Write the product in standard form.
(2 - 3i)(2 + i)​

Answer:

1,620in

Step-by-step explanation:

LxWxH

36 x 15 x 3 = 1,620 in

Answer:

1620

Step-by-step explanation:

Answer:

g(x)= 2/5

Step-by-step explanation:

g(xl=f(4x-2)+1

5×-2

5x/5

x=2/5

Answer:

6

Step-by-step explanation:

Similar triangles. MNE is ABC but 3/4 the size. Multiply each side by 3/4 to get lengths.

x = 8 *3/4 = 6

Answer:

A

Step-by-step explanation:

We know that in normal distribution, approximately 34% of bags will fall with in one standard deviation on one side. On both sides within the range of 1 standard deviation, 34 + 34 = 68 % of bags will fall.

Our range is:

1600 to 1620

1610 - 10 to 1610 + 10

So the answer is 1

That means, that 68% is the answer.

Answer:

The answer is A.

Step-by-step explanation:

Approximately 68%

Answer:

1/5

Step-by-step explanation:

switch sides, delete both common factors and your stuck with 5k=1. then you put both in a fraction and it gets you 1/5

Answer:

The experimental group in this case are the group of bees that are put in the small cage.

Step-by-step explanation:

The experimental group is the group of subjects that participate in the test. They are usually assigned to the treatments in study. In some cases there is a control group, with no assigned treatment.

In this case, the bees that she put in the cage, and they are not assigned to a particular treatment. It can be considered a control group.

Answer:

2160ft³

Step-by-step explanation:

V=whl=10·18·12=2160ft³

Answer:

[tex]\log_84+\log_8a+\log_8(b-4)-4\log_8c[/tex].

Step-by-step explanation:

The given expression is

[tex]\log_84a\left(\dfrac{b-4}{c^4}\right)[/tex]

Using the properties of logarithm, we get

[tex]\log_84+\log_8a+\log_8\left(\dfrac{b-4}{c^4}\right)[/tex]     [tex][\because \log_a mn=\log_a m+\log_a n][/tex]

[tex]\log_84+\log_8a+\log_8(b-4)-\log_8c^4[/tex]     [tex][\because \log_a \frac{m}{n}=\log_a m-\log_a n][/tex]

[tex]\log_84+\log_8a+\log_8(b-4)-4\log_8c[/tex]     [tex][\because \log_a x^n =n\log_a x][/tex]

Therefore, the required expression is [tex]\log_84+\log_8a+\log_8(b-4)-4\log_8c[/tex].

Answer:

B on edge

Step-by-step explanation:

Answer:

  3(cos(75°) +i·sin(75°)) and 3(cos(255°) +i·sin(255°))

Step-by-step explanation:

Using Euler's formula, this can be written as ...

  x^2 = 9·e^(i5π/6)

Then the square roots are ...

  x = (±√9)e^((i5π/6)/2) = ±3e^(i5π/12)

Of course, multiplying by -1 is the same as adding 180° to the angle.

The square roots are ...

  3(cos(75°) +i·sin(75°)) and 3(cos(255°) +i·sin(255°))

Answer:

The answer is "[tex]\bold{y=0.5 \cos 3 \theta}[/tex]"

Step-by-step explanation:

The choices were missing the question so the answer to this question can be defined as follows:

The answer is [tex]y= 0.5 \cos 3\theta[/tex] because:

[tex]\Rightarrow -1 \leq \cos 3 \theta \leq 1\\\\\Rightarrow -0.5 \leq \cos 3 \theta \leq 0.5\\[/tex]

So, the maximum value is = 0.5 and the minimum value is = -0.5 of [tex]\frac{2\pi}{3}[/tex].

Answer:

D. y= 0.5 cos 3 theta

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Because it would have less weight to carry

Answer:

Sample space: [tex]\Omega=\{1,2,3,4,5,6\}[/tex]

Event of rolling the number 1 3, or 4 : A={1,3,4}

Step-by-step explanation:

When you roll a number cube with faces labeled from 1 to 6 once.

The possible outcomes are: 1,2,3,4,5 or 6.

Therefore, the sample space of this event is:

Given the event of rolling the numbers 1, 3, or 4.

Now we are required to give the outcomes for the event of rolling number 1,3 or 4.  Let's call the event A. The set of possible outcomes for A has all the numbers 1, 3 and 4 as follows

Answer: $5.96

Step-by-step explanation:

4.99 + 0.46 + 0.89 is what she paid, not with tax. That equals 6.34.

Applying 6% means we calculate 6% of 6.34 and then subtract it from 6.34. (Or, we can also calculate 100-6%=94% of 6.34). Either way, the answer is 5.9596, or rounded, 5.96.

Hope that helped,

-sirswagger21

Answer:

The answer would be 5 and -12

Answer:

Step-by-step explanation:

a) We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 238

For the alternative hypothesis,

H1: µ < 238

This is a left tailed test

b) Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 231

µ = population mean = 238

s = samples standard deviation = 80

t = (231 - 238)/(80/√100) = - 0.88

We would determine the p value using the t test calculator. It becomes

p = 0.19

c) Since alpha, 0.05 < than the p value, 0.19, then we would fail to reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed insignificant evidence that the mean weekly unemployment insurance benefit in Virginia was below the national average.

d) Since α = 0.05, the critical value is determined from the t distribution table. Recall that this is a left tailed test. Therefore, we would find the critical value corresponding to 1 - α and reject the null hypothesis if the test statistic is less than the negative of the table value.

1 - α = 1 - 0.05 = 0.95

The negative critical value is - 1.66

Since - 0.88 is greater than - 1.66, then we would fail to reject the null hypothesis.

Answer:

21,000$

Step-by-step explanation:

part to whole method

20/100 and 4,200/

How many 20s to get to 4,200?

Answer:

x= 70

Step-by-step explanation:

These are supplementary angles

45+2x-5 = 180

Combine like terms

40+2x= 180

Subtract 40 from each side

40+2x-40 =180-40

2x= 140

Divide by 2

2x/2 =140/2

x = 70

Answer: 720 ft

Step-by-step explanation: He rides 720 feet.

if 120 feet are in 10 seconds then;

60 seconds are 60/10*120=720 feet

Answer:

720

Step-by-step explanation:

120/10 to find his feet per second which is 12 feet per second

12*60

since there are 60 seconds in a minute

= 720

Answer:

The value of Chi-square test statistic for a hypothesis test of independence is 14.22.

Step-by-step explanation:

The data provided is for one day's output of Kortholt's from the Melodic Kortholt Company.

The formula to compute the chi-square test statistic for a hypothesis of independence is:

[tex]\chi^{2}=\sum {\frac{(O-E)^{2}}{E}}[/tex]

The formula to compute the expected frequencies (E) is:

[tex]E=\frac{\text{Row Total}\times \text{Column Total}}{N}[/tex]

Consider the Excel output attached.

Compute the value of Chi-square test statistic as follows:

[tex]\chi^{2}=\sum {\frac{(O-E)^{2}}{E}}[/tex]

    [tex]=1.333+2.222+4.000+6.667\\=14.222\\\approx 14.22[/tex]

Thus, the value of Chi-square test statistic for a hypothesis test of independence is 14.22.

Answer: m is 13

m is 6

you find m by calculating!

Step-by-step explanation:

Answer:

  [tex]F^{-1}(x)=\dfrac{x-7}{4}[/tex]

Step-by-step explanation:

To find the inverse function, solve for y the relation ...

  F(y) = x

  4y +7 = x

  4y = x - 7

  y = (x -7)/4 . . . . the inverse function

  [tex]\boxed{F^{-1}(x)=\dfrac{x-7}{4}}[/tex]

Answer:

bag weigh 0.45 lbs

Step-by-step explanation:

Answer:

The test statistic to test the null hypothesis equals 1.059

Step-by-step explanation:

From the given information; we have:

Treatment               Observations

A                                20        30         25       33

B                                22         26        20       28

C                               40         30         28       22

The objective is to find the  test statistic to test the null hypothesis; in order to do that;we must first run through a series of some activities.

Let first compute the sum of the square;

Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex]  +    Error sum of squares   (ESS)

where:

(TSS) = [tex]\sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}oo)^2[/tex]  with (n-1)   df

[tex](T_r SS)[/tex]   [tex]= \sum \limits ^v_{i=1} n_i( \overline yio- \overline {y}oo)^2[/tex]   with (v-1)  df

[tex](ESS) = \sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}io)^2[/tex]   with (n-v) df

where;

v= 3

[tex]n_i=[/tex]4

i = 1,2,3

n =12

[tex]y_{ij}[/tex] is the [tex]j^{th[/tex] observation for the [tex]i^{th[/tex] treatment

[tex]\overline{y}io[/tex] is the mean of the  [tex]i^{th[/tex] treatment  i = 1,2,3 ;  j = 1,2,3,4

[tex]\overline y oo[/tex]   is the overall mean

From the given data

[tex]\overline y oo = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij)^2= 27[/tex]

[tex]TSS = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij- 27)^2 = 378[/tex]

[tex]T_r SS= \sum \limits^3_{i=1}4 (\overline y io - \overline yoo)^2[/tex]

[tex]=4(27-27)^2+4(24-27)^2+4(30-27)^2 = 72[/tex]

Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex]  +    Error sum of squares   (ESS)

(TSS) =  378 - 72

(TSS) =  306

Now; to the mean square between treatments (MSTR); we use the formula:

MSTR = TrSS/df(TrSS)

MSTR = 72/(3 - 1)

MSTR = 72/2

MSTR = 36

The mean square within treatments  (MSE) is:

MSE = ESS/df(ESS)

MSE = 306/(12-3)

MSE = 306/(9)

MSE = 34

The test statistic to test the null hypothesis is :

[tex]T = \dfrac{ \dfrac{TrSS}{\sigma^2}/(v-1) }{ \dfrac{ESS}{\sigma^2}/(n-v) } = \dfrac{MSTR}{MSE} \ \ \ \approx \ \ T(\overline {v-1}, \overline {n-v})[/tex]

[tex]T = \dfrac{36}{34}[/tex]

T = 1.059

Answer:

100+70+8+0.2+0.05. is the answer

Answer:

178.25 as a fraction is 178 1/4 or 713 / 4

Step-by-step explanation:

hope it works out !!

Answer:

8/9

Step-by-step explanation:

1 blue, 2 yellow, 7 red, 6 green, and 2 purple marbles = 18 marbles

The number that are not yellow = total - yellow

P( not yellow) = number that are not yellow / total

                       = (18-2) / 18

                       = 16/18

                       =8/9

Answer:

[tex]-\dfrac{1}{26}[/tex]

Step-by-step explanation:

[tex]-\dfrac{12}{13}\div 24=\\\\-\dfrac{12}{13} \times \dfrac{1}{24}=\\\\-\dfrac{12}{13\times 24}=\\\\-\dfrac{1}{26}[/tex]

Hope this helps!

Answer:

11.51% probability that the mean annual salary of the sample is between $71000 and $73500

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

[tex]\mu = 74000, \sigma = 2500, n = 36, s = \frac{2500}{\sqrt{36}} = 416.67[/tex]

What is the probability that the mean annual salary of the sample is between $71000 and $73500?

This is the pvalue of Z when X = 73500 subtracted by the pvalue of Z when X = 71000. So

X = 73500

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{73500 - 74000}{416.67}[/tex]

[tex]Z = -1.2[/tex]

[tex]Z = -1.2[/tex] has a pvalue of 0.1151

X = 71000

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{71000 - 74000}{416.67}[/tex]

[tex]Z = -7.2[/tex]

[tex]Z = -7.2[/tex] has a pvalue of 0.

0.1151 - 0 = 0.1151

11.51% probability that the mean annual salary of the sample is between $71000 and $73500

Answer:

Only 16 whole sandwiches can be produced

Step-by-step explanation:

From the question, we know that we will need two slices of bread to make a full sandwich.

We can divide the number of slices of bread by two to check how many full sandwiches can be made.

Number of complete sets of bread = 32/2 = 16 sets

Similarly, we can divide the number of slices of cheese by 3 to find out the number of complete sets of cheese that will be there:

Number of complete sets of cheese = 51/3 = 17 sets

Since we have more cheese than bread, the number of whole sandwiches that can be made will be limited to the number of sets of bread available. (in this case, the ingredient smaller in quantity will be used to limit the production) which is = 16

Therefore only 16 whole sandwiches can be produced

Answer:

The domain of the function H(t), is [-5, 30].

The range of the function H(t), is [(10% + average), (average - 20%)]

Step-by-step explanation:

The domain of a function is the complete set of possible values of the independent variable.

For this question, the function is H(t), with the temperature, t, serving as the independent variables and H(t) the evidently dependent variable.

The domain of a function refers to all the possible independent variable values that will give corresponding real dependent variable values.

For this question, Alice's model has the probability for the occurrence of heart disease (in percents relative to the global average) at an area, H(t) varying with the temperature of that area in degree Celsius.

At a temperature of -5°C (the lowest temperature in the model), the probability is 10% above the average.

Then, the probability decreases with increase in temperature, taking a value 20% lower than the average when the temperature is at its highest of 30°C in the model.

So, temperature ranges from -5°C to 30°C and the probability for the occurrence of heart disease ranges from 10% above the average to 20% below the average.

The domain of the function H(t), from the definition given above would therefore be [-5, 30]

And the range of the function H(t), is [(10% + average), (average - 20%)]

Hope this Helps!!!

The Real Number type is more appropriate fro the domain of H(t).

The domain of H(t) is given as  [tex]-5 \leq t \leq 30[/tex]

Given that:

The lowest temperature included in the model is -5° C

The highest temperature included in the model is 30° C

The domain of H includes the values of the temperature. Since the temperature can be non integer too, sometimes rational too, thus we use Real Number type for the domain of H(t).

The domain of H(t) will be given by the following interval on real number line:

[tex]\begin{aligned} Domain(H(t)) = [-5, 30]\\\end{aligned}[/tex]

or [tex]-5 \leq t \leq 30[/tex].

Hence, the Real Number type is more appropriate fro the domain of H(t).

The domain of H(t) is given as  [tex]-5 \leq t \leq 30[/tex].

Learn more here:

https://brainly.com/question/9463453

Answer:

  closest choice: (-2, 0.2)

Step-by-step explanation:

The attached image from a graphing calculator shows the solutions (to the nearest tenth) to be ...

  (-1.9, 0.2)

  (1.0, 6.0)

The closest of the offered choices is (-2, 0.2). None are actually correct.