The brightness of the Moon can make it difficult to see fainter stars in its vicinity, further decreasing the likelihood of seeing it near Polaris in the night sky.
The Earth revolves on its axis as the Moon travels around it. The location of celestial objects in the sky seems to vary over time because to the Earth's rotation. Since it sits practically immediately above the North Pole of the Earth, Polaris, also known as the North Star, seems to remain motionless in the sky while all other stars appear to revolve around it.
The Moon, on the other hand, does one full circuit of the Earth every 27.3 days, traveling a distance of around 384,400 kilometers (238,855 miles) on average. Its location in relation to the stars, including Polaris, shifts as it circles.
The Moon will occasionally seem near to Polaris in the night sky, while other times it will look far away due to the Earth's rotation and the Moon's orbit. It is quite uncommon to observe the Moon and Polaris in close proximity to one another since their positions in relation to one another are continually shifting. Further reducing the chances of spotting the Moon close to Polaris in the night sky is the brightness of the Moon, which can make it challenging to discern nearby fainter stars.
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Two hockey pucks with mass 0.1 kg slide across the ice and collide. Before the collision, puck 1 is going 15 m/s to the east and puck 2 is going 12 m/s the west. After the collision, puck 2 is going 15 m/s to the east. What is the velocity of puck 1?
The velocity of puck 1 after the collision is 15 m/s to the east.
Conservation of momentum principle to solve this problemThe total momentum of the system before the collision is equal to the total momentum of the system after the collision.
The momentum of each puck can be calculated as:
p = m * v
where
p is the momentum (in kg*m/s)
m is the mass (in kg)
v is the velocity (in m/s)
The total momentum of the system before the collision is:
p_total_before = p1_before + p2_before = m1 * v1_before + m2 * v2_before
where subscripts 1 and 2 refer to pucks 1 and 2, respectively, and "before" refers to the velocity before the collision.
Substituting the given values, we get:
p_total_before = (0.1 kg) * (15 m/s) + (0.1 kg) * (-12 m/s) = 0.3 kg*m/s
The total momentum of the system after the collision is:
p_total_after = p1_after + p2_after = m1 * v1_after + m2 * v2_after
where "after" refers to the velocity after the collision. We are given that puck 2 is going 15 m/s to the east, so the velocity of puck 2 before the collision is -12 m/s to the west, and the change in velocity is:
Delta_v2 = v2_after - v2_before = 15 m/s - (-12 m/s) = 27 m/s
The momentum of puck 2 is conserved during the collision, so we have:
p2_before = p2_after
m2 * v2_before = m2 * v2_after
v2_after = v2_before = -12 m/s
Substituting the given values and solving for the velocity of puck 1 after the collision, we get:
p_total_after = m1 * v1_after + m2 * v2_after
0.3 kg*m/s = (0.1 kg) * v1_after + (0.1 kg) * (-12 m/s)
v1_after = (0.3 kgm/s + 1.2 kgm/s) / (0.1 kg)
v1_after = 15 m/s
Therefore, the velocity of puck 1 after the collision is 15 m/s to the east.
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You toss a ball straight up in the air. Immediately after you let go of it, what force or forces are acting on the ball? For each force you name,
(a) state whether it is a contact force or a long-range force and
(b) identify the agent of the force.
a) Gravity: This is a long-range force and the agent of the force is the Earth. b) Air Resistance: This is a contact force and the agent of the force is the air molecules. c) Normal Force: This is a contact force and the agent of the force is the ground.
What is Air Resistance?Air resistance, also known as drag, is a type of frictional force that acts upon objects when they move through a fluid, such as air or water. Air resistance occurs when the air molecules surrounding an object collide with the object’s surface, resulting in a resistive force that opposes the object’s motion. The magnitude of air resistance is dependent on the object’s shape, size, mass, speed, and altitude. Objects with a large surface area, such as parachutes, are more affected by air resistance than objects with a smaller surface area. Air resistance increases with an object’s speed and is stronger at higher altitudes, where the air is thinner. The effects of air resistance can be seen in everyday objects, such as an airplane or a car, and can be reduced by altering an object’s shape or by decreasing its speed.
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A 65-kg student is in an elevator moving downward with constant velocity. He uses a bathroom scale to measure the upward force exerted on his feet.
What force magnitude does the scale read when the elevator is traveling at constant velocity?
What force magnitude does the scale read when the elevator slows to a stop with an acceleration of magnitude 2.0 m/s^2 ?
What force magnitude does the scale read when the elevator starts downward again with an acceleration of magnitude 2.0 m/s^2 ?
Force magnitude when elevator is traveling at constant velocity is, 637 N. Force magnitude does the scale read when the elevator slows to a stop is, 429 N (downward force). Force magnitude when elevator starts downward again is, 208 N.
Force magnitude when elevator is traveling at constant velocity, 65 kg x 9.8 m/s^2 = 637 N (upward force)
When the elevator slows to a stop with an acceleration of magnitude 2.0 m/s^2, the net force acting on the student is the sum of the gravitational force and the force exerted by the scale.
Net force: (65 kg) x (2.0 m/s^2) = 130 N (downward force)
Force magnitude when elevator slows to a stop: 637 N - 130 N = 507 N (upward force)
When the elevator starts moving downward again with an acceleration of magnitude 2.0 m/s^2, the net force is difference between the gravitational force and the force exerted by the scale,
Net force: (65 kg) x (9.8 m/s^2 - 2.0 m/s^2) = 429 N (downward force)
Force magnitude when elevator starts downward again: 637 N - 429 N = 208 N (upward force)
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when two sources of waves with the same frequency are active, what must the path length difference be at some point in space for the waves to interfere destructively? when two sources of waves with the same frequency are active, what must the path length difference be at some point in space for the waves to interfere destructively? the distance between the two sources. some whole multiple of the wavelength. 0 some whole multiple of the wavelength plus one half the wavelength.
When two sources of waves with the same frequency are active, the path length difference must be equal to some whole multiple of the wavelength plus one half the wavelength for the waves to interfere destructively.
This is because in order for two waves to interfere destructively, they must be exactly out of phase with each other. When waves are out of phase, the crest of one wave lines up with the trough of the other, resulting in a cancellation of the waves. This occurs when the path length difference between the two waves is equal to an odd multiple of half wavelengths. For example, if the distance between the two sources is exactly one wavelength, then the waves will interfere constructively, resulting in a stronger wave. However, if the distance is increased to one and a half wavelengths, then the waves will interfere destructively, resulting in a weaker or canceled wave. This pattern repeats for all odd multiples of half wavelengths.
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scientists studying the collision of particles note that a certain particle travels around a collider two times every second. if the tube's radius is , with what velocity is the particle traveling?
When two particles, groups of particles, or solid objects move in the same direction and get close enough to each other to interact, they collide.
What is the collision of particles?Even though the particles are travelling swiftly in all directions, collisions between them occur more frequently than in gases because of the closer proximity of the particles.
The equation relating velocity and radius is [tex]= \omega =\frac{v}{r}[/tex]
Because the equation can also be used to determine angular velocity
[tex]\omega = 2 \pi[/tex]f we can set the equations equal and solve for the velocity.
[tex]\frac{v}{r} = 2 \pi f[/tex]
[tex]v= 2 \pi f r[/tex]
Since we are given the radius of [tex]5000 m[/tex] And the frequency of [tex]2Hz[/tex], we can calculate the velocity. (Frequency can be found by the number of times an object travels around a full circle in one second).
[tex]V = 2 \pi (2hz) ( 5000 m) = 2 \pi \times 10^4\frac{m}{s}[/tex]
As an alternative, we can calculate the collider's circumference using its radius.
[tex]C = 2\pi r = 2\pi 5000= 10000\pi[/tex]
Every second, the particle does two full rotations.
[tex]v = \frac{d}{t} = \frac{2(10000\pi )m10^4\frac{}{}}{1s}= 2\pi\times 10^4 \frac{m}{s}[/tex]
Therefore, [tex]2\pi\times 10^4 \frac{m}{s}[/tex] is the velocity of particle while travelling.
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when a radiologist reads an mri or ct scan do they check everything visible or just the area in question?
While radiologists do review all the images in a study, they will typically give more attention to the area of interest in order to provide an accurate diagnosis and ensure that the patient receives the best possible care.
When a radiologist reads an MRI or CT scan, they typically review all the images in the study, not just the area of interest. This is because other areas of the body may contain important incidental findings that could impact a patient's overall health and require further investigation or treatment.
The radiologist will typically focus their attention on the area of the body that has been requested for imaging. They will thoroughly examine the relevant region, and looking for any abnormalities, injuries, or other issues that may be present.
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Which type of satellite is useless for meteorologists at 3AM?
Select one:
a. visible satellite imagery
b. infrared satellite imagery
c. water vapor imagery
what is the minimum possible diameter of the spot on the wall, defined as the diameter of the circle where the intensity is zero? (a) 2.03e-03 m
The minimum possible diameter of the spot on the wall is approximately 3.05e-4 mm or 2.03e-3 m.
The minimum possible diameter of the spot on the wall, also known as the diffraction spot or Airy disk, can be calculated using the formula:
d = 2.44 * λ * L / D
where λ is the wavelength of the light, L is the distance between the aperture and the wall, and D is the diameter of the aperture.
In this case, we are not given the wavelength or distance L, but we are given the diameter of the aperture, which is 0.4 mm or 4e-4 m. We can assume a typical visible light wavelength of 500 nm or 5e-7 m and a distance L of 1 m for this calculation.
d = 2.44 * 5e-7 m * 1 m / 4e-4 m
d = 3.05e-7 m or 3.05e-4 mm
Therefore, the minimum possible diameter of the spot on the wall is approximately 3.05e-4 mm or 2.03e-3 m.
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If the index of refraction of a material is 2, this means that light travels2 times as fast in the material as it does in air.2 times as fast in vacuum as it does in the material.2 times as fast in the material than it does in vacuum.2 times as fast in air as it does in vacuum.1/2 as fast in air as it does in the material.
If the index of refraction of a material is 2, it means that, 1/2 as fast in air as it does in the material. The correct answer is d.
The index of refraction of a material is defined as the ratio of the speed of light in a vacuum to the speed of light in the material. So, an index of refraction of 2 means that light travels half as fast in the material as it does in a vacuum.
It does not have any direct relation to the speed of light in air, which has an index of refraction very close to 1, and which is commonly used as a reference medium.
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--The complete question is, If the index of refraction of a material is 2, this means that light travels,
a. 2 times as fast in the material as it does in air.
b. 2 times as fast in vacuum as it does in the material.2 times as fast in the material than it does in vacuum.
c. 2 times as fast in air as it does in vacuum.
d. 1/2 as fast in air as it does in the material.--
an isolated charged point particle produces an electric field with magnitude 100 n/c at a point 2 m away. at a point 1 m from the particle, what is the magnitude of the field?
Magnitude of the electric field at a point 1 m from the particle is 400 N/C.
The magnitude of the electric field produced by an isolated charged point particle follows an inverse-square law, meaning that the field strength decreases as the distance from the particle increases. The electric field strength E is proportional to the inverse of the square of the distance r from the particle:
[tex]E = k*1/r^2[/tex]
We can use this relationship to solve the problem. If the electric field strength at a point 2 m away from the particle is 100 N/C, then we can write:
[tex]100 N/C = kQ/2^2[/tex]
where k is the Coulomb constant and Q is the charge of the particle. Rearranging this equation to solve for Q, we get:
[tex]Q = (100 N/C)(2^2/k)[/tex]
At a point 1 m from the particle, the distance is halved, so the electric field strength will be:
[tex]E = kQ/1^2 = kQ[/tex]
Substituting the value of Q we just calculated, we get:
[tex]E = (100 N/C)(2^2/1^2k) = 400 N/C[/tex]
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assuming the only force acting is the force of collision, which one experiences the most force during the crash - the car or the dump truck?
They experience the same size force. Both car and dump truck will experience the force of same magnitude. The main difference is the change in acceleration which is greater for smaller car.
Collision is when two or more objects collide with each other, either directly or indirectly. In physics, collision is defined as the interaction between two or more bodies, where the total kinetic energy of the two bodies before the collision is greater than the sum total of the entire kinetic energy of the two bodies after the collision.
Collisions can involve two or more objects and can be elastic or inelastic. Elastic collisions involve objects that bounce off of each other and inelastic collisions involve objects that stick together after the collision. Collisions can also involve two or more particles, where the particles interact and exchange energy, momentum and angular momentum.
Both car as well as the dump truck will experience the force of same magnitude.
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An object of mass 75 Kg is taken to moon, what will be its weight?(freefall acceleration on moon =1.6 m/s2)
Answer:
120 Newtons
Explanation:
Weight of an object is given by the relation
W = mg
where
W = weight
m = mass of the object
g = gravitational force or freefall acceleration
Given the numbers:
m = 75 kg
g = 1.6 m/s²
W = 75 x 16 = 120 kg m/s² or 120 Newtons
Can someone help me with this ?
The first image shows a speed - time relation in which the speed is zero and the the object is not moving. The second graph shows a constant velocity and the third one shows an increasing velocity with time.
What is speed - time graph ?A speed - time graph represents the change in speed of an object with respect to the time. The speed can be increasing with time or decreasing. Speed of an object is dependent on the path through which it is moving and the mass, frictional force etc.
Here, the first image shows no no values for the y - axis and and thus, the image is not moving. The second graph shows a parallel line which is showing there is no change in speed with the time. This indicates that the object is moving with a constant speed.
The graph C plots an increasing speed with respect to time. The straight line diagonal to the x, y axis indicates the increasing speed.
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What physical property of some energies correspond to the height of wave peaks?
Amplitude is a term used to describe a physical characteristic of some energies that is related to the height of wave peaks.
The term "amplitude" in physics refers to the strongest variation or oscillation, such as a wave or signal. It acts as a gauge for the magnitude of the change or displacement relative to rest.It just serves to represent the size or strength of a wave or signal. The relationship between a sound wave's amplitude and loudness is inverse. In terms of light, it corresponds to the intensity of the light wave.
The definition of amplitude is given as an energy measurement that is used to describe waves. An energy pulse travelling through a medium, or across empty space in the case of electromagnetic radiation, is referred to as a wave. A wave's amplitude may be thought of as a measurement of the energy it has transmitted; the more energy a wave has, the bigger its amplitude. Depending on the kind of wave, several answers can be given when asked what the amplitude of a wave is.
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In the opposite electric circuit, if the reading of the
voltmeter is 6 V, the resistance of R equals
Answer:
[tex]2\; {\rm \Omega}[/tex].
Explanation:
The lower case "[tex]r = 1\; {\rm \Omega}[/tex]" in the circuit diagram indicates that the internal resistance of this [tex]12\; {\rm V}[/tex]-battery is [tex]1\; {\rm \Omega}[/tex].
In practice, the rated [tex]12\; {\rm V}[/tex] voltage drop across this battery is split across not just the resistors in the external circuit, but also across the internal resistance of the battery.
The voltameter in this circuit measures the voltage drop across the [tex]3\; {\rm \Omega}[/tex] resistor and the unknown resistor [tex]R[/tex]. The voltage drop across the internal resistance and the other resistor (a total of [tex]1\; {\rm \Omega} + 4\; {\rm \Omega} = 5\; {\rm \Omega}[/tex]) would be [tex]12\; {\rm V} - 6\; {\rm V} = 6\; {\rm V}[/tex].
Divide the voltage drop by the resistance to find the current:
[tex]\begin{aligned}I &= \frac{V}{R} \\ &= \frac{6\; {\rm V}}{5\; {\rm \Omega}} = 1.2\; {\rm A}\end{aligned}[/tex].
Since this circuit is serial, current would be the same everywhere in the circuit. Given that voltage drop across the [tex]3\; {\rm \Omega}[/tex] resistor and the unknown resistor is [tex]6\; {\rm V}[/tex], the resistance of that part of the circuit would be:
[tex]\begin{aligned}\frac{6\; {\rm V}}{1.2\; {\rm A}} = 5\; {\rm \Omega}\end{aligned}[/tex].
Subtract the [tex]3\; {\rm \Omega}[/tex] from the resistance to find the value of [tex]R[/tex]:
[tex]R = (5\; {\rm \Omega} - 3\; {\rm \Omega}) = 2\; {\rm \Omega}[/tex].
What is moving faster, a 450 kg horse with a momentum of 765 kgm/s or an object with a different mass and momentum?
Therefore, the answer to this question is that it cannot be determined without more information.
The answer to this question can be determined by comparing the velocity of the two objects.
The formula for momentum is:
momentum = mass × velocityWe can rearrange this formula to solve for velocity:
velocity = momentum / mass For the horseWe can plug in the given values:
velocity = 765 kgm/s / 450 kg velocity = 1.7 m/sFor the other object, we do not have enough information to determine its velocity. We would need to know its mass and momentum in order to calculate its velocity and compare it to the horse's velocity. Without this information, we cannot determine which object is moving faster. Therefore, the answer to this question is that it cannot be determined without more information.
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Balancing a centrifuge requires that all tubes in the load:
A. have an equal amount of liquid of the same viscosity.
B. are of equal size and shape.
C. have a partner directly across in the rotor holder.
D. All of the above
Every tube in the load must have a companion right across in the rotor holder in order for the centrifuge to be balanced.
In many laboratories, centrifuges are employed to separate fluids, gases, or liquids according to their densities. Centrifuges are often employed in clinical and research facilities for the purification of cells, organelles, viruses, proteins, and nucleic acids.
The separation of different components of whole blood using a centrifuge is an example of its usage in a clinical environment. Serum or plasma is required for several tests and can be obtained by centrifugation.
A full blood sample is allowed to clot at room temperature in order to get serum. The clot is subsequently removed from the sample by centrifugation, leaving a serum supernatant behind.
Plasma, in contrast to serum, is made from whole blood that has not been allowed to clot; it contains serum as well as clotting factors. A full blood sample is taken in tubes that have been anticoagulant-treated in order to get plasma.
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what is true about the acceleration of a particle that is oscillating with simple harmonic motion (shm)? a. it is in the opposite direction to its velocity b. it is decreasing when the potential energy is increasing c. it is proportional to the frequency of the oscillation d. it is at a minimum when the velocity is at a maximum
The acceleration of a particle oscillating in a simple harmonic motion is always in the opposite direction to its velocity.
What is accurate regarding a straightforward harmonic oscillation's acceleration?The velocity is at its greatest point and the acceleration (a) has zeroed out at the equilibrium position. Simple harmonic motion can be distinguished by its variable acceleration, which is always pointing in the direction of the equilibrium position and is inversely proportional to the displacement from the equilibrium position.
What does the term "simple harmonic oscillation" mean, and how does it apply?It is a specific kind of periodic motion with two extremes as its boundaries. Simple pendulum oscillation and the spring-mass system are two examples. The object will continue to oscillate around a fixed point between two extreme points.
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A. An adaptive filter What type of digital signal processing filter is used to generate an SSB signal? A. An adaptive filter B. A notch filter C. A Hilbert-transform filter D. An elliptical filter
A Hilbert-transform filter is used to generate an SSB signal.
A Single Sideband (SSB) signal is generated by filtering one sideband of a modulated signal and suppressing the other sideband and the carrier signal. The most common way of generating an SSB signal is by using a Hilbert-transform filter.
This filter is used to shift the phase of the modulated signal by 90 degrees, effectively converting the upper sideband to the lower sideband, or vice versa. By filtering out one of the sidebands, the SSB signal can be generated. Therefore, option C is the correct answer.
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--The complete question is, What type of digital signal processing filter is used to generate an SSB signal?
A. An adaptive filter
B. A notch filter
C. A Hilbert-transform filter
D. An elliptical filter--
The current through a dryer is 12 A. If the input voltage is 220 v. What electrical energy does it make in 1.5 min?
The electrical energy consumed by the dryer in 1.5 minutes is 237,600 joules.
What is electrical energy?
Electrical energy is a form of energy that results from the movement of electric charge. It is the energy that is transferred or converted when electric current flows through a conductor or a circuit.
How is electricity generated?Electricity is generated at power plants using various sources of energy such as fossil fuels, nuclear power, or renewable energy sources like wind, solar, or hydroelectric power. This electrical energy is then transmitted through high-voltage power lines and distributed to homes.
First we should calculate the power:
power = voltage x current
power = 220 V x 12 A = 2640 W
Now we can calculate the electrical energy consumed by the dryer in 1.5 minutes:
Electrical energy = power x time
= 2640 W x 90 s
= 237,600 joules (J)
The electrical energy consumed by the dryer in 1.5 minutes is 237,600 joules.
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Define Resonance Physics
Answer:
Resonance is a phenomenon that occurs when the frequency at which an external force is applied to an object is equal to the natural frequency of vibration of that object.
In physics, resonance is a common occurrence in mechanical, electrical, and acoustical systems.
If the electric field between the plates of a given air-filled capacitor is weakened by removing charge from the plates, the capacitance of that capacitor A) decreases B) increases. C) does not change. D) It cannot be determined from the information given.
If the electric field between the plates of a given air-filled capacitor is weakened by removing charge from the plates, the capacitance of that capacitor does not change.
Capacitance is the amount of charge that can be stored at a given voltage by an electrical component called a capacitor.
C=Q/V
The unit of capacitance is the Farad (F)
C = εA/d,
C is capacitance; ε is permittivity, a term for how well dielectric material stores an electric field; A is the parallel plate area; and d is the distance between the two conductive plates.
electric field between two parallel conducting plates depends on the electric potential or voltage of the two plates and the distance between the two plates. So, the electric field E=Vd E = V d where d is the distance between the two charged plates.
The force on the charge is the same no matter where the charge is located between the plates. This is because the electric field is uniform between the plates.
If the electric field between the plates of a given air-filled capacitor is weakened by removing charge from the plates, the capacitance of that capacitor does not change.
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bulbs a, b, and c in the figure are identical, and all are glowing. (a) rank in order, from most to least, the brightnesses of the three bulbs. (b) suppose a wire is connected between points 1 and 2. what happens to each bulb?
Bulb C goes out, Bulb A shines brighter (due to higher current), and Bulb B goes out (because to insufficient current) ( due to no current )
What does the term "current" signify in relation to electricity?The term "electric current" is frequently used to describe how much electricity flows through a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A). As more electricity passes across the circuit, the ampere value increases.
What is a contemporary example?Starting a car, turning on a light, using an electric stove, watching TV, shaving with an electric razor, playing video games, using a phone, and charging a mobile phone are examples of current electricity.
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A system is at rest. The mass of each object is shown. Neglecting the mass of the strings, how many forces are acting on the 9 kg block?
A. There is 1 force.
B. There are 2 forces.
C. There are 3 forces.
D. There are 4 forces,
When the system is at rest, there are 2 forces acting on the 9 kg block.
Describe a force.An object experiences a push or pull as a result of interaction with another object. A force is exerted on each object when two of them come into contact. The newton, represented by the letter N, is the SI unit of force.
What different kinds of forces exist in physics?There are two different types of forces: contact forces and non-forces. A few examples of forces are nuclear force, gravitational force, frictional force, magnetic force, electrostatic force, spring force, and others.
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(a) Why the maximum tidal range (spring tide) occurs during a new moon and full moon phases?(b) Why the minimum tidal range (neap tide) occurs at first-quarter and third-quarter moons?
(a) The maximum tidal range (spring tide) occurs during a new moon and full moon phases because the sun and moon's gravitational pulls are aligned and amplified.
(b) The minimum tidal range (neap tide) occurs at first-quarter and third-quarter moons because the sun and moon's gravitational pulls are at right angles.
(a) As the sun and moon's gravitational pulls are aligned and amplified during the new moon and full moon phases, the maximum tidal range, or spring tide, occurs during these periods. With the moon and sun on opposing sides of the Earth, the sun, moon, and Earth are all in a straight line during a new moon. Due to the moon's proximity to Earth, its gravitational pull on the planet is at its greatest. Due to its alignment with the moon and Earth, the sun's gravitational pull also contributes to this. A broader tidal range results from the seas bulging due to this alignment, which also generates higher peak tides and lower low tides.
(b) As the sun and moon's gravitational pulls are at right angles during the first and third quarters of the moon, the shortest tidal range, or neap tide, occurs at these periods. With the sun and moon on opposing sides of the Earth, the sun, Earth, and moon make a straight angle during a first-quarter moon. The gravitational pull of the sun partially cancels out the gravitational pull of the moon on Earth, reducing the tidal range. When the moon is quartered, the same thing takes place. There is a narrower tidal range at these periods because the high tides are lower and the low tides are higher.
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What does the resolution limit of an optical system depend on? Choose all answers that are correct. (a) The wavelength of light (b) The diameter of the aperture (c) The distance to the object being viewed (d) The distance from the aperture to the light detectors
The resolution limit of an optical system depends on both (a) The wavelength of light and (b) The diameter of the aperture. These two factors determine the diffraction limit, which is the smallest distance between two points that can be resolved by the optical system.
The wavelength of light affects the resolution limit because shorter wavelengths are able to resolve smaller details than longer wavelengths. The diameter of the aperture also affects the resolution limit because a larger aperture allows for more light to enter the system, which can improve the resolution.
The distance to the object being viewed (option c) and the distance from the aperture to the light detectors (option d) do not affect the resolution limit of an optical system. These factors may affect the overall image quality, but they do not determine the smallest distance between two points that can be resolved by the system.
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r is not a readily measurable quantity for a given field. but we may have a sense of how large r is relatively for different fields. for example, field a is a subfield in physics that has very thorough background knowledge, with a small community, and the scientists have a good way of figuring out what hypotheses are important and should be tested. field b is a subfield of genetics which has attracted a lot of attention recently and is still in the exploratory phase of finding fruitful relations. which field has higher r?
Field A has higher r than field B, as the former has had more time to establish reliable methods and a more stable consensus within the scientific community.
Let's assume that "r" refers to the replicability of results within a given scientific field. That is, how likely it is that the results of a given study will be replicated in subsequent studies.
Based on the information given, we can infer that field A has a smaller community of scientists and a well-established set of hypotheses and theories. This indicates that the field has had more time to develop and refine its methods and that there is a higher degree of consensus among the scientific community about what research questions are important and how to approach them. These factors suggest that the replicability of results in field A is likely to be higher.
On the other hand, field B is described as being in an exploratory phase, with a larger community of researchers and a more recent influx of attention. This suggests that the field is still in the process of establishing a set of well-defined hypotheses and methods, which may lead to more variability in research results and lower replicability.
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a 1000-kg car experiences a net force of 9500 n while slowing down from 30 m/s to how far does it travel while slowing down?
By using the kinematic equation that relates the distance traveled by an object to its initial velocity, final velocity, acceleration, and time the car travels a distance of 450 meters while slowing down from 30 m/s.
What is a kinematic equation?A kinematic equation is a mathematical equation that relates the motion of an object to its position, velocity, acceleration, and time. These equations are derived from the principles of classical mechanics and are used to describe the motion of objects in a variety of physical contexts.
The most commonly used kinematic equations are those that describe the motion of an object with constant acceleration, which can be derived from the equations of motion of a particle under constant acceleration. These equations are:
v_f = v_i + at (the equation that relates the final velocity v_f, the initial velocity v_i, the acceleration a, and the time t)d = v_i*t + (1/2)at^2 (the equation that relates the displacement d, the initial velocity v_i, the acceleration a, and the time t)v_f^2 = v_i^2 + 2ad (the equation that relates the final velocity v_f, the initial velocity v_i, the acceleration a, and the displacement d)To calculate the distance covered by the car while slowing down:
Using Kinematic equation,
d = (v_f^2 - v_i^2 ) / (2a)
where:
d is the distance traveled
v_i is the initial velocity
v_f is the final velocity
a is the acceleration
In this case, the car is slowing down, so the acceleration is negative. We can calculate the acceleration using Newton's second law:
F_net = ma
where F_net is the net force, m is the mass of the car, and a is the acceleration. Solving for a, we get:
a = F_net / m = 9500 N / 1000 kg = 9.5 m/s^2 (in the opposite direction of the initial motion)
Now we can substitute the values into the kinematic equation:
d = (v_f^2 - v_i^2) / (2a) = (0 m/s - 30 m/s)^2 / (2(-9.5 m/s^2)) = 450 m
Therefore, the car travels a distance of 450 meters while slowing down from 30 m/s.
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we place a potential difference 6.11 v across a and b, how much charge is present on the c2 capacitor?
We cannot calculate the charge on the C2 capacitor without knowing the capacitance of the capacitor.
To determine the charge present on the C2 capacitor, we need to know the capacitance of the capacitor and the potential difference across it.
Assuming that the circuit is in steady state and neglecting any resistive losses, the potential difference across both capacitors will be equal to the applied potential difference of 6.11 V.
Let's call the capacitance of C2 as C2.
Then the charge present on the C2 capacitor can be calculated using the formula:
Q = C2 * V
where Q is the charge on the capacitor,
C2 is the capacitance of the capacitor, and
V is the potential difference across the capacitor.
Plugging in the values,
we get:
Q = C2 * V = C2 * 6.11 V
We cannot calculate the charge on the C2 capacitor without knowing the capacitance of the capacitor.
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IA battery moves a charge of 60coloumbs around a circuit at a constant rate in 29seconds .Find the current in the circuit
The current in the circuit is ≈ 2.07 amperes (A)
What is current circuit?A current circuit is a closed path through which electric current can flow. It typically consists of a power source, such as a battery or generator, a load, such as a light bulb or motor, and conductive wires or other components that connect the power source and load to form a complete path for the current to flow.
The current in the circuit can be calculated using the formula:
current = charge / time
In this case, the charge moved around the circuit is 60 coulombs and the time taken is 29 seconds. Thus, the current in the circuit is:
current = 60 coulombs / 29 seconds
current ≈ 2.07 amperes (A)
Therefore, The current in the circuit is ≈ 2.07 amperes (A)
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