Why does redshift occur?

The physical means of the slope between the static friction and the normal pressure is the coefficient of static friction of the surface on which the object is located.

Mathematically fstatic≤usΝ in which μs is the coefficient of friction and slope among fs and N will provide this μs mentioning that static friction increases with an increase in everyday pressure and vice versa. but we will see this linearity between fs and N most effective for the most static frictional pressure and till fs< usN we can't observe this linearity and when fs=uSN we will look at this linearity.

The slope of this graph represents the coefficient of friction, The more the force the more the friction because the pressure is higher the downward pressure is extra consequently the object. So the friction on the shoe does rely on the load. So the slope of the graph represents the coefficient of friction. Kinetic friction importance is directly proportional to the regular pressure magnitude and the roughness between the sliding surfaces. Static friction magnitude is immediately proportional to the normal pressure importance and the roughness among the sliding surfaces.

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The total forces acting on the rope is 125 N towards the right side.

125 N of total forces are being applied to the rope's right side.

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Yes, the stars going supernova will have impact on allowing life to exist in nearby planets.

When a star goes supernova, a large amount of radiation is emitted. So, if a nearby planet inhabiting life has a ozone layer, it will be depleted. This results in increased harmful radiation levels on the ground. There will be mutations in organisms that can survive the radiations. Those that are not strong will die.

A supernova is the explosion of a star. This phenomenon happens when a star's nuclear fuel in its core runs out. As a result the pressure created by the burning in its core becomes completely null. Thus the gravity is only force acting, so the star collapses on itself emitting huge quantities of light and harmful radiation.  

Therefore, the stars going supernova will have impact on allowing life to exist in nearby planets.

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1. The weight of a 12.5 kg mass is 122.625 N

2. The mass of a 2.5 N weight is 0.255 kg

3. The mass of a 200 N weight is 20.4 kg

4. The scale read for a 4 kg mass is 39.2 N

The mass of a substance is the quantity of matter present in that substance.

The quantity of matter or mass of a substance is constant and is measured using a weighing balance.

The weight of a substance is the product of the mass of a substance and the acceleration due to gravity.

The weight of a substance varies and is measured using a spring balance and the unit is N.

Weight = m * g

where;

m is mass in kg

g = 9.81 m/s²

Considering the given substances:

1. The weight of a 12.5 kg mass = 12.5 * 9.81

The weight of a 12.5 kg mass = 122.625 N

2. The mass of a 2.5 N weight = 2.5/9.81

The mass of a 2.5 N weight = 0.255 kg

3. The mass of a 200 N weight = 200/9.81

The mass of a 200 N weight = 20.4 kg

4. The scale read for a 4 kg mass = 4 * 9.81

The scale read for a 4 kg mass = 39.2 N

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Answer: C

Explanation:

The bigger the satellite, the longer it will take to get around the satellite. Hence, the velocity would get smaller.

r*v=4r*?

r*v/4r=?

r/4r * v=?

1/4 * v=?

?=v/4 ==> C

Answer:

A. Parallel connection

Answer:

Parallel circuit to be exact

Answer:

Development of acne in boyw

To find the component of car's average velocity along X-axis, the angle between the the direction of the velocity and the X-axis must be known.

The value of x component of the car's average velocity is Vcosx.

Let the angle be = x

The X-component of the car's average velocity = Vcosx.

V is the magnitude of the velocity.

To calculate the y component of the car's average velocity

The Y-component of the velocity = Vsinx

The difference between the change in position or displacement (x) and the time periods (t) during which the displacement happens is known as average velocity. Depending on the direction of the displacement, the average velocity could be either positive or negative. Meters per second (m/s or ms-1) is the SI unit of measure for average velocity.

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The package strike the ground relative to the point directly below it was released at 213.3m.

Given values,

Velocity of plane 45 m/s

Acceleration due to gravity 9.8 m/s²

horizontal component of plane velocity is

ux = 45 m/s

Vertical component is zero

In the same way

ay = - 9.8  m/s²

ax = .0 m/s^2

Motion in y direction = -110 m

From equation of motion time of flight is

d = u x t + 1/2 at²

where,

d is distance

u is velocity initial

a is acceleration

t is time

So, putting values

-110 = 0 + 1/2 (-9.8)t²

-110 = -4.9t²

t² = 110 / -4.9

t² = 22.45

t = √22.45

t = 4.74

Motion in x direction,

d = u x t + 1/2 at²

d = ( 45 x 4.74) + 1/2 (0) 4.74²

d = 213.3 + 0

d = 213.3m

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The average speed of the plane is 875.999 m/s.

Average speed can be defined as the ratio of total distanced travelled by the object to that of total time taken to cover the distance.

Mathematically, Average speed = Av = [tex]\frac{Total Distance}{Total Time}[/tex]

According to the question,

Speed of the plane away from its base V₁ = 730 m/s

Speed of the plane when it flies back V₂ = 1095 m/s

Plane flies the distance D = 404 km

Total Distance covered by the plane S = 404 * 2 km

(because the distance travelled by the plane when going away from the base and then flying back to the base is same)

Therefore S = 808 km = 808 ˣ 10³ m

Time taken by the plane while flying away from the base T₁ = [tex]\frac{D}{V1}[/tex]

T₁ =  [tex]\frac{404000}{730}[/tex] = 553.425 s

Time taken by the plane while flying back to the base T₂ = [tex]\frac{D}{V2}[/tex]

T₂ =  [tex]\frac{404000}{1095}[/tex] = 368.949s

Total Time T = T₁ + T₂ = 922.375 s

Therefore  Av = [tex]\frac{Total Distance}{Total Time}[/tex]

= [tex]\frac{D}{T}[/tex] m/s

=  [tex]\frac{808000}{922.375}[/tex]  m/s

= 875.999 m/s

The average speed of the plane will be 875.999 m/s.

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(a) The volume of asphalt needed is 6400 m³.

(b) The number of dump truck loads required is 320.

(c) The gross mass of each truck is 34400 kg.

The dimension of the two-lane highway 20 km long, 8 m wide, and 4 cm thick.

The mass of a dump truck is 20 metric tons, and carrying capacity is 20 m³ and the density is 0.72 g/cm³.

The two-lane highway:

length, l = 20 km = 20 × 10³ m

breadth, b = 8 m

Thickness, h = 4 cm = 4 × 10⁻² m

(a) The volume of the asphalt will be:

V = l × b × h

V = 20 × 10³ × 8 × 4 × 10⁻² m³

V = 64 × 10² m³

V = 6400 m³

V = 6400 × 10⁶ cm³

(b) The carrying capacity of 20 m³ asphalt.

Therefore, the number of truckloads required will be:

= 6400 m³ / 20 m³

= 320

(c) Now,

Density, d = 0.72 g/cm³ = 720 kg/m³

The empty mass is 20 metric tons which is equal to 20 ×10³ kg.

Therefore, the gross mass of each truck will be

m = 20 ×10³ kg + 720 kg/m³ × 20 m³

m = 20000 kg + 14400 kg

m = 34400 kg

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Although the bigger football player will move, his speed will be substantially slower than the smaller players due to his greater mass.

According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced. As a result, momentum cannot be gained or lost.

When a collision occurs, the point of impact is generated by two equal and opposing forces. The heavier mass will be forced to accelerate by the force applied to it, whereas the smaller mass will be forced to slow down by the force applied to it.

Because of their greater mass, larger masses will accelerate more slowly, reducing their velocity.

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The kinetic energy of of given data is K.E. = 1,047.62 J

To calculate kinetic energy using the formula,

K.E. = 1/2 m v²

where,

K.E is kinetic energy

m is mass

v is velocity

So, Putting values,

K.E. = 1/2 x 29 x (8.5m/s)²

K.E. = 1,047.62 J

The energy an object has as a consequence of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the object, which then moves at a new, constant speed.

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Answer:

Bannister = 3:59.4 sec = 239.4 sec

Guerruoj = 3:43.13 = 223.13 sec

1 mi = 5280 ft

G = 5280 / 223.13 = 23.66 ft/sec

B = 5280 / 239.4 = 22.06 ft/sec

In 223.13 sec B runs 223.13 * 22.06 = 4922 ft

G Wins by 358 ft = 119.3 yds = 109.1 meters

Answer:

The low of conservation of energy states that "energy can neither be created nor be destroyed but it can be changed from one form to another".

Memoir is a type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life.

Because it combines elements of creative writing with the relation of facts required to produce a work of nonfiction, narrative nonfiction is a type of writing that is occasionally referred to as creative nonfiction. This genre comprises of writing that is factually accurate yet written with a creative flair that contributes to improving the work's flow and appeal. The genre of narrative nonfiction can include journalism and some genres of biography, essay, memoir, and personal essay. When compared to plain nonfiction, this genre is very new, and as the genre has developed, so too has the scrutiny that is applied to this kind of writing.

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(a) The force the spring exert on glider A  is 1.88 N.

(b) The force the spring exert on glider B is 2.82 N.

The acceleration of the spring is calculated as follows;

F = ma

a = F/m

a = 5.4 N / (0.15 kg + 0.4 kg + 0.6 kg0

a = 4.7 m/s²

F(A) = ma

F(A) = 0.4 kg x 4.7 m/s²

F(A) = 1.88 N

F(B) = 0.6 kg x 4.7 m/s²

F(B) = 1.88 N

F(B) = 2.82 N

Thus, the force the spring exert on glider A  is 1.88 N.

The force the spring exert on glider B is 2.82 N.

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The apple takes 2.05 seconds to fall due to gravity.

Newton's Second Law of Motion and Newton's Law of Universal Gravitation serve as the foundation for the formula for the acceleration caused by gravity. The most practical formula for estimating the acceleration caused by gravity is given by these two laws: g = G*M/R2, where g is the acceleration caused by gravity, G is the universal gravitational constant, M is mass, and R is distance.

Everything has a gravitational pull on every other object, according to Newton's Law of Universal Gravitation. The force is inversely proportional to the square of the distance between the centers of both objects and directly proportional to the masses of both objects. This is determined mathematically by the formula F = G*(m1*m2/d2), where F is the force and G is the gravitational constant of the universe.

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The student can determine the average horizontal velocity of the object using a meter stick and a calculator by measuring the horizontal distance traveled, determine the flight time from the vertical drop, and then calculate the average horizontal velocity.

So option 3 is correct.

The horizontal velocity can be described as the velocity of any projectile along a horizontal path.

From the options given, the student can measure the horizontal distance traveled, determine the flight time from the vertical drop, and then calculate the average horizontal velocity.

Gravity  acts only in the vertical direction and doesn't affect horizontal motion directly.

Horizontal velocity comes from forces that act in the x-axis, that is directions from side to side and not up or down.

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When a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

From Newton's third equation of motion,

v^2 = u^2 + 2gh

where,

h is the height of the object or body from ground

u is the initial velocity of the body or object

v is the final velocity of the body or object

g is the acceleration due to gravity

Now, as we know that

Flowerpot is at rest. So, u = 0

g = 9.81m/s^2

h = 36.5m

By substituting all the values, we get

v^2 = 2 × 9.81 × 36.5

= 716.13

v = 26.7m/s

Thus, we concluded that when a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

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Answer:

1281

Explanation:

what is the magnitude of the resultant of a 61m north and 21m south vector

The straight line in the velocity versus time graph has a physical significance as it depicts constant acceleration of the motion.

Acceleration is a physical quantity which is defined as the change of velocity per unit time it is a vector quantity and therefore can be both positive and negative.

Velocity versus time graph is the depiction of emotion in which the y-axis represents the velocity of the motion and the x-axis represents the time the graph can either be a positive state line or a curve depending on the acceleration of the motion.

According to the question the velocity versus time graph in our case is a straight line.

A straight line in a velocity versus time graph means that motion has a constant acceleration.

The following conclusion can also be reached from the use of differential calculus as we differentiate velocity with respect to time we get a new physical quantity that is known as acceleration.

On differentiating velocity with respect to time we will get a new value that will represent the change in velocity per unit time and since from the definition of acceleration we know that acceleration is change in velocity per unit time therefore we can conclude that the straight line in the velocity time graph depicts constant acceleration.

Therefore, The straight line in the velocity versus time graph has a physical significance as it depicts constant acceleration of the motion.

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The frequency of the simple harmonic motion is 2 Hertz , the maximum acceleration is 3 u and the maximum velocity is equal to 2.48 m/s.

Oscillation is the repetitive or periodic variation, typically in time, of some measure about a central value or between two or more different states.

Time period in periodic oscillation refers to the time taken by the system to complete one oscillation.

Given:

Time period of the oscillation = 0.5 seconds

Amplitude of the oscillation = 2 cm

For determining frequency we use the formula of frequency.

f = 2π/T

Where,

f is the frequency of the oscillation

T is the time period of the oscillation

On substituting values we get,

Frequency (f) = 1/0.5

Frequency (f) = 2 Hertz

For determining maximum acceleration we use,

a = A × w × w

Where,

a is the acceleration

A is amplitude of the SHM

w is the angular frequency

Now,

a = A × w × w

a = 0.02 × 12.4× 12.4

a = 3 u

For maximum velocity we use,

v = A × w

Where v is maximum velocity

v = 0.02 × 12.4

v = 2.48 m/s

Therefore, the frequency of the simple harmonic motion is 2 Hertz , the maximum acceleration is 3 u and the maximum velocity is equal to 2.48 m/s.

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Answer:

VPA

Explanation:

Density calculations are 1.2L = 1200mL m = 2.9 x 10^4 g

Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimetre are a typical unit of measurement for density. Another way to state density is in kilogrammes per cubic metre (in metre-kilogram-second or SI units).

For instance, air weighs 1.2 pounds per cubic metre. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated. The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).

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Answer:

Final speed of car = 9.834 m/s

Displacement = 0.035 km

Explanation:

Part 1

Final velocity, v of an object moving with an acceleration a m/s² for t seconds and an initial velocity u m/s is given by the formula
v = u + at m/s

[tex]\textrm{Initial velocity } u = 22.1 km/h\\\\\textrm{Convert this to m/s:}\\\\\textrm{1 km/h = 1000m/3600 s}\\\\ 22.1 km/h = 22.1 x 1000/3600 = 6.139 m/s\\\\\boxed{\textrm{Final velocity } v = u + at = 6.138 + 0.84 x 4.4 = 9.834 m/s}[/tex]

Displacement s in m for a constant acceleration of a m/s² for a time t seconds is given by the formula:
[tex]x = ut+\dfrac{1}{2}at^2[/tex]
where u is initial velocity

Plugging in the values we get
[tex]s = 6.139\cdot 4.4 + \dfrac{1}{2}\cdot0.84\cdot (4.4)^2 = 35.143 \;\mathrm {meters}[/tex]
35.143 meters = 35.143/1000 =  0.035 km

Answer:

1)  9.83 m/s (2 d.p.)

2)  0.04 km (2 d.p.)

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Given:

Convert km/h into m/s by dividing by 3.6:

[tex]\implies \sf 22.1\;km/h=\dfrac{22.1}{3.6}\;m/s[/tex]

Substitute the given values into the formula and solve for v:

[tex]\begin{aligned}v&=u+at\\\implies v & = \dfrac{22.1}{3.6}+0.84(4.4)\\v & = 6.1388...+3.696\\v & = 9.834888...\\v & = 9.83 \sf \;m/s\;(2\:d.p.)\end{aligned}[/tex]

Therefore, the final speed of the car was 9.83 m/s (2 d.p.).

Substitute the given values into the formula and solve for s, remembering to use the initial velocity in m/s:

[tex]\begin{aligned}s & = ut+\dfrac{1}{2}at^2\\\implies s &=\dfrac{22.1}{3.6}(4.4)+\dfrac{1}{2}(0.84)(4.4)^2\\s &=27.0111...+8.1312\\s &=35.1423111...\sf m\end{aligned}[/tex]

Convert meters into kilometers by dividing by 1000:

[tex]\implies \dfrac{35.1423111...}{1000}=0.0351423111...=0.04 \sf \; km\;(2\:d.p.)[/tex]

Therefore, the displacement of the car after 4.4 s was 0.04 km (2 d.p.).

To determine the wavelength of a transverse wave, we use the graph of  y-position vs. x-position.

A transverse wave is a wave in which the direction of propagation of the wave is perpendicular to the direction of the disturbance causing the wave.

Plotting a transverse wave,

Now, we can have two graphs namely,

If we plot a cycle of each graph above, we see that position is plotted against time and y-position is plotted against x-position.

We note that the x - position is the direction of travel of the wave in which we measure its wavength. Since the wavelength is the x - position after one cycle, so, we use the graph of y-position vs. x-position to find its wavelength.

So, to determine the wavelength of a transverse wave, we use the graph of  y-position vs. x-position.

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