) = ln(3) + ln(a^b) = ln(3) + b ln(a).

4. False: The correct equation should be (ln(a))^3b = 3b ln(a). The exponent of 3 should be outside the natural logarithm, not inside.

Overall, two statements are true and two are false.

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Suppose we are given n data points {(X 1

,Y 1

,Z 1

),(X 2

,Y 2

,Z 2

),…,(X n

,Y n

,Z n

)}. We are interested in fitting the linear regression model Y i

=α+βX i

+ϵ i

and Z i

=γ+βX i

+η i

for i=1,2,…,n where the {ϵ i

} and the {η i

} are independent random variables with zero mean and common variance σ 2
. Derive the least squares estimates of α,β and γ algebraically. Note that we require the linear coefficient β in both the regression model for Y i

on X i

and Z i

on X i

to be the same. Hint: The least square objective function can be written as Q=∑ i=1
n

(Y i

−α−βX i

) 2
+∑ i=1
n

(Z i

−γ−βX i

) 2

Answers

Given n data points as (X1, Y1, Z1), (X2, Y2, Z2), ..., (Xn, Yn, Zn). The linear regression model for Yi = α + βXi + ϵi and Zi = γ + βXi + ηi for i = 1, 2, .., n is to be fitted. The {ϵi} and {ηi} are independent random variables having the common variance σ2.

The linear coefficient β in both the regression model for Yi on Xi and Zi on Xi is required to be the same. The least squares estimates of α, β, and γ can be algebraically derived.In order to obtain the least square estimates of α, β, and γ, we need to minimize the objective function Q, given as below:

Q = ∑i=1n (Yi - α - βXi)2 + ∑i=1n (Zi - γ - βXi)2.

Thus,

∂Q/∂α = -2∑i=1n (Yi - α - βXi) = 0 => nα + β∑i=1nXi = ∑i=1nYi ------------------(1)

∂Q/∂β = -2∑i=1n Xi(Yi - α - βXi) - 2∑i=1n Xi(Zi - γ - βXi) = 0=> αnβ∑i=1n Xi2 + ∑i=1n XiYi + ∑i=1n XiZi = β∑i=1n Xi2 + ∑i=1n Xi2Yi + ∑i=1n Xi2Zi ----------------(2)

∂Q/∂γ = -2∑i=1n (Zi - γ - βXi) = 0=> nγ + β∑i=1n Xi = ∑i=1nZi -----------------------(3).

Now, Eqn. (1) becomes:nα + β∑i=1nXi = ∑i=1nYi => α = (1/n)∑i=1nYi - β(1/n)∑i=1nXi ----------------------(4)Putting this value of α in Eqn. (2),

we have:(1/n)[∑i=1nYi - β∑i=1nXi]^2 - 2β{1/n ∑i=1nXi(Yi + Zi)} + β2(1/n) ∑i=1nXi2 + ∑i=1n Xi2Yi + ∑i=1n Xi2Zi = 0or β[(1/n) ∑i=1nXi2 - (1/n) ∑i=1nXi2 + ∑i=1nXi2] = (1/n)[∑i=1nXi(Yi + Zi)] - (1/n)[∑i=1nYi]∑i=1nXi - (1/n)[∑i=1nXiZi] - (1/n)[∑i=1nZi].

Now, let us simplify the above expression and put it in the form of β = ...β = [(1/n) ∑i=1nXi(Yi + Zi)] - (1/n)[∑i=1nYi]∑i=1nXi - (1/n)[∑i=1nXiZi] - (1/n)[∑i=1nZi] / (1/n)[∑i=1nXi2 + ∑i=1n Xi2 + ∑i=1n Xi2].

On simplification, we have β = (∑i=1n XiYi + ∑i=1n XiZi - n((1/n) ∑i=1nXi) ((1/n) ∑i=1n(Yi + Zi)) / ∑i=1n Xi2 + ∑i=1n Xi2 - n((1/n) ∑i=1nXi)2 -------------------(5).

Now, substituting the value of β from Eqn. (5) in Eqns. (4) and (3), we have:

α = (1/n) ∑i=1nYi - ((∑i=1n XiYi + ∑i=1n XiZi - n((1/n) ∑i=1nXi) ((1/n) ∑i=1n(Yi + Zi))) / ∑i=1n Xi2 + ∑i=1n Xi2 - n((1/n) ∑i=1nXi)2) (1/n) ∑i=1nXiγ = (1/n) ∑i=1nZi - ((∑i=1n XiYi + ∑i=1n XiZi - n((1/n) ∑i=1nXi) ((1/n) ∑i=1n(Yi + Zi))) / ∑i=1n Xi2 + ∑i=1n Xi2 - n((1/n) ∑i=1nXi)2) (1/n) ∑i=1nXi.

Thus, these are the least square estimates of α, β, and γ.

Thus, we have derived the least square estimates of α, β, and γ. The objective function Q is minimized with respect to these estimates of α, β, and γ. The algebraic derivations of α, β, and γ are mentioned stepwise above.

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nevaeh is older than kadeem. their ages are consecutive integers. find nevaeh's age if the sum of the square of nevaeh's age and 2 times kareem's age is 61.

Answers

In the given word problem, Nevaeh's age is 7.

Given that,

Nevaeh is older than Kareem.

Their ages are consecutive integers.

The sum of the square of Nevaeh's age and twice Kareem's age is 61.

Assume Nevaeh's age as x.

Since Nevaeh is older than Kareem, Kareem's age would be x-1.

According to the problem,

The sum of the square of Nevaeh's age and twice Kareem's age is 61.

So, we can write the equation as:

x² + 2(x-1) = 61.

Expanding the equation, we get:

x² + 2x - 2 = 61.

Rearranging the terms, we have:

x² + 2x - 63 = 0.

x² + 9x - 7x - 63 = 0

x(x + 9) - 7(x + 9) = 0

(x - 7)(x+9) = 0

x = 7 or x = - 9

Since age is a positive quantity, therefore, proceed x = 7

Therefore, Nevaeh's age is 7.

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Other Questions
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Executive Platinum passengers enjoy perks such as complementary upgrades from the cargo hold to main cabin. Super Executive Platinum 150,000 miles. Super Executive Platinum is a special sub-tier of Executive Platinum, reserved for the most loyal passengers. To save costs, airline management decided to eliminate the position of co-pilot, instead opting to reserve the co-pilots seat for Super Executive Platinum passengersFor example, if a passenger within the span of 1 year accumulates 32,000 miles, starting January 1 of the following year, that passenger will belong to the Gold tier of the rewards program, and will remain in that tier for one year. A passenger can only belong to one tier during any given year. If that passenger then accumulates only 12,000 miles, the tier for next year will be none, as 12,000 miles is not enough to belong to any tier.You will need to design and implement the reward tiers listed above. For each tier, you need to represent the miles a passenger needs to belong to the tier, and the perks (as a descriptive string) of belonging to the tier. The rewards program needs to have functionality implemented for querying. Any user of the program should be able to query any tier for its perks.In addition, a passenger should be able to query the program by member ID for the following: Miles accumulated in the current year. Total miles accumulated since joining the rewards program. A passenger is considered a member of the rewards program by default from first flight taken on the airline. Once a member, a passenger remains a member for life. Join date of the rewards program. Current reward tier, based on miles accumulated from the previous year. Given a prior year, the reward tier the passenger belonged toQueries can be partitioned into two groups: rewards program and rewards member. Queries for perks of a specific tier is part of the rewards program itself, not tied to a specific member. The queries listed above (the bullet point list) are all tied to a specific member.Incorporate functionality that allows the program to be updated with new passenger information for the following: When a passenger joins the rewards program, create information related to the new passenger: date joined, rewards member ID, and miles accumulated. As membership is automatic upon first flight, use the miles from that flight to initialize miles accumulated. When a passenger who is a rewards member flies, update that passengers miles with the miles and date from the flight.As the rewards program is new (ie, you are implementing it), assume for testing purposes that the program has been around for many years. To speed up the process of entering passenger information, implement the usage of a file to be used as input with passenger information. 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If a denctes the aduit. dosage (in midigrams) and if t is the child's ago (in years), then the child's dosage is given by the following function.D(t)= at/t+12 Suppose the adult dosage of a substance is 280mg. Find an expression that gives the rate (in mg/year) of change of a child's cosage with respect to the child's age. D(t)= What is the rate of change (in mg/year) of a child's dosage with respect to his or her age for a 3 -yr-old child? A 12 -yr-old child? (flound your answer to three decimal placesi) 3-yr-old _____ mg/year 12-yriold _____ mg/year under macrs, an asset which originally cost $10,000 is being depreciated using a 5 year normal recovery period. what is the depreciation expense in year 3? fishbone corporation bought a new machine and agreed to pay for it in equal annual installments of 4000 at the end ocf each of the next 10 years Why are last-minute airplane tickets so expensive? Why are last-minute Broadway show tickets so cheap? What strategy is proven effective in blocking the transmission of microbes from contaminated food (reservoir) to immunocompromised patients (susceptible hosts)? what is a benefit of source-based deduplication over target-based deduplication in most people, the __________ is specialized for withdrawal or escape. a)somatic nervous system right b)prefrontal cortex left c)prefrontal cortex d)reticular activating system Workplace Mental Health In 2021: How Can Leaders Build Enduring Change?The crises, challenges, and trauma of 2020 and 2021 have put mental health front-andcenter for employers like never before. But will this period represent a fundamental turning p workplace mental health? Can we usher in enduring change that not only addresses the COVID-19 pandemic, but outlasts it? These questions are on the minds of business and HR mental health experts, and, perhaps most importantly, employees, who are reexamining why and how they want to work.Responding to Tragedy and Trauma in the WorkplaceEmployers know that stress and trauma can each have a negative impact on mental health, especially given the traumatic events of the past 18 months. However, while stress can be managed, trauma is distinct and requires a heightened level of care and support. Because people dealing with trauma can often feel helpless, employers are increasingly directing mental health resources to proactively support these employees. A trauma-informed workplace has a plan in place to facilitate employees' healing and resilience as they navigate crisis and recovery.Framing Workplace Mental Health as a Source of PositivityWorkplace mental health is often presented in terms of risk or negative consequences. By contrast physical wellness is often depicted in terms of being an overall healthier and higher functioning individual. What would it mean to apply this positive framework to mental health? Instead of reacting to mental health and wellbeing with an acute or diagnostic approach, leaders should take a holistic view that frames the need for preventative care in a positive manner. Leaders can change the conversation around mental health in the workplace by ensuring employees can easily access resources and services and putting a positive frame on why they should proactively seek out these resources, even if they are not currently experiencing mental health challenges. Explain two (2) ways globalization are at play from the case study above.Explain two (2) ways globalization are at play from the case study above. Suppose the labour market is summarised as: Demand: P=100Q Supply: P=Q The government imposes a minimum wage. However, consumers (firms) are unsurprisingly unhappy with the increase in wages and are negotiating with labour unions to return to the equilibrium wage. The union will agree to this if fitms offer a lump sum transfer to producers (workers) equivalent to the maximum firms are willing to give, $1069.5. How much was the minimum wage? a. $97 b. $81 c. $73 d. $87 In January 1949, the magnetic declination of Acapulco was 543'W and the annual variation is 6'W.What will be the magnetic declination of January 1989? -Age: 62 years man-Evaluated for worsening cough, shortness of breath, and episodic hemoptysis over the past 6 months. The patient has also had a 15kg weight loss over the same period without any change in his diet or activity level-He has a 50-pack-year smoking history and does not use alcohol or illicit drugs. BMI (18). The patient appears cachectic with temporal wasting and generalized loss of muscle mass. Chest x-ray reveals a large lung mass with mediastinal lymphadenopathy and pleural effusion. Which of the following cellular processes is most likely responsible for this patient's muscle loss?a)Covalent attachment of ubiquitin to muscle proteinsb)Plasma membrane rupture with leakage of cellular contentsc)Plasma membrane instability due to defective dystrophind)Progressive shortening of chromosomal telomerese)Reprogramming of undifferentiated mesenchymal cells Which of the following modes of exercise is appropriate for paraplegic patients? a. Rockport Walking Test b. Treadmill c. Arm cycle d. Leg cycle. Fill in the blank: When finding the difference between 74 and 112, a student might say, and then I added 2 more tens onto "First, I added 6 onto 74 to get a ______80 to get to 100 because that's another______ Fill in the blanks. A d10 complex is likely to be andcoloured, paramagnetic(It depends on the ligands)not coloured, diamagneticcoloured, diamagneticnot coloured, paramagnetic The CNO cycle in high-mass main-sequence stars burns ______ to ______ in their cores. A. carbon;oxygenB. carbon;nitrogenC. hydrogen;helium Assume that a procedure yields a binomial distribution with a trial repeated n = 8 times. Use either the binomial probability formula (or technology) to find the probability of k 6 successes given the probability p 0.27 of success on a single trial.(Report answer accurate to 4 decimal places.)P(X k)- You traveled 35 minutes at 21 mph speed and then you speed up to 40k and maintained this speed for certain time. If the total trip was 138km, how long did you travel at higher speed? Write your answer