Which table represents a linear function?

Answer:

y = [tex]\frac{1}{5}[/tex] x - 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{1}{5}[/tex] x + 4 ← is in slope- intercept form

with slope m = [tex]\frac{1}{5}[/tex]

• Parallel lines have equal slopes , then

y = [tex]\frac{1}{5}[/tex] x + c ← is the partial equation

to find c substitute (5, - 4 ) into the partial equation

- 4 = 1 + c ⇒ c = - 4 - 1 = - 5

y = [tex]\frac{1}{5}[/tex] x - 5 ← equation of parallel line

9x + 3 = 30
9x = 27
x = 3

Then 3x + 1 = 3 * 3 + 1 = 10

[tex]9x + 3 = 30 \\ \\ 9x = 30 - 3 \\ \\ 9x = 27 \\ \\ x = \frac{27}{9} \\ \\ x = 3.[/tex]

putting x = 3 in 3x + 1

[tex]3x + 1 \\ \\ 3 \times 3 + 1 \\ \\ 9 + 1 \\ \\ 10.[/tex]

The value of 3x + 1 is 10.

The equation of the function is f(x) = x(x + 2)(x -1)(x -3)

From the graph, we have the following highlight:

The above means that:

f(x) approaches positive infinity irrespective of the x value

Hence, the end behavior of the function is:

[tex]\mathrm{as}\:x\to \:+\infty \:,\:f\left(x\right)\to \:+\infty \:,\:\:\mathrm{and\:as}\:x\to \:-\infty \:,\:f\left(x\right)\to \:+\infty \:[/tex]

Since, the function opens upward.

Then the sign of the leading coefficient is positive

This is the point, where the graph crosses the x-axis.

From the graph, we have the zeros to be:

x = -2, x = 0, x = 1 and x = 3

Since the graph crosses the x-axis at this point, then the multiplicity of the zeros is 1

In (c), we have:

x = -2, x = 0, x = 1 and x = 3

Rewrite as:

x + 2= 0, x = 0, x - 1 = 0 and x - 3 = 0

Multiply these values

f(x) = x(x + 2)(x -1)(x -3)

Hence, the equation of the function is f(x) = x(x + 2)(x -1)(x -3)

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Answer: A,B,C

Step-by-step explanation: A,B,C is the answer

The expression (2 + 3) + 4 = 2 + (3 + 4) illustrates the associative property of addition option (C) is correct.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

As we know with the help of associative property we can group the terms of addition or multiplication.

a + (b + c) = (a + b) + c

Option (C)

= (2 + 3) + 4

After using the associative property:

= 2 + (3 + 4)

Thus, the expression (2 + 3) + 4 = 2 + (3 + 4) illustrates the associative property of addition option (C) is correct.

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The t-test might be more useful in actual practice when standard deviation or variance is unknown.

The t-test is used to determine how the averages of various data sets differ from one another.

When variance is not provided, the T-test, a particular kind of parametric test, is used to determine how the means of two sets of data differ from one another. When variance is provided, the Z-test indicates a hypothesis test that determines whether the means of two datasets differ from one another.

Example of t-test: If you flip a coin 1,000 times, for instance, you can discover that the outcome is distributed normally over all trials.

Example of z-test: We are conducting research using information gathered from cohorts of students who have taken Elementary Statistics in the past.

T-tests are typically more suitable when addressing issues with small sample sizes, whereas z-tests are suitable for large sample sizes.

Using the t-test for an ordinal variable, their frequency is not even close to a normal distribution, and the arithmetic mean offers an unsuitable measure of location.

Because we frequently don't know the population standard deviation, Z-Tests have this drawback.

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The point (0, 0) is a solution to which of these inequalities are satisfied. so option B. y-7<2x-6is the only correct answer.

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

The point (0, 0) is a solution to which of these inequalities are satisfied.

A. y+7<2x - 6

      7 < -6

So, it is incorrect.

B. y-7<2x-6

      -7 < -6

So, it is correct.

C. y-6<2x-7

         -6 < -7

So, it is incorrect.

D. y+7<2x+6

7 < 6

So, it is incorrect.

Hence, option B is the only correct answer.

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Answer:

it depends on whether the outlier is a high outlier or a low outlier

Step-by-step explanation:

The mean of a data set is the average of the data set. So if I had the data set {5, 2, 10} the average would be (5+2+10)/3 = 5.667. Now if I added an outlier like 10,000 it would increase the mean significantly. It changes it significantly but I cannot say whether it increases or decreases it without knowing the value of the outlier, since if I had the outlier -10,000 that would decrease the mean, but I had the outlier 10,000 it would increase it. So it depends on whether the outlier is a high outlier or a low outlier

Answer:

x = 3/2 ± [tex]\sqrt{5}[/tex] /2

Step-by-step explanation:

4x²-12x+9 = 5

Rearrange:

4x²-12x+4 = 0

Solve using the quadratic equation:

x = 3/2 ± [tex]\sqrt{5}[/tex] /2  

Answer:

B

Step-by-step explanation:

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:f(x)= 9280 - 20x [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{1}{16} x + \cfrac{1}{320} y - 29 = 0[/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{1}{16} x + \cfrac{1}{320} y = 29[/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{20 x+ y}{320} = 29[/tex]

[tex]\qquad \tt \rightarrow \: 20x + y = 29 \sdot320[/tex]

[tex]\qquad \tt \rightarrow \: y = 9280 - 20x[/tex]

[tex]\qquad \tt \rightarrow \: f(x) = 9280 - 20x[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The maximum number of visits you can make with each membership is 104.

Gym membership refers to the cost to register, attend, and use a gym as a member for an agreed period.

Some gym memberships require one-time payments made monthly or annually.

Assume that the annual gym fee is $200 for Saturdays and Sundays only.

Thus, in this scenario, the maximum number of visits you can make with each membership is 104.

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A variation on Momentary Time Sampling that involves counting the number of students in a classroom engaged in a target behaviour at the designated time in the interval is known as Planned Activity Check ( PLACHECK)

Momentary Time Sampling is a method of recording a student's behaviour ,

It helps in understanding clearly the regularity of a student.

This method is used when the behaviour cannot be easily counted or it is difficult for the teacher to focus to get the exact duration in which the student showed severity to the work.

In easy words , a timer is set and from the start to the end of the timer , it is observed whether the required goal is achieved or not and what is the frequency at which that task is being done in the time interval.

Planned Activity Check ( PLACHECK) is when Momentary Time Sampling is done with the group , It provides the measure of a group behaviour.

Therefore ,

A variation on Momentary Time Sampling that involves counting the number of students in a classroom engaged in a target behavior at the designated time in the interval is known as Planned Activity Check ( PLACHECK)

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Answer:

6

Step-by-step explanation:

The equation becomes 9 *4 * 1/6. Then you simplify and get 6.

Please mark me as Brainliest if it is correct, thx.

From the given diagram <msr is a right angle (equal to 90 degrees) and <mrh is acute since it is less than 90degrees.

The given diagram is a rhombus that has the following properties

From the figure shown, we can see that;

<msr is a right angle (equal to 90 degrees)

<mrh is acute since it is less than 90degrees.

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Answer:

A (it must be acute)

Step-by-step explanation:

Answer:

[tex]m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right][/tex]

Step-by-step explanation:

Calculate the value of m

Given:

[tex]3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right][/tex]

Therefore:

[tex]\implies 3=\dfrac{2}{3}m[/tex]

[tex]\implies m=3 \times \dfrac{3}{2}[/tex]

[tex]\implies m=\dfrac{9}{2}[/tex]

Calculate the value of H

Given:

[tex]\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)[/tex]

Therefore:

[tex]\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right][/tex]

Calculating m × H

[tex]\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right][/tex]

[tex]\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right][/tex]

[tex]\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right][/tex]

The given radical root 84, the simplification is option B; [tex]2\sqrt{21}[/tex].

Usually, simplification involves proceeding with the pending operations in the expression.

Simplification usually involves making the expression simple and easy to use later.

The given radical;

[tex]\sqrt{84} \\\\\sqrt{42 \times 2} \\\\\sqrt{7\times3\times 2 \times 2} \\\\2\sqrt{21} \\[/tex]

Thus, the correct option is B; [tex]2\sqrt{21}[/tex].

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The e vertex of the decagon will be in the top position after rotating it counterclockwise by 3 times the smallest angle of rotation.

Which vertex will be in the top position of the regular decagon?

A regular decagon has 10 sides of equal lengths with points labeled 'a' through 'j' clockwise. It is given that the point a is the top-left point. Hence, the the vertex which is in the the top position currently is 'b'.

Now, the smallest angle of rotation will be the angle between the two sides of the decagon.

In the first rotation by the smallest angle in counterclockwise direction, point 'c' will come to the top position. In the second rotation by the smallest angle in counterclockwise direction,  point 'd' point will become the top most vertex. Finally, after the third similar rotation, 'e' vertex will be in the top position of the decagon. (Refer the attached diagram)

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Answer:

If two things have the same shape and size then they are congruent to one another. If they are only the same shape but not size, then they are similar.

If two things have the same shape and size then they are congruent to one another.

If they are only the same shape but not size, then they are similar.

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Answer:

yeheheehejehejejejjejjejejejejje

Answer:

(x - y)(x² + xy + y²)

Step-by-step explanation:

Since both are cubed (³),

we can apply the Difference of Cubes Formula:

A binomial that is of the form (something)³ – (something else)³

To factor any difference of cubes,

the formula a³ – b³ = (a – b)(a² + ab + b²).

hence, x³ - y³ = (x - y)(x² + xy + y²)

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Answer: C

Step-by-step explanation: Substitute the x’s into C’s equation.

2(0) is 0, 0+1 is 1 so the first row is correct. 2(2) is 4, 4+1 is 5, so the second row is correct. 2(4) is 8, 8+1 is 9, so the third row is correct. And lastly, 2(6) is 12, 12+1 is 13 so fourth row is correct as well. Assuming the rest of the rows follow this pattern, the correct answer should be C.

The explicit formula for the sequence is 3n -10

An arithmetic sequence is a series of terms which have  common difference between its consecutive numbers.

The sequence given is

−7, −4, −1, 2, 5, …

The common difference between each term is d =3

-4-(-7) = 3

-1-(-4) =3

The nth term for a sequence is given by

[tex]\rm T_n = a +(n-1)d[/tex]

Here a is the first term = -7

n is the no. of terms  = n

d is the common difference = 3

Therefore the equation will be

[tex]\rm T _n = -7 + (n-1) * 3[/tex]

[tex]\rm T _n[/tex] = -7 +3n -3

[tex]\rm T _n[/tex] = 3n -10

Therefore the explicit formula for the sequence is 3n -10 .

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Answer:

  (4, -2)  (see attached)

Step-by-step explanation:

Vector addition on a graph is accomplished by placing the tail of one vector on the nose of the one it is being added to. The negative of a vector is in the direction opposite to the original.

__

The components of the vectors are ...

  u  = (1, -2)

  v = (-6, -6)

Then the components of the vector sum are ...

  2u -1/3v = 2(1, -2) -1/3(-6, -6) = (2 +6/3, -4 +6/3)

  2u -1/3v = (4, -2)

The sum is shown graphically in the attachment. Vector u is added to itself by putting a copy at the end of the original. Then the nose of the second vector is at 2u.

One-third of vector v is subtracted by adding a vector to 2u that is 1/3 the length of v, and in the opposite direction. The nose of this added vector is the resultant: 2u-1/3v.

The resultant is in red in the attachment.

The answer is (4, -2) hope this helps!

The probability for event F or C is 0.80, or the value of the P(F or C) is 0.80 option (D) is correct.

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

The question is incomplete.

The complete question is:

Insurance company executives surveyed 200 young adults about their first motor vehicle. The results of the survey are given in the following two-way table(please refer to the attached picture)

A survey participant is randomly selected. Let F be the event that the participant’s first motor vehicle had four cylinders and let C be the event that the participant’s first motor vehicle was a car. What is the value of P(F or C)?

We have to find the value of P(F or C):

[tex]\rm P( F \ or \ C) = \dfrac{118+6+18+16+2}{118+6+18+16+12+20+2+6+2}[/tex]

[tex]\rm P( F \ or \ C) = \dfrac{160}{200}[/tex]

P(F or C) = 0.80

Thus, the probability for event F or C is 0.80, or the value of the P(F or C) is 0.80 option (D) is correct.

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The equation represents the amount of juice that remains, y, after x students are served is y = negative one-half x + 32; option C

y = 32 - 1/2x

This can also be written as;

y = -1/2x + 32

Therefore, the correct answer is option C; y = -1/2x + 32

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It looks like you're saying

[tex]f(x) = ax^2 + bx + c[/tex]

and you're asked to find [tex]a,b,c[/tex] given [tex]f(0)=-4[/tex], [tex]f(1)=-1[/tex], and [tex]f(-1)=-5[/tex].

Evaluate [tex]f[/tex] at the three given points:

[tex]x=0 \implies f(0) = \boxed{c = -4}[/tex]

[tex]x=1 \implies f(1) = -1 = a + b + c \implies a+b = 3[/tex]

[tex]x=-1 \implies f(-1) = -5 = a - b + c \implies a - b = -1[/tex]

[tex](a+b) + (a-b) = 3 + (-1) \implies 2a = 2 \implies \boxed{a=2}[/tex]

[tex]a-b = -1 \implies \boxed{b=3}[/tex]

and the mapping is [tex]f(x) = 2x^2 + 3x - 4[/tex].